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PHP - How To Send $_post Into Php File
I have tilbud.php file that has no output. Just receives data and adds them into MySQL table. Inside tilbud.php file I have JavaScript code that calls products.php. Product.php has the following code:
if(!isset($_POST['userid'])) { echo "<script type='text/javascript'>"; echo "window.location = 'index.php'"; echo "</script>"; exit; } So, I you call product.php without submitting $_POST['userid'] it redirects you into index.php. How to submit $_POST['userid'] into products php without using <form method='POST' action='product.php'> ? Similar TutorialsHi, I need to pass value of variable to another php file. I thought it is possible to do it as following: <form action="products.php"> <INPUT TYPE=hidden NAME='id' . VALUE='$id'> </form> But the problem is like that. The php file inside which I want to write above html code has not using <form> tag and it has no buttons. So how to initiate the transfer of variable into another php file? Is the above idea is not the good idea? Are there any another ways? Hi all, I've done a LOT of googling on this and found things that match what I need but nothing actual achieves what I need. I've used one php file before for doing multiple jobs (ie registration?step=2 / 3 etc), but I've boo-booed somewhere and it only works up until step 2, step 3 doesn't work. Here's what I have currently, it also leads me on to the next question. Code: [Select] <?php if(isset($_GET['step']) == 2) { ?> Please select the problem you are encountering. <a href="registration.php?step=3&console=<?php $_GET['console'] ?>&issue=1rrod"><img src="store/image/data/1rrod.gif" width="92" height="92" /></a> <?php } if (isset($_GET['step']) == 3) { ?> END <?php } else {?> Please select which type of Xbox 360 you have<br /> <a href="registration.php?step=2&console=xbox"><img src="images/xbox360.gif"></a> <a href="registration.php?step=2&console=xboxslim"><img src="images/xbox360e.gif"></a> <?php } ?> So, first step (which is bottom), lets you select which type of console it is - only two possible choices. That then passes that data to step 2, which is what issue the console is having. Now I've tried this with $_POST, as I would prefer to work that way. I've experimented with $_SESSION to try and pass everything I need, using code found elsewhere. But I just can't get it to pass from page to page and finally be able to use it to email in the final step. Final issue - I want to use images instead of buttons to be able to pass the variables. I've found that using hidden type input does work but I think this issue is related to the above one. Thanks! Jason I use WYSIWYG Web Builder. They have a file upload option in their form wizard. But I don't want to upload the file. I only want the name of the selected file sent on submit. No matter what I try it keeps trying to send the file, or just sends a blank when I remove the var I've looked though the code and this is the only parts I can find that have anything to do with the file upload. There will be more than one select B1-File, B2-File, B3-File etc.... I put one here. I only want to get the file name that is selected not the file to be sent to the server. If someone knows of an easier way to use a file select/browse button and get the file name only and wouldn't mind sharing it. Thanks I have been searching for a solution and have not been able to find the one. Thanks Bob Code: [Select] function ValidateForm1(theForm) { var extension = theForm.FileUpload2.value.substr(theForm.FileUpload2.value.lastIndexOf('.')); if ((extension.toLowerCase() != ".avi") && (extension.toLowerCase() != ".doc") && (extension.toLowerCase() != ".gif") && (extension.toLowerCase() != ".jpg") && (extension.toLowerCase() != ".mov") && (extension.toLowerCase() != ".mp3") && (extension.toLowerCase() != ".mp4") && (extension.toLowerCase() != ".mpeg") && (extension.toLowerCase() != ".pdf") && (extension.toLowerCase() != ".qt") && (extension.toLowerCase() != ".rtf") && (extension != "")) { alert("The \"FileUpload2\" field contains an unapproved filename."); theForm.FileUpload2.focus(); return false; } return true; } <body> <div id="container"> <input type="file" id="FileUpload2" class="Heading 5 <h5>" style="position:absolute;left:455px;top:592px;width:238px;height:22px;z-index:42" name="B1-File"> </form> </div> </body> </html> Hi Chaps, I'm working on a PHP script to mysqldump database to file. Using this as a base: http://www.edmondscommerce.co.uk/mysql/php-mysql-dump-script/, I've managed to strip it down to this: Code: [Select] set_time_limit(0); $mysql_host='localhost'; $mysql_database='database'; $mysql_username='username'; $mysql_password='pasword'; _mysql_test($mysql_host,$mysql_database, $mysql_username, $mysql_password); $print_form = 0; header('Content-type: text/plain'); header('Content-Disposition: attachment; filename="'.$mysql_database."_".date('Y-m-d').'.sql"'); $filename = $mysql_database."_".date('Y-m-d').'.sql'; _mysqldump($mysql_database); function _mysqldump($mysql_database) { $sql="show tables;"; $result= mysql_query($sql); if( $result) { while( $row= mysql_fetch_row($result)) { _mysqldump_table_structure($row[0]); _mysqldump_table_data($row[0]); } } else { echo "/* no tables in $mysql_database */\n"; } mysql_free_result($result); } function _mysqldump_table_structure($table) { echo "/* Table structure for table `$table` */\n"; echo "DROP TABLE IF EXISTS `$table`;\n\n"; $sql="show create table `$table`; "; $result=mysql_query($sql); if( $result) { if($row= mysql_fetch_assoc($result)) { echo $row['Create Table'].";\n\n"; } } mysql_free_result($result); } function _mysqldump_table_data($table) { $sql="select * from `$table`;"; $result=mysql_query($sql); if( $result) { $num_rows= mysql_num_rows($result); $num_fields= mysql_num_fields($result); if( $num_rows> 0) { echo "/* dumping data for table `$table` */\n"; $field_type=array(); $i=0; while( $i <$num_fields) { $meta= mysql_fetch_field($result, $i); array_push($field_type, $meta->type); $i++; } echo "insert into `$table` values\n"; $index=0; while( $row= mysql_fetch_row($result)) { echo "("; for( $i=0; $i <$num_fields; $i++) { if( is_null( $row[$i])) echo "null"; else { switch( $field_type[$i]) { case 'int': echo $row[$i]; break; case 'string': case 'blob' : default: echo "'".mysql_real_escape_string($row[$i])."'"; } } if( $i <$num_fields-1) echo ","; } echo ")"; if( $index <$num_rows-1) echo ","; else echo ";"; echo "\n"; $index++; } } } mysql_free_result($result); echo "\n"; } function _mysql_test($mysql_host,$mysql_database, $mysql_username, $mysql_password) { global $output_messages; $link = mysql_connect($mysql_host, $mysql_username, $mysql_password); if (!$link) { array_push($output_messages, 'Could not connect: ' . mysql_error()); } else { array_push ($output_messages,"Connected with MySQL server:$mysql_username@$mysql_host successfully"); $db_selected = mysql_select_db($mysql_database, $link); if (!$db_selected) { array_push ($output_messages,'Can\'t use $mysql_database : ' . mysql_error()); } else array_push ($output_messages,"Connected with MySQL database:$mysql_database successfully"); } } The problem is, I want the file to save to a specific network location, rather than the output being sent to headers. I've tried to play around with: Code: [Select] ob_start();.... $page = ob_get_contents(); ob_end_flush(); $fp = fopen("output.html","w"); fwrite($fp,$page); fclose($fp); But this outputs to the browser, then saves the file...I would like to load the page, and have the script create and save the file where I want it (without the output in the browser, or prompt to save/download file). Note: I need something like this as I'm running PHP/MySQL on IIS, so can use shell/system/etc. Any help will be hi-5-tastic! Hi all, I am quite new to PHP and MySql. I know how to upload a file a and save the path in the DB, but now I need to send an