PHP - Convert Time(); To Date();

Hi,

I am trying to convert a String date into numeric date using PHP function's, but haven't found such function.
Had a look at date(), strtotime(), getdate();

e.g. Apr 1 2011  ->    04-01-2011

Could someone please shed some light on this?

Regards,
Abhishek

PHP date and time function is not showing correct time on my local system

I have the following php code

date_default_timezone_set("Africa/Lagos");

$date = date('d-m-y h:i:s');

echo "Server Time ".$date ."<br>";

echo "The time is " . date("h:i:sa")."<br>";

$current_datetime = date("Y-m-d") . ' ' . date("H:i:s", STRTOTIME(date('h:i:sa')));

echo "Current time1: ".$current_datetime . "<br>";

 

Output

Server Time 21-05-21 09:55:39
The time is 09:55:39am
Current time1: 2021-05-21 09:55:39

 

Expected Output

Server Time 21-05-21 10:55:39
The time is 10:55:39am
Current time1: 2021-05-21 10:55:3

 

Any help would be appreciated.

 

Edited May 21 by Ponel

I am having a problem with PHP displaying the correct date and time. It updates as it should, but is fast by 4min and is always displaying a date in 2004. I ran a basic php script to make sure the application im using itself is not wrong. go to lunenburgledger.com/time.php

Anybody had any ideas on where to check? The system time on the Windows Server 2003 is correct. The only thing I can think of is that it was converted to a virtual machine on vmware esxi, but the system time stayed right. Any ideas?

Thanks!

OK So I've got a datepicker that sends a date in d/m/y format. My DB stores the data in Unix Timestamp Which I can convert the date to with strtotime however this does the exact date & time.

All I want is the actual day. I've spent hours trying to convert this with just the day with mixed results...

Thanks.

I have a form that submits G

How can I convert this to string of time when I need to insert it into the database and then turn it back around when it needs to be read?

          
<option>11:00 AM</option>
<option>11:30 AM</option>
<option>12:00 PM</option>
<option>12:30 PM</option>
<option>1:00 PM</option>
<option>1:30 PM</option>


Thank you.

Hi

In sql we have dates like this 134238

In php it shows -  19:10:11  . we can make it by using date('d.m.y', $date); where $date=134238 ;

my question is how can we turn 19:10:11 in to 134238 using PHP

I have all the dates stored in my database as UTC and I want to retrieves these UTC date/time to show the local time zone. So, example, If I live in New York, I want it to show east coast time zone and not the Universal Time. Any idea?

I have a string in php:
Quote

Sat, 28 Apr 2012 05:09:45 GMT

I want to convert it to timestamp
Example: 1335594473

Hi all,

I'm having a bit of trouble a script running on a site where it converts a date of birth in a database shown like this '30/04/1993' to an actual age, for instance 18 in this case. Only the script I'm using below shows this age as 17, not 18 as it should be.

Code: [Select]
<?php
   $birthday = $row_getdets['dob']; 
    function birthday ($birthday){
    list($day,$month,$year) = explode("/",$birthday);
    $day_diff   = date("d") - $day;
    $month_diff = date("m") - $month;
    $year_diff  = date("Y") - $year;
    if ($day_diff < 0 || $month_diff < 0)
      $year_diff--;
    return $year_diff;
  }
?>

So i've tried to remedy this myself with the following:

Code: [Select]
<?php
$birthday = $row_getdets['dob'];
function birthday ($birthday){
    list($year,$month,$day) = explode("/",$birthday);
     $year_diff  = date("Y") - $year;
     $month_diff = date("m") - $month;
     $day_diff   = date("d") - $day;
     if ($month_diff < 0) $year_diff--;
else if (($month_diff==0) && ($day_diff < 0)) $year_diff--;
return $year_diff;
  }
?>
..but I'm having a syntax error (unexpected T_LINE), most probably down to my novice ability, I bet I've missed something simple. I'm still learning guys and I'd really appreciate any help at all.

while I'm reading the cell value '20/09/1980' from an excel file using phpexcel class method

 $student[$i]['d_o_b'] = $objWorksheet->getCell('G' . $intRow)->getValue();

 getting the value as '29484' pls help me to convert it into the date format again.

sorry, I know this is simple, but stuck on it...

how would one go about converting 1/21/11 to a UNIX timestamp, something like 1293035229?

and while we are at it, how to convert 1293035229 to 1/21/11 ? (i know the timestamp is wrong, just for example)


thanks!!!!!

hello, i have the following code and it is ok.  what im trying to do is convert a 2010-09-20 post from a form and have it read out as Monday September 20, 2010.

is this possible?

Code: [Select]
$dateselected="$_POST[Y]-$_POST[M]-$_POST[D]";


echo "<table border='1'>";
echo "<tr><td width='100%' colspan='4' align='center'>$_POST[M]-$_POST[D]-$_POST[Y]</td></tr>";

Hi,

Sorry, me again!

Ok, so i've got my url:
http://www.mydomain.com/?ec3_after=2010-08-01&ec3_before=2010-08-07

I've then got the following code to get the values:

$afterDateParts = split("-", $_GET['ec3_after']); 
$after = $afterDateParts[2] . " " . $afterDateParts[1] . " " . $afterDateParts[0]; 
echo $after; 

which returns:
01 08 2010 (correct for this demo)

I've then got this to convert the above into a nicer format:

$convertMe = strtotime($after);
echo date('d-M-Y', $convertMe);

But it always returns:
01 Jan 1970

For the love of god, I cannot work out why. Is it really not that simple? 

Please someone put me out my misery. I'm loosing hair by the minute! Lol

TIA

So this is a simple code that finds out the difference between two dates and displays it in number of days.

$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");

// RESULT
+272 days

 

My first question. Is it possible to remove the + sign in the result above?

Second question. Is it possible to show "months" if it's greater than 30 days? And years if the days are greater than 365?

How would I do this?

Hi. I have an input field where a date is entered, format dd-mm-yy. I need to query the database to see if this date exists. How can I convert the date to yyyymmdd before the query?

Thanks