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PHP - Issue In Duplicate Display Data
Hi...
I encountered problem in my query and while loop my data was duplicates when I join 2 tables, because the one field that I need to display is from another table. here is my code: Code: [Select] <div> <table> <thead> <th>Items</th> <th>Sub Items</th> <th>Item Code</th> <th>Demanded Qty</th> <th>UoM</th> <th>Class</th> <th>Description</th> <th>BIN Location</th> </thead> <?php $sql = "SELECT Items FROM bom_items ORDER BY Items"; $res_bom = mysql_query($sql, $con); while($row = mysql_fetch_assoc($res_bom)){ echo "<tr> <td style='border: none;font-weight: bold;'> $row[Items]</td> </tr>"; //$sql = "SELECT SubItems, ItemCode, UoM, Class, Description FROM bom_subitems WHERE Items = '$row[Items]' ORDER BY Items"or die(mysql_error()); //$sql = "SELECT DISTINCT bs.SubItems, bs.ItemCode, bs.UoM, bs.Class, bs.Description,w.BINLocation FROM bom_subitems bs LEFT JOIN wms w ON bs.Items = w.Items WHERE bs.Items = '$row[Items]' AND w.Items = '$row[Items]' ORDER BY bs.Items, w.Items"or die(mysql_error()); $sql = "SELECT DISTINCT bs.SubItems, bs.ItemCode, bs.UoM, bs.Class, bs.Description,w.BINLocation FROM bom_subitems bs, wms w WHERE bs.Items = '$row[Items]' AND w.Items = '$row[Items]' ORDER BY bs.Items, w.Items"or die(mysql_error()); $res_sub = mysql_query($sql, $con); while($row_sub = mysql_fetch_assoc($res_sub)){ echo "<tr> <td style='border: none;'> </td> <td style='border: none;'> $row_sub[SubItems]</td> <td style='border: none;'> $row_sub[ItemCode]</td> <td> </td> <td style='border: none;' size='3'> $row_sub[UoM]</td> <td style='border: none;'> $row_sub[Class]</td> <td style='border: none;'> $row_sub[Description]</td> <td style='border: none;'> $row_sub[BINLocation]</td> </tr>"; } } ?> I will attach my sample page. Thank you Similar TutorialsI'm pulling data from an xml file and I'm getting a lot of duplicates. How can I remove the duplicates from the query? Code: [Select] foreach($xml->category->subcategory as $category){ echo $category[id]; }//end foreach Hi everybody, I have a problem and was wondering if I could pick your brains. My situation is that I am making a fitness website and one feature is that the user can set themselves targets. Now each target has some fields that are mandatory (for example the date to be completed) and some fields that are unique to each target (for example if the target is weight loss I will need to grab the current weight/target weight fields). Just to make it clear I have all fields in the same database table. So I have written a script that displays that users current targets they have set. It grabs all the data correctly but it duplicates the display and although I am pretty new to php even I can tell the code if not best practise because I have a query inside a loop and a loop inside another loop. Here is the code I have done so far: Code: [Select] //Get target types from database for that particular user $get_user_targets = mysql_query("SELECT target_type FROM user_targets WHERE user_id='$id'") or die (mysql_error()); while ($row = mysql_fetch_array($get_user_targets)){ $target_type_display = $row['target_type']; //If the target type is equal to Weight Loss run this script to get all the information and make a display if($target_type_display == 'Weight Loss'){ //Search the database for all weight loass goals $weight_loss_display_sql = mysql_query("SELECT current_weight, target_weight, target_date, date_set, extra_info FROM user_targets WHERE user_id='$id' AND target_type='$target_type_display'") or die (mysql_error()); //Put the data from the query into page variables while($row1 = mysql_fetch_array($weight_loss_display_sql)){ $current_weight_loss_dis = $row1['current_weight']; $target_weight_loss_dis = $row1['target_weight']; $weight_loss_date_set_dis = $row1['date_set']; $weight_loss_target_date_dis = $row1['target_date']; $weight_loss_extra_info_dis = $row1['extra_info']; //Convert date_set into ago time $convertedTime = ($myObject -> convert_datetime($weight_loss_date_set_dis)); $weight_loss_set = ($myObject -> makeAgo($convertedTime)); //Construst a display out of the collected variables $weight_loss_display .