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PHP - Inserting Data From A Dropbox Intoa Textbox
Hi have a dropbox in php and it works fine btu i want the data selected to go into a textbox:
Current Drop Box Code: [Select] <?php $sql = mysql_query("SELECT * FROM favourite_destinations WHERE User_ID =$userid"); while($row = mysql_fetch_array($sql)){ $uid = $row["User_ID"]; $username = $row["Name"]; echo '<option value="'.$uid.'">'.$username.'</option>' ; } ?> name="Customer_Destination" is the name of the textbox I know in javascript u can have a Code: [Select] onchange="document.theform.Customer_Destination.value=this.value"but the drop box stops working when i put this into the select tag name outside of the Php any help how i coudl achive this ? Similar TutorialsHey I created a drop box and got a form for that. Now when I click on submit I want the data to be compaired with the data inside the mysql. For example: Subject name = Subject id the drop down list contains subject names. And this should be compaired with the subject id and store the id into a new table called test. <Html> <?php session_start(); include '../Database/connection.php'; ?> <body> <form action="try1.php" method="post"> <?PHP include '../Database/subject_sql.php'; $result=mysql_query($query) or die ("Unable to Make the Query:" . mysql_error() ); echo "<select name=myselect>"; while($row=mysql_fetch_array($result)){ echo "<OPTION VALUE=".$row['Sub_ID'].">".$row['Sub_Name']."</OPTION>"; } echo "</select>"; ?> <input type="submit" value="submit"/> </form> </body> </html> This UPDATE script works:
$query = $pdo->prepare("UPDATE posts SET headline = ? WHERE id = ?");
$query->bindValue("1", $_POST['headline']);
$query->bindValue("2", "2");
$query->execute();
Though, this INSERT script does not work:
$query = $pdo->prepare("INSERT INTO posts (headline, post) VALUES (?, ?)");
$query->bindValue("1", $_POST['headline']);
$query->bindValue("2", $_POST['post']);
$query->execute();
Nothing gets added, when executing this script.
The connection:
<?php
$dsn = "mysql:dbname=phpblog;host=localhost";
$user = "root";
$password = "";
try{
$pdo = new PDO($dsn, $user, $password);
}catch(PDOException $e){
echo "Connection failed: " . $e->getMessage();
}
?>
Any suggestions why the INSERT script is not working?
Edited by glassfish, 25 November 2014 - 09:26 AM. Can someone please help me figure out how to insert "image" from table users, that contains the .jpg data associated with "screen_name", into table friends "friendimg" Here are the tables: friends: id, member, friendwith, friendimg users: id, screen_name, image $_GET["id"] only contains "screen_name" and"image" is not included add.php Code: [Select] <?php if(isset($_GET["id"])) { echo "<br/><a href=\"member?add=".$_GET["id"]."\">Add ".$_GET["id"]." to your list of friends</a>"; } ?>member.php Code: [Select] <?php if(isset($_GET["add"])) { $username = $_SESSION["screen_name"]; $friend = $_GET["add"]; $query = "SELECT * FROM friends WHERE member='$username' AND friendwith='$friend'"; $result = mysql_query($query); $exist = mysql_num_rows($result); if($exist=='0') { $query = "INSERT INTO friends(member,friendwith) VALUES('$username','$friend')"; mysql_query($query); echo "<br/>You are now friends with $friend"; } else { echo "<br/>$friend is already in your list of friends!"; } } ?> I am at a loss why my query is not inserting values into db. Even if I do echo $query or var_dump($query) there is nothing printed at all. All values are being passed successfully just not being inserted. I am getting 'Could not connect' but I do not know why. All connections are established and as a test I took this code and ran it on it's own with dummy data and it inserted the data fine. I can only think it has something to do with the $response_array. Where am I going wrong. and would appreciate any help. Thanks Code: [Select] <?php require_once('Connections/sample.php'); ?> <?php session_start(); $new = 1; $activity = 'General Contact Enquiry'; $mobile = 'Submitted from mobile'; $name = mysql_real_escape_string($_POST['GC_name']); $department = mysql_real_escape_string($_POST['GC_department']); $message = mysql_real_escape_string($_POST['GC_message']); $email = mysql_real_escape_string($_POST['GC_email']); $company = mysql_real_escape_string($_POST['GC_company']); $position = mysql_real_escape_string($_POST['GC_position']); //response array with status code and message $response_array = array(); //validate the post form //check the name field if(empty($name)){ //set the response $response_array['status'] = 'error'; $response_array['message'] = 'Name cannot be blank'; //check the name field } elseif(empty($company)) { //set the response $response_array['status'] = 'error'; $response_array['message'] = 'You must enter a company name'; //check the position field }elseif(empty($position)) { //set the response $response_array['status'] = 'error'; $response_array['message'] = 'You must enter a position'; //check the email field } elseif(empty($email)) { //set the response $response_array['status'] = 'error'; $response_array['message'] = 'You must enter a valid email address'; //check the dept field }elseif($department=="Choose Department") { //set the response $response_array['status'] = 'error'; $response_array['message'] = 'You must select a department'; //check the message field }elseif(empty($message)) { //set the response $response_array['status'] = 'error'; $response_array['message'] = 'You must enter a message'; //check the dept field } else { //set the response $response_array['status'] = 'success'; $response_array['message'] = 'Your enquiry has been sent succesfully'; $flag=1; } //send the response back echo json_encode($response_array); if($flag == 1) { mysql_select_db($database_sample, $sample); $query = 'INSERT INTO feedback (company, department, name, email, position, feedback, date, new) VALUES (\''.