PHP - Get This Error: Parse Error: Parse Error, Expecting `')'' In C:\wamp\www\chap6\r
$BoxSize = array("smallbox" = array("length" => 12, "width" => 10, "depth" => 2.5),
"mediumbox" = array("length" => 30, "width" => 20, "depth" => 4), "largebox" = array("length" => 60, "width" => 40, "depth" => 11.5)); Similar TutorialsHello I have one problem with fwrite() I have one script to get width and height from javascript and echo it with PHP. echo "Screen width is: ". $_GET['width'] ."<br />\n"; echo "Screen height is: ". $_GET['height'] ."<br />\n"; It works but i want to store the result in a file fwrite($info,"Height: $_GET['height'] <br />"); But then I get error Parse error: parse error, expecting `T_STRING' or `T_VARIABLE' or `T_NUM_STRING //////////////////////// it would be even better if I don't have to print the values but directly store them in $iinfo sorry if something similar was soved but those examples were different or i was unable to transform it to solve my problem hi all am new to this forum help me to overcome from this error Parse error: parse error, expecting `T_STRING' or `T_VARIABLE' or `T_NUM_STRING' in D:\wamp\www\quiz1\quiz1.php on line 12 Code: [Select] <?php include("contentdb.php"); $display = mysql_query("SELECT * FROM $table ORDER BY id",$db); if (!$submit) { echo "<form method=post action=$_SERVER['PHP_SELF']>"; echo "<table border=0>"; while ($row = mysql_fetch_array($display)) { $id = $row["id"]; $question = $row["question"]; $opt1 = $row["opt1"]; $opt2 = $row["opt2"]; $opt3 = $row["opt3"]; $answer = $row["answer"]; echo "<tr><td colspan=3><br><b>$question</b></td></tr>"; echo "<tr><td>$opt1 <input type=radio name=q$id value=\"$opt1\"></td><td>$opt2 <input type=radio name=q$id value=\"$opt2\"></td><td>$opt3 <input type=radio name=q$id value=\"$opt3\"></td></tr>"; } echo "</table>"; echo "<input type='submit' value='See how you did' name='submit'>"; echo "</form>"; } elseif ($submit) { $score = 0; $total = mysql_num_rows($display); while ($result = mysql_fetch_array($display)) { $answer = $result["answer"]; $q = $result["q"]; if ($$q == $answer) { $score++; } } echo "<p align=center><b>You scored $score out of $total</b></p>"; echo "<p>"; if ($score == $total) { echo "Congratulations! You got every question right!"; } elseif ($score/$total < 0.34) { echo "Oh dear. Not the best score, but don't worry, it's only a quiz."; } elseif ($score/$total > 0.67) { echo "Well done! You certainly know your stuff."; } else { echo "Not bad - but there were a few that caught you out!"; } echo "</p>"; echo "<p>Here are the answers:"; echo "<table border=0>"; $display = mysql_query("SELECT * FROM $table ORDER BY id",$db); while ($row = mysql_fetch_array($display)) { $question = $row["question"]; $answer = $row["answer"]; $q = $row["q"]; echo "<tr><td><br>$question</td></tr>"; if ($$q == $answer) { echo "<tr><td>»you answered ${$q}, which is correct</td></tr>"; } elseif ($$q == "") { echo "<tr><td>»you didn't select an answer. The answer is $answer</td></tr>"; } else { echo "<tr><td>»you answered ${$q}. The answer is $answer</td></tr>"; } } echo "</table></p>"; } ?