PHP - Session Side-effect Error
Hi, I have this script which does what it is meant to do.
I have assigned session_id() to the variable $sid so I can use it when logging in to a users account, however I get this error. How do I get around this? Warning: Unknown: Your script possibly relies on a session side-effect which existed until PHP 4.2.3. Please be advised that the session extension does not consider global variables as a source of data, unless register_globals is enabled. You can disable this functionality and this warning by setting session.bug_compat_42 or session.bug_compat_warn to off, respectively. in Unknown on line 0 As this is going to be installed on many servers, I do not want to have to edit the php.ini file on each one so as not to get this error. Is there an alternative way to assign the session_id() as so $sid = session_id(); so this doesnt happen? Code: [Select] <div id="pageNav"> <div id="sectionLinks"> <a href="admin.php?cmd=manage1&username=admin">Manage</a> <a href="admin.php?cmd=dashboard&username=admin">Dashboard</a> <a href="admin.php?cmd=msgcenter&username=admin">Message Center </a> <a href="admin.php?cmd=manage&username=logins">Logins</a> </div> </div> <div id="content"> <div class="page"> <table width="100%" border="1" align="center"> <td bgcolor="#99FF66"><div align="center"><span class="style3">Login</span></div></td> <td bgcolor="#99FF66"><div align="center"><span class="style3">Name</span></div></td> <td bgcolor="#99FF66"><div align="center"><span class="style3">Registration Date </span></div></td> <td bgcolor="#99FF66"><div align="center"><span class="style3">Approved </span></div></td> <td bgcolor="#99FF66"><div align="center"><span class="style3">Reset Password </span></div></td> <td bgcolor="#99FF66"><div align="center"><span class="style3">Delete</span></div></td> </tr> <?php session_start(); $sid = session_id(); session_register('sid'); include_once("data/mysql.php"); $mysqlPassword = (base64_decode($mysqlpword)); $db = mysql_connect("$localhost", "$mysqlusername", "$mysqlPassword") or die ("Error connecting to database"); mysql_select_db("$dbname", $db) or die ("An error occured when connecting to database"); $result = mysql_query("SELECT * FROM members"); while($row = mysql_fetch_assoc($result)){ echo "<tr><td><a href=templates/members/home.php?username=".$row['username']."&sid=$sid>".$row['username']."</a></td> <td>".$row['firstname']." ".$row['lastname']."</td> <td>".$row['registration_date']."</td> <td><a href=admin.php?cmd=approval&username=".$row['username']."&approved=".$row['approved'].">".$row['approved']."</a></td> <td><a href=templates/members/changepw.php?username=".$row['username']."&sid=$sid>Change Password</a></td> <td><a href=templates/members/delete.php?username=".$row['username']."&sid=$sid>Delete</a></td></tr>"; } ?> </div> </div> </div> <tr> <td> </td> <td> </td> <td> </td> <td> </td> <td> </td> <td> </td> </tr> </table> </div> </div> </div> Many Thanks Paul Similar TutorialsHi, I have an old code from 2004 and I would like to update it to use new Session object. That means instead of session_register using the $_SESSION super global variable. The main reason for this change is that wheneve I logged out from the software I get: Warning: Unknown: Your script possibly relies on a session side-effect which existed until PHP 4.2.3. Please be advised that the session extension does not consider global variables as a source of data, unless register_globals is enabled. You can disable this functionality and this warning by setting session.bug_compat_42 or session.bug_compat_warn to off, respectively in Unknown on line 0 Spo I replace my old code: <?php session_name("MySite"); session_start(); reset ($_GET); session_register("ADMIN"); session_register("ADMINNAME"); session_register("MAIL") ; $USERCOOKIE_FOR_TRACKING = array(); //to get all session variables foreach ($_SESSION as $key => $value) { $value=stripslashes(trim($value)); $$key=$value; } ?> with this new code: <?php session_name("MySite"); session_start(); reset ($_GET); $_SESSION['ADMIN']=""; $_SESSION['ADMINNAME']=""; $_SESSION['MAIL']=""; $USERCOOKIE_FOR_TRACKING = array(); //to get all session variables foreach ($_SESSION as $key => $value) { $value=stripslashes(trim($value)); $$key=$value; } ?> BUT now I cannot login to the software any more. looks like I am doing something wrong here. please tell me how do I upgrade my code. Thank you. Hello I am using JSONP as dataType on my AJAX, but there's an incident that a Transaction was successfully complete but a PHP error text occured while trying pass the data.