$company.'\', \''.$department.'\', \''.$name.'\', \''.$email.'\', \''.$position.'\', \''.$message.'\', NOW() , \''.$new.'\')'; mysql_query($query) or die("Could not connect"); } ?> Stuck again on simple code. I am trying to insert some fields extracted from one table into another. I'm using code that worked elsewhere. The SQL statement flies, the script runs, the input array is printed back I get an echo back from the end of the script but nothing is added to the table. Even aded an echo print_r in the conditional and I know the data is getting to the execute command. The script follows with a sample of the input array. I have attached am image of the table I am trying to insert the data into. --Kenoli
The script:
<?php
require '__classes/DB.php';
$sql = "SELECT name, table_id, image_name, description, medium FROM tbl_person_data ";
$stmt = $pdo->query($sql);
$array1 = $stmt->fetchall(PDO::FETCH_ASSOC);
$stmt = $pdo->prepare("INSERT INTO Images (name, person_id, filename, description, medium) VALUES (?,?,?,?,?)");
//$pdo->beginTransaction();
foreach ($array1 as $row)
{
$stmt->execute($row);
}
echo "<pre>";
print_r ($row);
echo "</pre>";
echo '<h4>Got to end of file</h4>';
?>
$array1: The input array
[0] => Array
(
[name] => Carol Lettko
[table_id] => 21
[image_name] => Carol_Lettko-DSC_3022.jpg
[description] => Baby Herons/Brickyard
[medium] => photo
)
[1] => Array
(
[name] =>
[table_id] => 22
[image_name] => Carol_Lettko-DSC_0164.JPG
[description] => Heron/Brickyard
[medium] => photo
)
[2] => Array
(
[name] =>
[table_id] => 23
[image_name] => Carol_Lettko-IMG_5723.jpg
[description] => Kayaker/Brickyard
[medium] => photo
)
hi guys Ive written this php to take in two variables from the http POST, the idea is that I can multiple devices submit temperature readings to the php script, the script then append the unix time stamp and then the the 3 variables - device id, temp and unix time are then stored in a mysql DB. I can get the variables to present on a php page for debugging but I cant get the variables to be stored in the mysql DB. See the code: Code: [Select] <?php $unixtime = time(); // get device variables $device_id=$_GET['device']; $device_temp=$_GET['temp']; /* //for testing purposes echo "unixtime: " . $unixtime . "<br />"; echo "device id: " . $device_id . "<br />"; echo "device_temp: " . $device_temp . "<br />"; */ // Make a MySQL Connection mysql_connect("localhost", "username", "password") or die(mysql_error()); mysql_select_db("test") or die(mysql_error()); //mysql query $query = "INSERT INTO temperature VALUES ('',$device_id,$temp,$unixtime)"; // Insert a row of information into the relevant device table mysql_query($query); or die(mysql_error()); mysql_close(); echo "Data Inserted!"; ?> I cant see where Im going wrong to correct this, but as nothing is displayed on the page i believe I am not forming the query correctly? - any ideas would be much appreciated. Thank you Mathew Hello All, First, I'm new to php and I have spent a lot of time searching forums and google for the answer to my question with no luck, so if it's a topic already covered, PLEASE reply with a link or point me in the right direction. OK, I have a form that let's users upload multiple images. The upload portion works fine. What I can't figure out how to do is put the image name of each file that gets uploaded all into the same table record. I also need each file name to be put into it's own column in the table. For example, file1, file2 and file3 will get dumped into the same record and into it's respective column (uploaded_image1, uploaded_image2, uploaded_image3). I've included the working upload code and the code that inserts some of the information into the database (just not the image names). Code: [Select] echo "<textarea name=challenge rows=15 cols=60> </textarea><br/><br/>" echo "<textarea name=insight rows=15 cols=60> </textarea><br/><br/>" for($i=1; $i<=$max_no_img; $i++){ echo "Image $i <input type=file name='image[]' ><br/>"; } echo "<input type=submit value=Submit>"; Code: [Select] // Connect to DB $host = 'xxx'; $user = 'xxx'; $pass = 'xxx'; $db = 'xxx'; mysql_connect($host,$user,$pass) or die(mysql_error()); mysql_select_db($db) or die(mysql_error()); // Post Variables $challenge = $_POST['challenge']; $insight = $_POST['insight']; $filename=serialize($_POST['filename']); // Upload Images while(list($key,$value) = each($_FILES[image][name])) { if(!empty($value)) { $filename = $value; $add = "upimage/$filename"; copy($_FILES[image][tmp_name][$key], $add); chmod("$add",0777); } } // Insert into database $query = "INSERT INTO table ( challenge, insight, uploaded_image1, uploaded_image2, uploaded_image3,)". "values ( '$challenge', '$insight', '$filename' '$filename2' '$filename3')"; mysql_query($query) or die('Error, query failed : ' . mysql_error()); I know just enough about php that the reason the above wont work, is because $filename2 and $filename3 haven't been given a value. Unfortunately, I have no idea how to separate that information in the array. If anyone can point me in the right direction I'd be forever grateful! Thanks, Gary I am trying to insert product descriptions into a mysql database, however they are failing because of apostrophes in the text. How do I fix this? Everything is working fine except $productdescription $ProductDescription contains, "Record In Stereo Sound, Then Play Back Your Videos Instantly On You Computer. The Sx130 Is Is All About Creativity, With Fun New Scene Modes Like Miniature