> thanks in adavance I am trying to put a href on a line to link me to another php module, but get an error: Parse error: parse error in C:\wamp\www\editpolicy.php on line 47 My code: while ($row2 = mysql_fetch_array($result2) ) { print "<tr><td>"; <a href='editpayment.php?payid=$row2[PaymentID]'>$row2[PaymentID]</a> .........THIS IS LINE 47 ??? print "</td><td>"; print $row2['Actioned']; print "</td><td align='right'>"; print $row2['PremiumPaidAmount']; print "</td><td align='right'>"; print $row2['Risk']; print "</td></tr>"; } echo "</select></td>\r\n </tr>\r\n \r\n <tr>\r\n <td align=\"right\">Total Views Allowed:</td>\r\n <td><input type=\"text\" id=\"ad_total_views\" style=\"width:50px;\" value=\"\" disabled=\"disabled\" /> <label><input type=\"checkbox\" checked=\"checked\" onclick=\"if(this.checked==true){$('#ad_total_views').val('');$('#ad_total_views').attr('disabled','disabled');}else{$('#ad_total_views').val('');$('#ad_total_views').removeAttr('disabled');$('#ad_total_views').focus()}\" />Unlimited</label></td>\r\n </tr>\r\n \r\n <tr>\r\n <td align=\"right\">Total Clicks Allowed:</td>\r\n <td><input type=\"text\" id=\"ad_total_clicks\" style=\"width:50px;\" value=\"\" disabled=\"disabled\" /> <label><input type=\"checkbox\" checked=\"checked\" onclick=\"if(this.checked==true){$('#ad_total_clicks').val('');$('#ad_total_clicks').attr('disabled','disabled');}else{$('#ad_total_clicks').val('');$('#ad_total_clicks').removeAttr('disabled');$('#ad_total_clicks').focus()}\" />Unlimited</label></td>\r\n </tr>\r\n </table></td>\r\n </tr>\r\n <tr bgcolor=\"#FFFFFF\">\r\n <td class=\"td_th\" align=\"center\">Smarty Code (Developer)</td>\r\n <td>{\$ads->getAdCode(<span id=\"smartycode\">1</span>)}</td>\r\n </tr>\r\n <tr bgcolor=\"#FFFFFF\">\r\n <td class=\"td_th\" align=\"center\"> </td>\r\n <td><input type=\"button\" value=\"Create New Campaign\" onclick=\"new_ad()\" /></td>\r\n </tr>\r\n </TBODY></TABLE>\r\n<br />\r\n\r\n<TABLE cellSpacing=1 cellPadding=4 width=\"100%\" border=0>\r\n <TBODY>\r\n <TR class=\"td_title\">\r\n <TD colSpan=7>Ad Campaigns</TD></TR>\r\n <TR bgColor=#ffffff>\r\n \r\n <TD width=\"10%\" align=\"center\" class=\"td_th\"> </TD>\r\n <TD width=\"4%\" align=\"center\" class=\"td_th\">ID</TD>\r\n <TD width=\"29%\" align=\"center\" class=\"td_th\">Campaign Name</TD>\r\n <TD width=\"12%\" align=\"center\" class=\"td_th\">Start Date</TD>\r\n <TD width=\"11%\" align=\"center\" class=\"td_th\">End Date</TD>\r\n <TD width=\"17%\" align=\"center\" class=\"td_th\">Viewed / Views Allowed</TD>\r\n <TD width=\"17%\" align=\"center\" class=\"td_th\">Clicked / Clicks Allowed</TD>\r\n </TR>\r\n "; Hi all, Does anybody can help me with this error...? I am trying create a simple form which insert data into mysql table called 'sample' Here is my code... Code: [Select] <?php $connection = mysql_connect("localhost","root", "123"); if(!$connection) { die("db connection error" .mysql_error()); } $db_select = mysql_select_db("project", $connection); if(!$db_select) { die("db select error" .mysql_error()); } $sql = "INSERT INTO sample (id,firstname,lastname,bio,gender) VALUES ('$_POST['ID_']','$_POST['firstname']','$_POST['lastname']','$_POST['bio']','$_POST['gender']')"; if(!$sql) { die('Error: ' . mysql_error()); } echo "1 record added"; ?> And every time I am getting this annoying error Quote Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in C:\wamp\www\project\process.php on line 19 and Line 19 is Code: [Select] ('$_POST['ID_']','$_POST['firstname']','$_POST['lastname']','$_POST['bio']','$_POST['gender']')"; Thanks in advance..! :-) I just edited the tablerate.php in magento, and now I am getting this error, but I don't know what's wrong. Anybody here can help me?
