PHP - Date And Time Quiery
hi all,
i have a script that im trying to add the @ sign after the date. code: Code: [Select] <td align='left' class='forumheader3' nowrap>".(($wardate == -1) ? "" : date($conf['formatdetails'], $wardate))."</td> resulting in this: Code: [Select] 1 Apr 2012 21:30 but i am trying to get the @ after the date so the result would be this: Code: [Select] 1 Apr 2012 @ 21:30 any help please Similar TutorialsHey guys, How would I go about subtracting Today from a previous day to find the difference? For example, I want to subtract TODAY from a previous date in my database, to determine if the difference is greater than 1 day. Any ideas? I tried doing the subraction in TIMESTAMPS, but when I convert the date back to Y-m-d H:i:s, I got some weird year and time. PHP date and time function is not showing correct time on my local system I have the following php code date_default_timezone_set("Africa/Lagos"); $date = date('d-m-y h:i:s'); echo "Server Time ".$date ."<br>"; echo "The time is " . date("h:i:sa")."<br>"; $current_datetime = date("Y-m-d") . ' ' . date("H:i:s", STRTOTIME(date('h:i:sa'))); echo "Current time1: ".$current_datetime . "<br>";
Output
Server Time 21-05-21 09:55:39
Expected Output
Server Time 21-05-21 10:55:39
Any help would be appreciated. Edited May 21 by Ponel I am having a problem with PHP displaying the correct date and time. It updates as it should, but is fast by 4min and is always displaying a date in 2004. I ran a basic php script to make sure the application im using itself is not wrong. go to lunenburgledger.com/time.php Anybody had any ideas on where to check? The system time on the Windows Server 2003 is correct. The only thing I can think of is that it was converted to a virtual machine on vmware esxi, but the system time stayed right. Any ideas? Thanks! OK So I've got a datepicker that sends a date in d/m/y format. My DB stores the data in Unix Timestamp Which I can convert the date to with strtotime however this does the exact date & time. All I want is the actual day. I've spent hours trying to convert this with just the day with mixed results... Thanks. Hey, I need help with date, I have stored dates in my table in this format: i.e. 22.10.2011 but now use timestamp to store dates. Problem is with this query the WHERE clause will find dates in the old format and I want to change that to the new format. Code: [Select] for($i = $count; $i > 0; $i--) { $day = date("d.m.Y", mktime(0, 0, 0, date("m"), date("d") - $i, date("Y"))); $tmp = mysql_fetch_array(safe_query("SELECT count FROM ".PREFIX."counter_stats WHERE dates LIKE '%".$day."'")); $array[] = $tmp['count'] ? $tmp['count'] : 0; } Am I making sense ? Hi! The below dropdown will show dates/times every 15 minutes from 12am to 11:45pm for only 1 day. I want it to show for 5 days, anyway I can do this? Below code: Code: [Select] $start = strtotime('12:00am'); $end = strtotime('11:45pm'); echo '<select name="time">'; for ($i = $start; $i <= $end; $i += 900) { echo '<option>' . date('F j, Y, \a\t g:i a', $i); } echo '</select>'; Thanks for any help. I have a field set as datetime and want to compare that field to see if it is older then ten minutes. Can anyone help I am having a brain fart? What is the best way to insert this time stamp into mysql? This is the info I want... Example: Sunday, 28.1.11, 9:56 How would I also select time from the database using mysql? I have a batch script that reads from a timestamp.txt file to determine the last time it ran and I need to modify that by two hours. What happens is the script will run to look for changes in the county records and their server time is two hours different from mine. Code: [Select] $fr=fopen("xml/timestamp.txt",'r'); $mydate=fread($fr, 50); if ($incremental_updates == 1){ $default_template_file="xml/incremental_template.xml"; $default_config_name="xml/incremental.xml"; $contest=file_get_contents($default_template_file); $contest=str_replace("{DATE_TAG}", $mydate, $contest); $f=fopen($default_config_name,'w+'); fwrite($f, $contest); fclose($f); fclose($fr); $fw=fopen("xml/timestamp.txt",'w'); fwrite($fw, substr(date('c'), 0, 19)); fclose($fw); }else{ $default_config_name = "xml/full_update.xml"; } I tried making a time stamp update look like $cur_timestamp=date("Y-m-d H:i:s", time() +14400); which is correct but it doesn't write to the text file properly. Using the above fwrite($fw, substr(date('c'), 0, 19)); I get the correct results in the timestamp.txt file for my server time. I need it to be +14400 2011-05-25T08:27:51 would essentially become 2011-05-25T10:27:51 when it writes to the timestamp.txt I hope that makes sense. J Hey, I need help with my date & time string. I need to edit it do show in a string + also use it for calculating things like when the date has passed. The string is like this: Code: [Select] <?php $string = '2011-01-01 00:00 AM'; ?