= '<div class="blackText" style="width: 475px"> <table width="475px" class="blackText"> <tr><td class="profileUsername" colspan="2">'.$target_type_display.'</td></tr> <tr><td width="250px">Current Weight:</td><td width="225px">'.$current_weight_loss_dis.'</td></tr> <tr><td>Target Weight:</td><td>'.$target_weight_loss_dis.'</td></tr> <tr><td>Date for completion:</td><td>'.$weight_loss_target_date_dis.'</td></tr> <tr><td>'.$weight_loss_extra_info_dis.'</td><td><h6>Date set: '.$weight_loss_set.'</h6></td></tr> </table> </div>'; } } } So far it just checks for a weight loss goal and I was going to expand the code with more if statements for each of the other types of target. So my questions a 1)Can anybody see why the data is displaying twice? 2) Is there a better way of doing this? (NOTE: im not too worried that the code isn't best practise, I just want to get it functioning properly) Thanks in advance for any help Hey guys, not sure what's gone wrong here, but this displays the select query twice on my page. Code: [Select] <?php $result = mysql_query("SELECT * FROM members WHERE Username='$_SESSION[Username]'") or die(mysql_error()); while($row = mysql_fetch_array( $result )) { echo '<b>Resources</b><br />'; echo 'Wood: ' . $row['res1'] . ' <br />'; echo 'Iron: ' . $row['res2'] . ' <br />'; } ?> Displays as: Resources Wood: 2000 Iron: 1000 Resources Wood: 0 Iron: 0 The first set of numbers are correct, but I'm not sure where the second lot are been called from? Thanks in advance. This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=327017.0 Hello. What I have created is a menu with links. The links will display content on the page from a database. I have the links with id displayed, but nothing is displayed when the link is clicks. I have seen isset() and $_GET used but not a form and I don't know how to change the code to allow the display of data using ID. My site is local, and I am using XAMPP. The database connections work. This is my code:
// query
$query = "SELECT * FROM topmenu ORDER BY id ASC";
$row = $PDO->query($query);
....
<table class="topmenu">
<tr>
<td>
<h1 class="siteName">site title</h1>
</td>
<?php
foreach($row as $data) {
?>
<td><a href="index.php?id=<?php echo $data['id']; ?>">
<?php echo $data['menuheader']; ?>
</a></td>
<?php
}
?>
</tr>
</table>
As a beginner, I would appreciate any help, no criticism of my code please! Also, is there a way of hiding the id in the url? Thanks in advance. Hi all. The following is a function to get and display data. However, I've hit a wall in my progress. It's only printing out one field. I need to have it print out every retrieved field. Any help is appreciated. function get_data($table_name){ $result=mysql_query("SELECT * FROM $table_name"); $num=mysql_num_rows($result); $i=0; while($i < $num){ $fields=mysql_fetch_field($result,$i); $display_fields=mysql_result($result,$i,$fields->name); echo $display_fields; $i++; }; }; I realized that (I think) I need the $display_fields var to be concatenated with the $i variable so there's a unique var name for each field retrieved from the mysql_fetch_field line. Any ideas? Hello, I just reach the ultimate high in frustration because i can not display all the data from my database in a table using php. Im trying to display all the members from my database (id, username, email and account type) in my admin cp, and what is happening is that i am displaying all my data in one td. (Ex, in the <td></td>, it will display all the usernames at once, rather than separating them). Code: [Select] <?php include_once "../config.php"; include_once "admin_check.php"; $get_members = mysql_query("SELECT * FROM members ORDER BY id"); while ($row = mysql_fetch_array($get_members)) { $id .