automatic email to the user when a new invoice is added to his directory. Please help. Thanks This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=322125.0 I would like to store PDF file into mysql (this part works) and then send it as email attachment and it should be retrieved from mysql table. Here's the code I have for now, but what it gives me is 0bytes large PDF file Saving PDF to mysql (it works), because size of blob in mysql table is OK. $fp = fopen('generated.pdf', 'r'); $content = fread($fp,filesize('generated.pdf')); $content = addslashes($content); fclose($fp); $DB->Query('insert into pdf_files (pdf_file, name) values ("'.$content.'", "'.$name.'")'); And here's the mailing part <?php $query = "SELECT name, pdf_file FROM pdf_files $result = mysql_query($query) or die(mysql_error()); while ($row = mysql_fetch_array ( $result)) { $fileContent =$row['pdf_file']; $fileName=$row['name']; } $fileatt = $fileContent; // getting file $fileatt_type ="application/pdf"; //type of file $fileatt_name = "attachment.pdf"; // name $fileatt_size = $fileSize; $email_from = "dont@have.it"; // mail from $email_subject = "Testtt"; // subject $email_message = "Testtt.<br>"; $email_message .= "Testtt.<br>"; // Message $email_to = $mail_user; // users mail $headers = "From: ".$email_from; $file = fopen($fileatt,'rb'); $data = fread($file,filesize($fileatt)); fclose($file); $semi_rand = md5(time()); $mime_boundary = "==Multipart_Boundary_x{$semi_rand}x"; $headers .= "\nMIME-Version: 1.0\n" . "Content-Type: multipart/mixed;\n" . " boundary=\"{$mime_boundary}\""; $email_message .= "Testtt.\n\n" . "--{$mime_boundary}\n" . "Content-Type:text/html; charset=\"iso-8859-1\"\n" . "Content-Transfer-Encoding: 7bit\n\n" . $email_message .= "\n\n"; $data = chunk_split(base64_encode($data)); $email_message .= "--{$mime_boundary}\n" . "Content-Type: {$fileatt_type};\n" . " name=\"{$fileatt_name}\"\n" . //"Content-Disposition: attachment;\n" . //" filename=\"{$fileatt_name}\"\n" . "Content-Transfer-Encoding: base64\n\n" . $data .= "\n\n" . "--{$mime_boundary}--\n"; $ok = @mail($email_to, $email_subject, $email_message, $headers); if($ok) { echo "<font face=verdana size=2><center>Mail was sent</center>"; } else { die("Error!"); } ?> I am working on a phpmailer script that sends an order confirmation email to the customer AND the client at the same time. If I have the customer email and client email set both to the originating domain's email addresses (myname@myserver.com), then it sends fine. However, if I try to send to an outside mail server (eg. someone@gmail.com), I get the following errors: Code: [Select] SMTP -> FROM SERVER:220 myserver.com ESMTP Exim 4.63 Sat, 18 Sep 2010 15:08:21 -0700 SMTP -> FROM SERVER: 250 myserver.com Hello localhost [127.0.0.1] 250-SIZE 52428800 250-PIPELINING 250-AUTH LOGIN PLAIN 250-STARTTLS 250 HELP SMTP -> FROM SERVER:250 OK SMTP -> FROM SERVER:250 Accepted SMTP -> FROM SERVER: SMTP -> ERROR: RCPT not accepted from server: SMTP Error: The following recipients failed: someone@gmail.com Message could not be sent. Mailer Error: SMTP Error: The following recipients failed: someone@gmail.com SMTP server error: I'm not sure what's going on here. Any SMTP or phpmailer geniuses here that can shed some light on what needs to happen here for this to send to any address? Hi, I'm trying to setup a quick PHP script that will grab the email from the url (see below) and after inserting into MySQL db - which is working fine - the script will complete two additional tasks: 1. send that same captured email out to a external db as in shown via http://domain1.com/insert.php?email=$lead (example), but then send to a DIFFERENT source - the originator of the lead - a portback acknowledgement using Header (sending the status and email to http://domain2.com/check.php?e=$lead&s=$status for their records). See the code below: ------------------------- Code: [Select] $lead = $_REQUEST['e_mail']; // will grab email from posted url string