PHP - Replacing Variable In Function

i want to use a variable that is created inside of a function in another function
some thing like this

function show_category ($cats, $index, $level)
{
global $categories_use_categories_top_only;
$categories_use_categories_top_only='no';
.
.
$catRow = '<tr class="scPL-' . $level . '">' . "\n" . '<th colspan="' . PL_COLCOUNT . '">' . $cats[$index]['categories_name'].'<br><i>'. $categories_use_categories_top_only . '</i><br><i>'. $cat_top . '</i></th>' . "\n" . '</tr>' . "\n";
    return $catRow;
}
function show_product ($cats, $cat_index, $prod_index)
{
global $categories_use_categories_top_only;
.
.
  if ($categories_use_categories_top_only=='no' )  { 
     include(DIR_WS_MODULES . 'options.php');
}
.
.


i want to use $categories_use_categories_top_only which its value determined in the first function in the second function as i showed. the first function acts correctly
how can i do this?

Hello

I have a question (that i think i know the answer to).

What would be more efficient:

1. Create a global variable and run a php function and store result in there and call back the variable when needed

2. just echo the return value of the function when needed

Now im guessing that calling the function once and storing that in a variable rather than keep calling the function is more efficient

I have just started using functions, and have been following a few tutorials. I think im misunderstanding returns.

lets say i have the variables called $math1 an $math2

and i want to make $total = $math1 + $math2;

i then use return $total;

I then thought i could echo $total and it would work outside of the function but its giving me an error of an underfines variable.

Could anyone explain what im doing wrong please? thanks

Hi,

I'm having an image upload function I did create for few weeks ago - it has an variable called $newname, which contains the path and file.

I'm then using the imageupload() function in another function called EditFrontPage(), which is used to 'update' some content.

If I update the image, it runs the imageupload function, which is great, it resize and optimize the image, and it moves it to the folder I specified.

What I then want, is within' my EditFrontPage() function, is to echo out the $newname variable from the imageUpload function.

is there a way to do this? in a smart way?

If my code is needed, you can take a look at it he http://codepad.org/poKNSU5H

Thank you a lot guys!

Help I am trying to pass a php variable into a javasript function. Here is my code.

<a href="<?php echo $row['track']; ?>" download="<?php echo $row['track']; ?>" onclick="myhit(<?php echo $row['track']; ?>)">Download</a>

<script>
function myhit(top){
alert(top);

}
</script>

the javascript function is never called

Hi,

Im trying to pass a variable ($in_this_instance) into, and then back out of a function.  The variable goes into the function no problem, and is echo'ed out fine.  However the echo after the close of the function, does not give anything out. 

Code: [Select]
$in_this_instance = 'boo';

function in_this_instance($data) {
global $in_this_instance;

echo $in_this_instance;

$in_this_instance = 'hoo';


$rep_val = '[front banner]';

    $test = strpos($data, $rep_val);
    if ($test === false) {
return $data;
    } else {
    return $data;;
    }
}

add_filter('the_content', 'in_this_instance');
echo $in_this_instance;

Could any one give me a pointer please?  Many Thanks!

Hi All,

I have a function that i want to pass a variable into so that i can do some SQL on it.

The information that i want to pass into it is a data-id on a button that is used to trigger the function.

The button that will be clicked is this

<div class='modaltrigger btn btn-primary' data-id='$itemId' data-toggle='modal'>Manage</div>

This button is being created by another function.

I would like to know either how i pass the variable from one function to another or how i pass it from the data-id to the function in php.

Thanks in advance.

I dont know why I'm having so many problems with this. I need to get a variable that defined in an included file inside of a function I've got this

Inside file.php I've got the $variable1 and $variable2 defined (they're dynamic/different to each user)

include('file.php');

function foo() {
GLOBAL $variable1, $variable2;

echo $variable1;
echo $variable2;
}

foo();

Yet it outputs nothing?

If I Include file.php right inside of the function it works however. Any idea?

Code: [Select]
class replayer extends users {
--SNIP--
public $islive = false;
--SNIP--
     function chat($id, $nick, $chat) {
          --SNIP--
          <-----------
     }
}
There's my code, I want to take the variable $islive from the above class and use it in the chat() function.

