PHP - Return Value With Function

Hello everyone,

Pretty much what I am trying to do is run a query and based of the queries result, return a string - as of now it is turning up blank and cant seem to pass any strings through the function.

Current function:

function addNewBookmark($hash,$url,$title,$username){
     
      Code: [Select]
$query = "INSERT INTO bookmarks (hash,url,title,username) VALUES '".md5($hash)."', '".$url."', '".$title."', '".$username."')";
      $result = mysql_query(query, $this->connection);
      $message = '';
      if(mysql_affected_rows($this->connection)!=1) {

        $message = 'This URL already exists in the database!';
                return $message;
        }
        else
        $message = 'The URL was shared!';
        return $message;
       
           }
The above code seems to run fine, just cant seem to pass a string...read that you can possibly use a __toString function?  but that keeps throwing errors when I try to work with it.

Thanks all!

not sure if this is possible but i do not know how to return multiple values and read them where the call was made.

Code: [Select]
$string = "clause1";
func1($string);
// somehow read the response and use the return values seperately.
// both $string2 and $string3

Code: [Select]
function func1($input) {
if ($input == "clause1") { $string2= "value2"; $string3= "value6"; }
if ($input == "clause2") { $string2= "value3"; $string3= "value7"; }
if ($input == "clause3") { $string2= "value4"; $string3= "value8"; }
if ($input == "clause4") { $string2= "value5"; $string3= "value9"; }
return  ($requesttype, $messagetitle);
}

My tree gather function gives me multidimensional array. However i want it to be one dimensional . I was getting one dimensional earlier however i forgot how i got it. Can someone please tell me my mistake

Code
Code: [Select]
<?php
include'config.php';
 function tree_gather($node)   
  {
     
 $sql = "SELECT lchild,rchild FROM tree WHERE parent = '$node'";
    $execsql = mysql_query($sql);
    $array = mysql_fetch_array($execsql);
    
    if(!empty($array['lchild']) || !empty($array['rchild']))
    {
   
      $child[] = $array['lchild'];
      $child[] = $array['rchild'];
      $eh[] = tree_gather($array['lchild']);
      $child = array_merge($child, $eh);
      $eh1[] = tree_gather($array['rchild']);  
      $child =   array_merge($child, $eh1);
     
    } 
     return $child;
  }
$pair = tree_gather(1000000);
echo "<pre>";
print_r($pair);
echo "</pre>";  
?> 
Output
Code: [Select]
Array
(
    [0] => 3632873
    [1] => 5951538
    [2] => Array
        (
            [0] => 8930480
            [1] => 7563232
            [2] => Array
                (
                    [0] => 1144744
                    [1] => 4386810
                    [2] =>
                    [3] =>
                )

            [3] =>
        )

    [3] =>
)

This is my error:
Code: [Select]
Fatal error: Can't use function return value in write context in /home/a8152576/public_html/SecretSanta.html on line 41
confused about why.
This is the line 41:
if(isset($_POST('submit')){

this is the php of my page (without the mysql data):

<?php
class functions{
public static function chooseGiftee($SS){
     $done = false;
        while($done=false){
     $sqllink= mysql_connect($mysql_host,$mysql_user,$mysql_password);
     if(!$sqllink){
     echo "Could not connect! Please Try Again";
         mysql_close($sqllink);
     } else {
     $selectGiftee = "SELECT * FROM SecretSantas ORDER BY RAND() LIMIT 0,10;";
             while($row=mysql_fetch_array($result)){
                 $results = mysql_query($selectGiftee);
              if(!$row['Gifter']=''){
                  $done=false;
                 } else {
              $gifteeResults = $row['Name'];
                        $addSS = "INSERT INTO SecretSantas (Gifter) VALUES ('" .$SS. "')";
                        $done=true;
              return $gifteeResults;
                 }
             }
     }
            mysql_close($sqllink);
        }
    }
}

if(isset($_POST('submit')){
$echoName = functions::chooseGiftee($_POST['gifterName']);
echo $echoName;
}
?>

This is html:

<form id="form1" name="form1" method="post" action="">
  <p>
    <label>Your Name:
      <input type="text" name="gifterName" id="gifterName" />
    </label>
    <input type="submit" name="submit" id="submit" value="Submit" />
  </p>
  <p>&nbsp;</p>
</form>


Confused about the issue, first time using functions.
Thanks in advance,
Brandon

Hi,
I have some strange issues with my code:

Code: [Select]
<?PHP
session_start();
$loginid = $_SESSION["valid_id"];
// First check if we are guest or user.
if (!$_SESSION["valid_email"])
{
$visitor = "yes";
}
else
{
$visitor = "no";
$email = $_SESSION['valid_email'];
$userid = $_SESSION['valid_id'];
}
//Load Header (blue menu)
require("./inc/header.php");
//Load Sub-acc (silver account menu)
require("./inc/sub-group.php");
//Load nav-group (Tabs)
require("./inc/nav-group.php");
//Load Config file
require("./inc/config.php");
//Set & get profile ID
$getid = $_GET["id"];
//check ID
$result = mysql_query("SELECT * FROM profiles WHERE id=('$getid')  LIMIT 1");
$row = mysql_fetch_array($result);

