PHP - Messages Not Being Removed When Page Refreshed First Time

When I use the following code, it doesn't print out "test" until after I refresh the page.

unset($_SESSION["product"]);

if ( !empty($_SESSION["product"]) && ($_SESSION["product"] != NULL)) {
echo "test";
}

When I use:

var_dump($_SESSION["product"]);

It shows:

array(0) { } 

I'm wondering it that's the problem. That it's array(0) when it should be array().

Im trying to create a page that collects personal info from users and registers them.  I have a page that contains the registration form which i will call page 1.  A second page which I will call page 2, processes the form.   A simplified version of page 2 looks like this Code: [Select]

<?php

if (isset($_POST['submitted'])) {
 
    $errors = array();


// Connect to the database.

        require_once ('config.php');


//Check for errors.


//Check to ensure that the password is long enough and is of the right format.

if (eregi ("^[[:alnum:]]{8,16}$" , $_POST['password'])) {

      $b = TRUE;

    } else {
     
      $b = FALSE;

     $errors[] = 'Please enter a password that consists only of letters and numbers between 8 and 16 characters long.';

    }     


//Check to make sure the password matches the confirmed password.

if ($_POST['password'] == $_POST['password2']) {

     $c = TRUE;

     $password =  $_POST['password']; //Encrypt the password.

    } else {

        $c = FALSE;

     $errors[] = 'The password you entered did not match the confirmed password.';

    }




//Check to make sure they entered their first name and it's of the right format.

if (eregi ("^([[:alpha:]]|-|')+$", $_POST['firstname'])) {

        $d = TRUE;

    } else {

        $d = FALSE;

        $errors[] = 'Please enter a valid first name.';


   }



//Check to make sure they entered their last name and it's of the right format.

if (eregi ("^([[:alpha:]]|-|')+$", $_POST['lastname'])) {

        $e = TRUE;

    } else {

        $e = FALSE;

        $errors[] = 'Please enter a valid last name.';


   }




    

//Insert data into database.

if (empty($errors)) {
//query the database.  for the sake of simplicity, I wont include the code
                                       
 // Show thank you message
            echo "<h3>Thank You!</h3>
            You have been registered";
        } else {
            echo '<font color="red">You could not be registered, please contact us about the problem and we will fix it as soon as we can.</font>';

        }


//Display error messages.


} else {// if errors array is not empty


header("Location: page1.php?message=$errors");//Trying to pass the errors array into the url for page1 

        
    }
}

?>



So the idea is to create an array that contains all the errors.  Upon querying the database, if the user completed the fields as required, a thank you message is printed. If not, he is redirected to the page containing the form (page 1) and the array containing the errors is transferred to page 1. Now I will include the relevant section of page 1 whihc is supposed to print the error messages.
Code: [Select]
<?php   if(isset($_GET['message'])  {
                
echo '<h3>Error!</h3>
         The following error(s) occured:<br />';

       
         foreach ($errors as $msg) {
             echo "$msg<br/>\n";
         }

  }

?>


 I get the following error message when I submit the registration forms with deliberate errors:



Error!

The following error(s) occured:

PHP Error Message

Warning: Invalid argument supplied for foreach() in /home/a4993450/public_html/register_page_content.php on line 66

Free Web Hosting
 
Can anyone point out why this error occurs?

I have finally gotten my registration form to work on my website but i have another question! When for example someone registers at my website and type in the wrong email address, i've set php to give out an error message like "Please enter a valid email address". But that message shows up at the verry top-left corner of my page and makes some objekts move around on my page and you can't click in the <input> fields anymore . How could i make those error messages show up above my registration form at the top of my site and maybe style them with a border and maybe make the text red and so that it doesnt change anything on my page? could i use css for that somehow or what?

