PHP - Admin Edit All Users
I need to know how to allow admin to essentially be "all users" in otherwords, edit everyones profile and not just their own. Tell me what codes would be helpful and i will send them on in. By the way, i do have a script that allows members to edit own profile.
Similar Tutorialshello, so i have a php login area for my clients... when i register a client it sets the user level to 1 admin user level is 9 any user whose level i >9 it redirect loops between the directory www.domain.com/ClientArea/ i changed that users level to 9, to see if it would log in, and it did fine... so i am a bit stuck as to where the problem is? here are some code snippets you'll need to help me if you can:) process.php (where the form is sent) function procLogin(){ global $session, $form; /* Login attempt */ $retval = $session->login($_POST['user'], $_POST['pass'], isset($_POST['remember'])); /* Login successful */ if($retval){ header("Location: ../ClientArea/"); } /* Login failed */ else{ $_SESSION['value_array'] = $_POST; $_SESSION['error_array'] = $form->getErrorArray(); header("Location: ../ClientArea/?login=failed"); } } session.php (where the magic happens) its inc into the process.php and inc into the index.php of clientarea /** * startSession - Performs all the actions necessary to * initialize this session object. Tries to determine if the * the user has logged in already, and sets the variables * accordingly. Also takes advantage of this page load to * update the active visitors tables. */ function startSession(){ global $database; //The database connection session_start(); //Tell PHP to start the session /* Determine if user is logged in */ $this->logged_in = $this->checkLogin(); /** * Set guest value to users not logged in, and update * active guests table accordingly. */ if(!$this->logged_in){ $this->username = $_SESSION['username'] = GUEST_NAME; $this->userlevel = GUEST_LEVEL; $database->addActiveGuest($_SERVER['REMOTE_ADDR'], $this->time); } /* Update users last active timestamp */ else{ $database->addActiveUser($this->username, $this->time); } /* Remove inactive visitors from database */ $database->removeInactiveUsers(); $database->removeInactiveGuests(); /* Set referrer page */ if(isset($_SESSION['url'])){ $this->referrer = $_SESSION['url']; }else{ $this->referrer = "/"; } /* Set current url */ $this->url = $_SESSION['url'] = $_SERVER['PHP_SELF']; } /** * checkLogin - Checks if the user has already previously * logged in, and a session with the user has already been * established. Also checks to see if user has been remembered. * If so, the database is queried to make sure of the user's * authenticity. Returns true if the user has logged in. */ function checkLogin(){ global $database; //The database connection /* Check if user has been remembered */ if(isset($_COOKIE['cookname']) && isset($_COOKIE['cookid'])){ $this->username = $_SESSION['username'] = $_COOKIE['cookname']; $this->userid = $_SESSION['userid'] = $_COOKIE['cookid']; } /* Username and userid have been set and not guest */ if(isset($_SESSION['username']) && isset($_SESSION['userid']) && $_SESSION['username'] != GUEST_NAME){ /* Confirm that username and userid are valid */ if($database->confirmUserID($_SESSION['username'], $_SESSION['userid']) != 0){ /* Variables are incorrect, user not logged in */ unset($_SESSION['username']); unset($_SESSION['userid']); return false; } /* User is logged in, set class variables */ $this->userinfo = $database->getUserInfo($_SESSION['username']); $this->username = $this->userinfo['username']; $this->userid = $this->userinfo['userid']; $this->userlevel = $this->userinfo['userlevel']; $this->firstname = $this->userinfo['firstname']; $this->lastname = $this->userinfo['lastname']; $this->company = $this->userinfo['company']; $this->tel = $this->userinfo['tel']; $this->address = $this->userinfo['address']; $this->email = $this->userinfo['email']; return true; } /* User not logged in */ else{ return false; } } /** * login - The user has submitted his username and password * through the login form, this function checks the authenticity * of that information in the database and creates the session. * Effectively logging in the user if all goes well. */ function login($subuser, $subpass, $subremember){ global $database, $form; //The database and form object /* Username error checking */ $field = "user"; //Use field name for username if(!$subuser || strlen($subuser = trim($subuser)) == 0){ $form->setError($field, "* Username not entered"); } else{ /* Check if username is not alphanumeric */ if(!eregi("^([0-9a-z])*$", $subuser)){ $form->setError($field, "* Username not alphanumeric"); } } /* Password error checking */ $field = "pass"; //Use field name for password if(!