Effect For Movies, And Fisheye Effect For Artistically Distorted Stills. While You're Having Fun Creating, The Camera's Smart Flash Exposure And Advanced Smart Auto Systems Are Ensuring That Every Image Is The Best It Can Be. Add The Digic 4 Image Processor, 12.1 Megapixels And Canon's Optical Image Stabilizer, And You've Got The Ideal Camera For Making The Good Times Last." SQL Error on insert, "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 're Having Fun Creating, The Camera's Smart Flash Exposure And Advanced Smart Aut' at line 1 " Code: [Select] mysql_select_db("testdb") or die(mysql_error()); mysql_query ("INSERT INTO product (merchantname, producttitle, productdescription, gtin, availability, price) VALUES ('$merchantname[1]','$producttitle[1]','$productdescription[1]','$gtin[1]',''$availability[1]','$price[1]')"); i want insert data from text box in html form.there are many text boxes gave name using 2 loops..please tell how can insert data to table?please reply i want to insert only whats checked to db:) but everything get posted for now i came upwith a for loop but thats for inserting all data not only whats checked any one know a good way to do this? Hello, I have three scripts below that I was wondering if someone can look at as a second opinion. What they all have in common is they are supposed to append data to some tables in my database. They match the code on all my other scripts but for some reason these particular scripts will not append the data to the files. This first one... is supposed to insert the name of the doctor this person uses, and then gets the last ID created and inserts it into another table...no matter what I try, it will not do it. Code: [Select] <?php session_start(); $userid=$_SESSION['userID']; $firstName=$_SESSION['fname']; $lastName=$_SESSION['lname']; $camperID=$_POST['camperID']; $physicianFName=$_POST['physicianFName']; $physicianLName=$_POST['physicianLName']; $physicianSuffix=$_POST['physicianSuffix']; $practiceName=$_POST['practiceName']; $physicianAddress1=$_POST['physicianAddress1']; $physicianAddress2=$_POST['physicianAddress2']; $physicianAddress3=$_POST['physicianAddress3']; $physicianCity=$_POST['physicianCity']; $physicianState=$_POST['physicianState']; $physicianZip=$_POST['physicianZip']; $physicianOfficeP=$_POST['physicianOfficeP']; $physicianOfficeF=$_POST['physicianOfficeF']; $physicianSpecialty=$_POST['physicianSpecialty']; echo $camperID. ' ' .$physicianFName. ' ' .$physicianLName; //htc information and physician $htcName=$_POST['htcInfo']; $htcPhysician=$_POST['htcPhysician']; $con=mysql_connect("xxx.xxx.xxx.xx", "xxx", "xxxx") or die ("cannot connect"); mysql_select_db("testcamp") or die ("cannot select database"); $sql="INSERT INTO Physicians(physicianFName, physicianLName, physicianSuffix, practiceName, physicianAddress1, physicianAddress2, physicianAddress3, physicianCity, physicianState, physicianZip, physicianOfficeP, physicianOfficeF, physicianSpecialty) VALUES ('$physicianFName', '$physicianLName', '$physicianSuffix', '$physicianAddress1', '$physicianAddress2', '$physicianAddress3', '$physicianCity', '$physicianState', '$physicianZip', '$physicianOfficeP', '$physicianOfficeF', '$physicianSpecialty')"; $result=mysql_query($sql,$con); $physicianID=mysql_insert_id(); $sql2="INSERT INTO CamperPhysicianInfo(physicianID, camperID) VALUES ('$physicianID', '$camperID')"; $result2=mysql_query($sql2,$con); $sql3="INSERT INTO CamperHTCInfo(camperID, htcID) VALUES ('$camperID', '$htcName')"; $result3=mysql_query($sql3,$con); $sql4="INSERT INTO camperHTCPhysicianInfo(camperID, htcPhysicianID) VALUES ('$camperID', '$htcPhysician')"; $result4=mysql_query($sql4,$con); ?> This next one...is supposed to enter data into the CamperRegistrations tables and also enter data into another table for a questionaire that was completed on the form previous to this page...same thing no matter what I try will not append data. Code: [Select] <?php $question12=$_POST['question12']; $question12a=$_POST['question12a']; session_start(); $userid=$_SESSION['userID']; $firstName=$_SESSION['fname']; $lastName=$_SESSION['lname']; $camperID=$_SESSION['camperID']; $con=mysql_connect("xxx.xxx.xxx.xx", "xxx", "xxx") or die ("cannot connect"); mysql_select_db("testcamp") or die ("cannot select database"); $sql="INSERT INTO Question12(camperID, question12Answer, teaching) VALUES ('$camperID', '$question12', '$question12a')"; $result=mysql_query($sql,$con); $date=date("Y-m-d"); $defaultStatus=1; $sql2="INSERT INTO CamperRegistrations(userID, camperID, registrationDate, registrationStatus) VALUES ('$userid', '$camperID', '$date', '$defaultStatus')"; $result2=mysql_query($sql2,$con); ?> and then on this same page with this script... is it possible to carry session information when using HTML links instead of a submit form? I need the userid to carry to the next page with a link, but it won't do that either... Any help would be appreciated and thanks in advance for looking. ~jcjst21 Hey all I really need help with a project I am doing. I need to create a website with a registration form that checks if the user exists if not to add the user details to my local database MySQL. My webpage looks like it should, it connects with the database but when I enter a new user it does nothing when it should save the new user to the database! I am guessing my problem is within the if...else section. Please help my code is: Code: [Select] <?php include('connect.php'); //connection details to database in a connect.php page $name = ""; $surname = ""; $username = ""; $password = ""; $confirmp = ""; $errorMessage = ""; $num_rows = 0; //if form was submitted if ($_SERVER['REQUEST_METHOD'] == 'POST'){ //get values from fields $submit = $_POST['Submit']; $title = $_POST['title']; $name = $_POST['name']; $surname = $_POST['surname']; $username = $_POST['username']; $password = $_POST['password']; $confirmp = $_POST['confirmp']; //getting string lengths $nameLength = strlen($name); $surnameLength = strlen($surname); $usernameLength = strlen($username); $passwordLength = strlen($password); $confirmpLength = strlen($confirmp); //testing if strings are between certain numbers if ($nameLength > 1 && $nameLength <= 20) { $errorMessage = ""; } else { $errorMessage = $errorMessage . "Name must be between 2 and 20 characters" . "<br>"; } if ($surnameLength >= 2 && $surnameLength <= 50) { $errorMessage = ""; } else { $errorMessage = $errorMessage . "Surname must be between 2 and 50 characters" . "<br>"; } if ($usernameLength = 6) { $errorMessage = ""; } else { $errorMessage = $errorMessage . "Username must be 6 characters long" . "<br>"; } if ($passwordLength = 6) { $errorMessage = ""; } else { $errorMessage = $errorMessage . "Password must be 6 characters long" . "<br>"; } if ($confirmpLength = 6) { $errorMessage = ""; } else { $errorMessage = $errorMessage . "Password must be 6 characters long" . "<br>"; } if ($errorMessage == "") { $query = "SELECT * FROM user WHERE username = '$username' AND password = '$password'"; $result = mysql_query($query); $num_rows = mysql_num_rows($result); //check to see if the $result is true if ($num_rows = 1){ $errorMessage = "Username already exists"; } else { if($password == $confirmp){ $query = "INSERT INTO user (title, name, surname, username, password) VALUES ('$title', '$name', '$surname', '$username', '$password')"; $result = mysql_query($query); session_start(); $_SESSION['login'] = "1"; header ("Location: login.php"); } else { $errorMessage = "Passwords do not match!"; } } } else { $errorMessage = "Error Registering"; } } else { $errorMessage = "Please enter your details"; } ?> <html> <head> <title>Mia's Beauty Products</title> </head> <body> <p><img src = "banner1.jpg" width = "975" height = "95" alt = "Mia's Beauty Product" /></p> <br> <p align= "center"><a href="register.php">Register</a> | <a href="login.php">Login</a> | <a href="insert.php">Insert</a> | <a href="list.php">List</a></p> <form method = "post" action = "register.php"> <table> <tr><td>Title:</td><td><select name = "title"> <option>Miss</option> <option>Mrs</option> <option>Mr</option> </select></td></tr> <tr><td>Name:</td><td><input name = "name" type = "text" value ="<?php print $name;?>"></td></tr> <tr><td>Surname:</td><td><input name = "surname" type = "text" value ="<?php print $surname;?>"></td></tr> <tr><td>Username:</td><td><input name = "username" type = "text" value ="<?php print $username;?>"></td></tr> <tr><td>Password:</td><td><input name = "password" type = "password" value ="<?php print $password;?>"></td></tr> <tr><td>Confirm Password:</td><td><input name = "confirmp" type = "password" value ="<?php print $confirmp;?>"></td></tr> <tr><td><input type = "submit" name = "Submit" value = "Submit"></td></tr> </table> </form> <p align= "center"><a href="code.txt">Code</a></p> <br> <?php print $errorMessage; ?> <p><img src = "banner2.jpg" width = "975" height = "95" alt = "Mia's Beauty Product" /></p> </body> </html> Thank you Amanda Hello, I'm having trouble inserting data into a MySQL table. The user has a form which is HEIGHT and WIDTH and NUMBER_OF_OBSERVATIONS. All these values are stored in the same table. NUMBER_OF_OBSERVATIONS does what it needs to and inserts its calculated results into the database, as does DATE_TIME. I've been trying for a couple of days to get this done, and I am having no luck in getting it sorted. Any help is greatly appreciated! Generator.php Code: [Select] $WIDTH = $_POST['WIDTH']; $HEIGHT = $_POST['HEIGHT']; $NUMBER_OF_OBSERVATIONS = $_POST['NUMBER_OF_OBSERVATIONS']; $db1 = new Number_Information(); $db1->openDB(); $OBSERVATION_ID = $db1->insert_Observation(); echo "<br /><br />Success. ID: <strong>$OBSERVATION_ID<strong>"; $db1->closeDB(); Number_Information.php Code: [Select] function insert_Observation() { //$Date_Now = datetime(); $sql = "INSERT INTO Observations (DATE_TIME, HEIGHT, WIDTH) VALUES (NOW(), '{$esc_HEIGHT}','{$esc_WIDTH}' )"; $result = mysql_query($sql, $this->conn); if (!$result) { die("SQL Insertion error: " . mysql_error()); } else { return mysql_insert_id($this->conn); } The table name is Observations Again - Any help is greatly appreciated! hello dear experts
good day dear friend - i need your help.
import urllib
import urlparse
import re
# import peewee
import json
from peewee import *
#from peewee import MySQLDatabase ('cpan', user='root',passwd='rimbaud')
db = MySQLDatabase('cpan', user='root',passwd='rimbaud')
class User(Model):
name = TextField()
cname = TextField()
email = TextField()
url = TextField()
class Meta:
database = db # this model uses the cpan database
User.create_table() #ensure table is created
url = "http://search.cpan.org/author/?W"
html = urllib.urlopen(url).read()
for lk, capname, name in re.findall('<a href="(/~.*?/)"><b>(.*?)</b></a><br/><small>(.*?)</small>', html):
alk = urlparse.urljoin(url, lk)
data = { 'url':alk, 'name':name, 'cname':capname }
phtml = urllib.urlopen(alk).read()
memail = re.search('<a href="mailto:(.*?)">', phtml)
if memail:
data['email'] = memail.group(1)
data = json.load('email') #your json data file here
for entry in data: #assuming your data is an array of JSON objects
user = User.create(name=entry["name"], cname=entry["cname"],
email=entry["email"], url=entry["url"])
user.save()
guess that there a data-file must exist: one that have been created by the script during the parsing... is this right?
