PHP - Simple Image Sorting
I am trying to show images in a directory by date last modified. The code below is showing the oldest ones first then by file type.
How do I modify it to show all files by last uploaded to the directory? I want the newest ones showing first. I am very new to PHP. Code: [Select] <?php //Your folder $files = glob("images/*.*"); $colCnt=0; echo '<table border="0" style="width:1000px;">'; for ($i=1; $i<count($files); $i++) { $colCnt++; if ($colCnt==1) echo '<tr>'; echo '<td width="20%" style="font-size:8.5px; font-family:arial">'; $num = $files[$i]; echo ' <a href="' . $num . '"><img class="thumb ImgBorder" src="'.$num.'" rel="lightbox" alt="random image"></a>'." "; echo '</td>'; if ($colCnt==6) { echo '</tr>'; $colCnt=0; } } echo '</table>'; ?> Similar TutorialsThe code below works well and shows all the images in a folder in reverse chronological order. But I want to limit it to a certain number of images . This would enable me to have several pages of images. So the first page would display the latest 50 images, the second page would show 50-100, and the third, 100-150. Any helps on how to modify? I can create the pages manually. I just want to know how to limit the current page to a certain range. Code: [Select] <?php //Your folder $files = glob("images/*.*"); function sortnewestfilesfirst($a, $b) { return filemtime($b) - filemtime($a); } usort($files, "sortnewestfilesfirst"); $colCnt=0; echo '<table border="0" style="width:1000px;">'; for ($i=0; $i<count($files); $i++) { $colCnt++; if ($colCnt==1) echo '<tr>'; echo '<td width="20%" style="font-size:8.5px; font-family:arial">'; $num = $files[$i]; echo ' <div class="ImgBorder"> <div class="clipout"> <div class="clipin"> <a href="' . $num . '" rel="lightbox[all]"><img class="thumb ImgBorder" src="'.$num.'"> </a> </div> </div></div>'." "; echo '</td>'; if ($colCnt==6) { echo '</tr>'; $colCnt=0; } } echo '</table>'; ?> ok so ive found what looks to be a decent image uploader. which if anyone is interested can be found here; http://www.white-hat-web-design.co.uk/blog/resizing-images-with-php/ I have followed the instruction and added the few bits needed to make it work properly. However hence me beening here, it doesnt work. Im not overly familiar with the syntax of -> so maybe I am outputting the wrong name in the move_upload_file but the error I get on the server is Unable to move '/tmp/phpJnOkXP' to bla bla bla upload-new.php on line 126 Upload fail which is the move_upload line Here is my code <?php if( isset($_POST['uploadbtn']) ) { $folder = "{$_SERVER['DOCUMENT_ROOT']}/images/test/"; $fileName = $_FILES['newImage']['name']; $tmpName = $_FILES['image']['tmp_name']; include('../simple-image.php'); $image = new SimpleImage(); $image->load($tmpName); $image->resizeToWidth(600); $image->output(); $uploaded = move_uploaded_file($tmpName , $folder.$fileName); if($uploaded){ echo "Upload success"; } else { echo "Upload fail"; } } ?> <form action="" method="post" enctype="multipart/form-data" name="uploadfrm"> <input name="image" type="file" /> <input name="uploadbtn" value="Upload" type="submit" /> </form> hey guys im trying to impliment a overlay to images uploaded by the user to allow to delete and crop...now im not sure if im going aroung this the right way (but it works sort of)...the problem im having is that the overlay.gif which is a transparent image which has 2 small images at the top of each corner...but when the original image is hovered over the overlay is out of position showing the 2 small images at the bottom of the div and not at the top where it should be.
