|
PHP - How To After Submit Got To Insert.php
Similar TutorialsHi, I am new to php and I desperately need help inserting an image into my php submit form. The form works perfectly but I have no idea how to get an image to be shown when the recipeint fo the email receive it (would love to have my company logo at the top of the mail just after $message.. Below is my code : .... // Create Mail Message and Send Mail $to = 'x@domain.coma'; $subject = "Website Enquiry Received from www.domain.com"; $message = "The following message has been sent from the website." . "\n" . "\n" . "Date Sent: " . date("j F Y") . "\n" . "Date Sent: " . date("g:i a") . "\n" . "\n" . "From: $contactName $contactSurname" . "\n" . "\n" . "Their Contact & Personal Details" . "\n" . "=====================" . "\n" . "\n" . "Marital Status: $contactStatus" . "\n" . "Email: $contactEmail" . "\n" . "Cellphone Number: $contactNumber" . "\n" . "Address 1: $contactAddress1" . "\n" . "Address 2: $contactAddress2" . "\n" . "Suburb: $contactSuburb" . "\n" . "Postal Code: $contactPostalcode" . "\n" . "\n" . "\n" . $headers = "From: $contactName $contactSurname <$contactEmail>" . "\r\n" . 'X-Mailer: PHP/' . phpversion(); mail($to, $subject, $message, $headers); mail($contactEmail, 'Confirmation of email: "' . $subject . '"', $message, $headers); // Thank You Message header('Refresh: 0; url=/quote_confirm.htm'); } } ?> Hi all!!! I could really use some help. I'm burning my brain out trying to figure out the easiest way to go about this. Here is what I am trying to do (in a nutshell) so I could really use full coding examples. I need to create a text area with simple formatting tools such as Bold, Italics, Underline, Bullets, and Numbering. After formatting the text with only those available formatting tools, everything in the text area needs to be converted into html tags. After the conversion, the HTML data that is create is submitted into a single field into a SQL database. Any help will be greatly appreciated!!! I am trying to get this query correct. I want to insert a record into the database upon form submission but only if the record does not already exist. If the record exists, then I want it to be updated in the database.
What is happening: Upon form submit, a new record is entered into the database every time. Note: The contact_id column is both primary key and unique in my database. Here is my code:
if($_POST['submit']){
$con=mysqli_connect("localhost","username","password","database_name");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$org = mysql_real_escape_string($_POST['organization']);
$namefirst = mysql_real_escape_string($_POST['firstName']);
$namelast = mysql_real_escape_string($_POST['lastName']);
$emailaddy = mysql_real_escape_string($_POST['email']);
$phonenum = mysql_real_escape_string($_POST['phone']);
$appquestion = mysql_real_escape_string($_POST['appquestion']);
$banner = mysql_real_escape_string($_POST['banner']);
$bulletin = mysql_real_escape_string($_POST['bulletin']);
$giveaway = mysql_real_escape_string($_POST['giveaway']);
$app = mysql_real_escape_string($_POST['app']);
$tshirt = mysql_real_escape_string($_POST['tshirt']);
$tshirtp = mysql_real_escape_string($_POST['tshirtp']);
$print = mysql_real_escape_string($_POST['print']);
$party = mysql_real_escape_string($_POST['party']);
$orgnotes = mysql_real_escape_string($_POST['notes']);
$sql="INSERT INTO database_name (contact_id, first_name, last_name, email_address, phone_number, org, appquestion, banner, bulletin, giveaway, app, tshirt, promised_tee, print, party, org_notes)
VALUES
('','$namefirst','$namelast','$emailaddy','$phonenum','$churchorg','$appquestion','$banner','$bulletin','$giveaway','$app','$tshirt','$tshirtp','$print','$party','$orgnotes')
ON DUPLICATE KEY UPDATE first_name = '$namefirst', last_name = '$namelast', email_address = '$emailaddy', phone_number = '$phonenum', org = '$org', appquestion = '$appquestion', banner = '$banner', bulletin = '$bulletin', giveaway = '$giveaway', app = '$app', tshirt = '$tshirt', promised_tee = '$tshirtp', print = '$print', party = '$party', org_notes = '$orgnotes'" ;
if (!mysqli_query($con,$sql))
{
die('Error: ' . mysqli_error($con));
}
echo "1 record added";
mysqli_close($con);
}
From everything I have read, I need to use ON DUPLICATE KEY UPDATE to replace the old information with new information in the database upon form submission. While the insert part of my code is working, the portion with ON DUPLICATE KEY UPDATE is not working.