E.g.
SMTP Error: Data not accepted. Unable to send Mail: SMTP Error: Data not accepted.<p>SMTP server error: Requested action aborted: This mail account has sent too many messages in a short amount of time. Please try later. </p> jQuery111001592713373247534_1407318091484({"result":11308,"err":"no"})There was an unexpected error happen, SMTP Error. So in my javascript jquery ajax the response will go to .error(function(xhr,status,error){ console.log(xhr); });But the thing here is that the transaction was successfully complete. So how do I tell the to the client side about the transaction process and the error happen? Hi all, Having a (probably basic) problem here, and as much as I have read about it, I still don't understand. I have a basic form in a page called book.php which upon submit calls sendmail.php to email me the details. Everything works as it should, including my current error handler, which is as follows. Code: [Select] elseif (empty($name) || empty($number) || empty($profexp) || empty($nonprofexp)) { header( "Expires: Mon, 20 Dec 1998 01:00:00 GMT" ); header( "Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT" ); header( "Cache-Control: no-cache, must-revalidate" ); header( "Pragma: no-cache" ); ?> <html> <head><title>Error</title></head> <body> Error <p> Oops, it appears you forgot to fill in all of your details. Please press the BACK button in your browser and try again. </p> </body> </html> <?php } This is fine, but what I would prefer is a seperate error for each user input section. So, for example, when the user does not enter anything in the $name feild and presses submit, the book.php page is displayed with the error message to the right of the text box. Any help would be appreciated. Thank you hey, i have this code: Code: [Select] <?php //-------------------------------- // Starting our session //-------------------------------- session_start(); //-------------------------------- // load database connection //-------------------------------- require "connect.php"; //-------------------------------- // Make some checks if the admin // Are loged in //-------------------------------- if ( ! isset($_SESSION['admin']) || ! isset($_SESSION['name']) ) { require "login.php"; die(); } if ( $_SESSION['admin'] != 1 || $_SESSION['name'] == "" ) { require "login.php"; die(); } if ( $core->input['act'] == logout ) { unset($_SESSION['admin']); unset($_SESSION['name']); session_destroy(); header('Location: index.php'); } ?> im trying to set a simple session, but i getting this error: Quote Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at /home/rangreiss/domains/greissdesign.com/public_html/articles/admin.php:1) in /home/rangreiss/domains/greissdesign.com/public_html/articles/admin.php on line 7 Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/rangreiss/domains/greissdesign.com/public_html/articles/admin.php:1) in /home/rangreiss/domains/greissdesign.com/public_html/articles/admin.php on line 7 but as you can see i put the session start in the top of the file... any ideas? Thanks! It is my understanding that <?php session_start (); ?> must go on the very first line otherwise "it won't work." But mine still isn't working, and I'm not sure why. These errors were returned EVEN AFTER I deleted everything in index.php except <? session_start (); ?>.... Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at /home/xxx/public_html/xxx/xxx/index.php:1) in /home/xxx/public_html/xxx/xxx/index.php on line 1 Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/xxx/public_html/xxx/xxx/index.php:1) in /home/xxx/public_html/xxx/xxx/index.php on line 1 Hi, i've got a strange problem: i get this errors: Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at e:\Internet\pmtopagents\test.php:1) in e:\Internet\pmtopagents\test.php on line 3 Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at e:\Internet\pmtopagents\test.php:1) in e:\Internet\pmtopagents\test.php on line 3 but in my test.php is nothing else than: <?php session_start(); ?