PHP - Trouble Appending File
Hi,
I have the following code which allows a user to enter a name for a mysql column field. Once they have submitted the form they are then redirected back to the form which allows them to enter the name for another mysql column form. When they are returned to the form, I would like the new column field added to the file named userinfo.php The problem is, I need the column field variable entered into the userinfo.php in the following format $newcolumn = $info['newcolumn'] but when I put it like this $stringData = "$newcolumn = $info['newcolumn']"; I get this error Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in /home/tropicsb/public_html/MemberSiteMaker/admin.php on line 398 Code: [Select] // Profile and Application details case "profileFields": session_start(); if(isset($_SESSION['username'])) { $newcolumn = $_GET['newcolumn']; $file = "lib/userinfo.php"; $fh = fopen($file, 'a') or die ("Cant open file"); $stringData = "$newcolumn = $info['newcolumn']"; fwrite($fh, $stringData); fclose($fh); echo "This is the logged in page\n<br>"; ECHO <<<PAGE <form action=admin.php?cmd=addfield&username=admin method=POST> <input type=text name=newcolumn> <input type=submit name=submit> PAGE; } else { echo "This is a failed login"; } break; case "addfield": include_once("data/mysql.php"); $newcolumn = $_POST['newcolumn']; $mysqlPassword = (base64_decode($mysqlpword)); $con = mysql_connect("$localhost", "$mysqlusername", "$mysqlPassword") or die(mysql_error()); mysql_select_db("$dbname", $con) or die(mysql_error()); $result=mysql_query("ALTER TABLE members ADD $newcolumn VARCHAR(30) AFTER approved") or die("Alter Error: ".mysql_error()); mysql_close($con); echo "Database has been modified successfully."; echo '<meta http-equiv="REFRESH" content="5;url=admin.php?cmd=profileFields&username=admin&$newcolumn">'; break; thanks Similar TutorialsHello everybody! Keep in mind I'm new to PHP but get the basics I'm trying to collect email addresses from a web-form that gets filled out on a website into a simple txt file on the server. The problem is the emails get appended one right after the other with no spaces so it looks like "user@server.comuser2@server.comuser3@server.com" and so on. What I'm trying to do is either separate them by a comma, or put them on a new line but whatever I try, it will not accept it. Anyway, here is the code that I have: Code: [Select] $fp = fopen("/home/fullertr/public_html/email_collector.txt","a"); fwrite($fp,$_POST['visitormail' . "\n"]); fclose($fp); unset($_POST); Thanks for any help! can someone give me a push here? I've tried "file_put_contents" and "fputs" and neither one works for me. I'm running PHP on an IIS server and a windows hosting plan. PHP version is 7.3.1 I believe. here is my code: if ($validation = "true") { file_put_contents("ValidationsRedeemed.txt", $validationKey . "|", FILE_APPEND); //$handle = fopen("ValidationsRedeemed.txt", "a"); //fwrite($handle, $validationKey . "|"); //fclose ($handle); } else { //user entered a product key that is not recognized. tell them to try again. echo "<script>alert('The product key entered is not valid.'+'\\n\\n'+'Please try again.'); window.location.href='test.php';</script>"; } thanks! hello. im having trouble getting my images to show my navigation (which i downloaded from http://www.dynamicdrive.com/dynamicindex17/ddaccordionmenu.htm) im pulling in the navigation dynamically. i can get it to show the navigation and css but not the images its quite a long destination url... if i put this code on the ddAccordian.php page it works Code: [Select] <link href="http://localhost:8888/djsonrotation/admin/pages/contElements/Navigation/Vertical/ddAccordion/css/styles.css" rel="stylesheet" type="text/css" /> if i try and shorten the url like below the css works but i get no images Code: [Select] <?PHP require_once("../includes/initialize.php"); ?