PHP - File Location Stored In Database Retrieval To Html

How can I run php code that is stored in a database?

I have my pages created by grabbing the contents of a pageBody mySQL table cell, but some pages require further php to be able to display correctly.

For example, I have a players page, which will list all players, and some information about them. The players and information is all saved in a players table in my database (separate to the pages table where pageBody is stored). I use simple php to grab all the players and format all of their information so it can be displayed on the page.

This is the flow of information that I would like:
User clicks on players page browser loads content page (this is a template page), and grabs the pageid from $_GET browser then reads pages table in database to get the pageBody associated with the pageid The pageBody will contain more php, which will run the players script to retrieve the list, and display
Doing it the above way will make it much easier to extend the website to include more types of pages that has to run additional php scripts.
The only way I can think of this working is by doing this:
user clicks on players page
browser loads content page, grabs pageid from $_GET browser checks the pageid for the one associated with players (hard coded into the php script) browser then loads the players.php script instead of going to the database This above way means that I will need to edit the index.php page everytime I add a new list type (example, coaches, volunteers etc).

Anyone have any suggestions? I know my question is long, but I was finding it hard to explain it in an easy to understand way, but I'm still not sure if I have :S.

Cheers
Denno

Hi,

I am trying to store a sql query in a database, but every time I try to read it, it shows all the code as text. eg just print ' . $parts_row['part_number'] . '

Here is the code on the page:       

    $parts_sql = "SELECT * FROM parts WHERE part_cat = " . $category_row['cat_id'] . " ORDER BY CAST(part_a AS DECIMAL(10,2))";
  			$parts_result = mysql_query($parts_sql);
  
  			if(!$parts_result)
  			{
  				echo '<tr><td>The parts could not be displayed, please try again later.</tr></td></table>';
  			}
  			else
 			{
 
 				while($parts_row = mysql_fetch_array($parts_result))
 				{
                                               $pageformat_sql = "SELECT * FROM category_pages WHERE catpage_number = " . $category_row['cat_page'] . "";
 
                                               $pageformat_result = mysql_query($pageformat_sql);
 
 
                                                if(!$pageformat_result)
                                                {
                                                echo 'Error';
                                                }
                                                 else
                                                 {
                                                 while($pageformat_row = mysql_fetch_assoc($pageformat_result))
                                                 {
                                                   $data = $pageformat_row['catpage_table'];
                                                 echo '<table class="table2 centre" style="width:750px">
 	                                              ' . $pageformat_row['catpage_tabletitle'] . '' . $data . '';
 
 
 
                                                 }
                                                 }
 
     }}

And this is what is stored in the database table:

 <tr>
 <td class="cell left">' . $parts_row['part_number'] . '</td>
 <td class="cell centre">' . $parts_row['part_a'] . ' mm</td>
 <td class="cell centre">' . $parts_row['part_b'] . ' mm</td>
 <td class="cell centre">' . $parts_row['part_c'] . ' mm</td>
 <td class="cell centre">' . $parts_row['part_d'] . ' mm</td>
 <td class="cell centre">' . $parts_row['part_e'] . ' mm</td>
 <td class="cell centre">' . $parts_row['part_imped100'] . '</td>
 <td class="cell centre"><a href="datasheets/' . $parts_row['part_datasheet'] . '.pdf"><img border="0" src="images/pdf.jpg" alt="Download"</a></td></tr>

I would be very grateful to anyone who can help me with this.

Hi Guys,

I have a webpage which has subsequent pages stored in a database e.g. index.php?id=1

The problem being, is that id=1 has it's data pulled from a database. This was fine & dandy until I started to insert PHP...I am trying to get the below to executre

<?php
$rater_id=1;
$rater_item_name='Rate This';
include("rater.php");?>

However nothing shows & nothing happens, I know eval can be used but have not been succesfull in implementing this, can someone  please help!

Hi Everyone,

I have a program that generates 200 unique images keeping the first image static in each run.The images keep scrolling on to the screen pause for 3 seconds and scroll off I'm able to generated all 200 unique images without repetition, everything is working well except for the lase two images the last two  images are scrolling on to the screen but are not been displayed in the database, Moreover The last image is a duplicate of 197th image.I don't know what is happening.....

Here is MY code..........