Why might this portion of the code not be working? Is there a better way to insert else update the information?
Thank you for any help or guidance you can give me! I've been working on this concept for three days and have read a ton of information about it, but am still not able to get it to work.
Say I have an "Entries" table. I want to submit same multiple entries using a form submission. And If I have other queries submitted in the same form, I want those quarries to be submitted only once. Is that possible to do? Here's my code.
if(isset($_POST['submit'])) {
$entries = 10;
$id = 55;
$name = 'Smith';
$insert = $db->prepare("INSERT INTO entries(id, name) VALUES(:id, :name)");
$insert->bindParam(':id', $id);
$insert->bindParam(':name', $name);
$result_insert = $insert->execute();
if($result_insert == false) {
echo 'Fail';
} else {
echo 'Success';
}
}
?>
<form action="" method="post">
<input type="submit" name="submit" value="SUBMIT" />
</form>
Edited January 13, 2019 by imgrooot Hi. Pretty straight forward I guess but as the name suggests am a newbie. I have a form that requires the user to enter certain parameters. If the values are blank it submits to itself and loads the error messages. What I want to do is create PHP code that submits the form to a different url. What I thought was create two forms (the second with hidden fields replicating the first form), each form having a different url in the action"" code. What I cant work out is the PHP IF ELSE code to submit form 2 if Form1 is is validated correctly. This is the PHP code relevant to the form validation. Help? <?php //If form was submitted if ($_POST['submitted']==1) { $errormsg = ""; //Initialize errors if ($_POST[width]){ $title = $_POST[width]; //If title was entered } else{ $errormsg = "Please enter width"; } if ($_POST[drop]){ $textentry = $_POST[drop]; //If comment was entered } else{ if ($errormsg){ //If there is already an error, add next error $errormsg = $errormsg . " & content"; }else{ $errormsg = "Please enter drop"; } } } if ($errormsg){ //If any errors display them echo "<div class=\"box red\">$errormsg</div>"; } //If all fields present if ($title && $textentry){ //Do something echo 'THIS IS WHERE I WANT THE CODE TO SUBMIT FORM 2 or SUBMIT FORM 1 TO A DIFFERENT URL'; } ?> Can anyone tell me why this is not INSERTing? My array data is coming out just fine.. I've tried everything I can think of and cannot get anything to insert.. Ahhhh! <?php $query = "SELECT RegionID, City FROM geo_cities WHERE RegionID='135'"; $results = mysqli_query($cxn, $query); $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($row = mysqli_fetch_array($results)) { $insert_city_query = "INSERT INTO all_illinois SET state_id=$row[RegionID], city_name=$row[City] WHERE id = null" or mysqli_error(); $insert = mysqli_query($cxn, $insert_city_query); if (!$insert) { echo "INSERT is NOT working!"; exit(); } echo $row['City'] . "<br />"; echo "<pre>"; echo print_r($row); echo "</pre>"; } //while ($rows = mysqli_fetch_array($results)) } //if (mysqli_num_rows($results)) else { echo "No results to get!"; } ?> Here is my all_illinois INSERT table structu CREATE TABLE IF NOT EXISTS `all_illinois` ( `state_id` varchar(255) NOT NULL, `city_name` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Here is my source table geo_cities structu CREATE TABLE IF NOT EXISTS `1` ( `CityId` varchar(255) NOT NULL, `CountryID` varchar(255) NOT NULL, `RegionID` varchar(255) NOT NULL, `City` varchar(255) NOT NULL, `Latitude` varchar(255) NOT NULL, `Longitude` varchar(255) NOT NULL, `TimeZone` varchar(255) NOT NULL, `DmaId` varchar(255) NOT NULL, `Code` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; I'm missing something here. I have a form, and when the submit is pressed, the relevant post data inserts into table one, then I want the last insert id to insert along with other form data into a second table. The first table's still inserting fine, but I can't get that second one to do anything. It leapfrogs over the query and doesn't give an error. EDIT: I forgot to add an error: I get: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'usage, why VALUES ('14', '', '123', '','1234', '', '')' at line 1 query:INSERT INTO tbl_donar (donar_fname, donar_name, donar_address, donar_address2, donar_city, donar_state, donar_zip, donar_email, donar_phone, donar_fax, donar_company) VALUES ('test 14', 'asdfa', 'asdf', 