PHP - Simple-image.php Error

I have an error somewhere in the form as it does not output what I want it too. I know the form itself is working as I have added an echo to see if the form inputs are processed.

the code:
Code: [Select]
<?php
$amount = $_POST['amount'];
$member = $_POST['member'];

$sql = ("SELECT name FROM vtp_members WHERE name=".$member." ");
$result = mysql_query($sql);
$numrows = mysql_num_rows($result);
if($numrows = '1')
{
  while($row = mysql_fetch_array($result, MYSQL_ASSOC))
    {
echo "You sent ". $amount . " to " . $member . ".<br />";
}
}
echo " ".$amount." and ".$member." ";
?>
It outputs the last echo correct.

is there anyone who can see what I'm doing wrong?

Hi Everyone,

Just wondered if someone could quickly help me out, im building a simple login system for my website but having a little bit of trouble, the error i keep getting is:

Quote

Cannot modify header information - headers already sent by (output started at /home/sites/cuju8.com/public_html/include.php:18) in /home/sites/cuju8.com/public_html/login.php on line 12


I have done some research but cant find the answer to this, my login script is as follows:

Code: [Select]
<?php
require_once('include.php');
$error = '';
$form = $_POST['submit'];
$email = $_POST['email'];
$password = $_POST['password'];

if( isset($form) ) {
if( isset($email) && isset($password) && $email !== '' && $password !== '' ) {
$sql = mysql_query("SELECT * FROM `usersystem` WHERE email='$email' and password='$password';");

if( mysql_num_rows($sql) != 0 ) { //success
$_SESSION['logged-in'] = true;
[b]header('Location: members.php');[/b]
exit;
} else { $error = "Incorrect login info"; }
} else { $error = 'All information is not filled out correctly';}
}
?>
I think its the header location code thats causing the problem but im not sure where to move it too.

If anyone could help i would really appreciate it.

Cheers

This is absolutely stupid. I'm debugging PHP in Eclipse PDT with XDebug and XAMPP on Windows 7. A section of code has been working for weeks. Suddenly I'm told the following is a syntax error (line 226)

$forumtitle = $forum['title'];
$threadtitle = $thread['title'];

Eclipse matches bracket and normally clipse would highlight [ when I put the cursor behind ]. Not here.

On similar statements before this I changed ' (single quote) to  (double quote)".  The brackets [ and ] highlighted correctly but the " produced a louder syntax error.. 

Then I simply removed the single quotes. No syntax error. Brackets match. But I will probably get a syntax error.

Usually stupidity like this indicates a quote problem somewhere before this code.  After looking very hard, I see none. It feels like something is wrong with the Eclipse editor and something has to be reset. But what?

I would appreciate any help.

Im sure this is simple, but I cannot see what my problem is!

I am hitting an error on my insert query

Code: [Select]
Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1
I know the output of $user_id is 1, so my error is on $mysavepath

Code: [Select]
$mysavepath = $folder.'/'.$worldname.'_'.date("dMjY");
echo $mysavepath;
$savepath = mysql_query("INSERT INTO saves (user_id,savepath) VALUES ('$user_id','$mysavepath')");
echo '<br>'.$savepath;
if(!mysql_query($savepath))
{
die('<br>Error: ' . mysql_error());
}

however it all echos out ok?

Code: [Select]
188ea678f0dcdc8252aeb15e3c910408/world_15Jan152012
1
Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1

Can anyone see the problem?

Cheers
Dave

i have this code
<?php
require_once('dbconnect.php')

$user = "test";
$pass = "test";

$result=mysql_query("SELECT * FROM accounts WHERE user = '$user' AND pass = '$pass' ");

if(mysql_num_rows($result) == 0) {
$login = "&err=Login Failed.";
echo($login);
} else {
$row = mysql_fetch_array($result);
$user = $row['user'];
$pass = $row['pass'];
$login = "&user=".$user."&pass=".$pass."&err=Login Successful.";
echo($login);
}

?>


and im getting this
Parse error: parse error in C:\wamp\www\flashstuff\WTF.php on line 4

line 4 is:
$user = "test";

all the dbconnect stuff is fine


help!

