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PHP - Hide Menu Button With Php Logon Script?
hey im doing a school project, where i need to limit the menu access to logged in people only.
is that even possible? Thanks for you help Similar TutorialsI have a php form in which ,on click of a edit button the contents of that table row will be displayed in a text area (which appears on the click of that edit button).Below the textarear i have a submit and delete button,i can perform any action.Ater performing the save or delete click the text area should be hidden. this is not happening,tried with js also. pasting the code below Code: [Select] <form name='add_title' method='post' action=''><?php echo "<br><br>"; if(isset($_POST['update'])) { if(isset($_GET['id'])) { $id = $_GET['id']; $comments=$_POST['comment']; $query1 = "update comments set comments='$comments' WHERE id = '$id' "; $result = mysql_query($query1); //$row=mysql_fetch_row($result); } } if(isset($_POST['delete'])) { if(isset($_GET['id'])) { $id = $_GET['id']; $comments=$_POST['comment']; $query1 = "delete from comments WHERE id = '$id' "; $result = mysql_query($query1); } } $query="select count(*) from comments"; $result =mysql_query($query); $row=mysql_fetch_row($result); $count= $row[0]; if($count!=0) { $query="select *from comments order by id desc"; $result=mysql_query($query); echo "<table width='700' align='center' border=1><tr bgcolor='green' align='center'><td><font color='black'> SlNo </font></td><td><font color='black'>Comment</font></td><td><font color='black'> Date Posted </font></td><td>Edit/Delete</td></tr></b>"; while($row = mysql_fetch_row($result)) { $d=$row['0']; $id=$row['0']; $name=$row['1']; $date_uploaded=$row['3']; echo "<td>$id</td><td>$name</td>". "<td>$date_uploaded</td>". "<td><a href='edit_comments.php?id=$id'>Edit </a></td>". "</tr>"; } if(isset($_GET['id'])) { $id = $_GET['id']; $query = "SELECT comments FROM comments WHERE id = '$id' "; $result = mysql_query($query); $row=mysql_fetch_row($result); echo"<center><table width='700' border='1'><tr><td > <textarea name='comment' cols='80' rows='10'>$row[0]</textarea> <td></tr><tr><td><a href='edit_comments.php?id=$id'><input type='submit' name='update' id='update' value='Save'></a><a href='edit_comments.php?id=$id'><input type='submit' name='delete' id='delete' value='Delete'></a> </td><td></td></center>"; } echo "</table>"; } else { echo "<table width='700' align='center'><tr bgcolor='white' align='center'><td><font color='red' size=2>No comments for you.</font></td></tr></table>"; } ?> Edit: Please use [code][/code] tags when posting code. Hi,
In reference to my first attached image, I have a form which displays two SELECT/drop-down fields (labeled "Store Name" and "Item Description".....and both of which pull-in values from two separate lookup/master tables, in addition to providing an additional option each for "NEW STORE" and "NEW ITEM").
Now, when first-run, and/or if "NEW STORE" and "NEW ITEM" are not selected from the drop-down's then the two fields in green ("New Store Name" and "New Item Name" are hidden, by means of the following code:
<div class="new-store-container" id="new-store-container" name="new-store-container" style="display:none;">
<div class="control-group">
<div class="other-store" id="new_store_name">
<?php echo standardInputField('New Store Name', 'new_store_name', '', $errors); ?>
</div>
</div>
</div>
Conversely, if "NEW STORE" and/or "NEW ITEM" are selected from the two drop-down's then one (or both) of the "New Name" fields are unhidden by means of the following two pieces of code, one PHP and the second JS:
<select class="store-name" name="store_id" id="store_id" onclick="toggle_visibility('store_id','new-store-container')">
<?php echo $store_options; ?>
<?php
if($values['store_id'] == "OTH")
{
echo "<option value='OTH' selected> <<<--- NEW STORE --->>> </option>";
}
else
{
echo '<OPTION VALUE="OTH"> <<<--- NEW STORE --->>> </OPTION>';
}
?>
</select>
function toggle_visibility(fieldName, containerName)
{
var e = document.getElementById(fieldName);
var g = document.getElementById(containerName);
if (e.value == 'OTH')
{
if(g.style.display == 'none')
g.style.display = 'block';
else
g.style.display = 'none';
}
}
All of that is working just fine. The problem I'm having is that when I click the "Create" button, after having left any one of the form fields blank, the two "New Name" fields are hidden again, which I don't want to happen i.e. I want them to remain visible (since the values of "store_id" and/or "item_id" are "OTH"), so that the user can enter values into one or both of them, without havng to click on the drop-down a second time in order to execute the "on-click" code.