> <style type="text/css" rel="stylesheet"> <?php include(NAVIGATION.DS."styles.css"); ?> </style> the Quote include(NAVIGATION.... is being created in my initialize file Code: [Select] defined('NAVIGATION') ? null : define('NAVIGATION', $_SERVER['DOCUMENT_ROOT'].DS.'djsonrotation'.DS.'admin'.DS.'pages'.DS.'contElements'.DS.'Navigation'.DS.'Vertical'.DS.'ddAccordion'.DS.'css'); in my css file i have tried all of these (1 at a time) but none work: Code: [Select] background: black url(titlebar.png) repeat-x center left; background: black url(/titlebar.png) repeat-x center left; background: black url(./titlebar.png) repeat-x center left; background: black url(../titlebar.png) repeat-x center left; background: black url(images/titlebar.png) repeat-x center left; background: black url(/images/titlebar.png) repeat-x center left; background: black url(./images/titlebar.png) repeat-x center left; background: black url(../images/titlebar.png) repeat-x center left; my folders are like this /ddAccordion/css/styles.css /ddAccordion/images/ /ddAccordion/js/ /ddAccordion/ddAccordion.php any thoughts. thanks ricky hello, i cant see why my navigation file path is not working im working on my localhost: http://localhost:8888/djsonrotation my initialize file is located at http://localhost:8888/djsonrotation/includes/initialize.php my navigation code is located at http://localhost:8888/djsonrotation/pages/pageContent/navigation/ddAccordion.php my js is located at http://localhost:8888/djsonrotation/js/ddaccordion.js if i put these on my ddAccordion.php it works Code: [Select] to find my initialize file <?PHP require_once("../../../includes/initialize.php"); ?> to find my js file <script type="text/javascript" src="../../../js/ddaccordion.js"> this is how my initialize file looks Code: [Select] <?PHP defined('DS') ? null : define('DS', DIRECTORY_SEPARATOR); defined('SITE_DOMAIN') ? null : define('SITE_DOMAIN', 'http://localhost/djsonrotation'); defined('SITE_ROOT') ? null : define('SITE_ROOT', $_SERVER['DOCUMENT_ROOT'].DS.'djsonrotation'); defined('LIB_PATH') ? null : define('LIB_PATH', SITE_ROOT.DS.'includes'); defined('ELEMENTS') ? null : define('ELEMENTS', $_SERVER['DOCUMENT_ROOT'].DS.'djsonrotation'.DS.'pages'.DS.'contElements'); the problem is i can't seem to change ../../../ in to a file path like this does not work Code: [Select] <?PHP require_once(include(LIB_PATH.DS."initialize.php")); ?> i tried a couple of different file paths for my js file but they dont work either Code: [Select] <script type="text/javascript" src="<?php include(SITE_DOMAIN.DS."js".DS."ddaccordion.js"); ?>"> or Code: [Select] <script type="text/javascript" src="<?php include(SITE_ROOT.DS."js".DS."ddaccordion.js"); ?>"> i guess i could just use ../../../ but why are the include paths not working ???? thanks I'm new to the PHP world and trying to work my way through a problem. I've gone down many roads, but can't seem to find the answer. I'm not even sure this is so much a PHP question at this point as a host configuration issue. I'm trying to grab an XML file from a remote server. My first try was to try to shell out a wget as follows: exec("wget -q -O status.xml - http://$username:$password@$hostname:$port/cgi-bin/status.xml",$xmlget,$err); This didn't work. Not a surprise since doing it directly from SSH gave: Connecting to mydomain.com|99.99.99.99|:8080... failed: Connection refused. [Note that the port 8080 above is, I think, key] I've since tried method using both file_get_contents and cURL. Similar results for all. I won't