PHP - Php Inside Variable To Echo Html?
I'm redoing my login script using functions and a basic switch function checking against a $_GET variable (hope you guys know what I'm talking about).
What I want to do is create two functions: 1 that displays the login form and 1 that processes the information The form tag would look like this: <form action=\"<?php $_SERVER['PHP_SELF']?>?action=process\" method=\"post\"> </form> Here's my switch statement: Code: [Select] <?php //**************************************** //****************Action****************** //**************************************** switch ($_GET["action"]) { default: case "index": if (!$_SESSION["member"]) { if (!$timeout) { display_form(); } else { echo $timeout_error; } } else { echo "You are already logged in."; } break; case "process": if (!$_SESSION["member"]) { if (!$timeout) { process_form(); } else { echo $timeout_error; } } else { echo "You are already logged in."; } break; } ?> This runs as soon as "login.php" loads. It'll automatically run the commands under case "default" and "index". It'll first check to see if the member's logged in. If not, it'll then check to see if "$timeout" is true ($timeout becomes true if the member has attempted to login 5 times and failed). If not, it'll display the login form, by running "display_form()". Once the form has been filled and submitted, the commands under case "process" will be performed. Again it will first check to see if the member's logged in. If not, it'll check to see if "$timeout" is true. If not, it'll start validating the forms. For the validation, I've created a variable called "$errors_found", and scripted one if statement checking to see if the email and password exist. If so, the variables "$rm_field_un" and "$rm_field_pw" become true, as well as "$errors_found". So, back to submission of the form... If "$errors_found" is true, display the form (when the form is displayed, there will be an if statement within that says "<?php if ($rm_field_un) { echo "Username is wrong."; } ?>", which will be displayed right underneath the username field and label. Same with the password elements). If "$errors_found" is not true, go ahead and register the member. Now, here's where I need help, because I'm really confused as to how to accomplish this. The "display_form()" function will contain a single variable called "$login_form". It will contain a value of the HTML constructed login form, and the function will return the variable. Remember how I stated in the third paragraph up that I will have <php> statements within the form which would display errors if necessary? Well, how do I put those if statements within the HTML, which is contained within the variable? If that last question confuses you, allow me to present you with an instance: Code: [Select] <?php function display_form() { $login_form = " <form name=\"login_form\" method=\"post\" action=\"<?php $_SERVER['PHP_SELF']?>?action=process\"> Username: <input type=\"text\"> <?php if ($rm_field_un) { echo "Username is wrong"; } ?> "; return $login_form; } ?> See what I mean? This code confuses me ALOT. I'm not sure if the <php> tags are needed as it is already contained within existing ones, or what. Can somebody please help me out? Any and all help is much appreciated. =D Similar TutorialsIm having a problem with getting the quotes correct with this. I can either get the variable to work in the href and img src or in the css. Anyone have any ideas on this. Cuase im really stuck. This allows the $address and $cos to echo in but not the css variables <td><?php echo "<a href='planet_profile.php?planet=$address'> <img src='images/star.jpg' id='$cos' style='position:absolute;' left:'$b_x px;' top:'$b_y px;'></a>"; ?></td> and this allows only the css variables to work <td><?php echo '<a href="planet_profile.php?planet="' . $address . '"> <img src="images/star.jpg" id="' . $cos . '" style="position:absolute; left:' . $b_x . 'px; top:' . $b_y . 'px;"></a>'; ?