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PHP - Get User Details From Mysql Database Using Php?
I have created a button which when pressed should present the user with their details (whoever is logged in), here is the form code:
<form id="form1" name="form1" method="post" action="getdetails.php"> <input type="submit" name="Get Details" value="Get Details" /> </label> </p> </form> Here is the getdetails.php file <?php mysql_connect("localhost","root",""); mysql_select_db("test"); $username = $_POST['textfield']; echo '</br>'; $query = mysql_query("SELECT * FROM membersdetails WHERE name=`$username` "); while($result = mysql_fetch_array($query)) { //display echo $result['firstname']; echo $result['surname']; } ?> Its not workin at all I have attacthed the error i am getting Any help please? Similar Tutorialshi i had database with field of name,title,post,content i want to fetch the post and content for a specific user from giving name of that user by form help me to get that ps just give me idea to how to do that/ Code: [Select] <form id="form1" name="form1" method="post" action="view.php"> <label>Name <input type="text" name="textfield" /> </label> <p> <label> <input type="submit" name="Submit" value="Submit" /> </label> </p> </form> Hello everyone, I am trying to have a function on my website where the administrator can add a new member to the database. Their details are to be stored in the table memberdetails, I have posted the code below, the error i recieve is "Error: Column count doesn't match value count at row 1" Can anybody help me please? form code: <form action="insert.php" method="post"> Username: <input type="text" name="username" /><br><br> Firstname: <input type="text" name="firstname" /><br><br> Surname : <input type="text" name="surname" /><br><br> Date Birth: <input type="text" name="dob" /><br><br> Total Wins: <input type="text" name="wins" /> Total Loses: <input type="text" name="loses" /><br><br> Email Add: <input type="text" name="email" /><br><br> Country : <input type="text" name="born" /><br><br> Other Info: <input type="text" name="other" /><br><br> <input type="submit" name="Submit" value="Create" align="right"></td> </form> insert.php <?php mysql_connect ("localhost","root","") or die("Cannot connect to Database"); mysql_select_db ("test"); $sql="INSERT INTO memberdetails (username, firstname, surname, dob, totalwins, totalloses, email, country, info) VALUES ('$_POST[username]''$_POST[firstname]','$_POST[surname]','$_POST[wins]''$_POST[loses]''$_POST[email]''$_POST[born]''$_POST[other]''$_POST[dob]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?> Hi All, I've searched long and hard accross the web for an answer to this and finnally given in and requesting help. Here's what i have, i have a database setup and working fine. What i would like to do is for an administrator to be able to update my users details. It may sound odd, why don't you let your users update their own details? Well the administrators are dispatchers if you like, and my users are the 'dispatchees', for want of a better word. So i would like my administrators to be able to dispatch my users with routes and my users be able to see the routes that have been dispatched to them. I've setup a login area and a page that pulls there routes off the database, depending on their login details, i.e. jack will see his routes and jill will see her's independantly. This works by me editing the appropriate columns/rows of my database using phpmyadmin. What i'd like now is for administrators (who are directed to a seperate page, with more controls) to be able to do the same as me (updating the database) but by using a php form/script. I'd like to be able to select the routes from a second table on the same database if possible, to try and keep everything tidy. So my dispatcher would select Route001 from a drop down list, this would fill in the text fields next to the route field with From To, so my dispatcher would know what route001 actually is from/ too, choose a username (now being driven from my other table) and hit dispatch. My user would login to their area, hit view dispatched routes and it would display Route 001 with the correct information. The login area was a downloaded script i modified to suit and is called Login-Redirect_v1.31_FULL Many thanks in advance, hope you can sort of understand what i want Josh PHP/MySQL ability:Novice Actually, what i want to do is to use the email to fetch the $email,$password and $randomnumber from database after Hi, I have created a session based logon system using php and MYSQL from some tutorials I found online which is working very successfully. I can log on and of and move through different pages with no problems. My query is how do I output or display the information that is specific to the user which is currently logged on and block access to any other users information. I am quite sure there is a simple solution that is escaping me. If you could point me in the right direction it would be greatly appreciated. Thanks in advance