PHP - Help With Functions With Multiple Variables
I have this function:
Code: [Select] function echo_exist($pre1,$ee,$post1) { if ($ee!='') { return $pre1; return $ee; return $post1; } else { //do nothing } } But when I try to echo it Code: [Select] echo_exist("(","$row['payment_type']",")"); I get syntax error, unexpected T_ENCAPSED_AND_WHITESPACE If $row['payment_type'] exists, I want it to be displayed in parentheses like: (AUTO) I suspect it has to do with my ' characters for the associative array, but I am new with functions so perhaps it is the multiple arguments that are wrong? Similar TutorialsI have a database that holds a list of companies. the database includes and ID, and name of each company. Now when an articles gets submitted to my site it can then be related to company. We a relate a company to an article its related through its ID. What I want to do is create a function that would let me easly convert my company ID into company name within having to write out the queries over and over again in my code. Only problem is I can't get it to work. I have two files, index.php and functions.php. functions.php Code: [Select] function cname($pubid) { global $db; $company= $db->query("SELECT * FROM my_database WHERE id='$pubid'") or die(mysql_error()); while($company= $db->fetch_array($company)) { $cname = $company['name']; } return $cname; } and within index.php I put Code: [Select] echo cname($companyID); Now, when I first looked at index.php I was getting an error. I know it had something to do with me using my variables within the function and after some searching I ended up getting rid of the error by adding "global $db;" to my code. Please note that I include functions.php at the top of index.php. What am I doing wrong and why wont it work? HELP PLEASE! also note that my i've rechecked and all the database info is correct and names spelt right. Just dont know what else to do. I've written the following code: Code: [Select] $mode = 'development'; // 'Development' or 'Public' // Writes a buffer to a file /** * ob_file_callback() * Writes the generated CSS to a file. * @param mixed $buffer * @return void */ function ob_file_callback($buffer) { // stylesheet-public.css is the output generated file $ob_file = fopen('stylesheet-' . $mode . '.css','w'); fwrite($ob_file, $buffer); } $buffer = 'test'; ob_start('ob_file_callback'); $mode is always empty when I run this code. Is it an issue because ob_file_callback is an overridden function? Still working on my project, and i have been learning a lot here! Thank you so much. But as you may have guessed, i still have problems. User registration is working, and new users are put in the database with a rank of 0. This means they can't do anything. (can there be trouble with this. I mean, a rank of "0"?) An admin needs to give access to these accounts, but that is where it becomes difficult. The following code is showing the new accounts to the admin. Code: [Select] <?php include("navbar.php"); if ($admin<2) //normal guy or not { die ("Du har ikke rettigheder til at se denne side!"); } else if(isset($_POST['submit'])) { //code to make the user able to use stuff } { $connect = mysql_connect("localhost","root",""); mysql_select_db("eksamen - phoenix"); $query = mysql_query("SELECT * FROM users WHERE rank='0'"); ?> <form action='admin.php' method='POST'> <table> <?php while($row = mysql_fetch_assoc($query)) { echo " <tr> <td> ".$row['username']." </td> <td> ".$row['email']." </td> <td> ".$row['real_name']." </td> <td> <input type=\"checkbox\" name=".$row['username']." value=\"Godkend\"> </td> </tr> ";} ?> <tr> <td> <input type='submit' name='submit' value='Register'> </td> </tr> </table> </form> <?php } ?> As you may see, there is a lot of turning php on and off. I made it work this way, but i guess there is nothing wrong with it. The problem is that the username is not stored, so i can connect to the database and change the "rank" value. Changing that value should be easy, but storing the username is as easy as i thought. Any ideas? I have a little problem. I have made a script(function) to connect to the database. this is the script: connect(php) Code: [Select] <?php $server = "localhost"; $username = "username"; $password = "password"; function connectdatabase($type,$database) { if($type == "mysql") { $mysql = mysql_connect($server, $username, $password); mysql_select_db($database, $mysql); } else if($type == "mysqli") { $mysqli = new mysqli($server, $username, $password, $database); } else if($type == "mssql") { $mssql = mssql_connect($server, $username, $password); mssql_select_db($database, $mssql); } function query($query) { if($type == "mysql") { mysql_query($query); } else if($type == "mysqli") { $mysqli->query($query); } else if($type == "mssql") { mssql_query($query); } } } ?