PHP - Preg_replace - I Don't Want It To Be Case Sensitive

I have taken over a wordpress site that a web developer set up and he is no longer working with me so I cant get his help with it, I have a custom front page that has been pulling press releases that where posted previously and categorized as "press" I was asked to add a blog which I did by categorizing the post as "blog"

In a nutshell, I now need the front page code to pull a mixture of both the "press" and "blog" each category has a numerical id so blog is 7 and press is 3

This is the current code that is in the page
<?php query_posts('category_name=press&showposts=10&offset=0'); ?>

I looked up wordpress support for this, and found this
query_posts(array('category__in' => array(2,6)));

How can I integrate this if possible with the top line so it pulls the newest posts from both categories? Any suggestions could REALLY help me out!

Thanks!

Hello,

I am completely new to php so please forgive me ahead of time. I am trying to create a link button on a website for a client that only directs to a certain external website on certain days and hours. Specifically, this is a web radio button that the client only wants to link to the web radio site when their live broadcast is on the air during certain hours on the weekend (i.e. Sundays 8-10 PM). Any other time, the client wants the web radio button to link to a default page since the web radio station plays unrelated music all other hours of the week. Does anyone know the best way to create such a time sensitive link for a button on a webpage?

Thanks.

I am by no means a security expert, but I would like to know if storing MySQL database information in an environment variable would be a good or bad idea. What are your thoughts?

hey guys im having a few problems with my query if anyone can please help...the two problems im having is   1.the total price returning as 00106. price = 100.00 and p_and_p = 6.00 in the database...im after a figure that looks like 106.00   2. @category will be a parameter like :category which will be binded to a value like 'al'l, 'videos', 'dvd's', but if the parameter is ALL i dont want to join my categories table allowing it to select all rows regardless of the category   any help, pointer would be truly appreciated...thank you

SELECT @category := 'Videos',
		         i.item_id, 
		         i.title, 
		         i.price,
		         i.p_and_p,
		         SUM(i.price + i.p_and_p) AS `total_price`,
		         i.listing,
		         i.condition,
		         CONVERT_TZ(DATE_ADD(i.start_date_time, INTERVAL concat(i.listing_duration) DAY), '+00:00', u.time_zone) AS `end_date_time`
		  FROM items i
		  LEFT JOIN sub_categories sc ON sc.sub_category_id = i.sub_category_id
  		  CASE @category != 'All'
          THEN 
		  LEFT JOIN categories c ON c.name = 'Videos'
          END CASE		
		  JOIN users u
		  WHERE u.user_id = '7'
		  AND MATCH (i.title, i.description) AGAINST ('bla' IN BOOLEAN MODE)
		  AND i.start_date_time < NOW() 
		  AND DATE_ADD(i.start_date_time, INTERVAL concat(i.listing_duration) DAY) >= NOW()
		  GROUP BY i.i

Hi, I have the following code:

Code: [Select]
case "Twitter";
        echo 'Twitter gadget will show here';
   break;

I  need to make it so it's like this:

Code: [Select]
case "Twitter" AND $member['top'] == "1"
echo "Twitter Gadget will show here";
break;

I need to add a IF onto the CASE is it possible?

Thank you.

hi,

i just wanted to know...

$arr[0] $arr[1] $arr[2] also this $arr[1] would be called a value, but how are the numbers 0,1 and 2 called? are that keys?

didn't know where else to post this question.

can i do something like this?

Code: [Select]
<?php
switch ($i) {
    case 0:
        echo "i equals 0";?>
////////////// html stuff ////////
<?php
        break;
    case 1:
        echo "i equals 1"; ?>
///////////////////html stuff//////////////
<?php
        break;
    case 2:
        echo "i equals 2"; ?>
////////////html stuff///////////////
<?php
        break;
}
?>

i've read and seen there are variations of what im trying to achieve but havent seen a exact example...what im trying to do is put a where clause in my query depending on if a set variable has a value

CASE WHEN (@category_id IS NOT NULL)
THEN
LEFT JOIN sub_categories sc ON sc.sub_category_id = i.sub_category_id
JOIN categories c ON c.category_id = sc.category_id AND c.category_id = :category_id
END

is this possible or have i just got the syntax wrong somewhere...thank you guys

I am trying to pull out the image HTML tag but its not working as expected.
Here is what I am doing
   $removeimagetag='/<a href/';
   $replacwith = "illegal";
$_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']);

in the 'descr' there is a <a href="http://s635.photobucket.com......
When it post it does not strip out the <a href
So the image is displayed.

