PHP - Variable Won't Exist Beyond Break;
Working with authorize.net script that is included in my php. Trying to figure out how to use a variable beyond the 'case' I can do just about anything... inside the case... But I need to use the variable outside of there.
Code: [Select] //several cases above case 5: $this->approval_code = $pstr_trimmed; break; // case 7 is the authorize.net transaction ID - This is the one I want to work with case 7: echo "Transaction ID: "; echo $pstr_trimmed; $trans_id_test = $pstr_trimmed; break; // but this below won't work. I can't use the variable anywhere outside of the case. echo "the new variable is now...".$trans_id_test; Similar TutorialsI guess I'm just stupid cause it seems like every time i get stuck and i post on here and its gets answered in less than 30 min.'s and i keep getting stuck! Here my script... function scoring($user){ $query = "SELECT Game_ID, Pick FROM Cfb WHERE User_ID= 1"; $result = mysql_query($query); $query1 = "SELECT Game_ID, Pick FROM Cfb WHERE User_ID= $user"; $result1 = mysql_query($query1); $affected = mysql_num_rows($result); for($i=0; $i< $affected; $i++) { $scores =mysql_fetch_assoc($result); $scores1 =mysql_fetch_assoc($result1); $main = array_diff_assoc($scores,$scores); $me = array_diff_assoc($scores, $scores1); $m = count($me); $m1 = count($main); if ($m == $m1){ $points += 1; }else{ $points += 0; } } echo '<br />'; echo '<br />'; echo $user; echo '<br />'; echo $points; echo '<hr />'; } $sql="SELECT id FROM users WHERE approved=1 AND user_level !=10"; $result=mysql_query($sql); while($row = mysql_fetch_object($result)) { $ids[] = $row->id; } print_r($ids); Alright heres what this script does... The script has a function that scores 1 individual user for his/her choices. Then I'm getting the user_ids from the users table at the bottom. Taking those and plugging them back into the function to score all the users at one time. Problem... Not all users will make picks. So how do i break the script in the function if that user_id is not is the CFB table attached to picks I have 2 tables im using Cfb and users users controls user info such as id # name username ect.. Cfb controls the picks. When a user makes there selection it stores there User_ID, Game_ID, and Pick So not all user ids are in the Cfb table. So if the script tries to input a user id thats not in the Cfb table it needs to break. Right now it just screws everything up! So how can i make it break that way? Thanks for any help hi, im having trouble adding a get variable to a url if one already exists. eg current url = http://www.example.com/index.php?var1=something i want to be able to change this to new url = http://www.example.com/index.php?var1=something&var2=another even so i can have a few get variable there. I can add the first var through a form or link, but how would i add more through a link or through the header function? I am positivly stuck. Thanks Quote
#adf #234432 #fwerfw I have this as a result of a form that has been completed. It might be twice that, it might be much much more. But what I want to do is render it on a page inside Divs. So each one is in a kind of shaded box. The CSS side of it is easy, but how do I extract each one of these into a variable useful means to surround each one by <div>$variable</div>? I thought it might be "explode", but you appear to have to state the [3] number of the variable to show. In this case, it's totally random. We won't be using these as Variables to trigger anything else, it's purely "for display" purposes. i have error where my code should update existing data where id exist, it get updated ..but the others data is disappeared .only the data updated is remained $sql1 ="select*from semakan_dokumen where email='$stdEmail'"; $sqlsearch1 = mysqli_query($dbconfig,$sql1); $resultcount1 = mysqli_num_rows($sqlsearch1); if($resultcount1 > 0){ $query1=("UPDATE semakan_dokumen set student_id='$noMatrik', email= '$stdEmail', surat_tawaran='$fileName', ic='$fileName1',sijil_lahir='$fileName2',sijil_spm= '$fileName3',sijil_sekolah= '$fileName4', sijil_dip= '$fileName5',sej_julai='$fileName6',bm_julai='$fileName7',muet='$fileName8', mid1='$fileName9',yuran= '$fileName10',umpa_bend1= '$fileName11',umpa_bend2='$fileName12',bpkp='$fileName13', penaja='$fileName14',kesihatan= '$fileName15', jhepa='$fileName16' where email= '$stdEmail' "); }else{ //filezip $query1 = "INSERT INTO semakan_dokumen (email,surat_tawaran,ic,sijil_lahir,sijil_spm,sijil_sekolah,sijil_dip,sej_julai,bm_julai,muet,mid1,yuran,umpa_bend1,umpa_bend2,bpkp,penaja,kesihatan,jhepa) VALUES ('$stdEmail','$fileName','$fileName1','$fileName2','$fileName3','$fileName4','$fileName5','$fileName6','$fileName7','$fileName8','$fileName9','$fileName10','$fileName11','$fileName12','$fileName13','$fileName14','$fileName15','$fileName16')"; }