<?php
      session_start();
      $sid = $_SESSION['id'];
      $_SESSION['imageDispCnt'] = 0;
$myQuery = "SELECT * from image";
$conn = mysql_connect("localhost","User","Passwd");
mysql_select_db("database_Name",$conn);
$result = mysql_query($myQuery);
$img =Array();
$id =Array();
$i =0;
$imagepath = 'http://localhost/images/';
while ($row = mysql_fetch_array($result))
      {
      $img[$i] =  $imagepath.$row['img_name'];
      $id[$i] =  $row['imageid'];
      $i = $i + 1;
       }
 ?>
      </head>
      <script language="JavaScript1.2">
var scrollerwidth='800px';
var scrollerheight='600px';
var scrollerbgcolor='white';
var pausebetweenimages=3200;
var s;
var sec;
var d;
var j;
var imgid;
var milisec = 0;
var seconds = 0;
var flag = 1;
var ses_id = '<?php echo $sid;?>';
var count = 0;
var i = 0;
var imgname;
var imgid;
var k =0;
var slideimages=new Array();
var img_id = new Array();
var index;

<?php
  $l =0;   
$count = array();
   $j = rand(0,199);
   while($l < 200)
   {
    while(in_array($j, $count))
        {
           $j = rand(0,199);
        }
        $count[$l] =  $j;
        $l++;
       
     }?>
    <?php
  $k = 0;
  for($k = 0;$k<count($count);$k++){
  ?>
  index = <?php echo $k;?>;
  <?php
        $indx = $count[$k];?>
  if(index == 0){
     slideimages[0] = '<img src="http://localhost/images/hbag044.jpg" name="r_img" id="0"/>';
     img_id[0] = '<input type="hidden" value="0" id="imgId" />';
  }
 
  else if(index > 0)
  {
    slideimages[<?php echo $k?>] = '<img src="<?php echo $img[$indx]?>" name="r_img" id="<?php echo $id[$indx]?>"/>';
     img_id[<?php echo $k?>] = '<input type="hidden" value="<?php echo $id[$indx]?>" id="imgId" />';
  }
<?php
}
?>


Can Any one plese help me

Appreciate your help...


Thanks

I put together the following blocs of code for uploading pictures into a database and displaying them on a webpage.  The pictures are supposed to be displayed on the member's only page of a website I'm working on, upon logging in, and they are supposed to be the member's uploaded picture.  I created several members and and used one of my existing member accounts to test the uploading process.  The picture upload process appeared to have been successful when I checked on myphpadmin.  Yet,  when I login with this account, no picture is displayed, instead, a tiny jpg icon is displayed at the top left corner of the box in which the picture was supposed to be displayed.  Same thing when I login with the other accounts with which I haven't yet uploaded a picture.

I'll start with the code that installs the table in the database

$query = "CREATE TABLE images (

image_id INT UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY ,
member_id INT UNSIGNED,
like_id INT UNSIGNED,
image LONGBLOB NOT NULL,
image_name varchar(255)  NOT NULL,
image_type varchar(4) NOT NULL,
image_size int(8) NOT NULL,
image_cartegory VARCHAR(20) NOT NULL,
image_path VARCHAR(300),
image_date DATE  

          )";




Then here is the code  which allows the member to upload his pictu
<form enctype="multipart/form-data" action="insert_image.php" method="post" name="changer">
                         <input name="MAX_FILE_SIZE" value="102400" type="hidden">
                         <input name="image" accept="image/jpeg" type="file">
                         <input value="Submit" type="submit">
                        </form>


 And here is the insertimage.php which inserts the image into our database:  Note that I have to authenticate the user in order to register his session id which is used later on in the select query  to identify him and select the right image that corresponds to him.


<?php

//This file inserts the main image into the images table.

//address error handling

ini_set ('display_errors', 1);
error_reporting (E_ALL & ~E_NOTICE);





//authenticate user
//Start session

session_start();

       
        //Connect to database
require ('config.php');

//Check whether the session variable id is present or not. If not, deny access.

if(!isset($_SESSION['id']) || (trim($_SESSION['id']) == '')) {

header("location: access_denied.php");

exit();

}

        else{ 
// Make sure the user actually 
// selected and uploaded a file
if (isset($_FILES['image']) && $_FILES['image']['size'] > 0) { 

      // Temporary file name stored on the server
      $tmpName  = $_FILES['image']['tmp_name'];  
       
      // Read the file 
      $fp      = fopen($tmpName, 'r');
      $data = fread($fp, filesize($tmpName));
      $data = addslashes($data);
      fclose($fp);
      

      // Create the query and insert
      // into our database.
      $query = "INSERT INTO images (member_id, image_cartegory, image_date, image) VALUES ('{$_SESSION['id']}', 'main', NOW(), '$data')";
      $results = mysql_query($query);
      
      // Print results
      print "Thank you, your file has been uploaded.";
      
}
else {
   print "No image selected/uploaded";
}

// Close our MySQL Link
mysql_close();


} //End of if statmemnt.
 