The second attached image shows how the fields are hidden, after clicking "Create".
How can I achieve that? It would be greate if someone could cobble-up the required code and provide it to me, since I'm relatively new to this.
Thanks much.
Snap1.png 26.14KB
0 downloads
Snap2.png 149.47KB
0 downloads
I'm not sure how this would be done with php or something else, what I want is to have a button and when the button is pressed it creates a drop down menu and if it's pressed again then it creates a second drop down menu. I've been googling but haven't found anything yet if someone has an idea or a tutorial that they could direct me to that would be very helpful!!!! Any help is greatly appreciated, thanks in advance!!! Hi guys! I need a little help in PHP. I need to put into the PHP code functions which will insert to mysql database "jobs" STATUS=2 for Pause button and STATUS=1 for Run button PHP code: <?php include("include/header.php"); if(!isset($_SESSION["userlogin"])) { header("location: login.php"); exit(); } $edit=dbFetchArray(dbQuery("select * from `user_registration` where `email`='".$_SESSION["userlogin"]."'"),MYSQL_BOTH); $Id=base64_decode($_REQUEST['Id']); $up=mysql_fetch_array(mysql_query("select * from `jobs` where `id`='".$Id."'")); $status=stripslashes($up["highlighted"]); $name=stripslashes($up["title"]); $explode=explode(" ",$name); $tit=isset($explode[0])?$explode[0]:''; $col=isset($explode[1])?$explode[1]:''; $cat=isset($explode[2])?$explode[2]:''; $user=mysql_fetch_array(mysql_query("select * from `user_registration` where `email`='".$_SESSION["userlogin"]."'")); $fullname=stripslashes($user['fullname']); $customer_id=$user['id']; $current_balence=$user['current_balance']; if(isset($_POST["Button"])) { if(isset($_REQUEST["Available_positions"])) { $Available_positions=$_POST["Available_positions"]; if(strpos($Available_positions,'.')===false) { $pos=$Available_positions; $pos1=0; } else { $pieces = explode(".", $Available_positions); $pos=$pieces[0]; $pos1=$pieces[1]; } $Payment_per_task=$_POST["Payment_per_task"]; $hid=$_REQUEST['hid']; if($pos1>0) { ?> <script> alert('Job Posting Suspended'); window.location.href="edit_job.php?Id=<?=base64_decode($hid)?>"; </script> <? } else { dbQuery("update `jobs` set `wd2`='".$Available_positions."',`price`='".$Payment_per_task."' where `id`='".$hid."' and `email`='".$_SESSION["userlogin"]."'"); ?> <script> window.location.href="employer.php"; </script> <? } } $_SESSION['hid']=$hid; if($hid>0) { $_SESSION["success"]=''; } else { $_SESSION["error"]=''; } } else if(isset($_POST["Cancel"])) { $hid=$_REQUEST['hid']; dbQuery("update `jobs` set `status`='3' where `id`='".$hid."' and `email`='".$_SESSION["userlogin"]."'"); $resJ=dbFetchArray(dbQuery("select * from `jobs` where `id`='".$hid."' and `email`='".$_SESSION["userlogin"]."'"),MYSQL_BOTH); if($resJ["wd1"]!=$resJ["wd2"]) { $CJ= $resJ["wd2"] - $resJ["wd1"]; $CJFees = $CJ*$resJ["price"]; dbQuery("insert into `myaccount`(`email`,`amount`,`type`,`createdate`,`jobid`) values('".$_SESSION['userlogin']."','$CJFees','10',NOW(),'".$resJ["id"]."')"); $rescurbal=dbFetchArray(dbQuery("select * from `user_registration` where `email`='".$_SESSION['userlogin']."'"),MYSQL_BOTH); dbQuery("update `user_registration` set `current_balance`='".($rescurbal["current_balance"]+$CJFees)."' where `email`='".$_SESSION['userlogin']."'"); } ?> <script> window.location.href="employer.php"; </script> <? } ?> ... and the buttons code: ... Code: [Select] <br><input type="submit" value="Submit Campaign" <?php if($up["status"]=='3') { echo 'disabled="disabled"';} ?> name="Button"> <input type="submit" value="Finished Campaign" <?php if($up["status"]=='3') { echo 'disabled="disabled"';} ?> name="Cancel"><br />... I tried to do that, but I always get some error . Please help! This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=350924.0 I'm having problems creating a working submit button for a php script. The script is sitting on index.php and if I browse to that page it will send the email as required... great. So I though happy days I'll make a simple button for it... 6 hours later no joking. Firstly this is working php
<?php
require 'includes/PHPMailer.php';
require 'includes/SMTP.php';
require 'includes/Exception.php';
use PHPMailer\PHPMailer\PHPMailer;
use PHPMailer\PHPMailer\SMTP;
use PHPMailer\PHPMailer\Exception;
$mail = new PHPMailer();
$mail->isSMTP();
