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PHP - Display Data From Database In Table Form
how i want to display data from database to look like this :
<table width="633" height="224" border="1"> <tr bgcolor="#999900"> <td width="45">Bil</td> <td width="121">Course_name</td> <td width="83">session</td> <td width="83">start_date</td> <td width="83">end_date</td> <td width="83">notes</td> <td width="89">pre-req</td> </tr> <tr bgcolor="#6A7AEA"> <td rowspan="2">1.</td> <td rowspan="2" bgcolor="#6A7AEA">Math</td> <td>1st session </td> <td>1 jan 11 </td> <td>6 jan 11 </td> <td rowspan="2"> </td> <td rowspan="2"><image icon that will link to the oter site> </td> </tr> <tr> <td bgcolor="#6A7AEA">2nd session </td> <td bgcolor="#6A7AEA">8 jan 11 </td> <td bgcolor="#6A7AEA">15 jan 11 </td> </tr> <tr> <td bgcolor="#0066CC">2.</td> <td bgcolor="#0066CC">English</td> <td bgcolor="#0066CC">1st session </td> <td bgcolor="#0066CC">1 feb 11 </td> <td bgcolor="#0066CC">6 feb 11 </td> <td bgcolor="#0066CC"> </td> <td bgcolor="#0066CC"><image icon that will link to the oter site></td> </tr> <tr> <td rowspan="2" bgcolor="#6A7AEA">3.</td> <td rowspan="2" bgcolor="#6A7AEA">Science</td> <td height="29" bgcolor="#6A7AEA">1st session </td> <td bgcolor="#6A7AEA">8 march 11 </td> <td bgcolor="#6A7AEA">15 march 11 </td> <td rowspan="2" bgcolor="#6A7AEA"> </td> <td rowspan="2" bgcolor="#6A7AEA"><image icon that will link to the oter site></td> </tr> <tr> <td bgcolor="#6A7AEA">2nd session</td> <td bgcolor="#6A7AEA">16 march 11 </td> <td bgcolor="#6A7AEA">21 march 11 </td> </tr> </table> ** all the view data is called from database including the icon image thanks... Similar TutorialsAs a complete newbie to php and webdesigning i have a following problem.I would like to retrieve the data from database and display it in a drop down menu.Then i should allow the user to select the values from drop down list along with other details,in other words i have to embed the drop down output as the form input for the user and store the form data in another table.I am running a xampp server and i am using php 5.4 version.Please help.My code is as follows.In this case project_name is displayed as the drop down output.but how do i use the same drop down output as a input in the form. <html> <head></head> <body> <?php error_reporting(E_ALL ^ E_DEPRECATED); include 'connect.php' ; $tbl_name="projects"; $sql="SELECT project_name FROM $tbl_name "; $result=mysql_query($sql); if($result === FALSE) { die(mysql_error()); } ?> <form name="resources" action="hourssubmit.php" method="post" > <?php echo "<select name='project_name'>"; while ($row = mysql_fetch_array($result)) { echo "<option value='" . $row['project_name'] ."'>" . $row['project_name'] ."</option>"; } echo "</select>"; ?> </form> </body> </html> i have 8 division (div), i want to display 4 rows in 4 division and the remain 4 rows in the next 4 division here is my code structure for carousel
<div class="nyie-outer"> second row third row
fourth row fifth row sixth row seven throw eighth row
</div><!--/.second four rows here-->
sql code
CREATE TABLE product( php code
<?php how can i echo that result in those rows
the second database found on the cloud
i try to get JSON data but how to insert and update them to another online database with the same table my php script to return json data <?php include_once('db.php'); $users = array(); $users_data = $db -> prepare('SELECT id, username FROM users'); $users_data -> execute(); while($fetched = $users_data->fetch()) { $users[$fetchedt['id']] = array ( 'id' => $fetched['id'], 'username' => $fetched['name'] ); } echo json_encode($leaders);
i get
