PHP - Sql Count Statement - This Is Probably Really Simple

I have a field in my MySQL DB that holds numbers separated by a comma (example: 1, 3, 45, 137, 87). I simply want to get a count of how many numbers are in there. (Using my example the result would be 5). I'm sure this is a simple question but I don't know how. I'm able to extract the numbers but I can't get the count to read anything other than 1. Can anyone help?

I'm usng this simple script to remove a row from a MySQL table:

Code: [Select]
<?php

$id = "123456789";
$pass = "bach";
$query = "DELETE FROM my_form WHERE member = ('$id') && password = ('$pass')";
$result = mysql_query($query);
echo "The data has been deleted.";

?>
Works as intended, if the password and ID match, then the row is deleted and it echos "The data has been deleted."  I want to add an "else" statement...  the the password and ID did not match, "the data has NOT been deleted".  I know I can't use "else" if I don' begin with an "if"... but I'm not sure where to put it (after the query?)

Thank you.

what am i doing wrong?

<?php

$input_value = a tall order;

if ( $input_value == a tall order ) {
   echo 'Correct!';
}
if ( $input_value = err on the side of caution ) {
   echo 'correct!';

} else {
   echo 'Sorry, try again.';
}

?>

also, once i get this to work i want it to be able to have the input value be a submit form in HTML so that anything the user puts in the box will go through this piece of code to decide what to do with what they put in. Thanks!

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=322930.0

This topic has been moved to Other Programming Languages.

http://www.phpfreaks.com/forums/index.php?topic=354391.0

Hi guys,

I need your help. I am trying to insert the rows in the mysql database as I input the values in the url bar which it would be like this:

Code: [Select]
www.mysite.com/testupdate.php?user=tester&pass=test&user1=tester&email=me@shitmail.com&ip=myisp

However i have got a error which i don't know how to fix it.


Error: Column count doesn't match value count at row 1


<?php
session_start();
    define('DB_HOST', 'localhost');
    define('DB_USER', 'mydbusername');
    define('DB_PASSWORD', 'mydbpassword');
    define('DB_DATABASE', 'mydbname');

$errmsg_arr = array();
    $errflag = false;

    $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
    if(!$link) {

die('Failed to connect to server: ' . mysql_error());
    }

    $db = mysql_select_db(DB_DATABASE);
    if(!$db) {

die("Unable to select database");
    }

   function clean($var){

return mysql_real_escape_string(strip_tags($var));
    }
  $username = clean($_GET['user']);
    $password = clean($_GET['pass']);
    $adduser = clean($_GET['user1']);
    $email = clean($_GET['email']);
    $IP = clean($_GET['ip']);
    if($username == '') {
  $errmsg_arr[] = 'username is missing';
  $errflag = true;
    }
    if($password == '') {
  $errmsg_arr[] = 'PASSWORD is missing';
  $errflag = true;
    }
    if($errflag) {
  $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
  echo implode('<br />',$errmsg_arr);
   }
   else {
   $sql = "INSERT INTO `members` (`username`,`email`,`IP`) VALUES ('$adduser','$email','$IP')";

if (!mysql_query($sql,$link))
  {
  die('Error: ' . mysql_error());
  }
echo "The information have been updated.";
  }
?>


Here's the name of the columns i have got in my database:

Code: [Select]
username
email
IP


I have input the correct columns names, so I can't correct the problem I am getting.

Please can you help?

This topic has been moved to MySQL Help.

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http://www.phpfreaks.com/forums/index.php?topic=330192.0

Why am I getting this error when there are 3 Fields with 3 values?

Column count doesn't match value count at row 1

Code: [Select]
$sql5="INSERT INTO participants (participant_name, team_no, sport)
VALUES ('".implode("','$_POST[team]'),('",$_POST['participant_name'])."','$_POST[team]','$sport')";

Anyone can help me?

<?php
$tbl_name="menu";
$kategorije = mysql_query("SELECT * FROM $tbl_name WHERE Left(menu_name, 1) BETWEEN 'A' AND 'M' ORDER BY menu_name ASC");
if (!$kategorije) {
die("Database query failed: " . mysql_error());
}

while ($row=mysql_fetch_array( $kategorije )) {
echo "<div id=lista-header><h4>{$row["menu_name"]}</h4></div>";
$id_sub=$row['id_menu'];
$podkategorije = mysql_query("SELECT * FROM submenu WHERE id_menu=$id_sub ORDER BY sub_name ASC", $connection);
if (!$podkategorije) {
die("Database query failed: " . mysql_error());
}
echo "<ul class=\"pod\">";
while ($pod=mysql_fetch_array( $podkategorije )) {
echo "<li><a href=index.php?=podkate?".$pod["id_sub"]." class=black>{$pod["sub_name"]}</a><hr size=1 align=left width=100px color=#cccccc></li>";
}
echo "</ul>";
}


?>

In this way, I get list with categories and hes subcategories. How to count how many subcategories have each categories, and count how many articles have each categories?