= $row['id']; $username .= $row['username']; $account_type .= $row['account_type']; $email .= $row['email']; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Welcome Admin!</title> </head> <body> <h1>Welcome admin! <a href='../index.php'> Click here to go back! </a></h1> <table cellspacing="5" cellpadding="5" style="border: black thin solid" align="center"> <tr> <td>ID</td> <td>Username</td> <td>Email</td> <td>Account Type</td> </tr> <tr> <td><?php echo $id;?></td> <td><?php echo $username;?></td> <td><?php echo $email;?></td> <td><?php echo $account_type;?></td> </tr> </table> </body> </html> Now i tried making the table in the while loop, but i am also having the same problem. Please help. Hello, this is my first PHP project, and I am having issues getting it to correctly display an error ONLY if the input is an error It displays the error upon first load of the page w/o pressing submit. How would I use Code: [Select] isset($_POST['submit'])to fix it? Code: [Select] <?php $inputid = $_POST['steamid']; $steam_prefix = substr($inputid, 0, 10); $prefix_length = 10; $char_total = strlen($inputid); $steam_suffixchars = ($char_total - $prefix_length); $suffix_check = substr($inputid, 10, $steam_suffixchars); $class_set = "notranslate"; $is_submit = isset($_POST['submit']); if(is_numeric($suffix_check) == true) $suffix_valid = true; elseif(is_int($suffix_check) == false) $suffix_valid = false; if($char_total > 25 || $char_total < 11) $char_valid = false; else $char_valid = true; if($steam_prefix === "STEAM_0:1:" || $steam_prefix === "STEAM_0:0:") $prefix_check = true; elseif($steam_prefix != "STEAM_0:1:" || $steam_prefix != "STEAM_0:0:") $prefix_check = false; if (preg_match('/^[A-Z0-9-:-_-]+$/', $inputid)) $chars_matched = true; else $chars_matched = false; if($suffix_check == true && $prefix_check == true && $char_valid == true && $chars_matched == true) echo "Approved!"; elseif(isset($_POST['anon'])) echo "Approved!"; else echo "error!"; ?> It's very possible, and I've seen a website that's done it (http://www.zybez.net/radio/) - They are able to include the recent songs played on there website. The information can be obtained from right he http://68.168.100.60:7942/played.html But I'm not sure if thats where they get it from. If I login to my Admin section, there will be an option that says get XML stats. But I'm not sure if that shows the recent songs played like it would at http://68.168.100.60:7942/played.html (Everytime I refresh the page, the stats/data/info in the XML change) Code: [Select] 1250001522Rockhttp://srbuckey.listen2myradio.comMusicPEAK - RockKings of Leon - Radioactive N/AN/AN/A226153140audio/mpeg1.9.86201901701119000000004013207.144.125.60NSPlayer/11.0.6001.7006 WMFSDK/11.0026101521287587284Kings of Leon - Radioactive 1287586919Three Days Grace - Riot 1287586542Alice In Chains - Here Comes The Rooster 1287586281Green Day - Boulevard of Broken Dreams 1287586277down 1287586075Green Day - American Idiot 1287586044Metallica - Enter Sandman 1287585836ACDC Highway To Hell.mp3 1287585449Metallica - 04 The Unforgiven I.MP3 1287585448[HTTP/1.1 200 OK] http://www.ventsi.com/Music/MetallicA/1991 - Black Album/Metallica - 04 The Unforgiven I.MP3 How do you display non-editable data that is part of a larger form? For instance, I have an "Add a Comment" for with... =========================== * Article Title (non-editable) * Name (non-editable) * Comment (editable) Submit button =========================== Do I just make a Form with one Input field for the editable field?! And then make the first two "fields" stylized <p> tags?? Debbie hey der.... m a newbie to php and i dont know if this is the right place for this post. i have a php code and i would like it to be displayed on the browser as well as store it in mysql server in i proper format.... i tried to work with cookies but got the data displayed in array format please help me store it and display it separately i.e., name="XXXX" age="YY".........and so on the code i used in cookies is as follows <?php setcookie("name", $_POST["name"], time()+3600, "/","", 0); setcookie("age", $_POST["age"], time()+3600, "/", "", 0); ?