PHP - Php Check Stored Data Help
Hey Guys,
I have got 3 chained select boxes working. Basically what you do is check for a region with the country, then once you pick a region, you select a club within that region. Once you have selected the club, you can then choose a team from within that club. Screenshot: Attchment As part of this chained select boxes's, a user can register. Although, the user has to FIRST check if the TEAM has already been registered in the database. I have taken a screenshot of my database, which shows the regions, clubs, and teams from the chained select boxes. What i want to do now is be able to check if a TEAM is already registered in the database. So as you can see in the database, the team 'NPOB, Senior As' has already been taken. Database Screenshot: Attachment *** How do i check if a user has been registered to one of the teams? And if there is not a registered user to that team, they can then register it. Here is my code: <?php include"database.php"; ?> <script type="text/javascript"> /* Triple Combo Script Credit By Philip M: http://www.codingforums.com/member.php?u=186 Visit http://javascriptkit.com for this and over 400+ other scripts */ var categories = []; categories["startList"] = ["Taranaki","Auckland"] // Regions + Clubs categories["Taranaki"] = ["NPOB","Tukapa"]; categories["Auckland"] = ["Marist","Takapuna"]; // Clubs + Teams within that Club categories["NPOB"] = ["Senior As","Senior Bs","Colts U21s"]; categories["Tukapa"] = ["Senior As","Senior Bs","Colts U21s"]; categories["Marist"] = ["Senior As","Senior Bs","Colts U21s"]; categories["Takapuna"] = ["Senior As","Senior Bs","Colts U21s"]; var nLists = 3; // number of select lists in the set function fillSelect(currCat,currList){ var step = Number(currList.name.replace(/\D/g,"")); for (i=step; i<nLists+1; i++) { document.forms['tripleplay']['List'+i].length = 1; document.forms['tripleplay']['List'+i].selectedIndex = 0; } var nCat = categories[currCat]; for (each in nCat) { var nOption = document.createElement('option'); var nData = document.createTextNode(nCat[each]); nOption.setAttribute('value',nCat[each]); nOption.appendChild(nData); currList.appendChild(nOption); } } // function getValue(L3, L2, L1) { // alert("Your selection was:- \n" + L1 + "\n" + L2 + "\n" + L3); // } function init() { fillSelect('startList',document.forms['tripleplay']['List1']) } navigator.appName == "Microsoft Internet Explorer" ? attachEvent('onload', init, false) : addEventListener('load', init, false); </script> <form name="tripleplay" action="testingdropdown.php" method="post"> <select name='List1' onchange="fillSelect(this.value,this.form['List2'])"> <option selected>Choose Region</option> </select><br /><br /> <select name='List2' onchange="fillSelect(this.value,this.form['List3'])"> <option selected>Choose Club </option> </select><br /><br /> <select name='List3' onchange="getValue(this.value, this.form['List2'].value, this.form['List1'].value)"> <option selected >Choose Team </option> </select> <input type="submit" name="tripleplay" value="Register"> </form> <?php if (isset($_POST['tripleplay'])) { $region = addslashes(strip_tags($_POST['List1'])); $club = addslashes(strip_tags($_POST['List2'])); $team = addslashes(strip_tags($_POST['List3'])); $email = 'email'; $check = mysql_query("SELECT * FROM managers WHERE email='$email'"); if ($email == '') { echo "You can register that club"; } else { echo "Sorry that team has already been registered"; } } ?> Similar TutorialsHi all, I've got a website for an event, each team have their details on a page which are recalled from a SQl database. But I'm wanting to create a password input box for each team, so when they enter the correct password they are taken to a page containing forms where they can edit the team details. Here is the page with the users details on where they anter the password: http://www.wharncliffenetwork.co.uk/wrc/entered/team.php?id=8 I'm not sure how to code it, Can an IF statement be used? Anyone got any pointers? I'f been unsuccessful in finding a tutorial or something similar. Hope that makes sense :S Cheers. Often times I need to convert between PHP Arrays, MySQL, XML, JSON sqlite etc. Lately I've been just building PHP arrays with all the data. Its a big hassle though when theres a lot of data. I'm thinking I should have one central location that I store data in, then export to other formats from there, but I dont know what that central location should be. I like MySQL because I'm used to it. Sometimes its not an option though, like if I need to make a really light script, I dont want the hassle of connecting to MySQL. Would XML be the best place to store data, then from the XML file I can convert it to whatever format I want?
