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PHP - Data Displaying At Bottom Of Code?
Hi guys, I have a problem.. I have a table which shows the results, but the table is showing right at the bottom below the button "delete members" although the code is right above it so I don't really understand.. and hope someone can shed the light?
Appreciated Code: [Select] <?php include "connect.php"; session_start(); if(!isset($_SESSION['email'])) { die('You have no access to this page.'); } else{ //Check if records were submitted for deletion if(isset($_POST['id']) && count($_POST['id'])) { //Ensure values are ints $deleteIDs = implode(', ', array_map('intval', $_POST['id'])); $query = "DELETE FROM member WHERE id IN ({$deleteIDs})"; //Debug line echo "Successfuly deleted member(s)"; mysql_query($query) or die(mysql_error()); } ?> <link rel="stylesheet" type="text/css" href="view.css" media="all"> <script type="text/javascript" src="view.js"></script> <body id="main_body" > <img id="top" src="top.png" alt=""> <div id="form_container"> <h1>Consult, Modify or Delete a Member</h1> <form id="form_362567" class="appnitro" method="post" action="searchmember.php"> <div class="form_description"> <h2> Consult, Search, Modify or Delete a Member</h2> <p></p> </div> <ul > <li class="section_break"> <br>Search members with any keyword or character within the options id/email/firstname/lastname/phone/address1/address2/city/county/postcode - relevant matches will show.<br><br> <b>Keyword/Character:</b><br> <input id="search" name="search" class="element text medium" type="text" maxlength="50" value=""/> <br><br> <b>Search on</b>:<br> <select name="searchvalue" id="searchvalue"> <option name="id" id="id">id</option> <option name="email" id="email">email</option> <option name="firstname" id="firstname">firstname</option> <option name="lastname" id="lastname">lastname</option> <option name="phone" id="phone">phone</option> <option name="address1" id="address1">address1</option> <option name="address2" id="address2">address2</option> <option name="city" id="city">city</option> <option name="county" id="county">county</option> <option name="postcode" id="postcode">postcode</option> </select><br><input type='submit' value='Search' name='go' /><INPUT TYPE="button" VALUE="Cancel" onClick="history.go(-1);return true;"><br> <br> To consult or modify a profile click on the member's E-mail address. <li class="section_break"> </form> <?php $result = mysql_query("SELECT * FROM member"); ?> <table border='1'> <tr> <th>First Name</th> <th>Last Name</th> <th>Phone Number</th> <th>Postcode</th> <th>E-mail</th> <th>Delete</th> </tr> <?php while($row = mysql_fetch_array($result)) { echo "<form action='' method='POST'>"; echo "<tr>"; echo "<td>" . $row['firstname'] . "</td>"; echo "<td>" . $row['lastname'] . "</td>"; echo "<td>" . $row['phone'] . "</td>"; echo "<td>" . $row['postcode'] . "</td>"; echo "<td>"; echo '<a href="consultmember.php?email='; echo $row['email']; echo '">'; echo $row['email']; echo "</a></td>"; echo "<td><input type='checkbox' name='id[]' value='{$row['id']}' /></td>"; echo "</tr>"; } ?> <br><input type='submit' value='Delete Members' name='delete' /><INPUT TYPE="button" VALUE="Cancel" onClick="history.go(-1);return true;"><br> </form> <div id="footer"> </div> </div> <img id="bottom" src="bottom.png" alt=""> </body> <?php } ?> Similar TutorialsHello everyone, I begin in everything web related but I have been programming for years. I tried to code something simple : small Mysql DB (works fine) and to begin a search bar to browse data. I adapted a code that I understood provided here : https://www.cloudways.com/blog/live-search-php-mysql-ajax/. Base principle is simple : as you type in your query, it will pass the text to script.js that will forward this request to ajax.php file. In the ajax.php, a javascript function named “fill()” will pass the fetched results. This function will also display the result(s) into “display” div in the “search.php” file. The problem is that when I type anything it displays, below the search bar, at the moment I type a character: Quote
'; //Fetching result from database. while ($Result = MySQLi_fetch_array($ExecQuery)) { ?> ")'>
instead of the actual answer from my database (no error in the browser console). I tested the SQL query + the user I provide and everything seems fine. Any clue what could be the root cause ? I strongly suspect a mistake in the code as I already corrected one (script.js instead of scripts.js) but I really cannot figure out where. Thanks in advance,
problematic code (ajax.php):
<?php
//Including Database configuration file.
include "db.php";
//Getting value of "search" variable from "script.js".
if (isset($_POST['search'])) {
//Search box value assigning to $Name variable.
$Name = $_POST['search'];
//Search query.
$Query = "SELECT Name FROM search WHERE Name LIKE '%$Name%' LIMIT 5";
//Query execution
$ExecQuery = MySQLi_query($con, $Query);
//Creating unordered list to display result.
echo '
<ul>
';
//Fetching result from database.
while ($Result = MySQLi_fetch_array($ExecQuery)) {
?>
<!-- Creating unordered list items.
Calling javascript function named as "fill" found in "script.js" file.
