PHP - Create An Image Of A Document When It Is Uploaded
Not sure if this is the right place to post this.
I have PHP form that I use to upload a document, PDF or Word Doc, I would also like the form to create a thumbnail of the document when it is uploaded, is this possible? Similar TutorialsHi, I have a script that uploads an image to a directory and then saves the fill path to a field in a table for later use. The only problem is people are uploading huge images and then when I produce a catalogue of my listings it takes forever to load because the images are so big. What I am after is an add in script to create an ADDITIONAL image 100 x 75px, I don't really want to change my upload script. Any ideas? Thanks in advace. Here is what I have: Code: [Select] <?php $idir = "../fleet/"; // Path To Images Directory if (isset ($_FILES['fupload'])){ //upload the image to tmp directory $url = $_FILES['fupload']['name']; // Set $url To Equal The Filename For Later Use if ($_FILES['fupload']['type'] == "image/jpg" || $_FILES['fupload']['type'] == "image/jpeg" || $_FILES['fupload']['type'] == "image/pjpeg") { $file_ext = strrchr($_FILES['fupload']['name'], '$account.'); // Get The File Extention In The Format Of , For Instance, .jpg, .gif or .php $copy = copy($_FILES['fupload']['tmp_name'], "$idir" . $_FILES['fupload']['name']); // Move Image From Temporary Location To Perm } } $fleetimage1 = mysql_real_escape_string("$idir" . $_FILES['fupload']['name']); //then insert sql code below... ?> Hi folks, Need some help with my php website. My website has provision for users to upload their documents (doc or pdf mainly). I want to have the ability to open those documents from my admin login, directly on the webpage in a standard format, and review the document and comment on it. I want to able to use highlighting and stickies to critique the uploaded document. Any pointers? Much appreciated, Jen Hi. I have a script here that will let users upload an image to my website but I just can't figure out how to save the uploaded image as "upload/logo.png" so that it will replace the already existing "upload/logo.png". Help would be greatly appreciated. Code: [Select] <html> <body> <form action="" method="post" enctype="multipart/form-data"> <label for="file">Filename:</label> <input type="file" name="file" id="file" /> <br /> <input type="submit" name="submit" value="Submit" /> </form> </body> </html> <?php if(isset($_POST['submit']) && !empty($_FILES["file"]["name"])) { $timestamp = time(); $target = "upload/"; $target = $target . basename($_FILES['uploaded']['name']) ; $ok=1; $allowed_types = array("image/gif","image/jpeg","image/pjpeg","image/png","image/bmp"); $allowed_extensions = array("gif","png","jpg","bmp"); if ($_FILES['file']['size'] > 350000) { $max_size = round(350000 / 1024); echo "Your file is too large. Maximum $max_size Kb is allowed. <br>"; $ok=0; } if ($_FILES["file"]["error"] > 0) { echo "Error: " . $_FILES["file"]["error"] . "<br />"; $ok=0; } else { $path_parts = pathinfo(strtolower($_FILES["file"]["name"])); if(in_array($_FILES["file"]["type"],$allowed_types) && in_array($path_parts["extension"],$allowed_extensions)){ $filename = $timestamp."-".$_FILES["file"]["name"]; echo "Name: " . $filename . "<br />"; echo "Type: " . $_FILES["file"]["type"] . "<br />"; $path_parts = pathinfo($_FILES["file"]["name"]); echo "Extension: " . $path_parts["extension"] . "<br />"; echo "Size: " . round($_FILES["file"]["size"] / 1024) . " Kb<br />"; //echo "Stored in: " . $_FILES["file"]["tmp_name"]. " <br />"; } else { echo "Type " . $_FILES["file"]["type"] . " with extension " . $path_parts["extension"] . " not allowed <br />"; $ok=0; } } if($ok == 1){ @move_uploaded_file($_FILES["file"]["tmp_name"], $target . $filename); $file_location = $target . $filename; if(file_exists($file_location)){ echo "Uploaded to <a href='$file_location'>$filename</a> <br />"; } else { echo "There was a problem saving the file. <br />"; } } } else { echo "Select your file to upload."; } ?> Thanks! Hi everyone, I have a script below, which uplads an image, however, the image name always starts with a capital letter, I want all letters to be small, how to adjust this please, thank you