> and aanmelden(php) Code: [Select] <?php include("config.php"); connectdatabase("mysql", "[ledensysteem]"); //example if(!empty($_POST)) { if(!preg_match('/^[A-Za-z1-9-]{'.$Minimale_Gebruikersnaam_Karakters.',}$/', $_POST['gebruikersnaam'])) { if(!isset($error)){ $error=1;}else{$error=$error+1;} echo "Je gebruikersnaam moet minimaal {$Minimale_Gebruikersnaam_Karakters} tekens bevaten en mag geen komma of andere onbedoelde tekens zijn<br>Toegestaan is <br>A t/m Z <br>a t/m z <br>1 t/m 9 <br>en -"; } else { echo "geldige gebruikersnaam(goedgekeurd)"; } if(preg_match('/^[A-Za-z1-9-]{'.$Minimale_Wachtwoord_Karakters.',}$/', $_POST['wachtwoord']) && preg_match('/^[A-Za-z1-9-]{'.$Minimale_Wachtwoord_Karakters.',}$/', $_POST['herhaalwachtwoord'])) { if($_POST['wachtwoord'] != $_POST['herhaalwachtwoord']) { if(!isset($error)){ $error=1;}else{$error=$error+1;} echo "niet hetzelfde wachtwoord"; } /*else { echo "hetzelfde wachtwoord (goedgekeurd)"; }*/ } else { if(!isset($error)){ $error=1;}else{$error=$error+1;} echo "wachtwoord moet minimaal {$Minimale_Wachtwoord_Karakters} tekens bevatten!"; } if(!preg_match("/^[A-Za-z1-9_.-]{1,}@[A-Za-z1-9-]{1,}\.[A-Za-z1-9]{2,3}$/", $_POST['email'])) { if(!isset($error)){ $error=1;}else{$error=$error+1;} echo "onjuiste email"; } else { echo "goedgekeurd!"; } if(!isset($error)) // this problem is fixed yesterday on phpfreaks.com forum! { echo "goedgedaan geen errors!"; query("SELECT username FROM phpfreaks WHERE password = private"); // example } } else { ?> <HTML> <HEAD> <TITLE>New Document</TITLE> </HEAD> <BODY> <form method="post"> <input type="text" name="gebruikersnaam" value="gebruikersnaam" maxlength="20" size="20"> <input type="password" name="wachtwoord" value="wachtwoord" maxlength="20" size="20"> <input type="password" name="herhaalwachtwoord" value="herhaalwachtwoord" maxlength="20" size="20"> <input type="text" name="email" value="voorbeeld@domeinnaam.extensie" maxlength="50" size="20"> <input type="submit" name="login" value="inloggen"> </form> </BODY> </HTML> <?php } ?> the problem is, is that i want to pass a variable between functions like $type (the database type) between connectdatabase(); and query(); in the 'aanmelden.php' file is an example of how i use the function (on line 3 and 45 the ones with //example comment) thanks for reading. please help. ps. config.php contains include("connect.php"); I think I need to use $this, but I need to be able to add the two values returned from both of my functions. How would I do that? Code: [Select] public function get_users_edge($uid) { $users_primary->get_users_primary_edge($uid); $users_dynamic->get_users_dynamic_edge($uid); echo $users_primary + $users_dynamic; } Learning something new here so if anyone can tell me why I this wont return a value? page1.php Code: [Select] <?php require "page2.php"; getuserid(); echo $userID; ?> page2.php Code: [Select] <?php function getuserid() { $user =& JFactory::getUser(); $userID = $user->id; global $userID; } ?> Hi, In all my classes, I need to declare globals for everything else, from site variables even to objects (other classes). I obviously don't want to as globals are horrible and I need to have functions clean without globals. I have included a list of all the global vars in the construct and it still doesn't work. Example: start.php <?php $vars = array(some values); $some = more; $variables = foo; $helper = new Helper(); $home = new Home(); This is a little bit simplistic, but for some reason, the variables just don't want to go in the main class without a global. Functions will not run if they require any of these variables. I have some questions about the scope of navigation : if i define a constant like define('constant'), php manuel says it's global, does this mean that i can use of different files also? like, i defined in define.php and used in anotherfile.php, or shoud the latter file be included then? what about file a.php includes file b.php which in turn includes file c.php. Can functions of a use variables of file c? ultimately: what about