> there is no space in front of <?php where could be the error? best hi all, I have a form that pass some $_POST values to a page that sets a session like this: session_start(); $_SESSION['TESTE'] = array ($_POST['sexo'],$_POST['nome'],$_POST['senha'],$_POST['senha2'],$_POST['login']); header ("Location: dddl.php"); Then the dddl.php should print the values on this line: print_r ($_SESSION['TESTE']) ; But when i run the application the dddl.php page returns this error: Notice: Undefined variable: _SESSION in C:\Users\Danilo\wamp\www\CNTur\dddl.php on line 2 Why it's not setting or why can't I reach the values? When I run the following code on the same page the session values are returned correctly: session_start(); $_SESSION['TESTE'] = array ($_POST['sexo'],$_POST['nome'],$_POST['senha'],$_POST['senha2'],$_POST['login']); print_r ($_SESSION['TESTE']) ; Thankx Danilo Jr. I’m trying to write a post-panel where the user can see the preview of his post to the right of the text area he’s writing into. I tried the following into a file called writepost.php : <?php $text=(isset($_GET['message']))?$_GET['message']:''; $formatted_text=nl2br(stripslashes(htmlspecialchars($text))); echo '<form method="post" action="proceedtopost.php?>'. '<table>'. '<td style width="50%"><tr>'. '<fieldset> Write your post here : <br> <textarea cols="50" rows="12" '. 'id="message" name="message">'.$text.'</textarea>'. '</fieldset> <p> '. '<input type="submit" name="submit" formaction="writepost.php" value="Preview" /> '. '<input type="submit" name="submit" value="Sent" /> '. '</p>'. '</td>'. '<td>'. '<fieldset> Your post will appear as follows :<br><p> '. $formatted_text. '</fieldset>'. '</td></tr>'. '</table>'. '</form>';There are several things wrong with this code : 1) When the user hits the "Preview" button, I expect writepost.php to be reloaded (this is what happens), and the current content of the textarea to be stored in $_GET['message'] (this is not what happens). 2) Why does my browser output the preview part under the text area (or in other words outputs the HTML table as a single column of two cells), when I insist in my HTML code for the table to be displayed as a single row ? I have a web portal which is scripted using client side scripting language i.e HTML. I want to create a login page in .php and want the other pages to be in .hmtl. Can i do so? I want to do this because i want the login password to be stored in a database. Also I want the password to get encrypted (by either MD5 javascript or OpenSSL ) when user enters it inside the login form. I cannot create the entire portal in php because my portal makes use of C code. And php doesn't have an interface with C language. Can a user get directed to a .html page after a secure login from login.php page ? My main aim is to secure the access to my web portal using a password. I tried to authenticate the login using javascript where the password was stored in an array. But i feel any one having moderate knowledge can easily break that password. Any help would be greatly appreciated!! I don't know how to solve this error;
Parse error: syntax error, unexpected '$db' (T_VARIABLE)
code:
SO I have been developing a log in system and wanted to make my own simple CAPTCHA. I found one on the internet and ported the code across to get started and see how someone had made it. The issue I am having is that the dynamically generated image that I have created it seems is one step ahead of the session variable (the string is generated and then saved into session - then generates the image). But when i echo back the session it is always one step behind the actual image... Anyway here is my code and ask away please
<?php require('includes/util.inc.php'); $form = ' <form action="register.php" method="post"> <p>username <input type="text" name="username" id="usrinp"></p> <p>email <input type="text" name="email" id="emainp"></p> <p>password <input type="password" name="password1" id="psw1inp"></p> <p>re-enter password <input type="password" name="password2" id="psw2inp"></p> <p><img src="captcha.php"/></p> <p>captcha <input type="text" name="captcha" id="capinp"></p> <p><input type="submit" value="Register" id="subinp"></p> </form> '; if(isset($_SESSION['captcha'])) { echo $_SESSION['captcha']; } if ($_SERVER['REQUEST_METHOD'] == 'POST' && !empty($_POST['username']) && !empty($_POST['email'])) { if($_POST['captcha'] == $_SESSION['captcha']) { $username = $_POST['username']; $email = $_POST['email']; $password = SHA1($_POST['password1']); $password = SHA1($_POST['password2']); $q = 'SELECT username FROM users WHERE username = :username'; $stmt = $pdo->prepare($q); $stmt->bindParam(':username', $username); $stmt->execute(); if($stmt->rowCount() > 0) { echo "<pre>This username has already been taken</pre>"; } else { $qi = 'INSERT INTO users ( username, password, email ) VALUES ( :username, SHA1(:password), :email )'; $query = $pdo->prepare($qi); $result = $query->execute( array( ':username'=>$username, ':password'=>$password, ':email'=>$email ) ); if($result) { header("location:login.php"); exit; } else { echo '<pre>Error, please try again</pre>'; } } } } $pageTitle = 'Register'; include('includes/header.inc.php'); include('pages/register.html'); ?