By passing fetched result as parameter. -->
<li onclick='fill("<?php echo $Result['Name']; ?>")'>
<a>
<!-- Assigning searched result in "Search box" in "search.php" file. -->
<?php echo $Result['Name']; ?>
</li></a>
<!-- Below php code is just for closing parenthesis. Don't be confused. -->
<?php
}}
?>
</ul>
Hello im working on a project which involves marking attendance via an RFID tag and saving the time into an sql file. Everything seems to be working fine and the time stamp is successfully punched into the SQL but something is wrong with the php code thats supposed to display this data. Please if any one can take a look and help.
MY CODE for displaying the data (ViewAttendance.php):
<?php
include_once("header.php");
$attData = array();
$totDays = 0;
if(isset($_REQUEST['submit'])){
$totDays = cal_days_in_month(CAL_GREGORIAN,$_REQUEST['month'],$_REQUEST['year']);
$attData = $commonObj->getAttendanceData($_REQUEST['month'],$_REQUEST['year']);
//print_r($attData);
//print_r(date("d",strtotime($attData[0]['punch_time'])));
}
?>
<div class="container">
<div class="row">
<div class="col-sm-12">
<h4>Showing Attendance</h4>
<form name="showAtt" method="post">
<div class="col-sm-4"><label>Select Month</label>
<select name="month" class="form-control">
<?php for($i=1;$i<=12;$i++){?>
<option value="<?php echo $i;?>"><?php echo $i;?></option>
<?php }?>
</select>
</div>
<div class="col-sm-4"><label>Select Year</label>
<select name="year" class="form-control">
<?php for($i=date("Y");$i>=2010;$i--){?>
<option value="<?php echo $i;?>"><?php echo $i;?></option>
<?php }?>
</select>
</div>
<div class="col-sm-4">
<p> </p>
<input type="submit" value="Show" name="submit" class="btn btn-primary">
</div>
</form>
</div>
</div>
<div class="row">
<div class="col-sm-2">
<label class="btn btn-success btn-sm">Month:<?php echo @$_REQUEST['month'];?></label>
</div>
<div class="col-sm-2"><label class="btn btn-info btn-sm">Year: <?php echo @$_REQUEST['year'];?></label></div>
</div>
<div class="row">
<div class="col-sm-12" style="overflow: scroll;">
<?php if($totDays>0){?>
<table class="table table-striped">
<tr>
<th>
Employee Name
</th>
<?php for($i=1;$i<=$totDays;$i++){?>
<th>
<?php echo $i;?>
</th>
<?php }?>
<?php foreach($attData as $attk=>$attv){
$punchin = $commonObj->getTimeOfDate($attData[$attk]['punchin']);
$punchout = $commonObj->getTimeOfDate($attData[$attk]['punchout']);
?>
<tr>
<th class="danger">
<?php echo $attv['name'];?>
</th>
<?php for($i=1;$i<=$totDays;$i++){?>
<?php if($commonObj->getDayOfDate($attData[$attk]['punch_time']) == $i){
echo "<td class='success' id='att_$i'>".$punchin.'-'.$punchout;?>
<table class="table table-responsive"style="display: none; position:relative;min-width:100px;max-width:200px; margin-top: -40px;" id="<?php echo "det_att_".$i;?>">
<tr>
<td>Total hours:</td>
<td><?php echo $commonObj->getHoursBetweenDates($attData[$attk]['punchin'],$attData[$attk]['punchout']);?>
</td></tr>
<tr>
<td>UID:</td>
<td><?php echo $attData[$attk]['rfid_uid'];?></td>
</tr>
</table>
<?php
}else {echo "<td class='info'>#na";}?>
</td>
<?php }?>
</tr>
<?php }?>
</tr>
</table>
<?php }?>
</div>
</div>
</div>
</body>
</html>
<script>
$(document).ready(function(){
$("td").hover(
function () {
var id = "#det_"+this.id;
$(id).css({"display":"block"});
},
function () {
var id = "#det_"+this.id;
$(id).css({"display":"none"});
//console.log(id);
//$(id).css("display","block");
});
});
</script>
Display of (ViewAttendance.php):
MY SQL TABLE :
hello, i have a table in a database that stores information on powerpoint presentations like so: id, title, filename, presenter, program, session I want to query the data so that all entries are grouped by session (which is a date) and each presentation is displayed under its respective session in a table like so: [session] (i want to display each session once) [title] - [program] (then i want to display this information for each presentation in each session) [presenter] [session] [title] - [program] [presenter] etc... i am thinking of using group_concat for this but am not sure exactly how to pull it off. any help is greatly appreciated. thank you! So I have an simple account centre up, and i'm wanting to display their 'Name' 'Username' and 'Email' as part of their details. But I have one problem... My code doesn't seem to be getting the data from my database... It may be messy to some people, just warning you! Code: [Select] <?php session_start(); if($_SESSION['username']){ $connect = mysql_connect("****","****","****") or die("Could not connect to database."); mysql_select_db("****") or die ("Could not find database!"); $sql = mysql_query("SELECT * FROM login"); $username = $rows['username']; $email = $rows['email']; $rows = mysql_fetch_assoc($sql); echo "<p>"; } else header("location: suggestion.html"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <link href="css/style.css" rel="stylesheet" type="text/css" /> <style type="text/css"> body { background-color: #CCC; } body,td,th { color: #000; font-family: "MS Serif", "New York", serif; } </style> </head> <body> <div id="wrap"> <!--Header--> <div id="header_member"> </div> <!--Log out and time--> <div id="info"> <div id="date"><script type="text/javascript"> var currentDate = new Date() var day = currentDate.getDate() var month = currentDate.getMonth() + 1 var year = currentDate.getFullYear() document.write("<b>" + day + "/" + month + "/" + year + "</b>") var currentTime = new Date() var hours = currentTime.getHours() var minutes = currentTime.getMinutes()</script> </div> <div id="time"><script type="text/javascript"> var suffix = "AM"; if (hours >= 12) { suffix = "PM"; hours = hours - 12; } if (hours == 0) { hours = 12; } if (minutes < 10) minutes = "0" + minutes document.write("<b>" + hours + ":" + minutes + " " + suffix + "</b>")</script> </div> </div> <div id="logout"><center><?php echo "<a href='logout.php'>Log out.