PHP - Variable Not Affected Outside If Statement

I'm having an issue with holding a session variable in the statement below $Color is losing its value in the if statement. For example int the (   ) $Color is a zero while in the echo part $Color is being displayed correctly as Blue.

What's the correct syntax for having a variable in a select statement?

Here's an example of what I'm trying to do (after I'm already connected to the database).

Code: [Select]
$username = "thomas";
$query = mysql_query( "SELECT * from users WHERE username = $thomas" );
if( mysql_num_rows( $query ) > 0 )
{
bla bla...
It works if I don't put the WHERE part in, but I get an error if I use it, so I'm assuming I have the wrong syntax for using a variable in the select statement.

Hi,
My issue here is that I cant get my query string variables to ONLY feed into if/else statement  on my secondary page. I include my secondary page (fine.php) from my index page. My query string variables keep being fed back into my original if/ese statement on index.php.

here is the if/else on index.php (these links work fine):

<?php
if($_SERVER['QUERY_STRING']=='/index.php' || $_SERVER['QUERY_STRING']=='')
{
include 'port.php';
}

elseif (isset($_GET['pos'])){
include 'pos.php';
}

elseif (isset($_GET['web'])){
include 'web.php';
}

elseif (isset($_GET['fine'])){
include 'fine.php';
}

        else {include '404.php';}






here is the if/else on my secondary page (fine.php). These links are supposed to alert the if/else in the next table cell. However, they instead alert the if/else in index.php.


<td><br/>
<a href="?backset"><img src="fine/thumbs/x-backset.jpg" border="0"></a><br/><br/> 
<a href="?backside"><img src="fine/thumbs/x-backside.jpg" border="0"></a><br/><br/> 
<a href="?bannerprint"><img src="fine/thumbs/x-bannerprint.jpg" border="0"></a><br/><br/> 
<a href="?chopu"><img src="fine/thumbs/x-chopu.jpg" border="0"></a><br/><br/> 
</td>
<td><br/>
<div id="DivPiece" align="left">
<?PHP 

if (isset($_GET['backset'])){
       include 'fine/backset.php';
}

elseif (isset($_GET['backside'])){
     include 'fine/backside.php';
}

elseif (isset($_GET['bannerprint'])){
     include 'fine/bannerprint.php';
}

elseif (isset($_GET['chopu'])){
include 'fine/chopu.php';
}

?>
</div>
</td>



How can I get the links on the secondary page to only alert the if/else statement on that page, and BLOCK the if/else statement on index.php from seeing them? I still want to use the query string though.

Thanks!
[/quote]

OK, I think I have confused this code and it is not calculating correctly.
$ckifdue = mysql_query("SELECT * FROM accounting WHERE ClientID = '$clientid'") or die(mysql_error());
while($ckdue =mysql_fetch_array($ckifdue)){
    if($ckdue['AmountDue'] == "0"){
        $_SESSION['MONEYOWED'] = "0.00";
    }
    else
    {
       $_SESSION['MONEYOWED'] = $_SESSION['MONEYOWED'] + $ckdue['AmountDue'];
    }
    if($ckdue['Amount1RS'] == "Balance Due"){
        $totcol = $ckdue['TotalCollected'];
        echo " total collected:" . $totcol;
        $monpaid = $_SESSION['MONEYPAID'];
        echo "money paid in:" . $monpaid;
        $_SESSION['MONEYPAID'] =  $totcol + $monpaid;
        echo "session money paid:" . $_SESSION['MONEYPAID'];
    }
}
$moneypaid  = $_SESSION['MONEYPAID'];
$moneyowed = $_SESSION['MONEYOWED'];
echo "money paid:" . $moneypaid;
echo " money owed:" . $moneyowed;
$moneyowed = $moneyowed - $moneypaid;
unset($_SESSION['MONEYOWED']);
unset($_SESSION['MONEYPAID']);
The echos look like:

total collected:100.00money paid in:200session money paid:300 total collected:100.00money paid in:300session money paid:400money paid:400 money owed:0.00

There should be $100 due, $200 paid, so a balance of -100. There is 2 balance due reciepts, this is just not calclating right in the sessions.