'adf','asdf', '', '', '', '123', '', '') Code: [Select] if (empty($errors)) { require_once ('dbconnectionfile.php'); $query = "INSERT INTO tbl_donar (donar_fname, donar_name, donar_address, donar_address2, donar_city, donar_state, donar_zip, donar_email, donar_phone, donar_fax, donar_company) VALUES ('$description12', '$sn', '$description4', '$cne','$description5', '$description6', '$description7', '$description8', '$description9', '$description10', '$description11')"; $result = @mysql_query ($query); if ($result) { $who_donated=mysql_insert_id(); $query2 = "INSERT INTO tbl_donation (donor_id, donor_expyear, donor_cvv, donor_cardtype, donor_authorization, amount, usage, why) VALUES ('$who_donated', '$donate2', '$donate3', '$donate4','$donate5', '$donate6', '$donate7')"; $result2 = @mysql_query ($query2); if ($result2) {echo "Info was added to both tables! yay!";} echo "table one filled. Table two was not."; echo $who_donated; //header ("Location: http://www.twigzy.com/add_plant.php?var1=$plant_id"); exit(); } else { echo 'system error. No donation added'; Hello, I'm having a bit of a problem here, all help to this issues would be much appreciated I am trying to use text boxes to insert numbers into the database based on what is inputed. If I have a string, like this for example: $variable = 09385493; And I want to insert it into the database like this: mysql_query("INSERT INTO integers(number) VALUES ('$variable')"); When checking the integers table in my database, looking at the number field, the $variable that was inserted is outputted as 9385493 Notice the number zero was taken out of the front of the number. If the number is double 0's (009385493), both of those zero's would disappear, too. Thanks the info posts beautifully i just canst seem to get the button to auto click or submit, tried numerous ways! help Code: [Select] <?php require_once "../store/paypal/utility.php"; require_once "../store/paypal/constants.php"; $url = "https://www.".DEFAULT_ENV.".paypal.com/cgi-bin/webscr"; $postFields = "cmd=".urlencode("_notify-synch"). "&tx=".urlencode(htmlspecialchars($_GET["tx"])). "&at=".urlencode(DEFAULT_IDENTITY_TOKEN); $ppResponseAr = Utils::PPHttpPost($url, $postFields, true); if(!$ppResponseAr["status"]) { Utils::PPError($ppResponseAr["error_msg"], $ppResponseAr["error_no"]); exit; } $httpParsedResponseAr = $ppResponseAr["httpParsedResponseAr"]; // assign posted variables to local variables $item_name = $httpParsedResponseAr['item_name']; $item_number = $httpParsedResponseAr['item_number']; $receiver_email = $httpParsedResponseAr['receiver_email']; $receiver_id = $httpParsedResponseAr['receiver_id']; $quantity = $httpParsedResponseAr['quantity']; $first_name = $httpParsedResponseAr['first_name']; $last_name = $httpParsedResponseAr['last_name']; $payer_email = $httpParsedResponseAr['payer_email']; $txn_type = $httpParsedResponseAr['txn_type']; $address_street = $httpParsedResponseAr['address_street']; $address_city = $httpParsedResponseAr['address_city']; $address_state = $httpParsedResponseAr['address_state']; $address_zip = $httpParsedResponseAr['address_zip']; $item_number = $httpParsedResponseAr['item_number']; $option_name1 = $httpParsedResponseAr['option_name1']; $option_selection1 = $httpParsedResponseAr['option_selection1']; $option_name2 = $httpParsedResponseAr['option_name2']; $option_selection2 = $httpParsedResponseAr['option_selection2']; $invoice = $httpParsedResponseAr['invoice']; $custom = $httpParsedResponseAr['custom']; $payer_id =$httpParsedResponseAr['payer_id']; ?> <html lang="en"> <head> <title>Rec</title> <link REL="stylesheet" href="include/style.css" type="text/css"> <!--[if IE]> <link REL="stylesheet" href="include/styleIE.css" type="text/css"> <![endif]--> <style> #center_block {width:50%;margin:0 auto;min-width:500px;} #contents_block {text-align:center;} #header_block {white-space:nowrap;height:25px;padding:0 10px 5px;text-align:center;} #fields_block {width:100%;margin:0;padding:10px} #header_block span {margin:0 5px} #buttons_block {padding:10px 10px 5px} #buttons_block div {padding:3px} #delimiter {margin:2px} #fields_block td {padding:3px 14px} #username_block td {padding-top:13px;white-space:nowrap;} #remember_block td {padding-bottom:13px;white-space:nowrap;} #required_block {text-align:left;padding:5px} </style> <!