$subpass){ $form->setError($field, "* Password not entered"); } /* Return if form errors exist */ if($form->num_errors > 0){ return false; } /* Checks that username is in database and password is correct */ $subuser = stripslashes($subuser); $result = $database->confirmUserPass($subuser, md5($subpass)); /* Check error codes */ if($result == 1){ $field = "user"; $form->setError($field, "* Username or password incorrect"); } else if($result == 2){ $field = "pass"; $form->setError($field, "* Username or password incorrect"); } /* Return if form errors exist */ if($form->num_errors > 0){ return false; } /* Username and password correct, register session variables */ $this->userinfo = $database->getUserInfo($subuser); $this->username = $_SESSION['username'] = $this->userinfo['username']; $this->userid = $_SESSION['userid'] = $this->generateRandID(); $this->userlevel = $this->userinfo['userlevel']; /* Insert userid into database and update active users table */ $database->updateUserField($this->username, "userid", $this->userid); $database->addActiveUser($this->username, $this->time); $database->removeActiveGuest($_SERVER['REMOTE_ADDR']); /** * This is the cool part: the user has requested that we remember that * he's logged in, so we set two cookies. One to hold his username, * and one to hold his random value userid. It expires by the time * specified in constants.php. Now, next time he comes to our site, we will * log him in automatically, but only if he didn't log out before he left. */ if($subremember){ setcookie("cookname", $this->username, time()+COOKIE_EXPIRE, COOKIE_PATH); setcookie("cookid", $this->userid, time()+COOKIE_EXPIRE, COOKIE_PATH); } /* Login completed successfully */ return true; } Hi, I'm very new to php/mysql, but for a project I'm working on I need to create users that are admins, and normal users. The admins would be able to post news stories, and delete user accounts. Whereas the users would just be able to comment on the news stories. I'm just wondering how I would create a normal 'register' page for both, which has the same fields, but somehow creates some people as admins, and others as normal users... with the ability to limit who can become an admin, so not everyone can register as one. I'm not sure how I would achieve this, or even know how to do it. Does anyone know any tutorials or code on how to achieve this? Your help is greatly appreciated, Thanks. Sir/ma'am,
With the script I'm using to run my website, I've been trying to add an additional feature for the users to add/edit. I'll try to provide as much info as I can, hopefully it'll help.
Here is the code I'm using to display the user's unique info from the db.
<a class="wallet-edit"><?php echo $_SESSION['simple_auth']['INFO']?></a>That displays the user's info from the column 'INFO' perfectly. It's also a js popup to a menu to where I'm hoping to add a single textbox to edit the INFO. The script uses a similar function to edit the password with a popup. I've tried modifying the code to edit the INFO column but it doesn't work. Here is the default code it has to edit the password. I'm not sure if it can be changed to edit another column or needs a new piece of code for that. // user edit $('body').on('click', '.username-edit', function() { $('#modal').html(' '); var output = '<div class="modal-content"><h5><?php echo lang::get("Change password")?></h5><hr />'; output += '<h5><?php echo lang::get("New password:")?></h5><input type="password" name="password" id="password" value="" class="text ui-widget-content ui-corner-all" />'; output += '<h5><?php echo lang::get("Confirm password:")?></h5><input type="password" name="password2" id="password2" value="" class="text ui-widget-content ui-corner-all" />'; output += '</div>'; output += '<div class="modal-buttons right">'; output += '<button id="confirm-button" type="button" class="nice radius button"><?php echo lang::get("Change")?></button>'; output += '</div>'; output += '<a class="close-reveal-modal"></a>'; $('#modal').append(output); $('#second_modal').hide(); $('#modal').reveal(); $('#confirm-button').click(function(){ $('#password').css('border-color', '#CCCCCC'); $('#password2').css('border-color', '#CCCCCC'); var password = $('#password').val(); var password2 = $('#password2').val(); if(typeof(password) === 'undefined' || password == ''){ $('#password').css('border-color', 'red'); return false; } if(password != password2){ $('#password2').css('border-color', 'red'); return false; } password_data = encodeURIComponent(password); $.post("<?php echo gatorconf::get('base_url')?>", { changepassword: password_data} ).done(function(data) { // flush window.location.href = '<?php echo gatorconf::get('base_url')?>'; }); }); });If the code above can be edited to work with what I'm trying to do, it of course only needs one textbox and doesn't have to be confirmed by a second input. Please help! Thanks! hi i was wondering how i would make a website that allowed a user to login and edit there website ... like im a hoster and they can have a webpage on my server... how would i do this? allow them to create a database , and use all types of code? please help me this is important , if i didnt explain good enough please tell me Hai..