?>  



On the page which is supposed to display the image upon login in, I inserted the following html code in the div that's supposed to contain the image:


                    <div id="image_box" style="float:left; background-color: #c0c0c0; height:150px; width:140px; border-           color:#a0a0a0;border-style:outset;border-width:1px; margin:auto; ">
                 
                         <img src=picscript.php?imname=potwoods>
                             
                    </div>

                   
And finally, the picscript.php  contained the select query:
<?php

                             //address error handling

                             ini_set ('display_errors', 1);
                             error_reporting (E_ALL & ~E_NOTICE);

                             //include the config file
                              require('config.php');

                             $image = stripslashes($_REQUEST[imname]);
                             $rs = mysql_query("SELECT* FROM images WHERE member_id = '".$_SESSION['id']."' AND cartegoty = 'main' ");
                             $row = mysql_fetch_assoc($rs);
                             $imagebytes = $row[image];
                             header("Content-type: image/jpeg");
                             print $imagebytes;

                            
 ?>



Now the million dollar question is, "What is preventing the picture from getting displayed?"  I know this is a very lengthy and laborious problem to follow but I'm sure there is someone out there who can point out where I'm not getting it.  Thanks.

this is the line in my script that I have to show the image:

Code: [Select]
$output .= "<img>{$row['disp_pic']}</img></br>\n";


As you can see I added the image tag, but it wont show the actual image. IE shows it as a small square with another small square picture icon in the middle of it (i'm sure you guys know what i mean).

Hi!

I was wondering if there is a way to execute php code which is stored in mysql database using php.

At the minute I am using a echo to try and run php code stored in a mysql database but this just displays the code and does not run the php code.

Thanks for any help!

Good afternoon all!! I have a very specific issue that, in my opinion, is quite complicated. In words, here is what I wish to achieve. I would like a page which displays users from the database. Each individual user has their own Div hidden below their name. Within this div, there is a form. The form is full of radio buttons. Once the user's name is clicked and form submitted, I wish to write the form data to the database for the specific user that was selected. See below example for better understanding:

Dale Gibbs
Chris Hansen
Steve Jobs

If I click Chris Hansen, the following happens

Dale Gibbs
==============
Chris Hansen

HIDDEN DIV FORM CONTENT
HIDDEN DIV FORM CONTENT
HIDDEN DIV FORM CONTENT
HIDDEN DIV FORM CONTENT
HIDDEN DIV FORM CONTENT

Submit Button
==============
Steve Jobbs


So as of now, the display is correct. I am seeing exactly what I want to see from my database. Also, my div IDs work just fine as well as the Javascript toggleSlidebox function. The only issue is for some reason, whenever I submit the form (no matter which user I select from my list), I can only write to the last inputted ID. So for example, if the last ID entered into the database was 6, then thats the only ID that will be returned when my form is submitted and the only place data will be written to, even if I select a user with ID 2. Please see below code for more information

Code: [Select]
<?php

$staff_display_query = "SELECT staff_info.id, staff_info.fname, staff_info.lname FROM staff_info, staff_projects WHERE staff_info.id = staff_projects.staff_id AND staff_projects.proj_id = '$c_project_id'";

$staff_display_sql = mysql_query($staff_display_query) or die (mysql_error());

while ($row = mysql_fetch_array($staff_display_sql)) {
$current_staff_id = $row['id'];
$staff_fname = $row['fname'];
$staff_lname = $row['lname'];

$list_staff .= '
' . $current_staff_id . '<br />
<a href="#" onclick="return false" onmousedown="javascript:toggleSlideBox(' . $current_staff_id . ');">' . $staff_fname . ' ' . $staff_lname . '</a>
<div class="hiddenDiv" id="' . $current_staff_id . '" style="border:#FFF 2px solid; width:553px;">

        <!--TASK 1-->
        <div id="task_1_permissions" class="task_permissions">
            <input name="permissions_1" type="radio" value="1"/>
            <input name="permissions_1" type="radio" value="2" />
            <input name="permissions_1" type="radio" value="3" />
            <input name="permissions_1" type="radio" value="0" />
        </div>