$target_dir = ""; $target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]); $target_file = "$get_current_user.jpg"; $uploadOk = 1; $imageFileType = strtolower(pathinfo($target_file,PATHINFO_EXTENSION)); // Check if image file is a actual image if(isset($_POST["submit"])) { $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]); if($check !== false) { echo ""; /// was File is an image $uploadOk = 1; } else { echo "File is not an image<br>"; $uploadOk = 0; } } // Check file size if ($_FILES["fileToUpload"]["size"] > 10000000) { echo "Sorry, this image is too large, please resize using Paint<br>"; $uploadOk = 0; } // Allow certain file formats if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg" && $imageFileType != "gif" ) { echo "Only JPG, JPEG, PNG & GIF files are allowed<br>"; $uploadOk = 0; } // Check if $uploadOk is set to 0 by an error if ($uploadOk == 0) { echo "There was an error<br>"; } else { if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) { echo "Uploaded successfully (You may need to clear Cache to see the new image)"; mysql_query("UPDATE user SET user_image = 'https://.../images/users/$get_current_user.jpg' WHERE user_name = '$get_current_user' "); } else { echo ""; /// was Select a suitable image, file not uploaded yet } }
Hello. I'm using an Amazon S3 class to uploaded to S3. I have 2 upload boxes - The first uploads once and the second needs to upload twice - 1 full size, 1 thumb. The issue i'm having is that the 2nd image (the thumb) seems to be failing, although if I don't save the first full sized image I am able to upload the thumb. So I think the issue is with using the temp file twice? This is my code: //retreive post variables $fileName = $randomString . "_" . $_FILES['theFile']['name']; $fileTempName = $_FILES['theFile']['tmp_name']; $fileName2 = $randomString . "_" . $_FILES['theFile2']['name']; $fileTempName2 = $_FILES['theFile2']['tmp_name']; //move the file if ($s3->putObjectFile($fileTempName, "containerhere", $fileName, S3::ACL_PUBLIC_READ)) { echo "<strong>Uploaded Image</strong>"; }else{ echo "<strong>Something went wrong while uploading your file... sorry.</strong>"; } //move the file if ($s3->putObjectFile($fileTempName2, "containerhere", $fileName2, S3::ACL_PUBLIC_READ)) { echo "<strong>Uploaded Image</strong>"; }else{ echo "<strong>Something went wrong while uploading your file... sorry.</strong>"; } include('simpleImage.php'); $image = new SimpleImage(); $image->load($_FILES['theFile2']['tmp_name']); $image->resizeToWidth(100); $image->save($_FILES['theFile2']['tmp_name']); $fileName3 = $randomString . "_" . $_FILES['theFile2']['name']; $fileTempName3 = $_FILES['theFile2']['tmp_name']; //move the file if ($s3->putObjectFile($fileTempName3, "containerhere", "thumbs/" . $fileName3, S3::ACL_PUBLIC_READ)) { echo "<strong>Uploaded Image</strong>"; }else{ echo "<strong>Something went wrong while uploading your file... sorry.</strong>"; } Can anyone offer any advice? Thanks. Hello I have uploaded images from a server onto a website, they run through a mysql database (database holds the image file names). The problem I am having is resizing the images. Can anyone help? Thank you in advance GWG I'm beginning with simple codes to understand how things work and work my way up with what I need. My upload form looks like this: <form name="upload about" action="display.php" enctype="multipart/form-data" method="post"> Header: <input type="text" name="header" /> Body: <input type="text" name="body" /> <input type="hidden" name="MAX_FILE_SIZE" value="30000" /> Image: <input type="file" name="pic" /> <input type="submit" /> </form> And my display page is just as simple. <?php echo $_POST["header"]; ?> <?php echo $_POST["body"]; ?> <?php echo $_FILES['pic']['name']; ?> The problem is, whenever I submit the data, everything is fine, except the image does not display and just posts the filename of the image I uploaded. According to my research setting the enctype to multipart/formdata should display the image, but it does not. Can anyone tell me what's wrong? OK, When the user fills the info in the form out it goes in the DB fine. I can then array them on the "showroom page" fine. When they upload a picture it goes into the /images/ folder fine. Problem is... On each array on the showroom page I need the image they uploaded to be displayed. Cant work it out. Help would be GREAT!!!!! hi to all.Im currently displaying the images from my upload directory but the image does not display.please help thanks Hey guys! I have the following php code that grabs variables (and the browsed image) from Flash. //FLASH VARIABLES $Name = $_POST['Name']; $itemNumber = $_POST['itemNumber']; $filename = $_FILES['Filedata']['name']; $filetmpname = $_FILES['Filedata']['tmp_name']; $fileType = $_FILES["Filedata"]["type"]; $fileSizeMB = ($_FILES["Filedata"]["size"] / 1024 / 1000); list($filename, $extension) = explode('.', basename($_FILES['Filedata']['name'])); $filename = $Name; $target = $filename . $itemNumber . "." . $extension; // Place file on server, into the images folder move_uploaded_file($_FILES['Filedata']['tmp_name'], "images/".