Hello all,

I am a beginner at PHP and trying to form an IF statement, I'm running into a problem which I cannot seem to solve.
Due to my lack of syntax knowledge I would appreciate if someone could point me in the right direction.

The combo variables are sent to this page through a form and defined as these variables at the top of the page.
e.g $combo0 = $_POST["combo0"];

When the results are displayed any form field which was left blank or empty I want to show "N/A" if data is detected in being sent through the form I then want the "Else" statement to take affect.

Currently when I run the below statement N/A is echoed despite if data was sent through the form fields or not....

if (empty($scrap))  {
echo "<h3>Submitted Scrap Results</h3> No scrap parts were booked off";
}
elseif (empty($combo0) || empty($combo1) || empty($combo2) || empty($combo3) || empty($combo4)) {
echo "N/A";
}
else {
echo "<h3>Submitted Scrap Results</h3> <b>Reason:</b> " .$combo0." - ".$combo1." - ".$combo2." - ".$combo3." - ".$combo4."
<br /> <b>on machine</b> " .$mid. " - <b>No. Scrap</b> " .$noscrap. "";
}

Anyone any ideas?

Code: [Select]
echo("<p class=\"commentboxContainer\"><table width=100% border=0>
                      <tr>
                        <td bgcolor=\"#EEE\"><strong><p class=fltlft>$name </strong>says:</p></td>
                      </tr>
                    </table>
                    <table width=100% border=0 bgcolor=\"#EEE\">
                      <tr>
                        <td width=40%><img src=../images/Icons/People/Anonymous.png width=64 height=64 border=1 /></td>
                        <td width=60%>$comment',0,6</td>
                      </tr>
                    </table>
                    <table width=100% border=0>
                      <tr>
                        <td bgcolor=\"#EEE\" ><p class=fltlft><em>$email</em></p></td>
                      </tr>
                      <tr>
                        <td bgcolor=\"#EEE\" ><p class=fltlft>added on $time</p></td>
                      </tr>
                    </table></p><br>");
Here's my echo statement for displaying comments by users.  I want to add a substr (); function to limit the amount of characters of the $comment field. That way if a user makes a long comment it doesn't push the page down.

I tried putting it after the echo ();  but that didn't work. I also tried putting it before $comment and that didn't even work. I know that if I make two separate echo statements, this can be done, but the field "$comment" is displayed within a table that is part of the original echo statement, so what do I do?

Please take a look at the following code (this would work if the statement was SELECT instead of UPDATE) But I need to grab the following:

Code: [Select]
$result = mysql_query("UPDATE `AUCTIONS_MAIN` SET Current_Price = Current_Price + '$increase_price', Last_Bidder_Time = '$last_bidder_time' WHERE PId = '$id'");
//grab the new updated current price to save on different bidding history DB
while($row=mysql_fetch_array($result))
{
$current_price = $row['Current_Price'];
    }

As you can see, I need to give the new Current_Price value to the $current_price variable.
Obviously the while function is incorrect,
I would really appreciate any ideas and/or suggestions on how I can grab this value.

PS: I can't make a new query call with a select statement in order to know the new Current_Price. I need the direct updated value coming from the Update Statement, is this possible?

Thanks a lot in advance!!

I'm trying to input the results from a query into html, but I'm just getting the variable names rather than their values.  I used single quotes for the echo statement, but I think I must need to switch to double to do that.  But then I have problems with the double quotes from the class names (ex. class="SideBoxTitle"). 

Code: [Select]
<?php
// get user's videos from database
$conn = mysqli_connect($dbhost, $dbuser, $dbpass) 
or die("MySQL Error: " . mysql_error());

$query = "SELECT * FROM haas12_test.videos";

$result = mysqli_query($conn, $query)
or die ("Couldn't execute query.");

while($row = mysqli_fetch_assoc($result))
{
extract($row);

echo ' 
<div id="topBox"  class="mainVideoSideBoxes" >
    
      <div class="SideBoxTitle" ><h3> $vidtitle </h3> </div><!-- close SideBoxTitle -->
        <div class="sideBoxVidContainer"> 
            <div class="SideBoxScreenCast" > $vidurl </div><!-- close SideBoxScreenCast -->
            <div class="SideBoxDesc" ><p> $viddesc </p> </div><!-- close SideBoxDesc -->
        </div><!-- close sideBoxVidContainer -->
    
