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PHP - Random Statement Script
Hello,
I have been using a random text script to display a useful tip to the user when they land on a certain page. This is how the script looks: Code: [Select] <?php $random_text = array("This is an example tip", "This is another example of a tip", "And another...", "And one more"); $sizeof = count($random_text); $random = (rand()%$sizeof); print("$random_text[$random]"); ?> At the moment the tip will display randomly everytime the page is loaded. Is there any way I can add a small button that says "Give me another" or something, so that when they click it another random fact will come out? If possible I would like to avoid them having to reload the page everytime. Any help is greatly appreciated. Similar TutorialsHi im struggling to find out how to get an if statement working with my random quote creator, here is the coding: Code: [Select] <?php include 'connect.php'; session_start(); $username = $_SESSION['loginusername']; $result = mysql_query("SELECT * FROM boxerinfo WHERE fighterrequest = '$username'"); while($row = mysql_fetch_array($result)) { $quotes[] = 'Go ahead, bite the big apple, don\'t mind the maggots, uh huh.'; $quotes[] = 'Happiness is a warm gun. (bang-bang, shoot-shoot.)'; $quotes[] = 'You may be a lover but you ain\'t no dancer.'; $quotes[] = 'Yeah you got lucky, babe. When I found you.'; $quotes[] = 'Out here in the fields, I fight for my meals.'; $quotes[] = 'You go back, jack, do it again. Wheel turnin\' round and round.'; $quotes[] = 'Don\'t let the sound of your own wheels drive you crazy.'; $quotes[] = 'Lord I\'m learning so much more, than back when I knew it all.'; $quotes[] = 'You get too much you get too high. Not enough and you\'re gonna die.'; $quotes[] = 'You were wrong when you said, \'everything was gonna be alright.\''; $quotes[] = 'I know just what you need. I might just have the thing.'; $quotes[] = 'I am hot, and when I\'m not, I\'m cold as ice.'; $random_number = rand(0,count($quotes)-1); echo $quotes[$random_number]; } ?> I just want if $quotes = (a certain quote) then insert into mysql table, anyone know how to do this on an array? thanks There are about 400 records in a database with a field zabp_package = T_SIMT. They were uploaded in an order where specific category lists were uploaded together. For example, first 100 dining, then 75 insurance, then 150 health, then 75 cars. So from an auto increment standpoint they were inserted in that order. I want to select at random 100 of these 400 and update two fields. My update statement is: update `usersOld` SET `m_org` = 'ZABP.org Corporate HQ' , `m_orgID` = 'PFL2a96bW' WHERE `zabp_package` = 'T_SIMT' This works for all, I just need to limit a random selection to 100. Any Help on this, thanks in advance. i have got this script which displays all folders within a folder but what i want to do now is get it to display a random picture for each of the folders that it is showing in the grid. i know how to display a random image using array_rand() but i don't know how i would implement it. Code: [Select] <form name="Gallery" method="post"> <?php $path = "gallery_files/gallery/"; $dir_handle = @opendir($path) or die("Unable to open folder"); echo "<table cellspacing='15'>"; echo "<tr>"; while (false !== ($folder = readdir($dir_handle))) { if($folder == "pictures.php") continue; if($folder == ".") continue; if($folder == "..") continue; echo ($x % 6 == 0) ? "</tr><tr>" : ""; echo "<td><a href='pictures/?folder=$folder'><img src='path/to/random/image' style='height:auto;width:110px;' alt='$folder'></a><br /><a href='pictures/?folder=$folder'>$folder</a></td>"; $x++; } echo "</tr>"; echo "</table>"; closedir($dir_handle); ?> </form> Hi, I am wanting to create a random fact script for a small website project. The idea is when the user loads a page a random fact will appear at the top ( I guess from an array of strings I will make?) Can anyone recommend the most efficient and easiest way to go about this please? This is my registering script: <?php include('connectvars.php'); $user_email = strip_tags(trim($_POST['email'])); $firstname = strip_tags(trim($_POST['firstname'])); $lastname = strip_tags(trim($_POST['lastname'])); $nickname = strip_tags(trim($_POST['nickname'])); $password = strip_tags($_POST['password']); $repassword = strip_tags($_POST['repassword']); $dob = $_POST['dob']; $find_us_question = strip_tags(trim($_POST['find_us_question'])); if (isset($_POST['submit_signup'])) { if ((empty($user_email)) || (empty($firstname)) || (empty($lastname)) || (empty($nickname)) || (empty($password)) || (empty($dob))) { echo "Please fill out all the fields!"; } else { // check char length of input data if (($nickname > 30) || ($firstname > 30) || ($lastname > 30) || ($user_email > 50)) { echo "Your nickname, first- and/or lastname seem to be too long, please make sure you have them below the maximum allowed length of 30 characters!"; } else { // check password char length if (($password > 25) || ($password < 6)) { echo "Your password must be between 6 and 25 characters!"; } else { // encrypt password $password = sha1($password); $repassword = sha1($repassword); if ($password != $repassword) { echo "Please make sure your passwords are matching!"; } else { $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); $query = sprintf("INSERT INTO user (firstname, lastname, nickname, password, email, dob, doj) VALUES ('%s', '%s', '%s', '%s', '%s', '%s', now())", mysqli_real_escape_string($dbc, $firstname), mysqli_real_escape_string($dbc, $lastname), mysqli_real_escape_string($dbc, $nickname), mysqli_real_escape_string($dbc, $password), mysqli_real_escape_string($dbc, $user_email), $dob); mysqli_query($dbc, $query); mysqli_close($dbc); echo "You have been successfully registered!"; } } } } } ?