|
PHP - Loading Another Form After Clicking A Radio Button..
Hi i am working one of my assignment for school.. i just studied php..
my problem is, is it possible to load another form once i clicked a radio button? if its a yes... can you teach me how to do that? thank you! Similar TutorialsDear All I have a form say i have selected Volva from drop down box . So without clicking on submit button when i move to next field that is `<input>` the value that is volva should get store in php variable <html> <body> <form action=""> <select name="cars"> <option value="volvo">Volvo</option> <option value="saab">Saab</option> <option value="fiat">Fiat</option> <option value="audi">Audi</option> </select> <input type="text" name="abc" /> </form> </body> </html> Hi people,
I'm new to PHP, and I'm having some real difficulties with trying to re-populate a radio button selection on a form.
Basically, I'm working on a WordPress plugin which uses custom fields to create a Bet custom post type.
I need to have my form submit the user input, then re-populate it so that if the user wants to edit and update the Bet data, they don't have to fill in the whole form details again, they can just edit what they need to, and update (re-submit) the form.
I've managed to get all of the form elements re-populating, apart from a radio button. I've been trawling round the internet for most of yesterday evening and this morning, trying different things, but nothing I've found works for me.
I'd really appreciate some help if anyone knows how to do this.
Here's my code so far (non working)
<?php Just a quick help here... When you click click this radio button. <input type="radio" name="radio" id="radio_id_card" /> ID Card it will open the form below the radio button. <form> First Name: <input type="text" name="textfield" id="textfield" /> Last Name: <input type="text" name="textfield" id="textfield" /> <input type="submit" id="Send" value="Submit" /> </form> ------------------------------- hope someone can help me... i really have a bad time thinking of ways to do it.. thank you in advance.. hi, I would like to know how do i modify this code if i Have more than 1 option in my dropdown list. Can someone help..Thankz <select name="mediaList" id="mediaList"> <option <?php echo ($rows['media_type'] =='Physical Only')?'selected="Selected"':'';?> >Physical Only</option> </select> I'm developing a form which is essentially a simple set of radio buttons. Conceptually, it is like this:
Please select a theme from the list:
o Black
o Blue
o Red
[Submit] [Reset]
I'm actually showing a slideshow of images showing the appearance of each of the themes in a slideshow that only shows one image at a time. I want my users to click on the image that represents the theme they want and, ideally, not have to click on the Submit button at all.
Then I will save the name of the theme they chose in a cookie (if cookies are enabled).
Many years ago, I dabbled in things like CGI and I have a vague recollection, possibly faulty, that it's not difficult to make a form that has only one set of radio buttons treat the selection of one of the radio buttons as a Submit. I don't remember how to do it though.
Can anyone advise me on whether it is indeed possible and, if it is, how I make the selection of the radio button cause the form to be submitted?
Im displaying the results of a database by using a while loop... so Im trying to figure out how to delete some entries from the datbase. What I wanted to do is add a button in each result that will have the value "delete"... but I cant figure out how to do this. Im kinda new to mysql. I just want it so when I click the button the result will get deleted from the database. I did some research on this but I cant really grasp the examples. Can anybody help me out with this one? Thanks! So, I just don't know where to post this question. I've written a quiz program where 50 English vocab words are pulled from a dB and displayed on one page with the order scrambled. My students then type the Spanish translation for each. When they submit the form the next page grades their work. They have to get a 90 or better for the grade to be automatically recorded, so I want them to click the back button and go back and make corrections. The problem is when they use a Chrome browser and click the back button the program re-sorts the order of questions. It leaves the order of their answers the same. So what they answered for number 1 is still in the field for number 1, but the questions (the English vocab word) is different. Chrome does this consistently so I thought this was a Chrome issue only. Then one of my students said the same thing happened to her when using Safari. So here is my question, how can I stop Chrome (or any other browser) from re-running my server-side PHP scripts (re-sorting the vocab array) when clicking the back button?