variables that are declared global inside a function but this variables is not initialized in that script, like in wordpress: function date_i18n( $dateformatstring, $unixtimestamp = false, $gmt = false ) { global $wp_locale; // more code } $wp_locale can be initialized in another script file? thanks in advance 've create a SOAP Server using the PHP Soap functions. It has 3 functions in it and is initialised as follows; // Initialise the SOAP Server $opts = Array(); $opts['compression'] = SOAP_COMPRESSION_ACCEPT | SOAP_COMPRESSION_GZIP; $server = new SoapServer('SOTBWSDL.wsdl', $opts); $server->addFunction('getAvailability'); $server->addFunction('putReservation'); $server->addFunction('putCancelBooking'); $server->handle();
There are then 3 Functions as defined with the code in for each . $client = new SoapClient('http://xxxxxxxxx/SOTBWSDL.wsdl',array('trace'=>1,'exceptions=>1')); $res = $client->getAvailability($xmlparams);
This works and returns data as expected. $res = $client->putReservation($xmlparams); (To another function)
it is the first function (get Availability) that is executed. I am currently building my own MVC Framework and I have run into an issue that I can't solve when attempting to use 2 methods from a single model. I know that this isn't an issue with the queries or information being return. I am unsure of the proper way that I can call 2 methods when checking to see if a user is logged in... The issue that I face is both methods are calling the DB and it throws a PDO error which I don't know how to get around the issue.. Any guidance would be nice as I have been banging my head over this issue. Thank you!
Fatal error: Uncaught Error: Call to undefined method PDO::Select() in C:\xampp\htdocs\PicWrist\app\models\user.class.php:318 Stack trace: #0 C:\xampp\htdocs\PicWrist\app\controllers\home.php(21): User->getUser('4') #1 C:\xampp\htdocs\PicWrist\app\core\app.php(36): Home->index() #2 C:\xampp\htdocs\PicWrist\app\init.php(47): App->__construct() #3 C:\xampp\htdocs\PicWrist\public\index.php(5): require('C:\\xampp\\htdocs...') #4 {main} thrown in C:\xampp\htdocs\PicWrist\app\models\user.class.php on line 318
//Controller <?php /** * Load the View */ class Controller{ public function view($view, $data = []) { if (file_exists('../app/views/' . $view . '.php')) { require_once '../app/views/' . $view . '.php'; } } public function model($model, $data = []) { if (file_exists('../app/models/' . $model . '.class.php')) { require_once '../app/models/' . $model . '.class.php'; return new $model(); } else return false; } } ?> //Home Controller <?php Class Home extends Controller { public static $user; public $errors; public function __construct() { self::$user = $this->model('user'); } public function index() { $userdata = []; $data = []; show(self::$user); $isLoggedin = self::$user->isLoggedin; show($isLoggedin); $userdata = self::$user->getUser($_SESSION['user_id']); show($userdata); $this->view('home', $data); } } ?> <?php /** * Users */ class User { private $db; private $errors = ''; public $isLoggedin = False; public $isAdmin = False; public function __construct() { $this->isLoggedIn(); } public function isLoggedIn() { if(isset($_SESSION['user_id'])){ $data['user_id'] = $_SESSION['user_id']; $db = Database::getInstance(); $query = "SELECT * FROM users WHERE user_id = :user_id LIMIT 1"; $results = $db->Select($query, $data); if (is_array($results)) { $this->isLoggedIn = True; } } } public function getUser($id) { if(isset($id)) { $data['user_id'] = intval($id); $db = Database::getInstance(); $query = 'SELECT * FROM users WHERE user_id = :user_id'; $results = $db->Select($query, $data); if (is_array($results)) { return $results; } else { return False; } } else { return False; } } //DB <?php /** * Database Connection */ class Database { private $dbHost = DB_HOST; private $dbUser = DB_USER; private $dbPass = DB_PASS; private $dbName = DB_NAME; private $statment; private static $dbHandler; private $error; public function __construct() { $conn = 'mysql:host=' . $this->dbHost . ';dbname=' . $this->dbName; $options = array( PDO::ATTR_PERSISTENT => true, PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION ); try { self::$dbHandler = new PDO($conn, $this->dbUser, $this->dbPass, $options); } catch (PDOException $e) { self::$error = $e->getMessage(); echo self::$error; } } public static function getInstance() { if(self::$dbHandler) { return self::$dbHandler; } return $instance = new Self(); } public function Select($query, $data = array()) { $statement = self::$dbHandler->prepare($query); $result = $statement->execute($data); If($result) { $data = $statement->fetchAll(PDO::FETCH_OBJ); if(is_array($data)) { // show($data); return $data; } } return False; } public function Update($query, $data = array()) { $statement = self::$dbHandler->prepare($query); $result = $statement->execute($data); If($result) { return True; } return False; } } ?