if so how would they be used in a mysql query? Does the concept of a "Namespace" exist in PHP? If so, how do you use them? This is a snippet from ASP.NET that made me ask this question... Quote <%@ Import Namespace="System.Data" %> <%@ Import Namespace="System.Data.SqlClient" %> TomTees Hi all - I have a form that let's a user upload an image to their specified folder. The folder is determined by the "password" the user inputs. The "password" is really just the folder name on my server, so if "michael83" was entered as a password, the directory would be "images/uploaded/michael83". That works great now, thanks to a forum user, litebearer. Thanks again. Here's my second question: I'm working on a "history" page so that a user can input their "password" and view their upload history. The form works right now. If you enter a "password" (folder name) that exists, the code will spit out the contents / files. So, now I'm looking for two things: (1) if a user enters a "password" (folder name) that exists, but there are no files in the folder, "There are no files in the $dir directory." will be echoed; and (2) if a "password" (folder name) is entered that does NOT exist, "The directory $dir does not exist." will be echoed. Here's my code so far (minus the if statements I'm looking for): $dir = $_POST['password']; $path = "images/uploaded/". $dir; $dir_handle = @opendir($path); while ($file = readdir($dir_handle)) { if($file == "." || $file == ".." ) continue; if(isset($_POST['Submit'])) $url = "http://www.mysite.com/". $path . "/" . $file; { echo "<a href=\"$url\">$url</a><br />"; }} closedir($dir_handle); As always, many thanks in advance for any help on this. hello, i am having an issue with tables using incorrect data. i have 2 columns, first is employee name, second is location if the employee doesnt have a location for the current day, it is telling me he is at the same location as the guy in the row above him. i need this to be blank. is this possible? Hi all, I want to make a script that identifies if an image JPG file exists. Would somthing like this work? <?php $file = "images/image.jpg"; if ($file > 0) { echo "file exists"; } else { echo "no file"; } ?> Gud pm!! So i made this script to check if a username and password exist but it kinda fails me. It gives me a database connection error from my confirm_query() which means it returned false? so here's my code: Code: [Select] function check_if_exist($username, $password) { global $connection; $query = "SELECT username, hashed_password"; $query .= "FROM users "; $query .= "WHERE username = '$username' "; $query .= "AND hashed_password = '$password' "; $query .= " LIMIT 1"; $result_set = mysql_query($query, $connection); confirm_query($result_set); if(mysql_num_rows($result_set) == 1) { return true; } else { return false; } } my confirm_query(): Code: [Select] function confirm_query($result) { if(!$result) { die("Database connection failure ". mysql_error()); } } I have a another script to check if the email exist and it works perfectly, i dunno why this won't work properly.. maybe another simple mistake.. Any ideas or Violent reaction? Thanks! Hi.. So what i want to do is basicly to check if id XX exist in my database. How can this be done? Im thinking of something like: if(xx exist){do this} else{do this} Iv'e tried google etc before i posted here, but couldent really find anything where i found a soutable answer.. Hope someone can help! (: Basically this gets a number from a table on my DB, and displays the content relevent to that number...the second part checks for that number and gets other information according to that number... what i want to do is make sure that the number from the first query exists in the table from the query, and if it doesn't print out and error saying "there is no information" or whatever.. anyone have an idea? hopefully this makes sense Code: [Select] <?php require_once('Connections/myConnect.php'); $detnum = $_GET['Details']; $detinfo = mysql_query("SELECT* FROM `Agency Stores - Table 1` WHERE F11=".$detnum); $det = mysql_fetch_array($detinfo); $salesnum = $det['F3']; $salesinfo = mysql_query("SELECT* FROM `By Agency Store _` WHERE store_store=".