PHP - Extend Variable From One Function To Another

Code: [Select]
class replayer extends users {
--SNIP--
public $islive = false;
--SNIP--
     function chat($id, $nick, $chat) {
          --SNIP--
          <-----------
     }
}
There's my code, I want to take the variable $islive from the above class and use it in the chat() function.

How would I do it? I've tried making it a global inside of the chat() function.

Help I am trying to pass a php variable into a javasript function. Here is my code.

<a href="<?php echo $row['track']; ?>" download="<?php echo $row['track']; ?>" onclick="myhit(<?php echo $row['track']; ?>)">Download</a>

<script>
function myhit(top){
alert(top);

}
</script>

the javascript function is never called

I dont know why I'm having so many problems with this. I need to get a variable that defined in an included file inside of a function I've got this

Inside file.php I've got the $variable1 and $variable2 defined (they're dynamic/different to each user)

include('file.php');

function foo() {
GLOBAL $variable1, $variable2;

echo $variable1;
echo $variable2;
}

foo();

Yet it outputs nothing?

If I Include file.php right inside of the function it works however. Any idea?

Hi,

Im trying to pass a variable ($in_this_instance) into, and then back out of a function.  The variable goes into the function no problem, and is echo'ed out fine.  However the echo after the close of the function, does not give anything out. 

Code: [Select]
$in_this_instance = 'boo';

function in_this_instance($data) {
global $in_this_instance;

echo $in_this_instance;

$in_this_instance = 'hoo';


$rep_val = '[front banner]';

    $test = strpos($data, $rep_val);
    if ($test === false) {
return $data;
    } else {
    return $data;;
    }
}

add_filter('the_content', 'in_this_instance');
echo $in_this_instance;

Could any one give me a pointer please?  Many Thanks!

Hello,

I have been trying to replace a variable's value inside a function in case it matches a certain criteria but I can't seem to get it right.

Let me give an example:

Code: [Select]
<?php

function replace_value($obj)
{
if($obj==1)
{
$obj=2;
}
}

$number = 1;
replace_value($number);

echo $number;
So how do I go about making $number = 2, because it still has a value of 1 even after I pas it through the function replace_value.

I have just started using functions, and have been following a few tutorials. I think im misunderstanding returns.

lets say i have the variables called $math1 an $math2

and i want to make $total = $math1 + $math2;

i then use return $total;

I then thought i could echo $total and it would work outside of the function but its giving me an error of an underfines variable.

Could anyone explain what im doing wrong please? thanks

Hello

I have a question (that i think i know the answer to).

What would be more efficient:

1. Create a global variable and run a php function and store result in there and call back the variable when needed

2. just echo the return value of the function when needed

Now im guessing that calling the function once and storing that in a variable rather than keep calling the function is more efficient

Hi All,

I have a function that i want to pass a variable into so that i can do some SQL on it.

The information that i want to pass into it is a data-id on a button that is used to trigger the function.

The button that will be clicked is this

<div class='modaltrigger btn btn-primary' data-id='$itemId' data-toggle='modal'>Manage</div>

This button is being created by another function.

I would like to know either how i pass the variable from one function to another or how i pass it from the data-id to the function in php.

Thanks in advance.

This seems really straight forward but I can't figure out why it's happening.  As a part of an account registration script, I'm randomly generating a password using a function called, generatePassword($length,$strength);
I hash the password (md5) before putting it in the database but I also email the non-hashed version to the user.  My problem is that each time I call the variable, it generates a new password so the one in the database does not match the one received by the user, $user_password_plain = generatePassword($length,$strength);
$user_password = md5($user_password_plain);
Is there a different way to store the variable so that I can access it later in the script and it will be the same?  I tried using a session variable but that didn't seem to work either.  Thanks!

Hi guys,

I have a trouble with my php snippet, when I insert the var function in the url bar something is like:

http://www.mysite.com/delete.php?favorites&id=0

or

http://www.mysite.com/delete.php?whateveritis&id=0

It doesn't get pass the favorites function to delete the id. It is the same things that it goes for each different function.