$mail->Host = "smtp.gmail.com";
$mail->SMTPAuth = "true";
$mail->SMTPSecure = "tls";
$mail->Port = "587";
$mail->Username = "Myemail@gmail.com";
$mail->Password = "Pass";
$mail->Subject = "Test email using PhPmailer";
$mail->setFrom("Myemail@gmail.com");
$mail->isHTML(true);
$mail->addAttachment('img/LifesaverFootage.mp4');
$mail->Body = "<h1>This is a HTML heading</h1></br><p>Title</p>";
$mail->addAddress("myemail@gmail.com");
if ($mail->Send() ) {
echo "Email sent..!";
}
else{
echo "Error..!";
}
$mail->smtpClose();
?>
Now I've been at this with everything but a blow torch these are some attempts below. I've also tried to just href to the page. All that happens is it creates another copy of the index.php file as if it were a download. The last thing I wanted to do was wrap this up as a function and I wanted to try something to do with Isset. But it won't even load the page if I define it as a function and then call it. I know I'm defining and calling the function correctly as I can do an echo function. Surely it couldn't be this hard. I mean all the thing has to do is dang trigger the page for goodness sake. Lol sighhhhhhh...Please help
<!--
</body> I have a PHP script that has hyperlinks on that allow for the user to go to different pages, and I have managed to mainly get the hyperlinks to be button based ones, except on one of the pages, an error message appears, reading: Parse error: syntax error, unexpected '<' in C:\xampp\htdocs\congrats.php on line 58 However, I do not see what the problem is. My congrats.php script is: Code: [Select] <!--Here, I am creating a header and title (for the webpage) with the use of the <head> and <title> HTML tags. The title given to the webpage is Login Details. I then am using the </title> and </head> HTML tags in order to stop the creation of the title and header of the webpage--> <head><title>Login Details</title> <link rel="stylesheet" type="text/css" a href="/rcm/stylesheet.css"> </head> <!--Here, I am starting a PHP script--> <?php //Here, I am creating two variables called $loginname and $loginpassword that are being assigned the values of what is entered into and posted from the text box called name and the password box called pass in the loginform.php webpage $loginname=$_POST['name']; $loginpassword=$_POST['pass']; //Here, an IF statement is being created and the empty keyword is being used to state that if the value assigned to the $loginname and the $loginpassword variables is empty (i.e. the 'name' text box and the 'pass' password box on the loginform.php page are both left empty), then the echo keyword is being used to help write a string to inform the user that they have not entered in a username or a password and a link back to the loginform.php page is provided to them to click on and the exit function with no arguments in the parameters is being used to exit the script if (empty($loginname) && empty($loginpassword)) { echo "You have not entered in a username or password"; echo"<br><a href=\"loginform.php\">Click here to try to log in again</a>"; exit(); } //Here, an elseif branch of the IF statement is being created and the empty keyword is being used to state that if the value assigned to the $loginname variable is empty (i.e. the 'name' text box on the loginform.php page is left empty), then the echo keyword is being used to help write a string to inform the user that they have not entered in a username and a link back to the loginform.php page is provided to them to click on and the exit function with no arguments in the parameters is being used to exit the script elseif (empty($loginname)) { echo "You have not entered in a username"; echo "<br><a href=\"loginform.php\">Click here to try to log in again</a>"; exit(); } //Here, an elseif branch of the IF statement is being created and the empty keyword is being used to state that if the value assigned to the $loginpassword variable is empty (i.e. the 'pass' password box on the loginform.php page is left empty), then the echo keyword is being used to help write a string to inform the user that they have not entered in a password and a link back to the loginform.php page is provided to them to click on and the exit function with no arguments in the parameters is being used to exit the script elseif(empty($loginpassword)) { echo "You have not entered in a password"; echo"<br><a href=\"loginform.php\">Click here to try to log in