       <!--TASK 2-->
        <div id="task_2_permissions" class="task_permissions">
            <input name="permissions_2" type="radio" value="1"/>
            <input name="permissions_2" type="radio" value="2" />
            <input name="permissions_2" type="radio" value="3" />
            <input name="permissions_2" type="radio" value="0" />
        </div>

       <!--TASK 3-->
        <div id="task_3_permissions" class="task_permissions">
            <input name="permissions_3" type="radio" value="1"/>
            <input name="permissions_3" type="radio" value="2" />
            <input name="permissions_3" type="radio" value="3" />
            <input name="permissions_3" type="radio" value="0" />
        </div>

       <!--TASK 4-->
        <div id="task_4_permissions" class="task_permissions">
            <input name="permissions_4" type="radio" value="1"/>
            <input name="permissions_4" type="radio" value="2" />
            <input name="permissions_4" type="radio" value="3" />
            <input name="permissions_4" type="radio" value="0" />
        </div>

    <input name="submit_user_permissions" type="submit" value="Submit Permissions" />
        
</div>
</div>     
<br /><br />
';
}

if (isset($_POST['submit_user_permissions'])) {
$permissions_1 = $_POST['permissions_1'];
$permissions_2 = $_POST['permissions_2'];
$permissions_3 = $_POST['permissions_3'];
$permissions_4 = $_POST['permissions_4'];
$query = "UPDATE staff_projects SET task_1='$permissions_1', task_2='$permissions_2', task_3='$permissions_3', task_4='$permissions_4' WHERE proj_id='$c_project_id' AND staff_id='$current_staff_id'";

$sql = mysql_query($query) or die (mysql_error());

echo 'Permissions set successfully.<br />';

}


After this PHP I have my standard HTML. Below is the javascript function I use for the slide box:

Code: [Select]

<script src="js/jquery-1.5.js" type="text/javascript"></script>

<script language="javascript" type="text/javascript">
function toggleSlideBox(x) {
if ($('#'+x).is(":hidden")) {
$(".hiddenDiv").slideUp(200);
$('#'+x).slideDown(300);
} else {
$('#'+x).slideUp(300);
}
}
</script>




Javascript works just fine by the way. Below is the form I have in the HTML of the code.

Code: [Select]

<form action="" method="post" enctype="multipart/form-data">

<?php echo "$list_staff"; ?>

</form>



This is of course wrapped around body tags and all the other necessary HTML. The view of the form is working right, the functions within the form are also working correctly. I just cant seem to separate the variables for each individual user. If I am in Chris Hansen's div, it should be his ID number that is being referenced for the database, not the ID number of the last person entered into the system. Any ideas? As always, thanks in advance guys!!!

Bl4ck Maj1k

i am developing online test ,after succesful completion of the test i want to display the correct answe,in databse i have stored corect answer as  radio button values(ex 1,2,3,4,) i want to display the coreect answer with a right mark,how can i achive this?could anybody help? here is my code

  <?php  $testid=$_GET['testid'];
include_once("header.php");
?>
<html>
<head>
<body>
<?php
include_once('connect.php');
$sqltest="select testname from test where testid='$testid'";
$sqltestresult=mysql_query($sqltest) or die(mysql_error());
while($result=mysql_fetch_array($sqltestresult))
{
 $testname=$result['testname'];


}




?>
<!--pass test name and time left -->
<table width="100%" cellpadding="0" cellspacing="0" border="0"><tr><td width="50%" valign="middle">
                           <h1 style="margin-left:0;"><?php 
  if(isset($testname))
  {
  
  echo $testname ;
  }
  ?></h1>
                         </td>
                         <td width="50%" align="right" valign="middle">
 <ul class="tabs" id="tabs">
                <li id="showtime" style="font-weight:bold; color:#FF0000; bottom:5px; font-size:16px; float:right"></li>
</ul>


                         </td>
                        </tr></table>
<div class="div-tabs-container" class="div-tabs-container" style="width:79%;margin-left:3%" > 
        <table cellpadding="0" cellspacing="0" border="0" id="questiontable" >
        <tr>
<?php
include_once('connect.php');
$sql="select * from testquestions where testid='$testid'";
$result=mysql_query($sql) or die(mysql_error());
if (mysql_num_rows($result)>0)
{
  $data = array(); // create a variable to hold the information
while (($row = mysql_fetch_array($result, MYSQL_ASSOC)) !== false)


{
$data[] = $row; // add the row in to the results (data) array
}
//shift off the first value
array_shift($data[0]);


$merge = call_user_func_array('array_merge', $data);