{"1":{"id":1,"username":"jeremia"},"2":{"id":2,"username":"Ernest"}} Edited March 24 by mahenda I have a form on our website that a user can fill out for custom product. I want the form data to be 1) stored into a mysql database AND after storing said data, 2) email the same data to our sales department. 1) The form data DOES get stored into mysql database (except for the first two fields, for some weird reason) 2) I added a "mail" section to the php file that stores the data into the database, but it is not working correctly. I have stripped the email portion down to sending just one of the fields in the "message" to make it easier for troubleshooting I have included here, both the form section of the html file, and the formdata.php file that processes the data for your analysis. I am relatively new to php so there are going to be some issues with security, but I can work on those after I get the store & email process to work correctly. Please review my code and see if anyone can be of assistance. I looked through the forums and couldn't find another issue that was the same as mine. If I just overlooked, please tell me the thread post #. Thanks THE FORM WHICH COLLECTS THE DATA ******************************* <form method=POST action=formdata.php> <table width="640" border=0 align="center"> <tr> <td align=right><b>First Name</b></td> <td><input type=text name=FName size=25></td> <td><div align="right"><b>Telephone</b></div></td> <td><input type=text name=Tel size=25></td> </tr> <tr> <td align=right><b>Last Name</b></td> <td><input type=text name=LName size=25></td> <td><div align="right"><b>Fax</b></div></td> <td><input type=text name=Fax size=25></td> </tr> <tr> <td align=right><b>Title</b></td> <td><input type=text name=Title size=25></td> <td><div align="right"><b>Email</b></div></td> <td><input type=text name=Email size=50></td> </tr> <tr> <td align=right><b>Company</b></td> <td><input type=text name=Comp size=25></td> <td> </td> <td> </td> </tr> <tr> <td align=right><b>Address</b></td> <td><input type=text name=Addr size=25></td> <td><div align="right"><b>Estimated Annual Volume</b></div></td> <td><input type=text name=EAV size=25></td> </tr> <tr> <td align=right><b>City</b></td> <td><input type=text name=City size=25></td> <td> </td> <td> </td> </tr> <tr> <td align=right><b>State/Province</b></td> <td><input type=text name=SProv size=25></td> <td><div align="right"><b>Application</b></div></td> <td><input type=text name=Appl size=25></td> </tr> <tr> <td align=right><b>Country</b></td> <td><input type=text name=Ctry size=25></td> <td><div align="right"><b>Type of System</b></div></td> <td><input type=text name=Syst size=25></td> </tr> <tr> <td align=right><b>Zip/Postal Code</b></td> <td><input type=text name=ZPC size=25></td> <td> </td> <td> </td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right> </td> <td><div align="right"><strong><font color="#FFFF00" face="Arial, Helvetica, sans-serif">COIL DESIGN</font></strong></div></td> <td><font color="#FFFF00" face="Arial, Helvetica, sans-serif"><strong>PARAMETERS</strong></font></td> <td> </td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right><b>Primary Resistance (ohms)</b></td> <td><input type=text name=Pres size=25></td> <td><div align="right"><b>Primary Inductance (mH)</b></div></td> <td><input type=text name=Pind size=25></td> </tr> <tr> <td align=right><b>Secondary Resistance (ohms)</b></td> <td><input type=text name=Sres size=25></td> <td><div align="right"><b>Secondary Inductance (H)</b></div></td> <td><input type=text name=Sind size=25></td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right><b>Peak Operating Current (Amps)</b></td> <td><input type=text name=POC size=25></td> <td> </td> <td> </td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right><b>Output Energy (mJ)</b></td> <td><input type=text name=Egy size=25></td> <td><div align="right"><b>Output Voltage (kV)</b></div></td> <td><input type=text name=Volt size=25></td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right><b># HV Towers per Coil</b></td> <td><input type=text name=TPC size=25></td> <td><div align="right"><b># of Coils per Package</b></div></td> <td><input type=text name=CPP