clutter this up with the code unless you ask. It's all very straightforward. [file_get_contents complains 'Connection refused' and curl_error says 'couldn't connect to host']. With all of the methods, I'm able to grab, say, google.com AND a page from mydomain.com (default port 80), just not from port 8080. I've set 'allow_url_fopen = on' in php.ini and in my code for good measure. Also, the XML file that lives at 8080 is retrieved fine through a browser. I'm hosted at GoDaddy on their "deluxe shared linux" plan. Is there something obvious I'm missing that would allow all this to work over port 80, but not 8080? Thanks is advance! Greg Hi everyone! Nice to meet/see/read you. This is my first post and it will probably be a lame one so apologies. I'm a pretty good frontend designer and I've always struggled to learn PHP and my new job is forcing it on me so I'm happy in a "throw me in the deep end" kinda way. I am really stuck! I have a single page that is using jquery to scroll my content left and right via the menu (example attached). What I am trying to do is when on the homepage, don't show the "main logo". When on any other link, show it. I immediately thought of an if/else statement but realised I don't know what or how exactly to target since everything is on the same page and the URL doesn't change. Could I target the image title that is the only image on the homepage? So, something like: <?PHP $image_title = 'home'; if (XXXXX($image_title)) { echo "IMAGE"; } else { echo "NO IMAGE"; } ?> I know that's wrong, I put XXX where I feel like something possibly helpful should go. Heh. I'm not asking for someone to write code for me, I'm happy to learn but but I would be very grateful if someone could just guide me to what I need to do and off to Google I will go. I haven't been able to find anything that is like: "if image title equals". Hmm... I hope I can do this with PHP. Thanks again, Linda Trying to a. check if dir exists if not create it, and b. save an uploaded file to that directory. Nothing however is working but I'm pulling no errors, heres the code: $test_pic = $_POST['test_pic']; // I've also tried $test_pic = $_FILES["test_pic"]; : with no success if (is_uploaded_file($test_pic)) { if (!file_exists("tests/uploads/" . $test_name . "/")) { $create_test_folder = (mkdir("tests/uploads/" . $test_name)); if (!$create_test_folder) { echo "cant create folder"; die; } } $target_path = ("tests/uploads/" . $test_name . "/" . $test_name . "_1"); if (($_FILES["test_pic"]["type"] == "image/gif") || ($_FILES["test_pic"]["type"] == "image/jpeg") || ($_FILES["test_pic"]["type"] == "image/jpg") || ($_FILES["test_pic"]["type"] == "image/png") && ($_FILES["test_pic"]["size"] < 50000)) { if (!copy($test_pic, $target_path)) { echo "cant copy picture"; die; } } else { echo "file type or size bad"; die; } } and I understand its not at all public-safe but I'm just wanting to get it to work before I throw in the security. Thanks for the help! Hey guys, I have a script that grabs data from a separate .txt file which is used to perform certain actions within a user's account. The data I'm having trouble with is user key which is used to authenticate an http header. An example of what the txt file would hold is this: 360235276 PbI1c5+PGHSshccYd58AklmTgf5u+tbWZplMRYYxFSivRYw4AZhaVNHwADozYZhZhPnXRSV1rmsrhf1td7w6bJbySZmPHLl+hleyz/Ht4iM= 477947328 cXTnFEVP74RWtAgqM5BlwtgW2i9rP/v44oANzwF+yJZ+9mpvaschyo/HaYP1qUXgIK8nK7jy74iSCEHAgpPgPdryzpReM5cbnVDjRw7h9S0= 503724987 XXEJsklZTFaTx8MLjuNIz0S65Sn02rgbHl2sahdReQdadKP39 evIXUoYdr5NyQMWDVE7cRpvn+zJ7mteH7WJzVh0U/sOcSG7kfcuaWpAOfo= The format I have is: account_ID user_key New account on a fresh line. So in my script I have it grabbing the data as so: $User_DataFile = "accountdata.txt"; $AccData = file($User_DataFile, FILE_SKIP_EMPTY_LINES); foreach($AccData as $line_num => $line) { $AccData = explode(" ", htmlspecialchars(str_replace(" "," ",$line))); if(stristr($AccData[1], "\n")) $AccData[1] = substr($AccData[1], 0, strlen($AccData[1])-2); $AccountID = $AccData[0]; $UserKey = $AccData[1]; echo "Account ID: ".