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PHP - Passing A Variable In The Redirect Statement
I want to display some specific data from my database (just data from a given date).
I first created a page where the user picks the date. After the date is defined it is passed to the next page where the data from that date is displayed. That page includes a form where users can edit the data. The form data is then passed to a third page for processing. All of this works fine. Now I want the user to be taken back to the previous page with the assigned date. On the processing page I am using this statement: Code: [Select] header("Location: /teetimes/adminteetimes.php?teetimedate=$dateID");and on the display page I'm using Code: [Select] $dateID = $_REQUEST[teetimedate];The display page is using a SELECT...WHERE Date='$dateID' statement and $dateID is defined in the processing page. Problem is: I'm redirected from the processing page back to the display page but the date isn't passed, so the correct data isn't being displayed. Can anyone help me pass a variable using a header?? Or show me where my logic is lacking?? Thanks! Similar Tutorials
User Authentication Help By Using If Elseif And Else Statement And Redirect Page On 3 Differnet Urls
Hello all, I'm an absolute Newbie to PHP. I'm struggling with a problem that I think is extremely basic to you experts but I just can't get it to work. In short, I have an application that has a link that goes to: Site1/dir/admin?id=(text)&page=(number) I want to redirect to a link that's identical except it's Site2 at the beginning instead of Site 1. What I've attempted so far is this: <?php $GLOBALS[$passid]=$_GET['id']; $GLOBALS[$passpage]=$_GET['page']; header( 'Location: http://site2.com/dir/admin/?page=$passpage&id=$passid'); ?> But it just redirects to http://site2.com/dir/admin/?page=$passpage&id=$passid (with all of that text being literally what is in the URL, not the variable values) I have a feeling I'm doing something small but very basic wrong. The $GLOBALS thing was an afterthought. Outcome is the same with or without that. Any help much appreciated!!! Hi guys I have 2 question. 1. Is it possible to use the a variable in a header redirect function i.e. Code: [Select] $test = 'index.php'; header("location: $test"); 2 assuming $test = 'index.php'; how do I pass the variable from one page to another? Thanks Hey here is my code im trying to redirect the index.php to index.php?id=1 the way i have done it doesn't look really good is there a better way to do it please? im trying to redirect to id=1 because otherwise i wont be able to echo out anything... id 1 is default category so is there a way to tell it if $id is empty echo from id 1? <?php $id = $_GET['id']; if($id == ''){ echo "<meta http-equiv=Refresh content=0;url=index.php?id=1>"; } $result = mysql_query("SELECT * FROM pages WHERE id='$id' ",$connect); while($row = mysql_fetch_assoc($result)) { echo $row['anything1']; echo $row['anything2']; } ?> Hi, Why doesn't this work? Driving me nuts! Thanks. <?php if($_SERVER[PHP_SELF] == 'somepage.php') { Header("Location: http://www.thissite.com"); } else { Header("Location: http://www.anothersite.com"); } ?> The code NEVER redirects to the first URL (thissite.com). It ALWAYS redirects to the second URL (anothersite.com). What the heck am I doing wrong? Below code is working fine but i need to redirect on 3 different pages and its giving me error. My table structure is as
User table
Email Password
admin@yahoo.com 123
tariq@yahoo.com 987
bilal@yahoo.com 456
if user name is like; admin@yahoo.com the page should redirect on welcome.php
if user name is like; info@aiousoft.com the page should redirect to welcome2.php
and if user doesnot exist in database then give error as ELSE "user doesnot exist"
thanks
signin.php