I'm using PHP 5.2 Server and Simple HTML DOM 1.5. This script scrape or extract data from a football site, its fully working on PHP 5.9 Server but I need to know how I can fix it for PHP 5.2 server. Can someone give me a hint on how can I fix the error? Thanks in advance.

My PHP 5.2 Server script output shows:
++++++++++++++++
Object id #599 Object id #604 Object id #609 Object id #614 Object id #619
Object id #627 Object id #632 Object id #637 Object id #642 Object id #647
Object id #655 Object id #660 Object id #665 Object id #670 Object id #675
Object id #683 Object id #688 Object id #693 Object id #698 Object id #703
Object id #711 Object id #716 Object id #721 Object id #726 Object id #731
++++++++++++++++

while PHP 5.9 Server says
++++++++++++++++
Rk Player Team POS OPPONENT
1 Aaron Rodgers GB QB at CAR
2 Tom Brady NE QB vs. SD
3 Matt Schaub HOU QB at MIA
4 Michael Vick PHI QB at ATL
++++++++++++++++

I did applied the bug solution listed on https://sourceforge.net/tracker/index.php?func=detail&aid=3107230&group_id=218559&atid=1044037 but it is still not working. It says:
++++++++++++++++
Details:

I get compiler errors in PHP 5.2 when using this as an object.

The offending lines are 609 and 940, which both contain this construct:

if ($this->size>0) $this->char = $this->doc[0];

This tries to get the first character of $this->doc, but PHP 5.2 sees it as trying to access it as an array. It's easily fixed by this:

if ($this->size>0) $this->char = substr($this->doc, 0, 1);

Or you could probably use chr(ord($this->doc)) as well. Either way solves the compile error without changing functionality.
++++++++++++++++

Here are my codes:

Code: [Select]
<?php
# don't forget the library
include('simple_html_dom.php');

# this is the global array we fill with article information
$articles = array();
$source = 'http://www.athlonsports.com/columns/winning-game-plan/fantasy-football-qb-rankings';
# passing in the first page to parse, it will crawl to the end
# on its own
getArticles($source);      


function getArticles($page) {
global $articles, $descriptions;

$html = new simple_html_dom();
$html->load_file($page);

//$items = $html->find('div[class=preview]');
$items = $html->find('tbody tr');

foreach($items as $post) {
    # remember comments count as nodes
   /*$articles[] = array($post->children(3)->outertext,
                        $post->children(6)->first_child()->outertext);*/
    $articles[] = array($post->children(0), $post->children(1), $post->children(2), $post->children(3), $post->children(4));
}

# lets see if there's a next page
if($next = $html->find('a[class=nextpostslink]', 0)) {
    $URL = $next->href;
    echo "going on to $URL <<<\n";
    # memory leak clean up
   $html->clear();
    unset($html);

    getArticles($URL);
}
}

?>


<html>
<head>
</head>
<body>
<?
echo "Source: " . $source;
?>
<table cellpadding="5" cellspacing="0" border="0">
<?php
    foreach($articles as $item) {
        echo "<tr>";
        echo "<td>" . $item[0] . "</td><td>" . $item[1] . "</td><td>" . $item[2] . "</td>";
        echo "<td>" . $item[3] . "</td><td>" . $item[4] . "</td>";
        echo "<tr>";
    }
?>
</table>


</body>
</html>

I have a table called "colors".  It has 2 columns, id and color.

All I'm trying to do is pull the data into the form, then edit the colors (for example - misspelled, etc.)
Then submit it back to the table.

Here is the code that pulls the data into a form so I can edit it:
Code: [Select]
<form action="adminupdatecolors.php" method="post">

<table width="500" border="1" cellpadding="10">

<tr>
  <td>Color Options:</td>
    <td>
    <?
$result = mysql_query("SELECT * FROM colors");
while ($row = mysql_fetch_assoc($result)) {

echo '<input type="text" name="color[]" value="' . $row['color'] . '"/>' . $row['id'] . '<br />';
}

?>
   </td>
</tr>

   <tr>
  <td>&nbsp;</td>
  <td><input type="Submit" value="Update Colors"></td>
  </tr>
</form>
</table>

Here is my update script:
Code: [Select]
<?php

include("config.php");
include("db.php");

$id=$_POST['id'];
$color=$_POST['color'];

$result = mysql_query("SELECT id FROM colors ORDER BY id DESC LIMIT 0,1");

if ($row = mysql_fetch_assoc($result)) {
$id = $row['id']; 
}
$sql = "DELETE FROM colors WHERE id='$id'";
mysql_query($sql) or die("Error: ".mysql_error());

foreach ($color as $colorvalue) {
$sql2 = "INSERT INTO colors (id,color) VALUES ($id,'$color')";
mysql_query($sql2) or die("Error: ".mysql_error());

}

header("Location: " . $config_basedir . "adminhome.php");

?>

Hello Freaks!

