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Hi guys,

a few days i upgrade php from 5.1 to 5.2.16
all seem fine and last 2 days i start to find some bugs.
I use this code to get url var and pass from a form:
                <?php
  echo $_GET['id'];
?>            
                <input name="ids" type="hidden" id="ids" value="<?php $_GET['id'];?>" />

In the email i receive all data from the form, but not this that i get from the URL.

in code to send to email i just use:
$_POST[id] 

This work fine in 5.1 but not in this version.

anyone have an idea why?

Wipe

This topic has been moved to JavaScript Help.

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I am UPGRADING some old files to MySQLi and while doing so have decided to complete some leftover projects.

In this project, I was counting vegetables sold to customers that displayed a report displaying information like this:

There were 3 orders for carrots for 1 lbs. each
There were 2 orders for carrots for 2 lbs. each
There were 1 orders for carrots for 3 lbs. each

The code I used to generate the messages was:

while($row = mysqli_fetch_array($result)){
	echo "There were ". $row['COUNT(carrots)'] ." orders for carrots for ". $row['carrots'] ." lbs. each <br />";
}

At the time, I was going to call a separate script for carrots, potatoes, and celery.

Now, with my worldly advancement (or maybe not.. LOL) I realize I should be able to use the same single script and assign a variable to accommodate each vegetable item.

After declaring the $item = 'carrots'   I inserted it to test my theory.  I tested the output in stages and all seemed okay until I did this:

while($row = mysqli_fetch_array($result)){
	echo "There were ". $row['COUNT($item)'] ." orders for carrots for ". $row['$item'] ." lbs. each <br />";
}

Is there an issue with using a variable inside a $row?  Is there a syntax error (no error messages)?  Perhaps a MySQLi addition that is required?

The Wordpress Atahualpa theme does not appear to be compatible with php 7.2. I know very little about php. I get the following error message in my error log:
=====
[24-Jan-2019 22:14:03 UTC] PHP Warning: Declaration of Walker_Comment2::end_el(&$output, $comment, $depth, $args) should be compatible with Walker::end_el(&$output, $object, $depth = 0, $args = Array) in /home/armst5/public_html/MyBlog/wp-content/themes/atahualpa.3.2/atahualpa/functions/bfa_comment_walker.php on line 145
=======
What does this mean and can I fix it?

See below my website is showing like this

I think debian upgraded from php 7.3 or 4 to 8.0

I am wondering if I am missing some php packages if run php -v at terminal I get

php -v
PHP 8.0.7 (cli) (built: Jun  4 2021 23:17:30) ( NTS )
Copyright (c) The PHP Group
Zend Engine v4.0.7, Copyright (c) Zend Technologies
    with Zend OPcache v8.0.7, Copyright (c), by Zend Technologies

and if I run php -m at terminal i get

php -m
[PHP Modules]
calendar
Core
ctype
date
dom
exif
FFI
fileinfo
filter
ftp
gd
gettext
hash
iconv
json
libxml
mysqli
mysqlnd
openssl
pcntl
pcre
PDO
pdo_mysql
Phar
posix
readline
Reflection
session
shmop
SimpleXML
sockets
sodium
SPL
standard
sysvmsg
sysvsem
sysvshm
tokenizer
xml
xmlreader
xmlwriter
xsl
Zend OPcache
zlib

[Zend Modules]
Zend OPcache

 

 

 

I've been out of coding for about 4 years.  My client called and said that they upgraded his server and now nothing works.  I've don't done some reading and see that there are changes to queries.  I originally wrote the program using mysql_query which is now deprecated replaced with MySQLi and PDO_MySQL which I thought would be that simple.  Apparently not.  My code is below.  The error I get is

Fatal error: Call to undefined function MySQLi() in /home1/zipclick/public_html/marketingteamates.com/_ZABP_merchants/main-w.php on line 304

which leads me to believe that the upgrade is now solely object oriented.  

 

$result = MySQLi( "SELECT * FROM $users WHERE username = '$username'" )
or die("SELECT Error: ". mysqli_errno());
$num_rows = mysqli_num_rows($result);
 while ($row = mysqli_fetch_array($result))
  {
     extract($row);

}

 

I have 2 pages in my flash site that call some PHP files. The pages are a feedback page and a locator page. When my server went from PHP4 to PHP5 both pages stopped displaying the content. When I load the flash pages with Fiddler open, fiddler shows a 500 error on the PHP files that the flash is calling. I'm certain my database connections are good, file paths have not changed since the server maintenance, and I have .htaccess files except they are blank.

Can anyone advise what I can do to find where the problem is? I have the PHP code below that showed the 500 errors. Any help would be really appreciated.

