|
PHP - Moved: Run Php In A Table Cell
This topic has been moved to JavaScript Help.
http://www.phpfreaks.com/forums/index.php?topic=355480.0 Similar Tutorials
Table Issue - Multiple Location Values For User Pushes Values Out Of Row Instead Of Wrapping In Cell
This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=314271.0 This topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=307147.0 I am having a problem trying to show if cell is empty echo one thing if empty and starttime if there is one: Code: [Select] if(isset($rown['starttime'])) { echo "Add Day"; } else { echo $rown['starttime']; } how to format only one specific row based on the value of one cell in a row? $result = mysql_query(select bal, etc. etc ..query ) while($row = mysql_fetch_assoc($result)) echo "<tr>"; echo "<td>" . $row['Account'] . "</td>"; echo "<td>" . $row['licence'] . "</td>"; echo "<td>" . $row['own'] . "</td>"; echo "<td>" . $row['bal'] . "</td>"; echo "</tr>"; Would appreciate help on how to format only the $row['bal'] output to red colour IF bal >5000 Thanks Trying to run this function so it displays the generated image in a table cell - Code: [Select] <?php function imgsecuregen($size = 6){ $width = 11*$size; $height = 25; $string = ""; for($i = 1; $i <= $size; $i++){ $string .= rand (0,9).""; } // for $im = ImageCreate($width, $height); $bg = imagecolorallocate($im, 102, 102, 102); // background $black = imagecolorallocate($im, 0, 255, 0); // text $grey = imagecolorallocate($im, 102, 102, 102); // border imagerectangle($im,0, 0, $width-1, $height-1, $grey); imagestring($im, 5, $size, 5, $string, $black); imagepng($im); imagedestroy($im); } imgsecuregen(8); // string length ?> Works if I load it directly, but not in a <td>. I am trying to insert data from a mysql in a table. I want the data to appear with the image on the left, item name on the top right followed by description underneath. <?php $sql = 'SELECT * FROM tbl_products ORDER BY id'; $result = $db->query($sql); $output[] = '<ul>'; $output[] = '<table border="3" bordercolor="#000000">'; while ($row = $result->fetch()) { $output[] = '<tr>'; $output[] = '<td><img src="images/'.$row['pic'].'" width="67" height="100" /></td>'; $output[] = '<td class="style10"><strong>'.$row['item_name'].'</strong></td>'; $output[] = '<td>'.$row['item_description'].'</td>'; $output[] = '</tr>'; } $output[] = '</table>'; echo join('',$output); ?> I would like the items to appear the same way as this page http://aafcollection.info/items/list.php Hi guys i have another question about my shopping cart.
I have in my sql database table called products. It consist of 4 columns (product_id, description, quantity, price).
Now on my index page, I want to call just one product from cell, which would have special price. But i don't know how to call one single product.
So my code looks like that:
<?php
$sql="SELECT product_id FROM Products";
$query=mysql_query($sql);
$row=mysql_fetch_array($query);
?><table >
<tr><img src="Images/Image.jpg" width="380" height="300" /> </tr>
<tr>
<td><a href="index.php?page=index&action=add&id=<?php echo $row['product_id']?>">Add to cart</a></td>
</tr>
<?php
?>
</table>
This code display me first product but i would like to call 3 product how would i do that, so i have 6 products and i would like to call product N.3 to my index page. My code calls the first one, how would it call the third.
Image name will come from database. It can be displayed in divs or table cells. Which is better using divs or table cells? Can anyone post sample code? http://img28.imageshack.us/i/44233003.png/ Hi I have a table that populated by a recordset, and wondered whether is was possible to make a row background colour = red where a particular cell = some text? I have been searching around and not managed to find anything of use. Any help would be appreciated.
When I echo out my variable in the php file it works fine but when I put the variable in a table cell it doesn't echo out. I have a stdClass Object array with nested User arrays as a value that I would like to display in a table cell. I am struggling and have exhausted a lot of time. I am hoping to get a shove in the right direction if possible. The image below will show what I am trying to do.
$someArray = json_decode($token_result);
foreach ($someArray as $key => $value) {
$combined[] =
"<tr><td>" .
$value->customer .
"</td><td>" .
$value->city .
'</td>
<td>' .
$value->state .
"</td><td>" .
$value->zipcode .
'</td>
<td>' .
$value->totalUsers .
"</td><td>" .
$value->totalActiveUsers .
"</td><td>" .
$value->totalInActiveUsers .
'</td><td>
<a href="">' .
$value->users .