)
martin@linux-70ce:~/perl> python cpan_100.py
Traceback (most recent call last):
File "cpan_100.py", line 47, in <module>
data = json.load('email') #your json data file here
File "/usr/lib/python2.7/json/__init__.py", line 286, in load
return loads(fp.read(),
AttributeError: 'str' object has no attribute 'read'
martin@linux-70ce:~/perl>
this script does not work
)
martin@linux-70ce:~/perl> python cpan_100.py
Traceback (most recent call last):
File "cpan_100.py", line 47, in <module>
data = json.load('email') #your json data file here
File "/usr/lib/python2.7/json/__init__.py", line 286, in load
return loads(fp.read(),
AttributeError: 'str' object has no attribute 'read'
martin@linux-70ce:~/perl>
well i suppose that in the first part of the script - the parser - part we parse data and - therefore we should create a file.I guess that this file is taken up within the second part of the script... load data . well why the script does not work!? I am setting up a PHP & MySql shopping cart. When a user adds products they are stored as sessions. The cart displays the products in an array: foreach($_SESSION as $product => $quantity) So the product is the product_id, and the quantity is the quantity of that product which has been added. When getting the information from the database to display it, it reads like this 1-----2 (product_id = 1, quantity = 2) 2-----1 (product_id = 2, quantity = 1) 3-----3 (product_id = 3, quantity = 3) 11---12 (product_id = 11, quantity = 12) 4-----1 (product_id = 4, quantity = 1) I'm basically trying to insert the product_id and quantity into a table called cart. I've been stuck for days and can still only manage to insert 1 row of values Searching around I saw that some people inserted arrays using implode or explode functions first, but I'm not sure how that would work in this case Any ideas? Hi,
I have a form like this
<tr>
<td><a href="edit_sales_invoice_details.php?id=<?php echo $row['dispatch_id']?>"><?php echo $row['oid'] ?></a></td>
<td><?php echo $row['dispatch_id'] ?></td>
<td><?php echo $row['cname'] ?></td>
<td><?php echo $row['iname'] ?></td>
<td><?php echo $row['quantity'] ?></td>
<td><?php echo $row['dispatch_quantity'] ?></td>
<td><select name="tax[<?php echo $row['dispatch_id']?>]" class="span9">
<option value="<?php echo $row['rate'] ?>"><?php echo $row['tname'].'-'.$row['rate'];?> %</option>
<option value="">Tax</option>
<?php
$s1 = mysql_query("select * from taxes");
while($s2 = mysql_fetch_array($s1))
{ ?>
<option value="<?php echo $s2['rate'] ?>"><?php echo $s2['name'].'-'.$s2['rate'] ?>%</option>
<?php } ?>
</select>
</td>
<td><input type="text" name="freight[<?php echo $row['dispatch_id']?>]" class="span6" /></td>
<td><input type="text" name="discount[<?php echo $row['dispatch_id']?>]" class="span6" /></td>
<input type="hidden" name="order_id[<?php echo $row['dispatch_id']?>]" value="<?php echo $row['oid']; ?>" />
<td><input type="checkbox" name="selector[]" value="<?php echo $row['dispatch_id']; ?>" /></td>
</tr>
<?php
}
?>
<tr><td colspan="11"><input type="submit" name="submit" value="SAVE INVOICE" class="btn btn-info" /></td></tr>
Here dispatch_id will be different but the order_id will be same. I want to generate a single invoice id for this and store it in this table
invoice.JPG 18.85KB
0 downloads
and by taking that invoice_id, i want to insert rest of the multiple line items to this table
invoice_line_items.JPG 29.7KB
0 downloads
I tried doing like this
I want to take data from one table and insert it into another in the same database, the problem is the two tables have different values so it wouldn't be as simple as using an INSERT INTO script. From table 1 I want to extract a row ID as well as a field called systems. I then want to insert that into the second table which is structured, Id (null) Name (games) Value (the data given from Systems in the other) ID2 (the ID from the other table) Category (news) Any ideas how I can go about this? Hi.. I need help in using for loop in saving data from while loop. Now, I encountered that the Demanded Qty was get only is the last Demanded Qty and save it to all Items. I want to happen is per Items will save the Demanded Qty. for example: Items Demanded Qty P28 ---1 P28 ---1 P28 ---1 P30 ---2 P30 ---2 P30 ---2 and so on.. here is my code: <?php error_reporting(0); date_default_timezone_set("Asia/Singapore"); //set the time zone $con = mysql_connect('localhost', 'root',''); if (!$con) { echo 'failed'; die(); } mysql_select_db("mes", $con); $sr_date =date('Y-m-d H:i:s'); $sql = "SELECT sr_number FROM stock_requisition ORDER BY sr_date DESC LIMIT 1"; $result = mysql_query($sql, $con); if (!$result) { echo 'failed'; die(); } $total = mysql_num_rows($result); if ($total <= 0) { $currentSRNum = 1; $currentYear = (int)(date('y')); $currentMonth = (int)(date('m')); $currentDay = (int)(date('d')); $currentSRYMD = substr($row['sr_number'], 0, 6); $currentYMD = date("ymd"); if ($currentYMD > $currentSRYMD) { $currentSRNum = 1; } else { $currentSRNum += 1; } } else { $row = mysql_fetch_assoc($result); $currentSRNum = (int)(substr($row['sr_number'],0,3)); $currentSRYear = (int)(substr($row['sr_number'],2,2)); $currentSRMonth = (int)(substr($row['sr_number'],0,2)); $currentSRNum = (int)(substr($row['sr_number'],6,4)); $currentYear = (int)(date('y')); $currentMonth = (int)(date('m')); $currentDay = (int)(date('d')); $currentSRYMD = substr($row['sr_number'], 0, 6); $currentYMD = date("ymd"); if ($currentYMD > $currentSRYMD) { $currentSRNum = 1; } else { $currentSRNum += 1; } } $yearMonth = date('ymd'); $currentSR = $currentYMD . sprintf("%04d", $currentSRNum); ?