<html><head><title>Sign In</title></head><body> <?php include 'header.php'; ?> <?php include 'menu.php'; ?> <center> <form method="post" action="checklogin.php"> <h3>Please Signin</h3> <table width="400" border="0"> <tr><td>Email</td> <td><input name="email" type="text" id="email"></td></tr> <tr><td>Password</td> <td><input name="password" type="password" id="password"></td></tr> </table> <p><label> <input type="submit" email="submit" value="Submit"> </label><input email="reset" type="reset"> </p> </form> </center> </body> </html> checklogin.php <html><head><title>Check Login</title></head><body> <?php include 'header.php'; include 'menu.php'; $email=$_POST['email']; $password=$_POST['password']; @ $db = mysql_pconnect('localhost', 'root', ''); if (!$db) { echo 'Error: Could not connect to database. Please try again later.'; exit;} mysql_select_db('car'); $q=mysql_query("select * from user where email='".$email."' and password='".$password."' ") or die(mysql_error()); $res=mysql_fetch_row($q); if($res) { header('location:welcome.php'); } else { echo' Please signin again as your user name and password is not valid'; } ?> </body> </html> Attached Files header.php 284bytes 0 downloads menu.php 308bytes 0 downloads This is driving me MAD! The Variable gets passed through the URL but when I try and echo the result I gte NOTHING. First Page. Code: [Select] <?php include'config.php'; $result = mysql_query("SELECT * FROM carbontrust"); while($entry = mysql_fetch_array($result)) Print "$entry[contact] - $entry[company] :: <a href='edit.php?id=$entry[id]'>Edit</a><br>"; exit; ?> Second Page. (Where I want the Variable passed to) Code: [Select] <?php include'config.php'; $id = $_GET['id']; echo "ID: $id"; } ?> Its probably just a stupid error but iv looked through a load of tutorials and this should be correct. :/ Hi, can anybody please tell me how i can make "Arson" into a php variable Code: [Select] <script type="text/javascript" src="js/swfobject.js"></script> <script type="text/javascript"> swfobject.embedSWF( "open-flash-chart.swf", "my_chart", "550", "400", "9.0.0", "expressInstall.swf", {"data-file":"ofc-chart.php?crime=Arson"} ); </script> hello all, I'm new here and I'm learning mysql/php. Currently I have a dynamic table on one of my webpages, and the loop code looks like this:while ($i < $numRows) { $fname = mysql_result($result, $i, "fname"); $fcode = mysql_result($result, $i, "fcode"); $ftype = mysql_result($result, $i, "ftype"); $fdesc = mysql_result($result, $i, "fdesc"); ?> <tr> <td><a href="showfunction.php?fname=<?php echo "$fname"; ?>" target="_self"> <?php echo "$fname"; ?></a></td> <td> <?php echo "$fdesc"; ?> </td> <td><div align="center"> <?php echo "$ftype"; ?> </div></td> </tr> <?php $i++; } ?> what I would like to do is pass the ''fname'' variable to the "showfunction" page so it can printed from the database. Here is the relevant portion of the page:<body><div class="codeblock"> <div class="title">Code:<br /> </div><code><pre> <?php echo $fcode; ?> </pre></code></div> <br /><pre><hr /> </pre> I know that doesn't work, and I didn't expect it to because there is no way to 'get' the 'fname' variable from the preceeding script. I do not want to use the GET method with this because from what I understand, you can only use it with Forms. I really don't want to put controls in all of my table fields just to be able to pass the function name to the next page. Does that make sense? If I could get a jumpstart on this one last hurdle, I would appreciate it. thank you so much! Cheers. Trying to set up an error message when someone tries to upload a file without the approved .ext. I have it working so it won't up load but I am trying to get an error to print out. I was thinking that I could do something like this if the ext are wrong set $errorMsg1 == 1; and then the page will refresh and I would pass that variable to echo out if ($errorMsg1 == 1){ echo "Invalid"; } else { but it isn't passing can anyone help me with this? Tyring to keep it simple this is the code to select an image else{ $result = mysql_query("SELECT * FROM photos WHERE userID LIKE '$clientID'"); while ($r=mysql_fetch_array($result)) { $photo_1=$r['photo_1']; $photo_2=$r['photo_2']; $photo_3=$r['photo_3']; $photo_4=$r['photo_4']; $photo_5=$r['photo_5']; echo " <form enctype='multipart/form-data' action='' method='POST'> <input type='hidden' name='MAX_FILE_SIZE' value='500000' /> <div id='imageTop'>Image &#35;1</div> "; if ($errorMsg1 == 1){ echo "Invalid"; } echo " <div id='imageBottom'> <span class='image'>"; if (empty($photo_1)) { echo " <img src='uploads/noPhoto.gif' width='75' height='75' class='zip'> "; } else { echo "<a href='uploads/$photo_1' ><img src='uploads/$photo_1' width='75' height='75' class='zip'></a> "; } echo " </span> <span class='action'> <input type='file' name='photo_1' class='zip'><br><br> <input type='checkbox' name='delete_1'>Select to Delete image </span> </div> } this is the code of what to