hey guys i have this code FILE NAME "index.php" Code: [Select] <?php // make a connection to the database mysql_connect ("localhost", "root", "vertrigo") or die ('Error: I Failed To Connect To The Database ' . mysql_error()); mysql_select_db ("test"); // Get Data $query = mysql_query("SELECT * FROM TestTable"); // display the data and loop while ($row = mysql_fetch_array($query)) { echo "<br /> ID: ".$row['ID']."<br /> First Name: ".$row['FName']."<br /> Last Name: ".$row['LName']."<br /> Contact Number: ".$row['CNumber']."<br />";} ?> <form method="post" action="update.php"> <table border="1" align="center"> <tr> <td align="right" width="220">ID: </td> <td align="left" width="220"> <input type="text" name="ID" size="30" /></td> </tr> <tr> <td align="right" width="220">First Name: </td> <td align="left" width="220"> <input type="text" name="FName" size="30" /></td> </tr> <tr> <td align="right" width="220">Last Name: </td> <td align="left" width="220"> <input type="text" name="LName" size="30" /></td> </tr> <tr> <td align="right" width="220">Contact Number: </td> <td align="left" width="220"> <input type="text" name="CNumber" size="30" /></td> </tr> <tr> <td align="right" width="220"><input type="reset" value="Reset" /> </td> <td align="left" width="220"> <input type="submit" value="Update Database" /></td> </tr> </table> </form> and i also have this code FILE NAME "update.php" Code: [Select] <?php $ID = $_POST['ID']; $FName = $_POST['FName']; $LName = $_POST['LName']; $CNumber = $_POST['CNumber']; mysql_connect ("localhost", "root", "vertrigo") or die ('Error: I Failed To Connect To The Database ' . mysql_error()); mysql_select_db ("test"); $query="INSERT INTO testtable (ID, FName, LName, CNumber)VALUES ('".$ID."','".$FName."', '".$LName."', '".$CNumber."')"; mysql_query($query) or die ('Error Updating Database'); echo "Database Updated Sucsessfully With: ".$ID." ".$FName." ".$LName." ".$CNumber ; ?> ok so the script is working like a charm its sending the data to the database as i want it to. the problem i have is that i want to be able to update the info that is already on the database lets say i want to change a phone/contact number i have typed the ID number into the ID text field and the same first and last name into there correct boxes and then typed in the new phone number i then click submit and i get the error ""Error Updating Database"" i have looked all over the forum and net to see what i have done wrong to not allow this code to update can anyone help me out here please im quite new to the php language and could really do with some pointers thanks Steve sorry if i have posted this in the wrong place, wasnt sure wether to post here or mysql. I have made a php calendar, and i am now wanting it to show if there is an event on that day and if so show it in a tool tip. the tool tip is populated by what is in the title="" of the link so i need my events to be shown in there. I have figured out how to show the event but now i am stuck on how to show all events if there is more than one one that day, how i have set it seems to only the second event, probably as the second variable overwrote the first variable. this is the code i have at the minute .............. $result = mysql_query("SELECT * FROM events WHERE day='$day_num' AND month='$fullmonth' AND year='$year'") or die(mysql_error()); $rows= mysql_num_rows($result); if ($rows !="false"){ while($rowout = mysql_fetch_array($result)) { $todayis = $rowout['day'] ."-". $rowout['month'] ."-". $rowout['year'] ."<br>"; $title= $rowout['event'] ."<br><br>";} $firstl = "<a href='' title='". $todayis . $title ."'>"; $lastl = "</a>";} else {$firstl = ""; $lastl = "";} then to display the day and links ................. Code: [Select] <td><? echo $firstl; ?><? print $day_num; ?><? echo $lastl; ?