im guessing it is a css issue...any advise would be greatly appreciated...thank you
#overlay { width: 110px; height: 110px; } .selected-image{ width: 110px; height: 110px; } #overlay:hover .selected-image { opacity: 0.4; filter: alpha(opacity=40); } #overlay:hover { background-image: url('overlay.gif'); width: 110px; height: 110px; } <div id="overlay"><img class="selected-image" src="logo.png" /></div> I am using cakephp and i need a quick simple image upload and re-size script, can any one help? Hi, I'm trying to make a simple slideshow with forward and back buttons that change the image inside a div in php. When I press the "further" button, it jumps from index[0] to index[1] and never shows the first image. Then when I click more it doesn't go forward. When I click back, it goes back to a black screen div. Any help getting this to work is GREATLY appreciated because I've been trying for 2 days with tutorials and can't get it. Thanks. Derek Here are the php parts that are relevant, my page was too large and confusing to include. first, the $background array where I store my images. Code: [Select] $background = array ( "<img src='sundragon_environments/ocean/ocean1_FRAME.jpg'/>", "<img src='sundragon_environments/ocean/ocean1_FRAME2.jpg'/>" ); then the code to move the images forward and backwards if the buttons are pressed. Code: [Select] if(!empty($_POST['further'])) { $currentBackground=next($background); } elseif(!empty($_POST['back'])) { $currentBackground=prev($background); } and now to echo out the images inside the div. Code: [Select] <div id="background"><?php echo $currentBackground;?></div> Hi Guys, Please can someone here help me with a simple browse for an image from the computer and then when the form is submitted it uploads the image and then saves the image url in my DB. my form page is here http://bit.ly/gntCvD Any help will be appreciated. thanks Craig This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=348759.0 Hi, I am planning to display remote images with the following code but it seems to return errors. <?php $image_dir = 'http://www.domain.com/images/' ; $dir_handle = opendir( $image_dir ); $count = 0 ; $display = '' ; while( $filename = readdir($dir_handle)){ if( preg_match( '/$[a-z0-9]{4}_th\.jpg$/' , $filename ) ){ $display .= " <img src='$image_dir$filename' /> " ; $count++ ; if( $count % 10 == 0 ){ $count=0; $display .= "<br />"; } } } closedir( $dir_handle ); echo $display ; ?> I am thinking might be the $image_dir cannot use address format.... Errors is as follow Quote Warning: opendir(http://www.foo.com/images/) [function.opendir]: failed to open dir: not implemented in /home/jch02140/public_html/test.php on line 3 Warning: readdir(): supplied argument is not a valid Directory resource in /home/jch02140/public_html/test.php on line 6 Warning: closedir(): supplied argument is not a valid Directory resource in /home/jch02140/public_html/test.php on line 16 Hi Guys I'm trying to get clients to: 1. upload an image 2. fill out details 3. submit image and details to me via email 1. Uploading the image is fine, they choose it and it displays on the next page 2. They fill in form details 3. then click submit to send to me - I get all details except the image How do I keep the image variable around to insert it into the details form and email it? The image appears to be displayed on the second page, then the variable disappears (is deleted) and isn't available in step 3 to submit as part of the email. I'm sure it's a simple fix - I'm pretty new with php and I've started kicking things so I thought it was time to ask for help. Upload-image-code <?php if($_FILES) { $img = $_FILES['filename']['img']; switch($_FILES['filename']['type']) { case 'image/jpeg' : $ext = 'jpg'; break; case 'image/png' : $ext = 'png'; break; default: $ext = ''; break; } if ($ext) { $n = "image.$ext"; move_uploaded_file($_FILES['filename']['tmp_name'], $n); echo "<span class='uploaded-photo'>uploaded image '$img' as '$n':</span> <br />"; echo "<img src='$n' />"; } else echo "'$img' is not a supported image file"; } //else echo "<span class='uploaded-photo'>No image has been uploaded</span>"; ?> $n is available to be displayed on page 2 and it works Page 2 contains the rest of the form, but when I submit the form $n isn't available to be sent with the other data (i have tried REQUEST $img as well. Submit form code <?php $name = $_REQUEST['name'] ; $email = $_REQUEST['email'] ; $phone = $_REQUEST['phone'] ; $address = $_REQUEST['address'] ; $pname = $_REQUEST['pname'] ; $pdescription = $_REQUEST['pdescription']; $plow = $_REQUEST['plow'] ; $phigh = $_REQUEST['phigh'] ; $purl = $_REQUEST['purl'] ; $ponline = $_REQUEST['ponline'] ; $n = $_REQUEST['n']; $img = $_REQUEST['img']; if (!isset($_REQUEST['email'])) { echo "we need your name and email address please" ; } elseif (empty($name)){ echo "please enter your name"; } elseif (empty($email)){ echo "please enter your email address"; } elseif (!eregi("^[_a-z0-9-]+(\.