Here is the code for students taking the quiz:
<form method="post" action="portal.php?load=vquiz_grade" style="margin-left: 50px; line-height: 30px;">
$max = $count-1;
?>
//print "<br>";
<input type="hidden" name="max" value="<?print $max?>"> And here is the code showing them what they missed.
<?
// Total grade
print "You missed ".$wcount." words.<br>";
print "<table>";
// Grade response and set color
if ($wrong == 1){ if ($grade >= 90){
$query = "SELECT * FROM inno_vocab_assignments WHERE key_code = '$key_code' AND uname = '$secure_uname' AND teacher = '$teacher'";
// Prevent student from changing vocab list so as to do an easier list
// Insert grade
}
Thank you!
Folks,
Look at this weird thing. I load the page and get echoed as expected: Did Not REQUEST_METHOD! Then, I click the SUBMIT button and to my astonishment I get echoed: Did Not POST->Submit! Got 2 buttons. Same result whenever clicking any. Why is that ? Check it out:
<?php
//include('error_reporting.php');
ini_set('error_reporting',E_ALL);//Same as: error_reporting(E_ALL);
ini_set('display_errors','1');
ini_set('display_startup_errors','1');
?>
<form name = "submit" method = "POST" action="">
<label for="domain">Domain:</label>
<input type="text" name="domain" id="domain" placeholder="Input Domain">
<br>
<label for="domain_email">Domain Email:</label>
<input type="email" name="domain_email" id="domain_email" placeholder="Input Domain Email">
<br>
<label for="url">Url:</label>
<input type="url" name="url" id="url" placeholder="Input Url">
<br>
<label for="link_anchor_text">Link Anchor Text:</label>
<input type="text" name="link_anchor_text" id="link_anchor_text" placeholder="Input Link Anchor Text">
<br>
<textarea rows="10" cols="20">Page Description</textarea>
<br>
<label for="keywords">Keywords:</label>
<input type="text" name="keywords" id="keywords" placeholder="Input Keywords related to Page">
<br>
<input type="checkbox" name="alert_visitor_type" id="alert_visitor_type" value="Give Alert: Visitor Type">
</label for="alert_visitor_type">Give Alert: Visitor Type</lablel>
<input type="checkbox" name="alert_visitor_potential" id="alert_visitor_potential" value="Give Alert: Potential Visitor">
</label for="alert_visitor_potential">Give Alert: Potential Visitor</lablel>
<br>
<input type="radio" name="tos_agree" id="tos_agree_yes" value="yes">
<label for="tos_agree_yes">Yes:</label>
<input type="radio" name="tos_agree" id="tos_agree_no" value="no">
<label for="tos_agree_no">No:</label>
<br>
<label for="tos_agreement">Agree to TOS or not ?</label>
<select name="tos_agreement" id="tos_agreement">
<option value="yes">Yes</option>
<option value="no">No</option>
</select>
<br>
<button type="submit" value="submit">Submit</button><br>
<button type="submit">Submit</button>
<br>
<input type="reset">
<br>
</form>
<?php
if($_SERVER['REQUEST_METHOD'] === 'POST')
{
if(isset($_POST['submit']))
{
mysqli_report(MYSQLI_REPORT_ALL|MYSQLI_REPORT_STRICT);
mysqli_connect("localhost","root","","test");
$conn->set_charset("utf8mb4");
$query = "INSERT into links (domain,domain_email,url,link_anchor_text,page_description,keywords,alert_visitor_type,alert_visitor_potential) VALUES (?,?,?,?,?,?,?,?)";
$stmt = mysqli_stmt_init($conn);
if(mysqli_stmt_prepare($stmt,$query))
{
mysqli_stmt_bind_param($stmt,'ssssssss',$_POST['domain'],$_POST['domain_email'],$_POST['url'],$_POST['link_anchor_text'],$_POST['page_description'],$_POST['keywords'],$_POST['alert_visitor_type'],$_POST['alert_visitor_potential']);
if(mysqli_stmt_execute($stmt) === FALSE)
{
die("Error\" . mysqli_stmt_error()");
}
mysqli_stmt_close($stmt);
mysqli_close($conn);
}
else
{
die("Did not INSERT!");
}
}
else
{
die("Did Not POST->Submit!");
}
}
else
{
die("Did Not REQUEST_METHOD!");
}
?>