></td> could some one be so kind and help me write it so that it displays all events? here is a link to the calendar, incase its needed. http://www.scripttesting.htmlstig.com/calendar/index.php Many thanks Carl i want the name of a picture stored in my db after i upload it the data is not stored in the db after i run this script, but i dont get errors either i print the two vars before sending them, and they get printed fine any help on this would be greatly appreciated thanks ! <?php error_reporting(E_ALL); ini_set("display_errors", 1); // INCLUDE THE CLASS FILE include('ImageLib.Class.php'); include("./includes/egl_inc.php"); $displayMessage = ''; if($_POST){ if(isset($_FILES['image_file'])){ // SEE THE MAGIC HAPPEN $destination_path = 'uploads/'; $post_file_name = 'image_file'; $width = 600; $height = 400; $scale = false; $trim = true; $uniqueName = true; $img = ImageLib::getInstance()->upload($post_file_name, $destination_path, $uniqueName)->resize($width, $height, $scale, $trim)->save(); $imgstr = mysql_real_escape_string ($img); $fileName = $_FILES['image_file']['name']; $displayMessage = '<div class="image"><img src="'.$destination_path.$fileName.'" /><br />Uploaded And Resized...With new file name : "'.$img.'"</div><br /><br />'; $playerid=$_SESSION['tid']; $matchdetails = mysql_fetch_array(mysql_query("SELECT id FROM ffa_matches WHERE status=2 and admin=$playerid")); $id = $matchdetails[id]; print $img;print $imgstr; print $id; mysql_query(" INSERT INTO ffa_screens (imgname,match) VALUES( '" . mysql_real_escape_string($imgstr) . "', '" . mysql_real_escape_string($id) . "' )"); }} ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html> <head> <title>ImageLib Samples By Rahul Kate</title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <style> body{font-family: arial; font-size:12px; color:#444444; padding:20px;} li{margin-top:10px;} .image{color:green;} .image img{margin-bottom:5px;} </style> </head> <body> <h1>ImageLib | Upload Image, move it to Uploads folder and Resize it and Trim</h1> <?php echo $displayMessage; ?> <form method="post" enctype="multipart/form-data"> Select Image<br /> <input type="file" name="image_file" id="image_file" /> <br /> <br /> <input type="submit" name="submit" value="Submit" /> <br /> <br /> <a href="index.html">Back TO Home</a> </form> </body> </html> I have stored supplier information in a table and same form user will select multiple products for that supplier and that will be stored in a seperate table against that supplier id. Now when i would like to display all supplier information with muliple products in a single line. Now all the information will be displayed as many time as the products are. How to display all the products in a same line.
Now my display is like this
if(isset($_POST['submit']) && ($_POST['vendor']!='') && ($_POST['item']!='')) { $sql="SELECT supplier.id AS sid, supplier.name AS SNAME, supplier.category, supplier.website, supplier.email, supplier.phone, supplier.vat, supplier.pan, supplier_location.id, supplier_location.supplier_id, supplier_location.location, supplier_products.id, supplier_products.supplier_id, supplier_products.product_id, location.loc_id, location.name AS locname, products.product_id, products.name AS pname FROM supplier INNER JOIN supplier_location ON supplier.id = supplier_location.supplier_id INNER JOIN supplier_products ON supplier.id=supplier_products.supplier_id INNER JOIN location ON supplier_location.location = location.loc_id INNER JOIN products ON supplier_products.product_id=products.product_id WHERE supplier.id=".$sup." AND supplier_products.product_id=".$product; $sql1 = mysql_query($sql) or die(mysql_error()); <table> <thead><tr> <th>Vendor ID</th> <th>Vendor</th> <th>Category</th> <th>Website</th> <th>Email</th> <th>Phone</th> <th>Products</th> <th>Locations</th> <th>VAT</th> <th>PAN</th> </tr> </thead> <tbody> <tr> <?php while($row = mysql_fetch_array($sql1)) { ?> <td><?php echo $row['sid'] ?></td> <td><?php echo $row['SNAME'] ?></td> <td><?php echo $row['category'] ?></td> <td><?php echo $row['website'] ?></td> <td><?php echo $row['email'] ?></td> <td><?php echo $row['phone'] ?></td> <td><?php echo $row['iname']; ?></td> <td><?php echo $row['locname']; ?></td> <td><?php echo $row['vat'] ?></td> <td><?php echo $row['pan'] ?></td> </tr> <?php } ?