PHP - Calling A Class With Several Variables

I have a PHP config file called config.php.

inside the file is simular to this:

Quote

<?php
class JConfig {
   var $offline = '0';
   var $editor = 'tinymce';
   var $list_limit = '20';
}
?>


From another file, i have included config.php, but how do I call $editor to get "tinymce"?

Thanks

I am calling my class constructor with the following code
class controller{
function _construct($name,$pass){
 session_start();
 get_model_class($name, $pass);
 echo "I\'m in controller";

}
} 
function get_model_class($username, $password){
$my_model = new  model();  
$my_model->check_users($username,$password);
}


$username = $_POST['username'];
$password = $_POST['password'];
echo "in controller.php";
$newUser = new controller($username,$password);

but it is not entering the constructor

I am working on a site that was made a while ago and on a custom page I am making I am needing to call up variables and my brain is too fried to think up the solution for this.  The standing code is this:

class site{
var $name = 'Site';
var $data = 'on';
{

What I need to do is callup the variables, such as $name, as simple as possible.  How would I do this?

can someone help me I am trying to call a class function using a varible.... example
say i go to index.php?page=contact i want to pull that class with out doing a switch statement can someone help me
Code: [Select]
<?php
$Site = page;
$Site->getPage($_GET['page']);
?>
Code: [Select]
<?php
class page extends site {

function getPage($page) {
return $this->$page;
}
function Contact() {
echo '<h2>Contact test</h2>';
echo '<form>

</form>';
}

}
?>

Hi

How do I turn this:
Code: [Select]
if($LCname=='Business_solutions'){
$newChild  = Business_solutions::find_by_id(1);
}

In to something like this:
Code: [Select]
$newChild  = $LCname::find_by_id(1);


I'm calling lots of class's, and want to make it more dynamic.
The 2nd example would be perfect, but that does not work.

Is there an alternative?

Thanks

I am calling an object from another class in the constructor of first class but when I call it in another function it does not access it's object. Here is the code.
Code: [Select]
<?php
/* This is controller.php used to control the flow of data between view.php and 
model.php. This file cotains all the controlling mechanism of the data 
It was created on 11th Feb 2011 By Narjis Fatima for an Open Source Project and
contains all the includes to the database etc.
*/
include ("view.php");
include ("functions.php");


$name = stripslashes($_GET['username']);
$email = stripslashes($_GET['email']);
//echo "in controller.php";
check_validate_input($name, $email);
$newUser = new controller($name, $email);
$action=$_GET['t'];
$newUser->display_view($action);


class controller
{
public $my_model;    //is an object of model class
public $user_info;//=array('id' , 'username' ,'role','email','interests','location', 'homepage');
    function __construct($name,$email)
    {
  
    $my_model = new model();
    $user_info =  $my_model->check_members($name,$email); echo "<pre>";
    print_r  ($user_info);

    }
    function __destruct()
    {
    }
    function display_view($token)
    {
    echo "In display function";
    echo "<pre>";
    print_r  ($user_info);
    if ($this->user_info == NULL)
    {
        if (($token=="register"))
        {
          show_registration_form();
        } 
        else{   
          show_mailing_form();  
        }
    }
    if ($this->user_info['role'] == "admin")
    {
         $myView = new view();
         $myView->view_admin_menu();
    }
     if ($this->user_info['role'] == "user")
    {
         $myView = new view();
         $myView->view_user_menu() ;
    }
    }//close of function display_view()
} 



/* name and email cominfg from index.php would be checked by the controoler class 
to be checked if it a vaild name and email. The database would be connected n the 
model.php*/
  
?>

The code for model.php is as follows
Code: [Select]
<?php
//This is model.php created on 10th Feb 2011  .It deals with daytabase connection
//
//By NArjis Fatima
//For the project of EDUForge an Open Source Software 
//include ("register.php");
class model{
public $dbh;
public $user_arr=array('username','password','email','location','interest','homepage');
//cunstructor of model class

