PHP - Make A Button A Link....

Hey again, was making a registration form with php and postgresql and  im stuck at making a 'log out' button, i need to make something simple like - press on a link, it redirects u to the index page and if u try to go 'back' it wouldn't let u..

I found something on google like this:

<a href="test.php?logout=1">Log out</a>


and on test.php:

<?php
if(isset($_GET['logout'])){
session_unset;
session_destroy;
}
?>
Succesfully logged out, go back to index page: <a href="index.php">Home</a>


but i didnt use any sessions at all.. is there something like 'session_destroy' with postgre? i mean smth like 'pg_desroy'?

so this is my code


Code: [Select]

<?
$b=$_GET['b'];
$m=$_GET['m'];
$y=$_GET['y'];

if  ($b <> '' && $m <> '' && $y <> '') {

$branch=$b;
$leavemonth=$m;
$leaveyear=$y;
}
else
{
$branch=$_POST['branch'];
$leavemonth=$_POST['leavemonth'];
$leaveyear=$_POST['leaveyear'];
}



$connection=mysql_connect("$server", "$username", "$password")
or die("Could not establish connection");
mysql_select_db($database_name, $connection)
or die ("Could not select database");


   
    $query="SELECT * from tblworkgroup";
    $result=mysql_query($query);?>


        &nbsp;&nbsp;Branch&nbsp;
        <select name="branch" >
<option value="all">ALL Branches</option>       
        <? while($row=mysql_fetch_array($result)) { ?>       
    <option value= "<?=$row['WorkGroupID']?>" <? if ($branch==$row['WorkGroupID']){ echo 'selected'; } ?> ><?=$row['WorkGroupName']?></option>
     <? } ?>
        </select>
           </td>
          </tr>
       <br><br><br>
  &nbsp;&nbsp;Month &nbsp;&nbsp;
<select name="leavemonth" >
<option value = "1" <? if ($leavemonth==1){ echo 'selected'; } ?>>January</option>
<option value = "2" <? if ($leavemonth==2){ echo 'selected'; } ?>>February</option>
<option value = "3" <? if ($leavemonth==3){ echo 'selected'; } ?>>March</option>
<option value = "4" <? if ($leavemonth==4){ echo 'selected'; } ?>>April</option>
<option value = "5" <? if ($leavemonth==5){ echo 'selected'; } ?>>May</option>
<option value = "6" <? if ($leavemonth==6){ echo 'selected'; } ?>>June</option>
<option value = "7" <? if ($leavemonth==7){ echo 'selected'; } ?>>July</option>
<option value = "8" <? if ($leavemonth==8){ echo 'selected'; } ?>>August</option>
<option value = "9" <? if ($leavemonth==9){ echo 'selected'; } ?>>September</option>
<option value = "10" <? if ($leavemonth==10){ echo 'selected'; } ?>>October</option>
<option value = "11" <? if ($leavemonth==11){ echo 'selected'; } ?>>November</option>
<option value = "12" <? if ($leavemonth==12){ echo 'selected'; } ?>>December</option>
</select>

&nbsp;&nbsp;
Year &nbsp;&nbsp;
<select name="leaveyear" >
<option value = "2010" <? if ($leaveyear==2010) { echo 'selected';} ?>>2010</option>
<option value = "2011" <? if ($leaveyear==2011) { echo 'selected';} ?>>2011</option>
<option value = "2012" <? if ($leaveyear==2012) { echo 'selected';} ?>>2012</option>
<option value = "2013" <? if ($leaveyear==2013) { echo 'selected';} ?>>2013</option>
<option value = "2014" <? if ($leaveyear==2014) { echo 'selected';} ?>>2014</option>
<option value = "2015" <? if ($leaveyear==2015) { echo 'selected';} ?>>2015</option>
<option value = "2016" <? if ($leaveyear==2016) { echo 'selected';} ?>>2016</option>
<option value = "2017" <? if ($leaveyear==2017) { echo 'selected';} ?>>2017</option>

</select>


  &nbsp;&nbsp;

<input type='submit' name='submit' value='Preview' Class="button" onclick='return validate()'>
   
   </div>

</form>


<br /><br />

<div id="box" valign="top">
                <h3>&nbsp;<strong>Leave Application Details</strong>&nbsp;&nbsp</h3>
<br><br>
<FORM name="printbutton" method="post" align="left" action="report_print.php" target="_blank">
<input type="hidden" name="leavemonth" value="<?php echo $leavemonth; ?>">
<input type="hidden" name="leaveyear" value="<?php echo $leaveyear; ?>">
<input type="hidden" name="branch" value="<?php echo $branch;?>">
<Input type = "Submit" Name = "Submit1" Class="button" VALUE = "Print Leave Details">
</form>
                <table width="80%" align="center" >
<thead>
<tr>
<th width="700px" align="left">Name</a></th>
                           