> A bunch of nested if statements, the read-ability gets worse after a while, I'm new to programming so I don't know if there's a better more read-able solution. Anyway, every time I try to sign up it's printing out the echo message: "Your password must be between 6 and 25 characters!" Which derives from: // check password char length if (($password > 25) || ($password < 6)) { echo "Your password must be between 6 and 25 characters!"; } else { EVEN if I stay between 6 and 25 characters it's still printing out this error message, let's say I have a password of 8 characters, and I've entered everything else correctly, it's still giving me all the time this error message, and I can not figure out why. As above, I have a lottery style site that picks a random number between 1-8 but my users complain for some reason that this is not enough. So i was told to look into using fopen and random.org to generate a random number. Anyone have experience of this and perhaps a code snippet for me to look at and possibly use? help will be appreciated. I'm having issues with the following: Code: [Select] <?php session_start(); $_SESSION['username']=$_POST['username']; $_SESSION['password']=$_POST['password']; if($_SESSION['username']=="username" && $_SESSION['password']=="password"){ if($_GET['product']=="add"){ $content.=' <p><label>Product Name:</label> <input type="text" name="product_name" size="30" /> <label>Product Price:</label> <input type="text" name="product_price" size="5" /> </p> <p><label>Product Category:</label> <input type="text" name="product_category" size="30" /></p> <p><label>Product Link:</label> <input type="text" name="product_link" size="30" /></p> <p><label>Product Image:</label> <input type="text" name="product_image" size="30" /></p> <p><label>Product Tag:</label> <input type="text" name="product_tag" size="30" /></p> <p><label>Product Keywords:</label> <input type="text" name="keyword" size="30" /></p> <p><label>Product Features:</label><br /> <textarea name="product_features" rows="10" cols="60"></textarea> </p> <p><label>Product Pros:</label><br /> <textarea name="product_pros" rows="5" cols="30"></textarea> </p> <p><label>Product Cons:</label><br /> <textarea name="product_cons" rows="5" cols="30"></textarea> </p> <p><label>Product Description:</label><br /> <textarea name="product_description" rows="10" cols="60"></textarea> </p> <p><label>Product Notes:</label><br /> <textarea name="product_notes" rows="5" cols="30"></textarea> </p> '; $logout='<div><a href="./acp_admincp.php?log-out">Log-Out</a></div>'; } elseif($_GET['product']=="view"){ } else{ $content.=' <a href="./admincp.php?product=add">Add New Product</a> <br /> <a href="./admincp.php?product=view">View Products</a> '; } } elseif(isset($_GET['log-out'])){ session_start(); session_unset(); session_destroy(); header("Location: ./admincp.php"); } else{ $content=' <form action="./admincp.php" method="post"> <p><label>Username:</label> <input type="text" name="username" size="30" />'; $content.='</p> <p><label>Password:</label> <input type="password" name="password" /></p>'; $content.='<p><input type="submit" value="Submit" name="Submit" /></p> </form>'; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> <head> <base href="http://ghosthuntersportal.com/" /> <title>Ghost Hunter's Portal - Admin Control Panel</title> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <meta name="verify-v1" content="" /> <meta name="keywords" content="ghost, hunters, hunter, ghosts, spirit, spirits, paranormal, investigation, investigator, investigators, k2, emf, meter, kii" /> <meta name="description" content="Ghost Hunters Potal. Parnormal research equipment store." /> <meta name="author" content="Andrew McCarrick" /> <meta name="robots" content="index, follow" <link rel="stylesheet" type="text/css" href="style.css" /> </head> <body> <img src="./logo.png" alt="Ghost Hunter's Portal Admin Control Panel" /> <br /> <div style="color: #AA44AA; font-size: 26px; margin-top: -30px; margin-left: 125px;">Admin Control Panel</div> <?php echo $logout; echo $content; ?> </body> </html> I can log-in, and get to the page with the two links on it. However, once I click one of the links it falls back to the log-in page, and it ends up being a never ending loop. It's doing this: Log-In --> Page with links ---> Log-In page again Should be doing this: Log-In --> Page with links --> Add Product page or View Products page I can never get into the the actual sub page. Just to be clear, the address bar actually shows product=add or product=view, but it still shows the log-in page. Hello Everyone, I have to change the if statements to a switch statement, in this game. Can anyone help? Thanks.
var checkKeyPressed = function (e) {
// Press key A or key D to make dog run to the left or right
// The running speed is specified by the step variable, 10 by default.