--[if IE]> <style> #main_block {width:100%} </style> <![endif]--> </head> <body> <script language="JavaScript" src="include/jquery.js"></script> <script language="JavaScript" src="include/jsfunctions.js"></script> <script language="JavaScript" src="include/runnerJS/RunnerBase.js"></script> <form action="rec.php" method="post" id="rec" name="rec.php"> <table id="center_block" align="center"> <tr><td id="contents_block"> <div class="main_table_border2 loginshade" id="main_block"> <table cellpadding=0 cellspacing=0 border=0 id="fields_block" class="loginshade"> <tr id="email_fieldblock"> <td align=left width=50% class=loginshade> <div align="left"><label for="value_email_1">Email:</label></div> </td> <td width=50% class=loginshade> <span id="edit1_email_0" style="white-space: nowrap;"><input id="value_email_1" style="" type="text" name="value_email_1" maxlength=50 value="<?php echo urldecode($httpParsedResponseAr["payer_email"]) ?>"> <font color="red">*</font></span> <div class="error"></div> </td> </tr> <tr id="pass_fieldblock"> <td align=left width=50% class=loginshade> <div align="left"><label for="value_pass_1">Pass:</label></div> </td> <td width=50% class=loginshade> <span id="edit1_pass_0" style=""><input style="" id="value_pass_1" type="Password" name="value_pass_1" maxlength=50 value="1234"> <font color="red">*</font></span> <div class="error"></div> </td> </tr> <tr id="confirm_block"> <td align=left width=50% class=loginshade> <div align="left"><label for="value_confirm_1">Re-enter password:</label></div> </td> <td width=50% class=loginshade> <span id="edit1_confirm_0" style=""><input style="" id="value_confirm_1" type="Password" name="value_confirm_1" value="1234"> <font color="red">*</font></span> <div class="error"></div> </td> </tr> <tr id="fname_fieldblock"> <td align=left width=50% class=loginshade> <div align="left"><label for="value_fname_1">First Name:</label></div> </td> <td width=50% class=loginshade> <span id="edit1_fname_0" style="white-space: nowrap;"><input id="value_fname_1" style="" type="text" name="value_fname_1" maxlength=50 value="<?php echo urldecode($httpParsedResponseAr["first_name"]) ?>"> <font color="red">*</font></span> </td> </tr> <tr id="lname_fieldblock"> <td align=left width=50% class=loginshade> <div align="left"><label for="value_lname_1">Last Name:</label></div> </td> <td width=50% class=loginshade> <span id="edit1_lname_0" style="white-space: nowrap;"><input id="value_lname_1" style="" type="text" name="value_lname_1" maxlength=50 value="<?php echo urldecode($httpParsedResponseAr["last_name"]) ?>"> <font color="red">*</font></span> </td> </tr> <tr id="address_fieldblock"> <td align=left width=50% class=loginshade> <div align="left"><label for="value_address_1">Address:</label></div> </td> <td width=50% class=loginshade> <span id="edit1_address_0" style="white-space: nowrap;"><input id="value_address_1" style="" type="text" name="value_address_1" maxlength=50 value="<?php echo urldecode($httpParsedResponseAr["address_street"]) ?>"> <font color="red">*</font></span> </td> </tr> <tr id="city_fieldblock"> <td align=left width=50% class=loginshade> <div align="left"><label for="value_city_1">City:</label></div> </td> <td width=50% class=loginshade> <span id="edit1_city_0" style="white-space: nowrap;"><input id="value_city_1" style="" type="text" name="value_city_1" maxlength=50 value="<?php echo urldecode($httpParsedResponseAr["address_city"]) ?>"> <font color="red">*</font></span> </td> </tr> <tr id="state_fieldblock"> <td align=left width=50% class=loginshade> <div align="left"><label for="value_state_1">State:</label></div> </td> <td width=50% class=loginshade> <span id="edit1_state_0" style="white-space: nowrap;"><input id="value_state_1" style="" type="text" name="value_state_1" maxlength=50 value="<?php echo urldecode($httpParsedResponseAr["address_state"]) ?>"> <font color="red">*</font></span> </td> </tr> <tr id="zip_fieldblock"> <td align=left width=50% class=loginshade> <div align="left"><label for="value_zip_1">Zip:</label></div> </td> <td width=50% class=loginshade> <span id="edit1_zip_0" style="white-space: nowrap;"><input id="value_zip_1" style="" type="text" name="value_zip_1" maxlength=50 value="<?php echo urldecode($httpParsedResponseAr["address_zip"]) ?