Am a newbie in php. Since I can't insert values to the database with respect to a user Id or with any other token using WHERE clause. I.e "INSERT INTO receipts(date) VALUES(example) where id="**....." If I need to fetch several values of column for a particular user, how do I go about it? Thank you!!! i am working on a project in which i am facing a problem. my question is that is it possible to get information/details of a user who is not logged in or who is not registered. if a user logged in then we can find get details easily. but how can i do this. is it possible. after the user has logged in, I would like to display their details by barcode id Login.php <?php $host=""; // Host name $username=""; // Mysql username $password=""; // Mysql password $db_name=""; // Database name $tbl_name=""; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); session_start(); // username and password sent from form $barcodeID=$_POST['barcode']; // To protect MySQL injection (more detail about MySQL injection) $barcodeID = stripslashes($barcodeID); $barcodeID = mysql_real_escape_string($barcodeID); $sql="SELECT * FROM $tbl_name WHERE BarcodeID='$barcodeID'"; $result=mysql_query($sql); $count=mysql_num_rows($result); if($count > 0){ $data = mysql_fetch_array ($result); $_SESSION["user_id"] = $data["BarcodeID"]; $_SESSION["user_firstname"] = $data["Firstname"]; $_SESSION["user_surname"] = $data["Surname"]; $_SESSION["user_jobrole"] = $data["JobRole"]; $_SESSION["user_manager"] = $data["Manager"]; $_SESSION["user_priority"] = $data["Priority"]; $_SESSION["user_datejoined"] = $data["DateJoined"]; $_SESSION["user_times_loggged_in"] = $data["TimesLoggedOn"]; if ($_SESSION["user_priority"] == '1') { header("Location: AdminSection.php"); } else { header("Location:LoggedIn.php"); } if ($_SESSION["user_times_loggged_in"] == '0') { header("Location:UsingTheSystem.html"); } } ?> LoggedIn.php I keep getting the error undefined index "barcode"? <?php $barcodeID = $_POST["barcode"]; include 'dbcon.php'; $sql = "SELECT Firstname, Surname, JobRole, Manager" . " FROM users" . " WHERE BarcodeID = .'$barcodeID'" ; $rows = mysql_query($sql); echo $rows; ?> Any help will be greatly appreciated Thanks Hi, I got this code which is meant to display the login details of the person that is logged in, however it just displays the details of the last person in the mysql table. I have set up some test logins, so if I login as paul1 the details for paul3 are displayed...confused Anyway, here is the page which displays the details Code: [Select] <?php session_start(); // This checks to make sure the session variable is registered // WARNING: DO NOT DELETE THE FOLLOWING LINE OF TEXT if( isset($_SESSION['username']) && isset($_SESSION['sid'])) { // You are free to edit the following code to suit your requirements include_once("../../data/server.php"); include_once("../../lib/userdata.php"); // THIS BIT WORKS AND DISPLAYS THE USERNAME $data = mysql_query("SELECT * FROM members") or die(mysql_error()); while($info = mysql_fetch_array( $data )) { include("../../lib/userinfo.php"); //////////////////////////////////////////// WARNING: YOU SHOULD NOT EDIT ANYTHING ABOVE THIS LINE //////////////////////////////////////////////////////// ECHO <<<PAGE <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>$siteName</title> <link rel="stylesheet" href="../../userstylesheet.css" type="text/css" /> </head> <div id="page"> <img alt="" src="../../images/leftCurve" height="6" width="6" id="left" /> <img alt="" src="../../images/rightCurve.gif" height="6" width="6" id="right" /> <div id="pageName"> <h1>$siteName</h1> </div> <div id="pageNav"> <div id="sectionLinks"> <a href="profile.php?username=$username">My Profile</a> <a href="modify.php?username=$username">Personal Details</a> <a href="message.php?username=$username">Messages</a> <a href="../../logout.php?username=$username">Logout</a></div> </div> <div id="content"> <div class="feature"> <h2>Welcome $username </h2> <p>This is the demonstration home.html template. You are free to edit this or any of the other templates to suit your own needs. </p> <p>This is the first page your member will see once they have logged in. </p> <p>If you look at the code for this page, you will see that all HTML code is placed between the ***PAGE and PAGE; tags. Please note that the three * should be replaced with the < character. This format must be kept to ensure that the user variables work. Changing this format may result in errors being returned.</p> <p>You may call member information using the $ tag and the variable name eg $ firstname without the space, will show the members first name, such as $firstname</p> <p>For any information please visit our site http://www.membersitemaker.co.uk. User guides will be added shortly and the forum will soon be full of help. </p> </div> </div> <div id="information"> <a href="#">About Us</a> | <a href="#">Site Map</a> | <a href="#">Privacy Policy</a> | <a href="#">Contact Us</a> | ©2011 $siteName </div> </div> </body> </html> PAGE; } //////////////////////////////////////// WARNING: DO NOT DELETE ANYTHING BELOW THIS LINE ////////////////////////////////////////////////////////// } else { // This will redirect the user to the login page if the session variables do not exist header( "Location: ../../../login.html" ); } ?