PHP - Moved: Can't Render A Background Image

whenever i try to view the product page through my testing server it says

Data to render this page is missing.

and when i try to go to the product page through the index page it says

That item does not exist.

[attachment deleted by admin]

This topic has been moved to Other.

http://www.phpfreaks.com/forums/index.php?topic=354424.0

This topic has been moved to CSS Help.

http://www.phpfreaks.com/forums/index.php?topic=333585.0

This topic has been moved to HTML Help.

http://www.phpfreaks.com/forums/index.php?topic=352099.0

This topic has been moved to JavaScript Help.

http://www.phpfreaks.com/forums/index.php?topic=347166.0

Ok this has been driving me absolutely crazy. I have a script that gets called by Prototype's Ajax.Updater() class which should then update a div. It does update the div but a portion of what gets outputted doesn't render.

Code: [Select]

if (is_array($PROCESSED["associated_proxy_ids"]) && count($PROCESSED["associated_proxy_ids"])) {
foreach ($PROCESSED["associated_proxy_ids"] as $student) {
                if ((array_key_exists($student, $STUDENT_LIST)) && is_array($STUDENT_LIST[$student])) {
?>
<li class="user" id="audience_student_<?php echo $STUDENT_LIST[$student]["proxy_id"]; ?>" style="cursor: move;"><?php echo $STUDENT_LIST[$student]["fullname"]; ?><img src="<?php echo ENTRADA_URL; ?>/images/action-delete.gif" onclick="removeAudience('student_<?php echo $STUDENT_LIST[$student]["proxy_id"]; ?>', 'students');" class="list-cancel-image" /></li>
<?php
}
}
}
I've echoed from within the foreach and the following if and the $student variable does have a value, however I'll point out that it also doesn't render but that may be because its not a <li>, I'm not sure. Now, if I take that li element lin end output it outside of the foreach loop it renders just fine(once I substitute the $student variable for a known index of course). Inside the loop it doesn't. I can see it in the source code of the page but for some reason its not rendering. I'll put the output from the source of the page below, the top is the code output from within the loop and the bottom is from outside of the loop. The bottom renders as expected, the top doesn't.
Code: [Select]
<!--foreach li element:doesn't render-->
<li class="user" id="audience_student_2" style="cursor: move;">Hudson, Tom<img src="http://localhost/entrada/www-root/images/action-delete.gif" onclick="removeAudience('student_2', 'students');" class="list-cancel-image" /></li>

<!--non foreach li element:renders-->
<li class="user" id="audience_student_2" style="cursor: move;">Hudson, Tom<img src="http://localhost/entrada/www-root/images/action-delete.gif" onclick="removeAudience('student_2', 'students');" class="list-cancel-image" /></li>

They're identical.
I can't figure out for the life of me why this isn't working. Any help would be great.

now i am getting this error

( ! ) Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'talos342c'@'localhost' (using password: YES) in C:\wamp\www\myNewweb\storescripts\connect_to_mysql.php on line 19
Call Stack
# Time Memory Function Location
1 0.0008 380440 {main}( ) ..\index.php:0
2 0.0012 384880 include( 'C:\wamp\www\myNewweb\storescripts\connect_to_mysql.php' ) ..\index.php:11
3 0.0012 385528 mysql_connect ( ) ..\connect_to_mysql.php:19

This topic has been moved to JavaScript Help.

http://www.phpfreaks.com/forums/index.php?topic=317921.0

Hi there,    My friend asked me to help him perform a task today and I was completely stumped as to how I should complete it. Being someone who is reasonably experienced with PHP programming I didn't think I would find it absolutely impossible to complete, maybe hard, but not impossible. So I wondered if someone would now be able to explain to me in order to assist me in expanding my knowledge how to complete this task.    https://www.dropbox....B8M6cr_z7a?dl=0   Here is a link to the files he sent me, please ignore the C++ section.   If anyone could help / begin to give an explanation please fire away. I feel so bad about myself for NOT knowing that I'm now motivated to learn more!   Many thanks!

This topic has been moved to JavaScript Help.

http://www.phpfreaks.com/forums/index.php?topic=317523.0

I have a page that displays various articles. I would like to show a background image for each article. Let's say I have articles for beaches. I would like to have a beach photo. Airplane article, show airplanes, etc. How can I accomplish this.

This creates an image 1500x1500 pixels. But it creates it in black... how can i make it white.
And i have to use imagecreatetruecolor() not imagecreate().


<?php

$im = imagecreatetruecolor(1500,1500);


// Output the image to the browser
header('Content-type: image/jpg');

imagejpeg($im);
imagedestroy($im);
?>


Thanks!

I was wondering if there is any way to let visitor chose image background of div and store it in session so every page have same background? 

Hello   I am working on a site and the theme is a responsive theme but the header background is not resizing on mobile and tablets below is a link to the site

http://unitednews.sr/category/news/

each category / page has a unique header , this is what I have in css for category news

body.category-news  #header-wrap { background: url( http://unitednews.sr/wp-content/uploads/2014/10/Header_UnitedNews.jpg);
background-repeat:no-repeat;
}

Adding background size: cover does not work any idea ?
Edited by crawling, 13 November 2014 - 11:47 AM.