currently i am developing client dashboard using php/mysql.Here is my problem i need to create a tab named as notes.Using this tab the logged in users can add a new note or edit his existing note and save as text file.. Hello
I am trying to work out how many regular users I have to my site and how long those users tend to be users..
So, I have a table that logs every time a user visits my site and logs in, it stores the date / time as a unix timestamp and it logs their user id.
I started by getting the id's of any user who logs in more than 5 times in a specified period, but now I want to extend that...
SELECT userID as user, count(userID) as logins FROM login_history where timestamp > UNIX_TIMESTAMP('2014-06-01 00:00:00') and timestamp < UNIX_TIMESTAMP('2014-07-01 00:00:00') group by user having logins > 5; hello. I need your help please. I'm building logistics website with user panel and admin panel. I've done all login and register forms. now I want to : admin can add package with: tracking number , weight , cost , and declaration form. user can fill declaration form after admin add package to user panel. then admin can see the declared form. is it possible in php? thank you in advance I just discovered that I have a major security flaw with my website. Anyone who logs in to the website can easily access other users information as well as delete and edit other users information just by changing the ID variable in the address bar. I have user ID Session started on these pages but still people can do anything they like with other users information just by editing the address bar. For example if your logged in in the address bar of www.mywebsite.com/delete_mystuff.php?id=5 and change the "5" say to a "9" then you will have access to user#9 information. Every important page that I have has this code: Code: [Select] session_start(); if (!isset($_SESSION['user_id'])) { // Start defining the URL. $url = 'http://' . $_SERVER['HTTP_HOST'] . dirname($_SERVER['PHP_SELF']); // Check for a trailing slash. if ((substr($url, -1) == '/') OR (substr($url, -1) == '\\') ) { $url = substr ($url, 0, -1); // Chop off the slash. } // Add the page. $url .= '/index.php'; ob_end_clean(); // Delete the buffer. header("Location: $url"); exit(); // Quit the script. } else { //Else If Logged In Run The Script if((isset($_GET['id'])) && (is_numeric($_GET['id']))) { $id = (int) $_GET['id']; } elseif ((isset($_POST['id'])) && (is_numeric($_POST['id']))) { $id = (int) $_POST['id']; } else { echo ' No valid ID found, passed in url or form element'; exit(); } What am I doing wrong? Please help if you know how to correct this. Many thanks in advance. Hallo I have a problem.