</a>";?></center></div> <!--Main section which will contain everything else--> <div id="member_main"> <div id="member_right"><center> <p><img src="images/accountinf.png" width="175" height="30" /></p> <p>Name: <?php echo $username;?></p> <p>Email: <?php echo $email;?></p> </center> </div> <div id="member_top"><center><?php echo "Welcome, ".$_SESSION['username'];?></center></div> <div id="member_left" align="center"><img src="images/navigation.png" width="105" height="30" /><img src="images/home_member.png" width="105" height="30" /><img src="images/account.png" width="105" height="30" /></div> </div> <!--Footer--> <div id="footer_member"></div> </div> </body> </html> I have a field in my table that gets populated with a custom value from a subscription form, but when the data gets inserted into the table, it adds some text I do not want to output. The field is for the user's name, but when the form saves it, it saves the name, plus the text #2# (this is from a Wordpress plugin and I can't figure out how to remove the #2# when I insert the value there either). Is there a way to remove this #2# text when I display the field's value in MySQL and PHP? So i pull some records out of a mysql table and i want to display them in 5 even columns. I'm not entirely sure how to do the math & logic to accomplish this. The pull is simple $qry = "SELECT DIST_PART_NUM FROM $tablename"; $sql = mysql_query($qry) or die(mysql_error()); while($res = mysql_fetch_assoc($sql)) { // CREATE 5 even columns here. } so let's say i just retrieved 5,000 part numbers, i'd like to display then in a table of 5 columns with 1000 records per column. This is easy math, but i need the script to automatically figure out the #'s. Also the tricky part is that i dont want to display the part numbers like so 11111 22222 33333 44444 55555 66666 77777 88888 99999 00000 but rather 11111 44444 77777 22222 55555 88888 33333 66666 99999 00000 the remainder if there is one can go in the last column or whatever is easier. I'd tried googling this, but it's not easy to phrase what i'm looking for. Thanks for the help. PS: I'm not looking to copy and paste code, if possible please explain your way so that i can learn the logic. Hey guys have been trying to get this script to work for a while now, i am new to php and mysql so i am sure i am missing something simple. I have DB setup and need to pull data based on the key item code and get the following I want to get the fields item_code description allergy_statement useable_units region_availability order_lead_time ingredients for item_code 12-100 LITERALLY 12-100, no range, but like i said before i am really new to php and mysql. I have 1187 items that when a user clicks a link in search results it takes them to the product details page for that item code All that data is in my database just can't figure out how to get it out of the database. Is this even the right script to achieve that result. here is the code to get the data from database Code: [Select] <?php require_once('includes/mysql_connect_nfacts_ro.php'); $query = "SELECT item_code, description, allergy_statement, useable_units, region_availability, order_lead_time, ingredients " . "FROM products " . "WHERE item_code = '12-100' "; $resuts = mysql_query($query) or die(mysql_error()); ?> And need to display the data like so : Code: [Select] <td width="715" align="center" valign="top"> <h1>Product Details</h1> <h3>DISPLAY description HERE</h3> <table width="420" border="0"> <td class="ingreg"> </td> </table> <h5>Item Number</h5> <table width="420" border="0"> <tr> <td class="ingreg">DISPLAY ITEM_CODE HERE</td> </tr> </table> <h3>Ingredients:</h3> <table width="420" border="0"> <tr> <td class="ingreg">DISPLAY INGREDIENTS HERE</td> </tr> </table> <h4>Allergy Statement:</h4> <table width="420" border="0"> <tr> <td class="ingreg">DISPLAY Allergy Statement HERE</td> </tr> </table> <h4>Useable Units Per Package:</h4> <table width="420" border="0"> <tr> <td class="ingreg">DISPLAY Useable Units Per Package HERE</td> </tr> </table> <h4>Region Availability: </h4> <table width="420" border="0"> <tr> <td class="ingreg">&DISPLAY ITEM_CODE HERE</td> </tr> </table> <h4>Order Lead Time:</h4> <table width="420" border="0"> <tr> <td class="ingreg">&DISPLAY order lead time HERE</td> </tr> </table> <p> </p> <div align="right"></div></td> </tr> </table> how do i get data in database to display where i need it to? Can any one shine some light on this I am trying to display data from a database from a form entry here is the php <?php include('dbconnect.php'); @mysql_select_db($database) or die( "Unable to select database"); $query="SELECT * FROM child_info"; $result=mysql_query($query); $num=mysql_numrows($result); mysql_close(); echo "<b><center>Database Output</center></b><br><br>"; $i=0; while ($i < $num) { $field1-name=mysql_result($result,$i,"file_number"); $field2-name=mysql_result($result,$i,"first_name"); $field3-name=mysql_result($result,$i,"middle_name"); $field4-name=mysql_result($result,$i,"last_name"); $field5-name=mysql_result($result,$i,"birthdate"); $field6-name=mysql_result($result,$i,"gender"); $field7-name=mysql_result($result,$i,"features"); $field8-name=mysql_result($result,$i,"diagnosis"); $field9-name=mysql_result($result,$i,"description"); echo "<b>$field1-name $field2-name2</b><br>$field3-name<br>$field4-name<br>$field5-name<hr><br>"; $i++; } ?