> </tbody></table> } Hey Folks! So, my brain is hurting now... I am making a little process to go through a table and if a row as one set of data, and the next row as the same data based on 3 fields then update a field in the current row. Here is a snippet of what I have been working on: <?php date_default_timezone_set('AUSTRALIA/BRISBANE'); $lasthour = (time() - 3600); $lastattack45 = (time() - 2820); $lasthalfhour = (time() - 1800); $lastfifteen = (time() - 900); $lastfhourhalf = (time() - 5400); $next15 = (time() + 900); $now = time(); mysql_connect($mysql_host, $mysql_user, $mysql_password) or die('Error connecting to mysql'); mysql_select_db($mysql_database); $result = mysql_query("SELECT feeder, attacker, defender, attacklandunix, smurfid, smurf, unixtime, record, leader FROM nation_incoming WHERE attacklandunix > $now && smurf <> 'smurfed' ") or die("SELECT Error: ".mysql_error()); while($row = mysql_fetch_array($result)){ $a[][feeder] = $row['feeder']; $a[][defender]= $row['defender']; $a[][landing]= $row['attacklandunix']; } foreach($a as $b){ //in here it is to compare the 'feeder' && 'defender' && 'attacklandunix' to the next row. IF the same combo exists, then update field 'leader' to "0". else update 'leader' to "1" } ?> How can/should I pull up the next row? Hi Guys, Im using the code below to display the value of checked checkboxes on form submission, however im also trying to pull the price from the database for each checked value. foreach ($_POST['check'] as $product) { echo $row['price'] . " " . $row['currency'] . " for " . $product . "<br />"; } Please could somebody point me in the right direction as to what id need to do. As iv only been able to get it to display the price of the first checked value. Thanks I have two questions regarding $byte_array. 1. Is there a general way to check if a $byte_array contains any data? 2. Is there a way to confirm if the $byte_array contains an actual PNG image? Hi guys, I'm recent working on my php to add the row in mysql database. I need a bit of your help as I would like to know how to check the data in mysql database if it have added in mysql and then print it out without adding another same row? here's the current code: Code: [Select] <?php session_start(); define('DB_HOST', 'localhost'); define('DB_USER', 'mydbuser'); define('DB_PASSWORD', 'mydbpass'); define('DB_DATABASE', 'mydbname'); $errmsg_arr = array(); $errflag = false; $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } function clean($var){ return mysql_real_escape_string(strip_tags($var)); } $username = clean($_GET['user']); $pass = clean($_GET['pass']); $login = clean($_GET['login']); $all = clean($_GET['all']); if($username == '' && $pass == ''){ // both are empty $errmsg_arr[] = 'Username and password are missing. You must enter both or the other one.'; $errflag = true; } if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; echo implode('<br />',$errmsg_arr); } else { $insert = array(); if(isset($_GET['user'])) { $insert[] = 'username = \'' . clean($_GET['user']) .'\''; } if(isset($_GET['pass'])) { $insert[] = 'pass = \'' . clean($_GET['pass']) . '\''; } if(isset($_GET['login'])) { $insert[] = 'LoggedUser = \'' . clean($_GET['login']) . '\''; } if(isset($_GET['all'])) { $insert[] = 'all = \'' . clean($_GET['all']) . '\''; } if (count($insert)>0) { $names = implode(',',$insert); if($username) { $qrytable1="SELECT username, LoggedUser FROM Online_Users WHERE username='$username'"; $result1=mysql_query($qrytable1) or die('Error:<br />' . $qry . '<br />' . mysql_error()); while ($row = mysql_fetch_array($result1)) { echo "<p id='LoggedUser'>"; echo $row['LoggedUser'] . "</p>"; } } if($username && $login == '1') { $sql="INSERT INTO Online_Users (username, LoggedUser) VALUES ('$_GET[user]','$_GET[login]')"; $result = mysql_query($sql); if($result) { $qrytable1="SELECT username, LoggedUser FROM Online_Users WHERE username='$username'"; $result1=mysql_query($qrytable1) or die('Error:<br />' . $qry . '<br />' . mysql_error()); while ($row = mysql_fetch_array($result1)) { echo "<p id='LoggedUser'>"; echo $row['LoggedUser'] . "</p>"; } } } elseif($username == 'all') { $names = implode(',',$insert); $result = mysql_query("SELECT * FROM Online_Users") or die('Error: ' . mysql_error()); $num_rows = mysql_num_rows($result); echo "There are $num_rows Users Online right now"; } } } ?