> <html> <title>Stock Requisition</title> <head> <link rel="stylesheet" type="text/css" href="kanban.css"> <script type="text/javascript"> function save_sr(){ var sr_date = document.getElementById("sr_date").value; var sr_number = document.getElementById("sr_number").value; var Items1 = document.getElementById("Items1").value; var SubItems = document.getElementById("SubItems").value; var ItemCode = document.getElementById("ItemCode").value; var DemandedQty = document.getElementById("DemandedQty").value; var UoM = document.getElementById("UoM").value; var Class = document.getElementById("Class").value; var Description = document.getElementById("Description").value; var BINLocation = document.getElementById("BINLocation").value; var RequestedBy = document.getElementById("RequestedBy").value; var ApprovedBy = document.getElementById("ApprovedBy").value; var ReceivedBy = document.getElementById("ReceivedBy").value; var IssuedBy = document.getElementById("IssuedBy").value; var Items = document.getElementById("Items").value; document.stock_requisition.action="StockRequisitionSave1.php?sr_date="+sr_date+"&sr_number="+sr_number+"&Items1="+Items1+ "&SubItems="+SubItems+"&ItemCode="+ItemCode+"&DemandedQty="+DemandedQty+"&UoM="+UoM+"&Class="+Class+"&Description="+ Description+"&BINLocation="+BINLocation+"&RequestedBy="+RequestedBy+"&ApprovedBy="+ApprovedBy+"&ReceivedBy="+ReceivedBy+ "&IssuedBy="+IssuedBy+"&Items="+Items; document.stock_requisition.submit(); alert("Stock Requisition data save."); window.location = "StockRequisition1.php"; } function disp(){ document.stock_requisition.action="StockRequisitionDisplay.php"; document.stock_requisition.submit(); } </script> </head> <body> <form name="stock_requisition" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <div id="SR_date"> <label>Date :</label> <input type="text" name="sr_date" value="<?php echo $sr_date; ?>" size="16" readonly="readonly"> </div> <div id="SR_number"> <label>SR# :</label> <input type="text" name="sr_number" value="<?php echo $currentSR; ?>" size="10" readonly="readonly"> <br/> </div> <div> <table> <thead> <th>Items</th> <th>Sub Items</th> <th>Item Code</th> <th>Demanded Qty</th> <th>UoM</th> <th>Class</th> <th>Description</th> <th>BIN Location</th> </thead> <?php $sql = "SELECT DISTINCT Items FROM bom_subitems ORDER BY Items"; $res_bom = mysql_query($sql, $con); while($row = mysql_fetch_assoc($res_bom)){ $Items = $row['Items']; echo "<tr> <td> <input type='name' value='$Items' name='Items[]' id='Items' readonly = 'readonly' size='5'></td> <td> </td> <td> </td> <td><center><input type='text' name='DemandedQty' id='DemandedQty[]' value='' size='7'></center></td> </tr>"; $sql = "SELECT Items, SubItems, ItemCode, UoM, Class, Description, BINLocation FROM bom_subitems WHERE Items = '$Items' ORDER BY Items"or die(mysql_error()); $res_sub = mysql_query($sql, $con); while($row_sub = mysql_fetch_assoc($res_sub)){ $Items1 = $row_sub['Items']; $SubItems = $row_sub['SubItems']; $ItemCode = $row_sub['ItemCode']; $UoM = $row_sub['UoM']; $Class = $row_sub['Class']; $Description = $row_sub['Description']; $BINLocation = $row_sub['BINLocation']; echo "<tr> <td> <input type='hidden' value='$Items1' id='Items1' name='Items1[]'></td> <td> <input type='text' name='SubItems[]' value='$SubItems' id='SubItems' readonly='readonly' size='10'></td> <td> <input type='text' name='ItemCode[]' value='$ItemCode' id='ItemCode' readonly='readonly' size='10'></td> <td> </td> <td> <input type='text' name='UoM[]' value='$UoM' id='UoM' readonly='readonly' size='3'></td> <td> <input type='text' name='Class[]' value='$Class' id='Class' readonly='readonly' size='10'></td> <td> <input type='text' name='Description[]' value='$Description' id='Description' readonly='readonly' size='10'></td> <td> <input type='text' name='BINLocation[]' value='$BINLocation' id='BINLocation' readonly='readonly' size='10'></td> </tr>"; } } ?> </table> </div> <?php $RequestedBy = array('AAA', 'BBB'); $ApprovedBy = array('EEE', 'FFF'); $ReceivedBy = array('III', 'JJJ'); $IssuedBy = array('MMM', 'NNN'); ?> <div id='Requested_By'> <label>Requested By:</label> <select name="RequestedBy"> <option value="Select">Select</option> <option value="AAA" <?php if($_POST['RequestedBy'] == 'AAA') echo "selected='selected'"; ?>>AAA</option> <option value="BBB" <?php if($_POST['RequestedBy'] == 'BBB') echo "selected='selected'"; ?>>BBB</option> </select> </div> <div id='Approved_By'> <label>Approved By:</label> <select name="ApprovedBy"> <option name='Select'>Select</option> <option value="EEE" <?php if($_POST['ApprovedBy'] == 'EEE') echo "selected='selected'"; ?>>EEE</option> <option value="FFF" <?php if($_POST['ApprovedBy'] == 'FFF') echo "selected='selected'"; ?>>FFF</option> </select> </div> <div id='Received_By'> <label>Issued By:</label> <select name="IssuedBy"> <option name='Select'>Select</option> <option value="III" <?php if($_POST['ReceivedBy'] == 'III') echo "selected='selected'"; ?>>III</option> <option value="JJJ" <?php if($_POST['ReceivedBy'] == 'JJJ') echo "selected='selected'"; ?