[_a-z0-9-]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,6})", "$email")) { echo"please check your email address - it doesn't appear to be a valid format"; } else { mail( "eamail@address.com", "Subject", "$name\n $email\n $phone\n $address\n $pname\n $pdescription\n $plow\n $phigh\n $purl\n $ponline\n $n\n $img", "$email"); header( "Location: ../index.php" ); } ?> Would really appreciate any help - if you need full code please let me know. Thanks @webecho I have a very simple piece of code to create a grid based gallery. The thumbnails are loaded from a single directory and are name 1.jpg... 2.jpg... 3.jpg etc At the moment the images appear to be loaded in randomly. I want them to load in numerically in terms of their filename. I know I may need to use 'sort' or 'natsort' but where in the code? Thanks for any help you can give me Code: [Select] <? $images = "Images/Bag Thumbs/"; # Location of small versions $big = "ruxxwomens.php?id="; # Location of big versions (assumed to be a subdir of above) $cols = 4; # Number of columns to display if ($handle = opendir($images)) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != ".." && $file != rtrim($big,"/")) { $files[] = $file; } } closedir($handle); } $colCtr = 0; echo '<table width="800" cellspacing="0" cellpadding="0" border="0"><tr>'; foreach($files as $file) { if($colCtr %$cols == 0) echo '</tr><tr>'; echo '<td align="center"><a href="' . $big . $file . '"><img src="' . $images . $file . '" cellspacing="0" cellpadding="0" border="0"></a></td>'; $colCtr++; } echo '</table>' . "\r\n"; ?> Hello. I have a multi dimensional array that needs to be sorted. Array top25 [index][product id][number_of_purchases]. The index will contain a unique number for each product id. First product will be 1, second product will be 2, etc. The product id will be a id number like 34324ac9a89. The number of purchases will be how many times the item has been purchased. - End result: I want to print the 25 most purchased products in this format. product id - number of purchases a39acz - 503 a8cz9c - 480 zc8ac - 392 How do I do this? Thanks I have a situation where I need to sort files on a screen based on the date that is embedded into the file name. The problem is that I am sorting based off the file name, and when I get my output the LEGACY file always comes out on top of the sort because it starts with a 0 meanwhile the rest have dates appended the the filename so I don't have a problem sorting those. Please help me if you can. <? //Special case for extra files IF($Recordmyrow['App'] == "(Printable)") { $display = false; $column3 = "Printable VER"; IF($securityvalue == "P") { if(substr($path, 0, 5) == "file:") { $filename = substr($path, 5); if(file_exists($filename)) { $basename = substr($filename, 0, strrpos($filename, '.')); $ext = ".pdf"; $allfiles = glob("{$basename}*.pdf"); rsort($allfiles, SORT_NUMERIC); foreach($allfiles as $file) { if($ext == ".pdf") { $column4 = "<a href=\"pdf.php?src={$file}\">VIEW</a><br />\n"; $codate = substr($file, 70, 8); $co = substr($file, 59, 1); if ($codate != "pdf") { $column3 = "Printable File - ".$codate; } elseif ($codate == "pdf") { $column3 = "Printable File - LEGACY"; } IF($lastGroup != $Recordmyrow['Grouping']) { $lastGroup = $Recordmyrow['Grouping']; ?> <TR> <TD colspan="4" align="center" bgcolor="#418765"><B><FONT color="white"><? echo $Recordmyrow['Grouping'] ?></FONT></B></TD> </TR> <? } ?> <TR> <TD class="display" align="center" bgcolor="<?=changeColor($rowcount)?>"><B><? echo $column1 ?></B></TD> <TD class="display" bgcolor="<?=changeColor($rowcount)?>"><B><? echo $column2 ?></B></TD> <TD class="display" bgcolor="<?=changeColor($rowcount)?>"><B><? echo $column3 ?></B></TD> <TD class="display" bgcolor="<?=changeColor($rowcount)?>" align="center"><B><? echo $column4 ?></B></TD> </TR> <? $rowcount++; } } } else { $column4 = "Not Available"; ?> <TR> <TD class="display" align="center" bgcolor="<?=changeColor($rowcount)?>"><B><? echo $column1 ?></B></TD> <TD class="display" bgcolor="<?=changeColor($rowcount)?>"><B><? echo $column2 ?></B></TD> <TD class="display" bgcolor="<?=changeColor($rowcount)?>"><B><? echo $column3 ?></B></TD> <TD class="display" bgcolor="<?=changeColor($rowcount)?>" align="center"><B><? echo $column4 ?></B></TD> </TR> <? $rowcount++; } } } } I have an array like this: $array[$row] = array ( 'name' = $name, 'discount' = $discount, 'price' = $price ); Now, I have about 200 of those in that array, and im trying to sort by the discount, highest 1st. How would I go about doing that? Thanks. i need to sort my database results by the day they were added to the database. There is a column with the timestamp of when they were inserted but how do i group them by the day they were inserted so i can display them as such: Mon 14th: 5 records Tues 15th: 11 records etc. Just a further question from a earlier post that was complete if i do a search and i want to order them from a drop box the if statement would it just look like Quote "select * from Table order by '".