PHP - Round Numbers

Code: [Select]
$newrating = round($imageinfo['rating'],2);
this outputs:

4.49

in my db rating is

4.4884   


all i need is the 4.... would i use some type of preg_replace or something just to grab the first 1 before the decimal? (all  i need is the first number before the decimal)

I need to take a time and convert so it is rounded up or down to the nearest 0 or 5.

Code: [Select]
function roundMe ($time, $upDown) {

  if($upDown==1) {
     //round up
  } else {
     //round down
  }

  return $x;

}

echo roundMe("16:22", 1); // returns 16:25
echo roundMe("16:22", 0); // returns 16:20
echo roundMe("16:25", 1); // returns 16:25
echo roundMe("16:59", 1); // returns 17:00
echo roundMe("16:59", 0); // returns 16:55

HOw to get the AVERAGE of my entire database?

$query = "SELECT ROUND(AVG(scores)) FROM table";

Thanks!
Bickey 

Hi..

I encountered problem in rounding of numbers into two decimal places.

here is my sample code:


if($W4_STATUS == 1 AND $DEPENDENTS == 0 AND $TotEarn >= 7917 AND $TotEarn <= 12500) {
   $TAX = ($TotEarn - 7917);
   $TAX = (937.50 + ($TAX * .25));
   $TAX = number_format($TAX, 2, '.', '');
}


for example from this:

 $TAX = ($TotEarn - 7917);
  $TAX = (937.50 + ($TAX * .25));

the output is: 1417.615

using this:

$TAX = number_format($TAX, 2, '.', '');

the output was : 1417.61

but it should be : 1417.62

Thank you

Hey guys,

I use the code below to add a corners to an image and it works great but when i add a border to the image it add a square.... any ideas how i can add a border to the rounded image?

<?php
$image_file = $_GET['src'];
$corner_radius = isset($_GET['radius']) ? $_GET['radius'] : 20; // The default corner radius is set to 20px
$topleft = (isset($_GET['topleft']) and $_GET['topleft'] == "no") ? false : true; // Top-left rounded corner is shown by default
$bottomleft = (isset($_GET['bottomleft']) and $_GET['bottomleft'] == "no") ? false : true; // Bottom-left rounded corner is shown by default
$bottomright = (isset($_GET['bottomright']) and $_GET['bottomright'] == "no") ? false : true; // Bottom-right rounded corner is shown by default
$topright = (isset($_GET['topright']) and $_GET['topright'] == "no") ? false : true; // Top-right rounded corner is shown by default
$imagetype=strtolower($_GET['imagetype']);
$backcolor=$_GET['backcolor'];
$endsize=$corner_radius;
$startsize=$endsize*3-1;
$arcsize=$startsize*2+1;

if (($imagetype=='jpeg') or ($imagetype=='jpg')) {
$image = imagecreatefromjpeg($image_file);
} else {
if (($imagetype=='GIF') or ($imagetype=='gif')) {
$image = imagecreatefromgif($image_file);
} else {
$image = imagecreatefrompng($image_file);
}
}


$size = getimagesize($image_file);
// Top-left corner
$background = imagecreatetruecolor($size[0],$size[1]);
imagecopymerge($background, $image, 0, 0, 0, 0, $size[0], $size[1], 100);
$startx=$size[0]*2-1;
$starty=$size[1]*2-1;
$im_temp = imagecreatetruecolor($startx,$starty);
imagecopyresampled($im_temp, $background, 0, 0, 0, 0, $startx, $starty, $size[0], $size[1]);
$bg = imagecolorallocate($im_temp, hexdec(substr($backcolor,0,2)),hexdec(substr($backcolor,2,2)),hexdec(substr($backcolor,4,2)));
$fg = imagecolorallocate($im_temp, hexdec(substr($forecolor,0,2)),hexdec(substr($forecolor,2,2)),hexdec(substr($forecolor,4,2)));

if ($topleft == true) {
imagearc($im_temp, $startsize, $startsize, $arcsize, $arcsize, 180,270,$bg);
imagefilltoborder($im_temp,0,0,$bg,$bg);
}

// Bottom-left corner
if ($bottomleft == true) {
imagearc($im_temp, $startsize, $starty-$startsize,$arcsize, $arcsize, 90,180,$bg);
imagefilltoborder($im_temp,0,$starty,$bg,$bg);
}

// Bottom-right corner
if ($bottomright == true) {
imagearc($im_temp, $startx-$startsize, $starty-$startsize,$arcsize, $arcsize, 0,90,$bg);
imagefilltoborder($im_temp,$startx,$starty,$bg,$bg);
}

// Top-right corner
if ($topright == true) {
imagearc($im_temp, $startx-$startsize, $startsize,$arcsize, $arcsize, 270,360,$bg);
imagefilltoborder($im_temp,$startx,0,$bg,$bg);
}


$newimage = imagecreatetruecolor($size[0],$size[1]);
imagecopyresampled($image, $im_temp, 0, 0, 0, 0, $size[0],$size[1],$startx, $starty);

// Output final image
header("Content-type: image/png");
imagepng($image);
imagedestroy($image);
imagedestroy($background);
imagedestroy($im_temp);
?>

hello, if i have the following, how would i display it?

