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PHP - How Can You Get A City By Zip Code?
Is there a way to auto populate someone's city by zipcode? Also is it possible to find out their county as well?
Similar TutorialsIn my registration form there are many form elements to give users' details for registration in my web site. among those elements there are two select boxes for user to select their district and city. I have created these two select box using ajax. Therefor a user select a district then automatically ajax creating second select box for cities is populating. I used separate php page called findcity.php to create city select box. I called this findcity.php page from my original register.php page through onChange attribute. and there I passed the district id with the url to findcity.php page. like wise, Now I need to bring city id to my original register.php page when user select a city from city select box in findcity.php page. my problem is that. I tried to get city Id to register.php page but still I couldn't get it. city id is needed me to send to the database with other form elements' values. can anybody help me to fix my problem? here is my coding for your reference. This code is, from my register.php page Code: [Select] <div> <label for="district">District <img src="../images/required_star.png" alt="required" /> : </label> <?php require_once ('../includes/config.inc.php'); require_once( MYSQL2 ); $query="select * from district order by district_id"; $result = mysqli_query( $dbc, $query); echo '<select name="district" class="text" onChange="getCity(' . "'" . 'findcity.php?district=' . "'" . '+this.value)">'; echo '<option value="">-- Select District --</option>'; while( $row = mysqli_fetch_array($result, MYSQLI_NUM)) { echo '<option value="' . $row[0] . '"'; // Check for stickyness: if ( isset( $_POST['district']) && ( $_POST['district'] == $row[0] )) echo ' selected="selected"'; echo " >$row[1]</option>"; } echo '</select>'; ?> </div> <div> <label for="city">City <img src="../images/required_star.png" alt="required" /> : </label> <input type="hidden" name="reg_locationid" id="reg_locationid" value="56" /> <div id="citydiv" style="position: relative; top: -14px; left: 130px; margin-bottom: -26px;"> <select name="city" class="text"> <option>-- Select City --</option> </select> </div> </div> this is, from my findcity.php page Code: [Select] <?php $districtId=$_GET['district']; require_once ('../includes/configaration.inc.php'); require_once( MYSQLCONNECTION ); $query="select city_id, city_name from city2 where district_id=$districtId"; $result=mysqli_query( $dbc, $query); echo '<select name="city" class="text"> <option>-- Select City --</option>'; while($row=mysqli_fetch_array($result, MYSQLI_NUM)) { echo '<option value="' . $row[0] . '"'; // Check for stickyness: if ( isset( $_POST['city']) && ( $_POST['city'] == $row[0] )) { echo ' selected="selected"'; //echo '<input type="hidden" name="city" value="' . $row[0] . '"'; } echo " >$row[1]</option>"; } echo '</select>'; ?> Greetings, Well i have a registration function in my website. User chooses his city of residence. Now all i need is to find the neighbouring city of the city he specifies while registering. This is required for the cities outside US and Canada [For these two we can use zip codes to find neighbouring cities.]. Is it possible to find neighbouring cities for cities of other countries?? Thanks I am looking for the easiest way to get live data for the current temperature for various U.S. cities. I just need to capture the data and display on the page. Any recommendations? ok guys, i know you guys are awesome and I always get the help and I need some help in figuring the current city and the metropolitan area from an ip address. For example, if I am in Harlem, NY, I need to get the Harlem and New York. I have a code that is partially working but not accurate enough, please guys help, something like groupon will do. Code: [Select] function currentCity () { ( ( (float)phpversion() < 5.3 ) ) ? die ( 'There is something wrong!' ) : ''; $site = file_get_contents( "http://www.google.com/search?q=VBXMCBVFKJSHDKHDKF" ); $getLocationViaGoogle = function ( $html ){ $regex = "#<\w+\s\w+=\"tbos\">([^<]{3,})<\/\w+>#i"; preg_match_all( $regex, $html, $matches ); return $matches[1][0]; }; print $getLocationViaGoogle( $site ); } This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=359321.0 I have a problem with the following code but i really don't see it: I try to populate the city textfield by the zipcode entered on the zipcode textfield function fillcitystate(controlname) { var zipstring = ""; xmlhttp = new XMLHttpRequest(); xmlhttp.open("GET", "postcode.php?postcode=" + controlname.value, true); xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4) { var zipstring = xmlhttp.responseText; if (zipstring!