> here is the form I am using <form name="child_info" action="selectdata.php" method="post" id="child_info"> <table width="444" align="center" > <tr> <td> Search by Name: </td> <td> First Name:<input type="text" class="form-textbox " id="first_name" name="first_name" size="20" /><br /> Last Name:<input type="text" class="form-textbox " id="last_name" name="last_name" size="20" /> </td> </tr> <tr> <td width="208"> Choose Male or Female: </td> <td width="224"> <input type="radio" name="gender" value="male" /> Male <input type="radio" name="gender" value="Female" /> Female </td> </tr> <tr> <td> Choose age range: </td> <td> <select name="first_age" id="first_age"> <option value="00">From</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option value="13">13</option> <option value="14">14</option> <option value="15">15</option> <option value="16">16</option> <option value="17">17</option> <option value="18">18</option> </select> <select name="second_age" id="second_age"> <option value="00">To</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option value="13">13</option> <option value="14">14</option> <option value="15">15</option> <option value="16">16</option> <option value="17">17</option> <option value="18">18</option> </select> </td> </tr> <tr> <td> </td> <td> </td> </tr> <tr> <td> </td> <td> <div align="right"> <input type="submit" name="submit" id="submit" value="submit" /> <input type="reset" name="reset" id="reset" value="reset" /> </div></td> </tr> </table> </form> first problem is getting the form to use the php second problem is when i try to use the php alone is I get this error Parse error: syntax error, unexpected '=' in /home/fathersh/public_html/selectdata.php on line 17 17 is highlighted above in the php PHP Code Code: [Select] <?php $username=""; $password=""; $database=""; mysql_connect("","",""); @mysql_select_db($database) or die( "Unable to select database"); $query="SELECT * FROM tablename"; $result=mysql_query($query); $num=mysql_numrows($result); mysql_close(); echo "<b><center>Database Output</center></b><br><br>"; $i=0; while ($i < $num) { $field1-name=mysql_result($result,$i,"id"); $field2-name=mysql_result($result,$i,"Location"); $field3-name=mysql_result($result,$i,"Property type"); $field4-name=mysql_result($result,$i,"Number of bedrooms"); $field5-name=mysql_result($result,$i,"Purchase type"); $field6-name=mysql_result($result,$i,"Price range"); echo "<b>$field1-name $field2-name2</b><br>$field3-name<br>$field4-name<br>$field5-name<hr><br>"; $i++; } ?> HTML code for the form Code: [Select] <table id="tb1"> <tr> <td><p class="LOC">Location:</p></td> <td><div id="LC"> <form action="insert.php" method="post"> <select multiple="multiple" size="5" style="width: 150px;" > <option>Armley</option> <option>Chapel Allerton</option> <option>Harehills</option> <option>Headingley</option> <option>Hyde Park</option> <option>Moortown</option> <option>Roundhay</option> </select> </form> </div> </td> <td><p class="PT">Property type:</p></td> <td><div id="PS"> <form action="insert.php" method="post"> <select name="property type" style="width: 170px;"> <option value="none" selected="selected">Any</option> <option value="Houses">Houses</option> <option value="Flats / Apartments">Flats / Apartments</option> </select> </form> </div> </td><td> <div id="ptype"> <form action="insert.php" method="post"> <input type="radio" class="styled" name="ptype" value="forsale"/> For Sale <p class="increase"> <input type="radio" class="styled" name="ptype" value="forrent"/> To Rent </p> <p class="increase"> <input type="radio" class="styled" name="ptype" value="any"/> Any </p> </form> </div> </td> </tr> </table> <div id="table2"> <table id="NBtable"> <tr> <td><p class="NBS">Number of bedrooms:</p></td> <td><div id="NB"> <form action="insert.php" method="post"> <select name="number of bedrooms"> <option value="none" selected="selected">No Min</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> </select> to <select name="number of bedrooms"> <option value="none" selected="selected">No Max</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> </select> </form> </div> </td> <td><p class="PR">Price range:</p></td> <td><div id="PR"> <form action="insert.php" method="post"> <select name="price range"> <option value="none" selected="selected">No Min</option> <option value="50,000">50,000</option> <option value="60,000">60,000</option> <option value="70,000">70,000</option> <option value="80,000">80,000</option> <option value="90,000">90,000</option> <option value="100,000">100,000</option> <option value="110,000">110,000</option> <option value="120,000">120,000</option> <option value="130,000">130,000</option> <option value="140,000">140,000</option> <option value="150,000">150,000</option> <option value="160,000">160,000</option> <option value="170,000">170,000</option> <option value="180,000">180,000</option> <option value="190,000">190,000</option> <option value="200,000">200,000</option> <option value="210,000">210,000</option> <option value="220,000">220,000</option> <option value="230,000">230,000</option> <option value="240,000">240,000</option> <option value="250,000">250,000</option> <option value="260,000">260,000</option> <option value="270,000">270,000</option> <option