This is how i show the error messages right now:
  public function show_errors()
  {
    echo "<h3>Errors</h3>";

    foreach($this->errors as $key=>$value)
      echo $value."<br>";
  }
  public function valid_data()
  {
    if($this->user_exists())
      $this->errors[] = 'Username already taken, choose another one!';
    if(empty($this->username))
      $this->errors[] = 'Please enter a valid username!';
if(empty($this->first_name))

We know that soon, a number of functions will be removed from PHP. There are Deprecation Warnings.   I would like to make experiments with functions that have already been removed, and that have suitable substitutes. For example, the ereg() family of functions and the split() function have a suitable substitute in the preg_*() family of functions.   Was there a simple, common function that was available in the core PHP build that is now actually removed as of PHP 5.4 (PHP 5.5, perhaps?), where another function can be used to simulate it?   I was thinking of the mysql_*() functions, but these functions, although deprecated, are made available by simply including the extension in the PHP.INI file (as I understand it). That is, I have the mysqli extension and not the mysql extension loaded. Thus, the mysql_*() family of functions is not available. So I would experiment to see what would happen if I created a 'wrapper' function named mysql_connect() with mysqli_connect() inside.   I am wanting to make this kind of experiment with a core function, like split(), that is already removed.    

Checking if php function mysqli_fetch_assoc() been removed from newer php versions.   Running LAMP Apache 2.4.7 PHP 5.5.9 MySQL 5.5.38   Running WAMPserver Apache 2.4.9 PHP 5.5.12 MySQL 5.6.17   LAMP system, this code works fine:

<?php

session_start();

$_SESSION['dbhost'] = $_POST['dbhost'];

$_SESSION['dbuser'] = $_POST['dbuser'];

$_SESSION['dbpass'] = $_POST['dbpass'];

$_SESSION['dbname'] = $_POST['dbname'];

?> <!store variables in a session>

<html>

<head>

<link rel="stylesheet" href="style.css">

</head>

<body>



<?php

if (!empty($_SESSION['dbname'])) {

    echo "Database connection settings are saved for ".$_SESSION['dbname'].".<br>";

    $con = mysqli_connect($_SESSION['dbhost'],$_SESSION['dbuser'],$_SESSION['dbpass'],$_SESSION['dbname']);

    if (mysqli_connect_errno()) {

        die("Failed to connect to your database with the saved settings.<br>");

    }

    else {

        echo "Successfully connected to the database.<br><br>";

    }

    $sql = "SELECT count(*) FROM account";

    $query=mysqli_fetch_assoc(mysqli_query($con,$sql));

    $count = $query["count(*)"];

    if ($count == 0) {

        echo "Detected your account has not been configured yet: <br>";

        echo 'Click <a href ="setup_account.html">here</a> to configure.<br><br>';

    }

    else {

        $sql = "SELECT ircnick FROM account";

        $query=mysqli_fetch_assoc(mysqli_query($con,$sql));

        $user = $query["ircnick"];

        echo "Found your previous saved settings: <br>";

        echo 'If you want to change the settings for '.$user.' click <a href="setup_account.html">here</a>.<br>';

    }

}

else {

    echo "Error saving your settings.<br>";

}



?>

But on WAMP get this output: (!) Warning: mysqli_fetch_assoc() expects parameter 1 to be mysqli_result, boolean given in C:\wamp\www\setup.php on line 44 Call Stack #  Time    Memory  Function                       Location 1  0.0000 249936   {main}()                        ..\setup.php:0 2 0.0156  260184   mysqli_fetch_assoc()   ..\setup.php:44   Trying to share my code with a friend who is using Windows.
Edited by SmexyPantsGnome, 25 August 2014 - 09:12 PM.

How is it possible, in PHP, to display an error message next to a form input text field if a user is attempting to submit a form with empty fields? Moreover, how is it possible to remove the same error message when the user fills in the input field with the required data and/or refreshes the page?

I have 2 files that I am working with: application.php and process.php.

application.php mainly has the HTML of the form.
process.php has the PHP for processing and validating the form.

I am very new to learning PHP (I started learning it last week) and I have been searching for hours for a clear answer. I have already tried different methods for generating the error message including: using empty(), !isset, $_POST["name"] = "", etc, and have tried using session_start();, $row, echo, print, and other variables to try and display error message on the page, and I have tried using unset();, and = null, to try and remove the error message once the input field has been filled but all to no avail. Either the method I try only half works, or nothing works, and I cannot pinpoint which is the part that is not working.