> Edited July 14 by avargas94 Wrong Code Hi, As the title suggests I am unsure on how to first run a query which stores values into an array. I then need to run a function multiple times but use the array within the function. How is this possible? I have had no luck figuring it out yet. 1. RUN QUERY 2. BUILD ARRAY USING QUERY RESULTS 3. RUN FUNCTION MULTIPLE TIMES 4. WITHIN FUNCTION I NEED TO USE ARRAY Many thanks Simon I have this script Code: [Select] <?php header("content-type: image/png"); include '../../api/config.php'; include "../../api/api.php"; $gamercard = getInfo($_GET['gamertag']); updateStats($gamercard['Gamertag'], "Nxe", 75); $type = $_GET['type']; switch ($type) { case "dark": $type = "dark.png"; break; case "light": $type = "light.png"; break; default: $type = "dark.png"; break; } $image = imagecreatefrompng("$type"); $img = imagecreatetruecolor(imagesx($image), imagesy($image)); $avatar_l = imagecreatefrompng($gamercard["Avatarpic-l"]); $avatar_body = imagecreatefrompng($gamercard["Avatarpic-body"]); imagecopy($img, $image, 0, 0, 0, 0, imagesx($image), imagesy($image)); imagecopy($img, $avatar_l, 64, 7, 0, 0, imagesx($avatar_l), imagesy($avatar_l)); imagecopy($img, $avatar_body, 175, -40, 0, 0, imagesx($avatar_body), imagesy($avatar_body)); for($i = 1; $i <=count($gamercard["RecentGames"]); $i++) { $gameimg = imagecreatefromjpeg($gamercard["RecentGames"][$i]["Icon"]); $x = ($i-1)*35 + 10; imagecopy($img, $gameimg, $x, 77, 0, 0, imagesx($gameimg), imagesy($gameimg)); } $ColorText = imagecolorallocate($img, 255, 255, 255); ImageTTFText($img, 10, 0, 10, 127, $ColorText, "font.ttf", $gamercard['Gamertag']); ImageTTFText($img, 10, 0, 135, 127, $ColorText, "font.ttf", $gamercard['Gamerscore']); imagepng($img); imagedestroy($img); ?> which is made to call the updateStats() function 1 time everytime the page loads. Heres the function (its in api.php) Code: [Select] function updateStats($gamertag, $type, $size) { $query = mysql_query("SELECT * FROM loadstats where Gamertag = '$gamertag' && Type = '$type'") or die(mysql_error()); $exists = mysql_num_rows($query); if ($exists == 0) { mysql_query("INSERT INTO loadstats (Gamertag, Type, Loads, Data) VALUES('$gamertag', '$type', '1', '$size' )") or die(mysql_error()); } else { $row = mysql_fetch_array($query); $newloads = $row['Loads'] + 1; $newdata = $row['Data'] + $size; mysql_query("UPDATE loadstats SET Loads = '$newloads' WHERE gamertag = '$gamertag' && Type = '$type'") or die(mysql_error()); mysql_query("UPDATE loadstats SET Data = '$newdata' WHERE gamertag = '$gamertag' && Type = '$type'") or die(mysql_error()); } } The wierd thing that is happening is, When i have the Header() set in the script, the updateStats() function appears to be called twice, but when the header is commented out, it is only called once. I can tell this by the change of data in the MYSQL database, the Loads value increases by 2 when the header is set, and it only creases by 1 when it isnt set. Any insight as to why this is happening would be greatly appreciated. This is a bit of a more advanced question so I am hoping there are some advanced programmers online at this time . Anyways basically I want to be able to "queue" functions from a class in a single call and am wondering if I am doing it correctly or if there is a better way to do it. Here is my code: <?php class test { private static $one; private static $two; private static $three; public function callOne($val){ $one .= $val; return $this; } public function callTwo($val){ $two .= $val; return $this; } public function callThree($val){ $three .= $val; return $this; } public function print(){ echo $this->one.' '.$this->two.' '.$this->three; } } ?