>>JJJ</option> </select> </div> <div id='Issued_By'> <label>Received By:</label> <select name="ReceivedBy"> <option name='Select'>Select</option> <option value="MMM" <?php if($_POST['IssuedBy'] == 'MMM') echo "selected='selected'"; ?>>MMM</option> <option value="NNN" <?php if($_POST['IssuedBy'] == 'NNN') echo "selected='selected'"; ?>>NNN</option> </select> </div> <div id="save_btn"> <input type="button" name="button" value="save" onClick="save_sr()" style="width: 5em;"> <input type="button" name="button" value="display" onclick="disp()"> </div> </form> </body> </html> and here is the save code: <?php error_reporting(0); date_default_timezone_set("Asia/Singapore"); //set the time zone $con = mysql_connect('localhost', 'root',''); if (!$con) { echo 'failed'; die(); } mysql_select_db("mes", $con); $sr_date = $_POST['sr_date']; $sr_number = $_POST['sr_number']; $Items1 = $_POST['Items1']; $SubItems = $_POST['SubItems']; $ItemCode = $_POST['ItemCode']; $DemandedQty = $_POST['DemandedQty']; $UoM = $_POST['UoM']; $Class = $_POST['Class']; $Description = $_POST['Description']; $BINLocation = $_POST['BINLocation']; $RequestedBy = $_POST['RequestedBy']; $ApprovedBy = $_POST['ApprovedBy']; $ReceivedBy = $_POST['ReceivedBy']; $IssuedBy = $_POST['IssuedBy']; $Items = $_POST['Items']; for($i = 0; $i < count($Items1); $i++) { if ( $DemandedQty != "" ) { $sql = "INSERT INTO stock_requisition (sr_date, sr_number, Items, SubItems, ItemCode, DemandedQty, UoM, Class, Description, BINLocation, RequestedBy, ApprovedBy, ReceivedBy, IssuedBy) VALUES ('$sr_date', '$sr_number', '$Items1[$i]', '$SubItems[$i]', '$ItemCode[$i]', '$DemandedQty', '$UoM[$i]', '$Class[$i]', '$Description[$i]', '$BINLocation[$i]', '$RequestedBy', '$ApprovedBy', '$ReceivedBy', '$IssuedBy') "; $result = mysql_query($sql, $con); } } ?> I attach my sample form and the data save in database. Thank you so much hello friends, actually i am trying to insert data in mysql database. here is my code
<?php
include_once("../includes/database.php");
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Insert Product</title>
</head>
<body>
<form action="insert_product.php" method="post" enctype="multipart/form-data">
<table align="center" width="600">
<tr align="center">
<td colspan="8"><h2> Insert New Post</h2></td>
</tr>
<tr>
<td align="right"><b>Product Title :</b></td>
<td><input type="text" name="product_title" size="50" style="background-color:#06C; color:#FFF" /></td>
</tr>
<tr>
<td align="right"><b>Product Category :</b></td>
<td>
<select name="product_cat" style="background-color:#06C; color:#FFF" >
<option>Select A Category </option>
<?php
$get_cats = "SELECT * FROM categories";
$run_cats = mysqli_query($con, $get_cats);
while($row_cats = mysqli_fetch_array($run_cats)){
$cat_id = $row_cats['cat_id'];
$cat_title = $row_cats['cat_title'];
echo "<option value='$cat_id'>$cat_title</option>";
}
?>
</select>
</td>
</tr>
<tr>
<td align="right"><b>Product Platform :</b></td>
<td>
<select name="product_brand" style="background-color:#06C; color:#FFF" >
<option>Select A Platform </option>
<?php
$get_brands = "SELECT * FROM brands";
$run_brands = mysqli_query($con, $get_brands);
while($row_brands = mysqli_fetch_array($run_brands)){
$brand_id = $row_brands['brand_id'];
$brand_title = $row_brands['brand_title'];
echo "<option value='$brand_id'>$brand_title</option>";
}
?>
</select>
</td>
</tr>
<tr>
<td align="right"><b>Product Image :</b></td>
<td><input type="file" name="product_image" /></td>
</tr>
<tr>
<td align="right"><b>Product Price :</b></td>
<td><input type="text" name="product_price" style="background-color:#06C; color:#FFF" /></td>
</tr>
<tr>
<td align="right" valign="top"><b>Product Description :</b></td>
<td><textarea name="product_desc" cols="50" rows="10" style="background-color:#06C; color:#FFF" ></textarea></td>
</tr>
<tr>
<td align="right"><b>Product Keywords :</b></td>
<td><input type="text" name="product_keywords" size="50" style="background-color:#06C; color:#FFF" /></td>
</tr>
<tr align="center">
<td colspan="8"><input type="submit" name="insert_post" value="Submit Now" /></td>
</tr>
</table>
</form>
</body>
</html>
<?php
if(isset($_POST['insert_post'])){
$product_title = $_POST['product_title'];
$product_cat = $_POST['product_cat'];
$product_brand = $_POST['product_brand'];
$product_price = $_POST['product_price'];
$product_desc = $_POST['product_desc'];
$product_keywords = $_POST['product_keywords'];
$product_image = $_FILES['product_image']['name'];
$product_image_tmp = $_FILES['product_image']['tmp_name'];
move_uploaded_file($product_image_tmp,"product_image/$product_image");
$sql = "INSERT INTO products (product_cat,product_brand,product_title,product_price,product_desc,product_image,product_keywords) VALUES ('$product_cat','$product_brand','$product_title','$product_price','$product_desc','$product_image','$product_keywords')";
$query = mysqli_query($con, $sql);
if($query){
echo "<script>alert('Product Has Been Inserted')</script>";
echo "<script>windoow.open('insert_product.php','_self')</script>";
exit();
}else{
echo "<script>alert('errror')</script>";
}
}
?>
but somehow its not insertingdata into my table can somebody tell wherre m i doing mistake. the categories and brands are displaying from database. But its not inserting data here is my database script.
