PHP - Why Are You Not Allowed To Use "default" As A Function Name?

Hi guys

I am a newbie with PHP and I have been trying to solve this problem for 3 days..

Ive set up a booking form on my website to be sent directly to my email once the client clicked on the send button..
The problem I am having while checking these pages on wamp is that the booking form is ok but when I click on the send button the following message error appears
"Warning: mail() [function.mail]: Failed to connect to mailserver at "localhost" port 25, verify your "SMTP" and "smtp_port" setting in php.ini or use ini_set() in C:\wamp\www\fluffy_paws\booking_form2.php on line 27"

When I check online I have this message "500 - Internal server error.
There is a problem with the resource you are looking for, and it cannot be displayed."

Are my codes wrong???

My webhosting is Blacknight.com , Im on Windows Vista, my internet is a dongle with O2 ireland

Thanks for your help!

Hi guys

I'm struggling a bit, I need to replace a word that occurs multiple times in text with an array("up","down","forward","backwards") of words.


$find = "left";
$replace = array("up","down","forward","backwards");
$text = "left left left left";

echo str_replace($find,$replace,$text);


The Output is: array array array array

Did try this with a foreach statement as well, but no luck. Is there a better way of doing this? 

Thanks

cant work out this mysql syntax error
"operation":"medupdate","medid":"","name":"ibo","medyear":"5","medmonth":"21","medday":"1","recuser":1,"SuccFail":"fail","SuccFailMessage":"error occured You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '''WHERE med_id=' at line 2","ResultData":""}

Code: [Select]
$sql="update metodology set med_description='".$req['name']."',
  med_year='".$req['medyear']."', med_month='".$req['medmonth']."', med_day='".$req['medday']."', med_recorddate= now(), med_recorduserid= 1'";
  $sql.= " WHERE med_id=".$req['medid'];

I am getting the following error when using composer: "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"?

Just started.  I am pretty sure composer.json wasn't changed.  journalctl doesn't show anything.  Maybe Doctrine related, however, nothing seems to help.

Any ideas?
 

[michael@devserver www]$ php -v
PHP 7.3.4 (cli) (built: Apr  2 2019 13:48:50) ( NTS )
Copyright (c) 1997-2018 The PHP Group
Zend Engine v3.3.4, Copyright (c) 1998-2018 Zend Technologies
    with DBG v9.1.9, (C) 2000,2018, by Dmitri Dmitrienko
[michael@devserver www]$ composer -V
Composer version 1.4.2 2017-05-17 08:17:52
[michael@devserver www]$ yum info composer
Loaded plugins: fastestmirror
Loading mirror speeds from cached hostfile
 * base: mirror.us.oneandone.net
 * epel: mirror.rnet.missouri.edu
 * extras: mirror.us.oneandone.net
 * remi-php73: mirror.bebout.net
 * remi-safe: mirror.bebout.net
 * updates: mirror.us.oneandone.net
Installed Packages
Name        : composer
Arch        : noarch
Version     : 1.8.4
Release     : 1.el7
Size        : 1.8 M
Repo        : installed
From repo   : epel
Summary     : Dependency Manager for PHP
URL         : https://getcomposer.org/
License     : MIT
Description : Composer helps you declare, manage and install dependencies of PHP projects,
            : ensuring you have the right stack everywhere.
            :
            : Documentation: https://getcomposer.org/doc/

[michael@devserver www]$ composer update
Loading composer repositories with package information
Updating dependencies (including require-dev)


  [ErrorException]
  "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"?


update [--prefer-source] [--prefer-dist] [--dry-run] [--dev] [--no-dev] [--lock] [--no-custom-installers] [--no-autoloader] [--no-scripts] [--no-progress] [--no-suggest] [--with-dependencies] [-v|vv|vvv|--verbose] [-o|--optimize-autoloader] [-a|--classmap-authoritative] [--apcu-autoloader] [--ignore-platform-reqs] [--prefer-stable] [--prefer-lowest] [-i|--interactive] [--root-reqs] [--] [<packages>]...

[michael@devserver www]$

 

This topic has been moved to Linux.

http://www.phpfreaks.com/forums/index.php?topic=318175.0

I have a registration form on my website and after Registration I want the user to activate first his account. I don't have problem on sending this email to the user. What I want to appear is like this..