> hi guys, in my form i need to insert an ID which is 5 digits number only. can anyone please tell me how can i check this before i insert? and also i need to check existing ID in my database. wrote a stored procedure this morning and i don’t know how to get the values out of it through a class function in php or phpmyadmin. here is what i wrote : public function totalProcedures($friend_name,$session_id) { /* *query to fetch stored procedure */ try { //executing the stored procedure $sql_sp="CALL timeline (:friend, :session,@updates, @group_posts)"; $stmt_sp= $this->_db->prepare($sql_sp); $stmt_sp->bindValue(":friend",$friend_name); $stmt_sp->bindValue(":session",$session_id); $stmt_sp->execute(); $rows=$stmt_sp->fetch(PDO::FETCH_ASSOC); $stmt_sp->closeCursor(); // closing the stored procedure //trying to get values from OUT parameters. $stmt_sp_2=$this->_db->prepare("select @updates,@group_posts"); $stmt_sp_2->execute(); return $stmt_sp_2->fetch(PDO::FETCH_ASSOC); } catch (PDOException $ei) { echo $ei->getMessage(); } } can someone helpme how to get results. here is the storedprocedu DELIMITER $$ CREATE DEFINER=`root`@`localhost` PROCEDURE `timeline`(IN `friend` VARCHAR(255), IN `session_id` VARCHAR(255), OUT `updates` VARCHAR(62555), OUT `group_posts` VARCHAR(62555)) BEGIN select * FROM updates where author in (friend,session_id) order by time desc limit 5; select * FROM group_posts where author_gp in (friend,session_id) order by pdate desc limit 5; END$$ DELIMITER ; i get the result in php myadmin as follows:
how do i do this inside a php class function. CALL timeline('shan2batman','aboutthecreator', @updates, @group_posts);
Hi, I have multiple table Table -1 order_no name 1 raj table -2 order_no name 1 raj table 3 order_no name 1 raj table 4 order_no name 1 raj table 5 order_no name 1 raj I want a query to check if the id (one) is present in all tables or not, i create this. select order_no from prepress, press, postpress, qc, binding, dispatch where order_no=prepress.order_no AND order_no=press.order_no AND order_no=postpress.order_no AND order_no=qc.order_no AND order_no=binding.order_no AND order_no=dispatch.order_no but the ambiguous error for order_no. how to achieve this can anyone suggest me? thanks Hello. I want to check if an e-mail address is stored into a database. I've found this type of code: Code: [Select] function verifmail($email) { db_connect(); if (mysql_num_rows(mysql_query("SELECT email FROM users WHERE email='$email';"))) { return 1; } else { return 0; } } Is it correct ? Is there any other way? hi all, I have an array(1,2,3,4) and i make a form and make checkboxes for this array and user selects 2,3 and 4 when user submit form then i save it in table by making selected check boxes and converting selected values into bitwise equivalent value like this foreach($data['meal_types'] as $v){ $mealTypeBits += pow(2,$v-1); } Now when i have to show user his selected data how will i compare table bitwise saved record with array(1,2,3,4) to get the values that he checked while saving. Hi guys, im inserting data into the table using drop-down list & multi select list,well it works very well. but i need to make sure i should not insert same StudentID & CourseID twice. here my code for you could anyone tell me pls where should i write code to check existing data? <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("uni", $con)or trigger_error('MySQL error: ' . mysql_error()); $result = mysql_query("SELECT * FROM student") or trigger_error('MySQL error: ' . mysql_error()); echo '<select name="sid">'; while($row = mysql_fetch_array($result)) { echo '<option value="' . $row['StudentID'] . '">' . $row['StudentName'] . '</option>'; } echo '</select>'; // ---------------- ?> </div> <div class="style41" id="Layer7"> <?php $result = mysql_query("SELECT * FROM course") or trigger_error('MySQL error: ' . mysql_error()); echo '<select name ="cid[]" multiple="multiple" size="10">'; while($row = mysql_fetch_array($result)) { echo '<option value="' . $row['CourseID'] . '">' . $row['CourseName'] . '</option>'; } echo '</select>'; mysql_close($con); ?> ------------------------------------ <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("uni", $con)or trigger_error('MySQL error: ' . mysql_error()); if (!empty($_POST['sid']) && !empty($_POST['cid'])) { $ct = 0; $student = $_POST['sid']; foreach ($_POST['cid'] as $key => $course) { $sql = "INSERT INTO take (StudentID, CourseID) VALUES('".mysql_real_escape_string($student)."', '".mysql_real_escape_string($course)."')"; $query = mysql_query($sql) or trigger_error('MySQL error: ' . mysql_error()); if (mysql_affected_rows() > 0){$ct++;} } echo $ct . ' rows added.'; } mysql_close($con); ?> //database create table mydata ( id int(11) NOT NULL PRIMARY KEY AUTO_INCREMENT, fname varchar(20), phoneno int(12) NOT NULL /*......