$AccountID."<br/>User Key: ".$UserKey."<br/><br/>"; I have it set to simply echo out the data for debugging which is where I noticed that any slashes or plus or equal signs were not included. When run in Apache it returns this: Account ID: 360235276 User Key: PbI1c5+PGHSshccYd58AklmTgf5u+tbWZplMRYYxFSivRYw4AZhaVNHwADozYZhZhPnXRSV1rmsrhf1td7w6bJbySZmPHLl+hleyz/Ht4iM Account ID: 477947328 User Key: cXTnFEVP74RWtAgqM5BlwtgW2i9rP/v44oANzwF+yJZ+9mpvaschyo/HaYP1qUXgIK8nK7jy74iSCEHAgpPgPdryzpReM5cbnVDjRw7h9S0 Account ID: 503724987 User Key: XXEJsklZTFaTx8MLjuNIz0S65Sn02rgbHl2sahdReQdadKP39 evIXUoYdr5NyQMWDVE7cRpvn+zJ7mteH7WJzVh0U/sOcSG7kfcuaWpAOfo So as you can see by comparison there is no slashes or plus or equal signs present, which is going to be a major problem. Is there any way of getting around this problem? Thanks. Hello fellow developers, Let me start by saying I'm still a PHP noob so please don't go too hard on me if I my code reflects this noobishness... So I'm trying to build a (very) simple RSS reader using jQuery and PHP. When the user clicks on an option from a dropdown, an AJAX call is made and passes the url selected from the list to a PHP script. The PHP script then loads the appropriate xml file from an 'xmlcache' folder. Everything is working just fine for files named as such: somefilename_1231231231.xml The problem is that I need it to be able to load files which have been urlencoded such as: http%3A%2F%2Ffeeds.feedburner.com%2Fajaxian_1235523548 In case you're wondering, the numbers at the end are a timestamp which will determine if the reader will load a cached copy of the desired xml file (if it's less than an hour old) or if it needs to get a fresh version (this part of the code is not written yet). Here is a look at my script thus far: <?php $url = "./xmlcache/" . urlencode($_REQUEST['url']); //access url from AJAX call echo $url; //outputs -> "./xmlcache/http%3A%2F%2Ffeeds.feedburner.com%2Fajaxian_1235523548.xml", which is the same as the file's name $curTime = time(); $urlParts = explode('_', $url); $urlTime = intval($urlParts[1]); $diff = $curTime - $urlTime; $urlAge = 60 * 60; //60sec * 60min = 3600sec or 1 hour if(file_exists($url)){ if($diff > $urlAge){ //the > will be switched to < to make logical sense once testing is done. $xml = simplexml_load_file($url); //ROOT TAG foreach($xml as $key0 => $value){ echo "$key0: $value"; foreach($value->attributes() as $attributeskey0 => $attributesvalue1){ echo "$attributeskey0: $attributesvalue1"; } echo "<br />"; //1 LEVEL BELOW ROOT TAG foreach($value as $key => $value2){ echo "$key: $value2"; foreach($value2->attributes() as $attributeskey => $attributesvalue2){ echo "$attributeskey = $attributesvalue2"; } echo '<br />'; //2 LEVELS BELOW ROOT TAG foreach($value2 as $key2 => $value3){ echo "$key2: $value3"; foreach($value3->attributes() as $attributeskey2 => $attributesvalue3){ echo "$attributeskey2 = $attributesvalue3"; } echo '<br />'; //3 LEVELS BELOW ROOT TAG foreach($value3 as $key3 => $value4){ echo "$key3: $value4"; foreach($value4->attributes() as $attributeskey3 => $attributesvalue4){ echo "$attributeskey3 = $attributesvalue4"; } echo '<br />'; //4 LEVELS BELOW ROOT TAG foreach($value4 as $key4 => $value5){ echo "$key4: $value5"; foreach($value5->attributes() as $attributeskey4 => $attributesvalue5){ echo "$attributeskey4 = $attributesvalue5"; } echo '<br />'; //5 LEVELS BELOW ROOT TAG foreach($value5 as $key5 => $value6){ echo "$key5: $value6"; foreach($value6->attributes() as $attributeskey5 => $attributesvalue6){ echo "$attributeskey5 = $attributesvalue6"; } echo '<br />'; } } } } echo '<br />'; } echo '<br />'; } }else{ //need to create the XML file from scratch, do a curl function, or read from a text file echo "need a new version"; //@unlink("$url); } }else{ echo "That file does not exist.