I only have 2 files to work with, and as an example of what I want to do is:

1. If the first name field is empty when the user clicks submit, an error message should appear next to the input.
2. If the user fills in the input and clicks submit, the form should be processed and added to the database.
3. When the user returns to the application to page to fill in another application form, the error message should not appear.

Is this possible with PHP?

  Hello, I removed  .php extension with .htaccess

Folks,

I am trying to grab the value selected in a Dropdown, with $_GET['q']. Then i am echoing the grabbed value.

Funny thing is, when i select value from HTML dropdown (onchange="location=this.value"), and when a new value is selcted, it appaears in url like this:

Quote

http://www.abc.com/?search=selected-value.html


But when i try to grab and echo the value of 'q' it gets passed only when i refresh the page and not when i change my selecting in dropdown.

Am not sure whats happening, can someone help me on this?

Cheers
NT

hello,

i want to get into a particular page if the user stays more than lets say 20 minutes to automatically load another php page.

More specific i have a page which is a test. The user answears to some multiple choice questions. i want him to have only a particular time to anwear. Lets say after 20 min i want to load the results page.

Any ideas?

Can someone tell me how to get my $row to just have the person logging in to be welcomed presently when I test the page it is welcoming everyone of the test names????
this is the welcome page after the form. But it is picking up all tested members???

<?php
session_start();
ini_set ("display_errors", "1");
error_reporting(E_ALL);
?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Welcome</title>
</head>

<body>
<?php
/* Program: login.php
 * Desc:

Displays the new member welcome page. Greets
 *

member by name and gives a choice to enter
 *

restricted section or go back to main page.
 */ 
if (isset($_SESSION['id'])) {    
include('Connections/connect_to_mysql.php');        
// Set the users session ID
    $id=$_SESSION['id'];

// Now let's initialize vars to be printed to page in the HTML section so our script does not return errors 
// they must be initialized in some server environments

$firstname = '';
$lastname = '';
$country = '';
$email = '';

//Formulate Query
//This is the best way to perform an SQL query
$query = "SELECT id, firstname FROM `Members` WHERE id={$_SESSION['id']}";
$result = mysql_query($query);

//Check result
//This shows the actual query sent to MySQL and the error. Useful for debugging.

if(!$result){

$message = 'Invalid query:' . mysql_error() . "\n";

$message .= 'Whole query:' . $query;

die($message);
}
//Use result
//Attempting to print $result won't allow access to information in the resource
//One of the mysql result functions must be used
//See also mysql_result(), mysql_fetch_array(), mysql_fetch_row(), etc.
while($row=mysql_fetch_assoc($result)){

  echo "Welcome, {$row['firstname']}";
}
}

   mysql_free_result($result);
?>
<p>Your new Member accounts lets you enter the members only section
of our web site. You'll find special discounts, a profile of matches,
live advise from experts, and much more.</p>
<p>Your new Member ID and password were emailed to you. Store them
carefully for future use.</p>
<div style="text-align: center">
<p style="margin-top: .5in; font-weight: bold">
Glad you could join us!</p>
<form action="profile.php" method="post">

<input type="submit"

value="Enter the Members Only Section">

</form>
<form action="index.php" method="post">

<input type="submit" value="Go to Main Page">

</form>

</div>
</body>
</html>

Hey,

I need to generate a script which tells me how long it takes for an external page to load...

Please can you help?