*/ ); //class my data php <?php include('connect.php'); class InsertMydata { public function insertnow($fname, $phoneno) { $connect = new Connect; $insrt = $db -> prepare('INSERT INTO mydata (fname, phoneno) VALUES (?,?)'); $insrt -> execute(array($fname, $phoneno)); } } ?> //insernow validate form <?php include('../classs/mydata.php'); //Declare data and error arrays $errors = []; $mydara = []; if(!preg_match('/^[a-zA-Z]{4,15}$/', $_POST['fname'])) { $errors['fname'] = 'Enter full name!'; } //this block not working even the phone exist $connect = new Connect; $phoneno = $_POST['phoneno']; $checkiexist = $connect -> prepare('SELECT * FROM mydata WHERE phoneno = ?'); $checkiexist -> execute([$phoneno]); if($checkiexist->rowCount() > 0) { $errors['phonenoexist'] = 'Try another phone number!'; } if(!empty($errors)){ $data['success'] = false; $data['errors'] = $errors; }else{ $data['success'] = true; $data['message'] = 'success message!'; $mydata = new InsertMydata; $mydata -> insertnow($fname, $phoneno); } echo json_encode($data); ?> //my ajax $("#insertbtn").click( function(e) { var fname = $('#fname').val(), phoneno = $('#phoneno').val(), $.ajax({ url: 'insertnow.php', type: 'POST', data: {fname:fname, phoneno:phoneno}, dataType: "JSON", encode: true, }).done( function (data) { if (data.success == false) { if (data.errors.fname) { $('#fname').append('<p class="text-danger">' + data.errors.fname + '</p>'); } if (data.errors.phonenoexist) { $('.card-header').append('<div class="alert alert-info alert-dismissible" role="alert"> <button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">×</span></button>'+data.errors.phonenoexist+'</div>'); } } else { $('.card-header').append('<div class="alert alert-success alert-dismissible" role="alert"><button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">×</span></button>'+data.message+'</div>'); } }); e.preventDefault(); }); //the problem is, the code insert data even if the phone exist why? the problem is, the code insert data even if the phone exist why? Edited April 8 by mahendaHi guys Can someone help me about this: The php code can be revise username and password with CURL then check database and if username & password is correct return true else false. Thanks Hey! I have it so users can submit info to my site. They have to check some check boxes and radio buttons. I want them to be able to edit this information, so I want to have the data pulled from the MySQL database and have the correct radio button selected (and the text bolded). So I'm thinking some sort of array to check for each value in the database... but I don't really know. There are a few groups of radio boxes and check boxes but here is an example of one. Code: [Select] <input type="radio" name="stage" value="Stage 1" /> Stage 1 <input type="radio" name="stage" value="Stage 2" /> Stage 2 <input type="radio" name="stage" value="Stage 3" /> Stage 3 The information is pulled from the database like this: Code: [Select] $res=mysql_query("SELECT * FROM ACTIVE WHERE INDEX_ID=$id"); if(mysql_num_rows($res)==0) echo "There is no data in the table <br /> <br />"; else { for($i=0;$i<mysql_num_rows($res);$i++) { $row=mysql_fetch_assoc($res); } } So when I pull information (lets say I want to echo it) it'd look like this: Code: [Select] $row[STAGE] The value for the stage selection can only be Stage 1, Stage 2 or Stage 3 so I need it to be selected when the page loads. Thanks! Ok this is puzzleing. I am geting "Could not delete data: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1". but its is deleting the entry that needs to be removed. The "1" is the entry. Just not sure what is causing the error. I do have another delete php but I have put that on the back burning for the time being.
<?php $con = mysqli_connect("localhost","user","password","part_inventory"); // Check connection if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); exit(); } else { $result = mysqli_query($con, "SELECT * FROM amp20 "); $amp20ptid = $_POST['amp20ptid']; // escape variables for security $amp20ptid = mysqli_real_escape_string($con, $_POST['amp20ptid']); mysqli_query($con, "DELETE FROM amp20 WHERE amp20ptid = '$amp20ptid'"); if (!mysqli_query($con, $amp20ptid)); { die('Could not delete data: ' . mysqli_error($con)); } echo "Part has been deleted to the database!!!\n"; mysqli_close($con); } ?> |