Example (I wanna get this kind of look):

Categories name (3)
subcategoriesname (2)
subcategoriesname (4)
subcategoriesname (7)

Categories name (5)
subcategoriesname (1)
subcategoriesname (14)
subcategoriesname (9)
subcategoriesname (2)
subcategoriesname (


Categories name (2)
subcategoriesname (28)
subcategoriesname (17)

Where the numbers represent how many categories and sub-items have articles

Hello,

I'm pulling data from a table in order to pre-populate a form.  I have either a "school" address or a "home "addresses" for each record in the table.  I've already connected to the table and made the query... what I need to do now is simply create an "else" statement.  If the value "Address_type" is "school", pre-populate the form... if it's not "school" then display an empty form:

I think I've got the idea, but my syntax can't be right:

Code: [Select]
<?php 
if ($Address_type = 'school') 
{ 
?>

School address street</b>:
<input type="text" name="Address_street" value="<?php echo stripslashes($row['school_address']); ?>" />

School address city</b>:
<input type="text" name="Address_city" value="<?php echo stripslashes($row['school_city']); ?>" />

School address state</b>:
<input type="text" name="Address_state" value="<?php echo stripslashes($row['school_state']); ?>" />

School address zipcode</b>:
<input type="text" name="Address_zip" value="<?php echo stripslashes($row['school_zip']); ?>" />

<?php
}else {
?>

School address street</b>:
<input type="text" name="Address_street" />

School address city</b>:
<input type="text" name="Address_city" />

School address state</b>:
<input type="text" name="Address_state" />

School address zipcode</b>:
<input type="text" name="Address_zip" />

<?php
}
?>

I'm having issues with the following:

Code: [Select]
<?php
session_start();
$_SESSION['username']=$_POST['username'];
$_SESSION['password']=$_POST['password'];
if($_SESSION['username']=="username" && $_SESSION['password']=="password"){
if($_GET['product']=="add"){
$content.='
<p><label>Product Name:</label> <input type="text" name="product_name" size="30" />
<label>Product Price:</label> <input type="text" name="product_price" size="5" />
</p>
<p><label>Product Category:</label> <input type="text" name="product_category" size="30" /></p>
<p><label>Product Link:</label> <input type="text" name="product_link" size="30" /></p>
<p><label>Product Image:</label> <input type="text" name="product_image" size="30" /></p>
<p><label>Product Tag:</label> <input type="text" name="product_tag" size="30" /></p>
<p><label>Product Keywords:</label> <input type="text" name="keyword" size="30" /></p>
<p><label>Product Features:</label><br />
<textarea name="product_features" rows="10" cols="60"></textarea>
</p>
<p><label>Product Pros:</label><br />
<textarea name="product_pros" rows="5" cols="30"></textarea>
</p>
<p><label>Product Cons:</label><br />
<textarea name="product_cons" rows="5" cols="30"></textarea>
</p>
<p><label>Product Description:</label><br />
<textarea name="product_description" rows="10" cols="60"></textarea>
</p>
<p><label>Product Notes:</label><br />
<textarea name="product_notes" rows="5" cols="30"></textarea>
</p>
';
$logout='<div><a href="./acp_admincp.php?log-out">Log-Out</a></div>';
}
elseif($_GET['product']=="view"){
}
else{
$content.='
<a href="./admincp.php?product=add">Add New Product</a>
<br />
<a href="./admincp.php?product=view">View Products</a>
';
}
}
elseif(isset($_GET['log-out'])){
session_start();
session_unset();
session_destroy();
header("Location: ./admincp.php");
}
else{
$content='
<form action="./admincp.php" method="post">
<p><label>Username:</label> <input type="text" name="username" size="30" />';
$content.='</p>
<p><label>Password:</label> <input type="password" name="password" /></p>';
$content.='<p><input type="submit" value="Submit" name="Submit" /></p>
</form>';
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<base href="http://ghosthuntersportal.com/" />
<title>Ghost Hunter's Portal - Admin Control Panel</title>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<meta name="verify-v1" content="" />
<meta name="keywords" content="ghost, hunters, hunter, ghosts, spirit, spirits, paranormal, investigation, investigator, investigators, k2, emf, meter, kii" />
<meta name="description" content="Ghost Hunters Potal. Parnormal research equipment store." />
<meta name="author" content="Andrew McCarrick" />
<meta name="robots" content="index, follow"
<link rel="stylesheet" type="text/css" href="style.css" />
</head>
<body>
<img src="./logo.png" alt="Ghost Hunter's Portal Admin Control Panel" />
<br />
<div style="color: #AA44AA; font-size: 26px; margin-top: -30px; margin-left: 125px;">Admin Control Panel</div>
<?php
echo $logout;
echo $content;
?>
</body>
</html>

I can log-in, and get to the page with the two links on it. However, once I click one of the links it falls back to the log-in page, and it ends up being a never ending loop.

It's doing this:
Log-In --> Page with links ---> Log-In page again

Should be doing this:
Log-In --> Page with links --> Add Product page or View Products page

I can never get into the the actual sub page.

Just to be clear, the address bar actually shows product=add or product=view, but it still shows the log-in page.

Hello Everyone,
I have to change the if statements to a switch statement, in this game. Can anyone help? Thanks.

var checkKeyPressed = function (e) {
// Press key A or key D to make dog run to the left or right
// The running speed is specified by the step variable, 10 by default.
// If you replace 10 with a larger integer, the dog will run faster.

    //press A, dog runs left
    if (e.keyCode == "65") {
        if (prex[0] > 5) {
            prex[0] = prex[0] - step;
        }
    }
    //press D, dog runs right
    if (e.keyCode == "68") {
        if (prex[0] < right) {
            prex[0] = prex[0] + step;
        }
    }
};