size=25></td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <td align=right> </td> <td> </td> <td> </td> <td> </td> </tr> <tr> <th colspan=4><b>Please enter any additional information he </b></th> </tr> <tr> <th colspan=4><textarea name=Mess cols=50 rows=10 id="Message"></textarea></th> </tr> </table> </dl> <div align="center"> <p> <input type=hidden name=BodyTag value="<body bgcolor="#484589" text="#FFFFFF" link="#FFFF00" alink="#FFFFFF" vlink="#FF7F00">"> <input type=hidden name=FA value=SendMail> </p> <p><font color="#FFFF00" face="Arial, Helvetica, sans-serif"><strong>PLEASE MAKE SURE ALL INFORMATION<br> IS CORRECT BEFORE SUBMITTING</strong></font></p> <p> <input type=submit value="Submit Form"> </p> </div> </form> THE FILE THAT PROCESSES THE FORM DATA (formdata.php) *********************************************** <?php $con = mysql_connect("localhost","XXX","XXX"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("customform", $con); $sql="INSERT INTO formdata (Fname, Lname, Title, Comp, Addr, City, SProv, Ctry, ZPC, Tel, Fax, Email, EAV, Appl, Syst, Pres, Pind, Sres, Sind, POC, Egy, Volt, TPC, CPP, Mess) VALUES ('$_POST[Fname]','$_POST[Lname]','$_POST[Title]','$_POST[Comp]','$_POST[Addr]','$_POST[City]','$_POST[SProv]','$_POST[Ctry]','$_POST[ZPC]','$_POST[Tel]','$_POST[Fax]','$_POST[Email]','$_POST[EAV]','$_POST[Appl]','$_POST[Syst]','$_POST[Pres]','$_POST[Pind]','$_POST[Sres]','$_POST[Sind]','$_POST[POC]','$_POST[Egy]','$_POST[Volt]','$_POST[TPC]','$_POST[CPP]','$_POST[Mess]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "Your Information Was Successfully Posted"; mysql_close($con); $to = "recipient email address here"; $subject = "Custom Form"; $email = $_POST['Email'] ; $message = $_POST['Comp'] ; $headers = "From: $Email"; $sent = mail($to, $subject, $message, $headers) ; if($sent) {print "Your mail was sent successfully"; } else {print "We encountered an error sending your mail"; } ?> Hello to all, I have problem figuring out how to properly display data fetched from MySQL database in a HTML table. In the below example I am using two while loops, where the second one is nested inside first one, that check two different expressions fetching data from tables found in a MySQL database. The second expression compares the two tables IDs and after their match it displays the email of the account holder in each column in the HTML table. The main problem is that the 'email' row is displayed properly while its while expression is not nested and alone(meaning the other data is omitted or commented out), but either nested or neighbored to the first while loop, it is displayed horizontally and the other data ('validity', 'valid_from', 'valid_to') is not displayed.'
Can someone help me on this, I guess the problem lies in the while loop? <thead> <tr> <th data-column-id="id" data-type="numeric">ID</th> <th data-column-id="email">Subscriber's Email</th> <th data-column-id="validity">Validity</th> <th data-column-id="valid_from">Valid From</th> <th data-column-id="valid_to">Valid To</th> </tr> </thead> Here is part of the PHP code:
<?php
while($row = $stmt->fetch(PDO::FETCH_ASSOC))
{
echo '
<tr>
<td>'.$row["id"].'</td>
';
while ($row1 = $stmt1->fetch(PDO::FETCH_ASSOC)) {
echo '
<td>'.$row1["email"].'</td>
';
}
if($row["validity"] == 1) {
echo '<td>'.$row["validity"].' month</td>';
}else{
echo '<td>'.$row["validity"].' months</td>';
}
echo ' <td>'.$row["valid_from"].'</td>
<td>'.$row["valid_to"].'</td>
</tr>';
}
?>
