PHP - Pulling Out My Hair!! On Php Form...
Hello all,
Would anyone know how to fix this code to work so that when a user fills out a simple form it update a row in my database? The code below doesn't get the parameters from the form. The $sql = 'UPDATE services SET `Description` = "$description1" WHERE ID=1'; line works perfect only its putting in the $description literally no form parameters?? I have a feeling I need to handle this a different way but other trys with different code were not successful. Using Myphpadmin and mysql 5.1 Thanks in advanced. Code: Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <?php $con = mysql_connect('localhost', 'DATA_BASE', 'test123'); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("DATA_BASE", $con); $sql = 'UPDATE services SET `Description` = "$description1" WHERE ID=1'; mysql_query($sql, $con); if($_POST['Submit']){ $description1=$description1=$_POST['description1']; $price1=$_POST['price1']; mysql_error(); header("location:updates.php"); exit; } mysql_close(); ?> <html> <head> <title>Updates Page</title> </head> <body bgcolor="#A55125"> <div align="center"> <form method="post" action="<? echo $PHP_SELF; ?>"> <span class="forms">Description:</span><br /> <textarea name="description1" cols="40" rows="5" > </textarea><br> <span class="forms">Price:<br /> </span> <input name="price1" type="text" id="price1"><br /> <input type="submit" value="Submit" /> </form> </div> </body> </html> MOD EDIT: [code] . . . [/code] tags added. Similar TutorialsHi all: I have been going nuts trying to get this to work. I have gone through many attempts based on internet searches and examples that simply do not work. I have files stored in my MySQL db. The files cna be of any type and are being displayed in a listed report. The files are hyperlinked and clickable, but here is the issue: When I click on a file in: http://development.products-and-services.ca/cms/test.php I get: http://development.products-and-services.ca/cms/test2.php?content=DHall_CV_webdev_eng.pdf as a blank page result. The objective is to get a file download alert or to see the file in the browser. Any ideas? Below are two pages...Post.php. and Posted.php the posted page checks and makes sure everything is filled out and makes sure that the link has not been already added. The problem I am having is that it is not pulling over the link information. Every time you hit submit it drops down and goes to saying that you forgot to fill something in and I have it showing everything right now so when that happens I can see what is not going through and the $link never comes through. Any ideas? if anyone needs a better explanation please post and I will try to explain better....basically I am trying to post and everything posts but the link. POST.PHP Code: [Select] <h1>Post</h1> <div class="descr"></div><form method="post" action="posted.php"> <table align="center"> <tr> <td> Youtube Embed Link </td> <td> <input name="link" type="text" id="link"/> </td> </tr> <tr> <td> Title Of Song </td> <td> <input name="title" type="text" id="title" /> </td> </tr> <tr> <td> Author </td> <td> <input name="author" type="text" id="author" /> </td> </tr> <tr> <td> Text: </td> <td> <input name="information" type="text" id="information" /> <br /> </td> </tr> <tr> <td colspan="2" align="center"> <br> <input name="submit" type="submit" value="Post" /> </td> </tr> </table> </form> POSTED.PHP Code: [Select] <?php //msut be logged in page session_start(); if ($_SESSION['username']) { echo""; } else die("You must log in first!"); //form information $submit = $_POST['submit']; $row4 = $_SESSION['username']; // form data $link = strip_tags($_POST['link']); $information = strip_tags($_POST['information']); $title = strip_tags($_POST['title']); $author = strip_tags($_POST['author']); $date = date('Y-m-d'); //Connect To Database $hostname=''; $username2=''; $password2=''; $dbname=''; mysql_connect($hostname,$username2, $password2) OR DIE ('Unable to connect to database! Please try again later.'); mysql_select_db($dbname); $querycheck = "SELECT * FROM videos WHERE username='$row4'"; $result = mysql_query($querycheck); while($rowz = mysql_fetch_array($result)) $linkcheck = $rowz['link']; if ($submit) { if ($link&&$information&&$title&&$author) { if ($link == $linkcheck) { die ("This link has already been posted."); } else { //Connect To Database $hostname=''; $username2=''; $password2=''; $dbname=''; mysql_connect($hostname,$username2, $password2) OR DIE ('Unable to connect to database! Please try again later.'); mysql_select_db($dbname); $queryreg = mysql_query("INSERT INTO videos Values ('','$row4','$link','$title','$author','$information','$date')"); } } else { die ("You forgot to put something in the link/title/author/text box. $information $title $link $author"); } } ?> Hey Guys, Struggling again with some full text searching etc. I have a MySQL statement in my code but it's not working. Now, it's probably something extremely simple, but I just can't see it. Code: [Select] //Now we search for our search term, in the field the user specified so we know how many pages to link to at the bottom $data = mysql_query("SELECT * , MATCH ('status', 'date', 'species', 'breed', 'sex', 'primary_colour', 'colour', 'distinctive_traits', 'fur_length', 'age', 'desexed', 'microchipped', 'suburb', 'pound_area', 'contact', 'link') AGAINST ('%$find%') AS score FROM animal_info WHERE MATCH ('status', 'date', 'species', 'breed', 'sex', 'primary_colour', 'colour', 'distinctive_traits', 'fur_length', 'age', 'desexed', 'microchipped', 'suburb', 'pound_area', 'contact', 'link') AGAINST ('%$find%') $max"); //Make sure we have some results to pass $result = mysql_query($data) or die("No Results Here"); //And we display the results of the search query as long as there is some while($row = mysql_fetch_array($result)) { //Build the HTML for the results in the table Now, my second question is that I've made a quick template for this, but I'm not sure how to format the "or die()" statement so it looks pretty with the header, footer etc. Code: [Select] $result = mysql_query($data) or die("**SOME HTML FORMATTING IN HERE**"); Any help, once again, would be greatly appreciated! Cheers, Dave So I'm having issue with trying to pull the ID from my database out correctly. This is the ideal way I want the ID to be pulled. http://a7.sphotos.ak.fbcdn.net/hphotos-ak-snc6/226659_219275201434540_100000561868489_827151_3402533_n.jpg But then it always pulls the ID like this and stacks the number ID ontop of each other and I want it to have separate DIVS. http://photos-e.ak.fbcdn.net/hphotos-ak-snc6/226659_219275204767873_100000561868489_827152_3422285_n.jpg This is the code that I'm using. Tell me what I'm doing wrong. Code: [Select] <? mysql_connect("localhost", "mysql_user", "mysql_password") or die("Could not connect: " . mysql_error()); mysql_select_db("mydb"); $result = mysql_query("SELECT id, name FROM mytable"); echo "<div class=\"body_resize\"><div class=\"left\"><br /><span class='date'>$timedate</span><br /><br />"; while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { printf("<h2>#%s</h2>", $row["id"], $row["name"]); } mysql_free_result($result); echo "<br /><div class=\"comment_gravatar left\"><img alt=\"\" src=\"http://photos-b.ak.fbcdn.net/hphotos-ak-snc6/229186_219276548101072_100000561868489_827154_8135363_n.jpg\" height=\"32\" width=\"32\" /></div><p>Posted By $name<br><br /><p>$message</p><br></div><div class=\"clr\"></div></div>"; if ($ip==$userip && $delcom==1) { ?