Code: [Select]
function minutes_round ($hour = "$signintime", $minutes = '5', $format = "H:i")
{
    $seconds = strtotime($hour);
    $rounded = round($seconds / ($minutes * 60)) * ($minutes * 60);
    return date($format, $rounded);
}

Hi there.

I am trying to display numbers if they have the numbers like:

number_format($price,2)

This gives us two decimal places i.e 7.23

Now thats fine, I would like to round the last two decimal places. I would like to make it 7.25, (rounding it from 7.23 to 7.25)

Similarly making:

12.44 to 12.45
33.18 to 33.20
52.13 to 52.15

So actually rounding the last two places. Coz obviously customers won't be able to pay 52 dollars 13 cents. So therefore rounding the last cent's (decimal part) making it to 52.15

Thank you.

All comments and feedback are welcomed.


(d

can you have something like..

echo $whatever;

this putput
1.2

can you split this number so the first integer will be in $val"(1)" or whatever and the second integer after the "." will be in $val2"(2)"

hello again

how to get ratio with result max 3 numbers such as 3.00 or 0.11


if im do $mynumbers = 1000 / 400;

so reusult to be 1.00 ?

and how to put full stop if it is more then 4 numbers

result instead of 1000 to have 1.000

Working through some beginner stuff and ive copied some code straight out the textbook, word for word yet it produces:

Parse error: syntax error, unexpected T_ECHO, expecting ',' or ';' in C:\wamp\www\PHP Work\StringtoNumbers.php on line 11


<html>
   <head>
      <title>Strings Into Numbers</title>
   </head>
   <body>
      <h1>Strings Into Numbers</h1>
      <ul>
      <?php
         $n = "0x237a";
         echo "<li>".$n."</li>"
         echo "<li>".($n * 3)."</li>";
         $n2 = "34re5";
         echo "<li>".($n2 + 2)."</li>";
         $n3 = "boo";
         echo "<li>".($n3 + 2)."</li>";
      ?>
      </ul>
   </body>
</html>

Hi i got an error. I cant get $new_score and $new_played variables.


$name = $_POST["name"];
$score = $_POST["score"];

$result = mysql_query("SELECT * FROM taure_lentele WHERE name='$name'");
$row = mysql_fetch_array($result);
if(mysql_num_rows(mysql_query("SELECT name FROM taure_lentele WHERE name='$name'") ) == 1 )
{
   $old_score = $row['score'];
   $score + $old_score = $new_score;

   $old_played = $row['played'];
 $new_played = $old_played++;

   mysql_query("DELETE FROM taure_lentele WHERE name='$name'");
   mysql_query("insert into `taure_lentele` set `name` = '$name', `score` = '$new_score',  `played` = '$new_played");
}

is this a proper way of entering this?

Code: [Select]
$result = mysql_query("SELECT * FROM jobs WHERE id2 >= '$startdate' AND id2 < '$enddate' ORDER BY id");

Hey I have a quick question.
I am trying to have a part of this PHP script compare two numbers.
There is a randomly generated two-digit number named $random and
There is another two digit number named $number.
I want to make it so the PHP checks to see if $number has any of the same charcters as $random.
I don't know how to do this though. I suspect that somehow both numbers need to be broken apart somehow.
Any advice would be appreciated.
Let me know if I should explain it more clearly
Thanks a ton!

Hey i'm just woundering how i would echo numbers from a database like  1000000 lets say 1 million
how would i go about on echoing it like this 1,000,000



ZhsHero

Hello Guys,

I have a var for height like $height="67" and  want to be able to split that number into, so that I can display
6 feet 7 inches but I have not figured out how to do it.. Please advise..

This is the current code I am working with but doesn't work. The problem is that explode won't work without some type of separator.

Code: [Select]
$height2 = explode(" ", $height);
echo "This is feet". $height2[0] ."<br>";
echo "This is inches". $height2[1]. "<br>";