$target); This works perfect, but what I want to change is the width and height of the uploaded image. Any ideas/suggestions on how this could be done? Thanks in advance!! Cheers! Hi Basically I've built a CMS where by my clients can upload a number of images. On the success page I want to display the images they uploaded by file name. The issue is the number of images can vary. They may upload 2 or 10 or 50 etc. So far I've come up with this: Code: [Select] // number of files $UN = 3; //I've set this to 3 for now, but this is passed from the upload page! // server directories and directory names $dir = '../properties'; $images = glob($dir.'/*.{jpg}', GLOB_BRACE); //formats to look for $num_of_files = $UN; //number of images to display from number of uploaded files foreach($images as $image) { $num_of_files--; $newest_mtime = 0; $image = 'BROKEN'; if ($handle = @opendir($dir)) { while (false !== ($file = readdir($handle))) { if (($file != '.') && ($file != '..')) { $mtime = filemtime("$dir/$file"); if ($mtime > $newest_mtime) { $newest_mtime = $mtime; $image = "$file"; } } } } if($num_of_files > -1) //this made me laugh when I wrote it echo $trimmed = ltrim($image, "../properties").'<br />'; //display images else break; } Without this piece of code: Code: [Select] $newest_mtime = 0; $image = 'BROKEN'; if ($handle = @opendir($dir)) { while (false !== ($file = readdir($handle))) { if (($file != '.') && ($file != '..')) { $mtime = filemtime("$dir/$file"); if ($mtime > $newest_mtime) { $newest_mtime = $mtime; $image = "$file"; } } } } It shows the first 3 files alphabetically. I want to view the last number of images added. With the above code it simply shows the last image added 3 times! So I need to get the time each image was added and then order by the newest added and limit to the number of images uploaded. Any suggestions please? Kindest regards Glynn I need help making the uploaded image file name, that's chosen to be uploaded, be displayed on the html page with the path /upload/ added to the beginning of the displayed file name like so: ../upload/test.png Any help/improvements will be appreciated. <html> <head> <title>PHP Test</title> </head> <body> <?php if ($form_submitted == 'yes') { $allowedExts = array("gif", "jpeg", "jpg", "png"); $temp = explode(".", $_FILES["file"]["name"]); $extension = strtolower( end($temp) ); if ( $_FILES["file"]["size"] < 200000 && in_array($extension, $allowedExts) ) { if ($_FILES["file"]["error"]!= 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br>"; } else { $length = 20; move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $newfilename ); $file_location = '<a href="http://../upload/' . $newfilename . '">' . $newfilename . '</a>'; } } else { echo "Invalid upload file"; } ?> <label for="file">Filename:</label> <input type="file" name="file" id="file"> </body> </html> could someone help in how to resize a uploaded image size, say if someone is uploading a 1mb photo to my server, i wish for it to become 100kb and also resize its width and height? here is my code Code: [Select] //////////////////////////////////////uploader else if($action=="uploader") { echo "Upload your picture and copy the link <br/>after uploading to user it at gallery.<br/><br/>"; echo "<form method=\"post\" enctype=\"multipart/form-data\" action=\"index.php?action=uploaded&sid=$sid\">"; echo "Choose Pictu <br />"; echo "<input name=\"uploaded\" type=\"file\" /><br /><br />"; echo "<input type=\"submit\" value=\"Upload\" />"; echo "</form><br/>"; echo "<p align=\"center\">"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; } //////////////////////////////////////uploader else if($action=="uploaded") { $blacklist = array(".php", ".php.jpg", ".php.jpeg", ".php.gif", ".php.png", ".phtml", ".php3", ".php4"); foreach ($blacklist as $item) { if(preg_match("/$item\$/i", $_FILES['uploaded']['name'])) { echo "<p align=\"center\">"; echo "Oops sorry we do not allow those files.<br/>"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; exit; } } $target = "../images/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if (file_exists("../images/" . $_FILES["uploaded"]["name"])) { echo "<p align=\"center\">"; echo $_FILES["file"]["name"] . "Oops file name already exists<br/> kindly rename your picture and upload again. <br/>"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; }else{ //This is our size condition if ($uploaded_size > 25600){ echo "Your file is too large. We have a 25kb limit.