> when i retrieve the cookie data by <?php print_r($_COOKIE)?> i get the output as: Array ( [name] => mohit [age] => 22 ) last but not the least to put the value of the cookie in mysql any help appreciated.... thnx Hello everyone, I'm trying to create a page that takes information from an existing database and displays it in a 'table' on a page. The table thing didn't seem to be working with some other pages I was working on so I split each database table into its own html table and rearrange accordingly. The code below doesn't output any information and I can't figure out why. Thanks in advance. $query = mysql_query("SELECT MAX(ART_ID) AS maxAID FROM Artisan"); while(mysql_fetch_array($query)) { $maxAID = $row["maxAID"]; for($artID = 1; $artID <= $maxAID; $artID++) { $Aquery = mysql_query("SELECT * FROM Artisan WHERE ART_ID = '$artID'"); ?> <table align = "center" width="90%" border="0" style="font-size: 12px; margin-top: 30px; font-family: Tahoma;"> <?php while(mysql_fetch_array($Aquery)) { $ART_Name = $row["ART_Name"]; ?> <tr> <td><?php echo $ART_Name; ?></td> <td> Filler </td> </tr> <?php }?></table><?php $Qquery = mysql_query("SELECT * FROM ArtisanQuestion ORDER BY ARQ_ID"); ?> <table align = "left" width="35%" border="0" style="font-size: 12px; margin-top: 30px; font-family: Tahoma;"> <?php while(mysql_fetch_array($Qquery)) { $Ques_ID = $row["ARQ_ID"]; $Ques = $row["ARQ_Question"]; ?> <tr> <td><?php echo "<b>".$Ques_ID."</b>. ".$Ques; ?></td> </tr> <?php }?></table><?php $Aquery = mysql_query("SELECT * ArtisanAnswer WHERE ART_ID = '$artID' ORDER BY ARQ_ID"); ?><table align = "right" width="35%" border="0" style="font-size: 12px; margin-top: 30px; font-family: Tahoma;"> <?php while(mysql_fetch_array($Aquery)) { $Ans = $row["ARAN_Answer"]; ?> <tr> <td><?php echo $Ans; ?></td> </tr> <?php }?></table><?php } } ?> I have a page in my admin control panel which allows for adding and editing an existing entry on the same page. At the moment, it displays the entries on the page in a table like format. After I edit an entry and hit Submit, I display a message on that page that says "Link updated successfully!", but the table on the page doesn't load the new entry until I refresh again - obviously since the data isn't entered into the database until I hit the submit button to process the form. But I'm wondering if it's possible to update the table on the page and display that new updated table all after hitting the submit button?? This is the php code i have wrote but i need some help....as this code is displaying my value from database when time(which is saved in database too) is equal to current server time. let say e.g : time saved in database is 6:00:00, so when current time is equal to database time which is 6:00:00 it then display my stored value(e.g 40 (int) ) from database. which is : 40 so i need help out here when the value shows : 40 on exact 6:00:00 (time) but disappear after a second i want to be display this value for 30 more sec.after that a new value from database will come and diplay as the time goes to 6:00:30 hope friend you will help me out soon thank you below is the code of php file. // First Connect to database echo "<meta http-equiv='refresh' content='20'>"; $link = mysql_connect("$dbhost","$dbuser","$dbpass") or die(mysql_error()); // Connection starts here mysql_select_db("$dbname") or die(mysql_error()); $sql = "SELECT * FROM datatable WHERE time = '$ctime' "; // simple sql example echo $cdate; echo "<br>"; echo $ctime; $re = mysql_query($sql) or die(mysql_error()); // Here's where you'll get an error if the SQL is invalid. while($row = mysql_fetch_array($re)) { // Beganing 1 include("variables.php"); echo "<br>"; echo $row['value']; // value to be displayed for 30Sec after displayed on site. } //Closing 4 mysql_close($link); // code ends here..:-) I want to fetch data from a table let's say table "activities". Uid | day | activity | time | remarks 1. Mon. Act1. 3pm. Good 2. Mon. Act1. 5pm. Bad 1. Tue. Act2. 12am. Bad 1. Tue. Act5. 1am. Bad 1. Thur. Act8. 9pm. Good 2. Wed. Act4. 7am. Good