value="280,000">280,000</option> <option value="290,000">290,000</option> <option value="300,000">300,000</option> <option value="310,000">310,000</option> <option value="320,000">320,000</option> <option value="330,000">330,000</option> <option value="340,000">340,000</option> <option value="350,000">350,000</option> </select> to <select name="price range"> <option value="none" selected="selected">No Max</option> <option value="50,000">50,000</option> <option value="60,000">60,000</option> <option value="70,000">70,000</option> <option value="80,000">80,000</option> <option value="90,000">90,000</option> <option value="100,000">100,000</option> <option value="110,000">110,000</option> <option value="120,000">120,000</option> <option value="130,000">130,000</option> <option value="140,000">140,000</option> <option value="150,000">150,000</option> <option value="160,000">160,000</option> <option value="170,000">170,000</option> <option value="180,000">180,000</option> <option value="190,000">190,000</option> <option value="200,000">200,000</option> <option value="210,000">210,000</option> <option value="220,000">220,000</option> <option value="230,000">230,000</option> <option value="240,000">240,000</option> <option value="250,000">250,000</option> <option value="260,000">260,000</option> <option value="270,000">270,000</option> <option value="280,000">280,000</option> <option value="290,000">290,000</option> <option value="300,000">300,000</option> <option value="310,000">310,000</option> <option value="320,000">320,000</option> <option value="330,000">330,000</option> <option value="340,000">340,000</option> <option value="350,000">350,000</option> </select> </form> </div> </td> </tr> </table> </div> <form id="submit" action=""> <input type="submit" value="search" /> </form> Hi all! I've been recently messing with PHP and MySQL to attempt to create a search function for my tables (too advanced, so I toned it down to learning to just display data from my table). Anyways, I'm watching a YouTube video on how to do it, and I'm copying his code exactly, but I'm still getting an error. Can anyone help? Thanks. Edit: Sorry, my error was snuggled down below the code. Anyways, my error is just my while echo appearing in and out of my tables on the page. My code:
<?php
//Make connection
mysql_connect('localhost', 'root', 'test');
// select db
mysql_select_db('testdatabase');
$sql="SELECT * FROM employees";
$records=mysql_query($sql);
?>
<html>
<head>
<title>Employee Data</title>
</head>
<body>
<table width="600" border="1" cellpadding="1" cellspacing="1">
<tr>
<th>ID</th>
<th>First name</th>
<th>Surname</th>
<th>Age</th>
</tr>
<?php
while($employees=mysql_fetch_assoc($records)){
echo "<tr>";
echo "<td>".$Employee['ID']."</td>";
echo "<td>".$Employee['First name']."</td>";
echo "<td>".$Employee['Surname']."</td>";
echo "<td>".$Employee['Age']."</td>";
echo "</tr>";
}
// end while
?>
</table>
</body>
</html>
Edited by thwikehu1990, 19 January 2015 - 01:33 PM. Ok... I need some help - I want to show a players balance in a game beside there name (Balance is in mysql database)I can do that but... - I also want to show if there online or offline at the same time( This is stored in a different database) I have the code which says whether they are online or offline <?PHP // Conect to the Mysql Server $connect = mysql_connect("localhost","scswccla_bukkit","********"); //connect to the database mysql_select_db("scswccla_bukkit"); //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 1"); //title echo "<font size='100'>NovaCraft Users</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='black'>|Online|<br><font color='green'>$users</font></font><br>"; endwhile; //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 0"); //title echo "<font color='black'>|Offline|</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='red'>$users</font><br>"; endwhile; ?> Here is the page: www.scswc.com/Offline_Users.php displaying that But I want to Create something like this: Nocvacraft Players |Online| Name:Player Balance:$20 |Offline| Name:Player Balance:$15 Here is what I have tried: <?PHP // Conect to the Mysql Server $connect = mysql_connect("localhost","scswccla_bukkit","**********"); //connect to the database mysql_select_db("scswccla_bukkit"); //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 1"); $query2 =mysql_query("SELECT * FROM iBalances WHERE player = $users"); //title echo "<font size='100'>NovaCraft Users</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query) $rows2 = mysql_fetch_array($query2)): $users = $rows['name']; $balance = $rows2['balance']; echo "<font color='black'>|Online|<br><font color='green'>Name:$usersBalance:$balance</font></font><br>"; endwhile; //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 0"); //title echo "<font color='black'>|Offline|</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='red'>$users</font><br>"; endwhile; ?> I know I am trying to use a variable before it is been set - but if I don't how I have tried this as well... <?PHP // Conect to the Mysql Server $connect = mysql_connect("localhost","scswccla_bukkit","**********"); //connect to the database mysql_select_db("scswccla_bukkit"); //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 1"); //title echo "<font size='100'>NovaCraft Users</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='black'>|Online|<br><font color='green'>Name:$users</font></font><br>"; endwhile; //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 0"); //title echo "<font color='black'>|Offline|</font><br>"; // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "<font color='red'>$users</font><br>"; endwhile; $query = mysql_query("SELECT * FROM iBalances WHERE player = $users"); WHILE($rows = mysql_fetch_array($query)): $balance = $rows['balance']; echo "<font color='red'>$users $balance</font><br>"; endwhile; // ?