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PHP - Using Absolute Pathing For Website Images.
Hey,
Im wondering how I go about creating a directory path to an image folder that can be opened from any folder inside my root web directory www/WEBROOT/IMAGES/SHOP/image.jpg When i add an absolute path to the images url in the database when its gets executed it will run the the path from the current folder. I was wondering how to make its always start looking for files from the root directory down instead of the current location. The reason im asking this is that i was to be able to open those images from seperate locations inside my website. Thanks Similar TutorialsI am using shared hosting at HostGator. I am trying to execute flare (a command line actionscript decompiler) via PHP. According to phpinfo() my System is Linux gator1854.hostgator.com 3.2.13 #4 SMP Thu Mar 29 19:22:42 CDT 2012 x86_64 In my public_html, I have a folder named "zachafer" and inside that folder, I have a folder named "flare". Inside the flare folder, I have the flare command line version, named "flare" and a file named movie.swf. The flare website says that I need to run "./flare somepath/somename.swf" Here is my code: <?PHP error_reporting(-1); $swf = 'movie'; chdir("/home/infamous/public_html/zachafer/flare"); $cmd = "./flare $swf.swf"; shell_exec($cmd); echo "Cmd: $cmd\n"; echo "File: ".file_get_contents("$swf.flr"); ?> Thank you. I'm working on an email template system where my client will go to a page and copy & paste the source code into their crm system. I'm trying to find a way to automatically replace the image path without the use of echo if possible. I've figured this out already with this script: Code: [Select] <? function GetFileDir($php_self){ $filename = explode("/", $php_self); // THIS WILL BREAK DOWN THE PATH INTO AN ARRAY for( $i = 0; $i < (count($filename) - 1); ++$i ) { $filename2 .= $filename[$i].'/'; } return $filename2; } ?> But I don't wanna have to go in and put Code: [Select] <?php echo GetFileDir("http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']); ?> before all the image paths. So basically anywhere that src="images/whatever.jpg" is listed it will replace "images/" with "http://www.mydomain.com/images/whatever.jpg" is it possible to do this without having to place code before "images" ? Hey y'all. Probably a dumb question here but I'm at a loss. I've got a PHP service script that has an include, written as so:
$config = new Config('config/config.json');
The config directory is next to the PHP script and does contain the config.json file, so when I run this from the CLI everything works great. However, I've got about 17 PHP services I need to start and really don't feel like typing them all out, so I've written a shell script that does this: #!bin/bash cd /path/to/my/script /usr/local/bin/php ./my-script.php This does start the service, but it bombs out because it can't find the config.json file. If I change the PHP to
$config = new Config('./config/config.json');
it works as expected from the shell script. Updating the files is technically possible, but fraught right now for reasons I can't really get into (sorry). Anybody know what the difference is, or have any ideas on how to get around this? Edited September 5, 2020 by maxxdHi, I have a php code that is used to find all the images in a website using simple_html_dom. When I tried to run it, this error occured:
Fatal error: Call to a member function find() on a non-object in C:\xampp\htdocs\myPHP\index.php on line 20
This is my code:
<!DOCTYPE html>
<html>
<body>
<?php
include_once("simple_html_dom.php");
//use curl to get html content
function getHTML($url,$timeout)
{
$ch = curl_init($url); // initialize curl with given url
curl_setopt($ch, CURLOPT_USERAGENT, $_SERVER["HTTP_USER_AGENT"]); // set useragent
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); // write the response to a variable
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true); // follow redirects if any
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout); // max. seconds to execute
curl_setopt($ch, CURLOPT_FAILONERROR, 1); // stop when it encounters an error
return @curl_exec($ch);
}
$html=getHTML("http://www.website.com",10);
// Find all images on webpage
foreach($html->find("img") as $element)
echo $element->src . '<br>';
?>
</body>
</html>
I have the simple_html_dom.php file in my directory. How can I correct this? thanks
Edited by Raex, 20 August 2014 - 09:05 PM. I'm trying to make a League of Legends (a video game) community website, both as a personal project and for practice. Now the game has a lot of champions, each of whom have 5 unique abilities. Now, I thought about manually inputting all the details about each champion into a MySQL database, but that would long and tedious, and I don't really have the time for it now. Also, the game patches very oftern (like, once every 2 weeks) which changes many of the stats, etc. of the champion, and it is not possible for me to keep manually updating these every time there is a patch. Fortunately, there is a League of Legends Wiki which has all the data I need in their specific champion pages, which they keep updated per patch. So I was wondering if there was any way to get the data from the divs in the wiki, and have it display on my site. What I want to do in my website is that whenever someone types a champion's name (in a post or whatever), I want it to display a hover-over dialog with some of the champions details. And a lot of other features such as that. In plain English I need a way to : > Tell PHP to go to the wiki's source code on a specific page > Find a specific div container > Get X data from there > Pass X data into a function to display the hover-over I think this way, I would not have to maintain a database as I can leech off the wiki's data. I have not coded anything like this before, so I would like a few pointers as to how to achieve this. Any help will be appreciated! hello My database is in a same server with seperate domain name , then I want to insert from website1 mysql data on website2 mysql data. can anyone help me? I tried searching on google but couldn't find any relevant information, please redirect me to relevant source or help me with the code. I want to pass a domain name in text field which will be scanned and then the script will display entire site map. Not external links or links on a page. Sorry it is not easy for me to explain. Eg. if i pass abc.com Script will display abc.com/12/adn.php abc.com/asd/asd/ etc Whatever their url format is. All the links on that domain. I have this script from http://lampload.com/...,view.download/ (I am not using a database) I can upload images fine, I can view files, but I want to delete them. When I press the delete button, nothing happens
http://www.jayg.co.u...oad_gallery.php
<form>
<?php $dir = dirname(__FILENAME__)."/images/gallery" ; $files1 = scandir($dir); foreach($files1 as $file){ if(strlen($file) >=3){ $foil = strstr($file, 'jpg'); // As of PHP 5.3.0 $foil = $file; $pos = strpos($file, 'css'); if ($foil==true){ echo '<input type="checkbox" name="filenames[]" value="'.$foil.'" />'; echo "<img width='130' height='38' src='images/gallery/$file' /><br/>"; // for live host //echo "<img width='130' height='38' src='/ABOOK/SORTING/gallery-dynamic/images/gallery/ $file' /><br/>"; } } }?> <input type="submit" name="mysubmit2" value="Delete"> </form>
any ideas please?