This is my code:
<?php include 'connect.php'; ?> <html> <head> <title>Admin Insert page!</title> </head> <body> <?php error_reporting(-1);ini_set('display_errors',1); if (isset($_POST['submit'])){ $name = $_POST['name']; $password = $_POST['password']; $result = mysql_query("SELECT * FROM users WHERE user='$name' AND password='$password'"); $num = mysql_num_rows($result); if($num == 0){ echo "Bad login, go <a href='login.php'>back</a>"; }else{ session_start(); $_SESSION['name'] = $name; header("Location: admin.php"); } }else{ ?> <form action='login.php' methody='post'> Username: <input type='text' name='name'/><br /> Password: <input type='password' name='password'/><br /> <input type='submit' name='submit' value='Login' /> </body> </html>I try to use console to find the problem but I didn't.... I know that there is some problem with $num Can somebody help me? Thank you. Edited by Artur, 19 October 2014 - 12:11 PM. I get this error: Code: [Select] Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\user\user.php on line 5 code: user.php: Code: [Select] <?php $get = (isset($_GET['id'])); //this means that user.php?id=1 would mean $get = 1. Note: This is not SQL Inject protected. $users = mysql_query("SELECT * FROM users WHERE id='".$get."'"); while ($row = mysql_fetch_array($users)) { echo ' Id = '.$row['id'].' Name = '.$row['name'].' Username = '.$row['username'].' Password = '.$row['password'].' Reg. on = '.$row['date'].' '; } ?> <html> <body> <form action='user.php' method='GET'> Username: <input type='text' value=''> <input type='submit' value='submit'> </form> <?php //what goes here? ?> </body> </html> Hey guys, I've set up a database with a login and logout script for my site.. There is a TINYINT value called admin and it either equals 1 or 0 depending on whether the user is an admin or not.. The registration script works perfectly to create the table value and the login script works fine for the site.. The question I had was if I wanted to add a link to the bottom of every page that said: Go to Administration Panel and make it only viewable by ADMINS I figured this little script would work.. Here would be the end of the page: Code: [Select] <br /> <center>Copyright © 2010 <a href="http://www.website.com">www.WEBSITE.com</a></center> <?php include('includes/start_admincheck.php'); ?> <center><a href="<?php echo $homedir .'admin.php'; ?>">Go to Administration Panel</a></center> <?php include('includes/end_admincheck.php'); ?> </body> </html> Inside start_admincheck.php I have: (NOTE: $cUsername refers to a setcookie and $cAdmin does as well.. They are defined on my Variable page included at the top.) Code: [Select] <?php include('variables/variables.php'); ?> <?php mysql_connect("$mysql_hostname", "$mysql_username", "$mysql_password") or die(mysql_error()); mysql_select_db("$mysql_database") or die(mysql_error()); if(isset($cUsername)) { $check = mysql_query("SELECT * FROM users WHERE username = '$cUsername'")or die(mysql_error()); while($info = mysql_fetch_array( $check )) { if (($cAdmin == 1) && ($info['admin'] == 1)) { ?> And this is the end_admincheck.php Code: [Select] <?php include('variables/variables.php'); ?> <?php } else die(); } } else die(); ?> ?> I get this Parse error thrown at the bottom of the page: Code: [Select] Parse error: syntax error, unexpected $end in /*******/includes/start_admincheck.php on line 15 Naturally I would checkout line 15 in start_admincheck.php, but normally when I get an $end error it is the last line of the code and leaves me lost.. Something I'm missing guys? As always, thanks in advance So i got my login down and the cookies, kinda set up my problem is how do i make the admin panle save the true/false in the string in settings.php id like do do it with a drop down menu to enable/disable it. any help? Code download Hey, in a nutshell the only thing in admin.php is the ability to moderate unapproved images, however, once approved, the "Approve Delete" links are still on screen. How it works is a user uploads an image, the filename is added to mysql and the image is added to uploads/ once I Approve an image, the image is then moved to img/ to display on the index.php (to prevent porn and anything that doesn't belong to the general public). I know what's happening, because I've got while loops to display the image while looping through the mysql database, so once the image is moved, the links are still on screen, displaying an "Approve Delete" for every image in the database. Also another thing that happens is the images on index.php are blank until approved. How can I work around this? Here is the index.php when an image hasn't been approved: http://www.xodiac.net/1.png And here is the admin.php displaying Approve and Delete once an image has been approved: http://www.xodiac.net/2.png Hello, Do you know where I can download a nice looking PHP admin dashboard for free? Thanks in advance for the help Any help would be greatly appreciated! <?php $host="localhost"; // Host name $username="user"; // Mysql username $password=""; // Mysql password $db_name=""; // Database name $tbl_name=""; // Table name mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $barcodeID=$_POST['barcode']; echo $barcodeID; $barcodeID = stripslashes($barcodeID); $barcodeID = mysql_real_escape_string($barcodeID); $sql="SELECT * FROM $tbl_name WHERE BarcodeID='$barcodeID'"; $result=mysql_query($sql); // Mysql_num_row is counting table row $count=mysql_num_rows($result); $count=mysql_num_rows($result); if($count==1){ $_SESSION['barcode'] = $barcodeSession; $_SESSION['userlevel'] = $row['Priority']; if($row['userlevel'] == "Admin") { header("location:AdminSection.php"); }else{ header("location:index.php"); } header("location:LoggedIn.php"); } else { header("location:index.php"); } ?> when the script has been run, I want it to redirect to either the user page or admin page depending on their priority level. if Priority field == "Admin" then go to admin page. Can you see anything missing? Thank You Hey, So i have an admin.php page that lists all of the users in the database and im wondering how i can add functions so the administrator can delete / ban the user from the webpage i'm not sure on how you would select the user?