$salesnum); $sales = mysql_fetch_array($salesinfo); if(mysql_query("SELECT* FROM `By Agency Store _` WHERE store_store=".$salesnum)){ } ?> hi, i have a select which gets todays schedule for each user. sometimes that user doesnt have anything for todays date and it will display the info from the user above him. how can i make it so it stays blank if there is no record? hi, im getting the error Quote Fatal error: Call to undefined function notification() in C:\xampp\htdocs\xampp\index.php on line 21 after including the functions.php file i wrote. It does include it but the data isnt being recognised from it. If i copy/paste the notification() function into index.php it works. Can someone tell me why so i can fix it? I need to insert data into a table if it doesn't exist or update if it does. Can someone give me an example of this code. im using mySQL 5.1.42 im using phpMyAdmin 3.1.o I have a field in a table named flights I hope to find a 1 line statement to bypass inserting a new row if $flight_no is already in the field flight_no btw flight_no is the primary key and won't allow a duplicate anyway but I want to avoid the error message this is what I tried but doesn't work if(SELECT * FROM flights WHERE flight_no !LIKE %$flight_no%) { This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=357281.0 I have an array like so Array (14) ( | ['0'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['1'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['2'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['3'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['4'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['5'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['6'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['7'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['8'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['9'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['10'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['11'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['12'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) | ['13'] => Array (5) | ( | | ['name'] = String(7) "Pikemen" | | ['hp'] = Integer(1) 0 | | ['atk'] = Integer(1) 5 | | ['def'] = Integer(1) 5 | | ['rng'] = Integer(2) 15 | ) ) what i want to do is add the details to a new multi dimensional array but only add one each like so array( ['units'] = array( ['name'] => 'Pikemen', ['lost'] => 14 ) ) basically where the HP is 0 in the first array i need to add them to the second if the name is unique. I have tried array unique but it didnt seem to work. Any ideas? All i get it a loop of each Pikemen Is it possible to check if multiple rows exist at the same time. For example, if a row with the id "1" and another row with id "2" exists, and return something like true then false if only the first exists?
I have a file that provides tens of thousands to check and it takes forever. I know this sounds bad off the start, but it's not something that is run normally. Only to update my database with new additions.
Is there any good way to check a lot at once? I know you can insert many at a time and save a lot of time.
Here is my code so far (I say it's PDO but it pretty much isn't. What is the object here? The database connection? LOL!); $sql = " SELECT SUM(IF(`sent` != 'N' , 1 , 0 )) as 'Emails Sent', SUM(IF(`completed` NOT IN('N','paper') , 1 , 0 )) as 'Completed Electronically', SUM(IF(`completed` = 'paper' , 1 , 0 )) as 'Completed Manually', SUM(IF(`completed` != 'N' , 1 , 0 )) as 'Total Number Completed', SUM(IF(`remindercount` = '1' , 1 , 0 )) as 'Reminder Sent Once', SUM(IF(`remindercount` = '2' , 1 , 0 )) as 'Reminder Sent Twice', SUM(IF(`remindercount` = '3' , 1 , 0 )) as 'Reminder Sent Thrice' FROM `tokens_$survey_id` "; $statement = $dbh->prepare($sql); $statement->execute(); $result = $statement->fetch(PDO::FETCH_OBJ); foreach($result as $key => $value) { echo "<tr> <td>$key</td> <td>$value</td> </tr>"; }This is all well and good if the tokens_$survey_id table is actually there. Sometimes, for a genuine reason, there won't be a tokens table for that particular survey. How do I account for this? At the moment I get an error.. Warning: Invalid argument supplied for foreach() in /var/www/html/index.php on line 149I tried this but I am not satisfied this is correct; if(!$result) { die(); }I don't want the code to die! If I take out the die() statement then this if is ignored for some reason I don't understand. |