> I can't figure out how to pull the number from a form name Unfortunately I cant use substr(); because non of the names are the same length... these are the form names cat_sub_id_1 cat_name_1 cat_order_1 cat_sub_id_2 cat_name_2 cat_order_2 cat_sub_id_3 cat_name_3 cat_order_3 this is a list of the numbers that I need to be pulled out. I am having trouble pulling a youtube embedded code from my database. Everything else comes out fine however it just doesnt pull anything out where the embedded code is supposed to be. Any ideas I put the code below. All help would be greatly appreciated, also if anyone is feeling generous and would like to help me some more please message me I have a couple other small questions. Code: [Select] <?php //open database $connect = mysql_connect("Database","name","password") or die("Not connected"); mysql_select_db("database") or die("could not log in"); $query = "SELECT * FROM boox ORDER BY date DESC"; $result = mysql_query($query); // Get the page number, if none is set - it is 0 if( isset($_GET['page']) ) { $page =$_GET['page']; } else { $page = 0; } $resultsPerPage = 15; $num = mysql_num_rows($result); // amount of rows $loops = $page*$resultsPerPage; // starting loops at.. while ($loops < $num && $loops < ($page+1)*$resultsPerPage ) { $link = mysql_result($result,$loops,"link"); // get result from the 'Title' field in the table $username = mysql_result($result,$loops,"username"); // get result from the 'Content' field in the table $messsage = mysql_result($result,$loops,"message"); $date = mysql_result($result,$loops,"date"); if ($pagelimit == 0) { $pagelimit == 1; } if ($pagelimit <= 15) // echo stuff here $loopz = $loops + 1; echo "   </br><align='left'><table width='297' height='900' border='1' align='center' bgcolor='#111'> <tr> <td>$loopz. </br> $message </br> Posted By: $username $date </td> </tr> </table></br><br>"; $count++ ; $pagelimit++; $loops++; } if ( $page!=0 ) // Show 'Previous' link { $page--; $prevpage = ($page + 1); echo "<br><br><br><a href='index.php?page=$page'>Previous $prevpage </a>"; $page++; } if ($loops > 5&&($page+1)*$resultPerPage < $num ) // Show 'next' link { $page++; $nextpage = ($page + 1); echo "<a href='index.php?page=$page'> Next $nextpage</a>"; } ?> FOr some reason i cant pull data from an XML file to insert into the database, it works without error just adds a blank value in the database? i have this code at the moment, i guess arrayValue[71] is the value i need to pull and add to the "TABLE2" table, but when i run the script it just adds a blank value in the database? <?php include "connect.php"; //Price check Isle 9001! Query EVE-Central API. Example XML file is: http://api.eve-central.com/api/marketstat?typeid=35®ionlimit=10000002 $queryItemList = mysql_query("SELECT * FROM TABLE2;") or die(mysql_error()); $rowCount = mysql_num_rows($queryItemList); $s=0; $typeArray = array(); $region = "regionlimit=10000002"; while($s<$rowCount){ $typeID = mysql_result($queryItemList,$s,"typeID"); echo $typeID."<br />"; //echo "start<br />"; $reader = new XMLReader(); //echo "initialized XMLReader<br />"; $url = "http://api.eve-central.com/api/marketstat?typeid=".$typeID; echo $url.$region."<br />"; $reader->open($url.'&'.$region); $t=0; $arrayName = array(); $arrayValue = array(); while ($reader->read()) { //echo $reader->name; $name = $reader->name; $arrayName[$t] = $name; if ($reader->hasValue) { //echo ": " . $reader->value."<br />"; $value = $reader->value; $arrayValue[$t] = $value; } $t++; } echo $arrayValue[71]; $import="UPDATE TABLE2 SET marketPrice='$arrayValue[71]' WHERE typeID='$typeID';"; mysql_query($import) or die(mysql_error()); $s++;; } print_r($typeArray); /*print_r($arrayName); echo "<br />"; echo "<br />"; echo "<br />"; print_r($arrayValue);*/ ?> an example XML file would be: Code: [Select] <!-- Automatically generated data from EVE-Central.com --> <!