IF (mysql_num_rows($result) != 1)
{
 exit("Invalid ID");
}

//If we are guest, do we allow anon access to the profile
IF ($row["privacy"] <= 10 && $visitor = "yes")
{
exit("You may not view this profile as a visitor, due to the users privacy settings");
}
//Let's check if we are friends
ELSEIF ($visitor = "no")
{
$result2 = mysql_query("SELECT * FROM profiles_friends WHERE user=('$getid') AND target=('$loginid')  LIMIT 1");
$row2 = mysql_fetch_array($result2);
$friends = $row2["status"];
if (mysql_num_rows($result2) = 0)
{
$friends = "no";
}
}

//If we are friend, do we allow access to the profile
IF ($row["privacy"] >= 9 && $friends != 1)
{
exit("You may not view this profile because of the privacy settings.");
}

$row = mysql_fetch_array($result);
$memgroup = $row["group"];
IF ($row["activated"] != 1)
{
 exit("This account is suspended and cannot be viewed.");
}


//Check what group member is in.
$result2 = mysql_query("SELECT * FROM profiles_groups WHERE id=('$memgroup')  LIMIT 1");
$row2 = mysql_fetch_array($result);

?>

Alright, so the error: Fatal error: Can't use function return value in write context in C:\xampp\htdocs\prog\profile.php on line 45
Code: [Select]
42. $result2 = mysql_query("SELECT * FROM profiles_friends WHERE user=('$getid') AND target=('$loginid')  LIMIT 1");
43. $row2 = mysql_fetch_array($result2);
44. $friends = $row2["status"];
45. if (mysql_num_rows($result2) = 0)
Alright, this is one thing that bothers me, the other is:
Code: [Select]
//check ID
$result = mysql_query("SELECT * FROM profiles WHERE id=('$getid')  LIMIT 1");
$row = mysql_fetch_array($result);

IF (mysql_num_rows($result) != 1)
{
 exit("Invalid ID");
I tried to put an invalid ID, and already here the script should have died/exited before executing the parts of the code that doesn't work.
I tested my code on another page and it works flawlessly, perhaps this error is just generated before it actually exists i dunno..

Any way, any help is much appreciated
}

I hate array...   😞

So I had a block of code inside my photo-gallery.php script that took the path to my photos directory, and went to that directory, and then read all of the photo filenames into an array.  Then in my HTML, I iterate through this array to display all of the photos for my gallery.

Now I would like to move that code to an included file so multiple scripts can access it and always be working with the same array.

It seems to me that I need to encapsulate my code inside a function?

Then I could call my getPhotoFilesArray back to my callings cript, and use that array for whatever.

I haven't coded PHP in like 4 years and I am struggling to return the entire array back to my caling script.

This is what I have so far...

	function getPhotoFilesArray($photoPath){
	     $photoFiles = array();
	     <code to find corresponding files>
	     $photoFiles gets populated in a loop
	     return $photoFiles;
	}
	

 

Then in my calling script, I have...

	<?php
	     require_once('../../../secure_outside_webroot/config.php');
	     require_once(WEB_ROOT . 'utilities/functions.php');
	     getPhotoFilesArray($photoPath);
	     var_dump($photoFiles);
	

 

I get some error...

	Notice: Undefined variable: phtoFiles in photo-gallery.php line 133 (which is my var_dump).
	

 

<br>

Would appreciate help getting this to work!

 

 

Edited December 6, 2019 by SaranacLake

HI guys

I have vreated a site and am now trying to validate the ip address i have created a function but am failing to get it to work i need to add the errors to add to the errors array but instead it keeps resetting and leaving me with the last error that is returned any help would be greatly appreciated im a newbie so if i can understand the concept behind whats happening it will be of great benefit
Thanks Sean

heres the code

// Function validateIpaddress($address,$record,$errors)
// {
//    if ($address !=="" or $address !=="ip_address")
//    {
//       Print_r($address);
//       echo "<br><br>";
//       $fullstoppos = strpos(($address), ".");
//       echo "strpos = $fullstoppos";
//       $fullstoppos2 = strpos(($address), ".", $fullstoppos+1);
//       echo "strpos2 = $fullstoppos2";
//       $fullstoppos3 = strpos(($address), ".", $fullstoppos2+1);
//       echo "strpos3 = $fullstoppos3";
//    }
//    if ($fullstoppos !==4 && $fullstoppos2 !==9 && $fullstoppos3 !==14)
//    {
//       $errors[] = "<br><font color='red'>Please correct the following.Or contact your client manager for assitance.<br>* $record is a required field.An ip address is a 16 digit numerical value.  </font>";
//    }
// }

$errors = validateIpaddres($_POST['destinationPoint'],A/AAAA record, $errors)

I'm trying to return to array of letters that bruteForce finally decides upon. However, I can't seem to pass the array to librarySolve.

I'm feeling dumb, any help?

