PHP - Preg_replace() Issue

im working on a php syntax highlighter for a bbeditor. basically all text within code tags will be placed into the function parse_code().

It works fine until i add the code to instantiate a class within the tags. This is supposed to just be a string but it looks like the 'e' modifier of preg_replace is recognising the code as php and executing it.

Is there any way around this?

Heres the regex:

Code: [Select]
'|\[code=(.*?)\](.*?)\[\/code\]|sie',


'self::parse_code("\\1", "\\2")',

and the parse_code method


public static function parse_code($code, $content)
    {
        $words = explode(' ', $content);
        
        dump($words);
        
        $keywords = array(
            'php_words' => array(
                'function',
                'echo',
                'class',
                'new',
                ),
        );

        foreach($words as $key => $value)
        {
            foreach($keywords as $group => $array)
            {
                foreach($array as $keyword)
                {
                    $words[$key] = preg_replace('|'.$keyword.'|si', '<span class="'.$group.'">'.$keyword.'</span>', $words[$key]);
                }
            }
            
            $words[$key] = preg_replace("|\\'(.*?)\\'|si", '<span class="string">\'\\1\'</span>', $words[$key]);
        }

        $content = implode(' ', $words);
        
        $lines = explode("\n", $content);
        
        unset($lines[0]);
        
        for($i=1; $i<count($lines); $i++)
        {
            $lines[$i] = '<p class="line_number">'.$i.'. </p>'.$lines[$i];
        }
        
        $content = implode("\n", $lines);

        return stripslashes('<blockquote class="code"><div class="code_header"><p>'.$code.'</p></div><div class="code_content"><p>'.$content.'</p></div></blockquote>');
    }

I am trying to pull out the image HTML tag but its not working as expected.
Here is what I am doing
   $removeimagetag='/<a href/';
   $replacwith = "illegal";
$_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']);

in the 'descr' there is a <a href="http://s635.photobucket.com......
When it post it does not strip out the <a href
So the image is displayed.

I tried a modified version to test to see if it work that looked like this.

   $removeimagetag='/goofy/';
   $replacwith = "illegal";
$_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']);

When the word goofy appears in the text then its replaced with the word illegal,

Also I would like to make it so that it replaces the entire line from the <a href....... to the </a> with a phrase that says "this feature is not allowed"  rather than just the part in the front...the <a href.

Any help you can be will be greatly appreciated.

Hi everyone,

how do i add and ampersand symbol into preg_replace

preg_replace("/[^a-zA-Z0-9\s\-\'\,\.\_]/"

where do i place the symbol? &

im trying to do a complex(i think) prg replace but i keep getting the error:

Code: [Select]
Failed evaluating code: $lang->showing-1,1
the code i am trying to replace is:

Code: [Select]
<asf: lang[showing-<asf: var[num_report_alerts]>,<asf: var[num_report_alerts]>]>
and the preg_replace is:

Code: [Select]
$content = preg_replace('|\<asf: lang\[(.*?)-(.*?)\]\>|e', '$lang->replace_vars($lang->//1, array(\\2))', $content);
its supposed to take everything inside <asf: lang[]> and echo \\1 which would be "showing" and then add \\2 into an array which would be "array(1,1)".

So the output would be showing 1 of 1.

Anyone know where im going wrong?

I'm trying to search a string for all occurences of a pattern, then append text after that pattern.  The example is:   SUM("foo") as "bar"   and have it display as:   SUM("foo") over() as "bar"   The "SUM" could be any SQL aggregate and be case insensitive.  So For bonus points, let's say the valid aggregates are  array('SUM', 'MAX', 'MIN', 'AVG').  My plan right now is to figure it out for SUM, then loop it replacing the aggregate.   This is what I have so far... and it is not working.   $l= 'SUM("foo") as "bar"'; $l=preg_replace('/([^"]+")/','\0 over()',$l);   Thanks,   Ryan