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PHP - Storing An The Image Url In A Mysql Table
Hey, i need help storing an image in my database via the URL(image location) at the moment my php code is storing the image in a folder on the directory called upload. here is the code:
<?php // Where the file is going to be placed $target_path = "upload /"; /* Add the original filename to our target path. Result is "uploads/filename.extension" */ $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); $target_path = "upload/"; $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) { echo "The file ". basename $_FILES['uploadedfile']['name']). " has been uploaded"; } else{ echo "There was an error uploading the file, please try again!"; } ?> Click <a href="products.php">HERE</a> to go back to form if someone could help me i'd be very grateful Similar TutorialsHi, I've read a lot of places that it's not recommended to store binary files in my db. So instead I'm supposed to upload the image to a directory, and store the link to that directory in database. First, how would I make a form that uploads the picture to the directory (And what kinda directories are we talking?). Secondly, how would I retrieve that link? And I guess I should rename the picture.. I'd appreciate any help, or a good tutorial (Haven't found any myself). Hey, I am a bit of a noob at php/mysql and trying to be clever(emphasis on trying). I want to pull some php/html code from a database in mysql, whilst it does display the html, the php does not. Can this even be done? Is it going to cause me issues later on? Code: [Select] [php] <?php $query = "SELECT * FROM pages"; $result = mysql_query($query) or die(mysql_error()); while ($row = mysql_fetch_array($result)){ $body = $row["body"]; echo $body; }?> [/php] Any help would really be appreciated. Ell I have a database with all users.. Within that database all users have an id. How would I make it so users can "friend" other users? Would I need to make a new table for that? Im sorry for the dumb question.. I havent dealt with php or mysql in about two years because I was busy getting engaged and all.. But now that I have time again I think im gonna take up one of my old projects. Granted I probably could have answered this question myself back then but now im finding some trouble taking up programming again. :\ I need to find a way to store a password for connection to a remote database. I'm writing a program that will create a database on whatever server the user is using. Obviously, they will have to provide their username and password in order to create the database and have access to it. I need my program to get the information once (when they use the setup utility), then be able to store it so they can automatically connect to the database whenever my program is used. I plan using a php file for storage and include() to gain access to the info. I just don't have an idea for getting the information into the php file in the first place. Thanks for any ideas! what's wrong with this ? i can't upload I've got an array like this: $firstquarter = array('January', 'February', 'March'); Then I'm adding it to a MySQL DB as follows: $insert = "INSERT INTO sometable (months) VALUES ('$firstquarter') "; $insertresult = mysql_query($insert) or die ('Error in Insert query: ' . mysql_error()); When I use PHPMyAdmin I see a this value stored in the DB: 'Array' Can I retrieve the values, by index, from this database field?? Hi I have an array of checkboxes whose values if checked can be updated in mysql. The code I have below accomplishes that just fine. On my form I have: print "<form method='post' action='update.php'>\n"; /////// mysQL query here $myID = $itemRow['myID']; $chk = $itemRow['item_shipped'] == 1 ? 'checked' : ''; echo "<input type=checkbox name=cbox[] value='{$itemRow['myID']}' $chk>"; echo"</form>"; The above code displays various items with a checkbox next to them. So if that checkbox is checked the code below stores that in mysql. On my update.php page I have: if(sizeof($_POST['cbox'])) { //means if at least one check box is selected foreach($_POST['cbox'] AS $id) { mysql_query("UPDATE om SET item_shipped ='1' WHERE myID=$id"); } //end foreach } //end IF The problem is though i can check a checkbox and store that value '1' in mysql, I have no way of unchecking an already checked checkbox and storing the '0' in mysql. Can anyone help? Thanks in advance I am currently looking to insert images into a database and then display them in php. I am thinking of storing the images as a VARCHAR data type but what would be a more suitable type? I need some help with this. A user fills out a form, one of the fields is a zip code field. I need to retrieve that value from MySQL store as a session var and set that value as a variable to use with a weather display API. The ID is being stored from the form page. Here is what I have so far, after the values are submitted into the DB. <?php session_start(); $con = mysql_connect("localhost","peter","abc123"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("my_db", $con); $result = mysql_query("SELECT * FROM Profile WHERE id='{$_SESSION['id']}"); while ($row = mysql_fetch_assoc($result)) { $_SESSION['id'] = $row['id']; $_SESSION['zip'] = $row['zip']; } mysql_close($con); ?