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PHP - Server Status Checker
Hi all, I have this script I used on a site hosted on my machine that checked if different servers and applications were running on my machine.
Here's the code. Code: [Select] <html> <body> <style> fd{ color: #000000 font-size:100% } </style> <?php function check_port($port) { $conn = @fsockopen("212.233.xxx.xxx", $port, $errno, $errstr, 0.2); if ($conn) { fclose($conn); return true; } } function server_report() { $report = array(); $svcs = array('21'=>'FTP', '22'=>'SSH', '25'=>'SMTP', '80'=>'HTTP', '110'=>'POP3', '143'=>'IMAP', '3306'=>'MySQL', '8080'=>'HFS', '8081'=>'Webcam', '3784'=>'Ventrilo'); foreach ($svcs as $port=>$service) { $report[$service] = check_port($port); } return $report; } $report = server_report(); ?> <center> <table> <tr> <td><font face="Verdana" size="1" color="#000000">Apache:</td> <td><font face="Verdana" size="1" color="#000000"> <?php echo $report['HTTP'] ? "<img src='main/images/on.png' width='16' height='15' border='0'>" : "<img src='main/images/off.png' width='16' height='15' border='0'>"; ?></font></td> </tr> <tr> <td><font face="Verdana" size="1" color="#000000">MySQL:</td> <td><font face="Verdana" size="1" color="#000000"> <?php echo $report['MySQL'] ? "<img src='main/images/on.png' width='16' height='15' border='0'>" : "<img src='main/images/off.png' width='16' height='15' border='0'>"; ?></font></td> </tr> <tr> <td><font face="Verdana" size="1" color="#000000">HFS:</td> <td><font face="Verdana" size="1" color="#000000"> <?php echo $report['HFS'] ? "<img src='main/images/on.png' width='16' height='15' border='0'>" : "<img src='main/images/off.png' width='16' height='15' border='0'>"; ?></font></td> </tr> <tr> <td><font face="Verdana" size="1" color="#000000">FTP:</font></td> <td><font face="Verdana" size="1" color="#000000"> <?php echo $report['FTP'] ? "<img src='main/images/on.png' width='16' height='15' border='0'>" : "<img src='main/images/off.png' width='16' height='15' border='0'>"; ?></font></td> </tr> <tr> <td><font face="Verdana" size="1" color="#000000">Webcam:</font></td> <td><font face="Verdana" size="1" color="#000000"> <?php echo $report['Webcam'] ? "<img src='main/images/on.png' width='16' height='15' border='0'>" : "<img src='main/images/off.png' width='16' height='15' border='0'>"; ?></font></td> </tr> <tr> <td><font face="Verdana" size="1" color="#000000">Ventrilo:</font></td> <td><font face="Verdana" size="1" color="#000000"> <?php echo $report['Ventrilo'] ? "<img src='main/images/on.png' width='16' height='15' border='0'>" : "<img src='main/images/off.png' width='16' height='15' border='0'>"; ?></font></td> </tr> </table> </center> </body> </html> I've added the HTML too. As you can see it checks if the ports are open. It worked perfectly and I didn't have any issues with it at all. Now, for a couple of days, I've been using an awardspace paid hosting, bought a domain name. I use wordpress now, and I pasted this code directly in a PHP/HTML code box (I use a plugin that enables use of PHP) and it shows the HTML formatting how it should be, but unfortunately doesn't work as intended. It shows everything to be down, while apache, mysql and my ftp server are still running on my computer (the IP it checks, 212.233.xxx.xxx). When I set the IP to be 127.0.0.1, the IP of the awardspace server as far as my script is concerned, it shows only that the IP is working. So, any suggestions? Any idea would be greatly appreciated Similar TutorialsI am trying to make a Server Status checker that uses a image to tell if it is online or not. I also am trying to make it so you can the URL as a image code(EX: http://Http://domain.com/statuscheck.php?ip=google.com&port=80). What I'm trying to say it, that if you do like <img src="http://Http://domain.com/statuscheck.php?ip=google.com&port=80"> it would go to my site, use the php script, and then have the image Online or Offline, were the <img> code was posted. Here's my code Im trying to make it from. <?php $ip="{$_GET['ip']}"; $port="{$_GET['port']}"; if(!