//function to connect to database
function __construct(){
          try{
    $this->dbh = new PDO("mysql:host=localhost;dbname=phpfaqproject",'root','');
//echo "connected";
      }
  catch(PDOException $e){
  echo $e-> getMessage();
} 
}
public function check_members($username,$email)
{
   //get_connected();
   
   
   $sql = "SELECT * FROM account WHERE (username='" .$username ."' AND email='"
      .$email."')";
       $sth = $this->dbh->prepare($sql);
      $sth->execute();
  
    
    $result = $sth->fetch();
   /* echo('<pre>');        
    print_r($result);*/
    return ($result);
      
}
 public function insert_data($user_info)
 {
 //$user_info = $user_in;
 //$dbh;
 try{
$dbh = new PDO("mysql:host=localhost;dbname=phpfaqproject",'root','');
//echo "connected";
}
catch(PDOException $e){
echo $e-> getMessage();
} 
         $dbh->exec("INSERT INTO account (username, userpassword, email, role, location, interest, homepage)
       VALUES ('" .$user_info['username']."','".$user_info['password'] 
      ."','".$user_info['email']."', 'user','".$user_info['location']."','".$user_info['interests']
      ."','".$user_info['homepage']."')");
}
 
}
?>


Please somebody help me. I am really stuck.
I am also sending my attachment.

Hello im receiving the error code,  Quote

Parse error: syntax error, unexpected ';'on line 58

Code: [Select]
<?php
mysql_connect("","business",""); 
mysql_select_db("business") or die("Unable to select database"); 
$result = mysql_query("SELECT subtype FROM business WHERE type ='restaurant' ORDER BY name");
$number_of_results = mysql_num_rows($result);
$results_counter = 0;
if ($number_of_results != 0) 
{while ($array = mysql_fetch_array($result);)  //THIS IS LINE 58 IN MY CODE
$results_counter++;
if ($results_counter >= $number_of_results);
?>

Firstly do you know why I would get this error?
and secondly how do i call my results.  I basically want to return my results and then later on format them into lists.

I would also like each result to have a different variable name.

eg.

result1 = $result1
result 2 = $result2
result3 = $result3 etc.

any guidance much appreciated.  Im a bit lost.

Hi,

i'm new to php and am trying to call $variables in different in multiple hierarchy from one main variable file.

I have one main file called variables.php that contain a list of variables
<?php
$variable1 = 'root/main/';
$variable2 = 'welcome';
$variable3 = 'testing';
?>

a second file called file1.php in the same directory as the variables.php file
<?php
require 'varibles.php';
include $variable1 . 'testing.php'
?>

a third file called testing.php inside root/main/
<?php
echo $variable2;
include $varible1 . 'temp/abc.php';
?>

a fourth file called abc.php inside root/main/temp
<?php
echo $variable3;
?>

the problem is testing.php is able to echo $variable2 but abc.php is not able to echo $variable3...is there a limit to the level of files before it can't echo a variable?

Dear all ,

i am trying the following :

i have a class named ACCOUNT with many properties in .some of these properties are array , it is like this :
Code: [Select]
class ACCOUNT
{

    PRIVATE $DB_LINK;
    PRIVATE $COMP;
    PRIVATE $BRANCH;
    PRIVATE $CURRENCY;
    PRIVATE $GL;
    PRIVATE $CIF;
    PRIVATE $SL;
    PRIVATE $EXIST;
    PRIVATE $STATUS;
    private $ACCOUNT_NAME=ARRAY("LA"=>'',"LE"=>'',"SA"=>'',"SE"=>'');
    private $ACCOUNT_BALANCE =ARRAY('FC_YTD','CV_YTD','CV_BAL','YTD_BAL','BLOCKED_CV','BLOCKED_FC');
    private $CY_NAME=ARRAY("LA"=>'',"LE"=>'',"SA"=>'',"SE"=>'');
    private $ACCOUNT_NAME_USR=ARRAY("LA"=>'',"LE"=>'',"SA"=>'',"SE"=>'');
    private $LEDGER_NAME= ARRAY("LA"=>'',"LE"=>'');



i have created the following method to call any property

[code]    FUNCTION GET_SPECIFEC_ATT($ATT,$LANG)
    {
    $ATT=$ATT."['L$LANG']";
    ECHO $this->$ATT;

