PHP - How Can I Best Allow Users To Syndicate My Content With One Line Of Code?

Hi,

I have a table row that has a dropdown and two textboxes in it.

I would like to use a button that allows me to add another row beneath the existing row.  It cannot be added to the bottom of the table as there is further content beneath.

The content of the dropdown comes from a database query.

The dropdown on the new row should have the selection in the first row greyed out.

I expect this will need to be a js function but i dont really know where to start with it being dynamic content.

This is the table as it stands if this provides clarity of my intentions - picture below

					echo "<form method='post' id='staffOrderForm'>";
							$stmt->close();
										echo "<table id='staffOrderTable' class='table table-striped table-bordered mt-3 text-center'>";
						foreach($daterange as $date){
														
									echo"
										<tr>
											<th class='table-dark' colspan='3'>".$date->format("l - jS F Y")."</th>
										</tr>
										<tr>
											<th class='' colspan='3'>Management	</th>
										</tr>
										<tr>
											<th class='col-4'>Name</th>
											<th class='col-4'>Start Time</th>
											<th class='col-4'>End Time</th>
										</tr>
										<tr>
											<td>
												<select class='custom-select managerSelect'>";
												$managerRoleId = 1;
												$stmt = $conn->prepare("
												 	SELECT user_firstname, user_lastname, user_id
												    FROM ssm_user
												    WHERE user_role_id = ? ");
												$stmt->bind_param("i", $managerRoleId);
												$stmt->execute();
												$stmt->store_result();
												$stmt->bind_result($ufn, $uln, $uid);
												while($stmt->fetch()){echo "<option>".$ufn." ".$uln."</option>";};
												echo"</select>
											</td>
											<td><input class='form-control' type='' name=''></td>
											<td><input class='form-control' type='' name=''></td>
										</tr>
										<tr>
											<th colspan='3'>Chefs</th>
										<tr/>
										<tr>
											<th class='col-4'>Name</th>
											<th class='col-4'>Start Time</th>
											<th class='col-4'>End Time</th>
										</tr>
										<tr>
											<td>
												<select class='custom-select chefSelect'>";
													$chefRoleId = 2;
													$stmt = $conn->prepare("
												 	SELECT user_firstname, user_lastname, user_id
												    FROM ssm_user
												    WHERE user_role_id = ? ");
													$stmt->bind_param("i", $chefRoleId);
													$stmt->execute();
													$stmt->store_result();
													$stmt->bind_result($ufn, $uln, $uid);
													while($stmt->fetch()){echo "<option>".$ufn." ".$uln."</option>";};
												echo"</select>
											</td>
											<td><input class='form-control' type='' name=''></td>
											<td><input class='form-control' type='' name=''></td>
										</tr>";
						}
						echo "</table></form>";

I appreciate that i will likely have to add a button with an onclick but from there i am pretty lost.

As always i appreciate the help provided.

Hello   I am trying to work out how many regular users I have to my site and how long those users tend to be users..   So, I have a table that logs every time a user visits my site and logs in, it stores the date / time as a unix timestamp and it logs their user id.   I started by getting the id's of any user who logs in more than 5 times in a specified period, but now I want to extend that...  

 
SELECT userID as user, count(userID) as logins FROM login_history where timestamp > UNIX_TIMESTAMP('2014-06-01 00:00:00') and timestamp < UNIX_TIMESTAMP('2014-07-01 00:00:00') group by user having logins > 5;
 

I looked up 'how to get all POST variables' and I ended up putting this bit of code together.  Im not experienced at all with OOP programming, but I think that when '=>' is used its to do with OOP?  Anyway.  I dont get this code.  I understand Foreach $_POST, as $someVar, (BTW im looking for checkboxes from a form), However, If I leave out the '=> $val' I simply get a lot of 'on' values, indicating the checkboxes I checked.

However, WITH the '=> $val' I end up with the checkbox name.  Now i've changed the name of '$val' so i know its not a keyword.  But i dont get it.  Is there a way to access the value of the checkbox? Can someone explain to me whats going on here?  I know that I can get the value of the checkbox by $_POST['$checkRows'] But, I have a feeling It can be done in the foreach line.

foreach($_POST as $checkRows => $hip)
      {
         echo "POSTED: $checkRows<br>\n";         
      }

Please help!

Hi, can any see is the are mistakes in this for me.

Thanks

echo'<img src="skinFiles/'.$skin['thumb_name'].'"class="skinImage" onclick="changeSkin(\'skinFiles/'.$skin["css_name"].'\')" />';

How do I remove the captcha check on this line and keep it valid?

if ($author && $message && ($capatcha == 6 || controlPosts::isAdmin()))

I tried

if ($author && $message && (controlPosts::isAdmin()))

but the script wont post like this?

ok, this is a much shorter version, but

i have:
Code: [Select]
$val = "1";

then i have a function
Code: [Select]

function  include_function_name{

echo'
<ul><li>
<a href="index.php?pageID="{$val}"">page name</a>
<li/><ul/>';
}


i have tried all sorts of variations but i can get it to make pageID=1



plaease help
thanks
ricky

for timthumb in my wordpress i use this code to
function first_image() {
  global $post, $posts;
  $first_img = '';
  ob_start();
  ob_end_clean();
  $output = preg_match_all('/<img.+src=[\'"]([^\'"]+)[\'"].*>/i', $post->post_content, $matches);
  $first_img = $matches [1] [0];
 
  if(empty($first_img)){ //Defines a default image
    $first_img = "images/default.gif";
  }
  return $first_img;
}

it works really well, then i thought why not to make it show random images if timthumb dont find any image?