> and then for the weather API, I need to set the stored variable to something $zip = 'stored zip code value'; I have insert image using this following code but i want to know where it is storing i want file path of the imahe what i have inserted Code: [Select] <html> <head><title>File Insert</title></head> <body> <h3>Please Choose a File and click Submit</h3> <form enctype="multipart/form-data" action= "<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <input type="hidden" name="MAX_FILE_SIZE" value="10000000" /> <input name="userfile" type="file" /> <input type="submit" value="Submit" /> </form> </body> <?php // check if a file was submitted if(!isset($_FILES['userfile'])) { echo '<p>Please select a file</p>'; } else { try { upload(); //this will upload your image echo '<p>Thank you for submitting</p>'; //Message after uploading image } catch(Exception $e) { echo $e->getMessage(); echo 'Sorry, could not upload file'; } } // the upload function function upload(){ include "file_constants.php"; $maxsize = $_POST['MAX_FILE_SIZE']; if(is_uploaded_file($_FILES['userfile']['tmp_name'])) { // check the file is less than the maximum file size if( $_FILES['userfile']['size'] < $maxsize) { // prepare the image for insertion $imgData =addslashes (file_get_contents($_FILES['userfile']['tmp_name'])); // put the image in the db... // database connection mysql_connect($host, $user, $pass) OR DIE (mysql_error()); // select the db mysql_select_db ($db) OR DIE ("Unable to select db".mysql_error()); // our sql query $sql = "INSERT INTO test_image (image, name) VALUES ('{$imgData}', '{$_FILES['userfile']['name']}');"; // insert the image mysql_query($sql) or die("Error in Query: " . mysql_error()); } } else { // if the file is not less than the maximum allowed, print an error echo '<div>File exceeds the Maximum File limit</div> <div>Maximum File limit is '.$maxsize.'</div> <div>File '.$_FILES['userfile']['name'].' is '.$_FILES['userfile']['size']. ' bytes</div> <hr />'; } } ?> </html> Here is my code... Code: [Select] <?php mysql_connect("localhost", "user", "pass")or die("cannot connect"); mysql_select_db("database")or die("cannot select DB"); $myemail = mysql_real_escape_string($_POST['myemail']); $mypassword = mysql_real_escape_string($_POST['mypassword']); $mypassword = md5($mypassword); $myemail = stripslashes($myemail); $mypassword = stripslashes($mypassword); $sql="SELECT * FROM users WHERE email='$myemail' and password='$mypassword'"; $result=mysql_query($sql); $count=mysql_num_rows($result); if($count==1){ session_start(); $_SESSION["myemail"]= "$myemail"; header("location:home.php"); } else { header("location:fail.php"); } ?> What can I do to this code so that it will also store first name from the database inside a session? I'm developing an arabic site...but also want to view it in English...I'm thinking of using windows translating service (depending on good it is). Now I was thinking of having columns in my table like so...english title, arabic title, english description, arabic description As it can charge for words to be translated...when translating arabic to english I can store the results in the column so they would no longer have to be translated again My question is...is it good practice to have separate columns for different languages?...thank you...any input would be great Hi all, I need to create a table which holds a list of values, for EG 1 PHP 2 MySQL 3 HTML 4 JS The reason im doing this is so when a user visits X page on my site, they are presented with a list of possible options which they can tick, for instance if you were asked what languages your fluent with you would tick HTML and JS (or w/e applies to you) What would be the best way of constructing the table? Thanks Not really sure how to get the images I have stored in MySQL into a html form. I can call-up the text fields from the database but it cannot seem to find the index for the images. Here is my code:- <?php session_start(); mysql_connect("localhost","root","abc") or die ("Error! Cannot connect to database"); mysql_select_db("theimageworks") or die ("Cannot find database"); $query = "SELECT * FROM jobs"; $result = mysql_query($query) or die (mysql_error()); ?> <?php //display data in html table echo "<table>"; echo "<tr><td>Username</td><td align='center'>Message</td><td>Product Image</td></tr>"; while($row = mysql_fetch_array($result)) { echo "</td><td>"; echo $row['username']; echo "</td><td>"; echo $row['message']; echo "</td></tr>"; echo $row['image']; } echo "</table>"; ?> The error message I get is "Notice: Undefined index: image in....." Thanks in advance! Hello everyone,
I have a card database and everything works perfectly besides one thing..
I can't store
'in my database via my form, i however do can store them into the database via PHPMyAdmin. I dont know what i've been doing wrong and it really bothers me. If any of you guys could help me out. Here's all the code you would need to find the issue. This is the form file
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Edit Page</title>
</head>
<body>
<h1 align="center"> Add Cards</h1>
<form action="insert.php" method="POST">
<input type="text" name="name" placeholder="Name" />
<input type="text" name="color" placeholder="Color" />
<input type="text" name="type" placeholder="Type" />
<input type="text" name="subtype" placeholder="Sub Type" />
<input type="text" name="power" placeholder="Power" />
<input type="text" name="toughness" placeholder="Toughness" />
<br>
<input type="text" name="manacost" placeholder="Converted Mana Cost" />
<input type="text" name="rarity" placeholder="Rarity" />
<input type="text" name="expansion" placeholder="Expansion" />
<input type="text" name="foil" placeholder="Foil" />
<input type="text" name="stock" placeholder="Stock" />
<input type="submit" value="Save" />
</form>
</body>
</html>
This inserts it into my database.