<th width="500px" align="center"></a>Application Date</th>

<th width="500px" align="center"></a> </th>
                           
<th width="500x" align="right"></a>Reason</th>
</tr>
</thead>
<tbody>
<?
/*echo "branch:".$branch.'<br />';
echo "leavemonth:".$leavemonth.'<br />';
echo "leaveyear:".$leaveyear.'<br />';*/
//--------------------------------------------------
if ($leavemonth =='' ||  $leaveyear =='' || $branch == '') {
// one value missing, so don't display
}
else
{
// start display data
$branchtracker = '';

if ($branch=='all'){
$branch = '%';
}

$rs = mysql_query( " call vwleavereport('$leavemonth', '$leaveyear', $branch, 0);");
$query="SELECT *,
MONTH(tblleaveapplication.DateFrom) as DFMonth,
MONTH(tblleaveapplication.DateTo) as DTMonth,
YEAR(tblleaveapplication.DateFrom) as DFYear
FROM `tblleaveapplication`
LEFT JOIN `tblemployee`
ON tblleaveapplication.employeeid = tblemployee.id
WHERE WorkGroupID LIKE '".$branch."'
AND (
(MONTH(tblleaveapplication.DateFrom)=".$leavemonth." AND YEAR(tblleaveapplication.DateFrom)=".$leaveyear.")
OR
(MONTH(tblleaveapplication.DateTo)=".$leavemonth." AND YEAR(tblleaveapplication.DateFrom)=".$leaveyear.")
)
ORDER BY WorkGroupID
";

$result = mysql_query($query);
while($row=mysql_fetch_array($result))
{
if ($branchtracker<>$row['WorkGroupID']){
echo '<tr><td colspan=4 style="background-color: #e8e8e8; font-weight: bold;">'.$row['WorkGroupID'].'</td></tr>';
$branchtracker = $row['WorkGroupID'];
}
echo '<tr>';
echo '<td>'.$row['EmployeeName'].'</td>';
echo '<td>'.$row['DateFrom'].'</td>';
echo '<td>'.$row['DateTo'].'</td>';
echo '<td>'.$row['Purpose'].'</td>';
echo '</tr>';
}

}
?>


the problem is i want the print button only appear when there is output..

Hi

I have made this simple login page by setcookies function and I want now to make a logout button.

Here the code 

<?php
/*
PHP Form Login Remember Functionality with Cookies
*/
if(!empty($_POST["remember"])) {
	setcookie ("username",$_POST["username"],time()+ 3600);
	setcookie ("password",$_POST["password"],time()+ 3600);
    setcookie ("color",$_POST["color"],time()+ 3600);
    //3600 = 1 hour
    //86400 = 1 day
    //(8640*30) = 1 month
	echo "Cookies Set Successfuly";
} else {
	setcookie("username","");
	setcookie("password","");
    setcookie("color","");
	echo "Cookies Not Set";
}
?>
  <form action="Cookies.php" method="post"
 style="border: 2px dotted blue;
 text-align:center; width: 400px;">

 <p>Welcome <?php echo ( !empty($_POST ['username']) ) ?
  $_POST ['username'] : 'USER'; ?>
    </p>
	<p>Username: <input name="username" type="text" 
    value="<?php if(isset($_COOKIE["username"])) 
    { echo $_COOKIE["username"],( !empty($_POST ['username']) ) ?
  $_POST ['username'] : '';} ?>" >
	</p>
	<p>Password: <input name="password" type="password" value="
    <?php if(isset($_COOKIE["password"])) 
    { echo $_COOKIE["password"]; } ?>" >
	</p>
    <p>Choose Your Favorite Color: <input name="color" type="color" 
    value="<?php if(isset($_COOKIE["color"])) 
    { echo $_COOKIE["color"]; } ?>">
	</p>
	<p><input type="checkbox" name="remember" /> Remember me</p>
	<p><input type="submit" value="Login"></p>  
</form>

Any idea ??

I have created a database that echos out the result on a webpage, what i want to do is create one of the echo results into a link - the code is as follows:

"Web Address: $web_address <br>" .

Is there an easy way to make the result a link as the input will always be a web address?

Thanks in advance!