Thank you. Hi I am trying to display data from the table "event" in my database, I use the code below but it will not work and I cannot figure out why. CAn anyone help? CODE: <?php $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="test"; // Database name $tbl_name="event"; // Table name mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $result = my_sql_query("SELECT * FROM event WHERE eventid = '1'"); while($row = mysql_fetch_array($result)) { $eventname= $row["eventname"]; $eventdate= $row["eventdate"]; echo "<b><u>Event Name:</b></u> $eventname" echo "<b><u>Event Date:</b></u> $eventdate<br>"; } ?> DISPLAY: Event Name: $eventname echo "Event Date: $eventdate "; } ?> I have got connection to the the mysql database, how do I get the data from the database to display on the webpage im making a game and i need to show a users money but i dont know how help? hey guys so im trying to display data into text boxes that are fetched from database according to checkbox with value id. processing is located before <!DOCTYPE html>:
if(isset($_POST['edit_event']) && isset($_POST['check']))
{
require "connection.php";
foreach ($_POST['check'] as $edit_id)
{
$edit_id = intval($GET['event_id']); //i tried (int)$edit_id;
$sqls = "SELECT event_name,start_date,start_time,end_date,end_time,event_venue FROM event WHERE event_id IN $edit_id ";
$sqlsr = mysqli_query($con, $sqls);
$z = mysqli_fetch_array($sqlsr);
{
}
button and form opens:
<form method="post" action="event.php"> <input type="submit" name="edit_event" value="Edit Event">this is the html where the data will be echoed:
<div id="doverlay" class="doverlay"></div>
<div id="ddialog" class="ddialog">
<table class="cevent">
<thead><tr><th>Update Event</th></tr></thead>
<tbody>
<tr>
<td>
<input type="text" name="en_" value="<?php echo $z['event_name']; ?>">
</td>
</tr>
<tr>
<td>
<input type="text" name="dates_" value="<?php echo $z['start_date']; ?>">
<input type="text" name="times_" value="<?php echo $z['start_time']; ?>">
</td>
</tr>
<tr>
<td><input type="text" name="datee_" value="<?php echo $z['end_date']; ?>">
<input type="text" name="time_" value="<?php echo $z['end_time']; ?>">
</td>
</tr>
<tr>
<td><input type="text" name="ev_" value="<?php echo $z['event_venue']; ?>">
</td>
</tr>
<tr>
<td><input type="submit" name="update" value="Update Event" id="update">
<input type="submit" id="cancelupdate" name="cancel" value="Cancel" >
</td>
</tr>
</tbody>
</table>
</div>
this is the part which is populated by data from database where isset($_POST['check']) gets the 'check' from:
echo
"<tr>
<td><input type='checkbox' name='check[]' value='$id'>$name
</td>
</tr>";
</form>
thanks in advance!
Edited by noobdood, 19 May 2014 - 10:42 PM. Hi guys, Should be a simple 1. If i have the following at the top of the page: $page_views = $row['page_views'] + 1; mysql_query("UPDATE table SET page_views='$page_views'"); and then the following at the bottom of the page: echo $row['page_views']; Should I see the page views as 1 the first time the page is visited, 2 the second time the page is visited, and so on......? At the moment im seeing 0 on the first page visit, 1 on the second page visit, 2 on the third..... I had this problem before on another page i was working, and i simply solved it by displaying the mysql query above the echo similar to the code above. However now it does not seem to be working. Am i missing something really simple? lol Thanks This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=321339.0 This is actually a page to edit the drama details. Database- 3 tables 1. drama dramaID drama_title 1 friends 2. drama_genre drama_genreID dramaID genreID 1 1 2 2 1 1 3 1 3 3. genre genreID genre 1 comedy 2 romance 3 family 4 suspense 5 war 6 horror <?php $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = ''; $dbname = 'drama'; $link = mysqli_connect($dbhost, $dbuser, $dbpass, $dbname) or trigger_error('Error connecting to mysql'); $id = $_GET['dramaID']; $link2 = mysqli_connect($dbhost, $dbuser, $dbpass, $dbname) or trigger_error('Error connecting to mysql'); $sql2 = "SELECT * from drama , drama_genre , genre WHERE drama.dramaID='".$id."' AND drama_genre.dramaID='".$id."' AND drama.dramaID = drama_genre.dramaID AND drama_genre.genreID = genre.genreID"; $status2 = mysqli_query($link2,$sql2) or die (mysqli_error($link2)); $link3 = mysqli_connect($dbhost, $dbuser, $dbpass, $dbname) or trigger_error('Error connecting to mysql'); $sql3 = "SELECT * from genre "; $status3 = mysqli_query($link3,$sql3) or die (mysqli_error($link3)); <form method='Post' action='doUpdate.php' enctype="multipart/form-data"> <?php while ($row2 = mysqli_fetch_assoc($status2)) { ?