"</a></td></tr>";
}
foreach ($combined as $value) {
print $value;
}
Here is what my Array and Objects look like Array
(
[0] => stdClass Object
(
[customer] => SWSH
[city] => Thomasville
[state] => GA
[zipcode] => 31792
[totalUsers] => 6
[totalActiveUsers] => 6
[totalInActiveUsers] => 0
[users] => Array
(
[0] => stdClass Object
(
[firstName] => xxx
[lastName] => xxx
[phoneNumber] =>
[userName] => cb_igwrth@xxx.com
[createdBy] =>
[isActive] => 1
)
[1] => stdClass Object
(
[firstName] => Dan
[lastName] => Stewart
[phoneNumber] => +11111111111
[userName] => dan.sxx@xxx.ga.gov
[createdBy] => kwilliams@xxx.com
[isActive] => 1
)
)
)
[1] => stdClass Object
(
[customer] => xxxx
[city] => Carver
[state] => MA
[zipcode] => 02330
[totalUsers] => 3
[totalActiveUsers] => 3
[totalInActiveUsers] => 0
[users] => Array
(
[0] => stdClass Object
(
[firstName] => Leo
[lastName] => Furtado
[phoneNumber] => 781-000-0000
[userName] => LFurtado@xxx.com
[createdBy] => TConger@ccccc.com
[isActive] => 1
)
)
)
)
Table is attached
I have learned php coding by doing (looking for patterns and trying things) and I have hit a roadblock trying to modify a template that creates a delimited text file of products from an ecommerce site (Sunshop) for upload to google base. I have tried to search for the answer but I don't know what I don't know so I may not have put the right search terms in. So I apologize if this has been addressed in the past. The script uses case to call up the contents of specific rows of the product table which I understand but in when I want to call up the manufacturer row Sunshop uses a reference number and then a different table called manufacturers with an ID row that matches the manufacturer row numbers (that are associated with each product) and then next to it a name row which contains the actual manuracturer names. Can I put code in the case that will pull up the referenced name as opposed to just the numbers that are in the column? This is what I have now that just calls up the cells from the manufacurer row: Code: [Select] case 'mfg': $item[mfg] = $item[manufacturer]; The mfg refers to this part of the code in an array: Code: [Select] array('header' => 'manufacturer', 'value' => 'mfg'), In case it helps I will attach the full document. Thanks. This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=317025.0 Hi, My company has 240+ locations and as such some users (general managers) cover multiple sites. When I run a query to pull user information, when the user has multiple sites to his or her name, its adds the second / third sites to the next columns, rather than wrapping it inside the same table cell. It also works the opposite way, if a piece of data is missing in the database and is blank, its pull the following columns in. Both cases mess up the table and formatting. I'm extremely new to any kind of programming and maybe this isn't the forum for this question but figured I'd give it a chance since I'm stuck. The HTML/PHP code is below: <table id="datatables-column-search-select-inputs" class="table table-striped" style="width:100%"> <thead> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> <th>Actions</th> </tr> </thead> <tbody> <?php //QUERY TO SELECT ALL USERS FROM DATABASE $query = "SELECT * FROM users"; $select_users = mysqli_query($connection,$query);
// SET VARIABLE TO ARRAY FROM QUERY while($row = mysqli_fetch_assoc($select_users)) { $user_id = $row['user_id']; $user_firstname = $row['user_firstname']; $user_lastname = $row['user_lastname']; $username = $row['username']; $user_phone = $row['user_phone']; $user_image = $row['user_image']; $user_title_id = $row['user_title_id']; $user_role_id = $row['user_role_id'];
// POPULATES DATA INTO THE TABLE echo "<tr>"; echo "<td>{$user_id}</td>"; echo "<td>{$user_firstname}</td>"; echo "<td>{$user_lastname}</td>"; echo "<td>{$username}</td>"; echo "<td>{$user_phone}</td>";
//PULL SITE STATUS BASED ON SITE STATUS ID $query = "SELECT * FROM sites WHERE site_manager_id = {$user_id} "; $select_site = mysqli_query($connection, $query); while($row = mysqli_fetch_assoc($select_site)) { $site_name = $row['site_name']; echo "<td>{$site_name}</td>"; } echo "<td>{$user_title_id}</td>"; echo "<td>{$user_role_id}</td>"; echo "<td class='table-action'> <a href='#'><i class='align-middle' data-feather='edit-2'></i></a> <a href='#'><i class='align-middle' data-feather='trash'></i></a> </td>"; //echo "<td><a href='users.php?source=edit_user&p_id={$user_id}'>Edit</a></td>"; echo "</tr>"; } ?>
<tr> <td>ID</td> <td>FirstName</td> <td>LastName</td> <td>Username</td> <td>Phone #</td> <td>Location</td> <td>Title</td> <td>Role</td> <td class="table-action"> <a href="#"><i class="align-middle" data-feather="edit-2"></i></a> <a href="#"><i class="align-middle" data-feather="trash"></i></a> </td> </tr> </tbody> <tfoot> <tr> <th>ID</th> <th>FirstName</th> <th>LastName</th> <th>Username</th> <th>Phone #</th> <th>Location</th> <th>Title</th> <th>Role</th> </tr> </tfoot> </table>
This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=348465.0 This topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=330967.0 This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=354977.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=321459.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=330834.0 |
|||||||