$sock=@fsockopen($ip,"$port", $num, $error, 5)) { Header('Content-type: image/png'); echo"<img src='images/offline.png'>"; } else { Header('Content-type: image/png'); echo"<img src='images/online.png'>"; } ?> I got this code off of this forum Code: [Select] <?php $ip="{$_GET['ip']}"; $port="{$_GET['port']}"; header('Content-type: image/png'); if(!$sock=@fsockopen($ip,"$port", $num, $error, 5)) { readfile('image/offline.png'); } else { readfile('image/online.png'); } ?>I'm able to check the status by going to Code: [Select] http://domain.com/statuscheck.php?ip=google.com&port=80 and it works fine. But I would like to show the status on my index.html page without having to click on a link. Is there anyway Please help. thank you in Advance. Hello I recently got a "to many connection" error on my site, and want to know if anyone here knows a few codes that will show how many connection currently are in use (maybe even what files that creates them). I found I can use "Threads_connected" to show current open connections, but no info on how to write the code or where to pu the file. I hope you can show my what to do Hello, I made a server statuc checking script that checks the status of a game server. It works fine on my computer, but when I upload it to my web host it stops working. I'm assuming my web host is blocking it in some way. My host is Yahoo Small Businesses. Does anyone know if they block this kind of thing, or if there is a way to unblock it? Perhaps editing the code? Here is my code, if that helps. Code: [Select] <?php function GetServerStatus($site, $port) { $status = array("OFFLINE", "ONLINE"); $fp = @fsockopen($site, $port, $errno, $errstr, 2); if(!$fp) { return $status[0]; } else { return $status[1]; } } $Redemption = GetServerStatus("174.142.118.233", 11661); $RedemptionPossible = GetServerStatus("174.142.118.234", 51665); $Tranquility = GetServerStatus("174.142.118.234", 11601); $TranquilityPossible = GetServerStatus("174.142.118.234", 51665); $Nemesis = GetServerStatus("174.142.118.241", 11601); $NemesisPossible = GetServerStatus("174.142.118.241", 64721); $OverallServer = GetServerStatus("174.142.118.237", 11093); $CodServer = GetServerStatus("8.9.6.122", 4230); echo($CodServer . "<br />"); echo("Overall Server: " . $OverallServer . "<br />"); echo("Redemption: " . $Redemption . "<br />"); echo("Tranquility: " . $Tranquility . "<br />"); echo("Nemesis: " . $Nemesis . "<br />"); ?> Hi all! Yet again I have a problem. I really couldn't find what the heck's wrong with this thing. It's extremely simple and still... I'm trying to put a php script in my website to monitor the status of my FTP and HFS servers. Help? <TITLE>Server Status</TITLE> <?php $data .= " </div> <center> <div style=\"border-bottom:1px #999999 solid;width:480;\"><b> <font size='1' color='#3896CC'>Server Status</font></b> </div> </center> <br>"; //configure script $timeout = "1"; //set service checks $port[1] = "80"; $service[1] = "Apache"; $ip[1] = "localhost"; $icon[1] = "habbo.jpg"; $alt[1] = "Apache"; $port[2] = "8080"; $service[2] = "HFS Server"; $ip[2] = "localhost"; $icon[2] = "web.png"; $alt[2] = "HFS Server"; $port[3] = "21"; $service[3] = "FTP Server"; $ip[3] = "localhost"; $icon[3] = "web.png"; $alt[3] = "FTP Server"; // // NO NEED TO EDIT BEYOND HERE // UNLESS YOU WISH TO CHANGE STYLE OF RESULTS // //count arrays $ports = count($port); $ports = $ports + 1; $count = 1; //beggin table for status $data .