PHP - Check If String Contains A Number

I was wondering if anyone knows a good way to check for an even number of each character in a string.  For example if the string is "abbacc" then it will return true as there are two of each character.  However if the string is "ababc" it will return false as there is only 1 c.  Thanks for any help

Hey

I have a string that looks like the following:
Quote

top-php-tutorials-2.html


I have a script that cycles through each page. The 2 in the quote above is the page number.

How can I extract the number between the - and the .html and replace it with another number?

I've tried
Code: [Select]
substr($engine->selectedcaturl, 0,-6).$v.".html"But then I realised this only works for numbers that are 1 digit long

Any input would be appreciated

Hello,
I'm currently creating a little script, and want to assign a random number to a row in the MySQL table as soon as it will be inserted. But that number may not have been used before. How will I do this?

I tried if else thingies, but then the code would be very long (just in case it randomly picks 10 times after each other a number that exists).

$randomnumber = rand(10000000, 99999999);
if(mysql_num_rows(mysql_query("SELECT * FROM table WHERE randomnumber='".$randomnumber."')) == 1) {
  $randomnumber = rand(10000000, 99999999);
  if(mysql_num_rows(mysql_query("SELECT * FROM table WHERE randomnumber='".$randomnumber."')) == 1) {
    $randomnumber = rand(10000000, 99999999);
  }else {
   // Insert into database
  }
}else {

// Insert into database
}


I hope you understand my problem.

Regards,

Hi Guys just need some advice really

I would like to know if there is a way I can check if a number is in a times table

for example

if(3 is in 4 times table){ do bla bla }
the result for above will be false as 4 times table does not contain 3

if(12 is in 4 times table){ do bla bla }
the above would be true

Thanks guys

Hi,

I'm totally new to PHP and I'm afraid I don't understand a lot yet. However, I need to make this: when you fill in a number in a form, it should be displayed whether the number is odd or even. I tried the following code, which is obviously not working and I have no idea on how to fix this.

Code: [Select]
<?php 
$var = $_POST['var'];

for ($i = 0; $i < $var; $i++) {
  if ($i % 2 == 0) {
    print("even");
  } else {
   print("odd");
  }
}
?>