> <?php require('includes/util.inc.php'); $string = ''; for ($i = 0; $i < 5; $i++) { $string .= chr(rand(97, 122)); } $_SESSION['captcha'] = $string; $font_path = 'includes/fonts/'; $captcha_image = imagecreatetruecolor(150, 60); $text_color = imagecolorallocate($captcha_image, 0, 0, 0); $bg_color = imagecolorallocate($captcha_image, 255, 255, 255); imagefilledrectangle($captcha_image, 0, 0, 399, 99, $bg_color); imagettftext($captcha_image, 30, 0, 10, 40, $text_color, $font_path . "dashdot.ttf", $_SESSION['captcha']); header("Content-type: image/png"); imagepng($captcha_image); ?> <?php session_start(); function class_loader($class) { require 'classes/' . $class . '.class' . '.php'; } spl_autoload_register('class_loader'); $user = (isset($_SESSION['user'])) ? $_SESSION['user'] : null; $cat = (isset($_SESSION['cat'])) ? $_SESSION['cat'] : null; try { $pdo = new PDO('mysql:dbname=phpcat; host=localhost', 'root', ''); } catch (PDOException $e) { $pageTitle = 'Error!'; include('header.inc.php'); include('../pages/error.html'); exit(); } need a little help guys! I use the script below to display profile images, trouble is it shows 1 on top of the other, and i need it to double up 2 profile images on top of 2 profile images ect any ideas how i can do this. require("./include/mysqldb.php"); $con = mysql_connect("$dbhost","$dbuser","$dbpass"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("$dbame", $con); $result = mysql_query("SELECT * FROM Search_profiles_up WHERE upgrade_one ='1' ORDER BY RAND() LIMIT 40"); print "<table width=\"293\" height=\"111\" border=\"0\"> <tr>\n"; while($row = mysql_fetch_array($result)) { print "<td width=\"142\"><img src=" . $row['search_small_image'] . " width=\"144\" height=\"169\" /></td>\n"; print " </tr>\n"; print " <tr> \n"; print "<td>" . $row['star'] . "</td>\n"; print " </tr>\n"; print " <tr>\n"; print "<td>" . $row['username_search'] . "</td>\n"; print " </tr>\n"; print " <tr> \n"; print "<td>" . $row['phone_search'] . "</td>\n"; print " </tr> \n"; } print "</table>"; mysql_close($con); ?> I am so glad someone told me about putting in the error_reporting ALL because I was not sure why my id for members was not picking up on the next pages. Can someone let me know how I can fix this I thought it automatically picks it up and sets it to private pages for each member. Notice: Undefined index: id in /home/ebermy5/public_html/login.php on line 25 <?php session_id(); session_start(); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Welcome</title> </head> <body> <?php /* Program: New_member.php * Desc: Displays the new member welcome page. Greets * member by name and gives a choice to enter * restricted section or go back to main page. */ error_reporting(E_ALL); ini_set("display_errors", 1); $firstname = ''; include('Connections/connect_to_mysql.php'); $result = mysql_query("SELECT firstname FROM `Members` WHERE id='{$_SESSION['id']}'"); $row = mysql_fetch_array($result); if ($firstname == ''){ //condition, is name equal to lower case firstname notice we use == and not = echo "Welcome, $firstname"; } else { //so incase the condition is not as expected echo "Sorry you are not $firstname"; } ?> <p>Your new Member accounts lets you enter the members only section of our web site. You'll find special discounts, a profile of matches, live advise from experts, and much more.</p> <p>Your new Member ID and password were emailed to you. Store them carefully for future use.</p> <div style="text-align: center"> <p style="margin-top: .5in; font-weight: bold"> Glad you could join us!</p> <form action="profile.php" method="post"> <input type="submit" value="Enter the Members Only Section"> </form> <form action="index.php" method="post"> <input type="submit" value="Go to eBermylove Main Page"> </form> </div> </body> </html> I am using the following code in PDO query $this->query('SELECT * FROM users WHERE id = :id'); // line 11 $this->bind(':id', $_SESSION['users']['id']); // line 12 it is working on local server, but on live server its giving some error or warning (i am not sure) PHP Notice: Undefined index: users in ... on line 12 but the query is still working correctly. Please guide me what should i do to stop getting this error or warning or notice. Thanks🙂 Is it a good practice to store error and success messages in SESSION?