$_POST['order']."'" Or would this not work ? Thanx Part of my code: Code: [Select] <?php $arr = array ("Christina", "Daniel", "Andreea); reset($arr); foreach ($arr as $username) { //more code here ... foreach ($stats as $result) { echo $username."'s points - ".$result."<br />"; } } ?> And gives this: Code: [Select] Christina's points - 14 Daniel's points - 45 Andreea's points 23 My question is: can you sort the the $result so it will show Code: [Select] Daniel's points - 45 Andreea's points 23 Christina's points - 14 Thank you I need to sort this: Code: [Select] customVar($var1, $var2, $var3); I have tried: Code: [Select] sort(customVar($var1, $var2, $var3)); Hi - I'm modifying some PHP code that someone else wrote. Below is a snippet of code that basically takes mp3 files files within all the folders in a directory, and creates an RSS feed. In the resulting feed, the files are intermingled in date order. Instead, I'd like them sorted by the directory that they are in. So, if there are files in these directories: 01-First 02-Second 03-Third I'd like all the files in the "01-First" directory to come before the "02-Second" directory and so on. Within each directory the files can be sorted as they currently are. The name of the directory in the code is signified by $dir_name. I tried sort() and array_multisort() but I couldn't get either of them to work the way I wanted. Any thoughts? if ($url_params['mode'] == 'rss2') { print getRSSHeader('UTF-8', $device, $vm_config, $vm_name, $web_master, $logo_image,$context); $mailboxes = array(); if ($dev_dir = @opendir($VMHome . $device)) { //might fail if mailbox has not received first message yet while ($f = readdir($dev_dir)) { if (!eregi("tmp","$f") && !eregi("\.+","$f") && !eregi("Exclude-From-CD", "$f")) { //skip tmp directory and Exclude-From-CD Directories array_push($mailboxes,"$f"); #collect all existing mailboxes } } array_multisort($mailboxes, SORT_DESC); foreach ($mailboxes as $mailbox) { $files=array(); $dir_name = $VMHome . $device . '/'. $mailbox .'/'; $dir = opendir($dir_name); while ($f = readdir($dir)) { if (eregi("\.txt",$f)){ #if filename matches .txt in the name array_push($files,"$f"); #push into $files array } } foreach($files as $file){ $props = getProperties($dir_name, $file); $uid = getMP3File($dir_name, $file, $props, $device, $mailbox, $vm_config, $vm_name,$context); print getRSSItem ($props, $uid, $dir_name, $device, '/' . $mailbox . '/', $context); } } } print ' </channel> </rss>'; } I am looking for information on how to accomplish this: I want to order an array based on a variable. I have an array that is set like this array(1,2,3,4,5,6). I want to order this array base on a variable that will be in the array. So say my variable $x = 3, I want to order the array starting with the number right after the $x. So the array would look like this now array(4,5,6,1,2,3). Is this even possible? Another example if $x = 6, The array would be array(1,2,3,4,5,6). So basically order the array so that the set variable (in this case $x) will be at the end and the rest will run in order. Is it possible to sort a table of mysql data, by using a variable? I'm trying this: Code: [Select] <?php $result = mysql_query("SELECT * FROM members ORDER BY '$totalpower'"); echo "<table border='1' cellpadding='10'>"; echo "<tr> <th>Rank</th> <th>Username</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo '<td> </td>'; echo '<td>' . $row['Username'] . '</td>'; echo "</tr>"; } echo "</table>"; ?> It display's a list of username's but not in the correct power order. $totalpower is defined: Code: [Select] <?php //power calculations $result = mysql_query("SELECT * FROM members WHERE Username='$_SESSION[Username]'") or die(mysql_error()); while($row = mysql_fetch_array( $result )) { $power1 = $row['ounit1'] * 50; $power2 = $row['ounit2'] * 70; $power3 = $row['ounit3'] * 110; $power4 = $row['ounit4'] * 200; $power5 = $row['ounit5'] * 150; $power6 = $row['ounit6'] * 300; $power7 = $row['ounit7'] * 500; $power8 = $row['ounit8'] * 450; $power9 = $row['ounit9'] * 650; $power10 = $row['ounit10'] * 350; $power11 = $row['ounit11'] * 600; $power12 = $row['ounit12'] * 1000; $dpower1 = $row['dunit1'] * 50; $dpower2 = $row['dunit2'] * 70; $dpower3 = $row['dunit3'] * 110; $dpower4 = $row['dunit4'] * 200; $dpower5 = $row['dunit5'] * 150; $dpower6 = $row['dunit6'] * 300; $dpower7 = $row['dunit7'] * 500; $dpower8 = $row['dunit8'] * 450; $dpower9 = $row['dunit9'] * 650; $dpower10 = $row['dunit10'] * 350; $dpower11 = $row['dunit11'] * 600; $dpower12 = $row['dunit12'] * 1000; $dbase = $row['baselevel'] * 3000; } $offencepower = $power1+$power2+$power3+$power4+$power5+$power6+$power7+$power8+$power9+$power10+$power11+$power12; $defencepower = $dpower1+$dpower2+$dpower3+$dpower4+$dpower5+$dpower6+$dpower7+$dpower8+$dpower9+$dpower10+$dpower11+$dpower12+$dbase; $totalpower = (($offencepower+$defencepower)/ 100 * 30) + $offencepower+$defencepower; ?> Also how do I add auto numbers in the left column e.g 1. 2. 3. 4. Thanks in advance. |