= "<table width='480' border='1' cellspacing='0' cellpadding='3' style='border-collapse:none' bordercolor='#CCCCCC' align='center'>"; while($count < $ports){ if($ip[$count]==""){ $ip[$count] = "localhost"; } $fp = @fsockopen("$ip[$count]", $port[$count], $errno, $errstr, $timeout); if (!$fp) { $data .= "<tr><td width='18' align='center'><img src='http://127.0.0.1/stat/$icon[$count]' title='$alt[$count]' alt='$alt[$count]'></td><td>$service[$count]</td><td width='18' align='center'><img src='http://127.0.0.1/stat/off.png'></td></tr>"; } else { $data .= "<tr><td width='18' align='center'><img src='http://127.0.0.1/stat/$icon[$count]' title='$alt[$count]' alt='$alt[$count]'></td><td>$service[$count]</td><td width='18' align='center'><img src='http://127.0.0.1/stat/on.png'></td></tr>"; fclose($fp); } $count++; } //close table $data .= "</table><div>"; echo $data; ?> The output of this is... Quote Parse error: syntax error, unexpected T_VARIABLE in D:\Program Files\xampp\xampp\htdocs\stat\server.php on line 18 Also, does somebody have a link or something to a tutorial/pre-made script (although I'd like to follow instructions about it) about server statistics? I want to have data on how much a certain partition on the server has free or full. Thank you in advance. Hello friends, I've tried to search over the Internet but didn't found any tutorial how to do the following :- let say we have form with input username and input email just 2 field HTML Code Code: [Select] <form> <table> <tr> <td>Username :</td> <td><input id="username" size="20" type="text" name="username"></td> </tr> <tr> <td>Email :</td> <td><input id="email" size="20" type="text" name="email"></td> </tr> </table> </form> As you can see no submit button cause we will only check out if username and/or email is not stored already, by using ajax My problem : i can only check out for username (1 field) but i can not check for 2 fields or more and i want to know how to apply it for 2 fields (username and email) Here is my idea for only one field (username) I'll add in the HTML code this Code: [Select] <td><div id="status"></div></td> and will add this java code Code: [Select] <SCRIPT type="text/javascript"> pic1 = new Image(16, 16); pic1.src = "loader.gif"; $(document).ready(function(){ $("#username").change(function() { var usr = $("#username").val(); if(usr.length >= 4) { $("#status").html('<img src="loader.gif" align="absmiddle"> Checking availability...'); $.ajax({ type: "POST", url: "check.php", data: "username="+ usr, success: function(msg){ $("#status").ajaxComplete(function(event, request, settings){ if(msg == 'OK') { $("#username").removeClass('object_error'); $("#username").addClass("object_ok"); $(this).html(' <img src="tick.gif" align="absmiddle">'); } else { $("#username").removeClass('object_ok'); $("#username").addClass("object_error"); $(this).html(msg); } }); } }); } else { $("#status").html('<font color="red">The username should have at least <strong>4</strong> characters.</font>'); $("#username").removeClass('object_ok'); $("#username").addClass("object_error"); } }); }); </SCRIPT> Explain : it will get the input of username and will send it to check.php Now check.php code (should have all usernames that will compare with it) Code: [Select] <?php if(isSet($_POST['username'])) { $usernames = array('john','michael','terry', 'steve', 'donald'); $username = $_POST['username']; if(in_array($username, $usernames)) { echo '<font color="red">The username<STRONG>'.$username.'</STRONG> is already in use.</font>'; } else { echo 'OK'; } } ?> Now it is very clear , if will automatic check the username now my problem is how to apply it for also email Any body here who can help me to make a plagiarism checker in php? that can accurately get the site of the content that is copied from internet. thanks in advance. godbless.