    }
but i am getting the below error :
Notice:  Undefined property: ACCOUNT::$BRANCH_NAME['LA'] in D:\wamp\www\EBANK\account.class on line 186

if i used this :
Code: [Select]
    echo $this->BRANCH_NAME['LA'];
it is working fine .
and the method is working fine i can iam trying to call property which is NOT an array.


Can you please help me in what iam doing wrong ?


Thanks in advance

Hi all,

I have two classes. Registration and Connection.

Inside a registration.php I include my header.php, which then includes my connection.php...

So all the classes should be declared when the page is loaded.

This is my code:


registration.php:

<?php include ('assets/header.php'); ?> 
        
    <?php
        class registration{                    
            public $fields = array("username", "email", "password");
            public $data = array();
            public $table = "users";
            public $dateTime = "";
            public $datePos = 0;
            public $dateEntryName = "date";
            
            function timeStamp(){
                return($this->dateTime = date("Y-m-d H:i:s"));
            }
            
            function insertRow($data, $table){      
                    
                    foreach($this->fields as $key => $value){
                        mysql_query("INSERT INTO graphs ($this->fields)
                        VALUES ('$data[$key]')");
                    }
                    
                    mysql_close($connection->connect);
            }
            
            function validateFields(){
            
                $connection = new connection(); 
                $connection->connect();
                        
                foreach($this->fields as $key => $value){
                    array_push($this->data, $_POST[$this->fields[$key]]);
                }
                $this->dateTime = $this->timeStamp();
                array_unshift($this->data, $this->dateTime);                
                array_unshift($this->fields, $this->dateEntryName);   
                
                foreach($this->data as $value){
                    echo "$value";
                }
                
                $this->insertRow($this->data, $this->table);
            }
        }
        
        $registration = new registration();
        $registration->validateFields();
    ?>

<?php include ('assets/footer.php'); ?>



At this point I cannot find my connection class defined on another included/included page.



                $connection = new connection(); 
                $connection->connect;





config.php (included within header.php)

<?
    class connection{ 
        public $dbname = '**';   
        public $dbHost = '**';
        public $dbUser = '**';
        public $dbPass = '**';
        public $connect;
        
        function connect(){
            $this->connect = mysql_connect($this->dbHost, $this->dbUser, $this->dbPass) or die ('Error connecting to mysql');
            mysql_select_db($this->dbname, $this->connect);
        }
    }
?>



Any ideas how to call it properly?

I have a class in which I have a function called connection. I am now trying to call this function from another class, but it will not work. It works if I put the code in from the other function rather than calling it but that defeats the purpous.

class locationbox

{
   function location()
   {
   
   
   $databaseconnect = new databaseconnect();
         $databaseconnect -> connection();{

$result = mysql_query("SELECT * FROM locations");

while($row = mysql_fetch_array($result)) // line that now gets the error, mysql_fetch_array() expects parameter 1 to be resource, boolean given //in
  {
  echo "<option>" . $row['location'] . "</option>";
    }
   
}
}}

Apologies for such a silly question.... Been away from php for a long time...

How can i call a variable from a position above where the variable is set? I need a variable to echo out near the top of my page but its defined near the bottom of my script.

As you can see i am tryin to echo the amount of rows found from the query below.