> <td height="1"></td> <td><select name="gdrop"> <option value="<?php echo $row2['genreID'];?>"><?php echo $row2['genre'];?></option> <?php while ($row3 = mysqli_fetch_assoc($status3)) { ?> <option value="<?php echo $row3['genreID'];?>"><?php echo $row3['genre'];?></option> <?php } mysqli_close($link3); ?> <input type='hidden' id='drama_genreID' name='drama_genreID' value = "<?php echo $row2['drama_genreID']; ?>"/> </select> <input type="hidden" id="dramaID" name="dramaID" value = "<?php echo $row['dramaID'];?>"/> <input type="submit" Value="Update"/> The result was there were 3 dropdown menus but only the first dropdown menu has all 6 genres from my database and also the genre that belongs to the drama. I'm also wondering how I can bring all the drama_genreIDs to my save(doupdate.php) page and update all 3 of them because it seems like only the last dropdown menu's data is saved. And also how can I display only 6 genres instead of 7 with the genre that belongs to the drama , being set as the default selection. Hello, I have coded a contact form in PHP and I want to know, if according to you, it is secure! I am new in PHP, so I want some feedback from you. Moreover, I have also two problems based on the contact form. It is a bit complicated to explain, thus, I will break each of my problem one by one. FIRST:The first thing I want to know, is if my contact form secure according to you: The HTML with the PHP codes: Code: [Select] <?php if ($_SERVER['REQUEST_METHOD'] == 'POST') { //Assigning variables to elements $first = htmlentities($_POST['first']); $last = htmlentities($_POST['last']); $sub = htmlentities($_POST['subject']); $email = htmlentities($_POST['email']); $web = htmlentities($_POST['website']); $heard = htmlentities($_POST['heard']); $comment = htmlentities($_POST['message']); $cap = htmlentities($_POST['captcha']); //Declaring the email address with body content $to = 'alithebestofall2010@gmail.com'; $body ="First name: '$first' \n\n Last name: '$last' \n\n Subject: '$sub' \n\n Email: '$email' \n\n Website: '$web' \n\n Heard from us: '$heard' \n\n Comments: '$comment'"; //Validate the forms if (empty($first) || empty($last) || empty($sub) || empty($email) || empty($comment) || empty($cap)) { echo '<p class="error">Required fields must be filled!</p>'; header ('refresh= 3; url= index.php'); return false; } elseif (filter_var($first, FILTER_VALIDATE_INT) || filter_var($last, FILTER_VALIDATE_INT)) { echo '<p class="error">You cannot enter a number as either the first or last name!</p>'; return false; } elseif (!filter_var($email, FILTER_VALIDATE_EMAIL)) { echo '<p class="error">Incorrect email address!</p>'; return false; } elseif (!($cap === '12')){ echo '<p class="error">Invalid captcha, try again!</p>'; return false; } else { mail ($to, $sub, $body); echo '<p class="success">Thank you for contacting us!</p>'; } } ?> <form action="<?php echo $_SERVER['PHP_SELF'];?>" method="post"> <p>Your first name: <span class="required">*</span></p> <p><input type="text" name="first" size="40" placeholder="Ex: Paul"/></p> <p>Your last name: <span class="required">*</span></p> <p><input type="text" name="last" size="40" placeholder="Ex: Smith"/></p> <p>Subject: <span class="required">*</span></p> <p><input type="text" name="subject" size="40" placeholder="Ex: Contact"/></p> <p>Your email address: <span class="required">*</span></p> <p><input type="text" name="email" size="40" placeholder="Ex: example@xxx.com"/></p> <p>Website:</p> <p><input type="text" name="website" size="40" placeholder="Ex: http//:google.com"/></p> <p>Where you have heard us?: <span class="required">*</span></p> <p><select name="heard"> <option>Internet</option> <option>Newspapers</option> <option>Friends