Hey guys, I have this little script, but it doesn't seem to work properly. <?php mysql_connect("localhost","root",""); mysql_select_db("chat"); $user = strip_tags(trim($_REQUEST['username'])); if(strlen($user) <= 0) { echo json_encode(array('code' => -1,'result' => 'Invalid username, please try again.')); die; } // Query database to check if the username is available $query = "Select * from users where username = '$user' "; $result = mysql_query($query); $avaliable = mysql_num_rows($result); // Execute the above query using your own script and if it return you the // result (row) we should return negative, else a success message. //$available = true; if($available) { echo json_encode(array('code' => 1,'result' => "Success,username $user is still available")); die; } else { echo json_encode(array('code' => 0,'result' => "Sorry but username $user is already taken.")); die; } die; ?> It keeps returning with 'Sorry but username iunsdbsyusaddssd763b373b is already taken'. Even when I type in some random gibberish like 'iunsdbsyusaddssd763b373b' Can anyone show me why it is doing that? Thanks alot friends. This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=357042.0 Alright, I have created a hash password checker and here is my code: include("include.php"); // include the mySQL info! $users = mysql_query(" SELECT * FROM User "); // Select all from the users table in the database! while($row = mysql_fetch_array($users)) // While it fetches the users do the following... { if (hash("sha256", $password) == $row["Password"]) echo "Congratulations! The Hash matches the password entered into the database!"; } elseif (hash("sha256", $password) != $row["Password"]) { echo "Your Hash failed to match the password entered!"; } Now for some reason this displays a totally blank page. When I turn error display on I get the error "Unexpected T_ELSEIF" on this line elseif (hash("sha256", $password) != $row["Password"]) Any help is appreciated... Hello, I am trying to get this backlink checker to work i have it working so it checks that the link itself matches and is there but this is the harder part that I don't understand. I want to have it also check the nodeValue to make sure that it matches one of the nodeValue's from a mysql table this is the code I have to make it check the href link Code: [Select] function CheckForTargetUrl($links, $target) { foreach ($links as $link) { if (strpos($link, $target) !== false) { return true; } } return false; } function ExtractHrefLinks($html) { $dom = new DOMDocument; $linkUrls = array(); @$dom->loadHTML($html); $links = $dom->getElementsByTagName('a'); foreach ($links as $link){ $linkUrls[] = $link->getAttribute('href'); } return $linkUrls; } function backlink_check($contenturl){ $url = 'businessinvestingsource.com'; $source = $contenturl; $falseFound = false; $html = file_get_contents ( $source ); $links = ExtractHrefLinks($html); if (CheckForTargetUrl($links, $url) === false) { $falseFound = "true"; $reportArray[$source] = 0; } else { $falseFound = "false"; } return $falseFound; } Now this all works fine, I just need it to check the actual nodeValue (anchor text as well) meaning check this: <a href="http://google.com">Google</a> There is a mysql table called "allowed_anchors" with 2 rows "id" and "anchor" I need it to check if the nodeValue matches 1 of the allowed_anchors from the table. If anyone knows how I can do this that would be very great i have been trying to figure it out for hours with no luck. Thanks very much for any help to come. I have a PHP web system that store in a windows server. In the system, there is a function for user to upload files to another server (Shared server in Unix). When i try to upload a file, it gives warning: Warning: move_uploaded_file(\\unixserver/sharedfolder/upload/test.txt) [function.move-uploaded-file]: failed to open stream: Permission denied in C:\wamp\www\upload\index.php on line 40 For your information, my username has been assigned in xxx's group that has access to read and write on that folder. Besides, i'm able to open,create and delete files on that folder's server manually (samba). The safe mode setting is off. Does anybody has any idea why this thing happen? I'm trying to make a simple website where people register to my website. When the user doesn't fill anything inside the boxes they get a message "Please fill all required fields" on the register.php page On my local host require_once works good. It shows up.
But when i upload the files to my sever the require_once does not show up on the register.php It just refreshes and i dont get the message "Please fill all required fields"
This is the code that works in local host but not in a live server <?php require_once 'messages.php'; ?>
Here is my full code
Register page: <html> <?php require_once 'messages.php'; ?> <br><br> <form action="register-clicked.php" method="POST"> Username:<br> <input type="text" name="usernamebox" placeholder="Enter Username Here"> <br><br> Email:<br> <input type="text" name="emailbox" placeholder="Enter email here"> <br><br> Password:<br> <input type="password" name="passwordbox" placeholder="Enter password here"> <br><br> Confirm Password:<br> <input type="password" name="passwordconfirmbox" placeholder="Re-enter password here"> <br><br> <input type="submit" name="submitbox" value="Press to submit"> <br><br> </form> </html>