and assign to local variable $result = mysql_query($command); // this is just to execute the MySQL insert which works just fine but included here to explain validation below // Create API Call string to insert lead into iContact folder $requestURL = "http://domain1.com/insert.php?email=$lead"; // Execute API Call to CAKE $xml = simplexml_load_file($requestURL) or die("feed not loading"); if ($result) { $status = 1; // mark lead as sucess // send postback on lead status header("Location: http://domain2.com/check.php?e=$lead&s=$status"); } -------- Problem: I'm getting all sorts of errors with the simplexml_load_file() function and can't figure out why it won't work. Any input appreciated as this the only way I know how to pass the lead onward and then inform/update the other party of receipt of information. thanks! Hello, My script here is not sending POST vars from form to script. I can't figure it out. Form: Code: [Select] <form action="train2.php" method="POST"> <tr> <td colspan="4"><center><img src="pic/toppage16.gif" /></center></td> </tr> <TR> <TD><FONT COLOR="white">Reassign Miners</FONT></TD> <TD align=right><FONT COLOR="white">0 Naquadah</FONT></TD> <TD align=middle><FONT COLOR="white"><INPUT size="6" maxlength="8" value="0" name="miner>"</FONT></TD> </TR> <TR> <TD><FONT COLOR="white">Reassign Normal Attackers</FONT></TD> <TD align=right><FONT COLOR="white">0 Naquadah</FONT></TD> <TD align=middle><FONT COLOR="white"><INPUT size="6" maxlength="8" value="0" name="atsold"></FONT></TD> </TR> <TR> <TD><FONT COLOR="white">Reassign Normal Defenders</FONT></TD> <TD align=right><FONT COLOR="white">0 Naquadah</FONT></TD> <TD align=middle><FONT COLOR="white"><INPUT size=6 maxlength=8 value=0 name="defsold"></FONT></TD> </TR> <TR> <TD><FONT COLOR="white">Reassign Covert Agents</FONT></TD> <TD align=right><FONT COLOR="white">0 Naquadah</FONT></TD> <TD align=middle><FONT COLOR="white"><INPUT size=6 maxlength=8 value=0 name="spy"></FONT></TD> </TR> <TR> <TD><FONT COLOR="white">Anti Covert Agents</FONT></TD> <TD align=right><FONT COLOR="white">0 Naquadah</FONT></TD><TD align=middle><FONT COLOR="white"><INPUT size="6" maxlength=8 value=0 name="spykiller"></FONT></TD></TR> <TR> <TD align=middle colSpan=3><FONT COLOR="white"><INPUT type="submit" value="UnTrain!" name="untrain"> </FONT> </TD> </form> Code: [Select] <?php if(isset($_POST['untrain'])){ die($_POST['miner']); $miners = securevar($_POST['miner']); $nattackers = securevar($_POST['atsold']); $ndefenders = securevar($_POST['defsold']); $covertunits = securevar($_POST['spy']); $anticovertunits = securevar($_POST['spykiller']); $totalunits+=$miners; $totalunits+=$nattackers; $totalunits+=$ndefenders; $totalunits+=$covertunits; $totalunits+=$anticovertunits; if($totalunits>=1){ $q = "UPDATE `accountinfo_db` SET `miners_1` = `miners_1`-'$miner', `attackers_1` = `attackers_1`-'$natta', `defenders_1` = `defenders_1`-'$ndefe', `covertagents` = `covertagents`-'$cover', `anticovertagents` = `anticovertagents`+'$antic', `untrainedunits` = `untrainedunits`+'$totalunits' WHERE `id` = '$id'"; $res = mysql_query($q) or die(mysql_error()); if(isset($res)){ header("Location: train.php?strmsg=".$totalunits."Troops Untrained! For 0 Naquadah."); } }else{ header("Location: train.php?strmsg=You must enter atleast 1 troop to be un-trained!"); } } ?> when I die($_GET['miner'); nothing is outputed even tho I submited the data. Thank you, Brian Hi guys, I have a form using radio buttons. For the radio button, lets just say i have the id name as 'rim' + number eg; rim0, rim1, rim2.... When i post the data to another file to execute the data collected, naturally i would use the: Code: [Select] $rim0=$_POST['rim0']; $rim1=$_POST['rim1']; .... $rim10=$_POST['rim10']; i tried to shorten this process using this method: Code: [Select] //$q is part of the post variable. for($x = 0; $x < count($q); $x++){ $rim[]=$_POST['"rim"."$x"']; } But i get this error Code: [Select] Notice: Undefined index: "rim"."