do with that image if (isset($_POST['delete_1'])) { $query = "UPDATE photos SET photo_1='' WHERE userID='$clientID'"; $result = mysql_query($query) or die(mysql_error()); echo " <div id='aboutUpdate'><img src='img/loader.gif'> Information is updating</div> "; echo "<meta http-equiv=refresh content=\"0; URL=photos.php\">"; } else if ($one != NULL) { $extension = strrchr($_FILES['photo_1']['name'],'.'); $extension = strtolower($extension); if($extension != '.jpg' && $extension != '.gif' && $extension != '.png' && $extension != '.bmp' ){ $errorMsg1 == 1; echo "<meta http-equiv=refresh content=\"0; URL=photos.php\">"; } else { $photoNumber="_1"; $finalName="$clientID$photoNumber"; $save_path = "uploads/"; $target_path = $save_path . basename( $_FILES['photo_1']['name']); $NewPhotoName = $finalName; $withExt = $NewPhotoName . $extension; $filename = $save_path . $NewPhotoName . $extension; if(move_uploaded_file($_FILES['photo_1']['tmp_name'], $filename)) { $query = "UPDATE photos SET photo_1='$withExt' WHERE userID='$clientID'"; $result = mysql_query($query) or die(mysql_error()); echo " <div id='aboutUpdate'><img src='img/loader.gif'> Information is updating</div> "; echo "<meta http-equiv=refresh content=\"0; URL=photos.php\">"; } } else { I'm an hour worth of searches into this. It's 2:30. I just want some nice person to give me the answer. I'm trying to pass a variable using href to another page. It works great if the variable is only one word. But it only passes the first word. There are multiple posts on this topic, but I can't seem to get any of those fixes to work for me. Here the code. Code: [Select] <?php $query = "select DISTINCT city from daily where open_bid>0 order by city ASC"; $result = mysql_query($query); while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $details=''; $details.='<li class="menu"><span class="name"><a href=list.php?city='.$row['city'].'>'.$row['city'].'</a>'; $details.='</li>'; echo($details); } ?> As you can imagine, some cities names are made up of two words. This is only passing the first word. Thanks for your help. The below script for some reason isn't passing along the product_id variable. Code: [Select] $product_id=$_GET['product']; session_start(); $error=$_SESSION['error']; $content.='<div class="product_information_text review_form"> <div class="review_header">Write a Review for '.$product_name.'</div> <form action="./review_process.php?product='.$product_id.'"> <p class="form_item"><label>Name:</label> <input type="text" name="review_name" size="30" /></p>'; if(isset($error[0])){$content.='<p class="red">This field is required.</p>';} $content.=' <p class="form_item"><label>E-Mail:</label> <input type="text" name="review_email" size="30" /></p> <p class="form_item"><label>Location:</label> <input type="text" name="review_location" size="30" /></p> <p class="form_item"><label>Describe Yourself:</label> <input type="text" name="review_describe" size="30" /></p> <p class="form_item"><label>Review Title:</label> <input type="text" name="review_title" size="30" /></p> <p class="form_item"><label>Best Use of Product:</label> <input type="text" name="review_best_use" size="30" /></p> <p class="form_item"><label>Product Pros:</label> <input type="text" name="review_pros" size="30" /></p> <p class="form_item"><label>Product Cons:</label> <input type="text" name="review_cons" size="30" /></p> <p class="form_item"><label>Product Rating:</label><br /> <div class="rating_radio"><input type="radio" name="review_product_rating" value="1" /> <br />1</div> <div class="rating_radio"><input type="radio" name="review_product_rating" value="2" /> <br />2</div> <div class="rating_radio"><input type="radio" name="review_product_rating" value="3" checked /> <br />3</div> <div class="rating_radio"><input type="radio" name="review_product_rating" value="4" /> <br />4</div> <div class="rating_radio"><input type="radio" name="review_product_rating" value="5" /> <br />5</div> <div class="worst">(Worst)</div><div class="best">(Best)</div> </p> <p> </p> <p class="form_item"><label>Comments on Product:</label><br /> <textarea name="review_text" rows="10" cols="60"></textarea> </p> <p><input type="submit" value="Submit" name="Submit" /></p> </form> </div> '; session_unset(); session_destroy(); That code shows the proper product=$product_id value in the form action tag. Code: [Select] $product_id=$_GET['product_id']; $review_name=$_POST['review_name']; $review_name = stripslashes($review_name); $review_name = mysql_real_escape_string($review_name); if($review_name==""){ $error0=1; } else{ $error0=0; } $review_title=$_POST['review_title']; $review_title = stripslashes($review_title); $review_title = mysql_real_escape_string($review_title); if($review_title==""){ $error1=1; } else{ $error1=0; } $review_email=$_POST['review_email']; $review_email = stripslashes($review_email); $review_email = mysql_real_escape_string($review_email); if($review_email==""){ $error2=1; } else{ $error2=0; } $review_location=$_POST['review_location']; $review_location = stripslashes($review_location); $review_location = mysql_real_escape_string($review_location); if($review_location==""){ $error3=1; } else{ $error3=0; } $review_describe=$_POST['review_describe']; $review_describe = stripslashes($review_describe); $review_describe = mysql_real_escape_string($review_describe); if($review_describe==""){ $error4=1; } else{ $error4=0; } $review_best_use=$_POST['review_best_use']; $review_best_use = stripslashes($review_best_use); $review_best_use = mysql_real_escape_string($review_best_use); if($review_best_use==""){ $error5=1; } else{ $error5=0; } $review_pros=$_POST['review_pros']; $review_pros = stripslashes($review_pros); $review_pros = mysql_real_escape_string($review_pros); if($review_pros==""){ $error6=1; } else{ $error6=0; } $review_cons=$_POST['review_cons']; $review_cons = stripslashes($review_cons); $review_cons = mysql_real_escape_string($review_cons); if($review_cons==""){ $error7=1; } else{ $error7=0; } $review_product_rating=$_POST['review_product_rating']; $review_product_rating = stripslashes($review_product_rating); $review_product_rating = mysql_real_escape_string($review_product_rating); $review_text=$_POST['review_text']; $review_text = stripslashes($review_text); $review_text = mysql_real_escape_string($review_text); if($review_text==""){ $error8=1; } else{ $error8=0; } $review_show="n"; date_default_timezone_set('US/Eastern'); $review_date = date("F j, Y, g:i a T"); $error="".$error0."".$error1."".$error2."".$error3."".$error4."".$error5."".$error6."".$error7."".$error8.""; if($error!=="000000000"){ session_start(); $_SESSION['error']=$error; header("Location: ./store.php?product=".$product_id."#review"); } else{ $sql="INSERT INTO $tbl_name3 (product_id, review_show, review_title, review_email, review_name, review_location, review_date, review_describe, review_best_use, review_pros, review_cons, review_product_rating, review_text) VALUES ('$product_id', '$review_show', '$review_title', '$review_email', '$review_name', '$review_location', '$review_date', '$review_describe', '$review_best_use', '$review_pros', '$review_cons', '$review_product_rating', '$review_text')"; mysql_query($sql); echo "Thank You for submitting your review. It should appear on the site within 48 hours."; } The above redirects to store.php?product=#review with no product id. Ideas on why? Hi, I am trying to pass a variable when posting a form. This is my form with the select: Code: [Select] <form id="form1" name="form1" method="post" action="products_2.php?id_subcategoria= WHAT SOULD I PUT HERE?"> <select name="subcats" class="subcatsSelectMenu" id="subcats" onchange="this.form.submit()"> <option value="">Ver placas por tipos</option> <?php do { ?> <option value="<?php echo $row_subcats_RS['id_subcategoria']?>"><?php echo $row_subcats_RS['subcategoria_esp']?></option> <?php } while ($row_subcats_RS = mysql_fetch_assoc($subcats_RS));$rows = mysql_num_rows($subcats_RS); if($rows > 0) { mysql_data_seek($subcats_RS, 0); $row_subcats_RS = mysql_fetch_assoc($subcats_RS); } ?> </select> </form>How can I pass the variable in the URL? Thanks How, if possible, can a $var be passed to the forms action php file? I tried everything with no success. Edited December 24, 2019 by cyberRobotRemoved email address I had an iframe working for the last few months on a site at hostgator. Yesterday, it quit working (403 permissions error). After a long bout of trouble-shooting, I found out that it has something to do with mod_security that they have suddenly enabled (have no idea as I'm not a Linux guy). They told me they fixed the problem on my domain by whitelisting it as an exception, but strangely, even though the permissions error went away, the actual src= box of the iframe, which was the url variable I was passing in the url, no longer loads. So.. I'm trying to break this down into the simplest form to figure it out. I just understand php basics so needing some verification that I'm doing this right/wrong. Here's my code.. page1.php Code: [Select] <? $testurl = "http://google.com"; ?