Folder pages/giftCards ->index.php ->viewGiftCardCodes.php ->redeemGiftCard.php ->giftCards.php index.php <?php if(defined('script') === FALSE){ exit('Hacking attempt...'); } if(loginCheck($userInfo) === FALSE){ redirect('index.php?do=login&returnUrl='.$_SERVER['REQUEST_URI'], FALSE, TRUE); } if($configs['giftCardEnabled'] == 'no'){ alert('This page is currently disabled.', 'index.php?do=home'); } $action = isset($_GET['action']) ? $_GET['action'] : ''; switch($action){ case 'redeemGiftCard'; include 'pages/giftCards/redeemGiftCard.php'; break; case 'viewGiftCardCodes'; include 'pages/giftCards/viewGiftCardCodes.php'; break; default: include 'pages/giftCards/giftCards.php'; break; } ?>Default action giftCards REDEEM BUTTON ................. <?php $action = '<input type="button" value="Redeem" onclick="location.href=\'index.php?do=giftCards&action=redeemGiftCard&id='.$row['id'].'¤cy='.$row['currency'].'&amount='.$row['amount'].'&csrfKey='.$csrf->csrfKey().'&csrfToken='.$csrf->csrfToken().'\'">'; ?>................. Action redeemGiftCard ................. If success <?php $_SESSION['message']['1'] = 'You have successfully redeemed a gift card worth '.$row['currency'].$row['amount'].''; redirect('index.php?do=testPage1', FALSE, TRUE);// Page, Refresh, Exit // ?>If error <?php $_SESSION['message']['2'] = 'Database error. Please try again later!'; redirect('index.php?do=testPage1', FALSE, TRUE);// Page, Refresh, Exit // ?>................. Default action giftCards ................. <?php if(!empty($_SESSION['message']['1'])){ $success = $_SESSION['message']['1']; unset($_SESSION['message']); } if(!empty($_SESSION['message']['2'])){ $error = $_SESSION['message']['2']; unset($_SESSION['message']); } if(!empty($success)){ print success($success);// HTML and success var // } if(!empty($error)){ print error($error);// HTML and error var // } ?>................. Deprecated: Function session_register() is deprecated in /home/james/public_html/funshizzle.com/install/session.php on line 0 That is my error, I have no idea, What is it?
Hi! The file login.php and the config file containing the db connection are in the model folder and the login_view is in view folder. I am trying to make a login form am display some error messages to the user, but I don't get the error messages. Can you help me figure it out? PS: the connection to the db works fine! Thx! LOGIN.PHP <?php //start the session session_start(); foreach (glob("model/*.php") as $filename) { include $filename; } //form defaults $error["alert"]= ""; $error["user"]= ""; $error["pass"]= ""; $input["user"]= ""; $input["pass"]= ""; if(isset($_POST["submit"])) { //process form if($_POST["username"] == "" || $_POST["password"] == ""){ //display errors if($_POST["username"] == ""){$error["user"] = "required";} if($_POST["password"] == ""){$error["pass"] = "required";} $error["alert"] = "Please fill in the required fields"; //get the values for the username and password $input["user"]= $_POST["username"]; $input["pass"]= $_POST["password"]; include("../views/login_view.php"); } }else{ include("../views/login_view.php"); } LOGIN_VIEW.PHP <?php session_start(); foreach (glob("model/*.php") as $filename) { include $filename; } ?> <link href="//maxcdn.bootstrapcdn.com/bootstrap/4.0.0/css/bootstrap.min.css" rel="stylesheet" id="bootstrap-css"> <script src="//maxcdn.bootstrapcdn.com/bootstrap/4.0.0/js/bootstrap.min.js"></script> <script src="//cdnjs.cloudflare.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script> <!------ Include the above in your HEAD tag ----------> <!--author:starttemplate--> <!