></td> Trying to figure out how to make it so name is a link to the profile when its echo anyone know how to do this? im at a huge stand still Code: [Select] <?php $sql = "SELECT name FROM users WHERE DATE_SUB(NOW(),INTERVAL 5 MINUTE) <= lastactive ORDER BY id ASC"; $query = mysql_query($sql) or die(mysql_error()); $count = mysql_num_rows($query); $i = 1; while($row = mysql_fetch_object($query)) { $online_name = htmlspecialchars($row->name); echo '<a href="Inbox.php">"'[$goauld]'</a>"'; ?> Hi all. I have this code. <?php $ext = ' <form action="/members/clubs/view-activity.php" method="post" name="venuefrm"> <button type="submit" id="close" class="link"><span>View Activity</span></button> <input name="activity" type="hidden" value="<?php echo $activites['activityID']; ?>" /> </form>'; ?> The code falls down at the value="<?php echo $activites['activityID']; ?>" part. Can someone please show me how I break into php to write this part properly as I dont understand an it is obviously wrong. Thanks Danny I'm trying to input the results from a query into html, but I'm just getting the variable names rather than their values. I used single quotes for the echo statement, but I think I must need to switch to double to do that. But then I have problems with the double quotes from the class names (ex. class="SideBoxTitle"). Code: [Select] <?php // get user's videos from database $conn = mysqli_connect($dbhost, $dbuser, $dbpass) or die("MySQL Error: " . mysql_error()); $query = "SELECT * FROM haas12_test.videos"; $result = mysqli_query($conn, $query) or die ("Couldn't execute query."); while($row = mysqli_fetch_assoc($result)) { extract($row); echo ' <div id="topBox" class="mainVideoSideBoxes" > <div class="SideBoxTitle" ><h3> $vidtitle </h3> </div><!-- close SideBoxTitle --> <div class="sideBoxVidContainer"> <div class="SideBoxScreenCast" > $vidurl </div><!-- close SideBoxScreenCast --> <div class="SideBoxDesc" ><p> $viddesc </p> </div><!-- close SideBoxDesc --> </div><!-- close sideBoxVidContainer --> </div><!-- close mainVideoSideBoxes --> </div><!-- close mainVideoSideBoxes --> '; // end echo staement } ?> OK, have no idea what's going on... I've done this a million times... why wont this output!?? I must have a major brain meltdown and dont know it yet!!! Code: [Select] <?php // this echoes just fine: echo $_POST['testfield']; // but this wont echo: echo if (isset($_POST['testfield'])) { $_POST['testfield'] = $test; } echo $test; /// or even this DOESNT echo either!: $_POST['testfield'] = $test; echo $test; ?> So I need to echo a row from my database with php, but where i need to echo is already inside an echo. This is my part of my code: $con = mysql_connect("$host","$username","$password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("main", $con); $result = mysql_query("SELECT * FROM Vendor"); while($row = mysql_fetch_array($result)) { //I need to echo right here .................. but I get a blank page when I try this. Please Help. echo '<option value=$row['vendor_id']>'; echo $row['vendor_id']; echo '</option>'; } mysql_close($con); Result: A Blank page. Thanks in advance! Is it possible to echo php inside php? Im guessing not because you are already inside php but there must be a way round my problem. What I would like to do is if the url has project = something then echo <?php require "footer.php"; ?> if not dont echo anything. What is the best way to go about doing this ? how can i put an if statement inside an echo this is what i want to do Code: [Select] <?php echo "<li> <a class='thumb' href='../images/Sections/pinkpanthers/" . $year . "/" . $sessions . "/" . $day . "/" . $y . ".jpg' title=''> <img src='../images/Sections/pinkpanthers/" . $year . "/" . $sessions . "/" . $day . "/thumbs/" . $y . ".jpg ' /></a><div class='caption'> <div class='download'><a href='../images/Sections/pinkpanthers/" . $year . "/" . $sessions . "/" . $day . "/big/" . $y . ".jpg ' target='_blank' />Download</a> </div><div class='image-desc'>" . if ($count == 1){echo "<a href='tag.php?tag=$name'" . $name . ">" . $name . "</a>";}if ($count > 1){$z = 0;$w = $count - 1;while ($z <= $w){$p = $multi[$z];echo "<a href='tag.php?tag=$p'" . $p . ">" . $p . "</a>";$z++;}} . "</div></div></li>"; ?