Register clicked <?php
session_start();
$data = $_POST;
if( empty($data['usernamebox']) ||
empty($data['emailbox']) ||
empty($data['passwordbox']) ||
empty($data['passwordconfirmbox'])) {
$_SESSION['messages'][] = 'Please fill all required fields';
header('Location: register.php');
exit;
}
if ($data['passwordbox'] !== $data['passwordconfirmbox']) {
$_SESSION['messages'][] = 'Passwords do not match';
header('Location: register.php');
exit;
}
$dsn = 'mysql:dbname=mydatabase;host=localhost';
$dbUser='myuser';
$dbPassword= 'password';
try{
$connection = new PDO($dsn, $dbUser, $dbPassword);
} catch (PDOException $exception){
$_SESSION['messages'][] = 'Connection failed: ' . $exception->getMessage();
header('Location: register.php');
exit;
}
messages.php <?php
session_start();
if (empty($_SESSION['messages'])){
return;
}
$messages = $_SESSION['messages'];
unset($_SESSION['messages']);
?>
<ul>
<?php foreach ($messages as $message): ?>
<li><?php echo $message; ?></li>
<?php endforeach; ?>
</ul>
Edited Wednesday at 12:49 AM by bee65 Hi, I am not a PHP programmer. I took on a new client with a simple PHP site, without any databases. The site is up and running on the web. I would like to get it running on my local machine for further development. I have latest version of WAMP installed, running Apache version 2.2.11 and PHP version 5.3.0 I created a directory in the WAMP "www" project directory and it shows up there like it's supposed to when I browse to "localhost" Problem: The home page of website displays text but no, images, styles, footer, header, nav links, etc. Here is the code for the home page: <? define("NAV","home"); require_once('local/local.php'); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>TITLE</title> <meta name="keywords" content=""> <meta name="Description" content=""> <? include("common/dochead.php"); ?> </head> <body onLoad="<? include('common/preloads.php'); ?>"> <!-- ============================ main ============================= --> <div id="main-frame"><div id="main" class="noCollapse"> <? include("common/sign.php"); ?> <div id="right-frame"> <? include("common/navigation.php"); ?> <div id="content-frame"> <div id="content"> <h1>Welcome</h1> <p>This is the content area. This is the content area. This is the content area. </p> </div><!-- end content --> </div><!-- end content-frame --> </div><!-- end right-frame --> <div class="clearFloats"></div> </div><!-- end main --></div><!-- end main-frame --> <? include("common/footer.php"); ?> </body> </html> Any help would be greatly appreciated. I have spent many hours on this. Regards Hi folks, I'm curious if I can for example, save a file from my server and it will save to all other servers - obviously if they accepted the connection first. It's for a software I developed and is almost complete and know there will be frequent updates to it. Instead of users downloading upates, I want the update files from my server to somehow synchronize to their server automatically? Anything called this?? Thanks for info. Following a tutorial on udemy, i tried to learn the very basics of mvc structure. I built the same project on my local server and it worked without giving me any error. but when i tried it on live server. its not working as it should. not showing any error. I tried to figure out the problem and found that for every page loading, it stops at the same line in my main.php file. <?php require($view); ?> starting from the above line. it stops. i came here to share my problem but i am unable to upload my files here. if there is a way to upload and share my files, please guide. zip file size of the whole project is 31.6 kb This isn't exactly an application design question, but rather a system design one.
I am about to install an Inventory Control System inside this store I work in.
The store itself also owns a Linode VPS running Centos 6.4 which hosts our website.
This new Inventory System will come built in with a Microsoft SQL Server, and supposedly it is a SQL Anywhere database, but I'm not too sure what that means.
I need to make this database publicly accessible, but only via the Linode VPS. Surely, setting restrictions is easy enough to address that issue. That isn't my question.
My first idea is to put this server into the DMZ, easy. But it doesn't exactly sound safe. So my next idea was to put a middleman server in the DMZ, this way the Linode can send queries to that middleman server and it will send that data to the SQL Server and back. This is very vaguely described I know, but I don't want to get too much into details, but rather, understand how I can create that middleman server, and what could Install onto it that would allow me to securely process queries?
My first thought was to install a webservice, that accepts an XML/JSON request and returns an XML/JSON response.
Then, I realized directly afterwards that I don't have any experience setting up a webservice like that.