</div><!-- close mainVideoSideBoxes -->

</div><!-- close mainVideoSideBoxes -->
'; // end echo staement
}

?>

Hi, I have an app that access a MySQL database via a php script.
I noticed that INSERT was returning error but the data was being recorded successfully.
I finally traced the problem to be related with the line 
echo $conn->affected_rows;   

For some reason when it is an SQL INSERT it returns -11 but as I said the INSERTS executes successfully.

The app requesting the service sends in sequence:

char* txtSQL[]={"INSERT INTO activity (mac,jd,date,time,area,type,value) VALUES ('a9c4952de6b4',2458454,'2018-12-01','10:22','Area0002','h',130)",
                            "INSERT INTO activity (mac,jd,date,time,area,type,value) VALUES ('a9c4952de6b4',2458454,'2018-12-01','10:22','Area0002','h',130)",
                            "INSERT INTO activity (mac,jd,date,time,area,type,value) VALUES ('a9c4952de6b4',2458454,'2018-12-01','10:22','Area0002','h',130)",
                            "INSERT INTO activity (mac,jd,date,time,area,type,value) VALUES ('a9c4952de6b4',2458454,'2018-12-01','10:22','Area0002','h',130)",
                            "UPDATE activity set value=333 where value=130",
                            "SELECT sum(value) from activity where mac='a9c4952de6b4'",
                            "DELETE from activity WHERE value=333"};

I set a monitor to check what was being returned and got:

query=INSERT INTO activity (mac,jd,date,time,area,type,value) VALUES ('a9c4952de6b4',2458454,'2018-12-01','10:22','Area0002','h',130)
HttpResponse:  -   httpResponseCode: -11
query=INSERT INTO activity (mac,jd,date,time,area,type,value) VALUES ('a9c4952de6b4',2458454,'2018-12-01','10:22','Area0002','h',130)
HttpResponse:  -   httpResponseCode: -11
query=INSERT INTO activity (mac,jd,date,time,area,type,value) VALUES ('a9c4952de6b4',2458454,'2018-12-01','10:22','Area0002','h',130)
HttpResponse:  -   httpResponseCode: -11
query=INSERT INTO activity (mac,jd,date,time,area,type,value) VALUES ('a9c4952de6b4',2458454,'2018-12-01','10:22','Area0002','h',130)
HttpResponse:  -   httpResponseCode: -11
query=UPDATE activity set value=333 where value=130
HttpResponse: 4 *   httpResponseCode: 201   -------------------------------------->As can be seem the INSERTS above returned error but worked OK
query=SELECT sum(value) from activity where mac='a9c4952de6b4'
HttpResponse: 1379 *   httpResponseCode: 200
query=DELETE from activity WHERE value=333
HttpResponse: 4 *   httpResponseCode: 201

The  PHP script do ing the job i s as be low :

<?php
include('connection.php');

//these are just in case setting headers forcing it to always expire 
header('Cache-Control: no-cache, must-revalidate');

error_log(print_r($_POST,TRUE));

if( isset($_POST['query']) && isset($_POST['key']) ){                                   //checks if the tag post is there and if its been a proper form post
  header('Content-type: application/x-www-form-urlencoded');
  if($_POST['key']==$SQLKEY){                                                           //validates the SQL key
    $query=urldecode($_POST['query']);
    if(get_magic_quotes_gpc()){     //check if the worthless pile of crap magic quotes is enabled and if it is, strip the slashes from the query
      $query=stripslashes($query);
    }
    $conn = new mysqli($DB_ADDRESS,$DB_USER,$DB_PASS,$DB_NAME);    //connect

    if($conn->connect_error){                                                           //checks connection
      header("HTTP/1.0 400 Bad Request");
      echo "ERROR Database Connection Failed: " . $conn->connect_error, E_USER_ERROR;   //reports a DB connection failure
    } else {