This is the locator page:
Code: [Select]
<?php
include_once('db_connect.inc.php');


$query = "SELECT state FROM stores group BY state ORDER BY state";

$result = mysql_query($query);



if(mysql_num_rows($result)==NULL){

$r_string = '&error=1&msg=No Records Found.';

}else{

$r_string = '&error=0&n='.mysql_num_rows($result) . '&r_states=';
  
  $i = 0;
  $r='';
      while ($row = mysql_fetch_assoc($result)) {
   if($r!='') $r .= '||';
            $r .= $row['state'];
         $i++;
      }
  $r_string .= $r;
      // add extra & to prevent returning extra chars at the end
      $r_string .='&';
  
  
  }
  
   
echo $r_string;
 ?>

This is the feedback page:
Code: [Select]
<?php
include_once('inc/feedbackconn.inc.php');

echo '&rsult=';
$query = "SELECT * FROM messages where active!=0";
$result = mysql_query($query);
$num = @mysql_num_rows($result);
$cfeed=$_POST['sFeed'];
$cfeed--;
$query = "SELECT * FROM messages where active='1' ORDER BY id LIMIT " . $cfeed . ',1';
$result = mysql_query($query);
//$row = mysql_fetch_array($result);

if($num==NULL){

echo "No Records.";
exit();
}

 while($row = @mysql_fetch_array($result)){

      $b_name = stripslashes($row[strName]);
      $b_loc = stripslashes($row[strLocation]);
      $b_mes = stripslashes($row[strMessage]);
  $b_id = $row[id];
  $b_active = $row[active];

      $feedArray[] = array("name"=>$b_name,"location"=>$b_loc,"feedback"=>$b_mes,"id"=>$b_id,"active"=>$b_active);

      }



/* /////////////// DISPLAY THE RECORDS ///////////////// */
$numOfMessages = sizeOf($feedArray);

for($i=0;$i<$numOfMessages;$i++){


//------------------------------------------------------------------
    //echo $feedArray[$i]['id']."<br>\n";
echo '<b><i>' . $feedArray[$i]['feedback']."</i><br><br>";
echo $feedArray[$i]['name']."<br>";
echo $feedArray[$i]['location']."</b>";
//---------------------------------------------------------------------
}
echo '&tFeeds=' . $num;
echo '&cFeed=' . $_POST['sFeed'];
?>

This topic has been moved to JavaScript Help.

http://www.phpfreaks.com/forums/index.php?topic=317523.0

I have had a problem with some scripts I wrote (Screenscrapers) that worked great in PHP4, but stopped working the minute I upgraded to PHP5.

I can change all of my filenames to have the .PHP4 extension and this solves the problem, but since this encompasses a number of sites, internal links and hundreds of files, this is not my first choice solution.

Here is the scraper, what it does, is it takes items from the zazzle Results Page by category, strips out the formatting, adds my affiliate ID and then I can present these items on my page.


<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Test of scrape</title>

<link rel="stylesheet" type="text/css" href="/css/scraper.css" />
<script type='text/javascript' src='http://www.zazzle.com/js/logging/omniture/s_code.zjs/r-52.78223/site-zazzle.js'></script>

</head>

<body>

<div class="gridCell " id="page_productsGrid_assetCell1">

<?php 
$page = file_get_contents("http://www.zazzle.com/cool+smiley+gifts");

//comment out the <span> tags completely
$page = preg_replace('/<span/', "<!-- <span", $page);
$page = preg_replace('/<\/span>/', "<\/span> -->", $page);
$page = preg_replace('/<a /', "<a rel=\"nofollow\" ", $page);


$rf_id="238219236805025733";
// Regular expression to parse "&rf=" and the $rf_id into the existing link
$page=preg_replace("/(.*?)(href\s*=+\s*[\"\'])(.*?)([\"\'])(.*?)/is","$1$2$3?rf=$rf_id$4$5",$page); 


$test = explode('<div style="position:relative" class="clearfix">',$page);
for($t=1;$t<=count($test)-2;$t++){
 print "<div class=\"gridCellInfo\" id=\"page_products\">";
 print $test[$t];
}
?>
</body>
</html>


This works find in PHP4; not at all in PHP5.

My ideal solution would be an .htaccess file that I could put in any directory under PHP5 to make it default to php4.
I have tried this, to no avail (.htaccess):
Code: [Select]
<IfModule mod_rewrite.c>
    RewriteEngine On
    AddType text/html .php4
    AddHandler php4-script .php .html php5
</IfModule>


I have also tried a few alternatives... this appears to be a common problem and I have scoured the web and found no solution.


Here are the two pages in PHP4 and PHP5:
php4: http://www.killersmiley.com/test/cool-smiley.php4
php5: http://www.killersmiley.com/test/cool-smiley.php