<?php
$con = mysqli_connect("localhost","root","","sg");
?>
Hi I try to build a login form in which the user enter its userid, and the system check in the database for the user name and present it There are several other fiels that should act the same way. the problem is that the description field not get the user name. I be glad if someone show me where is the problem here is the code i use: The index.php page
<!DOCTYPE html>
<!--
To change this license header, choose License Headers in Project Properties.
To change this template file, choose Tools | Templates
and open the template in the editor.
-->
<?php
require_once(".Includes/GlDbOra.php");
$logonSuccess = false;
//get user details
if (isset($_POST['userid_typed']))
{
$row = (DBOracle::getInstance()->get_user_details1($_POST['userid']));
if(!$row)
{
echo "The user code entered in invalid";
}
else
{
?>
<input type="text" name="userid_desc" id="user_desc" class="regular_textbox" value=<?php echo $row('username'); ?> readonly="readonly" disabled="disabled" />
<?php
}
}
?>
<html>
<head>
<meta charset="UTF-8">
<title>Login</title>
<script type="text/javascript" src="../../php-ajax/jquery-3.5.1.js"></script>
<link href="index.css" type="text/css" rel="stylesheet" madia="all"/>
</head>
<body>
<div class="logon">
<form name="logon" id="logon" action="index.php" method="POST" >
<span style="clear: both; float: left; margin-top: 20px; ">
<label for="userid">User Id</label>
<input type="text" name="userid" id="userid" class="left_radius_textbox" placeholder="<?php echo userid;?>"/>
<input type="text" name="userid_desc" id="user_desc" class="regular_textbox" value="" readonly="readonly" disabled="disabled" />
<label for="password">Password</label>
<input type="password" name="password" id="password" class="regular_textbox" placeholder="<?php echo password;?>"/>
</span>
<span style="clear: both; float: left; margin-top: 20px">
<label for="compid">Company</label>
<input type="text" name="compid" id="compid" class="left_radius_textbox" placeholder="<?php echo compid;?>"/>
<input type="text" name="compid_desc" id="compid_desc" class="regular_textbox" value="" readonly="readonly" disabled="disabled" />
<label for="language">Language</label>
<input type="text" name="language" id="language" class="left_radius_textbox" placeholder="<?php echo language;?>"/>
<input type="text" name="language_desc" id="language_desc" class="regular_textbox" value="" readonly="readonly" disabled="disabled" />
</span>
<span style="clear: both; float: right; margin-top: 20px">
<input type="submit" value="Login"style="margin-right: 500px; border-radius: 40px ; text-align:center;width: 220px; height: 30px;" class="" placeholder="<?php echo login;?>"/>
</span>
</form>
</div>
<script>
$(document).ready()
{
$("#userid").focusout()
{
var userid=$('input[name=userid]').val();
$.ajax
({
type:"POST",
url:"../AmiDorGL/Includes/GlDbOra.php",
data:
{
"userid_typed":1,
"userid":userid,
},
datatype:"text",
success:function(response)
{
$("#userid_desc").html(response);
}
});
};
};
</script>
</body>
</html>
the GlDbOra.php code:
<?php
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
class DBOracle {
private static $instance = null;
private $OracleUser="xxx";
private $OraclePwd="xxx";
private $OracleDB="xxx";
public static function getInstance() {
if (!self::$instance instanceof self) {
self::$instance = new self;
}
return self::$instance;
}
// The clone and wakeup methods prevents external instantiation of copies of the Singleton class,
// thus eliminating the possibility of duplicate objects.
public function __clone() {
trigger_error('Clone is not allowed.', E_USER_ERROR);
}
public function __wakeup() {
trigger_error('Deserializing is not allowed.', E_USER_ERROR);
}
public function __construct () {
$this->con = oci_connect($this->OracleUser, $this->OraclePwd, $this->OracleDB);
if (!$this->con) {
$m = oci_error();
echo $m['message'], "\n";
exit;
}
}
public function get_user_details1($userid)
{
$query = "select first_name||' '||last_name username, password from users where userid = :userid_bv";
$stid = oci_parse($this->con, $query);
oci_bind_by_name($stid, ':userid_bv', $userid);
oci_execute($stid);
$row = oci_fetch_array($stid, OCI_ASSOC);
return $row;
}
}
Edited May 29, 2020 by requinix please use the Code <> button when posting code |
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