Hello I am trying to add an IF statement to my login script so that if the username entered is 'admin' it directs to 'adminpage.php Here is my script: <?php include ("connection.php"); session_start(); // Collect data from form and save in variables //See if any info was submitted $Username = $_GET['Username']; //Clean data - trim space $Username = trim ( $Username); //Check its ok - if not then add an error message to the error string if (empty($Username)) $errorString = $errorString."<br>Please supply Username."; //See if any info was submitted $Password = $_GET['Password']; //Clean data - trim space $Password = trim ( $Password); //Check its ok - if not then add an error message to the error string if (empty($Password)) $errorString = $errorString."<br>Please supply Password."; // Query to search the user table $query= "SELECT * FROM Users WHERE Username='$Username' AND Password='$Password'"; // Run query through connection $result = mysql_query ($query); $row = mysql_fetch_assoc($result); // if rows found set authenticated user to the user name entered if (mysql_num_rows($result) > 0) { $_SESSION["authenticatedUser"] = $Username; $_SESSION['UserID'] = $row['UserID']; // Relocate to the logged-in page header("Location: loggedon.php"); } else // login failed redirect back to login page with error message { $_SESSION["message"] = "Could not connect as $Username " ; header("Location: login.php"); } ?> Thank you Hi, I am new here 🙂 I have been learning PHP and am currently working on my own OOP MVC CMS. I am up to the stage where I would like to start working on the admin area, but I am not sure how best to organise things. Should I create admin specific Controllers and Models? In Views, should I create a sub directory Admin, and place all admin view templates within it? Are there any good books on OOP/MVC you would recommend?
i want that when someone post some comment on post that don't insert in table directly before inserting i can check and after approving then insert in table for which what i doo ?any IDea about this Hello, I have a problem with my website, Admin login page (http://www.tranceprofile.com/storeadmin/admin_login.php I can not login to my Admin controle panel. Login information: Username: Mitch Password: schuur111 Username: Admin Password: poopoo Can someone help me ? Here is my admin_login.php source code. If you need some other source code in my /storeadmin folder please tell Code: [Select] <?php session_start(); if (isset($_SESSION["manager"])) { header("location: index.php"); exit(); } ?> <?php // Parse the log in form if the user has filled it out and pressed "Log In" if (isset($_POST["username"]) && isset($_POST["password"])) { $manager = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["username"]); // filter everything but numbers and letters $password = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["password"]); // filter everything but numbers and letters // Connect to the MySQL database include "../storescripts/connect_to_mysql.php"; $sql = mysql_query("SELECT id FROM admin WHERE username='$manager' AND password='$password' LIMIT 1"); // query the person // ------- MAKE SURE PERSON EXISTS IN DATABASE --------- $existCount = mysql_num_rows($sql); // count the row nums if ($existCount == 1) { // evaluate the count while($row = mysql_fetch_array($sql)){ $id = $row["id"]; } $_SESSION["id"] = $id; $_SESSION["manager"] = $manager; $_SESSION["password"] = $password; header("location: index.php"); exit(); } else { echo 'That information is incorrect, try again <a href="index.php">Click Here</a>'; exit(); } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Admin Log In </title> <link rel="stylesheet" href="../style/style.css" type="text/css" media="screen" /> </head> <body> <div align="center" id="mainWrapper"> <?php include_once("../template_header.php");?> <div id="pageContent"><br /> <div align="left" style="margin-left:24px;"> <h2>Please Log In To Manage the Store</h2> <form id="form1" name="form1" method="post" action="admin_login.php"> User Name:<br /> <input name="username" type="text" id="username" size="40" /> <br /><br /> Password:<br /> <input name="password" type="password" id="password" size="40" /> <br /> <br /> <br /> <input type="submit" name="button" id="button" value="Log In" /> </form> <p> </p> </div> <br /> <br /> <br /> </div> <?php include_once("../template_footer.php");?> </div> </body> </html> |