  I am having problem with following code:

<?php simplexml_load_string ('?xml version="1.0" encoding="utf-8"?>'); php?>

 This code is giving me following error

Parse error: syntax error, unexpected '<' in public_html/wp-content/plugins/pluginnamehere/whatever.php on line 665


I know there is only a minor bracket problem that causing me this error. I would be helpful to you if you can modify it for me

Thanks

PHP = 5.5.14 MySQL = 5.2.17   I've cloned a mysqli_connect() statement in a 'require' file placed in a non-public access location on the server.  It's the same format (and location) currently working fine with another application, EXCEPT i changed the database name to what I need to use for this application, AND added the $con= part on the front end to substitute for the commented out $con= line in the example code I'm modifying to insert data into a new MySQL DB Table.   The dB Table is fine and I have Inserted data via myPHPAdmin with no problems.  Only two form variables are in the simple PHP script thus far just to test if it will work before proceeding.   I've used pseudonames for the actual /home/.... location and filename, and am now Baffled about the Line 2 Error Message I'm getting (below the code).

<?php

require '/home/myusername/domains/mydomain.com/myclonedrequire.php';

//$con=mysqli_connect("example","uid","pwd","my_db");
// Check connection
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

// escape variables for security
$year = mysqli_real_escape_string($con, $_POST['year']);
$callsign = mysqli_real_escape_string($con, $_POST['callsign']);


$sql="INSERT INTO `lqplogs` (`year`, `callsign`)
VALUES ('$year', '$callsign');

if (!mysqli_query($con,$sql)) {
  die('Error: ' . mysqli_error($con));
}
echo "1 record added";

mysqli_close($con);
?>

ERROR Message:   Warning: Unexpected character in input: '\' (ASCII=92) state=1 in (above file & location) on line 2   There are NO '\' characters in any of my files.   Here is the simple Form file code:

<?php
?>
<html:
<head><title></title></head>
<body>
<form action="insert.php" method="post">
YEAR: <input type="text" name="year">
CALLSIGN: <input type="text" name="callsign">
<input type="submit">
</form>
</body>
</html>
<?php
?>

Thanks for any assistance!   -FreakingOUT      

Okay, I have no idea how this works out but this is really getting on my nerves.

Here is my logic for the following code. I manually register a user, It goes into the database and dispatches an email notification explaining that a user must activate their account and change their user name (OPTIONAL) and password. In the email, There is an automatically generated password with the username, And a link to activate the account. This leads to stage 1 of the activation process, In this stage the user is accepted, Registered as a verified user and then is sent to another page to change the details like login and password. As far as I know this page works except through trial and error I found that this little snippet of code is causing browsers to show an error 500 page, If I remove this the page works:

<?php
if($messages){

displayErrors($messages);
} else {

echo("<p align=\"center\" class=\"standard\">Your account has been activated.</p><p align=\"center\" class=\"standard\">You now need to change your password. If you like you can also change your username, Remember that you only have 3 days to do so and this change will be permanent.</p>");
}
?>

and this is the displayErrors function:

<?php
function displayErrors($messages) {

print("<p align=\"center\" class=\"standard\">"."<b>There were problems with the previous action:</b>\n<ul>\n");

foreach($messages as $msg){

print("<li>$msg</li>\n");

}

print("</ul>\n"."</p>");
}
?>


The displayErrors function is in a file called functions.php, Which is included in config.php, Which is included in every page including this one.