How would I do it? I've tried making it a global inside of the chat() function.

This seems really straight forward but I can't figure out why it's happening.  As a part of an account registration script, I'm randomly generating a password using a function called, generatePassword($length,$strength);
I hash the password (md5) before putting it in the database but I also email the non-hashed version to the user.  My problem is that each time I call the variable, it generates a new password so the one in the database does not match the one received by the user, $user_password_plain = generatePassword($length,$strength);
$user_password = md5($user_password_plain);
Is there a different way to store the variable so that I can access it later in the script and it will be the same?  I tried using a session variable but that didn't seem to work either.  Thanks!

Hi guys,

I have a trouble with my php snippet, when I insert the var function in the url bar something is like:

http://www.mysite.com/delete.php?favorites&id=0

or

http://www.mysite.com/delete.php?whateveritis&id=0

It doesn't get pass the favorites function to delete the id. It is the same things that it goes for each different function.

Here's the current code:

<?php
Code: [Select]
session_start();
    define('DB_HOST', 'localhost');
    define('DB_USER', 'mydbuser');
    define('DB_PASSWORD', 'mydbpass');
    define('DB_DATABASE', 'mydbtablename');

    $errmsg_arr = array();
    $errflag = false;

    $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
    if(!$link) {
  die('Failed to connect to server: ' . mysql_error());
    }

    $db = mysql_select_db(DB_DATABASE);
    if(!$db) {

die("Unable to select database");
    }

   function clean($var){

return mysql_real_escape_string(strip_tags($var));
    }
    $favorites = clean($_GET['favorites']);
    $id = clean($_GET['id']);

if($favorites && $id == ''){
   // both are empty
   $errmsg_arr[] = 'favorites id are missing.';
   $errflag = true;
}

    if($errflag) {
  $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
  echo implode('<br />',$errmsg_arr);
   }
   else {
$insert = array();
if(isset($_GET['id'])) {
    $insert[] = 'id = \'' . clean($_GET['id']) .'\'';
}
if(isset($_GET['favorites'])) {
    $insert[] = 'favorites = \'' . clean($_GET['favorites']) . '\'';
}

if($favorites && $id) {
   mysql_query("DELETE FROM favorites WHERE id='$id'");
   $deleted = mysql_affected_rows();
   if($deleted > 0)
   {
  echo "favorites channels is deleted";
   }
   else
   {
  echo("favorites is already deleted");
   }
 }
}
?>
If you do know how to get pass the favorites function, then please say so as i need your help.

Any advice would be much appreicated.

Ok it's abit complicated so i'll try to explain as best as I can.
Upon registration a file is created with your username that was registered and also a file for your profile named after your username so it would be /profiles/usernamesprofilehere.php.

I put a code into the profile that is:
Code: [Select]
include ("/home/giacjrdi/public_html/mysite/profiles/profileinfo/$username.info.php");
echo "<center><b><br /> $user's Profile <br /></b></center>";
$username is calling the cookie's username
while $user is calling the account's username.

eg if I try to view "bob"'s profile but logged in as "fred" since the include function is under $username which is cookies, it will retrieve "fred"'s information and post it on "bob"'s profile.

The only sollution i can think of would be to store a username variable in the url and use it for the include function.

I cant figure out how to add $recieved into this
needs to take place of time
hope someone knows how to do this
what im doing is adding in the UNIX time i want to offset


Code: [Select]
<?php $offset = date('m/d/Y/H:i:s', time()+$send1['time_offset']); ?>

I am going through the tutorial found at http://goo.gl/69MeY and in my ultimate wisdom have decided to see if I can create a form, which you input some text, and then in the php file that handles the form in puts that variable into a text document using the fwrite function, basically creating a file from the website containing whatever text you put in. There is no specific purpose to this idea, I am just trying to implement everything I have learnt so far.

Form: http://pastebin.com/J62UHBeT
PHP Handler: http://pastebin.com/FHuaKkxD

I someone could point me in the right direction of what I am doing wrong it would be much appreciated

Thanks in advance

Michael