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PHP - Little Preg_replace Trouble.
$titleurl = preg_replace('/[^a-zA-Z0-9_ -%]/', '-', $d); $titleurl = preg_replace('/[ ]/', '-', $titleurl); How do you add to this to replace ---- with - --- with - -- with - and remove quotes? How do you remove a - if it's at the very end of $titleurl. For example, replace My-iPhone- with My-iPhone Similar TutorialsI am trying to pull out the image HTML tag but its not working as expected. Here is what I am doing $removeimagetag='/<a href/'; $replacwith = "illegal"; $_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']); in the 'descr' there is a <a href="http://s635.photobucket.com...... When it post it does not strip out the <a href So the image is displayed. I tried a modified version to test to see if it work that looked like this. $removeimagetag='/goofy/'; $replacwith = "illegal"; $_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']); When the word goofy appears in the text then its replaced with the word illegal, Also I would like to make it so that it replaces the entire line from the <a href....... to the </a> with a phrase that says "this feature is not allowed" rather than just the part in the front...the <a href. Any help you can be will be greatly appreciated. Hi, I'm kind of new to PHP and very new to Regular Expressions and I was wondering if someone could help run through this code snippet from a callback function in a Joomla plugin called Affliates Feed. So far I have this is passed a pointer to variable item (I understand this is effectively the same as passing the variable but a lot less CPU intensive. Creates an array with keys and values Now the for loop I am stuck with, I understand the interation through the array. But what is preg_replace returning and why pass it back that way hasn't it already done its job? Can any one help? And please feel free to be as basic as possible :help: Thanks, Adam Code: [Select] function gardening(&$item) { #renaming categories, not the most efficient use for example strtolower first, and use only lowercase in the rename array $rename=array( ' Gardening?' => '', 'Climber Plants' => 'Climbing Plants', 'Seeds.*Bulbs' => 'Seeds Bulbs', 'Plant protection' => 'Horticultural goods', 'Garden structures' => 'Garden buildings',); foreach ( $rename as $k => $v ) { list($item['menu_1'],$item['menu_2'])=preg_replace("#$k#",$v,array($item['menu_1'],$item['menu_2'])); } $item['menu_1']=ucfirst(strtolower($item['menu_1'])); $item['menu_2']=ucfirst(strtolower($item['menu_2'])); $item['menu_3']=ucfirst(strtolower($item['menu_3'])); $item['menu_4']=ucfirst(strtolower($item['menu_4'])); } Hi everyone, how do i add and ampersand symbol into preg_replace preg_replace("/[^a-zA-Z0-9\s\-\'\,\.\_]/" where do i place the symbol? & Hello ppl, I have this website link http://www.somesite.com/anotherpage/yetotherpage.html what i want to make is using preg_replace that the final result will be www.somesite.com I currently have some custom tags, similar to BBCode, to be used for comments on my site. I'm trying to create a [nobr] tag (note: I know the no break tag will work in many major browsers, but it's deprecated, so I'm trying to be compliant). The idea is that if I encounter the [nobr] tag, I need to remove all line breaks. Here's the best I can do, but it's not working as I had hoped. Here's what I currently use to replace line breaks with a break tag. Code: [Select] $str=str_replace("\r\n","<br>",$str); Here's my attempt at introducing this new tag. Code: [Select] function BbToHtml($str) { $before=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\1",$str); $during=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\2",$str); $after=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\3",$str); $during=str_replace("\r\n","",$during); if($during != "") { // If the [nobr] tag was found, go with the new string. $str = $before.$during.$after; } else { // If the [nobr] tag was not found, go ahead like normal. $str=str_replace("\r\n","<br>",$str); } return $str; I can't get that working. Any ideas on how to fix that, or a completely alternate method of doing it? Thank you! Hi there! I need to echo some text from a database table, this text should be linked to a url stored in the same database. I am trying to do this with preg_replace but I am terrible at it! I keep getting this error: Warning: Wrong parameter count for preg_replace() while($row = mysql_fetch_array( $result )) { $reg_exUrl = "/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/"; echo preg_replace ($reg_exUrl, $row['title'); Any suggestion? Thanks I'm trying to search a string for all occurences of a pattern, then append text after that pattern. The example is:
SUM("foo") as "bar"
and have it display as:
SUM("foo") over() as "bar"
The "SUM" could be any SQL aggregate and be case insensitive. So For bonus points, let's say the valid aggregates are array('SUM', 'MAX', 'MIN', 'AVG'). My plan right now is to figure it out for SUM, then loop it replacing the aggregate.