="Error") { var ziparray = zipstring.split("|"); document.getElementById("test").innerHTML = ziparray[1]; } } } xmlhttp.send(null); } In postcode.php $returnval = "Error"; $postcode = $_GET['postcode']; $query = "SELECT * FROM city WHERE code='$postcode'"; $resultval = mysql_query($query); $rowcount = mysql_num_rows($resultval); if ($rowcount==1) { $row = mysql_fetch_array($resultval); $returnval = $row['code']."|".ucwords(strtolower($row['name']))."|".$row['province']; } else { } echo $returnval; When entering a zipcode, nothing happened so i decided to just echo the name of the city using the innerHTML. Still nothing happened, so i commented out all the php in my postcode.php and decided to just do: $postcode = $_GET['postcode']; echo $postcode; then it printed out: 'undefined' Can somebody point me out? Hi, I have some code which displays my blog post in a foreach loop, and I want to add some social sharing code(FB like button, share on Twitter etc.), but the problem is the way I have my code now, creates 3 instances of the sharing buttons, but if you like one post, all three are liked and any thing you do affects all of the blog post. How can I fix this? <?php include ("includes/includes.php"); $blogPosts = GetBlogPosts(); foreach ($blogPosts as $post) { echo "<div class='post'>"; echo "<h2>" . $post->title . "</h2>"; echo "<p class='postnote'>" . $post->post . "</p"; echo "<span class='footer'>Posted By: " . $post->author . "</span>"; echo "<span class='footer'>Posted On: " . $post->datePosted . "</span>"; echo "<span class='footer'>Tags: " . $post->tags . "</span>"; echo ' <div class="addthis_toolbox addthis_default_style "> <a class="addthis_button_facebook_like" fb:like:layout="button_count"></a> <a class="addthis_button_tweet"></a> <a class="addthis_counter addthis_pill_style"></a> </div> <script type="text/javascript">var addthis_config = {"data_track_clickback":true};</script> <script type="text/javascript" src="http://s7.addthis.com/js/250/addthis_widget.js#username=webguync"></script>'; echo "</div>"; } ?> I have the following code in html: <html> <head> <script type="text/javascript"> <!-- function delayer(){ window.location = "http://VARIABLEVALUE.mysite.com" } //--> </script> <title>Redirecting ...</title> </head> <body onLoad="setTimeout('delayer()', 1000)"> <script type="text/javascript"> var sc_project=71304545; var sc_invisible=1; var sc_security="9c433fretre"; </script> <script type="text/javascript" src="http://www.statcounter.com/counter/counter.js"></script><noscript> <div class="statcounter"><a title="vBulletin statistics" href="http://statcounter.com/vbulletin/" target="_blank"><img class="statcounter" src="http://c.statcounter.com/71304545/0/9c433fretre/1/" alt="vBulletin statistics" ></a></div></noscript> </body> </html> Is a basic html webpage with a timer redirect script and a stascounter code. I know a bit about html and javascript, but almost nothing about php. My question is: How a can convert this html code into a php file, in order to send a variable value using GET Method and display this variable value inside the javascript code where says VARIABLEVALUE. Thanks in adavance for your help. Advance thank you. Can you help please. The error..... Warning: mysql_fetch_assoc() expects parameter 1 to be resource, string given in C:\wamp\www\test_dabase.php on line 24 code. Code: [Select] <?php //database connection. $DB = mysql_connect("localhost","root") or die(mysql_error()); if($DB){ //database name. $DB_NAME="mysql"; //select database and name. $CON=mysql_select_db($DB_NAME,$DB)or die(mysql_error()."\nPlease change database name"); // if connection. }if($CON){ //show tables. $mysql_show="SHOW TABLES"; //select show and show. $mysql_select2="mysql_query(".$mysql_show.") or die(mysql_error())"; } //if allowed to show. if($mysql_select2){ //while it and while($data=mysql_fetch_assoc($mysql_select2)){ //show it. echo $data; } } ?> Hi, I need to insert some code into my current form code which will check to see if a username exist and if so will display an echo message. If it does not exist will post the form (assuming everything else is filled in correctly). I have tried some code in a few places but it doesn't work correctly as I get the username message exist no matter what. I think I am inserting the code into the wrong area, so need assistance as to how to incorporate the username check code. $sql="select * from Profile where username = '$username'; $result = mysql_query( $sql, $conn ) or die( "ERR: SQL 1" ); if(mysql_num_rows($result)!=0) { process form } else { echo "That username already exist!"; } the current code of the form <?PHP //session_start(); require_once "formvalidator.php"; $show_form=true; if (!isset($_POST['Submit'])) { $human_number1 = rand(1, 12); $human_number2 = rand(1, 38); $human_answer = $human_number1 + $human_number2; $_SESSION['check_answer'] = $human_answer; } if(isset($_POST['Submit'])) { if (!isset($_SESSION['check_answer'])) { echo "<p>Error: Answer session not set</p>"; } if($_POST['math'] != $_SESSION['check_answer']) { echo "<p>You did not pass the human check.