-- This is the new API :-) --> − <evec_api version="2.0" method="marketstat_xml"> − <marketstat> − <type id="24692"> − <all> <volume>4.00</volume> <avg>152500000.00</avg> <max>152500000.00</max> <min>152500000.00</min> <stddev>0.00</stddev> <median>152500000.00</median> <percentile>0.00</percentile> </all> − <buy> <volume>0.00</volume> <avg>0.00</avg> <max>0.00</max> <min>0.00</min> <stddev>0.00</stddev> <median>0.00</median> <percentile>0.00</percentile> </buy> − <sell> <volume>4.00</volume> <avg>152500000.00</avg> <max>152500000.00</max> <min>152500000.00</min> <stddev>0.00</stddev> <median>152500000.00</median> <percentile>152500000.00</percentile> </sell> </type> </marketstat> </evec_api> im looking at pulling the following value from the <sell> section: Code: [Select] <median>152500000.00</median> i am guessing the above should be arrayValue[71] but for some reason its not picking it up. any help on this would be greatly appreciated as im lost in this script. hello. please could someone help me with this conundrum im trying to pull my content dynamically. im almost there but im stuck with some code. so i have a layout with 3 columns and in each column i have a place holder. ph01, ph02, ph03 each page has its own id and depending on what the page id is i what to pull different elements into the 3 placeholders. so for this code in the database i have the following: table name: placeholders pages_id = page id ph_number = placeholder number contElements_id = element ids id pages_id ph_number contElements_id 1 1 1 1, 2, 3 2 1 2 4, 5, 6 3 1 3 7, 8, 9 table name: contelements name = name of the element id name 1 E1 2 E2 3 E3 4 E4 5 E5 6 E6 7 E7 8 E8 9 E9 SO, page_ID=1 has 3 placeholders and they should show: ph01 should display = E1, E2, E3 ph02 should display = E4, E5, E6 ph03 should display = E7, E8, E9 this is the code im trying to put together. on the page im using this include function in the left, center and right columns. Code: [Select] $phNo = "1"; echo include_admin_contElements($phNo, $pageID); $phNo = "2"; echo include_admin_contElements($phNo, $pageID); $phNo = "3"; echo include_admin_contElements($phNo, $pageID); now this is where the problem is.... i think in the function file i have this but its a mess.. Code: [Select] function include_admin_contElements($phNo, $pageID){ $PH = Placeholders::find_all(); foreach ($PH as $PHs){ $PHid = $PHs->id; $PHpid = $PHs->pages_id; $PHce = $PHs->contElelments_id; $PHn = $PHs->ph_number; if($pageID == $PHpid){ $CE = Contelements::find_by_PHce($PHce); foreach ($CE as $CEs){ echo $CEid = $CEs->id; echo $CEname = $CEs->name; } } } } - so the idea is i get $phNo, $pageID from the page, - then find all the placeholders in the database Quote Placeholders::find_all(); - then if the $pageID is the same as the $PHpid in the placeholder database Quote if($pageID == $PHpid){ get the content elents for that page. - then i want to get the elements that belong to that page using Quote Contelements::find_by_PHce($PHce); but that does not work Code: [Select] public static function find_by_PHce($PHce=0){ $sql = "SELECT * FROM ".self::$table_name." WHERE id=".$PHce.""; $result_array = self::find_by_sql($sql); return $result_array; } anyway... im stuck. this code doesn't even seperate the 3 different placeholders. it needs a more experienced eye.. its a mess please help thanks ricky Code: [Select] id: 20 Reason: this is a test id: 21 Reason: Tests id: 22 Reason: Lolcatz id: Reason: id: Reason: id: Reason: id: Reason: id: Reason: id: Reason: id: Reason: id: Reason: id: Reason: id: Reason: id: Reason: id: Reason: id: Reason: id: 36 Reason: Test As you can see on the 2nd code box there are id's 20,21,22 and 36 in the database the rest are not active in the database. i am using using Code: [Select] for to pull out the id that starts with the lowest value in the database, and only have it run until it gets to the maximum value. Code: [Select] for ($id=$set_min; $set_max<=7; $id++) { // $id=$set_min is pulling the smallest value and $set_max is pulling the maximum value so it stops after it gets to 36 $query=mysql_query("SELECT * FROM posted WHERE id = $id"); $query_row=mysql_fetch_array($query); $reason = $query_row[reason]; $pulled_id = $query_row[id]; $pulled_pic22 = $query_row[picture]; $href_pull = "<a href=" . "search.php?id=" . "$id" .">"; echo "<td>" . $href_pull . "<img src=$pulled_pic22 height=200 width=150 />" . "</td>"; } how would i make it so i do not pull the values 23-35 which are not in the active database. Example: http://dev.hackmuch.com/of-the-day/search.php?id=36 Code: [Select] <?php ob_start(); session_start(); $pagerank=2; if ($rank < $pagerank){ header('Location:main.php?id=lowrank.php'); } else{ $name1 = $_GET["name"]; $type2 = $_GET['type']; Echo "Your seach for ".$name1." gave the following results: "; $records_per_page = 15; $total = mysql_result(mysql_query("SELECT COUNT(*) FROM systems WHERE '$type2' LIKE '%$name1%'"), 0) or die(mysql_error()); $page_count = ceil($total / $records_per_page); Echo $total." Records Found"; echo "<table border=0>"; $page = 1; if (isset($_GET['page']) && $_GET['page'] >= 1 && $_GET['page'] <= $page_count) { $page = (int)$_GET['page']; } $skip = ($page - 1) * $records_per_page; $result = mysql_query("SELECT * FROM systems WHERE $type2 LIKE '%$name1%' ORDER BY Security DESC LIMIT $skip, $records_per_page") or die(mysql_error()); echo "<table border=1>"; echo "<td>System Name</td><td>Security</td><td>Class</td>"; while ($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td valign =top>".$row['System Name']."</td>"; echo "<td valign =top>".round($row['Security'],1)."</td>"; echo "<td valign =top>".$row['System Type']."</td>"; echo "</tr>"; } echo "</table>"; echo "<br>"; for ($i = 1; $i <= $page_count; ++$i) { echo '<a href="main.php?id=' . $_GET['id'] .'&name='.$name1.'&type='.$type1. '&page=' . $i . '">' . $i . '</a> '; } } ?> The above code takes data entered in a form and is suppose to show the matching results, but no records are showing, it works when I replace the $name1 and $type2 with the actual values, any ideas? Good evening, This has been bugging me for 24 hours now. I have created 2 web applications. The first one is the dummy, and the second one is the final. Basically, this two web applications does the same, just a few modifications made on the final one. I have a process of pulling out of information from the database should the user would want to modify a field. I have a problem though, the dummy one works perfectly, but the new one don't. In fact, if I use the dummy php file together with the new files, the dummy won't be working. But if I use it together with the old files, it works perfectly fine. This is the error I am getting: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in C:\xampp\htdocs\invent-asia\edit_client.php on line 46 <?php include("dbconnection.php"); if(isset($_POST["btnSubmit"])) { $id = $_POST["id"]; $territory = $_POST["territory"]; $job_title = $_POST["job_title"]; $area_of_work = $_POST["area_of_work"]; $employer = $_POST["employer"]; $location = $_POST["location"]; $job_title = $_POST["job_title"]; $date_posted = $_POST["date_posted"]; $closing_date = $_POST["closing_date"]; $department = $_POST["department"]; $gender = $_POST["gender"]; $first_name = $_POST["first_name"]; $last_name = $_POST["last_name"]; $title = $_POST["title"]; $telephone = $_POST["telephone"]; $address_1 = $_POST["address_1"]; $address_2 = $_POST["address_2"]; $address_3 = $_POST["address_3"]; $country = $_POST["country"]; $city = $_POST["city"]; $postal_code = $_POST["postal_code"]; $website = $_POST["website"]; $email_address = $_POST["email_address"]; $comment_by_cg = $_POST["comment_by_cg"]; $date_emailed = $_POST["date_emailed"]; $mailing_comments = $_POST["mailing_comments"]; $telesales_comments = $_POST["telesales_comments"]; $query = "UPDATE contacts SET territory= '".$territory."', job_title = '".$job_title."', area_of_work = '".$area_of_work."', employer = '".