The error message reads "Parse error: syntax error, unexpected '*', expecting function (T_FUNCTION) in /home/echoshom/public_html/app/code/core/Mage/Shipping/Model/Carrier/Tablerate.php on line 50"
Attached is tablerate.php
Attached Files
Tablerate.php 9.23KB
2 downloads can't seem to find the error. helppp Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /export/SOI-50/students/m2009/abhr428/web/WebIbs/view_user.php on line 20 <?php require_once( "common.inc.php"); require_once( "config.php" ); require_once( "users.class.php" ); require_once( "LogEntry.class.php" ); $userid = isset( $_GET["userid"] ) ? (int)$_GET["userid"] : 0; if ( !$user = user::getuser( $userid) ) { displayPageHeader( "Error" ); echo "<div>User not found.</div>; displayPageFooter(); exit; } $logEntries = LogEntry::getLogEntries( $userid ); displayPageHeader( "View user: ". $user->getValueEncoded( "usr_name") ." ". $user->getValueEncoded( "usr_surname") ); ?> <dl style="width: 30em;"> <dt>Username</dt> <dd><?php echo $user->getValueEncoded( "usr_username" ) ?></dd> <dt>First name</dt> <dd><?php echo $user->getValueEncoded( "usr_name" ) ?></dd> <dt> Last name</dt> <dd><?php echo $user->getValueEncoded( "usr_surename" ) ?></dd> <dt>Joined on</dt> <dd><?php echo $user->getValueEncoded( "usr_recordtime") ?></dd> <dt>Last time active</dt> <dd><?php echo $user->getValueEncoded( "usr_lastlogintime" ) ?></dd> </dl> <h2> Access Log </h2> <table cellspacing="0" style="width":30em; border: 1px solid #667;"> <tr> <th>Web Page</th> <th>Number of visits</th> <th> Last visit</th> </tr> <?php $rowCount = 0; foreach ~( $logEntries as $logEntry ) { $rowCount++; ?> <tr<?php if ( $rowCount % 2 == 0 ) echo ' class="alt"' ?>> <td><?php echo $logEntry->getValueEncoded( "pageUrl" ) ?></td> <td><?php echo $logEntry->getValueEncoded( "numVisits") ?></td> <td><?php echo $logEntry->getValueEncoded( "lastAccess") ?> </td> </tr> <?php </table> <div style="width: 30em; margin-top: 20px; text-align: center;"> <a href="javascript:history.go(-1)">back</a> </div> <?php displayPageFooter(); ?> This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=315281.0 I have been getting that error and I cannot figure out why it is happening Here is the error: Parse error: syntax error, unexpected T_ENDWHILE, expecting ',' or ';' in /home/scswc188/public_html/index.php on line 23 Here is my Code (Database Credentials removed for obvious reasons) <?PHP // Conect to the Mysql Server $connect = mysql_connect("IP","USER","PASS"); //connect to the database mysql_select_db("TABLE"); //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 1"); // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "'<font color='black'>Online:<font color='green'>$users, </font></font>;" endwhile; ?> or here http://pastebin.com/ZYh4t2pD Thanks Edit: Found the php tag Hey, Its something to do with the ' or \ I know that as Ive been trying alot. Code Code: [Select] if ($this->isAdmin && count ($func_players) > SettingsManager::GetSetting(Settings::BAN_LIMIT)) return $this->sendErrorBox('max', 'You can\'t ban that many Users at once!', 'Gosh', 'iBan'); foreach($func_players as $func_player) $func_player->ban(&this->playerName, $this->isAdmin); return $this->sendErrorBox('max', sprintf( '%s ha%s been banned.' $this->getPlayerString($func_players), count($func_players) == 1 ? 's' : 've'), 'SykoPwns:P', 'Sykos:iBan'); Thanks for your help! Ive tried alot of things I think I could just take out the \ or something!! <?php error_reporting(E_ALL); include_once("conninfo2.php"); include_once('classes/bcrypt.php'); class User { private $_bcrypt; $this->_bcrypt = new Bcrypt; if($this->_bcrypt->verify($password, $this->data()->password)){ } if(isset($_POST['username'])) { $firstname = strip_tags($_POST['firstname']); $surname = strip_tags($_POST['surname']); $pnumber = strip_tags($_POST['pnumber']); $username = strip_tags($_POST['username']); $email1 = strip_tags($_POST['email1']); $email2 = strip_tags($_POST['email2']); $password1 = $_POST['password1']; $password2 = $_POST['password2']; //code below will make sure all fields are filled in if(trim($firstname) == "" || trim($surname) == "" || trim($pnumber) == "" || trim($username) == "username" || trim($email1) == "" || trim($email2) == "" ||trim($password1) == "" || trim($password2) == "") { echo "Error, all fileds need to be filled in"; $db = null; exit(); } //code below checks that the emails entered both match one another if($email1 != $email2) { echo "Emails do not match, please try again"; $db = null; exit(); } //code below matches the passwords entered else if($password1 != $password2) { echo "Passwords do not match please try again"; exit(); } if(!filter_var($email1, FILTER_VALIDATE_EMAIL)) { echo "Your email is invalid, please try again"; $db = null; exit(); } //checks if the email exists within the database $stmt = $db->prepare("SELECT email FROM login WHERE email=:email1 LIMIT 1"); $stmt->bindValue(':email1',$email1, PDO::PARAM_STR); try{ $stmt->execute(); $count = $stmt->rowCount(); } catch(PDOException $e) { echo $e->getMessage(); $db = null; exit(); } //checks if the username exists $usernameSQL = $db->prepare("SELECT username FROM login WHERE username=:username LIMIT 1"); $usernameSQL->bindValue(':username',$username,PDO::PARAM_STR); try{ $usernameSQL->execute(); $usernameCount = $usernameSQL->rowCount(); } catch(PDOExemption $e) { echo $e->getMessage(); $db = null; exit(); } //checks if the email is already within the database if($count > 0) { echo "This email already exists"; $db = null; exit(); } //checks the username if($usernameCount > 0) { echo "This username is unavailable please try another"; $db = null; exit(); } $user = new User; $bcrypt = new Bcrypt; try { $email1->create(array( 'username' => Input::get('username'), 'password1' => $bcrypt->hash(Input::get('password')), 'firstname' => Input::get('name'), 'surname' => Input::get('surname'), 'pnumber' => Input::get('pnumber'), 'email1' => Input::get('email'), 'ipaddress' => Input::get('ipaddress'), 'signup_date' => date('Y-m-d H:i:s'), 'group' => 1 )); //grab the last id used within the database $lastId = $db->lastInsertId(); $stmt3 = $db->prepare("INSERT INTO activated (user, token) VALUES ('$lastId', :token)"); $stmt3->bindValue(':token',$token,PDO::PARAM_STR); $stmt3->execute(); //email activation $from = "From Auto Responder @ Mediaedit <admin@mediaedit.com>"; $subject = "IMPORTANT: Please activate your account"; $link = 'http://mediaed.it/roxanne/activate.php?user='.$lastId.'&token='.$token.''; //email body $message = " Thanks for register with Mediaedit, before your able to use our services you will need to verify your email so that we know your human $link "; //headers $headers = 'MIME-Version: 1.0' . "rn"; $headers .= "Content-type: textrn"; $headers .= "From: Mediaedit"; //send email now mail($email1, $subject, $message, $headers, '-f noreply@mediated.it'); $db->commit(); echo "Thanks for registering, before you can us our services you need to activate your account an email has been sent which you will recieve shortly"; $db = null; exit(); } catch(PDOException $e){ $db->rollBack(); echo $e->getMessage(); $db = null; exit(); } } ?>i keep getting Parse error: syntax error, unexpected T_VARIABLE, expecting T_FUNCTION I Can't find the problem. The code:
mysql_query("insert into games(week, fight, league_id)values($_REQUEST['week'],'$_REQUEST[home_team]-$_REQUEST[guest_team]',$_REQUEST['home_league'])", $Link);The error message: Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING Hi. I am having a problem with a php while loop.I am trying to draw a polygon using coordinates from a online data table called buildinglist.the loop is supposed to loop through each row drawing a polygon with each set of coordinates : <?php // Include file to Connnect to online database include_once "mysql_connect.php"; // Collects data from table $data = mysql_query("SELECT * FROM buildinglist") or die(mysql_error()); // puts the "buildinglist" info into the $info array // $info = mysql_fetch_array( $data ); ?> <!DOCTYPE HTML> <html> <head> <style type="text/css"> #theMap {background-image:url('MapImg.png'); } polygon:hover{fill:gold;} </style> <script type="text/javascript"> // This function is called when the lake is clicked. function buildingClick(<?php $id ?>) { // Display a fact. alert("<?php print $id; ?>"); } </script> </head> <body> <svg id="theMap" x="0" y="0" width="900" height="900"> <?php while($info = mysql_fetch_array( $data )){ //THE PROBLEM IS WITH THIS LINE// echo "<polygon fill="$info['fill_colour']" stroke="black" id="$info['id']" points="$info['coordinates']" />"; } ?