> now when I want to call this I can do: $test = new test(); $test->callOne('one')->callTwo('two')->callThree('three'); $test->callOne('another one'); $test->print(); Is there a better way to do this or is there a different method of doing this? Just wanna make sure I am doing it right lol. quick layout trying to accomplish Radio Boxes O O O O O O O SEARCH .............. -OK- OK is the submit button POST should be radiox (function to run) +search user select radiobox 4 and then searches xxxaaa then presses OK then POST PHP_SELF same page being used (index.php) im having an issue trying to get the radio to be selected with teh SEARCH then SUBMIT and RUN a function to perform with the DATA //later looking at trying to view it as the script in the backend is running rather then waiting for it BUT thats just me a google to find lol <?php if (isset($_REQUEST['search'])) { $search = escapeshellcmd($_REQUEST['search']); $command = '/etc/SCRIPT/BLAHLOG ' . $search; printCmd($command, true); } ?> <?php if radio3 SELECTED THEN $search = escapeshellcmd($_REQUEST['search']); $command = '/etc/SCRIPT/BLAHSQLscript ' . $search; printCmd($command, true); ?> <form> <div id="radio"> <input type="radio" id="radio1" name="radio" /><label for="radio1">BLAhscript</label> <input type="radio" id="radio2" name="radio" /><label for="radio2">BLAHTEST</label> <input type="radio" id="radio3" name="radio" /><label for="radio3">BLAHSQLscript</label> <input type="radio" id="radio4" name="radio" /><label for="radio4">BLAHTEST</label> <input type="radio" id="radio5" name="radio" /><label for="radio5">BLAHREAD</label> <input type="radio" id="radio6" name="radio" /><label for="radio6">BLAHLOG</label> <input type="radio" id="radio7" name="radio" /><label for="radio7">BLAHUSAGE</label> <input type="radio" id="radio8" name="radio" /><label for="radio8">BLAHNETWORK</label> <input type="radio" id="radio9" name="radio" /><label for="radio9">BLAH9</label> <input type="radio" id="radio10" name="radio" /><label for="radio10">BLAH10</label> </div> </form> <p> </p> <p><strong>Enter a site:</strong> <input type="text" name="search" id="search" /> <input type="submit" value="OK"/> (PUT IT IN THE SAME PAGE from the response of RADIO4 selected ---PLUS ----SEARCH) <div id="RESPONSE" style="width: 540px"></div> Hi, I'm having a bit of a problem sharing some variables I have across a few files. My first file (index.php) calls an ajax request for (display.php) and sends a few variables to it. All fine so far. display.php then does its thing and displays the content on index.php as it should. Now in display.php I need a variable to be passed back to index.php for use in a menu. I've tried setting a session variable in display.php but unfortunately this doesn't seem to work. I also can't use get or post as I don't want to refresh the page. Really scratching my head over this one! Edd I have a form with multiple options to fill out (its a admin form) i want to make sure only one of the of the options are set, so im checking if the variable is empty with if ($variable1 != NULL) { $new_variable = "yep, this option was filled out"; } so if the form sent anything from the form with the value 'variable1' it then sets a new variable ($new_variable) Problem is i have multiple fields so i need to make sure if it finds a a variable is not empty, then too check if the others have anything in them too. If it does find another (meaning more than one has been filled out) echo an error (echo "you must only complete one option..") What is the best way to check if more than one variable exists? Sorry if i explained it complicated. Thank you Hi, I want to send the following variable using the $_GET function: hello, im wondering how to properly code the following. Code: [Select] $stdate = date( 'Ymd', strtotime($pdate) ); $sttime = date( 'His', strtotime($tstart1) ); $dtStart = ".$stdate.'T'.$sttime.'Z'"; echo "$dtStart"; i would like the echo to read 20110309T050000Z Hello everyone, I'm sitting here in a position where I can't work on my site or test any code, but my mind is racing about what I can do to solve a particular problem that I have. I won't get into the problem because it would take more time to type than I have right now, but I have an idea for a simple solution, just not sure if it will work or not. So, here's my question: Is it possible to have multiple session variables during a session? Such as: $email=$_SESSION['email']; $user=$_SESSION['userid']; If this is possible, my problem is solved (I think)... otherwise, I have to keep thinking about it. Thanks for any help! Is there anyway I can like "exit" the variables so i can use the same variable name later in the page? |