I have a php form in which ,on click of a edit button the contents of that table row will be displayed in a text area (which appears on the click of that edit button).Below the textarear i have a submit and delete button,i can perform any action.Ater performing the save or delete click the text area should be hidden. this is not happening,tried with js also. pasting the code below Code: [Select] <form name='add_title' method='post' action=''><?php echo "<br><br>"; if(isset($_POST['update'])) { if(isset($_GET['id'])) { $id = $_GET['id']; $comments=$_POST['comment']; $query1 = "update comments set comments='$comments' WHERE id = '$id' "; $result = mysql_query($query1); //$row=mysql_fetch_row($result); } } if(isset($_POST['delete'])) { if(isset($_GET['id'])) { $id = $_GET['id']; $comments=$_POST['comment']; $query1 = "delete from comments WHERE id = '$id' "; $result = mysql_query($query1); } } $query="select count(*) from comments"; $result =mysql_query($query); $row=mysql_fetch_row($result); $count= $row[0]; if($count!=0) { $query="select *from comments order by id desc"; $result=mysql_query($query); echo "<table width='700' align='center' border=1><tr bgcolor='green' align='center'><td><font color='black'> SlNo </font></td><td><font color='black'>Comment</font></td><td><font color='black'> Date Posted </font></td><td>Edit/Delete</td></tr></b>"; while($row = mysql_fetch_row($result)) { $d=$row['0']; $id=$row['0']; $name=$row['1']; $date_uploaded=$row['3']; echo "<td>$id</td><td>$name</td>". "<td>$date_uploaded</td>". "<td><a href='edit_comments.php?id=$id'>Edit </a></td>". "</tr>"; } if(isset($_GET['id'])) { $id = $_GET['id']; $query = "SELECT comments FROM comments WHERE id = '$id' "; $result = mysql_query($query); $row=mysql_fetch_row($result); echo"<center><table width='700' border='1'><tr><td > <textarea name='comment' cols='80' rows='10'>$row[0]</textarea> <td></tr><tr><td><a href='edit_comments.php?id=$id'><input type='submit' name='update' id='update' value='Save'></a><a href='edit_comments.php?id=$id'><input type='submit' name='delete' id='delete' value='Delete'></a> </td><td></td></center>"; } echo "</table>"; } else { echo "<table width='700' align='center'><tr bgcolor='white' align='center'><td><font color='red' size=2>No comments for you.</font></td></tr></table>"; } ?> Edit: Please use [code][/code] tags when posting code. So I am trying to execute an sql query by clicking a button or a link. Ultimately I want users to be able to click the "Fav" button and it then fades into "Added to favorites!" (I am building a favorite system which first collects data on page load like userid and itemid and then it needs to send it to the DB after a button is clicked) The fade and stuff is not the most important part now (although a tip on doing that would be awesome) but the most important part is how to get this functional: PHP Code: <?php // Start Favorite System! $user =& JFactory::getUser(); $userid = $user->id; if ($userid == 62) { echo "userID: ".$userid."<p />"; if ($user->guest) {echo "You are a guest<p />";} $itemid = $this->item->id; echo "itemID: ".$itemid."<p />"; $catid= $this->item->category->id; echo "catID: ".$catid."<p />"; $query = "INSERT INTO jos_k2_fav_xref (userID, itemID, catID) VALUES ('$userid', '$itemid', '$catid')"; // Need a way to make this into a button $run = mysql_query($query) or die(mysql_error()); } else {} ?> Currently all the values get stored in the DB as the page is loaded. I however want to be able to click on something to execute that query how do i do that? I read a bunch of stuff on javascript and ajax but it got me nowhere... Help is greatly appreciated! This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=357107.0 This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=326913.0 I am trying to have the text alongside the radio button trigger the radio button (cannot use < a href ) e.g. () Trigger with this text The closest I have found is <label for="r1"><input type="radio" name="group1" id="r1" value="1" /> button one</label> But it does not seem to work? Any help greatly appreciated I have a function to display some images and allow a user to select a choice via a radio button.The value is then passed to another function. I have 2 problems My selection is not being passed back and I cant assign the value to a query sring in a link to another page. On the form do i need to add checked? Any help appreciated. Code: [Select] function cover() { echo'<h2>Please upload your book cover or choose one from the selection</h2> <p>All book ideas require a cover. Your choice can be changed at a later date.