Now assuming I want to fetch all the data that is related to user Id 1 and display them in another table (Uid 1). Which is 4 rows according to the table, how do I go about it using select query? Thanks!!! I tried something like this but it displays just one row
<?php
$uid = $_SESSION['login'];
$sql2 = "SELECT * FROM Activities WHERE uid=? ORDER BY Uid LIMIT 6";
$stmt2 = $connection->prepare($sql2);
$stmt2->bind_param('i', $Uid);
$stmt2->execute();
$result2 = $stmt2->get_result();
$row2 = $result2->fetch_assoc();
//now am stuck here
?>
now trying to display the fetch those data for only Uid 1 in these simple format...
<table style="width:100%"> <tr> <th>Day</th> <th>Activity</th> <th>Remarks</th> </tr> <tr> <td>Mon</td> <td>Act1</td> <td>Good</td> </tr> <tr> <td>Tue</td> <td>Act2</td> <td>Bad</td> </tr> <tr> <td>Tue</td> <td>Act5</td> <td>Bad</td> </tr> </table>
Hi, i need help for get data from following tables:
questions:
id
question
options:
id
ques_id
value
votes:
id
option_id
voted_on
ip
Question: What is your favorite color.
Option1: Test 1 - 83 votes
Option2: Test 2 - 0 votes
Option3: Test 3 - 51 votes
I'm using this sql for result:
SELECT options.id, options.value, COUNT(*) as votes FROM votes, options WHERE votes.option_id=options.id AND votes.option_id IN(SELECT id FROM options WHERE ques_id=2) GROUP BY votes.option_id;so i get this: id value votes 1 Test1 83 3 Test3 51 because there is not votes for option Test2 and doesn't show it. i need help to get all data like this: id value votes 1 Test1 83 2 Test2 0 3 Test3 51 I am managing a shop website which is using php and mysql for data. The website has a section that will display the related products with the one that you are watching. Now my problem is that if there are more than 5 items it will continue to display all the items in one row with the consequent that the page will not display well. I need to find a way to begin a new row after the 5th item so it will display 5 items in each row. this is my current code that is responsible for showing the related items. There is also a picture attached with the problem. while ($row = mysql_fetch_array($retd)) { $code = $row["code"]; $name = $row["name"]; echo("<td width=150 align=center>"); echo ("<a href=../products/info.php?scode=$code><img src=pictures/$code.gif border=0 alt=Item $name</a>"); echo ("<br><a href=../products/info.php?scode=$code><span class=fs13>$name</span></a>"); echo("</td>"); } Does anyone know how can I do this? Hi there I never had any php lessons. But I made a site, and now I'm kinda sorta working on a CMS so that someone else can edit the information on the site. Now I was wondering if there was a simple way of displaying all the data from a table, and editing it (not in phpmyadmin). This is my current method; it's rather sloppy but it works like a charm: Code: [Select] mysql_select_db('yourdatabase')or die(mysql_error()); $query = mysql_query("SELECT * FROM activiteit ORDER BY datum"); if(isset($_POST['editActiviteit'])){ $id = mysql_real_escape_string(htmlentities($_POST['id'])); }else{ $id = ''; } echo "<table border='1'><tr><th>Begindatum</th><th>Einddatum</th><th>Titel</th><th>Omschrijving</th><th>Zichtbaar?