again</a>"; exit(); } //Here, an elseif branch to the IF statement is being created and the empty keyword is being used to state that if the value assigned to the $loginname and the $loginpassword variables is incorrect (i.e. the 'name' text box and the 'pass' password box on the loginform.php page are both left incorrectly filled in), then the echo keyword is being used to help write a string to inform the user that they have not entered in a correct username and password and a link back to the loginform.php page is provided to them to click on and the exit function with no arguments in the parameters is being used to exit the script elseif (($loginname != "mrjones")&& ($loginpassword != "January")) { echo "You have entered an incorrect username and password"; echo"<br><a href=\"loginform.php\">Click here to try to log in again</a>"; exit(); } //Here, an elseif branch to the IF statement is being created and the empty keyword is being used to state that if the value assigned to the $loginname variable is incorrect and the value assigned to the $loginpassword variable is ccorrect (i.e. the 'name' text box on the loginform.php page was filled in incorrectly and the 'pass' password box on the loginform.php page was filled in correctly), then the echo keyword is being used to help write a string to inform the user that they have not entered in a correct username and a link back to the loginform.php page is provided to them to click on and the exit function with no arguments in the parameters is being used to exit the script else if (($loginname !="mrjones") && ($loginpassword == "January")) { echo "You have entered in an incorrect username"; echo"<br><a href=\"loginform.php\">Click here to try to log in again</a>"; exit(); } //Here, an elseif branch to the IF statement is being created and the empty keyword is being used to state that if the value assigned to the $loginname variable is incorrect and the value assigned to the $loginpassword variable is ccorrect (i.e. the 'name' text box on the loginform.php page was filled in correctly and the 'pass' password box on the loginform.php page was filled in incorrectly), then the echo keyword is being used to help write a string to inform the user that they have not entered in a correct password and a link back to the loginform.php page is provided to them to click on and the exit function with no arguments in the parameters is being used to exit the script elseif (($loginname =="mrjones") && ($loginpassword != "January")) { echo "You have entered in an incorrect password"; echo"<br><a href=\"loginform.php\">Click here to try to log in again</a>"; exit(); } //Here, an else branch to the IF statement is being created so as to essentially state that if all of the other branches of the IF statement above are passed through, then it means that the user managed to successfully log on and the echo keyword is being used to help write a string congratulating the user that they managed to log in and a link is provided for them to log off and go back to the loginform.php page and the exit function with no arguments in the parameters is being used to exit the script else { echo "<h1>Log In Successful!</h1>"; <form action="amendfile2.php" method="post"> <input type="submit" value="Amend to file"> </form> <form action="viewfile3.php" method="post"> <input type="submit" value="View Web Blog"> </form> <form action="loginform.php" method="post"> <input type="submit" value="Click here to go to the Log In Screen"> </form> } //Here, the PHP script is being ended ?> Any help is appreciated! I have a problem that is particular to the FF and Safari browsers. I do not see the problem in IE. Again, I am very new to php programming - no formal training - just a hacker. I have a web page that presents a form with a results table and a SUBMIT button. Each time the button is selected I want to present one of two different tables of results. Everything works fine the first time I hit the SUBMIT button. The page updates and shows the second table. But on the next SUBMIT the script that swaps things around is executed twice in FF and Safari vs. one time like in EI. This results in the same result table being displayed over and over vs. the two switching back and forth. Any idea what could be going wrong in these two browsers? Here's my swap script: Code: [Select] <?php session_start(); // This script reverses the coin flip to see what would happen the other way if ($_SESSION['Coin_Flip'] == "heads") { //switch to tails $_SESSION['Coin_Flip'] = "tails"; include ('tails_algo.php'); } elseif ($_SESSION['Coin_Flip'] == "tails") { $_SESSION['Coin_Flip'] = "heads"; include ('heads_algo.php'); } include ('kind-comp_result.php'); ?