--reference site : starttemplate.com--> <!DOCTYPE html> <html lang="en"> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, initial-scale=1, shrink-to-fit=no"> <meta name="keywords" content="unique login form,leamug login form,boostrap login form,responsive login form,free css html login form,download login form"> <meta name="author" content="leamug"> <title>Unique Login Form | Bootstrap Templates</title> <link href="/styles/style.css" rel="stylesheet" id="style" type="text/css"> <!-- Bootstrap core Library --> <link href="//netdna.bootstrapcdn.com/bootstrap/3.2.0/css/bootstrap.min.css" rel="stylesheet" id="bootstrap-css"> <script src="//netdna.bootstrapcdn.com/bootstrap/3.2.0/js/bootstrap.min.js"></script> <script src="//code.jquery.com/jquery-1.11.1.min.js"></script> <!-- Google font --> <link href="https://fonts.googleapis.com/css?family=Dancing+Script" rel="stylesheet"> <!-- Font Awesome--> <link href="//maxcdn.bootstrapcdn.com/font-awesome/4.2.0/css/font-awesome.min.css" rel="stylesheet"> </head> <body> <!-- Page Content --> <div class="container"> <div class="row"> <div class="col-md-offset-5 col-md-4 text-center"> <h1 class='text-white'>Login Form</h1> <form action ="" method="POST"> <div class="form-login"></br> </br> <?php if($error["alert"] != ''){ echo "<div class='alert'>".$error["alert"]."</div>"; } ?> <div> <input type="text" name ="username" id="userName" class="form-control input-sm chat-input" placeholder="Username" value= "<?php echo $input['user'] ?>" required/> <?php echo $error['user'] ?> </div> </br></br> <input type="text" name ="password" id="userPassword" class="form-control input-sm chat-input" placeholder="Password" value= "<?php echo $input['password'] ?>" required/> <div class="error"> <?php echo $error['pass'] ?> </br></br> <div class="wrapper"> <input type="submit" class="btn btn-primary" value="submit"> </div> </div> </div> </form> </div> </div> </body> </html> Edited October 28, 2020 by Alexa I am getting an error message. But the program works Code: [Select] Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at C:\xampp\htdocs\Exam_Online\try.php:3) in C:\xampp\htdocs\Exam_Online\Staff_login_process.php on line 4 Wrong Username or Password my code is <Html> <?php //session_start(); include 'Staff_login_process.php'; MYSQL_CONNECT(localhost,'root','') OR DIE("Unable to connect to database"); @mysql_select_db(Examination) or die( "Unable to select database"); ?> <body> <form action="try1.php" method="post"> <?PHP $query=("SELECT * FROM User u, User_X_Subject us, Subject s WHERE u.Use_Name = '{$_SESSION['username']}' AND u.Use_ID= us.Use_ID AND s.Sub_ID=us.Sub_ID"); $result=mysql_query($query) or die ("Unable to Make the Query:" . mysql_error() ); echo "<select name=myselect>"; while($row=mysql_fetch_array($result)){ echo "<OPTION VALUE=".$row['Sub_ID'].">".$row['Sub_Name']."</OPTION>"; } echo "</select>"; ?> <input type="submit" value="submit"/> </form> </body> </html> Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/hedgehog/public_html/class/class.phpmailer.php:3005) in /home/hedgehog/public_html/admin/class/authenticate.class.php on line 15 I own a website, www.gpstudios.com Some time ago I started recieiving this error after posting comments on the playgame page/news page. Try posting comments yourself on this game: http://www.gpstudios.com/playgame.php?gameid=324 I have attached a picture of the error. Unfortunately, I have no idea when this bug appeared. It must have happened a while ago, but I never noticed. Anyone know how or why I am getting this bug? Because I'm unsure as to where/when the error occurred, I cannot supply the code. Sorry for the lack of details, but I'm hoping someone will understand this error a little better than me :S Thanks, -Tom |