      $result=$conn->query($query);                                                     //runs the posted query                        

      if($result === false){
        header("HTTP/1.0 400 Bad Request");                                             //sends back a bad request error
        echo "Wrong SQL: " . $query . " Error: " . $conn->error, E_USER_ERROR;          //errors if the query is bad and spits the error back to the client
      } else {
        if (strlen(stristr($query,"SELECT"))>0) {                                       //tests if it's a SELECT statement
          $csv = '';                                                                                // bug fix Undefined variable: csv
          while ($fieldinfo = $result->fetch_field()) {
            $csv .= $fieldinfo->name.",";
          }
          $csv = rtrim($csv, ",")."\n";
//********************************          echo $csv;                                                                    //prints header row
          $csv = '';

          $result->data_seek(0);
          while($row = $result->fetch_assoc()){
            foreach ($row as $key => $value) {
              $csv .= $value.",";
            }
            $csv = rtrim($csv, ",");                                                 //."\n";
          }
          echo $csv;                                                                    //prints all data rows
        } else {
          header("HTTP/1.0 201 Rows");
          echo $conn->affected_rows;       //if the query is anything but a SELECT, it will return the number of affected rows (INSERT IS  RETURNING -11)
        }
      }
      $conn->close();                                          //closes the DB
    }
  } else {
     header("HTTP/1.0 400 Bad Request");
     echo "-Bad Request";                                       //reports if the secret key was bad
  }
} else {
        header("HTTP/1.0 400 Bad Request");
        echo "*Bad Request";
}
?>

Any help will be much appreciated.
Thanks

Paulo Borges

When I run

'select 1700-price as blah from goldclose as t2 order by dayid desc limit 1'

by itself in mysql I get a numerical result: one row, one column.

In my php script, the 1700 is actually a variable. so here it is

$changequery = sprintf("select $goldprice-price as change from goldclose order by dayid desc limit 1");
$change = mysql_query(changequery);
while ($row = mysql_fetch_array($change)) {
    printf("$row[0]"); 
}

mysql_free_result($changeresult);


I get the following error,

Warning:  mysql_fetch_array(): supplied argument is not a valid MySQL result resource in <b>/root/fuzzy/htmlmain4.php on line 99

Warning:  mysql_free_result(): supplied argument is not a valid MySQL result resource in <b>/root/fuzzy/htmlmain4.php on line 103

Not sure why? All i want is to get the result of that select statement into a variable such as $change

 

I'm having issues with the following:

Code: [Select]
<?php
session_start();
$_SESSION['username']=$_POST['username'];
$_SESSION['password']=$_POST['password'];
if($_SESSION['username']=="username" && $_SESSION['password']=="password"){
if($_GET['product']=="add"){
$content.='
<p><label>Product Name:</label> <input type="text" name="product_name" size="30" />
<label>Product Price:</label> <input type="text" name="product_price" size="5" />
</p>
<p><label>Product Category:</label> <input type="text" name="product_category" size="30" /></p>
<p><label>Product Link:</label> <input type="text" name="product_link" size="30" /></p>
<p><label>Product Image:</label> <input type="text" name="product_image" size="30" /></p>
<p><label>Product Tag:</label> <input type="text" name="product_tag" size="30" /></p>
<p><label>Product Keywords:</label> <input type="text" name="keyword" size="30" /></p>
<p><label>Product Features:</label><br />
<textarea name="product_features" rows="10" cols="60"></textarea>
</p>
<p><label>Product Pros:</label><br />
<textarea name="product_pros" rows="5" cols="30"></textarea>
</p>
<p><label>Product Cons:</label><br />
<textarea name="product_cons" rows="5" cols="30"></textarea>
</p>
<p><label>Product Description:</label><br />
<textarea name="product_description" rows="10" cols="60"></textarea>
</p>
<p><label>Product Notes:</label><br />
<textarea name="product_notes" rows="5" cols="30"></textarea>
</p>
';
$logout='<div><a href="./acp_admincp.php?log-out">Log-Out</a></div>';
}
elseif($_GET['product']=="view"){
}
else{
$content.='
<a href="./admincp.php?product=add">Add New Product</a>
<br />
<a href="./admincp.php?product=view">View Products</a>
';
}
}
elseif(isset($_GET['log-out'])){
session_start();
session_unset();
session_destroy();
header("Location: ./admincp.php");
}
else{
$content='
<form action="./admincp.php" method="post">
<p><label>Username:</label> <input type="text" name="username" size="30" />';
$content.='</p>
<p><label>Password:</label> <input type="password" name="password" /></p>';
$content.='<p><input type="submit" value="Submit" name="Submit" /></p>
</form>';
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<base href="http://ghosthuntersportal.com/" />
<title>Ghost Hunter's Portal - Admin Control Panel</title>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<meta name="verify-v1" content="" />
<meta name="keywords" content="ghost, hunters, hunter, ghosts, spirit, spirits, paranormal, investigation, investigator, investigators, k2, emf, meter, kii" />
<meta name="description" content="Ghost Hunters Potal. Parnormal research equipment store." />
<meta name="author" content="Andrew McCarrick" />
<meta name="robots" content="index, follow"
<link rel="stylesheet" type="text/css" href="style.css" />
</head>
<body>
<img src="./logo.png" alt="Ghost Hunter's Portal Admin Control Panel" />
<br />
<div style="color: #AA44AA; font-size: 26px; margin-top: -30px; margin-left: 125px;">Admin Control Panel</div>
<?php
echo $logout;
echo $content;
?>
</body>
</html>