Here's the current code:

<?php
Code: [Select]
session_start();
    define('DB_HOST', 'localhost');
    define('DB_USER', 'mydbuser');
    define('DB_PASSWORD', 'mydbpass');
    define('DB_DATABASE', 'mydbtablename');

    $errmsg_arr = array();
    $errflag = false;

    $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
    if(!$link) {
  die('Failed to connect to server: ' . mysql_error());
    }

    $db = mysql_select_db(DB_DATABASE);
    if(!$db) {

die("Unable to select database");
    }

   function clean($var){

return mysql_real_escape_string(strip_tags($var));
    }
    $favorites = clean($_GET['favorites']);
    $id = clean($_GET['id']);

if($favorites && $id == ''){
   // both are empty
   $errmsg_arr[] = 'favorites id are missing.';
   $errflag = true;
}

    if($errflag) {
  $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
  echo implode('<br />',$errmsg_arr);
   }
   else {
$insert = array();
if(isset($_GET['id'])) {
    $insert[] = 'id = \'' . clean($_GET['id']) .'\'';
}
if(isset($_GET['favorites'])) {
    $insert[] = 'favorites = \'' . clean($_GET['favorites']) . '\'';
}

if($favorites && $id) {
   mysql_query("DELETE FROM favorites WHERE id='$id'");
   $deleted = mysql_affected_rows();
   if($deleted > 0)
   {
  echo "favorites channels is deleted";
   }
   else
   {
  echo("favorites is already deleted");
   }
 }
}
?>
If you do know how to get pass the favorites function, then please say so as i need your help.

Any advice would be much appreicated.

I am going through the tutorial found at http://goo.gl/69MeY and in my ultimate wisdom have decided to see if I can create a form, which you input some text, and then in the php file that handles the form in puts that variable into a text document using the fwrite function, basically creating a file from the website containing whatever text you put in. There is no specific purpose to this idea, I am just trying to implement everything I have learnt so far.

Form: http://pastebin.com/J62UHBeT
PHP Handler: http://pastebin.com/FHuaKkxD

I someone could point me in the right direction of what I am doing wrong it would be much appreciated

Thanks in advance

Michael

This is object programming right?

Is there a performance issue with this?

for example:

$notfications = ( blah blah ) ? : '';
then
if ($notificatiosn != blabla){
echo 'hey';
}

or....

$notifications = function(){
do my stuff here
then return 'hey';
}

Which way is faster or slower? Reason I Ask this is because I've been doing some object orientated programming in javascript, and didn't know you could do it in php.

I'd rather do the objective way so I don't have to use so many freaking variables above the regular way, lol.
Edited by Monkuar, 22 January 2015 - 12:22 PM.

I cant figure out how to add $recieved into this
needs to take place of time
hope someone knows how to do this
what im doing is adding in the UNIX time i want to offset


Code: [Select]
<?php $offset = date('m/d/Y/H:i:s', time()+$send1['time_offset']); ?>

I am currently using a javascript to redirect the page using a select tag and the onchange property. Each page calls a different function.

I want to be able to pass the <select> value to a variable that I can use within a php condition statement on the same page. This will generate the required output based on the <select> value. This way I dont require a seperate page for each query.

So onchange.... $select_value == this.value?

Then within my page:
Code: [Select]
if ($select_value == 'alpha') {
    get_query_alpha();
}
if ($select_value == 'bravo') {
    get_query_bravo();
}

This is my current set up...
Code: [Select]
<p>Order by:
<select name="query" id="query" onchange="gotourl(this.value)">
<option value="query1.php" >Sort by A</option>
<option value="query2.php" >Sort by B</option>
<option value="query3.php" >Sort by C</option>
<option value="query4.php" >Sort by D</option>
</select></p>

<table> <?php get_query_1();?> </table>

and js...
Code: [Select]
function gotourl(url){
window.location= url;
}
function selectsubject(){
alert("Please select a subject!");
}

Is there a simple way to do this? Thanks.

http://pastebin.com/DbHQSYd7

Been stumbling my way through OOP and seem to be understanding it for the most part (I think..) But I've got a couple questions / kinks that I can't seem to work out.

a) How do I return a variable from a class so that a different class has access to it (meta_data)
b) I'm getting a "$this" cannot be redefined error (which I know why, but I don't know how to fix))
c) How do I call a function from within one class, where the function resides in another class, AND pass it variables?

Any help would be greatly appreciated

I've tried to Google warrior A and I think I can figure that one out, but B and C are proving to be the real stumbling blocks.