// If you replace 10 with a larger integer, the dog will run faster.
//press A, dog runs left
if (e.keyCode == "65") {
if (prex[0] > 5) {
prex[0] = prex[0] - step;
}
}
//press D, dog runs right
if (e.keyCode == "68") {
if (prex[0] < right) {
prex[0] = prex[0] + step;
}
}
};
I know this is not coding.. However... How tolerant is PHP from generating a random output from 1000s of entry columns in a mysql database. I would like to make a script that would potentially pick one of a 1000 results at random. is this a problem with being ran multiple times? i wanted to choose 5 random numbers from 0-20. each number represents an index in an array. is there a way to pick out 5 random items from the array. say if random number generator piked a number 22, the last item in the array is at index 20, it wud then have to go to index 0. thanks! Hi Guys I need some help this is my first real php website. Im trying to retrieve results from an accommodation database, to make the results fair I need to return a random set of results so each accommodation get a fair viewing and nobody is always at the bottom. The problem arises when i paginate the results, because each page executes a separate randomly ordered offset mysql query I can end up showing the some of the same results over and over on multiple pages. This is going to confuse and irritate searchers. How can i achieve results and paginate them where each accommodation gets a fair chance at the first page each time the database is searched? Okay, minor issue, but not sure how to resolve. I have a form that processes through PHP and has it's fields validated with JS and sends the data to an e-mail address and a database. It works fine, but there are random times where a submitted entry will show up blank in the e-mail and not be in the database at all, any ideas on what might be causing this? Thanks. Im trying to figure out the best way to random a line from a text file and after the random delete that line from the file. This way the same username cannot be picked twice thanks for any input How would I make it so that for every set of data where a fieldname is 1+ it picks a random one out. For example User Hit Luke 0 Peter 1 Alex 3 Peter 1 For every value where Hit is 1 or over it selects out of the query results a random username. Wow, I have no clue what I'm doing.. I'm trying to make a random game and if you roll a 6, you will win 500 rp and I'm trying to insert the 500 rp into the user who is logged in ($_SESSION['username'). But I... just don't know where to begin. Here is my crappy coding that I just.. am stumped on: <p><?php $dice = rand(1,6); if($dice == 1){ echo "You rolled a <br><b>1</b>"; }if($dice == 2){ echo "You rolled a <br><b>2</b>"; }if($dice == 3){ echo "You rolled a <br><b>3</b>"; }if($dice == 4){ echo "You rolled a <br><b>4</b>"; }if($dice == 5){ echo "You rolled a <br><b>5</b>"; }if($dice == 6){ echo "You rolled a <br><b>6</b>"; } $winner = "500"; if($dice == 6); { include("haha.php"); $cxn = mysqli_connect($dbhost,$dbuser,$dbpassword,$dbdatabase); $sql = "INSERT INTO Member (rp) VALUES ('$winner')"; mysqli_query($cxn,$sql); } ?> I'm just searching for some input on a function I saw and wanted someone who could explain to me what this function would mean. As I have the same db structure and was curious specifically to know what sort of values I should have inside of the fields for varcharfield and textfield. function customfieldinput($fedid,$id,$groupid,$styleid) { $query = "SELECT field.id as getfieldid, field.is_custom as getiscustom, field.fullname as getfullname, customfields.id as getcustomfieldid, customfields.varcharfield as getvarchar, customfields.textfield as gettext FROM efed_list_fields as field LEFT JOIN efed_content_customfields as customfields ON ( field.id = customfields.field_id and customfields.character_id = '$id' ) WHERE field.fed_id = '$fedid' and field.style_id = '$styleid' and field.group_id = '$groupid' and field.enabled = '1' and field.is_custom > '0' ORDER BY field.is_custom,field.fullname"; $result = mysql_query ($query); while ($row = mysql_fetch_assoc($result)) { $fieldarray=array('getfieldid','getiscustom','getfullname','getvarchar','gettext','getcustomfieldid'); foreach ($fieldarray as $fieldlabel) { if (isset($row[$fieldlabel])) { $$fieldlabel=$row[$fieldlabel]; $$fieldlabel=cleanquerydata($$fieldlabel); } } if ((isset($getcustomfieldid)) && ($getcustomfieldid > "0")) { $update = "update"; } else { $update = "new"; } if ($getiscustom == "1") { print "<tr>\n"; print "<td width=120 class=rowheading>".