What kind of options are there out there? Ultimately, my question is, should I just put the Server in the DMZ or should I create the middleman, and if so, can someone point me in the right direction as to getting a webservice set up? Edited by Zane, 15 July 2014 - 11:28 PM. Problem: I'm trying to make it so the array responds to the integer of status in the database. So, to check if it's one, I try this: $get["status"]["1"] = "Message here..."; But, on my result, I'm just getting WWTT - And the value in the database for the ticket is 0. I'm not sure if I'm using the array correctly. My full code: <?php session_start(); include("../includes/mysql.php"); include("../includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <link href="../style.css" rel="stylesheet" type="text/css" /> <title><?php echo $title; ?></title> </head> <body> <div id="container"> <div id="content"> <div id="left"> <div class="menu"> <?php include("../includes/navigation.php"); ?> <div class="menufooter"></div> </div> <?php include("../includes/menu.php"); ?> </div> <div id="middle"> <?php $existing = $_POST['existing']; $query = mysql_query("SELECT COUNT(id),id,status,date,question,title FROM tickets WHERE id='$existing'"); $get = mysql_fetch_assoc($query); if(!$existing) { echo ' <div class="post"> <div class="postheader"><h1>Error</h1></div> <div class="postcontent"> <p>You have not enetered in a ticket ID. Please go back and do so.</p> </div> <div class="postfooter"></div> </div> '; } elseif($get['COUNT(id)'] < 1) { echo ' <div class="post"> <div class="postheader"><h1>Error</h1></div> <div class="postcontent"> <p>The ticket ID you are trying to use doesnt exist. Please go back or submit another ticket.</p> </div> <div class="postfooter"></div> </div> '; } else { $get["status"]["0"] = "Waiting for support..."; $get["status"]["1"] = "Waiting for user..."; $get["status"]["2"] = "Ticket Closed..."; $get["status"]["3"] = "Ticket Opened..."; echo ' <div class="post"> <div class="postheader"><h1>View Ticket Status - ID '. $get["id"] .'</h1></div> <div class="postcontent"> <p>Title: '. $get["title"] .' - Posted on: '. $get["date"] .'</p> <p>Ticket Status: '. $get["status"] .'</p> <p>Question: '. nl2br($get["question"]) .'</p> </div> <div class="postfooter"></div> </div> '; } ?> </div> </div> </div> </body> </html> Hello, I have a webpage that runs some php code to control electrical devices. One part of it controls outside lights. Another part controls an electric door striker. I keep expanding the functionality of it and need to change one pin of the port without affecting the others. So far I use a different port for each function but I am out of ports so I need to use the different pins of the parallel port. I am using a linux ubuntu server. From my php webpage I issue this command: <?php exec("/home/setSerialSignal /dev/ttyS0 0 0"); ?> which controls the lights using the serial port. I can control 2 pins but I can't check the status of them so if I make a change to one pin it cancels the other. For another one I use the parallel port with this command: <?php exec("/home/parashell 0x378 1"); ?> which turns on pin #2 of the parallel port. Parashell has an executable called "pin". If you type the command "pin 0x378" it will return a value for the status of the parallel port. "1" for example which tells me that pin #2 is on. Is there a way to pass this value to a php variable? I am looking to be able to read the status of the port and make changes to just the pin I want. Lets say pin #2 is on and I want to turn pin #3 on. I would have to issue <?php exec("/home/parashell 0x378 2"); ?> to turn pin #3 on, but that would turn off pin #2. If I could pass the "1" from the "pin" command I could add it to the "2" and give it the command with a variable as "3". Thanks in advance for any help you can give. I hope I explained it ok and didn't confuse everyone. Okay I now have a working extract ZIP archive script. What I am now looking to do is have a loop which checks the percentage complete the extraction is and at 100% (with no erros) carry out a PHP function. The code so far is (and includes comments on how the new function would be placed): $dir = opendir('temp'); while(false !==($file=readdir($dir))){ if(strpos($file, '.zip',1)){ extractupdate($file); } } function extractupdate($file){ $zip=new ZipArchive; if($zip->open('temp/'.$file) == TRUE){ $update=rtrim($file, ".zip"); $zip->extractTo($_SERVER['DOCUMENT_ROOT']."/update/temp/$update"); $zip->close(); echo "Extraction started."; // Place loop here to run untill 100% extraction completed and then run function "intsallupdate($update);" } else { echo "Failed to start extraction."; } } function installupdate($update){ // installupdate() will now shift the files around as necessary. // NB to PHPFREAKS, no assistance with code for installupdate() is required, only the loop. Cheers. } Many thanks in advance. |
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