> And here is the code for userdata.php Code: [Select] <?php // Decode sitename function decode_variable(&$siteName) { $siteName = urldecode($siteName); $siteName = str_replace('%20',' ',$siteName); return $siteName; } decode_variable($siteName); // Connnect to MySQL database include_once("../../data/mysql.php"); $mysqlPassword = (base64_decode($mysqlpword)); $db = mysql_connect("$localhost", "$mysqlusername", "$mysqlPassword") or die ("Error connecting to database"); mysql_select_db("$dbname", $db) or die ("An error occured when connecting to database"); // Carry out MySQL query ?> and userinfo.php Code: [Select] <?php $username = $info['username']; $firstname = $info['firstname']; $lastname = $info['lastname']; $address = $info['address']; $town = $info['town']; $county = $info['county']; $postcode = $info['postcode']; $email = $info['email']; $birth_year = $info['birth_year']; $country = $info['country']; $telephone_number = $info['telephone_number']; $mobile_number = $info['mobile_number']; $nickname = $info['nickname']; As always, your help is much appreciated Paul Hi all I need some help with displaying user account details i am currently able to show only the email address and i would like to show the name school name and yeargroup heres my code for myaccount.php <?php require_once('Connections/isn_1.php'); ?> <?php if (!isset($_SESSION)) { session_start(); } $MM_authorizedUsers = "1,2,3,4"; $MM_donotCheckaccess = "false"; // *** Restrict Access To Page: Grant or deny access to this page function isAuthorized($strUsers, $strGroups, $UserName, $UserGroup) { // For security, start by assuming the visitor is NOT authorized. $isValid = False; // When a visitor has logged into this site, the Session variable MM_Username set equal to their username. // Therefore, we know that a user is NOT logged in if that Session variable is blank. if (!empty($UserName)) { // Besides being logged in, you may restrict access to only certain users based on an ID established when they login. // Parse the strings into arrays. $arrUsers = Explode(",", $strUsers); $arrGroups = Explode(",", $strGroups); if (in_array($UserName, $arrUsers)) { $isValid = true; } // Or, you may restrict access to only certain users based on their username. if (in_array($UserGroup, $arrGroups)) { $isValid = true; } if (($strUsers == "") && false) { $isValid = true; } } return $isValid; } $MM_restrictGoTo = "login.php?login=false"; if (!((isset($_SESSION['MM_Username'])) && (isAuthorized("",$MM_authorizedUsers, $_SESSION['MM_Username'], $_SESSION['MM_UserGroup'])))) { $MM_qsChar = "?"; $MM_referrer = $_SERVER['PHP_SELF']; if (strpos($MM_restrictGoTo, "?")) $MM_qsChar = "&"; if (isset($_SERVER['QUERY_STRING']) && strlen($_SERVER['QUERY_STRING']) > 0) $MM_referrer .= "?" . $_SERVER['QUERY_STRING']; $MM_restrictGoTo = $MM_restrictGoTo. $MM_qsChar . "accesscheck=" . urlencode($MM_referrer); header("Location: ". $MM_restrictGoTo); exit; } ?> <!DOCTYPE HTML> <html> <head> <title>My Account - <?php echo($_SESSION['MM_Username']); ?></title> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <style type="text/css"> @import url("style.css"); </style> </head> <body class="about"> <!-- Start NavBar --> <div id="topnavbar"> <dl> <dt id="home"><a href="index.php">Home</a></dt> <dt id="about"><a href="about.php">About</a></dt> <dt id="account"><a href="myaccount.php">Account</a></dt> <dt id="login"><a href="login.php">Login</a></dt> </dl> <dl id="rightnavbar"> <dt id="ISN"><a href="index.php">ISN</a></dt> </dl> </div> <!-- End NavBar --> <div id="page-container"> <div id="header"> </div> <div id="sidebar-a"></div> <div id="content"> <div class="padding"> <center> <table width="631" border="0"> <tr> <td colspan="2">Personal Details</td> </tr> <tr> <td width="229"> </td> <td width="648"></td> </tr> <tr> <td>Name</td> <td></td> </tr> <tr> <td>Email</td> <td><?php echo($_SESSION['MM_Username']); ?></td> </tr> <tr> <td>School Name</td> <td></td> </tr> <tr> <td>Year Group</td> <td></td> </tr> <tr> <td>DOB</td> <td></td> </tr> <tr> <td> </td> <td><a href="updateprofile.php">Modify my details</a></td> </tr> </table> <a href="logout.php">Logout?</a> </center> </div> </div> <div id="footer"> <div id="altnav"> <a href="index.php">Home</a> - <a href="login.php">Login</a> - <a href="register.php">Register</a> - <a href="about.php">About</a> - <a href="terms.php">Terms & Conditions</a> </div> <div id="copyright">© 2011 InterSchoolsNetwork, All Rights Reserved - A <a href="http://jordansmithsolutions.co.uk">Jordan Smith Solutions</a> & <a href="http://www.joecocorp.webs.com/">JoeCo Corp Production</a><br /> </div> </div> </div> </body> </html> <?php mysql_free_result($rsUpdateUser); ?> If you need any other code to help answer it for me then let me no please Hello everyone.