or relatives</option> <option>Others</option> </select></p> <p>Your message: <span class="required">*</span></p> <p><textarea cols="75" rows="20" name="message"></textarea></p> <p>Are you human? Sum this please: 5 + 7 = ?: <span class="required">*</span></p></p> <p><input type="text" name="captcha" size="10"/></p> <p><input type="submit" name="submit" value="Send" class="button"/> <input type="reset" value="Reset" class="button"/></p> </form> SECOND PROBLEM:If a user has made a mistake, he gets the error message so that he can correct! However, when a mistake in the form occurs, all the data the user has entered are disappeared! I want the data to keep appearing so that the user does not start over again to fill the form. THIRD: When the erro message is displayed to notify the user that he made a mistake when submitting the form, the message is displaying on the top of the page. I want it to appear below each respective field. How to do that? In JQuery it is simple, but in PHP, I am confusing! Hi, here's my problem: I am trying to make a simple online buying website and I want to display a table with all the fields for each item. So I got that part down which is to just use mysql_fetch_assoc("SELECT * FROM myTable") and use the html table tags stuff, but now I want to display my images in the table, so here's my code to display my mysql database table in html's table tag along w/ php: <html> <head> <title>My Online buying website project</title> </head> <body> <?php mysql_connect("localhost","root"); mysql_select_db("myTable"); $imagesArray=array("Apple_iPhone3GS.jpg","Apple_iPhone4.jpg","product3.jpg","product4.jpg","product5.jpg"); $result=mysql_query("SELECT Name, Manufacturer, Price, Description, SimSupport FROM myTable"); if(mysql_num_rows($result))//if there is at least one entry in bellProducts, make a table { print "<table border='border'>"; print "<tr> <th>Name</th> <th>Manufacturer</th> <th>Price</th> <th>Description</th> <th>SimSupport</th> </tr>"; //NB: now output each row of records while($row=mysql_fetch_assoc($result)) { extract($row); print "<tr> <td>$Name</td> <td>$Manufacturer</td> <td>$Price</td> <td>$Description</td><td>$SimSupport</td> </tr>"; }//END WHILE }//END IF ?> </table> </body> </html> *So how do I go about adding my images in this table? Hello, What I am looking to do is have a series of buttons laid out and when the user 'onClick', a table from my MySQL database will load into a scrollable textbox within the same webpage. I figure I need to go about this using AJAX, which unfortunately I have basically no experience in. For example purposes here is what I have going: This php code basically just displays the table we want to tie the button click to. Code: [Select] <?php include("connect.php"); //Query of facebook database $facebook = mysql_query("SELECT * FROM facebook") or die(mysql_error()); //Output results if(!$facebook) { echo "There was an error running the query: " . mysql_error(); } elseif(!mysql_num_rows($facebook)) { echo "No results returned"; } else { $header = false; echo "<table border='1'>\n"; while($row = mysql_fetch_assoc($facebook)) { if(!$header) { echo "<tr>\n"; foreach($row as $header => $value) { echo "<th>{$header}</th>\n"; } echo "</tr>\n"; } echo "<tr>\n"; foreach($row as $value) { echo "<th>{$value}</th>\n"; } echo "</tr>\n"; } echo "</table>\n"; } mysql_close(); ?> I'd really like to make this as easy as possible. After doing research, I figured that just Javascript would not be enough because it is client-side. It would be great if someone could point me in the right direction. Thanks in advance to anyone who replies. Sorry for the beginner question, here I'm trying to retrieve data from the database and display it in the table format. But only table headers are printed, and not the actual values. The count variable is echoing 2 saying that data is present and correctly retrieved. Can anyone help?