GoodDay "username",

Blah Blah!

how can you actually do that? I know that you can do that through session variables but the thing is email's can't accept scripts on sending emails. how can I get the value from a session variable for example and convert it to plain html text so that i can OUTPUT it to the email.. HELP PLEASE!

This topic has been moved to PHP Installation & Configuration.

http://www.phpfreaks.com/forums/index.php?topic=347922.0

Hi, I currently have an if, elseif, else program that starts off with

Code: [Select]
if( $v_name == "" || $v_msg == "" )
echo "something"
how do I turn this into a switch?

but the very next elseif I have

Code: [Select]
elseif( strcspn( $_REQUEST['msg'], '0123456789' ) == strlen( $_REQUEST['msg'] ) )
echo "something"

is it possible to turn this into a switch with 2 different strings like that to evaluate?

Im dealing with html links in a database where I need to execute a small piece of php code. Well mysql doesnt execute php code thats held in a table. The easiest way for me to do this is just add the links without the code, & set up a function that will replace anything I set to for example in my case a link lookin like this:

http://mysite.com/index.php?page=offers&blah=blah&sid=

needs to look like this;

http://mysite.com/index.php?page=offers&blah=blah&sid=<?php echo $_SESSION['login']; ?>

so I would need a function like

<?php
$replace('sid=','sid=<?php echo $_SESSION['login'];?>
?>

something like that.

And I know its possible & I could create a function like this but honestly right now I am so tired after working 12 hours im lazy dont want to think to hard while I know there are a lot of people out there that have a function like this already.

If you dont have one & dont feel like writing one for me could you atleast point me in the right direction so I dont have to think to hard?!

Thanks!!

$query  = "SELECT * FROM School_Registrations WHERE School_Name= '$_POST[SchoolName]' ";
$result2 = mysql_query($query);
if (mysql_numrows($result2) > 0) {
while($row = mysql_fetch_array($result2))
{
echo" 
<h2>ERROR</h2>
...rest of the error code...
";} 
}
else {

mysql_query("INSERT INTO ``.`` (...all the variables...);") 

or die(mysql_error( 'Location: http://www...php' ));  
 
 echo "
...success code...


$url = 'http://www.mypage.com/page.php?';
$url .= 'email='.urlencode($_POST['email']);
 
$result = getPage('', $url, '', 15);
 
function getPage($proxy, $url, $header, $timeout) {
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_HEADER, $header);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_PROXY, $proxy);
    curl_setopt($ch, CURLOPT_HTTPPROXYTUNNEL, 1);
    curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
    curl_setopt($ch, CURLOPT_REFERER, 'http://mypage.org');
    curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.0.8) Gecko/2009032609 Firefox/3.0.8');
    $result['EXE'] = curl_exec($ch);
    $result['INF'] = curl_getinfo($ch);
    $result['ERR'] = curl_error($ch);
    curl_close($ch);
    return $result;
}
}
?>


Ok, so this code verifies what the name entered in the forms is not already in database. If it is it gives you the ...error code... and nothing else. If it does not it gives you ...success code... and it creates new table record, and it sends out email address entered to designated page. Bu I keep getting:

Fatal error: Call to undefined function getPage()

It still fully works, but no email goes out as defined. I am stuck. Help?

...added to an error log? Currently, my coding is as follows:

Form to gather data:
Code: [Select]
<html><head><title>Car Accident Report Form</title></head>
<form action="errorlog.php" method="post">
First Name: <br><input type="text" name="name"><br>
Surname:<br> <input type="text" name="surname"><br>
Age: <br><input type="text" name="age"><br>
Weeks Since Accident: <br><input type="text" name="weeks"><br>
<input type="submit" value="Submit">
</form>