I can log-in, and get to the page with the two links on it. However, once I click one of the links it falls back to the log-in page, and it ends up being a never ending loop.

It's doing this:
Log-In --> Page with links ---> Log-In page again

Should be doing this:
Log-In --> Page with links --> Add Product page or View Products page

I can never get into the the actual sub page.

Just to be clear, the address bar actually shows product=add or product=view, but it still shows the log-in page.

Hello Everyone,
I have to change the if statements to a switch statement, in this game. Can anyone help? Thanks.

var checkKeyPressed = function (e) {
// Press key A or key D to make dog run to the left or right
// The running speed is specified by the step variable, 10 by default.
// If you replace 10 with a larger integer, the dog will run faster.

    //press A, dog runs left
    if (e.keyCode == "65") {
        if (prex[0] > 5) {
            prex[0] = prex[0] - step;
        }
    }
    //press D, dog runs right
    if (e.keyCode == "68") {
        if (prex[0] < right) {
            prex[0] = prex[0] + step;
        }
    }
};

I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here.  It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere.

<?PHP require('connect.php'); ?>

<form action ='' method='post'> <select name="id">

<?php
$extract = mysql_query("SELECT * FROM cars");
   
   while($row=mysql_fetch_assoc($extract)){
   $id = $row['id'];
   $make= $row['make'];
   $model= $row['model'];
   $year= $row['year'];
   $color= $row['color'];

echo "<option value=$id>$color $year $make $model</option>
";}?>

</select>

Which attribute would you like to change?<br />
<input type="radio" name="getchanged" value="make"/>Make<br />
<input type="radio" name="getchanged" value="model"/>Model<br />
<input type="radio" name="getchanged" value="year" />Year<br />
<input type="radio" name="getchanged" value="color"   />Color<br /><br />

   <br /><input type='text' value='' name='tochange'>
   <input type='submit' value='Change' name='submit'>

</form>

//This is where I need help...

<?PHP
if(isset($_POST['submit'])&&($_POST['tochange'])){
mysql_query("
   UPDATE cars
   SET '$_POST[getchanged]'='$_POST[tochange]'
   where id = '$_POST[id]'
         ");}?>

Hello all. I am very new to PHP, and I am not sure where to look or what I'm looking for in my current assignment.

My task is to take in two numbers between 0-100. Once I take in that number, it should state beside it "The __ was accepted."
The program should not accept any numbers greater than 100 or any characters.

Once I do this, I must take a second number and do a similar thing.

Finally, I must have a statement show up at the bottom stating which number is greater.

Essentially, I need help in determining what I should use to place parameters, and how I can keep the program from echo ing any statement until input has been taken and tested for parameters.

Any help you can provide will be greatly appreciated!