<?php
include 'connect.php';
error_reporting(E_ALL ^ E_DEPRECATED);
error_reporting(E_ERROR | E_PARSE);
$sql="SELECT * FROM `resources` as r INNER JOIN `project_resources` as pr
ON r.res_id =pr.res_id WHERE project_id='$_POST[project_id]'";
$result=mysql_query($sql);
$count=mysql_num_rows($result);
if($result === FALSE) {
die(mysql_error());
}
echo "$count";
echo '<table>
<tr>
<th>Resource ID</th>
<th>Resource Name</th>
<th>Email</th>
<th>Phone Number</th>
<th>Reporting Manager</th>
<th>Role</th>
<th>Designation</th>
</tr>';
while ($row = mysql_fetch_array($result)) {
echo '
<tr>
<td>'.$row['res_id'].'</td>
<td>'.$row['res_name'].'</td>
<td>'.$row['email'].'</td>
<td>'.$row['phone_number'].'</td>
<td>'.$row['reporting_manager'].'</td>
<td>'.$row['role'].'</td>
<td>'.$row['designation'].'</td>
</tr>';
}
echo '
</table>';
?>
Edited by mac_gyver, 22 September 2014 - 07:25 AM. code tags please Hello,
I am trying to display the data from two tables with proper format. But Its not happening
Here is my 1st table - orders
2.PNG 10.12KB
0 downloads
and my 2nd table - order_line_items
1.PNG 14.92KB
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I want to display like this
3.PNG 4.03KB
0 downloads
Here is my code
$query = $mysqli->query("SELECT orders.order_id, orders.company_id, orders.order_for, order_line_items.order_id, order_line_items.item, order_line_items.unit,SUM(order_line_items.unit_cost * order_line_items.quantity) AS 'Total', order_line_items.tax from orders INNER JOIN order_line_items ON orders.order_id = order_line_items.order_id where orders.order_quote = 'Order' GROUP BY order_line_items.id"); ?>
<table id="dt_hScroll" class="table table-striped">
<thead><tr>
<th>Order ID</th>
<th>Company</th>
<th>Contact Person</th>
<th>Products</th>
<th>Total</th>
</tr>
</thead>
<tbody> <?php
while($row = $query->fetch_array())
{
?>
<tr>
<td><?php echo $row['order_id']; ?></td>
<td><?php echo $row['company_id']; ?></td>
<td><?php echo $row['contact_person'] ?></td>
<td><?php echo $row['item']; ?></td>
<td><?php echo $row['Total']; ?> %</td>
</tr>
<?php
}
But here order ID, Company ID, Contact Person are also repeating thrice with item in order_line_items table
Please suggest me how to do this
i'm trying to echo out the results from a query onto a page, but rather than having them echo out as rows in a table, i want them to be displayed in columns, i.e. first column would have the first 10 results and the second column would have the next to. Any ideas on how i could do this? at the moment i'm using this code to display my results $read=mysql_query("SELECT * FROM entry WHERE category_id=".$id." ORDER BY entry_title") or die("query failed".mysql_error()); $result=mysql_num_rows($read); for($j = 0; $j < $result; $j++) { $row = mysql_fetch_array($read); echo "<a href=article.php?id=".$row['entry_id']. ">".$row['entry_title']."</a><br />"; } but this just displays it as a list down the middle thanks Hello everyone,
i'm Osiris and i'm stuck with this PHP/HTML code, i'm fairly new at this so this might be a dumb question.
i have a database, but i want to output all data into a table from the database using HTML codes.
i had it so far that i could outpust the info in just plain text but it doesn't output in the HTML table.
Can anyone see what i did wrong?
This is my PHP code its in the body section
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = 'password';
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(! $conn )
{
die('Could not connect: ' . mysql_error());
}
$sql = 'SELECT `Name`, `Color`, `Type`, `Subtype`, `Power`, `Toughness`, `Manacost`, `Rarity`, `Expansion`, `Foil`, `Stock` FROM `mtgtabel`';
mysql_select_db('mtgstock');
$retval = mysql_query( $sql, $conn );
if(! $retval )
{
die('Could not get data: ' . mysql_error());
}
echo '<table class=mytable>';
echo "<tr><th >Name</th><th >Color</th><th >Type</th><th >Sub Type</th><th >Power</th><th >Toughness</th><th >Converted mana cost</th><th >Rarity</th><th >Expansion</th><th >Foil</th><th >Stock</th></tr>";
while($row = mysql_fetch_array($retval, MYSQL_ASSOC))
{
echo "<tr><td>";
echo $row['Name']
echo "</td><td>";
echo $row['Color'];
echo "</td><td>";
echo $row['Type'];
echo "</td><td>";
echo $row['Subtype'];
echo "</td><td>";
echo $row['Power'];
echo "</td><td>";
echo $row['Toughness'];
echo "</td><td>";
echo $row['Manacost'];
echo "</td><td>";
echo $row['Rarity'];
echo "</td><td>";
echo $row['Expansion'];
echo "</td><td>";
echo $row['Foil'];
echo "</td><td>";
echo $row['Stock'];
echo "</td></tr>";
}
echo "</table>";
mysql_close($conn);
?>
Thanks in advance!
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