$employer."', location = '".$location."', job_title = '".$job_title."', employer = '".$employer."', date_posted = '".$date_posted."', department = '".$department."', closing_date = '".$closing_date."', gender = '".$gender."', first_name = '".$first_name."', last_name = '".$last_name."', title = '".$title."', telephone = '".$telephone."', address_1 = '".$address_1."', address_2 = '".$address_2."', address_3 = '".$address_3."', country = '".$country."', city = '".$city."', postal_code = '".$postal_code."', website = '".$website."', email_address = '".$email_address."', comment_by_cg = '".$comment_by_cg."', date_emailed = '".$date_emailed."', mailing_comments = '".$mailing_comments."', telesales_comments = '".$telesales_comments."' WHERE id = '".$id."'"; mysql_query($query) or die(mysql_error()); echo "<script> alert('You have successfully updated a record'); window.location = 'view.php'; </script>"; } $query = "SELECT * FROM contacts WHERE id = '".$_GET["id"]."'"; $result = mysql_query($query, $connection); if(mysql_num_rows($result) > 0) - THIS IS THE 46th LINE IN THE CODE { $territory = mysql_result($result,0, "territory"); $job_title = mysql_result($result, 0, "job_title"); $area_of_work = mysql_result($result, 0, "area_of_work"); $employer = mysql_result($result, 0, "employer"); $status = mysql_result($result, 0, "status"); $location = mysql_result($result,0, "location"); $department = mysql_result($result,0, "department"); $date_posted = mysql_result($result,0, "date_posted"); $closing_date = mysql_result($result,0, "closing_date"); $gender = mysql_result($result,0, "gender"); $first_name = mysql_result($result,0, "first_name"); $last_name = mysql_result($result,0, "last_name"); $title = mysql_result($result,0, "title"); $telephone = mysql_result($result,0, "telephone"); $address_1 = mysql_result($result,0, "address_1"); $address_2 = mysql_result($result,0, "address_2"); $address_3 = mysql_result($result,0, "address_3"); $city = mysql_result($result,0, "city"); $country = mysql_result($result,0, "country"); $postal_code = mysql_result($result,0, "postal_code"); $website = mysql_result($result,0, "website"); $email_address = mysql_result($result,0, "email_address"); $comment_by_cg = mysql_result($result,0, "comment_by_cg"); $date_emailed = mysql_result($result,0, "date_emailed"); $mailing_comments = mysql_result($result,0, "mailing_comments"); $telesales_comments = mysql_result($result,0, "telesales_comments"); } ?> Can anyone help me solve this issue? This is the only feature in my project that is left bugged Your quick response is well appreciated. Thank you very much I am pulling records from a mysql db. Example Output: Team A= Our Team Team b = An opponent team Team A score = 7 Team B score = 8 Team A = Our Team Team b = Another Opponent Team A score = 3 Team B score = 1 What I need now is to add ONE more output, which is whether this is a "WIN" or a "LOSS". Should I add a field into the table that calc's this? If so, how? Please be specific. Or, should I use php to compare Team A score vs Team B score PER every record and then insert this new variable into the output. If so, how do I create a new variable value for every single output in the table? I know ultimately that this is a IF THEN type of calc, but can't quite figure out how specifically. Please be specific. Thanks Hi the I have a PDF form that generates an XFDF file (form field valies in XML form) and I am passing it to PHP for processing. I am having trouble pulling a specific value from the XML block because of the way that the XML data is generated and organized. Please see a sample of the XML block below: 'test.xml' file: Code: [Select] <?xml version="1.0" encoding="UTF-8"?