<br/>"; } ?> The error message I'm getting is this: Warning: simplexml_load_file() [function.simplexml-load-file]: I/O warning : failed to load external entity "./xmlcache/http%3A%2F%2Ffeeds.feedburner.com%2Fajaxian_1235523548.xml" in C:\wamp\www\reader\loadfeed.php on line 13 Warning: Invalid argument supplied for foreach() in C:\wamp\www\reader\loadfeed.php on line 16 The second error is obviously thrown because the file doesn't get loaded. I appreciate any help you gurus have to offer, and if you have any suggestions for the best way to load a fresh version that will be handled by the first else statement, I'm all ears. Thanks guys! I am very new to php and am trying to create a simple application that uploads a PDF file to a database. I have one field for the Volume Number and on file field for the PDF to be uploaded. My issue is i can't get the PDF to upload or insert the name of the pdf (eg volume1.pdf) into the data base. I would also like to point out that I know i have a low post count, but i only seek help when i truly need it and have exhausted all other resources... Here is what i have, please go easy on me this is my first round at php: Code: [Select] <?php if(isset($_POST['submit'])){ $vol_num = $_POST['vol_num']; $pdf = $_FILES['pdf']['name']; $path = '../pdf/'.$_FILES['pdf']['name']; move_uploaded_file($_FILES["pdf"]["tmp_name"], $path); mysql_query("INSERT INTO volumes set vol_num='$vol_num', vol_link='$pdf'") or die (mysql_error()); echo "<script>location.href='add_volume.php'</script>"; } ?> what am i doing wrong here? Thanks in advance Hi. So I've coded many a file upload form and never had any trouble. Until now. For some reason when I try to upload MP3 files, I'll hit submit and the page just reloads. Once it does so, the file upload field is once again blank. What's odd is that images and documents upload just fine. It's only audio tracks that cause the page to reload and clear. My php.ini max file upload size is at this point set to 100M, and the files I'm trying to upload are under 10M. Any ideas? Here's the form code, just to post it-- pretty basic. I'm at a loss here.... Any ideas would be appreciated. Thanks very much. <form action="test.php" enctype="multipart/form-data" method="POST"/> <input type = "file" name = "audio" /> <p><input type ="submit" name="submit" value="do it."/><p> </form> I am trying to append data to a variable through each loop of a MySQL array, but I am doing it wrong. Is this possible? Here is the code. $html = <<<TABLE <table border = "1" align = "center"> TABLE; //// Get Endorsement Info $endo = mysql_query("SELECT * FROM endorse WHERE endonum = '$endonum' AND agency = '$agency' ORDER BY ID DESC LIMIT 1"); while($endofetch = mysql_fetch_array($endo)){ $endotype = $endofetch['type']; $typeid = $endofetch['typeid']; $change = $endofetch['changetype']; $info = mysql_query("SELECT * FROM $endotype WHERE ID = '$typeid'") or die(mysql_error()); $infoout = mysql_fetch_array($info); $date = date("m/d/Y g:i a", strtotime($endofetch['date'])); if($endotype == "drivers"){ $firstname = $infoout['firstname']; $lastname = $infoout['lastname']; $licnum = $infoout['driverslic']; $vyear = $infoout['year']; $vmake = $infoout['make']; $vmodel = $infoout['model']; $vvin = $infoout['year']; $html .