$x" in D:\Apache Software Foundation\Apache2.2\htdocs\.....\#####.php on line 20 Notice: Undefined index: "rim"."$x" in D:\Apache Software Foundation\Apache2.2\htdocs\.....\#####.php on line 20 Notice: Undefined index: "rim"."$x" in D:\Apache Software Foundation\Apache2.2\htdocs\.....\#####.php on line 20 Notice: Undefined index: "rim"."$x" in D:\Apache Software Foundation\Apache2.2\htdocs\.....\#####.php on line 20 Notice: Undefined index: "rim"."$x" in D:\Apache Software Foundation\Apache2.2\htdocs\.....\#####.php on line 20 Notice: Undefined index: "rim"."$x" in D:\Apache Software Foundation\Apache2.2\htdocs\.....\#####.php on line 20 Notice: Undefined index: "rim"."$x" in D:\Apache Software Foundation\Apache2.2\htdocs\.....\#####.php on line 20 Notice: Undefined index: "rim"."$x" in D:\Apache Software Foundation\Apache2.2\htdocs\.....\#####.php on line 20 Notice: Undefined index: "rim"."$x" in D:\Apache Software Foundation\Apache2.2\htdocs\.....\#####.php on line 20 Notice: Undefined index: "rim"."$x" in D:\Apache Software Foundation\Apache2.2\htdocs\.....\#####.php on line 20 Is there something wrong with my POST syntax? I use a form to sent date and use php to display it . However , the code only can working on one page. I can not turn the page. I do not why . Please tell me reason . Thank you very much. <select name="kind"> <option >kind</option> <option value="Copier Toner">Copier Toner</option> <option value="Laser Toner">Laser Toner</option> <option value="MICR Toner">MICR Toner</option> <option value="Inkjet">Inkjet</option> php code if (isset($_GET["page"])) { $page = $_GET["page"]; } else { $page=1; }; $start_from = ($page-1) * 18; $select="select * from $chun where brand = '$_POST[brand]' or sort ='$_POST[kind]' or type='$_POST[type]' LIMIT $start_from, 18"; $result2=mysql_query($select, $connection) or die (mysql_error()); <?php $sql = "select count(*) from $chun where brand = '$_POST[brand]' or sort='$_POST[kind]' or type='$_POST[type]' "; $rs_result = mysql_query($sql,$connection); $row = mysql_fetch_row($rs_result); $total_records = $row[0]; $total_pages = ceil($total_records / 18); for ($i=1; $i<=$total_pages; $i++) { ?> <div class="trunpage"><a href='table2.php?page=<?php echo "$i" ; ?>&id=<?php echo "$_POST[brand]";?>&cd=<?php echo "$_POST[kind]";?>&td=<?php echo "$_POST[type]";?>' ><?php echo "$i" ; ?></a> </div> The first page is working fine. The second page I get error message. Undefined index: brand in C:\wamp\www\php1000\table2.php on line 234 hey guys I know this is html but I'm using the php $_POST to grab the information the user chooses, i can't figure out though how to grab the info i'm looking for in this select option form if they choose PasswordCracker v3.0 what is it i'm looking to set my $_post['']; to? <FORM action="buy.php" method="POST"> <select name="passwordcrakers"> <option value="v2.0">PasswordCracker V2.0</option> <option value="v3.0">PasswordCracker V3.0</option> <option value="v4.0">PasswordCracker V4.0</option> <option value="v5.0">PasswordCracker V5.0</option> <option value="v6.0">PasswordCracker V6.0</option> <option value="v7.0">PasswordCracker V7.0</option> <option value="v8.0">PasswordCracker V8.0</option> <option value="v9.0">PasswordCracker V9.0</option> <option value="v10">PasswordCracker V10</option> </select><br /> <input type="submit" value="Buy" name="submit" /> </FORM> Hi guys, running through this tutorial at the moment: http://www.tizag.com/phpT/forms.php I seem to keep having problems with the $_POST variable. Is that obsolete syntax now? Here's the part I get an error on: <html> <body> <?php $quantity=$_POST['quantity']; $item=$_POST['item']; echo "You ordered".$quantity."".$item.".<br/>."; echo "Thank you for ordering from Boombaby art supppplies!"; ?> </body> </html> Here's the error: ( ! ) Notice: Undefined index: quantity in C:\wamp\www\process.php on line 4 Call Stack # Time Memory Function Location 1 0.0009 363936 {main}( ) ..