This is what I have so far... and it is not working.
$l= 'SUM("foo") as "bar"';
$l=preg_replace('/([^"]+")/','\0 over()',$l);
Thanks,
Ryan
im trying to do a complex(i think) prg replace but i keep getting the error: Code: [Select] Failed evaluating code: $lang->showing-1,1 the code i am trying to replace is: Code: [Select] <asf: lang[showing-<asf: var[num_report_alerts]>,<asf: var[num_report_alerts]>]> and the preg_replace is: Code: [Select] $content = preg_replace('|\<asf: lang\[(.*?)-(.*?)\]\>|e', '$lang->replace_vars($lang->//1, array(\\2))', $content); its supposed to take everything inside <asf: lang[]> and echo \\1 which would be "showing" and then add \\2 into an array which would be "array(1,1)". So the output would be showing 1 of 1. Anyone know where im going wrong? i have: $msg = ereg_replace("[^A-z0-9]"," ",$msg); $msg = ereg_replace(" "," ",$msg); $msg = ereg_replace(" "," ",$msg); how will i apply preg_replace please??? thank you After days of searching I found this thread http://www.phpfreaks.com/forums/index.php?topic=236954.0 that helped me do what I was trying to do. I've gotten the code to create and rename my html document but I can't figure out how to use the preg_replace part. This is my template with the 3 variables I want to replace with values from a form. Code: [Select] <html> <head> <link rel="stylesheet" type="text/css" href="style.css" /> </head> <body> <?php include_once('content.php') ?> </body> <SCRIPT language="JavaScript" SRC="javascript.js"></SCRIPT> <script type="text/javascript"> function nametitle(){ parent.iframe1.document.getElementById("div1").innerHTML = "VARIABLE1 <br>VARIABLE2"; parent.iframe1.document.getElementById("quotes").innerHTML = "VARIABLE3"; } </script> </html> I've spent hours reading and trying to understand how to make it work but it's a little over my head. Could someone help me with this? Thanks, im not sure how to do this: my code used the deprecated ereg_replace like this: $name = ereg_replace(" ", "", $name); i replaced it with this: $name = preg_replace(" ", "", $name); //this is line 65 but know get a warning: Warning: preg_replace(): Empty regular expression on line 65 what am i doing wrong please? thank you This topic has been moved to PHP Regex. http://www.phpfreaks.com/forums/index.php?topic=350441.0 Hi there! I'm trying to use preg_replace to include/get content a php file with dynamic variable $txt = "Bla bla bla bla bla [gls]12[/gls] bla bla bla"; $txt = preg_replace("#\[gls\](.*?)\[/gls\]#si",file_get_contents('shipping.php?id=\\1'),$txt); ..and it doesn't work. I can not get ID. When I do like that $txt = preg_replace("#\[gls\](.*?)\[/gls\]#si","My Id is - \\1"),$txt); i see it, but not when I'm using file_get_contents function. Thanks in advance for help. Quote Hi Guys, I have a small issue with doing a preg_replace on a string. Here is the string I wish to use preg_replace on Code: [Select] <?php $mystring = "This is my test string that has {['site_info']} and some more stuff {['taste']} then nothing" ?> Quote I want to do a preg_replace and replace {['site_info']} with $stuff['major']['site_info'] through the string Quote I want to replace the placeholder with real variables from the array Any help would be great I'm working with the youtube API and the function Code: [Select] $relatedVideo->watchURL returns a video url However when I use Code: [Select] preg_replace("youtube","test",$relatedVideo->watchURL); it gives me the following error Code: [Select] preg_replace() [<a href='function.preg-replace'>function.preg-replace</a>]: Delimiter must not be alphanumeric or backslash in <b>C:\wamp\www\site\test.php</b> on line <b>317 Help please? What I'm trying to do is replace message_tags to links and web addresses to links in facebook json data, the problem is I need to do these in 2 steps, first do the message tags then then web addresses. The message_tags need to be done first because they rely on offset and length of the message to do the replace.