> all the code works wright up until i added the if statements in the last little bit Hello, I need to add rel="..." in the first part of the script but it is not working, below is the script: Code: [Select] echo " <a href='products/".$image[$abc]."' target='_blank'><img border=0 src='products/thumbs2/".$image[$abc]."' /></a>"; Thank you, Currently whether data from the queries are found or not, its surrounded inside the div tags... i want to somehow echo the div tags inside the while loop, but only echo once. the confusing part for me is that the queries are connecting to 2 different tables for data.. and both need to be found for the div to be echo. if($item['quantity'] >= 1){ if($item2['type'] == 'weapon'){ code below.... Code: [Select] <div class="g_content"><h3 style="text-align: left"> Weapons</h3><div class="g_text"> <table align='center' cellspacing='10'> <?php $current_col = 1; $max_col = 4; $query = $db->execute("select * from items where `player_id`=?", array($player->id)); while($item = $query->fetchrow()) { $query2 = $db->execute("select * from `blueprint_items` where `id`=?",array($item['item_id'])); $item2 = $query2->fetchrow(); //DISPLAY IF QUANTITY IS 1 OR MORE. if($item['quantity'] >= 1){ if($item2['type'] == 'weapon'){ //Open new row if first column if($current_col==1) { echo "<tr>\n"; } //Display current record echo "<td width='25%'>"; echo "<center><img src=\"{$item2['img']}\" width='80' height='80' style=\"border: 1px solid #CC9900\"></center>"; echo "<center><a href=\"../description.php?id={$item2['id']}\">{$item2['name']}</a> [x".$english_format_number = number_format($item['quantity'])."]</center>"; echo "<center>$".$english_format_number = number_format($item2['value'])."</center>"; echo "<center>[<a href='../item.php?sell=".$item['id']."'>Sell</a>] [<a href='../item.php?market=".$item['id']."'>Market</a>] <br>[<a href='../item.php?send=".$item['id']."'>Send</a>] [<a href='../item.php?equip=".$item['id']."'>Equip</a>]</center><br>"; echo "</td>\n"; //Close row if last column if($current_col==$max_col) { echo "<tr>\n"; $current_col = 0; //<---Changed } $current_col++; } } } //Close last row if needed if ($current_col!=1) { for(; $current_col<=$max_col; $current_col++) { echo "<td> </td>\n"; } } ?> </table> </div></div> This probably doesn't matter much, but I am using a 'Display' class for final output to the browser. The class will display the obvious HTML header and then display either the full site or the mobile site. It also displays the CSS / JS (which is previously selected in the page-specific controller code as there are variations based on server-side checks). Basically it is the ONLY class that actually needs to send anything to the browser. When I begin output and echo inside the class, that is the end of the script - there is no more server-side code to execute. If I shouldn;t echo inside the class, is it that bad to do so? Hello guys im new to php i been coding for like a week now, i need some help here i have been stuck for like 6 hours XD,is it possible to write an IF Statement inside an echo? //this is what i want to do // echo a table and a delete button // and if you click on the delete button it echoes out "DELETED" echo " <table width='528px'> <tr> <td> </td> <td> <center><font size='5'>$tittle</font></center><br> </td> </tr> <tr> <td> </td> <td> $message </td> </tr> <tr> <td> </td> <td> <font size='1'>Posted By:<font color='green'>$author</font> on <font color='gray'>$date</font> at <font color='gray'>$time</font></font> <input id='delete' name='delete' type='submit' value='Delete' > if ($_POST['delete']) { echo "DELETED"; } <td> </td> </tr><br><br> </table> "; Hi
I try to echo out random lines of a html file and want after submit password to whole content of the same html file. I have two Problems.