> You would think the answer would be all over the Internet and easy to find, but it’s not. I have searched many times, and in all the multitude of search results I have still never found an adequate usable answer. The MOST you ever find is someone saying how easy it is with PHP, but they don’t tell you how, even when the person they are answering asks them (odd). You can be that one in a billion person who finally answers it for real and helps someone out. I have a simple HTML form with data fields first_name, last_name, email, phone, country, a few hidden inputs, and a single submit button, like so: (Please note: the method is GET, not Post.) <form action="https://MyDomainOnMyServer.com/MyPHPScript.php”> <input type="text" name="first_name" value="" /> <input type="text" name="last_name" value="" /> <input type="text" name="email" value="" /> <input type="text" name="phone" value="" /> <input type="hidden" name="type" value="type123"> <input type="hidden" name="project" value="new123"> <select required name="country"> <option value="">Choose your country</option> <option value="US">United States</option> <option value="CA">Canada</option> <option value="GB">United Kingdom</option> <option value="Many More">Many More Countries</option> </select> <input type="submit" value="Submit Form" /> </form> NOTE: Originally, the form action would have been: action="https://TheirExampleDomainOnTheirRemoteServer.com/TheirRemotePHPScript.php" name="form1234" Upon clicking the single submit button only, what I need to have happen is this: 1. Send me an email to whatever@whatever.tld containing all the form submission data 2. Place the form submission data into a MySQL database having the corresponding data fields 3. Send the form submission contents including the hidden input values to "https://TheirExampleDomainOnTheirRemoteServer.com/TheirRemotePHPScript.php" name="form1234" AS IF that had remained set as the original form action to begin with So basically what I’m trying to obtain is the cleanest possible PHP script that will do those three things, which is essentially what others have asked for over the years in search results I have found, but no one has ever provided it in a clear instance that works. If I can just see such a script, I should be able to see how it works and then do what I need. Thanks. Reply Hi, First of all, this is not a spam. Someone with the username Pikachu2000 removed it thinking it was a spam so now I have to post it again. I really need you help fixing this problem. Anyway, I'm building a site where I used a "php include once" for the navigation menu. I was able to show the active pages when they don't have sub pages but I can't seem to show the active sub pages. I've been trying for days and nothing I try seems to work! I'm sure some people have asked this before but I can't find any forums that describe how to do this with sub navs rather then just the main nav buttons. The coding is below along with a link to one of the sub pages in the site I'm working on. The problem is with the sub pages under "Our Coffee Farm". Thanks for reading my post. Website Link: http://vanessajohodesigns.com/sarpa/the_farm/plantation.php before DOCTYPE: <?php $thisPage="The Plantation"; ?> after body tag: <?php include_once("../includes/nav.php");?> nav.php include once file: <div class="arrowsidemenu"> <div<?php if ($thisPage=="Home") echo " class=\"active\""; ?>> <a href="../index.php">Home</a></span></div> <div class="menuheaders"><a>Our Coffee Farm</a></div> <ul class="menucontents"> <li<?php if ($thisPage=="The Plantation") echo " class=\"active\""; ?>><a href="plantation.php">The Plantation</a></li> <li<?php if ($thisPage=="Blooming & Harvest") echo " class=\"active\""; ?>><a href="bloom_harvest.php">Blooming & Harvest</a></li> <li<?php if ($thisPage=="Coffee Processing") echo " class=\"active\""; ?>><a href="processing.php">Coffee Processing</a></li> </ul> <div<?php if ($thisPage=="About Us") echo " class=\"active\""; ?>> <a href="../about_us.php">About Us</a></div> <div<?php if ($thisPage=="Rainforest Alliance") echo " class=\"active\""; ?