</p>"; exit(); } $validator = new FormValidator(); $validator->addValidation("FirstName","req","Please fill in FirstName"); $validator->addValidation("LastName","req","Please fill in LastName"); $validator->addValidation("UserName","req","Please fill in UserName"); $validator->addValidation("Password","req","Please fill in a Password"); $validator->addValidation("Password2","req","Please re-enter your password"); $validator->addValidation("Password2","eqelmnt=Password","Your passwords do not match!"); $validator->addValidation("email","email","The input for Email should be a valid email value"); $validator->addValidation("email","req","Please fill in Email"); $validator->addValidation("Zip","req","Please fill in your Zip Code"); $validator->addValidation("Security","req","Please fill in your Security Question"); $validator->addValidation("Security2","req","Please fill in your Security Answer"); if($validator->ValidateForm()) { $con = mysql_connect("localhost","uname","pw") or die('Could not connect: ' . mysql_error()); mysql_select_db("beatthis_beatthis") or die(mysql_error()); $FirstName=mysql_real_escape_string($_POST['FirstName']); //This value has to be the same as in the HTML form file $LastName=mysql_real_escape_string($_POST['LastName']); //This value has to be the same as in the HTML form file $UserName=mysql_real_escape_string($_POST['UserName']); //This value has to be the same as in the HTML form file $Password= md5($_POST['Password']); //This value has to be the same as in the HTML form file $Password2= md5($_POST['Password2']); //This value has to be the same as in the HTML form file $email=mysql_real_escape_string($_POST['email']); //This value has to be the same as in the HTML form file $Zip=mysql_real_escape_string($_POST['Zip']); //This value has to be the same as in the HTML form file $Birthday=mysql_real_escape_string($_POST['Birthday']); //This value has to be the same as in the HTML form file $Security=mysql_real_escape_string($_POST['Security']); //This value has to be the same as in the HTML form file $Security2=mysql_real_escape_string($_POST['Security2']); //This value has to be the same as in the HTML form file $sql="INSERT INTO Profile (`FirstName`,`LastName`,`Username`,`Password`,`Password2`,`email`,`Zip`,`Birthday`,`Security`,`Security2`) VALUES ('$FirstName','$LastName','$UserName','$Password','$Password2','$email','$Zip','$Birthday','$Security','$Security2')"; //echo $sql; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } else{ mail('email@gmail.com','A profile has been submitted!',$FirstName.' has submitted their profile',$body); echo "<h3>Your profile information has been submitted successfully.</h3>"; } mysql_close($con); $show_form=false; } else { echo "<h3 class='ErrorTitle'>Validation Errors:</h3>"; $error_hash = $validator->GetErrors(); foreach($error_hash as $inpname => $inp_err) { echo "<p class='errors'>$inpname : $inp_err</p>\n"; } } } if(true == $show_form) { ?> hey gurus, i am a newbie php coder.. i am learning by example. what i am trying to do is write a piece of code which will alter 3 tables (user, bonus_credit, bonus_credit_usage) ---------------------------------------------------------------- the table structure that will be used is as follows: user.bonus_credit user.ID bonus_credit.bonusCode bonus_credit.qty bonus_credit.value bonus_credit_usage.bonusCode bonus_credit_usage.usedBy ---------------------------------------------------------------- so lets say, in bonus_credit i have the following bonusCode = 'facebook' (this is the code they have to type to redeem the bonus qty = '10' ( number of times the bonusCode can be redeemed, but same person can't redeem it more than once) value = '5' (this is the amount of bonus_credit for each qty) Now, I need to write a code that check to see if the code has been redeemed in the bonus_credit_usage table and if the user.ID exists in this table as bonus_code_usage.usedBy, then give an error that its already been used and if it hasn't been used, then subtract 1 from qty, add ID to usedBy and then add the value to the bonus_credit ----------------------- i have started the steps just to create a simple textbox and entering a numeric value to bonus_credit, and that works.. but now i have to use JOIN and IF and ELSE.. which is a little too advanced for me.. so i'd appreciate a guide as i write the code. if(isset($_REQUEST['btnBonus'])) { $bonus_credit = addslashes($_REQUEST['bonusCode']); $query = "update user set bonus_credit=bonus_credit+'".$bonus_credit."' where id='".$_SESSION['SESS_USERID']."'"; echo "<script>window.location='myreferrals.php?msgs=2';</script>"; mysql_query($query) or die(mysql_error()); } Can you help me integrate this code :