\process.php:0 ( ! ) Notice: Undefined index: item in C:\wamp\www\process.php on line 5 Call Stack # Time Memory Function Location 1 0.0009 363936 {main}( ) ..\process.php:0 You ordered. .Thank you for ordering from Boombaby art supppplies! Any help would be appreciated. I tried googling but everything didn't seem to answer my question or was too confusing. Thanks. ok am workin on this script its a points market for a text based game but my money is not taking the amount of the players i points on the market ... just say i post 10 points for $29.000.000 ... and when the player buys the points it takes the money from that user and give the user points but .... when the user buy the points it dont give the user the money it give $290 ?? not sure is its my SQL av post that to Code: [Select] <?php include 'header.php'; $_POST['buypoints'] = abs(intval($_POST['buypoints']));{ $result = mysql_query("SELECT * FROM `pointsmarket` WHERE `id`='".$_POST['points_id']."'"); $worked = mysql_fetch_array($result); $price = $worked['price']; $amount = $worked['amount']; $totalcost = $price * prettynum($_POST['amount']); $newpointsinmarket = $amount - prettynum($_POST['amount']); $user_points = new User($worked['owner']); if ($worked['owner'] == $user_class->id) { echo Message("You have taken ".$_POST['amount']." points off the market."); $newpoints = $user_class->points + $_POST['amount'];; $result = mysql_query("UPDATE `grpgusers` SET `points` = '".$newpoints."' WHERE `id`='".$user_class->id."'"); $user_class = new User($_SESSION['id']); if ($newpointsinmarket == 0){ $result = mysql_query("DELETE FROM `pointsmarket` WHERE `id`='".$worked['id']."'"); } else { $result = mysql_query("UPDATE `pointsmarket` SET `amount` = '".$newpointsinmarket."' WHERE `id`='".$worked['id']."'"); } include 'footer.php'; die(); } $_POST['amount'] = abs(intval($_POST['amount'])); $_POST['points_id'] = abs(intval($_POST['points_id']));{ } $_POST['amount'] = abs(intval($_POST['amount'])); $_POST['points_id'] = abs(intval($_POST['points_id']));{ } if ($totalcost > prettynum($user_class->money)){ echo Message("You don't have enough money."); } if($_POST['amount'] >= 1 && $_POST['amount'] <= $amount && $totalcost <= $user_class->money){ echo Message("You have bought ".$_POST['amount']." points for $".$totalcost); $newpoints = $user_class->points + $_POST['amount']; $newmoney = $user_class->money - $totalcost; $result = mysql_query("UPDATE `grpgusers` SET `money` = '".$newmoney."', `points` = '".$newpoints."' WHERE `id`='".$user_class->id."'"); $newmoney = $user_points->money + $totalcost; $result = mysql_query("UPDATE `grpgusers` SET `money` = '".$newmoney."' WHERE `id`='".$user_points->id."'"); $user_class = new User($_SESSION['id']); if ($newpointsinmarket == 0){ $result = mysql_query("DELETE FROM `pointsmarket` WHERE `id`='".$worked['id']."'"); } else { $result = mysql_query("UPDATE `pointsmarket` SET `amount` = '".$newpointsinmarket."' WHERE `id`='".$worked['id']."'"); } } } $_POST['addpoints'] = abs(intval($_POST['addpoints'])); $_POST['id'] = abs(intval($_POST['id']));{ } if($_POST['amount'] < 1){ } if($_POST['price'] < 1){ } if ($_POST['amount'] >= 1 && prettynum($_POST['amount']) <= $user_class->points && $_POST['price'] >= 1){ echo Message("You have added ".$_POST['amount']." points to the market a price of $".$_POST['price']." per point."); $result= mysql_query("INSERT INTO `pointsmarket` (owner, amount, price)"."VALUES ('$user_class->id', '$_POST[amount]', '$_POST[price]')"); $newpoints = $user_class->points - $_POST['amount']; $result = mysql_query("UPDATE `grpgusers` SET `points` = '".$newpoints."' WHERE `id`='".$user_class->id."'"); $user_class = new User($_SESSION['id']); } ?> <link href="style.css" rel="stylesheet" type="text/css" /> <tr><td class="contenthead">Point Market</td></tr> <tr><td align="center" class="contentcontent"> <p> </p> <p><strong>You need to be a Respected Warrior to add points to the market</strong><br> Use this form to add points to the points market.