PHP - Replace Image With An Uploaded One?

Hello. I'm using an Amazon S3 class to uploaded to S3. I have 2 upload boxes - The first uploads once and the second needs to upload twice - 1 full size, 1 thumb.

The issue i'm having is that the 2nd image (the thumb) seems to be failing, although if I don't save the first full sized image I am able to upload the thumb. So I think the issue is with using the temp file twice?

This is my code:

 //retreive post variables

$fileName = $randomString . "_" . $_FILES['theFile']['name'];

$fileTempName = $_FILES['theFile']['tmp_name'];

$fileName2 = $randomString . "_" . $_FILES['theFile2']['name'];

$fileTempName2 = $_FILES['theFile2']['tmp_name'];

    //move the file

if ($s3->putObjectFile($fileTempName, "containerhere", $fileName, S3::ACL_PUBLIC_READ)) {

echo "<strong>Uploaded Image</strong>";

}else{

echo "<strong>Something went wrong while uploading your file... sorry.</strong>";

}

//move the file

if ($s3->putObjectFile($fileTempName2, "containerhere", $fileName2, S3::ACL_PUBLIC_READ)) {

echo "<strong>Uploaded Image</strong>";

}else{

echo "<strong>Something went wrong while uploading your file... sorry.</strong>";

}

  include('simpleImage.php');

  $image = new SimpleImage();

  $image->load($_FILES['theFile2']['tmp_name']);

  $image->resizeToWidth(100);

  $image->save($_FILES['theFile2']['tmp_name']);

$fileName3 = $randomString . "_" . $_FILES['theFile2']['name'];

$fileTempName3 = $_FILES['theFile2']['tmp_name'];

//move the file

if ($s3->putObjectFile($fileTempName3, "containerhere", "thumbs/" . $fileName3, S3::ACL_PUBLIC_READ)) {

echo "<strong>Uploaded Image</strong>";

}else{

echo "<strong>Something went wrong while uploading your file... sorry.</strong>";

}

Can anyone offer any advice?

Thanks.

hi to all.Im currently displaying the images from my upload directory but the image does not display.please help thanks

Hey guys!
I have the following php code that grabs variables (and the browsed image) from Flash.


//FLASH VARIABLES
$Name = $_POST['Name'];
$itemNumber = $_POST['itemNumber'];
$filename = $_FILES['Filedata']['name'];
$filetmpname = $_FILES['Filedata']['tmp_name'];
$fileType = $_FILES["Filedata"]["type"];
$fileSizeMB = ($_FILES["Filedata"]["size"] / 1024 / 1000);


list($filename, $extension) = explode('.', basename($_FILES['Filedata']['name']));
$filename = $Name;
$target = $filename . $itemNumber . "." . $extension;


// Place file on server, into the images folder
move_uploaded_file($_FILES['Filedata']['tmp_name'], "images/".$target);



This works perfect, but what I want to change is the width and height of the uploaded image.
Any ideas/suggestions on how this could be done?

Thanks in advance!!
Cheers!

Hi

Basically I've built a CMS where by my clients can upload a number of images. On the success page I want to display the images they uploaded by file name.

The issue is the number of images can vary. They may upload 2 or 10 or 50 etc.

So far I've come up with this:

Code: [Select]
// number of files
$UN = 3; //I've set this to 3 for now, but this is passed from the upload page!

// server directories and directory names
$dir = '../properties';

$images = glob($dir.'/*.{jpg}', GLOB_BRACE); //formats to look for

$num_of_files = $UN; //number of images to display from number of uploaded files

foreach($images as $image)
{
$num_of_files--;

$newest_mtime = 0;
$image = 'BROKEN';
if ($handle = @opendir($dir)) {
while (false !== ($file = readdir($handle))) {
if (($file != '.') && ($file != '..')) {
$mtime = filemtime("$dir/$file");
if ($mtime > $newest_mtime) {
$newest_mtime = $mtime;
$image = "$file";
}
}
}
}

if($num_of_files > -1) //this made me laugh when I wrote it
echo $trimmed = ltrim($image, "../properties").'<br />'; //display images
else
break;
}
Without this piece of code:

Code: [Select]
$newest_mtime = 0;
$image = 'BROKEN';
if ($handle = @opendir($dir)) {
while (false !== ($file = readdir($handle))) {
if (($file != '.') && ($file != '..')) {
$mtime = filemtime("$dir/$file");
if ($mtime > $newest_mtime) {
$newest_mtime = $mtime;
$image = "$file";
}
}
}
}
It shows the first 3 files alphabetically. I want to view the last number of images added.

With the above code it simply shows the last image added 3 times!

So I need to get the time each image was added and then order by the newest added and limit to the number of images uploaded. Any suggestions please?

Kindest regards
Glynn

OK,

When the user fills the info in the form out it goes in the DB fine.  I can then array them on the "showroom page" fine.