> Can you use variables in mysql_query()?Is that why it isn't working? This is my first php script so if I need to give you more information for you to help me just tell me Thanks Here is database pictures iBalances users_online Hi, I'm trying to joing two tables together, in the resulting PHP coding (See below) the issue I'm having the coding saying select the colour from the colour table where the model of car is the same as the model in the cars table. For example, if the car model is KA and in the table it is KA show the colours. I know this manual fix does the trick. [ $test = "KA"; $query_cols = "SELECT * FROM colours WHERE colours.model = '$test' "; ] But not the soultion any help would be much appericated thank you. [ include "connections/dbconnect.php"; $manfactures = "Ford"; $car_query = "SELECT * FROM cars WHERE make = '$manfactures'"; $car_result = mysql_query($car_query) or die ("Error in query: $car_query. ".mysql_error()); setlocale(LC_MONETARY, 'en_GB'); $fmt = '%i'; if (mysql_num_rows($car_result) > 0) { while ($car_row = @ mysql_fetch_array($car_result)) { $test = "KA"; $query_cols = "SELECT * FROM colours WHERE colours.model = cars.model"; $cols_result = mysql_query($query_cols) or die ("Error in query: $query_cols. ".mysql_error()); print " <table class='details'> <tr> <td rowspan='2'> <img src=\"". $car_row["image"] ."\" alt='" . $car_row["image_alt"] . "' /> </td> <td colspan='2'> <a href='" . $car_row["what_link"] . "'> " . $car_row["model"]." ".$car_row["model_details"] . " </a> </tr> <tr> <td> <p class='info'> RRP:<br/> What Price:<br/> Our Price:<br/> Savings of:<br/> Delivery Time: </p> </td> <td> <p class='info1'> "; echo money_format($fmt, $car_row["rrp"] ); print "<br/>"; echo money_format($fmt, $car_row["what_price"] ); print "<br/>"; echo money_format($fmt, $car_row["our_price"] ); $savings = $car_row["rrp"] - $car_row["our_price"]; print " <br/> <font color=\"red\">"; echo money_format($fmt, $savings ); print " </font><br/> " . $car_row["delivery_time"] . " </p> </td> </tr> <tr> <td> "; while ($cols_row = @ mysql_fetch_array($cols_result)) { ?> <a href='#' onmouseout='hideTooltip()' onmouseover='showTooltip(event,"<?php print "" . $cols_row["colour"] . ""; ?>");return false'> <?php print " <img src=\"". $cols_row["colour_img"] ."\" alt='" . $cols_row["colour_img_alt"] . "' /> "; } print " </td> </tr> "; } } else { echo "Aids!"; } print "</table>"; ?>] I have page1.php which has a post form and page2.php which display data/results. I have a seperate php script file which queries a database. Having completed the query and assuming a result, I would end up with something like Code: [Select] while($result = mysql_fetch_assoc($query)) how do I get the data onto the display page. Looking at example approaches I found this using a go-between file Code: [Select] <?PHP include_once(process.php; process($_POST); display_results; ?> would display_results be a form of redirect? If not? Any help appreciated. Hello, When a user sends a message using my contact form, they will get a confirmation to the supplied email to confirm that the email has been recieved, one problem is, the auto-reply message displays "donotreply@website.com" at the bottom of it, here is some of my code: //AUTO-REPLY CLIENT CODE START $confirmation = $visitor_email; $consubject="Your message has been recieved"; $body2 = "Hello $name, \nThe below message has now been recieved.\n\n >> $user_message <<\n\nWe will reply to you shortly.\n\nThank you,\n\nThe website Team.\n\n\nThis is an automated message, please do not reply to it.\n". $fromnoreply = 'donotreply@website.com'; //AUTO-REPLY CLIENT CODE END //TO WEBMAIL CODE START $to = $your_email; $subject="Contact form - $name"; $from = $visitor_email; $from = $your_email; $ip = isset($_SERVER['REMOTE_ADDR']) ? $_SERVER['REMOTE_ADDR'] : ''; $body = "A user $name submitted the contact form:\n". "Name: $name\n". "Email: $visitor_email \n". "Message: \n ". "$user_message\n". "IP: $ip\n"; //TO WEBMAIL CODE END //headers $headers = "From: $from \r\n"; $headers .= "Reply-To: $visitor_email \r\n"; $headers2 = "From: $fromnoreply \r\n"; $headers2 .= ""; // the important stuff!, yes definately! JAMES mail($to, $subject, $body,$headers); mail($confirmation, $consubject, $body2,$headers2); header('Location: ?sent'); //where shall i go once message is sent?? Possibly here. *wink* The above code automatically sends the below email to the client aswell as sending the clients message to me. Code: [Select] Hello Bob Smith, The below message has now been recieved. >> This is a test << We will reply to you shortly. Thank you, The website Team. This is an automated message, please do not reply to it. donotreply@website.com My objective is to remove the displayed email at the bottom of the message. Many thanks I am querying my database to show the visit statistics for a particular week and it shows the number of visits for the countries, but does not display the country name.
I have proved that the MySQL works by going into phpMyAdmin and pasting the query into SQL query tab, replacing the POST with 1, for week 1.
I can't see why it is not displying the country.