>"> <font color="red">*</font></span> </td> </tr> <tr id="cosponsor_fieldblock"> <td align=left width=50% class=loginshade> <div align="left"><label for="value_cosponsor_1">Cosponsor:</label></div> </td> <td width=50% class=loginshade> <span id="edit1_cosponsor_0" style=""><input id="type_cosponsor_1" type="hidden" name="type_cosponsor_1" value="checkbox"><input id="value_cosponsor_1" type="Checkbox" name="value_cosponsor_1" ></span> </td> </tr> <tr id="recipients_fieldblock"> <td align=left width=50% class=loginshade> <div align="left"><label for="value_recipients_1">Recipients:</label></div> </td> <td width=50% class=loginshade> <span id="edit1_recipients_0" style="white-space: nowrap;"><input id="value_recipients_1" style="" type="text" name="value_recipients_1" maxlength=50 value="<?php echo urldecode($httpParsedResponseAr["quantity"]) ?>"> <font color="red">*</font></span> </td> </tr> <tr id="clients_fieldblock"> <td align=left width=50% class=loginshade> <div align="left"><label for="value_clients_1">Clients:</label></div> </td> <td width=50% class=loginshade> <span id="edit1_clients_0" style=""><input id="type_clients_1" type="hidden" name="type_clients_1" value="checkbox"><input id="value_clients_1" type="Checkbox" name="value_clients_1" ></span> </td> </tr> <tr id="space_block"></tr> </table> </div> </td></tr> </table> <input type=submit value="Submit" class=button id="saveButton1" onload="Submit"></form> </body> </html> Hey, who can help? Example: I want to insert a row with a input and a select option. I am inserting now with select option, but i want to insert with a input too, because if i need to insert a link instead of choosing from select option. --------- (puts a link)Link: ...link... (chooses nothing)Select: Choose one... Submit --------- I need something like if LINK is filled insert it. Nothing happens to SELECT, but they have to have the same row names. Hope its clear enough. Cheers i need the insert code I am wondering about the following problem: I have two sessions, one for the user ($_SESSION['user_id']) and second one for the products inside cart ($_SESSION['cart']). I need to insert data into table racun. I did it this way and it works, but i want to know if this can be done better? Code: [Select] while ($row=mysql_fetch_array($query)){ $id = $_SESSION['korisnik_id']; $idp = $row['product_id']; $kol = $_SESSION['cart'][$row['product_id']]['quantity'] ."<br>"; $insert = "INSERT INTO racun (product_id, quantity, korisnik_id) VALUES ('$idp', '$kol', '$id') "; $result = mysql_query($insert); } Just a quick question I have a form, couple of drop down boxes, input fields etc.. at the end is the submit button. now my question is should my insert into database sqls go before the submit button inside the form? out side the form? after the button inside the form? If by any chance you could give me some advice on the best way to layout my sql that would be great. They are big and go into three tables, at the moment I have them as three seperate queries but I think they must be able to go into one. can someone please help me with the layout and syntax. here is what the queries look like at the moment: if ($IBselect=$_POST ['IBselect']); { //CUSTOMER $enterCust="INSERT INTO customer(username, password, title, firstName, lastName, address, town, country, postCode, phone, email, dateCust) VALUES ('$_POST[username]', '$_POST[password]', '$_POST[title]', '$_POST[firstName]', '$_POST[lastName]', '$_POST[address]', '$_POST[town]', '$_POST[country]', '$_POST[postCode]', '$_POST[phone]', '$_POST[email]', 'DATE: Auto CURDATE()', CURDATE()"; $enterCust_query=mysql_query($enterCust)or die(mysql_error()); //CARD $enterCard="INSERT INTO card(cardNumber, name, expDate, cardID) VALUES ('$_POST[cardNumber]','$_POST[name]', ' $_POST[expDate]', '$_POST[cardID]')"; $enterCard_query=mysql_query($enterCard); //BOOKING $RCenterBook=mysql_query("INSERT INTO booking (custNumber, cardID, rideName, seatNo1, seatNo2, price, price2, dateBook, ID_time_tbl) VALUES ('$custNumber', '$_POST[cardID]', '$rideName', '$_SESSION[IBextract]', '$_SESSION[IBextract2]', '$IBendPrice1', '$IBendPrice2', 'DATE: Auto CURDATE()', CURDATE()', '$_SESSION[IB_slot_Time]'"); $IBenterBooking_query=mysql_query($IBenterBook); if (!mysql_query($enterCard, $enterCust, $IBenterBook)) { die("Error:" .mysql_error()); } echo "1 record added IB"; } Thanks =) Dear Sir/Madame I am trying to insert comments into a table called comments using echo ID in the input form but so far i can insert the comments with the post id but unable re-comment again kindly help me what do i do?