> </svg> </body> </html> Can anybody help?it would be highly appreciated Eoin. Hi, I was wondering if somebody can help me with an error I am getting. Here is my code: Code: [Select] if ($_SESSION['username']=='login') { if (isset($_REQUEST['file'])) { $fc = file_get_contents($_REQUEST['file']); $text = explode("<!-- EDITABLE -->",$fc); echo "<form method='post' action=''><textarea name='content'>$text[1]</textarea>"; echo "<p><input type='hidden' name='file' value='".$_REQUEST['file']."' /><input name='submitUpdate' type='submit' value='Update Page'></form>"; } else { echo "<p align='center'> <a href="index.html">Home Page</a><br/> //THIS IS THE LINE THAT IS GIVING THE ERROR <a href="contact_us.html">Contact Us</a><br/> <br/> <em>Click on the links above to edit the files.</em><br/> <a href="?logout">logout</a></p>"; } } This code is within php tags is that correct? As I am coding in notepad ++ and it doesn't have any colour which makes me think something is wrong. If someone could help that would be brilliant! Thanks in advance Hey guys, I am getting the same error and I can't figure out why, I've double checked all my brackets and everything. It's probably just something simple but once you've been staring at it for ages you can't see very much. My code is: Code: [Select] if (isset($_POST['Submit'])) { if (isset($_POST['username'] == '***') && ($_POST['password'] == '***')) { //THIS IS THE LINE $_SESSION['username'] = 'login'; } else { echo "<b>Your login details are not correct. Please login again</b>"; } } I've highlighted the line that the error appears on , can anybody help me? Having a problem with a php code. Im new to php and have only been learning for one day but have had previous experiances with php in which i have copied and pasted and edited to suit my needs . This is my code Code: [Select] <?php $username = $_POST["user"]; $password = $_POST["pass"]; $login = $_GET["login"]; setcookie("username","$username",time()+86400); if($login=="yes") { $con = mysql_connect("localhost","root","arceye"); mysql_select_db("login"); $get = mysql_query("SELECT count(id) FROM login WHERE user='$username' and pass='$password'"); $result = mysql_result($get, 0); if($result!=1) { echo "Invalid Username Or Password"; } else { echo "Login Successful" $_SESSION["username"] = $username; } } i named that login.php im running a wamp server thinge on localhost. when i try to run it on http://localhost/login.php i get the error Parse error: syntax error, unexpected T_VARIABLE, expecting ',' or ';' in C:\wamp\www\login.php on line 23 can anyone help i had 5 other error but managed to use common sense to fix them this one i cant seem to work out. Thanks in advance MOD EDIT: code tags added. I am getting this error and cant figure it out: Parse error: syntax error, unexpected ')', expecting '&' or T_VARIABLE in /path/to/app/cool.php on line 150 this is line 50: function GetParentIDS(){ this is the rest of the function: global $wpdb; $CATS = ""; $Maincategories = get_categories('use_desc_for_title=1&hide_empty=0&hierarchical=0'); $Maincatcount = count($Maincategories); foreach ($Maincategories as $Maincat) { if($Maincat->parent ==0){ $CATS .= $Maincat->cat_ID.","; } } return $CATS; } this is the function above it: function sidebarArticles(){ global $wpdb; global $PPT; $string=""; $posts = query_posts('meta_key=type&meta_value=article&posts_per_page=5'); foreach($posts as $article){ $Artimage = get_post_meta($article->ID, 'image', true); $string .= "<li>"; if(strlen($Artimage) > 1){ $string .= '<a href="'.get_permalink($article->ID).'" title="'.$article->post_title.'"><img src="'.$PPT->ImageCheck($Artimage).'" style="float:right; max-width:40px; max-height:40px;" /></a>'; } $string .= "<h4><a href='".get_permalink($article)."'>".$article->post_title."</a></h4> <cite>Posted <em>".$PPT->TimeDiff($article->post_date)."</em></cite> <p>".$article->post_excerpt."</p> </li>"; } return $string; } Any ideas? Hi, I'm trying to create a cms and am encountering an error which I can't figure out. The error message reads: Parse error: syntax error, unexpected T_IS_NOT_EQUAL, expecting ',' or ')' in C:\wamp\www\cms\admin.php on line 6 The section of code that is giving me the error is as follows: if (isset( $_GET['action'] != "login") && $_GET['action'] != "logout" && !$_SESSION['username'] ) { //THIS IS LINE 6 login(); exit; } Is there anybody that can help me figure out what is going wrong? Thanks in advance |