The entire "Change password and login page thingie" is he


<?php
include("config.php");
global $link, $messages;
require_once('recaptchalib.php');
if($_GET['error']){

$id=$_GET['id'];

$messages[]="There is more than one or no accounts with the verification code you are using. <a href=\"mailto:rentals@nivso.co.uk?subject=Two or no accounts with activation ID of $id\">Click here to email us about this and have the problem sorted.</a>";

doIndex();

exit;
}
if(isset($_POST['submit'])){

if(!isset($_POST['activationid'])){

die("Doesn't exist -.- might as well quit this is *STUFF* -.-");

}

$privatekey = "YOUR NOT HAVING THIS";

$resp = recaptcha_check_answer ($privatekey,

$_SERVER["REMOTE_ADDR"],

$_POST["recaptcha_challenge_field"],

$_POST["recaptcha_response_field"]);

if (!$resp->is_valid) {

$messages[]="The code you entered is incorrect. Please go back and try again!";

doIndex();

exit; // exit or the below lines will be processed.

} else {

//This is where the fun starts!

$login=$_POST['login'];

$passw=$_POST['password'];

$passc=$_POST['passwordc'];

$id2=$_POST['activationid'];

$changinglogin=false;

$get1=excDB("SELECT * FROM `users` WHERE `activeID`='$id2'");

if($get1[0]){ $get1=$get1[1]; } else { die($get1[2]); }

$pro1=mysql_fetch_array($get1);

if($pro1['login']!=$login){

$changinglogin=true;

field_validator("Login", $login, "alphanumeric", 4, 15);

}

field_validator("Password", $passw, "string", 6, 20);

if($passw!=$passc){

$messages[]="The passwords do not match, Please make sure that the passwords are the same!";

}

if($messages){

doIndex();

exit;

}

$passcl=mysql_escape_string($passw);

$passen=md5($passcl);

if($changinglogin){

$wri1=excDB("UPDATE `users` SET `login`='$login', `password`='$passen', `passchange`='1', `loginchange`='1' WHERE `activeID`='$id2';");

if($wri1[0]){ $wri1=$wri1[1]; } else { die($wri1[2]); }

header("Location: login.php?created");

} else {

$wri1=excDB("UPDATE `users` SET `password`='$passen', `passchange`='1', `loginchange`='0' WHERE `activeID`='$id2';");

if($wri1[0]){ $wri1=$wri1[1]; } else { die($wri1[2]); }

header("Location: login.php?created2");

}

}
} else { 

doIndex();
}
function doIndex(){
?>
<!DOCTYPE html>
<head>
<title>Family Rental System! - Rent your DVDs here - Design by Alex, Coding by Gergy008</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<link type="text/css" href="css/main.css" rel="stylesheet">
<style type="text/css">
<!--
body {

background-color: #333333;
}
-->
</style></head>
<body style="text-align:center;">
<div class="first">
<div class="backgrounder1"></div>
<div class="headerbar1"></div>
<div class="headerbar2"></div>
</div>
<div align="center">
<table border="0" cellpadding="0" cellspacing="0" width="900">
  <tr>
   <td><img src="images/spacer.gif" width="52" height="1" border="0" alt="" /></td>
   <td><img src="images/spacer.gif" width="123" height="1" border="0" alt="" /></td>
   <td><img src="images/spacer.gif" width="352" height="1" border="0" alt="" /></td>
   <td><img src="images/spacer.gif" width="33" height="1" border="0" alt="" /></td>
   <td><img src="images/spacer.gif" width="55" height="1" border="0" alt="" /></td>
   <td><img src="images/spacer.gif" width="110" height="1" border="0" alt="" /></td>
   <td><img src="images/spacer.gif" width="110" height="1" border="0" alt="" /></td>
   <td><img src="images/spacer.gif" width="50" height="1" border="0" alt="" /></td>
   <td><img src="images/spacer.gif" width="15" height="1" border="0" alt="" /></td>
   <td><img src="images/spacer.gif" width="1" height="1" border="0" alt="" /></td>
  </tr>