<form method="post" action="submit.php"> <input type="checkbox" class="required" /> Click to check <br /> <input disabled="disabled" type='submit' id="submitBtn" value="Submit"> </form>In to this Contact Form code, please? <form action="../page.php?page=1" method="post" name="contact_us" onSubmit="return capCheck(this);"> <table cellpadding="5" width="100%"> <tr> <td width="10" class="required_field">*</td> <td width="80">Your Name</td> <td><input type="text" name="name" maxlength="40" style="width:400px;/></td> </tr> <tr> <td class="required_field">*</td> <td>Email Address</td> <td><input type="text" name="email" maxlength="40" style="width:400px;/></td> </tr> <tr> <td></td> <td>Comments:</td> <td><textarea name="comments" style="width: 400px; height: 250px;"></textarea></td> </tr> </table> </form I use this type of a code to send automatic emails from my website: Code: [Select] $headers = ; $headers .= ; $to = ; Click here to go to Google. ", $headers); I am having hard time figuring out how to do hyperlink on words (like here). If I do something like this: Code: [Select] <a href='http://www.google.com'>here</a> it spits out that exact thing out. Thanks you for your input Can I combine also HTML code in PHP function? For example, can a PHP function include HTML form and the PHP code to handle this form? If yes, this will make my main code much more smaller and readable. If not, is there a way to define an "external macro" like, which allow me to replace pre-defined lines of code with short alias? Hi, Look at this code below: Code: [Select] <?php function outputModule($moduleID, $moduleName, $sessionData) { if(!count($sessionData)) { return false; } $markTotal = 0; $markGrade = 0; $weightSession = 0; $grade = ""; $sessionsHTML = ""; foreach($sessionData as $session) { $sessionsHTML .= "<p><strong>Session:</strong> {$session['SessionId']} <strong>Session Mark:</strong> {$session['Mark']}</strong> <strong>Session Weight Contribution</strong> {$session['SessionWeight']}%</p>\n"; $markTotal += round($session['Mark'] / 100 * $session['SessionWeight']); $weightSession += ($session['SessionWeight']); $markGrade = round($markTotal / $weightSession * 100); if ($markGrade >= 70) { $grade = "A"; } else if ($markGrade >= 60 && $markGrade <= 69) { $grade = "B"; } else if ($markGrade >= 50 && $markGrade <= 59) { $grade = "C"; } else if ($markGrade >= 40 && $markGrade <= 49) { $grade = "D"; } else if ($markGrade >= 30 && $markGrade <= 39) { $grade = "E"; } else if ($markGrade >= 0 && $markGrade <= 29) { $grade = "F"; } $moduleHTML = "<p><br><strong>Module:</strong> {$moduleID} - {$moduleName} <strong>Module Mark:</strong> {$markTotal} <strong>Mark Percentage:</strong> {$markGrade} <strong>Grade:</strong> {$grade} </p>\n"; return $moduleHTML . $sessionsHTML; } $output = ""; $studentId = false; $courseId = false; $moduleId = false; while ($row = mysql_fetch_array($result)) { if($studentId != $row['StudentUsername']) { //Student has changed $studentId = $row['StudentUsername']; $output .= "<p><strong>Student:</strong> {$row['StudentForename']} {$row['StudentSurname']} ({$row['StudentUsername']})\n"; } if($courseId != $row['CourseId']) { //Course has changed $courseId = $row['CourseId']; $output .= "<br><strong>Course:</strong> {$row['CourseId']} - {$row['CourseName']} <strong>Course Mark</strong> <strong>Grade</strong> <br><strong>Year:</strong> {$row['Year']} </p>\n"; } if($moduleId != $row['ModuleId']) { //Module has changed if(isset($sessionsAry)) //Don't run function for first record { //Get output for last module and sessions $output .= outputModule($moduleId, $moduleName, $sessionsAry); } //Reset sessions data array and Set values for new module $sessionsAry = array(); $moduleId = $row['ModuleId']; $moduleName = $row['ModuleName']; } //Add session data to array for current module $sessionsAry[] = array('SessionId'=>$row['SessionId'], 'Mark'=>$row['Mark'], 'SessionWeight'=>$row['SessionWeight']); } //Get output for last module $output .= outputModule($moduleId, $moduleName, $sessionsAry); //Display the output echo $output; } } } ?> This code allallows me to make calculations and display a student's course and linked with it the course the modules in the course and linked with modules are all the sessions. It is able to display what marks each student have got for each module and session. Now look at code below, it is able to display modules and in those modules the sessions that link to those modules: Code: [Select] <?php if($moduleId != $row['ModuleId']) { //Module has changed if(isset($sessionsAry)) //Don't run function for first record { //Get output for last module and sessions $output .= outputModule($moduleId, $moduleName, $sessionsAry); } //Reset sessions data array and Set values for new module $sessionsAry = array(); $moduleId = $row['ModuleId']; $moduleName = $row['ModuleName']; } //Add session data to array for current module $sessionsAry[] = array('SessionId'=>$row['SessionId'], 'Mark'=>$row['Mark'], 'SessionWeight'=>$row['SessionWeight']); } What I want to know is how can I do something similar for course so that it picks out the right modules depending on the course it displays. There maybe some code that needs to be added in the function. Michael Feathers coined the term Legacy Code as being code without automated tests.