= <<<TABLE <tr> <td>Endorsement Request Date:</td><td>{$date}</td> </tr> <tr> <td>Change Requested:</td><td>{$change} Driver</td> </tr> <tr> <td>Driver Info:</td><td>{$firstname} {$lastname} </td> </tr> <tr> <td>License Number:</td><td>{$licnum}</td> </tr> <tr> <td>Signature __________________</td><td>Date:_____________</td> </tr> TABLE; } if($endotype == "vehicles"){ if($change == "Delete"){ $veyear = $endofetch['year']; $vemake = $endofetch['make']; $vemodel = $endofetch['model']; $vevin = $endofetch['vin']; $html .= <<<TABLE <tr> <td>Endorsement Request Date:</td><td>{$date}</td> </tr> <tr> <td>Change Requested:</td><td>Delete Vehicle</td> </tr> <tr> <td>Vehicle Info:</td> </tr> <tr> <td>Year:</td><td>{$veyear}</td><td>Make:</td><td>{$vemake}</td><td>Model:</td><td>{$vemodel}</td> </tr> <tr> <td>Vin Number:</td><td>{$vevin}</td> </tr> <tr> <td>Signature __________________</td><td>Date:_____________</td> </tr> TABLE; } else { $html .= <<<TABLE <tr> <td>Endorsement Request Date:</td><td>{$date}</td> </tr> <tr> <td>Change Requested:</td><td>{$change} Vehicle</td> </tr> <tr> <td>Vehicle Info:</td> </tr> <tr> <td>Year:</td><td>{$vyear}</td><td>Make:</td><td>{$vmake}</td><td>Model:</td><td>{$vmodel}</td> </tr> <tr> <td>Vin Number:</td><td>{$vvin}</td> </tr> <tr> <td>Signature __________________</td><td>Date:_____________</td> </tr> TABLE; } } } $html .= <<<TABLE </table> TABLE; echo $html; This code is for creating a PDF with fpdf and a third party table class. Its only displaying the last table data in the loop when I echo $html so the data is being overwritten each loop. Hi! Thank you in advance for the time and assistance. I am writing a form and some php code that writes to a text file. I have that accomplished. My issue is that my form that writes to the text file appends to the bottom of the text file and I need it reversed. The latest form entry needs to be on top... and then the older posts to follow. I have tried the w+ r+ and c+ but that is not doing it. Is there something that I am missing? I appreciate the assistance! Mike Hi Guys Again, another noob question that I can't seem to find a concise answer to. What is the best way to append a query string to a url? I've tried using the Header() function but this didn't seem to work - i.e. Code: [Select] Header("Location: enc.php?ID=test"); My goal is to change the query string depending on the output of various if else statements. For instance if $test isset then execute some code. The script will be self contained so it'll be posting back to itself with the query string and reacting differently depending on the query string. Any ideas? PS sorry if i am asking too many questions. Eager to learn and struggling to find answers to some things. What I basically want to do (and not sure if this is possible) is to append a different query string based on Hey guys This is the first loop i have attempted on my own, so please tell me if ive done something completely stupid.. What happens is the suer specifies a number of thumbnails on the previous page, these are posted to the form and then that amount of thumbnails should be displayed. Heres what i have so far $cd = 0; while ($cd < $numberofthumbnails) { $displaythumbs . '<div class="ThumbnailHolder"> <div class="LeftThumb"><a class="group" href="../../../Images/Lighthouses/Beachy-Head/1.png"><img src="../../../Images/Lighthouses/Beachy-Head/Mini/Thumbnail-1.png" width="430" height="200" alt="Thumbnail 1"></a></div> <div class="RightThumb"><a class="group" href="../../../Images/Lighthouses/Beachy-Head/2.png"><img src="../../../Images/Lighthouses/Beachy-Head/Mini/Thumbnail-2.png" width="430" height="200" alt="Thumbnail 2"></a></div></div> '; $cd++; } Essentially what im trying to do is as thumbnail code to $displaythumbs for each time the loop goes round. What am i doing wrong? Thanks Danny. Hi all I am trying to loop through an array and output as JSON. What I'm looking to do is create something like: Code: [Select] "something": [ {"title":"Test 1"}, {"title":"Test 2"} ], Notice that the final row has no comma. My code is as follows: <?php foreach($something as $thing): ?