Thanks

Code: [Select]
  <?php
    mysql_connect("localhost","root") or die(mysql_error());
    mysql_select_db("Regis") or die(mysql_error());



     if (isset($_POST["sub"]))
     {
      $usercheck = $_POST["username"];

       $check = mysql_query("SELECT username FROM registration WHERE username = '$usercheck'") or die(mysql_error());

       $check2 = mysql_num_rows($check);
        //if the name exists it gives an error
     if ($check2 != 0)
     {
      echo("<script LANGUAGE='JavaScript'>window.alert('Sorry, the username" . $usercheck . "is already in use.')</SCRIPT>");
       echo ("<script LANGUAGE='JavaScript'>window.location = 'registration.php'</script>");


      // print("url=registration.php\");
     }

     }
?>
<html><head></head><body>
 <form action="submit.php" method="post">

 <table border="0">

 <tr><td colspan=2><h1>Login</h1></td></tr>

 <tr><td>Username:</td><td>

 <input type="text" name="username" maxlength="40">

 </td></tr>

 <tr><td>Password:</td><td>

 <input type="password" name="pass" maxlength="50">

 </td></tr>

 <tr><td><a href="register.php">Register</a></td>

 <td><input type="submit" name="submit" value="Login">

 </td></tr>

 </table>

 </form>
 
 </body></html>




my problem is  if ($check2 != 0)
     {
      echo("<script LANGUAGE='JavaScript'>window.alert('Sorry, the username" . $usercheck . "is already in use.')</SCRIPT>");
       echo ("<script LANGUAGE='JavaScript'>window.location = 'registration.php'</script>");



when it redirect to registration.php its seem it take more than 5 seconds to redirect any solution to make it faster????

I have a Yahtzee system

Code: [Select]
session_start();
$_SESSION['Yahtzee']['totaltime'] =time();
echo $_SESSION['Yahtzee']['totaltime'];
Now, Long STORY Short when somone finishes playing the Yahtzee, I update there username with the score they had, and I want to update how long they have been playing, and it will be for "Total Time Playing globally" no matter how many games.

If I do this session and echo it out, it echo's out the time, but I need it to echo out seconds instead so I can just add that to my totaltime field in my database each time they finished a game.

hi! i dont know if the query below from mysql is slowing down the page or i have not written it properly:
It is very slow, even when you limit the results to 100 . Thanks in advance..
Code: [Select]
SELECT  `tbl_business`.`appformno`, " _
            & "`tbl_business`.`pobox`, `tbl_business`.`plotno`, `tbl_business`.`postalcode`, " _
            & "`tbl_business`.`zonecode`, `tbl_business`.`ne`, `tbl_activities`.`act_code`, " _
            & "`tbl_activity_codes`.`approved_fee`, `tbl_payment_status`.`status`, " _
            & "`tbl_business`.`company`, `tbl_activity_codes`.`description` " _
            & "FROM (`citycouncil`.`tbl_activity_codes` `tbl_activity_codes` " _
            & "LEFT JOIN (`citycouncil`.`tbl_business` `tbl_business` " _
            & "LEFT JOIN `citycouncil`.`tbl_activities` `tbl_activities` " _
            & "ON `tbl_business`.`appformno`=`tbl_activities`.`appformno`) " _
            & "ON `tbl_activity_codes`.`act_code`=`tbl_activities`.`act_code`) " _
            & "LEFT JOIN `citycouncil`.`tbl_payment_status` `tbl_payment_status` " _
            & "ON `tbl_activities`.`id`=`tbl_payment_status`.`activity_id` " _
            & "WHERE tbl_business.appformno LIKE '%" & strFormNo & "%' " _
            & "AND tbl_business.bid LIKE '%" & strBizIdNo & "%'" _
            & " AND `tbl_business`.`contperson` LIKE '%" & strContPerson & "%' " _
            & "AND `tbl_business`.`zonecode` LIKE '%" & strZoneCode & "%' " _
            & " AND `tbl_activities`.`act_code` LIKE '%" & strBizActCode & "%' " _
            & "AND `tbl_business`.`roadstreet` LIKE '%" & strStreet & "%' " _
            & " AND `tbl_business`.`company` LIKE '%" & strBizName & "%' " _
            & "AND `tbl_business`.`building` LIKE '%" & strBuilding & "%' " _
            & "ORDER BY `tbl_business`.`appformno`

Hello Coders,

Iam in a confused situation. I made a php script & in that script i want to check how much time (in seconds) the page is taking to fetch the content from the server.
If the time is greater than to i defined time then i want to show a error message to the users.


Anybody can give me ideas ..................... ??