$size=sizeof($merge);
$newdata=array();
$num=1;
$correctanswerarray=array();
$selctedanswers=array();
/* echo "<form action='fetchquestion.php' method='post' id='formsubmit' onsubmit='return out()' name='test'>"; */


foreach ($merge as $key => $value ) 
{


$sql2="select qid, question,option1,option2,option3,option4,correct_answer from question where qid='$value'  ";


$result2=mysql_query($sql2) or die(mysql_error());




  while($row2=mysql_fetch_assoc($result2))
{
                  $questionid=$row2['qid'];
    $question=$row2['question'];
$option1=$row2['option1'];
$option2=$row2['option2'];
$option3=$row2['option3'];
$option4=$row2['option4'];
        $correctanswer=$row2['correct_answer'];
#array to store the correct answer.
$correctanswerarray[] = $questionid.$correctanswer; 
   #$newdata[]=$row2;






echo "


 <table class='bix-tbl-container' cellspacing='0' cellpadding='0' border='0' width='100%' id='questiontable'><tr>
                <td class='bix-td-qno jq-qno-2413'  rowspan='2' valign='top' align='left'>$num</td>
                <td class='bix-td-qtxt' valign='top'><p>$question</p></td>
            </tr>
            <tr>
                <td class='bix-td-miscell' valign='top'><table class='bix-tbl-options' id='tblOption_2413' border='0' cellpadding='0' cellspacing='0' width='100%'><tr><td nowrap='nowrap' class='bix-td-option bix-td-radio' width='1%'  id='tdOptionNo_A_2413'>


<input type='radio' class='result-option cls_2413' name='option_$questionid' value='1'  id='disable'/>
</td><td class='bix-td-option' width='1%'>A.</td>
                         <td class='bix-td-option' width='48%' id='tdOptionDt_A_2413'><table border='0' cellpadding='0' cellspacing='0'>
        <tr>                                                          
        <td class='bix-inner-td-option'>$option1</td>                                                         
        <td id='tdAnswerIMG_A_2413' class='jq-img-answer'  valign='middle'style='display:none;padding-left:10px;'>               
           <img src='/_files/images/website/accept.png' alt='' />  
        </td>                                                         
        </tr>                                                         
        </table></td></tr><tr><td nowrap='nowrap' class='bix-td-option bix-td-radio' width='1%'  id='tdOptionNo_B_2413'>


<input type='radio' class='result-option cls_2413' name='option_$questionid'  value='2' id='disabble'/>
</td><td class='bix-td-option' width='1%'>B.</td>
                         <td class='bix-td-option' width='48%'id='tdOptionDt_B_2413'><table border='0' cellpadding='0' cellspacing='0'>
        <tr>                                                          
        <td class='bix-inner-td-option'>$option2</td>                                                         
        <td id='tdAnswerIMG_B_2413' class='jq-img-answer'  valign='middle' style='display:none;padding-left:10px;'>               
           <img src='/_files/images/website/wrong.gif' alt=''/>  
        </td>                                                         
        </tr>                                                         
        </table></td></tr><tr><td nowrap='nowrap' class='bix-td-option bix-td-radio' width='1%'  id='tdOptionNo_C_2413'>


<input type='radio' class='result-option cls_2413' name='option_$questionid'  value='3' id='disable'/>
</td><td class='bix-td-option' width='1%'>C.</td>
                         <td class='bix-td-option' width='48%' id='tdOptionDt_C_2413'><table border='0' cellpadding='0' cellspacing='0'>
        <tr>                                                          
        <td class='bix-inner-td-option'>$option3</td>                                                         
        <td id='tdAnswerIMG_C_2413' class='jq-img-answer'  valign='middle' style='display:none;padding-left:10px;'>               
           <img src='/_files/images/website/wrong.gif' alt='' />  
        </td>                                                         
        </tr>                                                         
        </table></td></tr><tr><td nowrap='nowrap' class='bix-td-option bix-td-radio' width='1%'  id='tdOptionNo_D_2413'>


<input type='radio' class='result-option cls_2413' name='option_$questionid' value='4' id='disable'/>
</td><td class='bix-td-option' width='1%'>D.</td>
                         <td class='bix-td-option' width='48%' id='tdOptionDt_D_2413'><table border='0' cellpadding='0' cellspacing='0'>
        <tr>                                                          
        <td class='bix-inner-td-option'>$option4</td>                                                         
        <td id='tdAnswerIMG_D_2413' class='jq-img-answer'  valign='middle' style='display:none;padding-left:10px;'>               
           <img src='/_files/images/website/wrong.gif' alt='' />  
        </td>                                                         
        </tr>                                                         
        </table></td></tr></table>
 \n 