<?php
($GLOBALS["___mysqli_ston"] = mysqli_connect("", "", "", , ))or die("cannot connect");
((bool)mysqli_query($GLOBALS["___mysqli_ston"], "USE e_industries"))or die("cannot select DB");
$name = $_POST['name'];
$color = $_POST['color'];
$type = $_POST['type'];
$subtype = $_POST['subtype'];
$power = $_POST['power'];
$toughness = $_POST['toughness'];
$manacost = $_POST['manacost'];
$rarity = $_POST['rarity'];
$expansion = $_POST['expansion'];
$foil = $_POST['foil'];
$stock = $_POST['stock'];
$sql="INSERT INTO Osiris (Name, Color, Type, Subtype, Power, Toughness, Manacost, Rarity, Expansion, Foil, Stock)
VALUES ('$name', '$color', '$type', '$subtype', '$power', '$toughness', '$manacost', '$rarity', '$expansion', '$foil', '$stock')";
$result=mysqli_query($GLOBALS["___mysqli_ston"], $sql);
if($result){
echo "Successful";
echo "<BR>";
echo "<a href='add.html'>Back to main page</a>";
}
else {
echo "ERROR";
}
?>
If anyone could help me out that would be great!
Edited by OsirisElKeleni, 05 October 2014 - 12:29 PM. Hello! I am designing a user registration form which has some radio buttons for people to select. I am confused as to how I should store the value selected by the user into the database. Here is my code, just in case. <li id="li_2" > <label class="description" for="element_2">I am a </label> <span> <input id="element_2_1" name="element_2" class="element radio" type="radio" value="1" /> <label class="choice" for="element_2_1">Student</label> <input id="element_2_2" name="element_2" class="element radio" type="radio" value="2" /> <label class="choice" for="element_2_2">Staff</label> <input id="element_2_3" name="element_2" class="element radio" type="radio" value="3" /> <label class="choice" for="element_2_3">Member</label> <input id="element_2_4" name="element_2" class="element radio" type="radio" value="4" /> <label class="choice" for="element_2_4">Other</label> </span> </li> I am working on a kind of CMS for my own website which no one else will be using but me as a way of improving my php skills, and am having problems with retrieving data from the database that holds both text and php code. I have searched the web and found that i should be using eval() for the code to be executed before it is send to the browser but cannot get it to work and can't find my mistake(s). the php code will always be the same, and is supposed to retrieve the id number of a page to use in a link (and works fine when tested by loading the code directly without retrieving it from the database) this is an example of data stored in the database Code: [Select] The <a href="page_builder.php?id=<?php echo $page->id('mines_DwarvenMines') ?>">Dwarven Mines</a> have a great selection of Ores,... Of course when I leave it like this, hovering over the link in my page will show exactly that and lead to nowhere Code: [Select] localhost/page_builder.php?id=<?php echo $page->id('mines_DwarvenMines') ?> Most of these links appear in tips given at the end of the page and are processed as followed Code: [Select] $questtips = $quest->getQuestTips(); $tips = ""; if ($questtips == "none") { $tips = "/"; } else { foreach($questtips as $tip) { $tips .= "<li>"; $tips .= $tip->getTip(); $tips .= "</li>"; } } and finally put on screen by the presentation layer as followed Code: [Select] <h2>Tips & Extra Info</h2> <div class="tipsList"> <ul> <?php echo $tips ?> </ul> </div> I have tried all sorts to get the code to be executed when retrieved from the database before being send to the browser so that this particular link would say "localhost/page_builder.php?id=57" but I cannot get it to work, though I suspect it is fairly easy. I suspect I would have to store the data in a different format in the database? And how exactly do I use the eval() function in my case? Could someone please adjust my code so that it does work? Thanks Hi,
I would like to store sql query strings in a database. A query might look this like:
SELECT * from ListTable where id = '$id'
The idea would be to retrieve the string and run it as a SQL string. $id would be defined in the procedure so the idea is that when I send the SQL String through, $id would be replaced with its value and everything would work.
Under normal circumstances, the code would look like this:
$id = "somevalue"; $lcSQL = "SELECT * from ListTable where id = '$id'";I would pass the SQL select off to mySQL and all is right with the world. I just want to store the string in a database, retreieve it and use it. Thanks for your help in advance... i have a dictionary - THIS IS obviously a python dictionary an this has approx 8 000 lines with records [/CODE] $ python printer.py {'url': 'http://www.site1_com' 'cname': 'butcher', 'name': 'cheng', 'email': 'mail1@hotmail.com'} {'url': 'http://www.site2_com' 'cname': 'dilbert', 'name': 'James', 'email': 'mail2@hotmail.com'} [code=auto:0]i have a mysql-db up and runing in my opensuse there i have created a db with the fields url cname name i use the import MySQLdb i studied this documentation he http://stackoverflow...abase-in-python but i think this goes a bit over my head. - well how can i get the data ( in other words the dictionary) into the database? love to hear from you greetings |
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