</p>'; //process selection of cover if (isset($_POST['submit'])) { $coverID=$_POST['cover']; echo $coverID; ?>   <ul><li class="demo-menu-link"><a href="?page=submenu7&coverID=$coverID">Finnished Cover</a></li></ul><?php exit(); } else{ echo "not Submitted"; } global $wpdb; $query = "select * from wp_cover"; $result = mysql_query($query) or trigger_error("Query: $query\n<br />MySQL Error: " . mysql_error()); echo mysql_error(); if (!$result){ return false; } echo'<div class="wrap"><p>choose from one of the covers below</p></div>'; ?><form action="<?php $_SERVER['PHP_SELF'] ?>" method="POST" id="cover" enctype="multipart/form-data"> <table><tr><?php /* display picture and radio button */ while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $coverID=$row['coverID']; echo"<img src=\"/wordpress_3/wp-content/plugins/Authors2/jackets/{$row['pix']}\" />"; echo"<td>"; echo $coverID; echo "<Input type = 'Radio' Name ='cover' value= '$coverID'/>"; ?> </tr></table> <input type=submit value=submit> </form><?php } } What am I doing wrong with this selected radio button? <form action="Process/privacy.php" method="post" enctype="multipart/form-data" id="privacy"> <div id="privacy_vis">Your profile is visible to:</div> <div id="privacy_select"> <label> <input name="RadioGroup1" type="radio" id="RadioGroup1_0" value="1" <?if($visible=="1")echo 'checked="checked"';?> /> Everyone</label> <label> <input name="RadioGroup1" type="radio" id="RadioGroup1_1" value="0"/> Members Only</label> </div> <br /> <div id="privacy_vis">Your Password to view your private pictures is:</div> <div> <input name="pictures_pw" type="text" id="pictures_pw" value="<? echo "$xxx_pw" ?>" size="50" maxlength="20" /> </div> <br /> <div> <input name="submit" type="submit" class="button" id="submit" value="Save Changes" /> </div> </form> </div> Hello, I had 3 radio buttons with the same name, well, I had created 3 text box that are next to those 3 radio buttons. When I click save to the form, I need to know which radio button had been pressed, so that I can detect & retrieve its value. Any help? Thanks I have a group of 4 radio buttons. my mysql database knows which one the user selected previously when they stored some information. I now wish to display the same buttons but have radio button checked that the user chose before. I know this can be done but having one of those mind melt moments where I cannot think of the solution so I have 4 buttons that look like this Code: [Select] <input type="radio" name="clarity" id="clarity" value="Opaque"> Opaque<br> <input type="radio" name="clarity" id="clarity" value="Deep"> Deep<br> <input type="radio" name="clarity" id="clarity" value="Mid"> Mid<br> <input type="radio" name="clarity" id="clarity" value="Pale"> Pale<br></td> I just need to attached a checked field to the correct item i would like to display the value of the selected radio button on the same page... what i want is just reload the page and if there is a radio button selected displays it but i cant display it <?PHP if (isset($_GET["submit"])) { echo $_GET["myradio"]; } ?> <html> <head> </head> <body> <form action="<?PHP $_SERVER["PHP_SELF"]; ?>" method="get"> One <input type="radio" name="myradio" value="one"> Two <input type="radio" name="myradio" value="two"> <a href="<?PHP $_SERVER["PHP_SELF"]; ?>" name="submit">test </a> </form> </body> </html> please help guys...thanks how do you make it so that a radio button is either checked or unchecked based on database? |
|||||||