> So i wanted to check if there was a function that can automatically convert it, so it would say for example: Quote Sunday, 1st of January 2011 00:00 AM But at the same time compare $string against server time to see if the date has expired? Hope you can help Hi, I am new to this forum as of now. I have a question which probably has a very straightforward answer but I just can't solve it. I am using mysql and have the following code: while($row=mysqli_fetch_array($result)) { $time1=date("j F Y G: i", $row[1]); echo "<tr><td>$row[email]</td>"; echo "<td>$time1</td>"; echo "<td>$row[comment]</td></tr>"; } It is the first line in the curly brackets that is causing the problem. If I replace $row[1] with $time I get today's date/time. But I need the date/time from what has been input so that won't work. Can anyone explain to me what is wrong with my code please? It gives the following error message: Notice: A non well formed numeric value encountered in C:\xampp\htdocs Thanks very much Hey guys, What i would like to create is the ability to calculate the difference between two dates / times. For example: 2010-12-13 10:00:00 to 2010-12-17 17:00:00 In a format of days / hours and minutes / seconds. However, I only want to calculate for an 9-5 work day, not the hours outside. Is this possible? If so, how would I go about creating something like this. how to calculate the difference between the current datetime from the stored one(ie date_field = 2020-08-09 23:13:06) in order to compare with 15min, i mean if the resulted time exceed 15 min and not the same day(date) the provided link will show expire message. i.e $some_variable = $date_in_db - current_date; if((time() - $some_variable > 15*60) && not the same day or the same day){ echo 'the link has expired'; }
the TIMESTAMP from mysql returns in this format: 2012-04-20 14:25:50 How could I rearrange this with PHP to read as: 04/20/2012 14:25 Thanks I just recalled using date(); time() for lots of things in my database, including post times etc. At first I simply assumed this used server time or something, but when I changed my PC's time, it changed ! Now, shortly after this I simply assumed this was because of me using a localhost? But I am not certain anymore.. If I would place this online, would date() and time() return you server time or user time? I couldnt find it on google =-( hi, I have some code that deals with sending out reminders for appointments due the following day. So if today is the 21/3 then only reminders for appointments due on the 22/3 should be sent. Currently this isn't happening... If reminders are sent on 21/3 at 9.50 am, my code adds 24 hours to this datetime and sends reminders due for all appointments that fall bewteen 21/3 9.50am and 22/3 9.49 am. What I want to do is simply send all reminders for appointments that are on the 22/3 exclusive of time. I'm not sure how do this in php, which uses the unix datetime format to mildy complicate issues anhy help or solutions would be massive, thanks.how to Code: [Select] $days = time() + (1 * (60 * 60 * 24)); $apts = $db->fetch_all('status = 1 AND time > ? AND time < ?', array(time(), $days)); I have a time and date using the code echo date("l jS \of F Y H:i:s."); Now I need to show this in several different languages, including French German and Dutch I have tried setlocale(); and echo strftime The date shows but still in English. Any idea how to show the day date and time in Php for the languages suggested. Are time zones when calling the date function automatically decided based on where you live? Or is that something that I have to implement--Because the time is wrong according to my time zone. I am writing an app that takes ofx banking files files on convert them to csv for excel or importation into sql. I am on the last task. Converting the nonstandard date:time stamp. I am using preg_replace(). I am not the best at regular expressions. I am getting this error: "Warning: preg_replace() [function.preg-replace]: Unknown modifier '\' in C:\xampp\htdocs\banking\ofx-date.php on line 13" CODE: // Date Time 20110228000600 (2011/02/28/, 00:06:00) // Expected Return '<DTPOSTED>2011/02/28,00:06:00' $ofxDate = '<DTPOSTED>20110228000600'; $ofxNewDate = substr($ofxDate,0,10) . substr($ofxDate,10,4) . '/' . substr($ofxDate,14,2) . '/' . substr($ofxDate,16,2) . ',' . substr($ofxDate,18,2) . ':' . substr($ofxDate,20,2) . ':' . substr($ofxDate,22,2); echo htmlentities($ofxNewDate) . PHP_EOL;; $patternA = '/<DTPOSTED>/\b[0-9]+\b'; //$replacement = '/<DTPOSTED>/'; $stringB = preg_replace($patternA, $ofxNewDate, ofxDate); echo htmlentities($StringB) . PHP_EOL; Is it possible to convert time(); to date();? |