</p> <p><strong>Bank Account[<? echo prettynum($user_class->bank) ?>]</strong><strong></strong><br /> <strong><a href="pointmarket.php">[Refresh</a>]</strong></p> <form method='post'> <table align="center"> <tr> <td>Amount of points</td><td> <input name='amount' type='text' class="areatest" value='0' size='10' maxlength='20'></td> </tr> <tr> <td>Price per point</td><td>$<input name='price' type='text' class="areatest" value="0" size='10' maxlength='20'></td> <tr><td align="center" colspan="2"><input name='addpoints' type='submit' class="buttong" value='Add Points'></form></td> </tr></table> </td></tr> <tr><td class="contentcontent"> <?php $result = mysql_query("SELECT * FROM `pointsmarket` ORDER BY `price` DESC"); while($line = mysql_fetch_array($result, MYSQL_ASSOC)) { $user_points = new User($line['owner']); if ($user_points->id == $user_class->id){ $submittext = "Remove"; } else { $submittext = "Buy"; } echo "<form method='post'>"; echo $user_points->formattedname." - ".$line['amount']." points for ".prettynum($line['price'],1)." per point <input type='text' name='amount' size='3' maxlength='20' value='".prettynum($line['amount'])."'><input type='hidden' name='points_id' value='".$line['id']."'><input type='submit' name='buypoints' value='".$submittext."'></form><br>"; } ?> </td></tr> <?php include 'footer.php'; ?> SQL Code: [Select] CREATE TABLE IF NOT EXISTS `pointsmarket` ( `owner` int(10) NOT NULL default '0', `amount` text NOT NULL, `price` text NOT NULL, `id` int(10) NOT NULL auto_increment, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 ROW_FORMAT=DYNAMIC AUTO_INCREMENT=81 ; How do I post data when a user clicks a link? I know that for a submit button you just use the name attribute, but I'm not sure how to do it with a link. I want to link this two file but not working,
first file to make drop down option form Hey, I have a database with user info in it. I was wondering would it be possible to have a link post info to a page and then have that page display info relevant to the received info?... Link page: <a href="profile.php?name=<? print $_GET['Username'] ?>" method="post"><? $row['Username'] ?></a> Profile page: <?php $username = $_POST['Username']; $query = $query = mysql_query('SELECT * FROM users WHERE Username') ?> You are viewing: <? echo $username ?>'s profile. Email: <? echo $row['Email'] ?> I have predefined $row. Is it possible to do this way or would I have to use a different method?... Cheers Here's the result of my problem: Array ( [nav_create_title] => hel [nav_visible] => 1 [category_position] => 4 ) ( ! ) Notice: Undefined index: category_postion in C:\wamp\www\tryitandbuyit\includes\category_create_process.php on line 7 Call Stack # Time Memory Function Location 1 0.0010 370336 {main}( ) ..\category_create_process.php:0 Here's how I'm trying to assign and echo $_post. print_r($_POST); $category_pos = $_POST["category_postion"]; $nav_title=$_POST["nav_create_title"]; $nav_visible=$_POST["nav_visible"]; echo $nav_title; echo $category_pos; echo $nav_visible; As you can see, it prints the correct value and name from the array... why the heck can't I assign or echo it? Here is how I am sending it from the other page in a form (it used to be simple, but I've been trying every work around i can think of: <?php $result=mysql_query("SELECT * FROM category WHERE visible='1' ORDER BY position ASC"); $row=mysql_fetch_array($result); $positionID=$row['position']; $position=$row['position']; $selectname= "Select A Position:<br />"; $selectname .= "<select name="; $selectname .= "'category_position'"; $selectname .= ">"; echo $selectname; $rownumber=mysql_num_rows($result); $rownumber_temp=$rownumber+1; For($i=1; $i<=$rownumber_temp; $i++) { echo "<option value= $i>" . $i . "</option></br>"; } $selectname2 = "echo \"<br />\""; $selectname2 .= "echo \"<br />\""; $selectname2 .= "echo \"</select>"; echo $selectname2; |
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