Here is the code:
<?php
include('connect_visits.php');
doDB7();
$WVisit_data="SELECT WeekNo15.WNo, WeekNo15.WCom, Countries.Country, Countries.CID, ctryvisits15.CVisits
FROM ctryvisits15
LEFT JOIN Countries
ON ctryvisits15.country = Countries.CID
LEFT JOIN WeekNo15
ON ctryvisits15.WNo = WeekNo15.WNo
WHERE ctryvisits15.WNo = '{$_POST['WeekNo']}'
ORDER BY ctryvisits15.CVisits DESC";
$WVisit_data_res = mysqli_query($mysqli, $WVisit_data) or die(mysqli_error($mysqli));
$display_block ="
<table width=\"20%\" cellpadding=\"3\" cellspacing=\"1\" border=\"1\" BGCOLOR=\"white\" >
<tr>
<th>Country</th>
<th>Visits</>
</tr>";
while ($WV_info = mysqli_fetch_array($WVisit_data_res)){
$Ctry = $WV_info['country'];
$Visits = $WV_info['CVisits'];
//add to display
$display_block .="
<tr>
<td width=\"10%\" valign=\"top\">".$Ctry."<br/></td>
<td width=\"5%\" valign=\"top\">".$Visits."<br/></td>
";
}
mysqli_free_result($WVisit_data_res);
mysqli_close($mysqli);
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<!--
Design by Free CSS Templates
http://www.freecsstemplates.org
Released for free under a Creative Commons Attribution 2.5 License
Name : Yosemite
Description: A two-column, fixed-width design with dark color scheme.
Version : 1.0
Released : 20091106
-->
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta name="keywords" content="" />
<meta name="description" content="" />
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>1066 Cards 4U - Stats for country</title>
<link href="style.css" rel="stylesheet" type="text/css" media="screen" />
</head>
<body>
<div id="wrapper">
<div id="menu">
<ul>
<li class="current_page_item"><a href="index.php">Home</a></li>
<li><a href="Links.html">Links</a></li>
<li><a href="Verse_Menu.html">Verses</a></li>
<li><a href="Techniques.html">Techniques</a></li>
<li><a href="blog.php">Blog</a></li>
<li><a href="Gallery.html">Gallery</a></li>
<li><a href="contact.html">Contact</a></li>
<li><a href="AboutUs.html">About Us</a></li>
<li><a href="stats1.html">Stats</a></li>
</ul>
</div><!-- end #menu -->
<div id="header">
<div id="logo">
<h1><a href="http://www.1066cards4u.co.uk">1066 Cards 4U</a></h1>
</div><!-- end #wrapper -->
</div><!-- end #header -->
<div id="page">
<div id="page-bgtop">
<div id="page-bgbtm">
<div id="content">
<h3>Statistics for Week Commencing <? echo $WkCom; ?> in 2015</h3>
<div id="table">
<?php echo $display_block; ?></div>
</div><!-- end #content -->
</body>
</html>
Can you help please?
Edited by rocky48, 07 January 2015 - 07:33 AM. Hello, I have a simple feedback form which asks for name, location and a simple comment about the business. I have inserted data into the database successfully but I'm not sure on the best way to display the data from the table on the same page as the form (after redirection). Here is my code: FORM: Code: [Select] <form id="feedback" name="feedback" action="php/phpcustom.php" method="POST"> <fieldset> <legend>Gardenable.com Feedback</legend> <p><label for="fname">Name:</label><input type="text" size="30" maxlength="40" id="fname" name="fname" /></p> <p><label for="loc">Location:</label><input type="text" size="30" maxlength="40" id="loc" name="loc" /></p> <p><label for="com">Comments:</label><textarea cols="40" rows="6" maxlength="300" id="com" name="com"></textarea></p> <p><input type="submit" name="send" id="submitbutton" value="Submit" /><input type="reset" name="reset" value="Reset" /></p> </fieldset> </form> ACTION SCRIPT on submit: Code: [Select] <?php session_start(); $dbhandle = mysql_connect('localhost', 'root', '') or die("Unable to connect to MySQL"); $selected = mysql_select_db("commentdatabase",$dbhandle) or die("Could not select the database"); $name = $_POST['fname']; $loc = $_POST['loc']; $com = $_POST['com']; $sql = "INSERT INTO userinfo (name, location, comment) VALUES ('{$name}','{$loc}','{$com}')"; if(!mysql_query($sql, $dbhandle)) { die('Error: ' . mysql_error()); } $dbselect = "SELECT * FROM userinfo"; if(!mysql_query($dbselect, $dbhandle)) { die('Error: ' . mysql_error()); } header('Location: ../contact.htm'); mysql_close(); ?> //This is underneath the FORM CODE: Code: [Select] <div id="feedbackDiv"> <?php $dbhandle = mysql_connect('localhost', 'root', '') or die("Unable to connect to MySQL"); $selected = mysql_select_db("commentdatabase",$dbhandle) or die("Could not select the database"); $result = mysql_query("SELECT * FROM userinfo"); while ($row = mysql_fetch_array($result)) { echo "ID:".$row{'name'}." Name:".$row{'location'}."Year: ". $row{'comment'}."<br />"; } ?> </div> It is displaying a tiny part of php code rather than the returned data. This is what i being displayed: "; } ?