Coding for error log:
Code: [Select]
<html><head><title>Validating Car Accident Report Form Details</title></head>
<?php
$name=$_POST["name"];
$surname=$_POST["surname"];
$age=$_POST["age"];
$weeks=$_POST["weeks"];
$subtime = strftime('%c');
$pass = "The details uploaded are fine<br><br>";
if ((((trim($name)="" && trim($surname)="" && trim($age)="" && trim($weeks)=""))))
{
echo "It seems that you have not entered a value for the Name, Surname, Age or Weeks fields. This has been added to the error log.<br><br>";
error_log("<b><u>Error</b></u><br>The user has not entered any values", 3, "C:/xampp/htdocs/errorlog.txt");
}
if (($age<18)&& ($weeks<=1))
{
echo "It seems that you have entered an invalid age and number of weeks since the accident. This has been added to the error log.<br><br>";
error_log("<b><u>Error</b></u><br>The user has entered an age that is below 18 and the number of weeks since the accident is equal to or under 1 week!<br>Age entered:" . $age . "<br>Number Of Weeks Since Accident entered:" . $weeks . "<br>Time that form was submitted:" . $subtime . "<br><br>", 3, "C:/xampp/htdocs/errorlog.txt");
} 
else if ($age<18)
{
echo "It seems that you have entered an invalid age. This has been added to the error log.<br><br>";
error_log("<b><u>Age Error</b></u><br>The user has entered an age that is below 18!<br>Age entered:" . $age . "<br>Time that form was submitted:" . $subtime . "<br><br>", 3, "C:/xampp/htdocs/errorlog.txt");
}
else if ($weeks<=1)
{
echo "It seems that you have entered an invalid age number of weeks since the accident. This has been added to the error log.<br><br>";
error_log("<b><u>Week Error</b></u><br>The user has entered a number of weeks since the accident that is equal to or under 1 week!<br>Number Of Weeks Since Accident entered:" . $weeks . "<br> Time that form was submitted:" . $subtime . "<br><br>", 3, "C:/xampp/htdocs/errorlog.txt");
}
else
{
echo $pass;
}
echo "Car Accident Report Form details have been sent<br>";
echo "<a href='readlog.php'>Read Error Log</a>"
?>

</html>

How can I get it so that if a user presses the space bar in a field, then the trim function sees that there's no white space and then this gets added to the error log?

Any help is appreciated!

okay..  so I found a list of bad words on line that I want to work into my website's insert.  I took the time to create a long comma-delimited list and I'm trying to use this in my page but I keep getting errors.  I'm not sure what I'm supposed to be escaping because of the many numerous characters in this list.  Might someone help?  As I didn't want to post a bunch of foul words on this forum, I posted it he   http://snipt.org/xmpgk 

You might not want to visit if you don't like bad words. 

As the list currently is, I'm getting this error:
Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING, expecting ')' in /home/jeffro/public_html/all/xyzman/inserttodb.php on line 114

....right on the line where $newwords begins.

Hi all,

Using a form with check boxes divided into different categories, I collect data selected by the user.

I now want to combine each choice in each category with each choice in the other categories and list the combinations to the user.

If the user chooses one or more options in each category, it is relatively easy to nest foreach loops, since the number of categories will always be the same. For example, if the form contains three categories of options, the code will be:

Code: [Select]
foreach ($form['cat_1'] as $k1 => $val1)
{
foreach ($form['cat_2'] as $k2 => $val2)
{
foreach ($form['cat_3'] as $k3 => $val3)
{
echo  $val1.' _ '.$val2.' _ '.$val3.'<br/>';
}
}
}

Things get complicated if the user does not select options within a given category. More generally, I want to be able to generate the list regardless of the number of categories in which the user selects options.

Thank you in advance for your advice.

hello,

I was wondering what is the point of writing

for a dropdown: <?php if ($_POST[inputfieldID] == "value") { echo "selected"; } ?>

or for a checkbox/ radio button: <?php if ($_POST['cb/radioID'] == "value") { echo "checked"; } ?>

I guess it's for after submit, if there is any error, the values filled will still be echoed in the inputfield, or am i wrong?

But then if that is true, i have a php search box where i use AJAX object to to send all the input they filled in after submit. But after pushing submit the inputted values remain.

I guess when using AJAX to send the information i don't need  <?php if ($_POST[inputfieldID] == "value") { echo "selected"; } ?> in my html forms?


Little confused Can maybe somebody bring clearness

Hey guys!
I have the following doubt:

I have a php file that does the following alongside with other code not displayed he

$fp = fopen("emails.txt", "w");

It opens a txt file called emails.txt that is in the same folder where the php is saved but how do I tell $fp = fopen("/folderbefore/emails.txt", "w"); ??

In other words, how do I write the path on the script that the emails.txt is located in a previous folder where the php file is located??

Thanks in advance for your help
Cheers!