PHP - Getting Time Added With Date
I have a form that has this:
Code: [Select] <input type="text" name="notes_date" size="10" value="<?php echo date("m/d/Y");?>" /> I enter into the database after processing the variable like this: Code: [Select] $notes_date=date ("Y-m-d H:i:s", strtotime($_POST['notes_date'])); However, it gets stored at 2012-03-15 00:00:00 How do I fix this so that the current time gets stored instead of 00:00:00? Similar TutorialsHey guys, How would I go about subtracting Today from a previous day to find the difference? For example, I want to subtract TODAY from a previous date in my database, to determine if the difference is greater than 1 day. Any ideas? I tried doing the subraction in TIMESTAMPS, but when I convert the date back to Y-m-d H:i:s, I got some weird year and time. Hi Is it possible to make a row(with number) increase every time the same value is added to the table? Example: I enter "test" into a table and it gets the following data: id=1 name=test count=1 And the next time I enter "test" into the table it becomes id=1 name=test count=2 instead of id=1 name=test count=1 id=2 name=test count=1 I want to create a form where users can suggest stuff and I want to see what is the most popular ect. Thanks in advance PHP date and time function is not showing correct time on my local system I have the following php code date_default_timezone_set("Africa/Lagos"); $date = date('d-m-y h:i:s'); echo "Server Time ".$date ."<br>"; echo "The time is " . date("h:i:sa")."<br>"; $current_datetime = date("Y-m-d") . ' ' . date("H:i:s", STRTOTIME(date('h:i:sa'))); echo "Current time1: ".$current_datetime . "<br>";
Output
Server Time 21-05-21 09:55:39
Expected Output
Server Time 21-05-21 10:55:39
Any help would be appreciated. Edited May 21 by Ponel OK So I've got a datepicker that sends a date in d/m/y format. My DB stores the data in Unix Timestamp Which I can convert the date to with strtotime however this does the exact date & time. All I want is the actual day. I've spent hours trying to convert this with just the day with mixed results... Thanks. I am having a problem with PHP displaying the correct date and time. It updates as it should, but is fast by 4min and is always displaying a date in 2004. I ran a basic php script to make sure the application im using itself is not wrong. go to lunenburgledger.com/time.php Anybody had any ideas on where to check? The system time on the Windows Server 2003 is correct. The only thing I can think of is that it was converted to a virtual machine on vmware esxi, but the system time stayed right. Any ideas? Thanks! Hi! The below dropdown will show dates/times every 15 minutes from 12am to 11:45pm for only 1 day. I want it to show for 5 days, anyway I can do this? Below code: Code: [Select] $start = strtotime('12:00am'); $end = strtotime('11:45pm'); echo '<select name="time">'; for ($i = $start; $i <= $end; $i += 900) { echo '<option>' . date('F j, Y, \a\t g:i a', $i); } echo '</select>'; Thanks for any help. What is the best way to insert this time stamp into mysql? This is the info I want... Example: Sunday, 28.1.11, 9:56 How would I also select time from the database using mysql? Hey, I need help with my date & time string. I need to edit it do show in a string + also use it for calculating things like when the date has passed. The string is like this: Code: [Select] <?php $string = '2011-01-01 00:00 AM'; ?> So i wanted to check if there was a function that can automatically convert it, so it would say for example: Quote Sunday, 1st of January 2011 00:00 AM But at the same time compare $string against server time to see if the date has expired? Hope you can help Hey, I need help with date, I have stored dates in my table in this format: i.e. 22.10.2011 but now use timestamp to store dates. Problem is with this query the WHERE clause will find dates in the old format and I want to change that to the new format. Code: [Select] for($i = $count; $i > 0; $i--) { $day = date("d.m.Y", mktime(0, 0, 0, date("m"), date("d") - $i, date("Y"))); $tmp = mysql_fetch_array(safe_query("SELECT count FROM ".PREFIX."counter_stats WHERE dates LIKE '%".