I tried a modified version to test to see if it work that looked like this.

   $removeimagetag='/goofy/';
   $replacwith = "illegal";
$_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']);

When the word goofy appears in the text then its replaced with the word illegal,

Also I would like to make it so that it replaces the entire line from the <a href....... to the </a> with a phrase that says "this feature is not allowed"  rather than just the part in the front...the <a href.

Any help you can be will be greatly appreciated.

Hi,

I'm kind of new to PHP and very new to Regular Expressions and I was wondering if someone could help run through this code snippet from a callback function in a Joomla plugin called Affliates Feed.

So far I have this
is passed a pointer to variable item (I understand this is effectively the same as passing the variable but a lot less CPU intensive.
Creates an array with keys and values

Now the for loop I am stuck with, I understand the interation through the array. But what is preg_replace returning and why pass it back that way hasn't it already done its job?

Can any one help? And please feel free to be as basic as possible :help:

Thanks,
Adam


Code: [Select]
function gardening(&$item) {
   #renaming categories, not the most efficient use for example strtolower first, and use only lowercase in the rename array
   $rename=array(
      ' Gardening?' => '',
      'Climber Plants' => 'Climbing Plants',
      'Seeds.*Bulbs' => 'Seeds Bulbs',
      'Plant protection' => 'Horticultural goods',
      'Garden structures' => 'Garden buildings',);
   foreach ( $rename as $k => $v ) {
      list($item['menu_1'],$item['menu_2'])=preg_replace("#$k#",$v,array($item['menu_1'],$item['menu_2']));
   }
   $item['menu_1']=ucfirst(strtolower($item['menu_1']));
   $item['menu_2']=ucfirst(strtolower($item['menu_2']));
   $item['menu_3']=ucfirst(strtolower($item['menu_3']));
   $item['menu_4']=ucfirst(strtolower($item['menu_4']));
}

i have:


$msg = ereg_replace("[^A-z0-9]"," ",$msg);
$msg = ereg_replace("  "," ",$msg);
$msg = ereg_replace("    "," ",$msg);


how will i apply preg_replace please???
thank you

After days of searching I found this thread http://www.phpfreaks.com/forums/index.php?topic=236954.0 that helped me do what I was trying to do.  I've gotten the code to create and rename my html document but I can't figure out how to use the preg_replace part.  This is my template with the 3 variables I want to replace with values from a form.

Code: [Select]
<html>
<head>
<link rel="stylesheet" type="text/css" href="style.css" />
</head>
<body>
<?php include_once('content.php') ?>
</body>
<SCRIPT language="JavaScript" SRC="javascript.js"></SCRIPT>
<script type="text/javascript">
function nametitle(){
parent.iframe1.document.getElementById("div1").innerHTML = "VARIABLE1
<br>VARIABLE2";
parent.iframe1.document.getElementById("quotes").innerHTML = "VARIABLE3";
}
</script>
</html>
I've spent hours reading and trying to understand how to make it work but it's a little over my head.  Could someone help me with this?

Thanks,

Hi everyone,

how do i add and ampersand symbol into preg_replace

preg_replace("/[^a-zA-Z0-9\s\-\'\,\.\_]/"

where do i place the symbol? &

Hi there!

I need to echo some text from a database table, this text should be linked to a url stored in the same database. I am trying to do this with preg_replace but I am terrible at it! I keep getting this error:

Warning: Wrong parameter count for preg_replace()

while($row = mysql_fetch_array( $result ))
 {

$reg_exUrl = "/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/";

echo preg_replace ($reg_exUrl, $row['title');


Any suggestion?

Thanks

Hello ppl,
I have this website link http://www.somesite.com/anotherpage/yetotherpage.html what i want to make is using preg_replace that the final result will be www.somesite.com