<br/>"; $ok=0; } $types = array('image/jpeg', 'image/gif', 'image/png'); if (in_array($_FILES['uploaded']['type'], $types)) { // file is okay continue } else { $ok=0; } //Here we check that $ok was not set to 0 by an error if ($ok==0){ echo "<p align=\"center\">"; Echo "Sorry your file was not uploaded.<br/> It may be the wrong filetype. <br/>We only allow JPG, GIF, and PNG filetypes.<br/>"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; } //If everything is ok we try to upload it else{ if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)){ echo "<p align=\"center\">"; echo "The file ". basename( $_FILES['uploadedfile']['name']). " Picture uploaded successfully.<br/><br/><b>$target <br/>"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; } else{ echo "<p align=\"center\">"; echo "Sorry, there was a problem uploading your file.<br/>"; echo "<a href=\"index.php?action=main&sid=$sid\">Home</a>"; echo "</p>"; } } } } Hi all I am trying to write a piece of code to take an image, resize it and centre it on a canvas 300 pixels tall by 400 pixels high. I know I need to use imagecopymerged but how do I add it to the below code: Code: [Select] $imagelarge = $_FILES['image']['tmp_name']; $imagelargemain = $_FILES['image']['name']; $src = imagecreatefromjpeg($imagelarge); list($width,$height)=getimagesize($imagelarge); $newwidth=300; $newheight=($height/$width)*$newwidth; $tmp=imagecreatetruecolor($newwidth,$newheight); imagecopyresampled($tmp,$src,0,0,0,0,$newwidth,$newheight,$width,$height); $filename = WEB_UPLOAD."images/right-images/". $_FILES['image']['name']; imagejpeg($tmp,$filename,100); imagedestroy($src); imagedestroy($tmp); Many thanks for your help! Pete Hello i just learned how to use .ttf fonts on a webpage ,but i noticed that IE Browsers arent supporting it so i thought to make add the Fonted Text into a image so IE Browsers will see the font in a image and not a replaced font text Could someone please provide me a Simple Script to make a PNG image with the text and font and a invisible background ? Hi! my code uploads an image and saves it to an upload folder, but I want to create a thumbnail of it. For example, if I upload a 1400x1000 JPG, I would like to resize the image and it has to respect the proportion given a maximum size. if I say the maximum width/height is 250px, the image should be thumbnailed according to the max height/width, and in proportion with the width/height Thanks in advance Fernando Hi, How to create an invisible text in an image. Any idea? Thanks. Here is the script the reads a twitter xml feed and generates a png from the first tweet. What I want to be able to is specify a width so the text will wrap and be able to position the text within a certain dimensions. I created the files with a base image because I didn't know how to create an image with a specific color. So removing the base image section would be great. Lastly, I would like to style the font with a certain font and weight. <?php // Get the XML data from Feedburner $sxe = new SimpleXMLElement('twitter.xml', NULL, TRUE); $tweet = $sxe->status[0]->text; // Create the image from the base image $img = imagecreatefrompng('tweet-base.png'); $color = imagecolorallocate($img, 0x33, 0x33, 0x33); imagestring($img, 2, $xpos, 2, $tweet, $color); // Save the image imagepng($img, 'tweet.png'); ?> I need to upload an image using php and store the image as blob in mysql. I understand the standard way is to create a form for the user, let the user choose the image to upload, click submit. But I need to create a php, for example, uploadImage.php?image="c:\myPhoto.jpg" and when I type http:\\www.myhome.com\uploadImage.php?image="c:\myPhoto.jpg" from a web browser in my pc, I can automatically upload myPhoto.jpg to the myhome.com server? Thank you for your kind help. Hi guys, I have a simple code below which allows to me to upload image to a file directory and save the location of my file in database the only thing i dont understand is how to 1-resize the images 2- create a thumbnail while uploading 3- allow only jpeg & JPG files to be uploaded with 200kb max also, could you tell me what is the best size i can store the images in? thanks in advance //image1 $nameone=$_FILES['myfileone']['name']; $tmp_name= $_FILES['myfileone']['tmp_name']; if ($nameone) { $locationone="images/$nameone"; move_uploaded_file($tmp_name, $locationone); $image1 = mysql_query ("UPDATE user SET image1='$locationone'"); } |