$day."'")); $array[] = $tmp['count'] ? $tmp['count'] : 0; } Am I making sense ? I have a field set as datetime and want to compare that field to see if it is older then ten minutes. Can anyone help I am having a brain fart? I have a batch script that reads from a timestamp.txt file to determine the last time it ran and I need to modify that by two hours. What happens is the script will run to look for changes in the county records and their server time is two hours different from mine. Code: [Select] $fr=fopen("xml/timestamp.txt",'r'); $mydate=fread($fr, 50); if ($incremental_updates == 1){ $default_template_file="xml/incremental_template.xml"; $default_config_name="xml/incremental.xml"; $contest=file_get_contents($default_template_file); $contest=str_replace("{DATE_TAG}", $mydate, $contest); $f=fopen($default_config_name,'w+'); fwrite($f, $contest); fclose($f); fclose($fr); $fw=fopen("xml/timestamp.txt",'w'); fwrite($fw, substr(date('c'), 0, 19)); fclose($fw); }else{ $default_config_name = "xml/full_update.xml"; } I tried making a time stamp update look like $cur_timestamp=date("Y-m-d H:i:s", time() +14400); which is correct but it doesn't write to the text file properly. Using the above fwrite($fw, substr(date('c'), 0, 19)); I get the correct results in the timestamp.txt file for my server time. I need it to be +14400 2011-05-25T08:27:51 would essentially become 2011-05-25T10:27:51 when it writes to the timestamp.txt I hope that makes sense. J I'm trying to make $time be a variable with the current time and I want it to have the same format as mysql. I can't figure out what I am doing wrong here Wrror: Warning: date_format() expects parameter 1 to be DateTime, integer given Code: [Select] $time = date_format(time(),'Y-m-d H:i:s'); I'm looking to enter the current time and date into a mysql database using php. My current code looks like this: Code: [Select] $now = date("m/d/y",time()); I then insert $now into the table into a datetime column. This all works but the time when read from the column appears as 0000-00-00 00:00:00. Any ideas what I'm doing wrong? Thanks in advance. Hey guys, What i would like to create is the ability to calculate the difference between two dates / times. For example: 2010-12-13 10:00:00 to 2010-12-17 17:00:00 In a format of days / hours and minutes / seconds. However, I only want to calculate for an 9-5 work day, not the hours outside. Is this possible? If so, how would I go about creating something like this. Hi there, what I have been trying to do is add some additional logic.. My problem is I want to stop displaying the month and day after the year 2000? I know I need to add an if and else statement but this is my first actual project and I am a little stuck.. here is the page, it's a plugin for a timeline http://www.llandover...oject-timeline/
And the file is attached below.. any help would be appreciated. The plugin code was too long to just post in here, didn't want to cause any slow loading issues for people on a slow connection.. Thanks and I appreciate any help.
Attached Files
annual_archive.php 18.15KB
5 downloads hello i got this small function i`m working on to get the date of a month something like get current date - 1 but not sure how to handle jan month can someone help me please ? $month = date('m') - 1; $date_startt = date('Y').'-'.$luna.'-01'; $timestamp_start = strtotime($data_start); Are time zones when calling the date function automatically decided based on where you live? Or is that something that I have to implement--Because the time is wrong according to my time zone. I am writing an app that takes ofx banking files files on convert them to csv for excel or importation into sql. I am on the last task. Converting the nonstandard date:time stamp. I am using preg_replace(). I am not the best at regular expressions. I am getting this error: "Warning: preg_replace() [function.preg-replace]: Unknown modifier '\' in C:\xampp\htdocs\banking\ofx-date.php on line 13" CODE: // Date Time 20110228000600 (2011/02/28/, 00:06:00) // Expected Return '<DTPOSTED>2011/02/28,00:06:00' $ofxDate = '<DTPOSTED>20110228000600'; $ofxNewDate = substr($ofxDate,0,10) . substr($ofxDate,10,4) . '/' . substr($ofxDate,14,2) . '/' . substr($ofxDate,16,2) . ',' . substr($ofxDate,18,2) . ':' . substr($ofxDate,20,2) . ':' . substr($ofxDate,22,2); echo htmlentities($ofxNewDate) . PHP_EOL;; $patternA = '/<DTPOSTED>/\b[0-9]+\b'; //$replacement = '/<DTPOSTED>/'; $stringB = preg_replace($patternA, $ofxNewDate, ofxDate); echo htmlentities($StringB) . PHP_EOL; Is it possible to convert time(); to date();? |