>> <a href="../rainforest_alliance.php">Rainforest Alliance</a></div> <div<?php if ($thisPage=="Social Commitment") echo " class=\"active\""; ?>> <a href="../social_commitment.php">Social Commitment</a></div> <div<?php if ($thisPage=="News & Events") echo " class=\"active\""; ?>> <a href="../news_events.php">News & Events</a></div> <div<?php if ($thisPage=="Web Cameras") echo " class=\"active\""; ?>> <a href="../webcams.php">Web Cameras</a></div> <div<?php if ($thisPage=="Photo Gallery") echo " class=\"active\""; ?>> <a href="../gallery.php">Photo Gallery</a></div> <div<?php if ($thisPage=="Contact Us") echo " class=\"active\""; ?>> <a href="../contact_us.php">Contact Us</a></div> <!--end .arrowsidemenu --></div> Friends I am new to php and i have to submit my coursework in php by 3rd dec, I stuck at one place where i have to upload multiple photo and one can see all the photo he has uploaded and can edit or delete that photo so i have done uploading now i am showing those pics in table by running loop and generating tr and td but now i have two buttons with each row edit and delete now when i clicked on one delete or edit that pic should be delete or give text box to edit description of pic, Please help me how to do that....... If you look at this form: kmkwebdevelopment.com/formtest/upload.php you will see that when you click on the "add another upload box" button, instead of it adding another upload box, it is submitting the form for some reason. Can anyone see where the error lies? Relevant snippet of code below: <?php //deafult number of upload boxes $upload_quant = 4; //if the user increased the number of boxes if(isset($_POST['increase_upload'])) { //increasing the number of upload boxes $upload_quant = $_POST['previous_upload'] + 1; } $upload_quantity = $_POST['previous_upload']; //getting all the names into an array $uplaoded_array = array(); for($i=0;$i<$upload_quantity;++$i) { $ii = $i+1; $upload_name = 'upload'.$ii; $get_upload_name = $_POST['$upload_name']; array_push($uplaoded_array,$get_upload_name); } ?> <form class="uploadform" action="<?php echo $_SERVER["PHP_SELF"] ?>" method="post" enctype="multipart/form-data" onSubmit="return CheckForm(this);"> <?php IsThereErrors("0", $_iserrors); ?> <input type="hidden" name="_referer" value="<?php echo $_referer ?>"> <input type="hidden" name="_next_page" value="1"> <p class="form_expert_style"><input name="URL" type="text" value=""/></p> <table> <tr> <td>First Name *</td> <td><input type='text' size='30' name='firstname' onBlur="FieldBlur(this.name+'_tooltip')" <?php mark_if_error("firstname", "") ?> value="<?php echo isset($_values["firstname"]) ? htmlspecialchars($_values["firstname"]) : "" ?>"></td> </tr> <tr> <td>Last Name *</td> <td><input type='text' size='30' name='lastname' onBlur="FieldBlur(this.name+'_tooltip')" <?php mark_if_error("lastname", "") ?> value="<?php echo isset($_values["lastname"]) ? htmlspecialchars($_values["lastname"]) : "" ?>"></td> </tr> <tr> <td>E-mail *</td> <td><input type='text' size='30' name='email' onblur="FieldBlur(this.name+'_tooltip')" <?php mark_if_error("email", "") ?> value="<?php echo isset($_values["email"]) ? htmlspecialchars($_values["email"]) : "" ?>"></td> </tr> <tr> <td>Company Number *</td> <td><input type='text' size='30' name='companynumber' onBlur="FieldBlur(this.name+'_tooltip')" <?php mark_if_error("companynumber", "") ?> value="<?php echo isset($_values["companynumber"]) ? htmlspecialchars($_values["companynumber"]) : "" ?>"></td> </tr> <?php for($i=0;$i<$upload_quant;++$i) { $ii = $i+1; $upload_name = 'upload'.$ii; echo <<<_END <tr> <td>Upload $ii</td> <td><input class="image" type='file' size='30' name='$upload_name'></td> </tr> _END; } echo <<<_END <tr> <td> <input type="hidden" value="$upload_quant" name = "previous_upload"/> <input type="submit" name="increase_upload" value="Add another upload box" /> </td> <tr> <td><input type="submit" name="SubmitBtn" onClick="CheckForm1();" value="SUBMIT" /></td> </tr> </table> </form> _END; } ?> </html> <?php Thanks Does showing .php on the end of web pages pose any security risk? My websites uses mod_rewrites pretty extensively, e.g.
www.mysite.com/profiles/saranaclake www.mysite.com/subscribe/view-offers
However I still have a lot of web pages which are static pages that end with .php and I'm wondering if I should clean that up both for aesthetic reasons and for security...