> <?php $something_array = array('title'=>$thingt->getId()); ?> <?php echo json_encode($something_array).','."\n"; ?> <?php endforeach; ?> I had to add a comma to the end of the array, or the JSON rows would not be ended with one. How can I get it so that, no matter how many items are in the array, the last row, wil not have the comma at the end? With the comma at the end, my JSON doesn't validate Thanks [/code] I have an array of $fl By using values of this array, i want to create a new string. I need string size will be maximum 200 characters. When i try below code snipped, $f value is added to string two times. How can i add $f to array only one time, with checking size of string. Thank you Code: [Select] $fl=getsomelist(); // gives an array $userList=''; foreach ($fl as $f) { if ( strlen($userList .= $f) <= (200) ) { $userList .= $f; } else { break; } } Hello. I'm trying to append the loop keys and values into a string and store it into a hidden field. This is the code I have : Code: [Select] if (isset($_POST['ordered'])) { // We can assign $_POST['product'] to a variable to make it easier to type out $prod = $_POST['product']; // Throw a little intro to see how many they checked echo 'You selected ' , count($_POST['ordered']) , ' products.'; // Now we loop through it and get the IDS that were selected // Foreach lets you select the $key and the $value for each iteration of the loop // $strOrder = ""; foreach ($_POST['ordered'] as $key=>$id) { echo '<p/> ProdName: ' , $prod[$id]['name'] , '<br/> ProdPrice: ' , $prod[$id]['price'] , '<br/> ProdQty: ' , $prod[$id]['qty'] , ' <hr/>'; $strOrder .= $key . " " . $id; $TOT += $prod[$id]['price'] * $prod[$id]['qty']; } $TOT2 = $TOT + 55; echo '<input type="hidden" Name="TOT" value ="'. $TOT .'">'; echo '<input type="hidden" name="TOT2" value =". $TOT2 .'">'; echo '<input type="hidden" name="Order" value=". $strOrder . '">'; } strOrder does not get set to a value. Hi,
what I'm tryng is to append a table row with associated jquery code...
I have a jquery code just like this
<script type="text/javascript"> jQuery(function($) { var rowCtr = 0; $('.addRow').click(function(){ $('#tableID > tbody:last').append('<tr name="rowEq['+rowCtr+']" id="rowEq['+rowCtr+']"><td>'+ '<select id="stype'+rowCtr+'" name="rowData['+rowCtr+'][equipment_type]">'+ '<option value="0"> -- </option>'+ '<option value="1"> Type 1 </option>'+ '<option value="2"> Type 2 </option>'+ '<option value="3"> Other </option>'+ '</select>'+ '<input id="other_type'+rowCtr+'" type="text" name="rowData['+rowCtr+'][other_type]">'+ ); $('#stype'+rowCtr).change(function() { if(jQuery('#stype'+rowCtr).val() == '3') { jQuery('#other_type'+rowCtr).show(); }else{ jQuery('#other_type'+rowCtr).hide(); } }); if(jQuery( '#stype'+rowCtr ).val() != '3') { jQuery('#other_type'+rowCtr).hide(); } rowCtr++; }); }); </script>And html like this.. <input type='button' class='addRow' value="Add Row"> <form> <table id="tableId"> <thead> <tr> <th> Type </th> </tr> </thead> <tbody> <tr> <td> dummy text.. </td> </tr> </tbody> </table> </form>The appending is ok but the hidding/showing of "other_type" field is not working. It always hide "other_type" field even if I already selected the 'other' option. tbl1.png 3.38KB 0 downloads |