Still however Legacy Code evokes a vision in me that it is code that is ugly, old, runs on mainframes, and is probably 3000 lines long, uses globals and questionable code practices.
But say we take this ugly nasty code, and put it very nicely under test, but without doing any refactoring, other than that necessary to be able to put it under test in the first place.
Now that code is under test. But it it still ugly. How would you call ugly code under test?
Would you make a differentiation between old & ugly and modern & pretty code if both are under test?
Hello Everyone I am new to php and indeed Web Development. After testing and Playing a bit, I can get the following code to work as two files, the form calling the *.php file to insert into the database, however, I am trying to create one html/php file that displays the form and then executes the php code to insert into the database once user clickes the button. Please can you assist me with the code? I have something horribly wrong and I cannot find it. Code: [Select] <?php> <html> <head> <title>Personal Details</title> </head> <body> <form method="post" action="contactdetails.html"><font face="Arial"> Call Sign:<br> <input name="callsign" size="5" type="text"><br> Surame:<br> <input name="surname" size="30" type="text"><br> First Name:<br> <input name="firstnames" size="30" type="text"><br> Known as:<br> <input name="knownas" size="30" type="text"><br> RSA ID No.:<br> <input name="rsaid" size="13" type="text"><br> Birth Date:<br> <input name="birthdate" size="12" type="text"><br> <input name="Insert" value="Next" type="submit"></form> </font><br> </body> </html> //php to insert data into table $callsign = $_POST['callsign']; $surname = $_POST['surname']; $firstnames = $_POST['firstnames']; $knownas = $_POST['knownas']; $rsaid = $_POST['rsaid']; $birthdate = $_POST['birthdate']; mysql_connect ("localhost", "jredpixm_testuse", "PHPDevelopment") or die ('I cannot connect to the database because: ' .mysql_error()); mysql_select_db ("jredpixm_test"); $query="INSERT INTO personal_details (callsign, surname, firstnames, knownas, rsaid, birthdate)Values ('$callsign', '$surname', '$firstnames', '$knownas', '$rsaid', '$birthdate')"; mysql_query($query) or die ('Error updating Database'); echo "<p>Thanks, your information has been added to the database.</p>"; ?> Regards Allen How can I make sure that when I submit an new form and new ID (record) is created it is always 4-Digits. record 14 = 0014, record 225 = 0225. Thanks Hi, this is my first time posting here. I am just delving into PHP and I am learning about foreach loops. I have written code in Notepad++ EXACTLY the way I saw it in a tutorial video I watched (I wish I could show the tutorial video to you, but it is on Lynda.com and you have to pay to watch) I attached the file with my code. The example 1 code works just fine. The example 2 code is the one that is not working for some reason. However, it worked for the guy that wrote it in the video, so I am not sure where I am going wrong? *The comments in green are mainly for myself, I explain things to myself so that I don't forget what the code does forloops.php 1.74KB 2 downloads I would appreciate some help. Thank you!!! Alright so I'm attempting to save config data via php. Bellow is the code I currently have, however I'm afraid that when I "flip the switch" and use it that it will error out because of the <?php and ?> tags inside of it... Ideas, suggestions? $config = '../includes/config.php'; $fh = fopen($config, 'w'); $data = ' <?php $dbhost = "'.$database_host.'"; $dbuser = "'.$database_username.'"; $dbpass = "'.$database_password.'"; $dbname = "'.$database_name.'"; $key = "'.$site_key.'"; $cron_key = "'.$database_cron_key.'"; ?> '; fwrite($fh, $data); fclose($fh); |
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