> <xfdf xmlns="http://ns.adobe.com/xfdf/" xml:space="preserve"> <annots/><fields> <field name="Non"> <value>Off</value> </field> <field name="PayRequest"> <value>XYZ</value> </field> From the above XML snip it, once it's sent to PHP, I would like to somehow reference the "PayRequest" field value and retrieve the value "XYZ" and assign it to a variable. I have been kicking around some code that I thought should work, but doesn't appear to. If anyone could offer any insight to get it working that would be greatly appreciated. PHP Code: Code: [Select] $prq_ret = simplexml_load_file('test.xml'); foreach($prq_ret->xpath("//field[@name='PayRequest']") as $item) { $row = simplexml_load_string($item->asXML()); //print $item->value; print $row; } So I am trying to pull the first image that was uploaded to the database. But for some reason this only works part of the time and if you delete any image in the database it seems to just pic another another random one. Any suggestions? <?php { $row = getad(); header("Content-type: image/jpeg"); $pic = ($row['image']); print "$pic"; } function getad() { $ads = array(); mysql_connect("localhost","******","********"); mysql_select_db("users"); $query = "SELECT image FROM image_ads"; $result = mysql_query($query); $i = 0; while($row = mysql_fetch_array($result)) { $i ++; $ads[$i] = $row; } $id = date("z"); $index = $id % $i + 1; mysql_close(); return $ads[$index]; } ?> Hi Everyone, Let me start by saying i need any help put to me in dumb person terms, i know nothing but the bare bare basics of most web coding let alone php, enough to make very simple pages and forms. On to my problem... What i am aiming for us a single web page which takes a list of names from a file, generates a 2 column table, makes the second column into boxes where data can be entered in to, then i want it to be submitted to email in the form of a html email, the email doesn't need any fancy formatting or colour scheme, just want the the table of names and entered information sent Now this is how far i have got (with help obviously): Code: [Select] <body> <h1 align="center"><u>7B Praise Points</u></h1> <div id="contact-wrapper"> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>" id="contactform"> <?php $file = file("7B.txt"); $count = 0; print "<table cellspacing='2'>\n <tr><td>Student Name</td><td>Number of Praise Points</td></tr>\n"; foreach($file as $line){ $line = trim($line); $split = split("\t",$line); print "<tr>\n<td>$split[0]<input name='name$count' type='hidden' value='$split[0]'></td>\n<td>$split[1]<input name='points$count' type='hidden' value='$split[1]'></td>\n</tr>"; $count++; } print "</table>"; ?> <p> <input name="submit" type="submit" value="Submit"> </p> </form> </div> </body> So i've got it generating the table from the list of names in the file called "7B.txt" all i need to be able to do is making the second column in to a data entry box and generating the email Starting with the first problem of making the second column in to data entry boxes how do i go about doing this? Thanks Hi. I am trying to figure out the best approach to pull THE most recent record for display, and ONLY the most recent one. I am really not sure how to go about doing this. Ive just started into stored procedure programming and php, but havent found anything yet on this one. Thanks. I'm not sure I know how to explain what I want to allow you to understand. I'm working on a ventilation app that has different fan sizes. In the input php file I have a dropdown list that's populated by what's in the database. I'd like a results page that lists the fan size and number of each size and the cfm's each fan kicks out. the problem is that I don't know how to do anything with it other than hard code it. What I'd like, is for it to also pull all of the fan sizes and list them, that way the database can be fluid. This is the code I'd like to replace with some sort of loop. //9" fan $results = mysql_query("SELECT * FROM fan WHERE size=9", $link); while ($row = mysql_fetch_array($results)) { $capacity9 = $row['capacity']; }; //--------------------------------------------------------- //10" fan $results = mysql_query("SELECT * FROM fan WHERE size=10", $link); while ($row = mysql_fetch_array($results)) { $capacity10 = $row['capacity']; }; //--------------------------------------------------------- //14" fan $results = mysql_query("SELECT * FROM fan WHERE size=14", $link); while ($row = mysql_fetch_array($results)) { $capacity14 = $row['capacity']; }; //--------------------------------------------------------- //16" fan $results = mysql_query("SELECT * FROM fan WHERE size=16", $link); while ($row = mysql_fetch_array($results)) { $capacity16 = $row['capacity']; }; //--------------------------------------------------------- //18" fan $results = mysql_query("SELECT * FROM fan WHERE size=18", $link); while ($row = mysql_fetch_array($results)) { $capacity18 = $row['capacity']; } //--------------------------------------------------------- //20" fan $results = mysql_query("SELECT * FROM fan WHERE size=20", $link); while ($row = mysql_fetch_array($results)) { $capacity20 = $row['capacity']; }; //--------------------------------------------------------- //24" fan $results = mysql_query("SELECT * FROM fan WHERE size=24", $link); while ($row = mysql_fetch_array($results)) { $capacity24 = $row['capacity']; }; //--------------------------------------------------------- //36" fan $results = mysql_query("SELECT * FROM fan WHERE size=36", $link); while ($row = mysql_fetch_array($results)) { $capacity36 = $row['capacity']; }; This topic has been moved to Other Libraries and Frameworks. http://www.phpfreaks.com/forums/index.php?topic=355580.0 I am creating a music blogging site however the main page will only show one video the code is below anyone have any ideas? " <?php //open database $connect = mysql_connect("******","username","password") or die("Not connected"); mysql_select_db("collegebooxboox") or die("could not log in"); $query = "SELECT * FROM boox ORDER BY date DESC"; $result = mysql_query($query); // Get the page number, if none is set - it is 0 if( isset($_GET['page']) ) { $page =$_GET['page']; } else { $page = 0; } $resultsPerPage = 15; $num = mysql_num_rows($result); // amount of rows $loops = $page*$resultsPerPage; // starting loops at.. while ($loops < $num && $loops < ($page+1)*$resultsPerPage ) { $link = mysql_result($result,$loops,"link"); // get result from the 'Title' field in the table $username = mysql_result($result,$loops,"username"); // get result from the 'Content' field in the table $messsage = mysql_result($result,$loops,"message"); $date = mysql_result($result,$loops,"date"); if ($pagelimit == 0) { $pagelimit == 1; } if ($pagelimit <= 15) // echo stuff here $loopz = $loops + 1; echo "   </br><align='left'><table width='297' height='900' border='1' align='center' bgcolor='#111'> <tr> <td>$loopz. $link </br> $message </br> Posted By: $username $date </td> </tr> </table></br><br>"; $count++ ; $pagelimit++; $loops++; } if ( $page!=0 ) // Show 'Previous' link { $page--; $prevpage = ($page + 1); echo "<br><br><br><a href='index.php?page=$page'>Previous $prevpage </a>"; $page++; } if ($loops > 5&&($page+1)*$resultPerPage < $num ) // Show 'next' link { $page++; $nextpage = ($page + 1); echo "<a href='index.php?page=$page'> Next $nextpage</a>"; } ?> " This is working just fine on a single page. It gives me all information I need. But I want to send an email with it. Although I couldn`t figure out how can I do it Code: [Select] $db = new mysqli('localhost', 'root', '', 'panel'); $sql = "select * from detail"; $read = $db->query($sql); <table style="border:0;width:600px;"> <tr> <td width="50px">Who</td> <td width="150px">Time</td> <td width="300px">What</td> </tr> <?php while($wr = mysqli_fetch_array($read)) { echo' <tr> <td>'.$wr['Who'].'</td> <td>'.$wr['Time'].'</td> <td>'.$wr['What'].'</td> </tr> '; } ?> |