I have a fully working form that gets data from a user (with $_post array) , and stores it in a database (mysql).
After successfulIy filling the form, I refer him to the "dashboard" page. In this page, i am having trouble to get his details from the database. How should I recognize him as the user that just registered?
should I use a $_post? or maybe a session? could you please give me a clue how to solve this?
I am ok with codeing but NOT half-as good as some of your GUYS here. I'm trying to write a simple sql query based on returning certain values from a table for that user. I would like to just beable to include this as a page user.info.php and render it on any page as include to return need values . See My CODE. PLESE HELP ME. Code: [Select] <?php @session_start(); $user = $_SESSION['username']; // Set cookie $userid = JRequest::getVar('userid'); $data = new stdClass(); $model =& $this->getModel('profile'); $my = CFactory::getUser(); // Test if userid is 0, check if the user is viewing its own profile. $db =& JFactory::getDBO(); $user =& JFactory::getUser(); $userId = $user->id; // Return with empty data if($userId == null || $userId == '') { //return false; } $user =& JFactory::getUser($userId); if($user->id == null){ //return false; } $id = & JFactory::getUser($userId); $query = 'SELECT user_id, id, format_id, year, name FROM #__muscol_albums WHERE user_id = ' . $id; //$query = 'SELECT user_id FROM #__muscol_albums WHERE id = ' . $album_id ; $result = mysql_query($query) or die('Error, No Album Search failed'); list($name, $user_id, $id, $year) = mysql_fetch_array($result); echo $id; echo $user_id; echo $year; // preform id return check and redirecto to correct url if ($user->get('id') == 0 || $userid == 0 || $userid <> $user->get('id')){ $url=JURI::root().'index.php?'.$component.'&id='.$id.'&tmpl=component&print=1'; } else { $url=JURI::root().'index.php?option=com_community&view=profile&id=1&tmpl=component&print=1'; //redirect is a function } ?> hi im new to php
im using a script that i found at the link below:
http://forums.devshe...sql-891201.html
It works fine but i have added a couple of fields to the database : telephone and mobile_telephone
Ive change the register.php to include these fields but im struggling with the edit_account
Could anyone help please
Hi, I have created a form (code below) to show details about members of my website. When the user enters the username of a certain member the form should retrieve these details from my database(phpmyadmin) and display them. I cant get this to work. Here is the code for my form: <form id="form1" name="form1" method="post" action="getdetails.php"> username <input type="text" name="textfield" value ='' /> <input type="submit" name="Get Details" value="Get Details" /> </label> </p> </form> Here is my getdetails.php file <?php mysql_connect ("localhost","root",""); mysql_select_db ("test"); $sql = "select * from memberdetails"; $result = mysql_query ($sql); while ($row = mysql_fetch_array($result)) { $username= $row["username"]; $firstname= $row["firstname"]; $surname= $row["surname"]; $dob= $row["dob"]; $totalwins= $row["totalwins"]; $totalloses= $row["totalloses"]; $email= $row["email"]; $country= $row["country"]; $info= $row["info"]; echo "<b><u>Username:</b></u> $username<br>"; echo "<b><u>Firstname:</b></u> $firstname<br>"; echo "<b><u>Surname: </b> </u> $surname<br>"; echo "<b><u>Date of Birth:</b></u> $dob<br>"; echo "<b><u>Total Chess Wins:</b></u> $totalwins<br>"; echo "<b><u>Total Chess loses:</b></u> $totalloses<br>"; echo "<b><u>Email Address: </b></u> $email<br>"; echo "<b><u>Born in: </b></u> $country<br>"; echo "<b><u>Other Details:</b></u> $info<br>"; } ?> The above code displays all the users' details from the table not just the one which was typed in. Thanks for any help! Hi, I have a form that allows a user to enter details and also to upload a image. The form works great and inserts into the database if i dont include the file input. What i would like happen is: The user enters details and selects a file The file then gets uploaded to ../images and the path is then written to bedroom1 variable The addresses and the bedroom1 variable that now holds the uploaded file path e.g. images/test.jpg is written to the database Form Code: [Select] <form action="admin.php" method="POST"> <table> <tr><td> Address 1: </td><td> <input type="text" name="address1" id="address1" onfocus="selected(this)" onblur="notselected(this)"> </td><td> <div id="dynamicText1"> </div> </td></tr> <tr><td> Address 2: </td><td> <input type="text" name="address2" id="address2" onfocus="selected(this)" onblur="notselected(this)"> </td><td> <div id="dynamicText1"> </div> </td></tr> <tr><td> County: </td><td> <input type="text" name="county" id="county" onfocus="selected(this)" onblur="notselected(this)"> </td><td> <div id="dynamicText1"> </div> </td></tr> <tr><td> Bedroom 1: </td><td> <input type="file" name="bedroom1" id="bedroom1" input name="uploadedfile"> </td><td> <div id="dynamicText1"> </div> </td></tr> <tr><td> <input type="submit" name="submitaddapartment" value="Add" id="registerbutton"> </td></tr> </table </form> And the php code to add it to the database Code: [Select] <?php //get variables $submitaddapartment = $_POST['submitaddapartment']; $address1 = strip_tags($_POST['address1']); $address2 = strip_tags($_POST['address2']); $county = strip_tags($_POST['county']); $bedroom1 = strip_tags($_POST['bedroom1']); if ($submitaddapartment) //if submit button was pressed { if ($address1&&$address2&&$county&&$bedroom1&&) //if fields arn't blank { include 'dbase.php'; //connect to database if ((($_FILES["bedroom1"]["type"] == "image/gif") || ($_FILES["bedroom1"]["type"] == "image/jpg") || ($_FILES["bedroom1"]["type"] == "image/pjpeg")) && ($_FILES["bedroom1"]["size"] < 20000000)) { if ($_FILES["bedroom1"]["error"] > 0) { echo "Return Code: " . $_FILES["bedroom1"]["error"] . "<br />"; } else { echo "Upload: " . $_FILES["bedroom1"]["name"] . "<br />"; echo "Type: " . $_FILES["bedroom1"]["type"] . "<br />"; echo "Size: " . ($_FILES["bedroom1"]["size"] / 1024) . " Kb<br />"; echo "Temp file: " . $_FILES["bedroom1"]["tmp_name"] . "<br />"; if (file_exists("../images/" . $_FILES["bedroom1"]["name"])) { echo $_FILES["bedroom1"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["bedroom1"]["tmp_name"], "/" . $_FILES["bedroom1"]["name"]); echo "Stored in: " . "../images/" . $_FILES["bedroom1"]["name"]; $bedroom1=".'images/.' $_FILES["bedroom1"]["name"]"; } } } else { echo "Invalid file"; } mysql_query ("INSERT INTO user VALUES(NULL,'$address1','$address2','$county','$bedroom1')"); } else { } } ?> Any help would be greatly appreciated. Thanks Fred Perhaps this is a rather lay question, but, is there a way to gather specific connection details about an open MySQL connection in php? Example: <?php $connect = mysql_connect('localhost', 'username', 'password'); ?> Using the $connect variable, could I run a command that dumps the host, and username to a log file?? Thanks in advance, I'm still searching. E Obviously when connecting to php Im not going to show all of my login details; mysql_connect("details","details","password") or die(mysql_error()); mysql_select_db("details") or die(mysql_error()); whats the best way to hide them? Ive seen some people using an include file with their login details on but say for eg. <?php include('con.php'); ?> Whats to stop somone looking at www.myweb/con.php and obtaining my details there instead? hi, i'm new in php/mysql. i'm stored student marks values in following format in mysql db table. id student_code Tamil English Maths Science Social 1 1 100 75 78 88 95 2 2 85 90 88 80 100 But i want to search and display the specific student marks in following format. id:1 student_code:1 Tamil:100 English:75 Maths:78 Science:88 Social:92 Total:? Avg:? please give correct code for this format. i want to make a monthly report the user selects month from drop down and i must get the specified dates of that month from the DB I am using ajax to get the dates Hi, I have successfully implemented a master details page with the results aligned in columns linking to a details page. I wish to maintain the recordID passed from the master details page and make the dynamic text, which reads Shade A tree that is capable of..... in the attached screen shot a link to another details page referencing the same recordID. The detailspage2.php would look the same as the screenshot except the Shade text and description below will be highlighted, which I can do, there will be a new image and a new image description. All other dynmaic elements on the page will remain the same. I tried to simply save as my detailspage.php to detailspage2.php and create a link to detailspage2.php. It linked to detailspage2.php but none of the record info showed up in their respective table cells. I have all the names desc's, images, etc setup in a table in my database. Please let me know what code and other info you need to help me out with this procedure. Thanks. |
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