  <tr>
   <td colspan="9" background="images/template.slice.1.png">&nbsp;</td>
   <td><img src="images/spacer.gif" width="1" height="20" border="0" alt="" /></td>
  </tr>
  <tr>
   <td colspan="5" background="images/template.slice.2.png">&nbsp;</td>
   <td colspan="2" rowspan="2" background="images/template.slice.3.png"><span class="login"><?php echo(loginHandler()); ?></span></td>
   <td colspan="2" rowspan="3" background="images/template.slice.4.png">&nbsp;</td>
   <td><img src="images/spacer.gif" width="1" height="30" border="0" alt="" /></td>
  </tr>
  <tr>
   <td rowspan="8" background="images/template.slice.5.png">&nbsp;</td>
   <td colspan="2" background="images/template.slice.6.png"><form>
     <div align="center">
       <input name="textfield" type="text" id="textfield" size="40" style="height:16px;">
       <input type="submit" name="button" id="button" value="Search" style="height:20px;">
     </div>
   </form></td>
   <td colspan="2" rowspan="2" background="images/template.slice.7.png">&nbsp;</td>
   <td><img src="images/spacer.gif" width="1" height="30" border="0" alt="" /></td>
  </tr>
  <tr>
   <td colspan="2" rowspan="3" background="images/template.slice.8.png"><p>&nbsp;</p>
    <p>&nbsp;</p></td>
   <td colspan="2" background="images/template.slice.9.png">&nbsp;</td>
   <td><img src="images/spacer.gif" width="1" height="70" border="0" alt="" /></td>
  </tr>
  <tr>
   <td rowspan="2" background="images/template.slice.10.png">&nbsp;</td>
   <td colspan="4" background="images/template.slice.11.png">&nbsp;</td>
   <td rowspan="6" background="images/template.slice.12.png">&nbsp;</td>
   <td><img src="images/spacer.gif" width="1" height="30" border="0" alt="" /></td>
  </tr>
  <tr>
   <td colspan="4" background="images/template.slice.13.png"></td>
   <td><img src="images/spacer.gif" width="1" height="8" border="0" alt="" /></td>
  </tr>
  <tr>
   <td rowspan="4" background="images/template.slice.14.png">&nbsp;</td>
   <td colspan="4" background="images/template.slice.15.png">&nbsp;</td>
   <td colspan="2" rowspan="4" background="images/template.slice.16.png">&nbsp;</td>
   <td><img src="images/spacer.gif" width="1" height="35" border="0" alt="" /></td>
  </tr>
  <tr>
   <td colspan="4" background="images/template.slice.17.png">&nbsp;</td>
   <td><img src="images/spacer.gif" width="1" height="37" border="0" alt="" /></td>
  </tr>
  <tr>
   <td colspan="4" align="center" valign="top" background="images/template.slice.18.png" style="vertical-align:top;"><p class="standard">&nbsp;</p>
     <table width="80%" border="0">
      <tr>
        <td colspan="2">
          <?php
          

if($messages){

//displayErrors($messages);

} else {

//echo("<p align=\"center\" class=\"standard\">Your account has been activated.</p><p align=\"center\" class=\"standard\">You now need to change your password. If you like you can also change your username, Remember that you only have 3 days to do so and this change will be permanent.</p>");

?></td>
        </tr>
      <form name="ChangeDetails" method="post" action="<?=$_SERVER['PHP_SELF']?>">
      <input type="hidden" name="activationid" value="<?php if($_GET['id']){ $id=$_GET['id']; echo($id); } elseif($_POST['activationid']){ $id=$_POST['activationid']; echo($id); } else { die("No ID") } ?>" />
      <tr>
        <td width="50%"><div align="right" class="standard">New Username: </div></td>
        <td width="50%"><input name="login" type="text" id="login" size="35" maxlength="30" /></td>
      </tr>
      <tr>
        <td><div align="right" class="standard">New Password:</div></td>
        <td><input name="password" type="password" id="password" size="35" maxlength="30" /></td>
      </tr>
      <tr>
        <td><div align="right" class="standard">Re-enter password:</div></td>
        <td><input name="passwordc" type="password" id="passwordc" size="35" maxlength="30" /></td>
      </tr>
      <tr>
        <td><div align="right" class="standard">Please enter the code: </div></td>
        <td>

<?php

require_once('recaptchalib.php');