so the 1st googling i did came up with this function:
<?php 
function getRandomFromArray($ar) { 
    mt_srand( (double)microtime() * 1000000 ); 
    $num = array_rand($ar); 
    return $ar[$num]; 
} 

function getImagesFromDir($path) { 
    $images = array(); 
    if ( $img_dir = @opendir($path) ) { 
        while ( false !== ($img_file = readdir($img_dir)) ) { 
            // checks for gif, jpg, png 
            if ( preg_match("/(\.gif|\.jpg|\.png)$/", $img_file) ) { 
                $images[] = $img_file; 
            } 
        } 
        closedir($img_dir); 
    } 
    return $images; 
} 

$root = ''; 
// If images not in sub directory of current directory specify root  
//$root = $_SERVER['DOCUMENT_ROOT']; 

$path = 'images/'; 

// Obtain list of images from directory  
$imgList = getImagesFromDir($root . $path); 

$img = getRandomFromArray($imgList); 

?>

and to show random image i Place the following where i wish the random image to appear:

Code: [Select]
<img src="<?php echo $path . $img ?>" alt="" />
my question is how to place this code in my function first_image??
i need to do something like this, but it doesnt make any sense:
if(empty($first_img)){ //Defines a default image
    $first_img = " <img src="<?php echo $path . $img ?>" alt="" />
this was my thought, if i can mix those 2 normally it should work, right?

or maybe there is another way to show random image in the Code: [Select]
[i] if(empty($first_img)){ //Defines a default image[/i]
  [b]  $first_img = ?

Can you suggest a better way to write this code (I didn't create it):

<body onload="getParameterByName('url')">

<a href="" id="urllink" >Click Here</a>

</body>

so, I don't have to change the <body> tag?

I just discovered that I have a major security flaw with my website.
Anyone who logs in to the website can easily access other users information as well as delete and edit other users information just by changing the ID variable in the address bar.
I have user ID Session started on these pages but still people can do anything they like with other users information just by editing the address bar.
For example if your logged in in the address bar of www.mywebsite.com/delete_mystuff.php?id=5 and change the "5" say to a "9" then you will have access to user#9 information.

Every important page that I have has this code:
Code: [Select]
 session_start();

if (!isset($_SESSION['user_id'])) {
// Start defining the URL.
         $url = 'http://' . $_SERVER['HTTP_HOST'] . dirname($_SERVER['PHP_SELF']);
// Check for a trailing slash.
         if ((substr($url, -1) == '/') OR (substr($url, -1) == '\\') ) {
         $url = substr ($url, 0, -1); // Chop off the slash.
}
// Add the page.
$url .= '/index.php';
ob_end_clean(); // Delete the buffer.
header("Location: $url");
exit(); // Quit the script.
} else {
                //Else If Logged In Run The Script

if((isset($_GET['id'])) && (is_numeric($_GET['id']))) {
         $id = (int) $_GET['id'];
} elseif ((isset($_POST['id'])) && (is_numeric($_POST['id']))) {
         $id = (int) $_POST['id'];
} else {
         echo ' No valid ID found, passed in url or form element';
        
         exit();
}



What am I doing wrong?
Please help if you know how to correct this.

Many thanks in advance.

I'm using a templated PHP script and have successfully added a link (to an image) 

$tab is a variable for my table's name


<?php
       while($row=mysqli_fetch_assoc($result)){
?>

       <?php echo $row['{$tab}_name']?>




   

I've made up some new code but I have an issue with trying to figure out why it won't work. Do you see any issues with it?

$rss = fetch_feed('<?php echo get_post_meta($post->ID, "linktosource", true);?>');

Thanks in advance

can anyone help me with an overwhelming problem ?

I want to use this command in the php curl code.

curl -v --data "WSCommunityStringRW?2=1200ve50set&Submit=Submit" http://10.2.3.111/Forms/SnmpCommunityString -u "admin:a1s2d3" --anyauth

I have a mysql table which will store users email addresses (each is unique and is the primary field) and a timestamp. 
I have added another column called `'unique_code' (varchar(64), utf8_unicode_ci)`.

What I would very much appreciate assistance with is;

a) Generating a 5 digit alphanumeric code, ie: 5ABH6 
b) Check all rows the 'unique_code' column to ensure it is unique, otherwise re-generate and check again 
c) Insert the uniquely generated 5 digit alphanumeric code into `'unique_code'` column, corresponding to the email address just entered. 
d) display the code on screen.

What code must I put and where?


**My current php is as follows:**

Code: [Select]
    require "includes/connect.php";
   
    $msg = '';
   
    if($_POST['email']){
   
    // Requested with AJAX:
    $ajax = ($_SERVER['HTTP_X_REQUESTED_WITH']  == 'XMLHttpRequest');
   
    try{
    if(!filter_input(INPUT_POST,'email',FILTER_VALIDATE_EMAIL)){
    throw new Exception('Invalid Email!');
    }
   
    $mysqli->query("INSERT INTO coming_soon_emails
    SET email='".$mysqli->real_escape_string($_POST['email'])."'");
   
    if($mysqli->affected_rows != 1){
    throw new Exception('You are already on the notification list.');
    }
   
    if($ajax){
    die('{"status":1}');
    }
   
    $msg = "Thank you!";
   
    }
    catch (Exception $e){
   
    if($ajax){
    die(json_encode(array('error'=>$e->getMessage())));
    }
   
    $msg = $e->getMessage();
    }
    }

I hav a php page which takes data from the db.But the problem i am facing is for a particular fild in database ,i have long data,which i need to b displayed in a wordwrap way

eg my data is "    Description      need a site for school    gave order on 12-10-2010     work started on 12-10-2010   "
this shuld  be displayed as
"Description      need a site for school
                        gave order on 12-10-2010
                        work started on 12-10-2010"

Description is the field in the database and rest of them are the datas in it