When they upload a picture it goes into the /images/ folder fine.

Problem is... On each array on the showroom page I need the image they uploaded to be displayed.

Cant work it out.

Help would be GREAT!!!!!

I need help making the uploaded image file name, that's chosen to be uploaded, be displayed on the html page with the path /upload/ added to the beginning of the displayed file name like so:
../upload/test.png
Any help/improvements will be appreciated.

<html>
 <head>
  <title>PHP Test</title>
 </head>
  <body>
 <?php
 if ($form_submitted == 'yes') {
 $allowedExts = array("gif", "jpeg", "jpg", "png");
 $temp = explode(".", $_FILES["file"]["name"]);
 $extension = strtolower( end($temp) );
 if (  $_FILES["file"]["size"] < 200000
       && in_array($extension, $allowedExts) )
 {
     if ($_FILES["file"]["error"]!= 0)
     {
         echo "Return Code: " . $_FILES["file"]["error"] . "<br>";
     } else {
         $length = 20;
         move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $newfilename );
         $file_location = '<a href="http://../upload/' . $newfilename . '">' . $newfilename . '</a>';
     }
 } else {
   echo "Invalid upload file";
 }
?>
<label for="file">Filename:</label>
<input type="file" name="file" id="file">
</body>
</html>

I've managed to insert an image in my database, but when i upload a second picture it replaces the first!What should i do?

hello again need some advice

cant get it working

Code: [Select]
SELECT * FROM `tsue_members` WHERE memberid=0

if ($row['memberid'] == '0')
        {
$img = "1.gif";
}

echo $img;

could someone help in how to resize a uploaded image size, say if someone is uploading a 1mb photo to my server, i wish for it to become 100kb and also resize its width and height?

here is my code

Code: [Select]
//////////////////////////////////////uploader
else if($action=="uploader")
{



echo "Upload your picture and copy the link <br/>after uploading to user it at gallery.<br/><br/>";

echo "<form method=\"post\" enctype=\"multipart/form-data\" action=\"index.php?action=uploaded&amp;sid=$sid\">";
echo "Choose Pictu <br />";
echo "<input name=\"uploaded\" type=\"file\" /><br /><br />";
echo "<input type=\"submit\" value=\"Upload\" />";
echo "</form><br/>";


echo "<p align=\"center\">";
echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";
}


//////////////////////////////////////uploader
else if($action=="uploaded")
{



$blacklist = array(".php", ".php.jpg", ".php.jpeg", ".php.gif", ".php.png", ".phtml", ".php3", ".php4");
foreach ($blacklist as $item) {
if(preg_match("/$item\$/i", $_FILES['uploaded']['name'])) {
echo "<p align=\"center\">";
echo "Oops sorry we do not allow those files.<br/>";
echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";
exit;
}
}

$target = "../images/";
$target = $target . basename( $_FILES['uploaded']['name']) ;
$ok=1;

if (file_exists("../images/" . $_FILES["uploaded"]["name"]))
      {
echo "<p align=\"center\">";
      echo $_FILES["file"]["name"] . "Oops file name already exists<br/> kindly rename your picture and upload again. <br/>";

echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";   
 }else{

//This is our size condition
if ($uploaded_size > 25600){

echo "Your file is too large. We have a 25kb limit.<br/>";
$ok=0;
}

$types = array('image/jpeg', 'image/gif', 'image/png');

if (in_array($_FILES['uploaded']['type'], $types)) {
// file is okay continue
} else {
$ok=0;
}


//Here we check that $ok was not set to 0 by an error
if ($ok==0){
echo "<p align=\"center\">";
Echo "Sorry your file was not uploaded.<br/> It may be the wrong filetype. <br/>We only allow JPG, GIF, and PNG filetypes.<br/>";

echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";
}

//If everything is ok we try to upload it
else{
if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)){
echo "<p align=\"center\">";

echo "The file ". basename( $_FILES['uploadedfile']['name']). " Picture uploaded successfully.<br/><br/><b>$target <br/>";

echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";
}
else{
echo "<p align=\"center\">";

echo "Sorry, there was a problem uploading your file.<br/>";
echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";
}
}
}
}

The situation is that I have a large string with some identifiers to say "replace me" with something else. My goal is to replace the values, but if one replacement includes one of the other keys, I don't want to replace it.   For example:

<?php
$str = 'some blob ~abc~ followed by ~def~';

$arr_orig = array(
	'~abc~',
	'~def~'
);

$arr_new  = array(
	'value~def~',
	'blah'
);

echo str_replace( $arr_orig, $arr_new, $str );
?>

This will echo: some blob valueblah followed by blah   But that's not what I'm trying to accomplish. Basically, I want ~abc~ to be replaced with the literal: value~def~ and for the ~def~ that happens to be part of that string to NOT be replaced. I hope what I'm asking is clear. Basically, preg_replace/str_replace with arrays seems no different than just doing a FOR loop and replacing ~abc~ and then ~def~. But that's not what I need.   I'm hoping that if ~abc~ is replaced with text that happens to be another identifier -- ~def~, ~xyz~, whatever -- that this already replaced text is not again replaced. Is there a built-in function to do something like this? If not, should I just parse the whole string and count characters or something? Seems like a pain (and slow!)