<input type='hidden' name='count' value='$num' id='count'>
<input type='hidden' name='queId[]' value='$questionid' id='queId'> 
                  
    
    


                </td>
            </tr>
            </table>
";










$num++;


}


} 
  
 echo " 
      </tr>
        </table>  
   "; 
#array of correct answrer 
#echo "array of correct answer<br/>";
#print_r($correctanswerarray);
#echo "size of the coreect answer array";
   $size1=sizeof($correctanswerarray);
echo "<br/>";




}
else
{
echo " no questions available for selected test";
}
?>
 </div>
 <!-- add div right side -->
 <div style="height:500px;width:150px;float:right;margin-top:-500px;border:1px solid #99CCFF">
</div>


<div style="height:30px">
</div>
<!--  add div bottom -->
<div style="height:125px;border:1px solid #99CCFF">
</div>


<?php
 include('footer.html'); 
?>


</body>
</html>

Edited by mac_gyver, 25 October 2014 - 10:05 AM.
code tags around code please

Hi all,

I've got a website for an event, each team have their details on a page which are recalled from a SQl database.

But I'm wanting to create a password input box for each team, so when they enter the correct password they are taken to a page containing forms where they can edit the team details.

Here is the page with the users details on where they anter the password: http://www.wharncliffenetwork.co.uk/wrc/entered/team.php?id=8

I'm not sure how to code it, Can an IF statement be used? Anyone got any pointers? I'f been unsuccessful in finding a tutorial or something similar.

Hope that makes sense :S Cheers.

I really like how Blob and Long blob handle pictures so I decided to try it with audio...I can get the file to upload fine but my problem using the file once its in the database...

This is kind of what I am doing.

This is my file called get_audio.php:

Code: [Select]
<?php
mysql_connect("localhost","root","") or die(mysql_error());
mysql_select_db("my_db") or die(mysql_error());

$id = addslashes($_REQUEST['id']);

$audio = mysql_query("SELECT* FROM wineAudio_tbl WHERE audio_id=$id");
$audio = mysql_fetch_assoc($audio);
$audio = $audio['audioFile'];

header("Content-type: audio/mp3");

echo $audio;

?>

When I want to use the audio I would just have a link something like this:

Code: [Select]
<a href="get_audio.php?id=12" target="_blank">Play Audio</a>

When you click on the "Play Audio" button it opens a browser mp3 player, but does not start the file..

Any ideas what I could be doing wrong ?

Hi all:

I have been going nuts trying to get this to work. I have gone through many attempts based on internet searches and examples that simply do not work.

I have files stored in my MySQL db. The files cna be of any type and are being displayed in a listed report. The files are hyperlinked and clickable, but here is the issue:

When I click on a file in:
http://development.products-and-services.ca/cms/test.php
I get:
http://development.products-and-services.ca/cms/test2.php?content=DHall_CV_webdev_eng.pdf
as a blank page result.
The objective is to get a file download alert or to see the file in the browser.

Any ideas?

Hi everyone,

This is driving me crazy. I need to reference different files located in different folder structure. For example, I have the following file structure.

/my_project/
/my_project/database/database_script.php
/my_project/index.php

1. If I want to reference /my_project/index.php from /my_project/database/database_script.php, how can I reference it ?
2. From /my_project/index.php to /my_project/database/database_script.php , it's obvious all I gotta do it include("/database/database_script.php").

I use $_SERVER('DOCUMENT_ROOT"), to solve the 1. problem. It works on my XAMPP local machine but when I uplode it onto the server, there's a problem.  The path becomes '/my_project/my_project/database/database_script.php". Is there a universal way (more like a standard way) to reference files in php so that I won't need to change every file path once I upload those onto the server ?

Regards,

I am using a script found off the web to upload file and show a ajaxy waiting image.

In the code for the actual upload is this code

$destination_path = getcwd().DIRECTORY_SEPARATOR;
$result = 0;
$target_path = $destination_path . basename( $_FILES['myfile']['name']);

if(@move_uploaded_file($_FILES['myfile']['tmp_name'], $target_path)) {
$result = 1;
}

I am running it from domain.com/label/manage/add-file/upload.php and it uploads the file to domain.com/label/manage/add-file/

How can I upload the file to domain.com/files/123/432/

Do I need to modify the destination path? Also do i need to start it from /home/user/.........

Thanks