$getfullname.":</td>"; print "<td class=row3><textarea name=\"custom".$getfieldid.$update."\" class=\"textarea490x100\">"; if ((isset($gettext)) && ($gettext != "")) { print $gettext; } print "</textarea></td>\n"; print "</tr>\n\n"; } else { print "<tr>\n"; print "<td width=120 class=rowheading>".$getfullname.":</td>"; print "<td class=row3><input type=text name=\"custom".$getfieldid.$update."\" class=fieldtext490"; if ((isset($getvarchar)) && ($getvarchar != "")) { print " value=\"".$getvarchar."\""; } print "></td>\n"; print "</tr>\n\n"; } if (isset($getcustomfieldid)) { unset ($getcustomfieldid); } if (isset($getvarchar)) { unset ($getvarchar); } if (isset($gettext)) { unset ($gettext); } } } The purpose of this function is to go to the characters table and grab all of the characters that have a statusID of one however I want it to limit it to any ONE of those characters as this is a random image it's going to show and then I want it to have that charactes shortName and then use it to find their spotlight image from inside of the images/spotlight folder. All its showing right now in its spot is the the filename of the image when I call this function. function spotlight(){ $query = "SELECT * FROM characters WHERE characters.statusID = 1 LIMIT 1"; $result = mysql_query($query); $row = mysql_fetch_assoc($result); $labels = array('shortName'); $img = array(); if($handle = opendir('images/spotlight/')) { $count = 0; while (false !== ($file = readdir($handle))) { if(strlen($file) > 2){ $img[$count] = $file; $count++; } } } echo $img[rand(0, (count($img)-1))]; } Hi Guys, I have a php script to upload a photo to a mysql table. This works great, until someone uploads a file with the same name, then it replaces the old one. Bad times! So Ive researched it and I have put a timestamp on the filename and it uploads with the correct timestamp in the images folder. However the data that it uploads to the table is just the original filename, ie it doesnt stamp the filename in the table therefore they dont match... Any ideas... <?php include('config.php'); if (isset($_GET['Ter']) ) { $ter = (int) $_GET['Ter']; if (isset($_POST['submitted'])) { //Photo Upload //This is the directory where images will be saved $name=time(); $target = "images/"; $target = $target .$name. basename( $_FILES['photo']['name']); //This gets all the other information from the form $photo = ($_FILES['photo']['name']); //Pause Photo Upload foreach($_POST AS $key => $value) { $_POST[$key] = mysql_real_escape_string($value); } $sql= "UPDATE `ter` SET `Ter` = '{$_POST['Ter']}' , `BranchName` = '{$_POST['BranchName']}' , `BranchAddress` = '{$_POST['BranchAddress']}' , `BranchTel` = '{$_POST['BranchTel']}' , `BranchEmail` = '{$_POST['BranchEmail']}' , `BranchLink` = '{$_POST['BranchLink']}' , `Theme` = '{$_POST['Theme']}' , `LocalInfo` = '{$_POST['LocalInfo']}' , `BranchInfo` = '{$_POST['BranchInfo']}' , `photo` = '{$_FILES['photo']['name']}' WHERE `Ter` = '$ter' "; mysql_query($sql) or die(mysql_error()); //Unpause Photo Upload //Writes the photo to the server if(move_uploaded_file($_FILES['photo']['tmp_name'], $target)) { //Tells you if its all ok echo "<br />The file ". basename( $_FILES['photo']['name']). " has been uploaded. <br />"; } else { //Gives and error if its not echo ""; } //End of Photo Upload echo (mysql_affected_rows()) ? "<br />Edited Branch.<br />" : "<br />Nothing changed. <br />"; } $row = mysql_fetch_array ( mysql_query("SELECT * FROM `ter` WHERE `Ter` = '$ter' ")); ?> Hi, I want to pick out a random letter from a to h. How can I do this? So everytime the page re-loads, a random letter (range a-h) will show. Thanks alot for any help. here is the database: its a facebook app i want that my sql will choose every time random but considerate in the sex parameter. i mean that if the user is boy i will put it in parameter and boys is num-1 girls-0 and if the user is boy it will run random sql just on the boys and if its girls so random on the girls here what i did: $sql = "SELECT * FROM pcm ORDER BY RAND() LIMIT 1"; $Recordset3 = mysql_query($sql) or die(mysql_error()); $row2 = mysql_fetch_object($Recordset3); print_r($row2); but for some reason i get an error that the database is not selected maybe i didnt select my database right? please help tnx.... |
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