This is the input form:
<div>
<form action="ehscomment.php" method="post">
<input type="hidden" name="id" value="<?php echo $id ?>">
<div>
<label>Add comment</label>
<div>
<textarea rows="6" cols="110" name="comment" placeholder="comment"></textarea>
</div>
</div>
<input type="submit" name="postcomment" value="comment"></form>
</div>
And this is ehscomment.php
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "registration";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
if(isset($_POST['postcomment'])){
$id = $_POST['id'];
$comment = $_POST['comment'];
$sql = "INSERT INTO comments (id,comment)
VALUES ('$id','$comment')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();}
?>
Error message: Error: INSERT INTO comments (id,comment) VALUES ('242','asddd') I'm trying to use PDO and get used to doing things this way. I've been away from php/mysql for a few years, so, I'm crusty. I'm not getting any error messages back on this code, but the insert just doesn't happen. My first guess is that I'm doing something wrong with the datetime now() function. But, I may not have the PDO code right. I tried the script the old fashion way with mysql_query() and that worked. So, it has to be something in this code. I believe my server is set up to do PDO as it shows: PDO PDO support enabled PDO drivers mysql, sqlite pdo_mysql PDO Driver for MySQL, client library version 5.0.45 My php version is 5.2.14 and Mysql is 5.0.45. Any help would be appreciated. Code: [Select] $DBH = new PDO("mysql:host=$host;dbname=$dbname", $user, $pass); $DBH->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION ); $sql=$DBH->prepare("INSERT INTO assets(asset_name,date_added,short_desc) VALUES (:asset_name,NOW(),:short_desc)"); $sql->bindParam(':asset_name',$asset_name); $sql->bindParam(':short_desc',$short_desc); $name=$_POST["input1"]; $short_desc=$_POST["input2"]; $DBH->exec(); echo $name; echo "\nPDO::errorInfo():\n"; print_r($DBH->errorInfo()); } catch(PDOException $e) { echo "Syntax Error: ".$e->getMessage(); } I get the following message: Quote name4Query failed: Unknown column 'late' in 'field list' with this code. What does it mean? Code: [Select] <?php $apt=$_POST['search_term']; $stat = mysql_connect("localhost","root",""); $stat = mysql_select_db("prerentdb"); $query = "SELECT name FROM payments WHERE late = 'L'"; $stat = @mysql_fetch_assoc(mysql_query($query)); echo $stat["name"]; $name=$_POST['name']; $apt=$_POST['apt']; $amtpaid=$_POST['amtpaid']; $rentdue=$_POST['rentdue']; $prevbal=$_POST['prevbal']; $hudpay=$_POST['hudpay']; $tentpay=$_POST['tentpay']; $datepaid=$_POST['datepaid']; $late=$_POST['late']; $comments=$_POST['comments']; $paidsum=$_POST['paidsum']; $query = " INSERT INTO payhist (name,apt,amtpaid,rentdue,prevbal, hudpay,tentpay,datepaid,late,comments,paidsum) VALUES('$name','$apt','$amtpaid','$rentdue','$prevbal', '$hudpay','$tentpay','$datepaid','$late','$comments','$paidsum')"; $stat = mysql_query($query) or die('Query failed: ' . mysql_error()); mysql_close(); echo "data inserted<br /><br />"; ?> Hello!Is this correct? Code: [Select] $sql="INSERT INTO pacienti (nume, prenume, cnp, varsta, sex, casa_asigurari, oras, strada, numar, judet, data_inregistrarii) VALUES ('$_POST[nume]','$_POST[prenume]','$_POST[CNP]','$_POST[varsta]','$_POST[sex]','$_POST[casa]','$_POST[oras]','$_POST[strada]','$_POST[nr]','$_POST[judet]','$_POST[internare]')"; $sql="INSERT INTO diagnostic (nume) VALUES ('$_POST[diagnostic]')"; and i mean..if i can do 2 insert in 2 different tables...or how can i do this? Okay, I'm hoping one of you can help me. I have a mysql database that I have configured through phpmyadmin. I have an android app that simply makes and sends a mysql query I can get it to successfully return values when using Select statements but when I use INSERT INTO, it