$publickey = "6Le4fsESAAAAAKMOHb8aaiyDfGRJyr0y0EU7dXm-"; // you got this from the signup page

echo recaptcha_get_html($publickey);
            ?>
        </td>
      </tr>
      <tr>
        <td>&nbsp;</td>
        <td><input type="submit" name="submit" id="submit" value="Change your details" /></td>
      </tr>
      </form>
    </table>
     </td>
   <td><img src="images/spacer.gif" width="1" height="450" border="0" alt="" /></td>
  </tr>
  <tr>
   <td colspan="4" background="images/template.slice.19.png">&nbsp;</td>
   <td><img src="images/spacer.gif" width="1" height="50" border="0" alt="" /></td>
  </tr>
  <tr>
   <td colspan="9" background="images/template.slice.20.png">&nbsp;</td>
   <td><img src="images/spacer.gif" width="1" height="40" border="0" alt="" /></td>
  </tr>
</table>
</div>
</body>
</html>
<?php
} ?>


Thanks to all you kind people that take your time to read and help me with this problem. I'm sorry if it is a really simple problem I missed out that makes me look like a right idiot and wasted your time, but that's me I'm always missing stuff out like that, I do proof read though just sometimes not good enough.

Thanks in advance!

I am trying to show images in a directory by date last modified. The code below is showing the oldest ones first then by file type.

How do I modify it to show all files by last uploaded to the directory? I want the newest ones showing first.

I am very new to PHP.

Code: [Select]
<?php

//Your folder
$files = glob("images/*.*");

$colCnt=0;
echo '<table border="0" style="width:1000px;">';

for ($i=1; $i<count($files); $i++)
  {
  $colCnt++;
  if ($colCnt==1)
  echo '<tr>';
  echo '<td width="20%" style="font-size:8.5px; font-family:arial">';

  $num = $files[$i];
   
echo ' 
   <a href="' . $num . '"><img class="thumb ImgBorder" src="'.$num.'" rel="lightbox" alt="random image"></a>'."&nbsp;&nbsp;";



  echo '</td>';

  if ($colCnt==6)
    {
    echo '</tr>';
    $colCnt=0;
    }
  }

echo '</table>';
?>

hey guys im trying to impliment a overlay to images uploaded by the user to allow to delete and crop...now im not sure if im going aroung this the right way (but it works sort of)...the problem im having is that the overlay.gif which is a transparent image which has 2 small images at the top of each corner...but when the original image is hovered over the overlay is out of position showing the 2 small images at the bottom of the div and not at the top where it should be.   im guessing it is a css issue...any advise would be greatly appreciated...thank you

#overlay
{
	width: 110px;
	height: 110px;	
}
.selected-image{
	width: 110px;
	height: 110px;
}
#overlay:hover  .selected-image  
{ 
opacity: 0.4;
    filter: alpha(opacity=40);	
}

#overlay:hover
{

	background-image: url('overlay.gif');
	width: 110px;
	height: 110px;
	
}

<div id="overlay"><img class="selected-image" src="logo.png" /></div>

The code below works well and shows all the images in a folder in reverse chronological order. But I want to limit it to a certain number of images .   This would enable me to have several pages of images.

So the first page would display the latest 50 images, the second page would show 50-100, and the third, 100-150.

Any helps on how to modify? I can create the pages manually. I just want to know how to limit the current page to a certain range.
Code: [Select]
<?php

//Your folder
$files = glob("images/*.*");

function sortnewestfilesfirst($a, $b) {
    return filemtime($b) - filemtime($a);
}
usort($files, "sortnewestfilesfirst");

$colCnt=0;
echo '<table border="0" style="width:1000px;">';

for ($i=0; $i<count($files); $i++)
  {
  $colCnt++;
  if ($colCnt==1)
  echo '<tr>';
  echo '<td width="20%" style="font-size:8.5px; font-family:arial">';

  $num = $files[$i];
   
echo ' 
  <div class="ImgBorder">
   <div class="clipout">
    <div class="clipin"> <a href="' . $num . '" rel="lightbox[all]"><img class="thumb ImgBorder" src="'.$num.'">  
</a> </div>
   </div></div>'."&nbsp;&nbsp;";


  echo '</td>';

  if ($colCnt==6)
    {
    echo '</tr>';
    $colCnt=0;
    }
  }

echo '</table>';
?>

I am using cakephp and i need a quick simple image upload and re-size script, can any one help?

Hi Guys,

Please can someone here help me with a simple browse for an image from the computer and then when the form is submitted it uploads the image and then saves the image url in my DB.

my form page is here http://bit.ly/gntCvD

Any help will be appreciated.

thanks

Craig