Code: [Select]
function librarySolve($string){
$temp = $this->bruteForce($string, FALSE, 0);
return $temp;
}

function bruteForce($string, $state, $trys){
$base = $string;
$state = $state;
$new_letters = array();

if($trys <= 6000){
$this->new_letters = $this->generateRandomCipher();
$string = preg_replace('/[^a-zA-Z0-9-\s]/', '', $string);

for($a=0;$a<=strlen($string);$a++){
$letter = substr($string, $a, 1);
$pattern = "/[A-Z]/";

if(preg_match($pattern, $letter)!=0){
$new_letter = $this->new_letters[$letter];
} else if(preg_match($pattern, $letter)==0) {
$new_letter = $letter;
}
$decipher .= $new_letter;
}

$word_array = explode(" ", $decipher);

$count = 0;
for($a=0;$a<count($word_array);$a++){
$do = $this->checkWord($word_array[$a]);
if(!empty($do)){
$count++;
}
}

if($count>=2){ $state = TRUE; } else { $state = FALSE; }

if($state==TRUE){
return $this->new_letters;
} else {
$trys++;
$this->bruteForce($base, $state, $trys);
}
}
}

hi guys
i am including a function in my main script, and i'm calling it aftwerwards. except i cannot echo successfully the data in the $result variable, why?


function echoResult(){
  $result = 'dan';
  return $result;
}
// 1
echo echoResult(); // don't work. i get empty data.
// 2
$fnResult = echoResult();
echo $fnResult; // don't work. get empty data.


i have ran get_included_files and the include is being made successfully.
i read on php.net and these are the examples they use (user comments!)
how do i get the data out of the function and echo it, using this way?

I created a function called converter.  My code doesn't look like it processes anything after the first if . This is what is displayed in browser.

Convert a String

original string: roses Are red, violets are blue....
converted string: roses are red, violets are blue....
converted string: roses are red, violets are blue....
converted string: roses are red, violets are blue....



<html>
<head>
<title>Create a PHP Function to Convert a String</title>
</head>
<body bgcolor="pink">
<h2>Convert a String</h2>



<?php
   $phrase = "roses Are red, violets are blue....";
   function converter($arg1, $arg2){
   
   if($arg1="lower"){
   return strtolower($arg2);
}
   elseif ($arg1="upper"){
   return strtoupper($arg2);
}
   else
   /* if($arg1="title")*/{
   return ucwords($arg2);
}
}

print "original string: ".$phrase."<br />";

print "converted string: ".converter("upper",$phrase)."<br />";

print "converted string: ".converter("lower",$phrase)."<br />";

print "converted string: ".converter("title",$phrase)."<br />";

?>
</body>
</html>

return  (int) $value   VS return $value   What is the purpose of using int in a bracket?    return  (int) $value     Which is the best and safest method? Thank you

If a user is on Page X, but not logged in, when they log in to my website, I want them to return back to Page X (in this example).

To handle this, I am adding this code to the top of each webpage...
Code: [Select]
// Set current Script Name.
$_SESSION['returnToPage'] = $_SERVER['SCRIPT_NAME'];

And then as part of my Log In script I have...
Code: [Select]
// Redirect User.
if (isset($_SESSION['returnToPage'])){
header("Location: " . BASE_URL . $_SESSION['returnToPage']);
}else{
// Take user to Home Page.
header("Location: " . BASE_URL . "index.php");
}

What do you think about this approach?   

Thanks,


Debbie

Hey all. My site has a config database table that has a column showlogin to set whether or not login functionality is enabled.

I'm playing around with MySQLi, Classes, and Returns.  My return is always 1. Where am I going wrong?

test.php
<?php
// Start Session
session_start();

// Production Settings
ini_set('display_errors', 1);
mysqli_report(MYSQLI_REPORT_ALL);

include 'db.php';
$mysqli = new mysqli($host, $user, $pass, $db);

class styles
{
function showlogin($show)
{
global $mysqli;
$select = $mysqli->query("SELECT showlogin FROM config LIMIT 1");
$value = $select->fetch_object();

if ($value->showlogin = 1) { 
return 1;
}
return 0;
}
}
$login = new styles();
echo $login->showlogin($show);
?>

Hi Everyone,   My name is Raoul Grosser, live in The Netherlands. I'm a front/backend developer working with AngularJS and Bootstrap and Symphone2. I've been writing PHP code for over 4 years now my focus is on opensource projects.   If you have any question, please let me know! 

Hello
First of all i am very weak about OOP and classes in php. I am learning now but i stuck with very silly problem.
My codes are below.
<?php
   class myTestClass
   {
       function __construct()
       {
         $this->OldName("This is Old Name");
       }
       
       function OldName($VeryOld)
       {
           if($VeryOld == "This is Old Name")
               $this->NewName();
            else
               $VeryOld = "Something Wrong";
            return $VeryOld;
       }
       
       function NewName()
       {
           echo "This is Brand New Name";
       }
   }
   
   $i = new myTestClass();
?>

if i send value to  OldName "This is Old Name" then codes works fine.
But if i send "This is Old Nameeee" then does not appear anything.

what i want to do is print "Something Wrong" text if i enter different value. I have no idea what return do and how it do? How to retrieve/print "Something Wrong"?
i can do that with echo but i want to transfer result of return to another function.

Really appreciate for any help/idea.