</th><th>Aanpassen</th><th>Verwijderen</th><th>Voorbeeld</th></tr>"; while($row = mysql_fetch_array($query)){ if($id == $row['id']){ if(empty($row['einddatum'])){ $einddatum = "<input type='text' size='2' name='activiteitDagEind' placeholder='dd' />/<input type='text' size='2' maxlength='2' name='activiteitMaandEind' placeholder='mm' />/<input typ='text' size='4' maxlength='4' name='activiteitJaarEind' placeholder='jjjj' />"; }else{ $explode = explode('/',$row['einddatum']); $einddatum = "<input type='text' size='2' name='activiteitDagEind' value='$explode[0]' />/<input type='text' size='2' maxlength='2' name='activiteitMaandEind' value='$explode[1]' />/<input typ='text' size='4' maxlength='4' name='activiteitJaarEind' value='$explode[2]' />"; } $explode2 = explode('/',$row['datum']); $datum = "<input type='text' size='2' name='activiteitDag' value='$explode2[0]' />/<input type='text' size='2' maxlength='2' name='activiteitMaand' value='$explode2[1]' />/<input typ='text' size='4' maxlength='4' name='activiteitJaar' value='$explode2[2]' />"; if($row['actief'] == 0){ $actief = "<select name='actief'><option value='1'>1</option><option value='0' selected='selected'>0</option></select>"; }else{ $actief = "<select name='actief'><option value='1' selected='selected'>1</option><option value='0'>0</option></select>"; } echo "<form action='ward.php' method='post'>"; echo "<tr><td>$datum</td><td>$einddatum</td><td><input type='text' name='activiteitTitel' value='".$row['titel']."' /></td><td><textarea name='activiteitOmschrijving'>".$row['omschrijving']."</textarea></td><td>$actief</td><td><input type='hidden' value='".$row['id']."' name='id' /><input type='submit' value='Slaag op' name='saveActiviteit' /></form></td><td><form action='ward.php' method='post'><input type='hidden' value='".$row['id']."' name='id' /><input type='submit' name='verwijderActiviteit' value='verwijderen' /></form></td><td><input type='button' disabled='disabled' value='Voorbeeld' /></td></tr>"; }else{ echo "<tr><td>".$row['datum']."</td><td>".$row['einddatum']."</td><td>" . $row['titel'] . "</td><td>" . bbcode_format($row['omschrijving']) . "</td><td>" . $row['actief']."</td><td><form action='ward.php?fx=activiteit' method='post'><input type='hidden' value='".$row['id']."' name='id' /><input type='submit' value='Pas aan' name='editActiviteit' /></form></td><td><form action='ward.php' method='post'><input type='hidden' value='".$row['id']."' name='id' /><input type='submit' value='verwijderen' name='verwijderActiviteit' /></form></td><td><input type='button' value='Voorbeeld' onClick=\"parent.location='ward.php?fx=activiteit&voorbeeld=".$row['id']."'\" /></td></tr>"; } } echo "</table><br /><br />"; I just copy pasted all the code but I'll explain it in big lines: First I open a table. I manually enter a row with the headers. Then every result of the query gets shown in a cell. The last cells of each row contain a delete and an edit button. The delete button deletes that row with the hidden id and reloads the page. When the edit button is clicked, it sends a form with the name of the button, here 'editActiviteit', and the id of the entry. And then the page gets reloaded. When the query is then done again, it checks if $_POST['editActiviteit'] is set, and if it is, it displays input fields with the values in the cells instead of pure text, and a save button instead of a edit button. The system works just fine, but it's heaps of work every time I implement it, for activities, users, ... Also I've been told that table's are not the correct way for displaying results (and they also get a little stretched). How should it be displayed? Thanks in advance. The program is working for part of the data . It can display in the CSS and HTML code, however, the other data can not display . I do not why . They are same structure . Please tell me the reason. Thank you very much. This topic has been moved to Application Design. http://www.phpfreaks.com/forums/index.php?topic=342944.0 |
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