Hi
i wrote a find and replace code but my code replace last value of array and skip the first, second.... values in the array.
Please give me an idea because i stack with this code.

Regards


$KeyWord  = explode("\n", $RowGetWords['KEYWORDS']);
$Replace  = explode("\n", $RowGetWords['ReplaceTo']);

for($i=0; $i<count($KeyWord); $i++){
$pattern = $KeyWord[$i];
$replace = "<a href=\"" .$URL. "\" target=\"_blank\" >" .$Replace[$i]. "</a>";
$html = str_replace($pattern, $replace, $Row['MessageBody']);
}

Hello,

I have a form for uploading CV files into a CV database.

Once the files are uploaded to their directory (e.g. www.jobsboard.com/cvdatabase/) please could someone tell me how to restrict access to users?

e.g. once a user logs into their userpanel they should be able to click on a hyperlink to download a CV e.g. (www.jobsboard.com/cvdatabase/CV1.doc) but a user who isn't logged in shouldn't be able to access www.jobsboard.com/cvdatabase/CV1.doc

Please could you tell me whether this is possible?

Many thanks,

Stu

At the moment I have been uploading files to my server using <input type='files'> and binary encrytion. I would like to have more controll over the files tmp_name. is there a way to assing it befor hand?

Hi Everyone,
I've been studying the topics at this site and others on ways to count uploaded images; and what I've tried hasn't worked. I have seen this question posed and answered many times and most of the answers are something akin to this:

        Code: [Select]
$count = count($_FILES['userfile'] ['name']);
echo "the number of photos is ".$count;
The explanation usually states that "count($_FILES['userfile'])" will simply count the number of elements in the array and return 5. But including ['name'] will return the number of files (images) uploaded. I will allow up to five photos to be uploaded (less is OK too) and want to count them in order to iterate through the proper number of loops to filter and process the photos. I've tested both of the above and get 5 (elements) when I count the ['userfile']; but get 0 (zero) when I test "['userfile'] ['name']". Here's the html code:

Code: [Select]
<!-- html here to input form data -->
<label></label><input type="hidden" name="MAX_FILE_SIZE" value="500000000" /><br />
<label for="userfile">Upload photo 1</label>
<input type="file" name="userfile1" id="userfile1" /><br />
<label for="userfile">Upload photo 2</label>
<input type="file" name="userfile2" id="userfile2" /><br />
<label for="userfile">Upload photo 3</label>
<input type="file" name="userfile3" id="userfile3" /><br />
<label for="userfile">Upload photo 4</label>
<input type="file" name="userfile4" id="userfile4" /><br />
<label for="userfile">Upload photo 5</label>
<input type="file" name="userfile5" id="userfile5" /><br /><br />
<label></label><input type="submit" name="userfile" value="Send Ad" />
</form>
I've been testing the uploads with two files (jpg) and have tried to come up with an alternative that can iterate through the file arrays and determine how many photos I have. The code I've been testing is as follows:

    Code: [Select]
$num = 1;
$count = 0;
while ($num <=5) {
  foreach ($_FILES['userfile'.$num] as $upload){
    if ($upload ['error'] != 4){
  }
$count ++;
  }
  $num++;
}
echo "the number of photos is ".$count;
I'm using "['error'] !=4" because some times people won't have 5 photos to upload. The result I get is 25 or 5 (files) x 5 (elements) for a total of 25. Does anyone know the proper way of doing this? Thanks for you input!
Cheers,
Rick

Why does the following code not detect the following file? After I select a file and I click upload, it goes back to the upload form.


<?php
include_once("includes/config.php");

//grab their type
if(!$_COOKIE['user'])
{

//they are a guest

$info = "Guest";
}
else
{

//they are a user

$info = $_COOKIE['user'];
}


if(!$_FILE['file'])
{

$content = '<form action="submit.php" method="post" enctype="multipart/form-data">
<label for="file">SELECT SKIN:</label>
<input type="file" name="file" id="file" />
<input type="submit" name="submit" value="Submit" />
</form>';
}
else
{

if($_FILES['file']['error'] > 0)

{

$content = "There was an error trying to upload the skin ".$_FILES['file']['name'].".".$_FILES['file']['error'];

}

}

?>
<html>
<head>
<title><?php $title; ?></title>
<link rel="stylesheet" type="text/css" href="theme/style.css" />
</head>
<body>
<div id="header">

MCSkins
</div>

<?php echo "Submitting as: ".$info."<br/><br/>".$content; ?>
</body>
</html>