thanks
I'm really sorry if this has been answered (I assume it has) I'm unfamiliar with search terms of what I am trying to do. I have this web page Code: [Select] <html> <body> <?php $con = mysql_connect("localhost","user","pass"); if (!$con) { echo "Fail"; die('Could not connect: ' . mysql_error()); } echo "Triumph"; ?> </body> </html> Which I got from a snippet. I load the webpage expecting to see fail or triumph, but I see nothing. My question is how to run the php script so I see something on the page (hopefully triumph. I apoligise for my noobness, I'm a PHP know nothing at the moment. What this parameter 'absolute' in DateTime::diff does? I have done some tests but i cant percept what is different when i set this parameter 'true'. Can you explain to me?! Thanks a lot. Best regards. For the includes I use the following:
include($_SERVER['DOCUMENT_ROOT'] . "/cms/includes/connection.php");And for these following examples I use "http://localhost/": <img class="header_image" src="http://localhost/cms/assets/image/capture.png" /> <script type="text/javascript" src="http://localhost/cms/jquery/jquery.js"></script> <link rel="stylesheet" type="text/css" href="http://localhost/cms/assets/style.css" />With these examples I use "http://localhost/" because "$_SERVER['DOCUMENT_ROOT']" is not working with these above. My Question: Is there a function I could be using and replace it with "http://localhost/"? I am looking to have it like following: When I upload the web app onto the web server it still should be working out. EDIT: "Un-linking" those links which happen did not work. Edited by glassfish, 29 October 2014 - 06:46 AM. Hope this goes here. I run php5 apache 2.2 with mysql4 on my local machine I prefer relative addresses. Can someone help with the correct syntax to call... say.. the Home page (index.php) in the root directory with something like <a href="../" (../ takes me back too far) when called internally At the moment I have to stipulate eg. <a href=index.php> etc Cheers Brian Hi, I'm sorry if this has already been posted, a search of the forum didn't turn anything up so i'll ask away. I'm trying to fetch urls from a document on my server and convert them into absolute urls. I can extract them but some of my links use ../ or ./. I think i've solved the ./ one but I can't find anything on getting the url when ../ is used. As an example some urls use ../index.php when in a directory so http://www.example.com/dir/test.php, so a url of ../index.php from here would land the user on http://www.example.com/index.php. At the moment it's landing on http://www.example.com/../index.php. Any ideas? Help would be appreciated I am trying to load an xml file but I can't seem to find the location to load it. Here is the location of the xml file: C:\inetpub\wwwroot\php\webphp.xml Here is the location of the file trying to load the xml: C:\inetpub\wwwroot\php\gui\guiindex.php What location would I put in he $xml = new SimpleXMLElement("XMLFILELOCATION", NULL, true); Because I have include files in a subdirectory called "incl", I cannot rely on using relative paths because that include file is in a header on and the pages are in multiple subdirectories (or in the root). I need some way to get the location of the root (the one where my index file is located). I want to use something like this: $path= $_SERVER['DOCUMENT_ROOT']; include $path."/subdirectory/file.php"; However, when I use $_SERVER['DOCUMENT_ROOT'] I get : /home/content/j/p/f/name55/html/ which is not where the index file sits. Any ideas on how to get the directory where my index file sits? (i.e. the index that gets read when you got to www.domain.com) This topic has been moved to CSS Help. http://www.phpfreaks.com/forums/index.php?topic=345942.0 In the file "secure/checkout.php" I have... Code: [Select] <?php require_once "../config.inc.php"; ?> which is Relative. Can I use an Absolute Path instead?? Debbie I found one post that related to this topic but I want to make sure I understand. If I have a site with the structu /root/ ____pageone.php ____common/ ___________base.php ___________header.php ____inc/ ______constants.inc.php ____admin/ _________login.php and base.php includes: <?php // Include site constants include_once "../inc/constants.inc.php"; ?> and login.php includes: <?php include_once "../common/base.php"; $pageTitle = "Log in"; include_once "../common/header.php"; ?> and pageone.php includes: Code: [Select] <?php include_once "common/base.php"; $pageTitle = "Page One"; include_once "common/header.php"; ?>the login page loads normally, but pageone.php is broken; I get error messages like Quote Warning: include_once(../inc/constants.inc.php) [function.include-once]: failed to open stream: No such file or directory in /Applications/XAMPP/xamppfiles/htdocs/rootdirectory/common/base.php on line 10 . From what I understand, PHP doesn't want to include the same files from different relative paths; you either need to use absolute paths or change the directory structure so that the included files are accessed through the exact same relative path. Is this correct? I find that if I move pageone.php to the admin folder and make the relative path the same, it does work. I have to say, I'm leery of using absolute paths; and if I'm understanding this correctly, you're really constrained on how you set up your directory structure. Comments? due to mod_rewrite flaws, i have to give everything an absolute path. somehow though, the stylesheet's absolute path wont work. heres the code: <link href="C:/xampp/htdocs/lso/style.css" rel="stylesheet" type="text/css" /> the stylesheet is in the lso folder, yet somehow this wont work and no styles are loaded! |
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