> <a href="http://mysite.blah/page2.php?url=<? echo $testurl; ?>">page2.php</a> page2.php Code: [Select] if (isset($_GET['testurl'])) echo $testurl; else echo "sorry dude"; I am only able to print "sorry dude". Am I doing something wrong or shouldn't this send the url? Thanks for the help! hi, i was wondering if i could automattically redirect a page to another page directly based on a PHP variable like so: <?php header("Location: http://www.mywebsite.com/<?php echo $_POST["username"]; ?>.php"); ?> OR <?php header("Location: http://www.mywebsite.com/profile.php+action=<?php echo $_POST["username"]; ?>; ?> this page already exists. This is already protected. Thanks in advance Hello, I'm trying to build a small project; and as part of it - I want users to search and when presented with relevant enteries in the SQL database - they should be able to click and retrieve a page dedicated to that entity. The problem I am having is in passing the 'id' of the search result onto the next (description) page. Code: [Select] $SQL = "SELECT * FROM loads"; $result = mysql_query($SQL); while ($db_field = mysql_fetch_assoc($result)) { $clickid = $_GET['id']; print $db_field['id'] ."<a href=\"load_info.php?id=$id" . $id . "\" target=\"_self\" title=\"\">More Info</a>;"; print $db_field['depart:'] . "<BR>"; print $db_field['dest'] . "<BR>"; } I thought it was easy enough to pass the variable like above ("load_info.php?id=$id) and then grab it on the next page like so: $val = $_GET['clickid']; Unfortunately, it doesn't retrieve the info from the page before. If I insert a number in there, it does work correctly, but I really need the ID of the database entry to pass on so as to provide the user with further information. If anyone could help it would be appreciated. L. <head> <script language="javascript" type="text/javascript" src="datetimepicker.js"> </script> </head> <form action="main.php?id=test.php" method="post"> <p>Start Date: <input name="start" id="start" type="text" size="10"> <a href="javascript:NewCal('start','ddmmyyyy')"><img src="cal.gif" width="16" height="16" border="0" alt="Pick a date"></a> End Date: <input name="end" id="end" type="text" size="10"> <a href="javascript:NewCal('end','ddmmyyyy')"><img src="cal.gif" width="16" height="16" border="0" alt="Pick a date"></a> <input name="submit" type="submit" value="Look Up"> </form> <?php if(isset($_POST['submit'])) { $start = $_POST['start']; $end = $_POST['end']; $sql = "SELECT * FROM `corps` WHERE `notedate` BETWEEN '$start' AND '$end'"; $results = mysql_query($sql) OR DIE(mysql_error()); $numrow = mysql_num_rows($results) ; $i = 0; While ($i < $numrow) $shownotes = mysql_result($results,$i,'notes'); echo $shownotes."<br>"; { Echo "Records found ".$i."<br>"; $i++; } } The $start, and $end don't seem to be getting any values Please forgive my limited knowledge of php. I am trying to pass a variable from 1 page to the next. I have SCRIPT A (I didn't write it) that parses an rss feed and then calls SCRIPT B to insert it into a database. Everything works great.. and all I'm trying to do is add a new piece of information. In my db, I added a column called 'city'. There are currently 25 different SCRIPT A's (25 different city names). I could create 25 SCRIPT Bs and call them individually, but I'm trying to use 1 SCRIPT B and just send the city name. I've read about POST and GET but still not sure on this? Can't I just hard code my city name into each SCRIPT A like this: Code: [Select] $city = "miami"; And then put this at the top of SCRIPT B? Code: [Select] $city = $_GET['city']; Well.. apparently, I can't because that doesn't work. Again.. sorry for the dumb question. It's my first time attempting anything with php. Thanks. i have this code in a form, i need to pass a variable $time to next page, how can i do that ? if( $sErr ) print "<script language='javascript' type='text/javascript'>location.href='#error';</script>";;; else: print "<script language='javascript' type='text/javascript'>location.href='paypal.php';</script>";;; |
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