> The data is inserting correctly but i'm unsure as to whether or not I need to pass the values in the url string in the header function? Thank you for any information you can provide me. Regards, BuNgLe Hey, I have written a script for a very simple PHP wall and comment system. This works fine but the problem I have is displaying the comments. It seems to display the comments associated with the post as well as the comments on the posts above it. I have checked the database and the post ID's are correct. Here is my code: Code: [Select] <?php $wallDisplay = ''; $commentDisplay = ''; $wallDisplaySql = mysql_query("SELECT * FROM wall WHERE to_id='$id' ORDER BY datetime DESC") or die (mysql_error()); while($row = mysql_fetch_array($wallDisplaySql)){ $wallPostId = $row["id"]; $to_id = $row["to_id"]; $from_id = $row["from_id"]; $message = $row["message"]; $dateTime = $row["datetime"]; $getFromData = mysql_query("SELECT username FROM members WHERE id='$from_id'") or die (mysql_error()); while($row2 = mysql_fetch_array($getFromData)){ $wallUsername = $row2['username']; } $displayComments = mysql_query("SELECT * FROM wallComments WHERE wallPostId='$wallPostId' ORDER BY datetime DESC"); while($row3 = mysql_fetch_array($displayComments)){ $wallComment = $row3['comment']; $commentFrom = $row3['from_id']; $commentDate = $row3['datetime']; $getUsername = mysql_query("SELECT username FROM members WHERE id='$commentFrom'"); while($row4 = mysql_fetch_array($getUsername)){ $commentUsername = $row4['username']; } $cheersCheck_pic = "members/$commentFrom/pic1.jpg"; $cheersDefault_pic = "members/0/defaultMemberPic.jpg"; if (file_exists($cheersCheck_pic)) { $cheers_pic = "<img src=\"$cheersCheck_pic?$cacheBuster\" width=\"40px\" />"; } else { $cheers_pic = "<img src=\"$cheersDefault_pic\" width=\"40px\" />"; } $commentDisplay .= '<table width="500px" align="right" cellpadding="4" bgcolor="#FFF"> <tr> <td width="10%" bgcolor="#FFFFFF"><a href="member_profile.php?id=' . $commentFrom . '">' . $cheers_pic . '</a><br /> </td> <td width="90%" bgcolor="#DBE4FD"><a href="member_profile.php?id=' . $commentFrom . '"><span class="blackText">' . $commentUsername . '</span></a> • <span class="blackTetx">' . $commentDate . '<br /><font size="1"></font></span><br /> <span class="blackText">' . $wallComment . '</span></td> </tr> </table>'; } $cheersCheck_pic = "members/$from_id/pic1.jpg"; $cheersDefault_pic = "members/0/defaultMemberPic.jpg"; if (file_exists($cheersCheck_pic)) { $cheers_pic = "<img src=\"$cheersCheck_pic?$cacheBuster\" width=\"40px\" />"; } else { $cheers_pic = "<img src=\"$cheersDefault_pic\" width=\"40px\" />"; } $wallDisplay .= '<table width="100%" align="center" cellpadding="4" bgcolor="#FFF"> <tr> <td width="7%" bgcolor="#FFFFFF"><a href="member_profile.php?id=' . $from_id . '">' . $cheers_pic . '</a><br /> </td> <td width="93%" bgcolor="#DBE4FD"><a href="member_profile.php?id=' . $from_id . '"><span class="blackText">' . $wallUsername . '</span></a> • <span class="blackTetx">' . $dateTime . '<br /><font size="1"></font></span><br /> <span class="blackText">' . $message . '</span></td> </tr> </table> <div id="commentList">' . $commentDisplay . '</div> <div id="comment" align="right"> <form id="comment" name="comment" method="post" action="member_profile.php?id=' .$id. '"> <textarea name="comment" id="comment" rows="1" cols="35"></textarea> <input type="hidden" name="wallPostId" id="wallPostId" value="'. $wallPostId .'" /> <input type="hidden" name="commentFrom" id="commentFrom" value="'. $_SESSION['id'] .'" /> <input type="submit" name="submitComment" id="submitComment" /> </form> </div><br /> '; } ?> I have been looking at it for ages but can think why this is happening. Thanks in advance for any help Hi i'm new to PHP/web development but not new to coding. I have some php code that I grabed from a template where I am selecting data from a file and having it diplay on the screen in a form. My $query = "select * from file where" statement works and bring the data back to the screen. However, I want the data to be returned in a textarea instead of a text field that is not big enough to display the 3 paragraph that i need to display. Please see code below, thsi code will return the data but the text box only returns the data in a line, I need the data to be returned in a textarea, so I can update it. I have looked for the correct syntex with no luck, please correct me. $row = mysql_fetch_array($result, MYSQL_ASSOC); $recordid = $row['recordid']; $homepage = $row['homepage']; echo "<h2>Update About Us Information</h2>\n"; echo "<form enctype=\"multipart/form-data\" action=\"admin.php\" method=\"post\">\n"; echo "<table width=\"100%\" cellpadding=\"1\" border=\"1\">\n"; echo "<tr><td><h3>Record ID</h3></td><td>$recordid</td></tr>\n"; echo "<tr><td><h3>Homepage</h3></td><td><input type=\"text\" size=\"100\" name=\"homepage\" value=\"$homepage\" /></td></tr>\n"; echo "</table>\n"; echo "<input type=\"submit\" name=\"button\" value=\"Update\">\n"; echo "<input type=\"submit\" name=\"button\" value=\"Delete Product\">\n"; echo "</form>\n"; |
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