To code to first replace the message_tags is
// convert message tags to links
if($post->message_tags) {
usort($post->message_tags, 'mySort');
foreach($post->message_tags as $message_tag) {
foreach($message_tag as $link) {
$post_text = substr_replace($post_text,"<a href=\"https://www.facebook.com/".$link->id."\" target=\"_blank\">".$link->name."</a>",$link->offset,$link->length);
}
}
}
The second part is to convert any web address (http://example.com) to a link (<a href ="http://example.com" title="http://example.com" target="_blank">http://example.com</a>)
// check if any entites exist and if so, replace them with hyperlinked versions
$post_text = preg_replace("/((http:\/\/|https:\/\/)[^ )]+)/e", "'<a href=\"$1\" title=\"$1\" target=\"_blank\">'. ((strlen('$1')>=250 ? substr('$1',0,250).'...':'$1')).'</a>'", $post_text);
So now to the problem, the second part now rewrites the first part and completely destroys the link because it just looks for http: and https: so in my preg_replace I need a way to not include anything that has already been converted, so not include anything that already has href="http
Hello. Im working on a function: Code: [Select] function image_vote_img_replace($content) { preg_match_all('/<img[^>]+>/i',$content, $result, PREG_PATTERN_ORDER); foreach ($result[0] as $img_oryg) { $result = '<div class="test">'.$img_oryg.'</div>'; $content = preg_replace( $img_oryg, $result , $content ); } return $content; } It gets as input content from CMS. It supposed to add overlaping div to each <img src="xxxx" /> so it looks like: <div class="test"><img src="xxxx" /></div>. But instead i get: <<div class="test"><img src="xxxx" /></div>> with additional < and > at beginning and end. I thin ,that it might be first regexp problem, but in second hand - entire img is extracted properly... Thanks in advice. Martin. Code: [Select] $str = preg_replace('/('.$word.')/i', '<em>\1</em>', $str); how come this doesn't work when $word = 'http://www.google.com', or any other URL? i'm having trouble in combining the 2 preg_replace into 1. basically i have a string witch strange chars, first i remove all except alphanumeric chars and the remaining string has 1 or 2 spaces and i replace them with dash. Code: [Select] strtolower(preg_replace('/\s+/', '-', preg_replace("/[^0-9a-zA-Z]/i", ' ',$a['item']))); Okay, i know there are lots of these questions out there and tons of ways to do this. I do have it working to replace URLs with <a href="URLs">URLs</a> but now i need some help detecting <a href=""></a> so the preg_replace will not double up the code and mess up the link. here is my code so far. Code: [Select] <?php echo 'COMMENTS<br /><br />'; while($rows = mysql_fetch_array($comres)){ list($comid, $menu_title, $post_id, $comdate, $comname, $comment) = $rows; $comment = nl2br($comment); $comment = preg_replace('/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/', '<a href="$0" target="_new">$0</a>', $comment); $comment = str_replace("´", "'", $comment); $comdate = date("g:ia - M j, Y",strtotime("$comdate")); echo 'User: '.$comname.'<font color="#B20303"> - '.$comdate.'</font><br />'; echo ' - '.$comment.'<br /><br />'; } ?> so with this code, if someone commented a link like this http://example.com it will turn it this <a href="http://example.com" target="_new">http://example.com</a> but now if someone knew some basic HTML coding, and they used this <a href="http://example.com">Example.com</a> it will look like this... <a href=<a href="http://example.com" target="_new">http://example.com</a>>Example.com</a> |
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