returns " Error Query is invalid" BUT BUT BUT, when I use the same string and enter it through the sql tab in myphpadmin it works fine ! So here is the string ( the semicolons at the end of each field name are so I can use something common to split the string up when the data arrives back on the phone) Code: [Select] randomkey||||||INSERT INTO table4 (`geolat;` , `geolong;` , `mode;` , `destgeolat;` , `destgeolong;` , `cellphone;` , `email;` , `carrego;` , `colour;` , `rating;` , `comment;`) VALUES (0.0,0.0,'driver' ,-43.54779,172.62472, , '' ,'' , 'text' , 'ratingleftblank' , 'commentblank' ) the index4.php script is as follows Code: [Select] ?php /* * Written By: * James */ /************************************CONFIG****************************************/ //DATABSE DETAILS// $DB_ADDRESS="mysql1.openhost.net.nz"; $DB_USER="bling44"; $DB_PASS="sadlyinept"; $DB_NAME="bling44"; //SETTINGS// //This code is something you set in the APP so random people cant use it. $SQLKEY="randomkey"; /************************************CONFIG****************************************/ //these are just in case setting headers forcing it to always expire and the content type to JSON header('Cache-Control: no-cache, must-revalidate'); header('Content-type: application/json'); if(isset($_POST['tag'])){ //checks ifthe tag post is there $tag=$_POST['tag']; $data=explode("||||||",$tag); //split the SQL statement from the SQLKEY if($data[0]==$SQLKEY){ ///validate the SQL key $query=$data[1]; $link = mysql_connect($DB_ADDRESS,$DB_USER,$DB_PASS); //connect ot the MYSQL database mysql_select_db($DB_NAME,$link); //connect to the right DB if($link){ $result=mysql_query($query); //runs the posted query (NO PROTECTION FROM INJECTION HERE) if($result){ if (strlen(stristr($query,"SELECT"))>0) { //tests if its a select statemnet $outputdata=array(); while ($row = mysql_fetch_assoc($result)){ $outputdata[]=$row; //formats the result set to a valid array } echo json_encode(array("VALUE",$tag,array_merge($outputdata))); //sends out a JSON result with merged output data } else { echo json_encode(array("VALUE",$tag,array_merge(array(array("AFFECTED_ROWS ".mysql_affected_rows($link)))))); //if the query is anything but a SELECT it will return the array event count } } else echo json_encode(array("VALUE",$tag,array_merge(array(array("ERROR QUERY IS INVALID"))))); //errors if the query is bad mysql_close($link); //close the DB } else echo json_encode(array("VALUE",$tag,array_merge(array(array("ERROR Database Connection Failed"))))); //reports a DB connection failure } else { echo json_encode(array("VALUE",$tag,array_merge(array(array("ERROR BAD CODE SUPPLIED"))))); //reports if the code is bad } } ?> So to reiterate. I can search the DB but can't INSERT INTO, unless I go through the myphpadmin interface. Any ideas are very much appreciated I am working with a insert query... Code: [Select] $query="INSERT INTO user_info_more (website) VALUES ('".$website."') WHERE id='$_SESSION[id]'"; mysql_query($query) or die ('Unable to register an account with following details 1'); but the output is " Unable to register an account with following details 1" Basically i have a row with 6 cloumns in mysql database in which only the id column and name column is filled... Now i want to insert $website in the "website" column of the database... Neither i can update as the website column initially is null... I do not know what to do.... A lot of cnfusion Would someone be able to tell me why I can't run a successful mysql_query($sql) with $sql="INSERT INTO myDB.Titles (Title, Year, cID) values('". $title . "', '" . $year . "', '" . $cID . "')"; $sql echoes out to "INSERT INTO myDB.Titles (Title, Year, cID) values('Test', '2000', '2')" It looks right but I'm probably off on the quotes somewhere. Thanks in advance. |
|||||||