1st Problem When I echo out the random lines of the html file I don't get just the text but the code of the html file as well. I don't want that. I just want the text. How to do that?
for($x = 1;$x<=40;$x++) { $lines = file("$filename.html"); echo $lines[rand(0, count($lines)-1)]."<br>"; }I tried instead of "file("$filename.html");" "readfile("$filename.html");" But then I get the random lines plus the whole content. Is there anything else I can use instead of file so that I get the random lines of text without the html code?P.S file_get_contents doesn't work either have tried that one. 2nd Problem: As you could see in my first problem I have a file called $filename.html. After I submit the value of a password I want the whole content. But it is like the program did forget what $filename.html is. How can I make the program remember what $filename.html is? Or with other words how to get the whole content of the html file? My code: if($_POST['submitPasswordIT']){ if ($_POST['passIT']== $password ){ $my_file = file_get_contents("$filename.html"); echo $my_file; } else{ echo "You entered wrong password"; } }If the password isn't correct I get: You entered wrong password. If the password is correct I get nothing. I probably need to create a path to the file "$filename.html", but I don't know exactly how to do that. hello, im trying to add a hyperlink that launches in a new window to the following (in the last column) any ideas? Code: [Select] echo "<tr>"; echo "<td align='center'>" . $row["ID"] . "</td>"; echo "<td align='center'>" . $row["Name"] . "</td>"; echo "<td align='center'>" . $row["jobNO"] . "</td>"; echo "<td align='center'>" . $epn . "</td>"; echo "<td align='center'>" . $cname . "</td>"; echo "<td align='center'>" . $cadd . "</td>"; //want to add a hyperlink here echo "</tr>"; } echo "</table>"; } Hi I am trying to use the nl2br function like this while ($row = mysqli_fetch_array($query)) { //May need this later to output pictures // $imageURL = 'upload/'.rawurlencode($row["filename"]); echo " <div class='divTableRow'> <div class='divTableCell'>{$row['User']} ;</div> <div class='divTableCell'>nl2br({$row['CommentText']});</div> </div> \n"; } However the output just looks like the attached picture. When I check in the sql db I can see the line breaks when doing a select * from Table ;
Hi I am new to PHP and this is my first post one here so appologies is this questions seems a bit dumb! I have an if clause such that if a button is pressed on my web page then i want to reload the page and include a new form on it. I am having a problem getting the $_SERVER['PHP_SELF'] command to work from iside a echo command. I must not be escaping the code correctly with back slashes: I currently have the line : echo"<form method=\"POST\" action=\"\<?$_SERVER['PHP_SELF']?\>\">"; However this doesnt seem to work as my page just doesnt display in the browser. Any advice is much appreciated. Thanks for taking the time to read. how do i get the image to show as the code i have is echoing what i have been told is binary, not confirmed. and not the images. all images are .jpg Code: [Select] $allowed_types = array('png','jpg','jpeg','gif'); $imgdir = '/home/mysite/ftpfolder'; $imgFilesArray = scandir($imgdir); foreach ($imgFilesArray as $imgkey => $imgvalue) { $imgInfo = pathinfo($imgdir . '/' . $imgvalue); $imgExtension = $imgInfo['extension']; if(in_array($imgExtension, $allowed_types)) { readfile($imgdir . '/' . $imgvalue); //echo '<img src = "'. $imgdir .'/'. $imgInfo['basename'].'" alt="" />'; } } images are FTP'd to the ftpfolder and can not be placed anywhere else but this folder due to security reasons. Hi! My question is probably simple but I've been scratching my head for hours now... I'm pretty new to php. I have an online form for orders; when submitted, an email is sent to the shop manager containing the info the client has filled in. So I pass all the info in the code below, but I can't manage to echo the array containing the order's items/qty/item_code. (I'm using Wordpress, Oxygen Builder, Metabox and Code Snippets, if that helps). Here's the code (used as a Code Snippet):
add_action( 'rwmb_frontend_after_process', function( $config, $post_id ) {
$name = rwmb_meta( 'name', '', $post_id );
Nom: $name
$headers = ['Content-type: text/html', "Reply-To: $email"];
Help with this would be greatly appreciated! Please let me know if any details are missing. Thanks in advance! Jordan Edited June 23 by JordanCThis topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=316454.0 |