Hi everyone! I've been working on a php script to replace links that contain a query with direct links to the files they would redirect to. Hi all I know this contains a bit of JavaScript but it comes from some dynamically created pages using php which are causing it an issue. Here's my scenario. I have a DB with locations, regions, jobtitles and names in it. My users can select from the DB a specific job title or a location. This can produce a report of information from a couple of people, up to over 100 (who can still be filtered by any of the above DB columns) I want to dynamically produce some JS buttons to show / hide any sections which are irrelevant to the user. eg I select by job title, it gives me all the managers, duty managers, staff, cleaners, etc from the DB for all locations. I then want 5 buttons to be on the page, each with a different region on it. (this I can do) I can dynamically label the divs around each of the user information. The issue I have is making the buttons do what I want. So if you press a button labelled "North West" it hides all records which are not from northwest region. Here's what I have so far, I just can't seem to get the functionality right as I know very little about JS. Code: [Select] <script language=javascript type='text/javascript'> function showdiv(pass) { var divs = document.getElementsByTagName('div'); for(i=0;i<divs.length;i++){ if(divs[i].id.match(pass)){//if they are 'see' divs if (document.getElementById) // DOM3 = IE5, NS6 divs[i].style.visibility="visible";// show/hide else if (document.layers) // Netscape 4 document.layers[divs[i]].display = 'visible'; else // IE 4 document.all.divs[i].visibility = 'visible'; } else { if (document.getElementById) divs[i].style.visibility="hidden"; else if (document.layers) // Netscape 4 document.divs[i].visibility = 'hidden'; else // IE 4 document.all.divs[i].visibility = 'hidden'; } } } </script> and then one my php has processed I get a record such as. Code: [Select] <div id='NEREGION'> <table border='1' > <tr><td colspan='4'>Glasgow </td></tr> <tr><td colspan='2' >Employee Name : **********</td><td >Employee Number : *****</td><td colspan='2'>Start Date 25th November 2002</td></tr> <tr><td colspan='3'> </td><td rowspan='3'><img src='image.php?ed=2063&y2007=1&y2008=1&y2009=0&y2010=0&y2011=0&forename=1234&surname=5436' height ='400px' width='350px'></td></tr><tr><td colspan='2'>20th June 2007</td><td> NFR Petrol Delivery - Refresher Course</td></tr><tr><td colspan='2'>2nd December 2008</td><td> Incremental Sales</td></tr></table></div> Any ideas? I have a particular PHP file which is publicly located, however, I don't want anyone but me to access. Below are my thoughts how to do so. Please comment.
Use an uncommon name, and definitely not index.php.
Either include a file called index.html in the same directory, or set up Apache not to show them using Options -Indexes, or maybe both for good measure.
Require some variable to be set to a given value in either the GET or POST array, and if not set, throw a 404 header and display the 404 missing file HTML. In my php web site the video player appears and plays the video. In Chrome you can right click on the player screen and choose 'inspect element' etc, but another choice is 'Copy video URL'. How can I block that, or hide (or disguise/rename) video URLs?
Hi all, Relitively new to PHP but am trying to code a site that dynamically creates urls using Joomla CMS. Basically I'd like a div to show on pages' url starts /component/.... but hide it if not. The urls of the pages on which the div is to be hidden start /index.php?. I've tried Code: [Select] <?php if (strpos($_SERVER['REQUEST_URI'], 'component') > 0) { echo '<div id=\"stuffdiv\">stuff</script></div>';} ?> only issue is... its always fasle hence the div never shows. If i replace > with >= its always true, and appears on all pages, even those not containing 'component'... Can someone tell me if this should work or if Im being really stupid? Thanks in advance! Tom Here is what is echoing the string "Resource id #1". However I do not know if it is the php or javascript that is outputting this. Can anyone tell me why this is showing and how to make it not show? PHP: Code: [Select] $directory = "Images/items/$product/"; //get all image files with a .jpg extension. $images = glob($directory . "*.jpg"); $imgone = $images[0]; $gallery = '<tr><td valign="top" align="center">'; foreach($images as $image) { $tn = explode("/", $image); $tnname = $tn[3]; $gallery .= '<a href="#" rel="'.$image.'" class="image" alt="Images/items/'.$product.'/large/'.$tnname.'"><img src="Images/items/'.$product.'/thumbs/'.$tnname.'" class="thumb" border="1" style="margin-bottom:7px;"/></a> '; } if(is_dir("Images/items/".$product)) $gallery .= "</td></tr><tr><td width='300'>".$link."<div id='image' class='bigimg' align='left'>"; if(is_dir('Images/items/'.$product)) $gallery .= '<img src="'.$imgone.'" border="0"/></div></a></td></tr>'; JS (jQuery) Code: [Select] $(function() { $(".image").click(function() { var image = $(this).attr("rel"); var large = $(this).attr("alt"); $('#image').hide(); $('#image').fadeIn('slow'); $('#image').html('<a href="' + large + '" ><img src="' + image + '"/></a>'); return false; }); }); It is possible to hide the data in the url?! I have something like this: ?action=viewArticle&articleid=1 |
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