Code: [Select]
<?php

echo $num_rows;



$query = "SELECT  Name,  FROM table";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){

$num_rows = mysql_num_rows( $result );
}
?>

Thanks in advance

Hello,   I am having some troubles and was hoping someone could guide me through it.   Q: When ever I try call my get_status function all I get is a white page of nothing, no errors to work from etc... Can anyone here see what I am doing wrong?     PATH: index.php   NOTICE //<<-- KILLS PAGE

<?php
spl_autoload_register(function ($class) {
    include '/lib/' . $class . '.inc';
});

$servers = new servers;
echo $servers->get_servers(); 
echo "STATUS: ".$servers->get_status("0.0.0.0",80); //<<-- KILLS PAGE
?>

Page works fine until I want to use the status function, I get no errors or anything just a blank page.   PATH: Lib/Servers.inc   NOTICE //<<-- KILLS PAGE

<?php
ini_set('display_errors',1);
ini_set('display_startup_errors',1);
error_reporting(E_ALL);
error_reporting(-1);

	include_once '../../Global-Includes/ServerStatus/db-connect.php';
	
//namespace xStatus;

class servers {

	private $db_Hostname	= HOSTNAME;
	private $db_Username	= USERNAME;
	private $db_Password	= PASSWORD;
	private $db_Database	= DATABASE;
	
	private $dbSQL			= '';
 
    function __construct() {
		
	} // End Construct
	
		public function get_servers(){
			
			$db = new mysqli($this->db_Hostname,$this->db_Username,$this->db_Password,$this->db_Database); 
		
				$message = '';

				// list current servers from database
				$sql = "SELECT * FROM tbl_servers";
				$res = $db->query($sql);
				
				if ($res->num_rows > 0) {
					
					$message = '<h3>Current Servers</h3>';
					
					while ($row = $res->fetch_assoc()) {
						
						$message .= $row['HostGame'] . '<br>';
						$message .= $row['HostIP'] . '<br>';
						$message .= $row['HostPort'] . '<br>';
						$message .= $this->get_status($row['HostIP'],$row['HostPort']) . '<br>'; //<<-- KILLS PAGE!
						
					}
				}
				
				$message .= "<br>End of the \"Server List\" ";
				
			return $message;
			
			}
		
	
		public function get_status(&$ServerIP,&$ServerPort){
			
			if(@stream_socket_client("tcp://".$this.$ServerIP.":".$this.$ServerPort."", $errno, $errstr, 1) !== false) {
				return "Online";
			} else {
				return "Offline";
			}
			return "Offline";
			}
	
} // End class

?>

Kind regards and thank you.        

This is a bit of a more advanced question so I am hoping there are some advanced programmers online at this time . Anyways basically I want to be able to "queue" functions from a class in a single call and am wondering if I am doing it correctly or if there is a better way to do it. Here is my code:


<?php
class test {
     private static $one;
     private static $two;
     private static $three;

     public function callOne($val){
          $one .= $val;
          return $this;
     }
     
     public function callTwo($val){
          $two .= $val;
          return $this;
     }

     public function callThree($val){
           $three .= $val;
           return $this;
     }

     public function print(){
          echo $this->one.' '.$this->two.' '.$this->three;
     }
}
?>


now when I want to call this I can do:

$test = new test();
$test->callOne('one')->callTwo('two')->callThree('three');
$test->callOne('another one');
$test->print();


Is there a better way to do this or is there a different method of doing this? Just wanna make sure I am doing it right lol.

I am getting the following error:

Parse error: parse error, expecting `T_OLD_FUNCTION' or `T_FUNCTION' or `T_VAR' or `'}'' in /Library/WebServer/Dev/classtest/lib/class_userdata.php on line 5

on this class code:

Code: [Select]

class userdata {

public $name = "";
public $city = "";
public $phone = "";

function setData($n, $c, $p) {

$name = $n;
$city = $c;
$phone = $p;

}

function getData() {

$userdata=array('name'=>$name, 'city'=>$city, 'phone'=>$phone);
return $userdata;

}

}


I thought that was a proper way to set up some class variables. (http://www.victorchen.info/accessing-php-class-variables-and-functions/). Thanks.